Answers
Answer: 2a- 0.4167s
Explanation:
Given: distance= 5m, speed= 12m/s
Unknown: time
Equation: t= d/s
Substitution: t=5/12
t=0.4167s
Related Questions
a generator uses loops of area 0.239 m^2, rotating 373 rad/s in a 0.0639 t magnetic field. how many loops must the coil have to generate a maximum emf of 2500 v?
Answers
The loops must the coil have to generate a maximum emf of 2500 will be 439.
What is the faraday law of electromagnetic induction?According to Faraday's law of electromagnetic induction, the rate of change of magnetic flux linked with the coil is responsible for generating emf in the coil resulting in the flow of amount of current.
Given data;
Area,A = 0.239 m²
Angular velocity,ω=373 rad/sec
Magnetic field,B=0.0639 T
Maximum emf,E= 2500V
The formula for the maximum induced voltage is;
E{max} = N × B × A × ω
2500 = N × 0.639 × 0.0239 × 373
N = 438.66
N = 439 \ turns
Hence, loops must the coil have to generate a maximum emf of 2500 will be 439.
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Answer: 11392.99
Explanation: I had the same problem and here are the steps:
Values:
N (Number of loops) = 2000
A (area) = 0.239
ω (angular velocity) = 373
B (magnitude) = 0.0639
ε = NABω
= (2000)(0.239)(373)(0.0639)
ε = 11392.99 (FINAL ANSWER)
Use the force diagrams below to determine whether the cart is not moving, moving at a constant speed speeding up or slowing down
Answers
a) Cart is speeding up ; b) cart is slowing down and c) cart is not moving.
What do you understand by force and friction?Force of friction is a contact force whereas friction is the force that resists motion when surface of one object comes in contact with surface of another. Example is the force of friction between two stones rubbed with each other.
Static friction magnitude is directly proportional to normal force magnitude and the roughness between sliding surfaces. The ratio of magnitude of frictional force divided by normal force magnitude is called as coefficient of friction. Friction takes place at the point of contact between two bodies.
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5. Hilda is trying to move a 40 kg couch across a level floor and pushes with a horizontal force of
150 N, but the couch does not move. What is the minimum coefficient of static friction with the
floor? Assume the acceleration due to gravity is g = 9.8 m/s2
Answers
The minimum coefficient of static friction with the floor is 0.3846.
To find the minimum coefficient of static friction with the floor, we need to consider the forces acting on the couch. In this case, the force of gravity is pulling the couch downward with a magnitude of mg, where m is the mass of the couch (40 kg) and g is the acceleration due to gravity (9.8 m/s²).
Since the couch does not move, the force of static friction between the couch and the floor must be equal in magnitude but opposite in direction to the horizontal pushing force of 150 N.
Therefore, we have the equation F_friction = F_push, where F_friction is the force of static friction.
The force of static friction can be calculated using the formula F_friction = μ_s * N, where μ_s is the coefficient of static friction and N is the normal force.
Since the couch is on a level floor and is not accelerating vertically, the normal force N is equal in magnitude but opposite in direction to the force of gravity, which is mg.
Substituting the values into the equation, we have μs * mg = 150 N.
Solving for μs, we get μs = 150 N / (mg).
Substituting the given values, we have μ_s = 150 N / (40 kg * 9.8 m/s²).
Simplifying, we find that μs = 0.3846.
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The diagram below shows four layers of Earth.
The picture shows the internal structure of Earth. The central region is labeled 'A.' The layer around the central region is labeled 'B.' The outermost layer is labeled 'D.' The layer inside Earth which is just after layer D is labeled 'C.'
In which of these layers does hot material move upwards and cool material sink downwards?
Layer A
Layer B
Layer C
Layer D
Answers
Answer:
Layer C
Explanation:
Hope this helps!
-Liyah<3
The vector diagram below represents the path and
distances run by a student in a cross-country race.
N
W
S
E
Start
Finish
0.80 km
1.00 km
1.80 km
0.60 km
0.80 km
The displacement of the student from start to
fi nish is
(1) 1.40 km north (3) 5.00 km north
(2) 1.40 km south (4) 5.00 km south
Answers
The displacement of the student from start to finish is 1.4 km South
What is the difference between distance and displacement?Distance is the total motion of an object from start to finish without giving regard to direction of motion. Distance can be said to be how much ground an object has covered from the start to the end of it motion.
Displacement on the other hand is the distance travelled in a specified direction.
The displacement between two points is the shortest possible distance of separation of the two two points along a straight line.
Considering the vector diagram representing the path and distances run by a student in a cross-country race:
The displacement of the student from start to finish = 0.8 km + 0.6 km
The displacement of the student from start to finish = 1.4 km South
In conclusion, the displacement of the student gives the distance travelled in a specific direction.
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Focal distance of a concave lens is always:
O A. smaller than the image distance.
O B. positive.
O C. negative.
O D. larger than the object distance.
Answers
Part one: Multiple choices
1) A person sitting in the compartment of moving train is:
a) in the state of rest with respect to surroundings of the compartment,
b) in the state of motion with respect to surroundings of the compartment.
C) in the state of rest with respect to surroundings outside of the compartment
d)all of them
2) The motion of tuning fork prongs on vibration is:
a) Linear motion
b) periodic motion
c) circular motion
d) projectile motion
3) All the following are periodic motion except
a) moving car in straight line
b) Earth's rotation
c) pendulum
d) Swing
4) The rate of change of displacement is:
a) Acceleration
b) force
c) distance
d) velocity
5) When an object moves at negative acceleration in a straight line its:
a) displacement equals zero
b) velocity decrease
C) velocity increase
d) none of them
6) When the object speeds up its acceleration:
a) decreases
b) increases c) it has no acceleration d) All of them
7) The rate of change of velocity is:
a) force
b) variable velocity
c) instantaneous velocity
d) acceleration
8) If a train is moving in a straight line to cover a distance of 600 m in a minute its
velocity is:
a) 600 m/s
b) 60 m/s c) 100 m/s d) 480 m/s
9) The division between total displacement and total time is the:
a) variable velocity b) average velocity c) speed d) Instantaneous velocity
10) The rate of change of displacement at a given instant is called the
a) average velocity
b) instantaneous velocity
C) average velocity
d) instantaneous acceleration
11) A body completes one circular revolution in a roundabout whose diameter
140 m.
Find its displacement,
a) 439.6 m
b) 440 m
c) zero
d) 879.2 m
Answers
Answer:
1)
a) in the state of rest with respect to surroundings of the compartment,
2)
b) periodic motion
3)
a) moving car in a straight line
4)
d) velocity
5)
b) velocity decrease
6)
b) increases
7)
d) acceleration
8)
10 m/s
9)
b) average velocity
10)
b) instantaneous velocity
11)
a) 439.6 m
Explanation:
1)
With respect to the inside surrounding the person will be at rest. Because the person is not moving inside the compartment.
2)
The vibration motion follows periodic motion.
3)
The car moving in a straight line is an example of rectilinear motion and its wheels are in rotational motion. They are not in periodic motion.
4)
Definition of velocity.
5)
Acceleration is the rate of change of velocity. So negative acceleration means a decrease in velocity.
6)
Acceleration is the rate of change of velocity. So an increase in velocity means an increase in acceleration.
7)
Definition of acceleration.
8)
\(velocity = \frac{Distance}{Time}\\\\velocty = \frac{600\ m}{1\ min}\frac{1\ min}{60\ s}\\\\velocity = 10\ m/s\)
Hence, none of the options is correct. The correct answer is 10 m/s.
9)
Definition of average velocity.
10)
Definition of instantaneous velocity.
11)
\(Displacement = Circumference = \pi d\\Displacement = \pi(140\ m)\\Displacement = 439.6\ m\)
A ball is dropped from a height of 10m. At the same time, another ball is thrown
vertically upwards at an initial speed of 10m/sec. How high above the ground will the two balls
collide?
Answers
5.1 m
Explanation:
Let's set the ground as our reference point. Let's also call the dropped ball to be ball #1 and its height above the ground at any time t is given by
\(y_1 = 10 - \frac{1}{2}gt^2\) (1)
where 10 represents its initial height or displacement of 10 m above the ground. At the same time, the displacement of the second ball with respect to the ground \(y_2,\) is given by
\(y_2 = v_0t - \frac{1}{2}gt^2\) (2)
At the instant the two balls collide, they will have the same displacement, therefore
\(y_1 = y_2 \Rightarrow 10 - \frac{1}{2}gt^2 = v_0t - \frac{1}{2}gt^2\)
or
\(v_0t = 10\:\text{m}\)
Solving for t, we get
\(t = \dfrac{10\:\text{m}}{v_0} = \dfrac{10\:\text{m}}{10\:\text{m/s}} = 1\:\text{s}\)
We can use either Eqn(1) or Eqn(2) to hind the height where they collide. Let's use Eqn(1):
\(y_1 = 10\:\text{m} - \frac{1}{2}(9.8\:\text{m/s}^2)(1\:\text{s})^2\)
\(\:\:\:\:\:\:\:= 5.1\:\text{m}\)
Which of the following is a vector quantity
weight
temperature
acceleration
distance
Answers
Answer:
weight, acceleration
Explanation:
weight = mass x gravity(meaning the direction of the mass)
acceleration = v-u/t
v-u is the change in velocity
Which chemical equation is balanced?
O Na + O2--> Na20
O 2Na + 202 --> 2Na20
O 2Na2 + 02 --> 2Na20
4Na + 02 --> 2Na20
G
Answers
The work-energy theorem states that the change in the kinetic energy of an object is equal to what?
Answers
The work-energy theorem states that the change in the kinetic energy of an object will be equal to the net work done on the object.
Mathematically, it can be expressed as;
ΔKE = W
Where; ΔKE represents the change in kinetic energy of the object,
W represents the net work done on the object.
This theorem states that when work is done on an object, it results in a change in its kinetic energy. If work is done on an object, its kinetic energy increases, and if work is done by an object, its kinetic energy decreases.
This theorem is a fundamental principle in physics that relates the concepts of work and energy, and it is often used to analyze the motion and behavior of objects in various physical systems.
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ian pushed a piano across the room with the correct amount of force. Which of newton’s laws is this?
Newton’s 1st, 2nd, 3rd, or 1st and 2nd law?
Answers
Answer:
1st and 2nd
Explanation:
The velocity time graph of an object mass 50 g is shown in figure study graph and answer
1)calculate force acting on object in time interval 0-3 seconds
2)calculate the force acting on the object in the time interval 6-10 seconds
3)Is there any time interval in which no force acts on object.Justify
Answers
1) The force acting on the object during the time interval 0-3 seconds is 1/3 N.
2) The force acting on the object during the time interval 6-10 seconds is -0.5 N.
3) There is no time interval in which no force acts on the object.
(i) Force acting on the object in time interval 0-3 seconds. Force acting on the object is equal to the product of its mass and acceleration, i.e.,F = ma.
In the given velocity-time graph, the acceleration of the object can be determined by determining the slope of the velocity-time graph from 0 to 3 seconds.
Slope = (change in velocity) / (change in time)= (20-0) / (3-0) = 20/3 m/s^2
Acceleration, a = slope= 20/3 m/s^2
Mass of the object, m = 50 g = 0.05 kg
∴ Force acting on the object, F = ma= 0.05 × 20/3= 1/3 N.
Therefore, the force acting on the object during the time interval 0-3 seconds is 1/3 N.
(ii) Force acting on the object in time interval 6-10 seconds. Similar to the first question, the force acting on the object in time interval 6-10 seconds can be determined by determining the acceleration of the object during this time interval.
The slope of the velocity-time graph from 6 seconds to 10 seconds can be determined as follows:
Slope = (change in velocity) / (change in time)= (-20-20) / (10-6) = -40/4= -10 m/s^2 (negative sign indicates that the object is decelerating)
Mass of the object, m = 50 g = 0.05 kg
∴ Force acting on the object, F = ma= 0.05 × (-10)= -0.5 N.
Therefore, the force acting on the object during the time interval 6-10 seconds is -0.5 N.
(iii) Time interval in which no force acts on the object. There is no time interval in which no force acts on the object. This is because, as per Newton's first law of motion, an object will continue to remain in a state of rest or uniform motion along a straight line unless acted upon by an external unbalanced force.In other words, if the object is moving with a constant velocity, there must be a force acting on the object to maintain its motion.
Therefore, there is no time interval in which no force acts on the object.
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If John throws a "ball” from a cliff with a speed of 15 m/s, how far from the bottom of the cliff does it land after 10 seconds?
Answers
Answer:
wazzam blood
Explanation:
the tighter the threads of the screw the greater
Answers
The brain is responsible for storing memories. How is this helpful for helping the body react to stimuli?
please answer
Answers
Answer:
The brain controls what you think and feel, how you learn and remember, and the way you move and talk. But it also controls things you're less aware of, like the beating of your heart and the digestion of your food. Think of the brain as a central computer that controls all the body's functions. The rest of the nervous system is like a network that relays messages back and forth from the brain to different parts of the body. It does this via the spinal cord, which runs from the brain down through the back. It contains threadlike nerves that branch out to every organ and body part.
Explanation:
A 0.60-kgkg ball, attached to the end of a horizontal cord, is rotated in a circle of radius 1.3 mm on a frictionless horizontal surface. Part A If the cord will break when the tension in it exceeds 60 NN , what is the maximum speed the ball can have
Answers
11.4 m/s
Explanation:
The cord will break when the centripetal force exerted on it meets or exceeds the maximum tension \(T_{max}\) that it can handle.
\(T_{max} = m\dfrac{v_{max}^2}{r}\)
Solving for \(v_{max},\) we get
\(v_{max}^2 = \dfrac{rT_{max}}{m}\)
or
\(v_{max} = \sqrt{\dfrac{rT_{max}}{m}} =\sqrt{\dfrac{(1.3\:\text{m})(60\:\text{N})}{(0.6\:\text{kg})}}\)
\(\:\:\:\:\:= 11.4\:\text{m/s}\)
explain in terms of the arrangement of particles the kinetic theory of matter
Answers
Answer:
The kinetic theory of matter can be used to explain how solids, liquids and gases are interchangeable as a result of increase or decrease in heat energy. When an object is heated the motion of the particles increases as the particles become more energetic
Obtain an expression for the viscous force acting on a sphere of radius r moving in a viscous fluid with velocity v, if the viscosity coefficient is η.
Answers
The force of viscosity is F = k r v η. Spherical balls of radius R are falling in a viscous fluid of viscosity η with a velocity v.
What is viscous force?
Viscosity refers to a material's capacity to resist movement between its layers. It is the force that resists relative motion between the layers. It is also known as viscous force.
What is viscous force formula?
In the above equation, the shear force is the viscous force, which is the only internal resistance that causes shear stress to develop along with the fluid layers. As a result, the viscous force formula will be given as. F=Aμdudy.
Hence F = k r v η is a correct answer.
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A small oil droplet is sprayed between the plates of a parallel plate capacitor. The droplet has a net charge equal to that of 3 electrons and feels a total force equal to 9.6 x 10-15 N. What is the electric fieldbetween the plates of the parallel plate capacitor
Answers
Answer:
…..
Explanation:
give brainiest
What does volume measure name two different units that might be used to measure volume
Answers
Answer:
Volume measures liquid
Explanation:
Volume can be measured in meters and centimeters
* What is the effect of temperature
on density of liquid?
-)
Answers
Answer:
evaporation?
sorry if im wrong
Explanation:
Temperature is inversely propotional to the density of liquid
the mass of the velociraptor and cage together is 175 kg. What is the gravitational potential energy added when when the velociraptor and cage is lifted from the ground to a height of 9 m?
Answers
The gravitational potential energy added when the velociraptor and cage is lifted from the ground to a height of 9 m is approximately 15,998.95 joules.
What is Potential Energy?
Potential energy is a form of energy that is stored in an object due to its position or configuration in a system. It is the energy that an object has the potential to possess, or the ability to do work, as a result of its position or state.
The gravitational potential energy (GPE) added when the velociraptor and cage is lifted from the ground to a height of 9 m can be calculated using the formula:
GPE = mgh
Where m is the mass of the velociraptor and cage, g is the acceleration due to gravity (approximately 9.81 m/\(s^{2}\)), and h is the height lifted.
Given that the mass of the velociraptor and cage together is 175 kg, and the height lifted is 9 m, we can substitute these values into the formula:
GPE = mgh
GPE = (175 kg) x (9.81 m/\(s^{2}\)) x (9 m)
GPE = 15,998.95 J (joules)
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Pls help I will give Brainliest to First and Correct Answer.
You want to move your tv unit back closer to the wall. The first way is to push it from the middle. The second way would be to push it from the top.
Which point of application would result in the tv unit tipping over? Why?
Answers
Answer:
I would say pushing it from the top because when you push anything from the top it basically flips over. You can go ahead and try to push anything forward from the top and starts tipping forward. I think the reason would be because you're putting weight only on the top of the tv and that is what would cause it to topple
Explanation: Hope this helps:)
Chloe's mother threatens to ground her for life if she comes home after curfew. Chloe knows her mother cannot follow through with that punishment and comes home late anyway. Chloe's mother should have used which tip for effective punishment?
She should have used a punishment that is really punishing.
She should have punished Chloe immediately after the bad behavior occurred.
She should have remained calm while punishing Chloe to eliminate the chance of abuse.
She should have punished Chole each and every time the bad behavior occurred.
Answers
Answer:
The third option
Explanation:
The third option would be the best choice because while staying calm, Cloe will feel guilty and her mother will not be stressed. Staying calm also shows that Cloe's mother loves her but is disapointed, making Cloe think twice about her actions, while yelling and whipping only puts fear into her mind.
Determine the average velocity of the cart during the time interval from frame 100100 to frame 124124. For all vector quantities, we’ll use the convention that right is positive and left is negative.
Answers
The video showing the movement of the cart during the time interval is gotten from the link;
https://mediaplayer.pearsoncmg.com/assets/_frames.true/frames.true_white_ruler
Answer:
V_avg = 1.8 m/s
Explanation:
From the video, the distance moved by the cart during the 24 frames is 18 cm or 0.18 m.
Now, the speed is at the rate of 240 frames per seconds.
Now, average velocity is given as;
V_avg = distance/time
Time = 24 frames/240 frames/s
Time = 0.1 s
Thus;
V_avg = 0.18/0.1
V_avg = 1.8 m/s
A projectile is fired at an upward angle of 45.0º from the top of a 265-m cliff with a speed of .sm 185 What will be its speed when it strikes the ground below? (Use conservation of energy.)
Answers
The final velocity of the projectile when it strikes the ground below is 198.51 m/s.
Time of motion of the projectileThe time taken for the projectile to fall to the ground is calculated as follows;
h = vt + ¹/₂gt²
where;
h is height of the cliffv is velocityt is time of motion265 = (185 x sin45)t + (0.5)(9.8)t²
265 = 130.8t + 4.9t²
4.9t² + 130.8t - 265 = 0
solve the quadratic equation using formula method,
t = 1.89 s
Final velocity of the projectilevyf = vyi + gt
where;
vyf is the final vertical velocityvyi is initial vertical velocityvyf = (185 x sin45) + (9.8 x 1.89)
vyf = 149.322 m/s
vxf = vxi
where;
vxf is the final horizontal velocityvxi is the initial horizontal velocityvxf = 185 x cos(45)
vxf = 130.8 m/s
vf = √(vyf² + vxf²)
where;
vf is the speed of the projectile when it strikes the ground belowvf = √(149.322² + 130.8²)
vf = 198.51 m/s
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A square meter of the axon membrane has a resistance of 0.2 ohms. The membrane is 7.5 x 10‐⁹ m thick. What is the resistivity of the membrane?
Answers
Answer:
using the formula
Resistance=Resistivity × length/area
Area=1 ,Resistance(R)=0.2ohm ,resistivity(P)=? ,length=7.5×10^-9
R=Pl/A
Pl=RA
P=RA/l
P=0.2×1/7.5×10^-9
P=0.027×10^9
P=2.7×10^7ohmsmeter
The resistivity of the membrane is 2.7×10⁷ ohm-meter.
What is resistivity?
Electrical resistance of a conductor with a unit cross-sectional area and unit length is called resistivity. Resistivity is a distinctive attribute of any material that may be used to compare different materials based on how well they conduct electric currents. Low conductivity is indicated by high resistance.
Mathematically the relation between resistance and resistivity can be written as:
Resistance=Resistivity × length/area
Given parameters:
Area of the membrane: A=1 m²
Resistance(R)=0.2ohm ,
resistivity(ρ)=?
length=7.5×10^-9 m.
Now:
R=ρl/A
⇒ρl=RA
⇒ρ=RA/l
⇒ρ=0.2×1/7.5×10⁻⁹
⇒ρ=0.027×10⁹
⇒ρ=2.7×10⁷ ohm-meter.
Hence, the resistivity of the membrane is 2.7×10⁷ ohm-meter.
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Evaluate (2-3)^(4) - 9 - 3.
-7
VX
-2.
1
2
Answers
Answer:
−10.1−3.−7VX,2
Explanation:
Answer:
Evaluate (2 - 3)4(4) - 9 ÷ 3.
-7
-2
1
2
Explanation:
answer is 1
At which position do you expect its speed to be one-half the speed at which it eventually hits the ground?
At which position do you expect its speed to be one-half the speed at which it eventually hits the ground?
Higher than the midpoint of the path.
Lower than the midpoint of the path.
At the midpoint of the path.
Answers
The point where the object's speed is one-half its final speed may located at 3/4 of the initial height of the object, the answer would be "lower than the midpoint of the path."
Assuming the object is subject to a constant acceleration due to gravity, the speed of the object at any given point can be described by the following equation:
v² = u² + 2as
Where:
v = final velocity
u = initial velocity
a = acceleration due to gravity (approximately 9.8 m/s² near the Earth's surface)
s = distance traveled
Let's suppose the object is dropped from rest at a height h above the ground. Then its initial velocity is u=0, and the equation simplifies to:
v² = 2gh
where g is the acceleration due to gravity and h is the initial height of the object.
To find the point at which the object's speed is one-half its final speed, we can set v = 1/2 * √(2gh) and solve for s:
1/2 * √(2gh) = √(2gh - 2gs)
Simplifying this equation, we get:
1/4 * 2gh = 2gh - 2gs
s = 3/4 * h
This means that the point where the object's speed is one-half its final speed is located at 3/4 of the initial height of the object. Therefore, the answer is "lower than the midpoint of the path."
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