graduated cylinder. (plz help)​

Connecting a zinc rod to an iron pipe offers advantages in protecting the iron surface from corrosion. The zinc acts as a sacrificial anode, corroding in place of the iron and providing uniform and extended protection to the entire iron pipe.

Connecting a zinc rod to an iron pipe is advantageous to protect the iron (Fe) surface from undergoing corrosion. This process is known as cathodic protection, where the zinc acts as a sacrificial anode. Here's the justification for this answer:

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Answer:

its B

Explanation:

this is pretty obvious since I know about this and did it already.

I Hope this helps!

GOODLUCK!!!!!!!

1) First, let's calculate the molar mass of NaCl and CoCl₂:

Atomic mass of:

Na - 22.99 g/mol

Cl - 35.45 g/mol

Co - 58.93 g/mol

So for NaCl:

22.99 + 35.45 = 58.44 g/mol

Molar mass of NaCl = 58.44 g/mol

For CoCl₂:

58.93 + (2x35.45) = 129.83 g/mol

Molar mass of CoCl₂: 129.83 g/mol

2) Now let's find out the number of moles of each sample. For this, we use the following equation:

moles = mass / molar mass

NaCl:

mole = 116.8 / 58.44

mole = 1.999 moles of NaCl

CoCl₂:

mole = 259.7 / 129.83

mole = 2.000 moles of CoCl₂

3) To find the amount of particles, we use the Avogadro's constant. Avogadro's constant is a constant of proportion between the amount of matter and the number of entities that are linked to that amount. These entities can be atoms, molecules, ions, electrons, protons, neutrons.

In this case, we have the same number of moles, so we will have the same number of particles for both NaCl and CoCl₂.

The part of the enzyme molecule into which the substrate fits is called the active site. The active site is a specific region on the surface of an enzyme to which the substrate binds and chemically reacts.

The substrate is a molecule that fits perfectly into the active site of an enzyme, and the chemical reaction can only occur in the presence of the appropriate enzyme and substrate. The substrate is the molecule that binds to the active site on an enzyme to catalyze a chemical reaction. The active site is the specific area on the surface of the enzyme to which the substrate binds to form an enzyme-substrate complex. The enzyme's active site and the substrate's chemical structure must be complementary for the enzyme to catalyze the reaction effectively.

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Answer:

Place the graduated cylinder on a flat surface and view the height of the liquid in the cylinder with your eyes directly level with the liquid.

hope it helps :)

1 mole of methane (CH4) is burned it releaes 326.3 KJ of heat then the ΔH for the process in which 8.7 g of methane is burned is 176.8 kJ.

the number of moles of methane in 8.7 g:

molar mass of CH4 = 12.01 + 4(1.01) = 16.05 g/mol

moles of CH4 = 8.7 g / 16.05 g/mol = 0.542 moles

Now, we can use the given information to calculate the heat released:

ΔH = q/n

where q is the heat released and n is the number of moles of methane.

ΔH = (326.3 kJ/1 mol) x (0.542 mol) = 176.8 kJ.

Methane is a chemical compound that consists of one carbon atom and four hydrogen atoms, with the chemical formula CH4. It is a colorless, odorless, and flammable gas that is the main component of natural gas. Methane is the simplest hydrocarbon molecule and is a major contributor to greenhouse gas emissions. It is produced naturally by the breakdown of organic matter in wetlands, rice paddies, and the digestive systems of some animals.

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Answer:

The mole and Avogadro’s number are two important concepts of science that provide a link between the properties of individual atoms or molecules and the properties of bulk matter. It is clear that an early theorist of the idea of these two concepts was Avogadro. However, the research literature shows that there is a controversy about the subjects of when and by whom the mole concept was first introduced into science and when and by whom Avogadro’s number was first calculated. Based on this point, the following five matters are taken into consideration in this paper. First, in order to base the subject matter on a strong ground, the historical development of understanding the particulate nature of matter is presented. Second, in 1811, Amedeo Avogadro built the theoretical foundations of the mole concept and the number 6.022 × 1023 mol−1. Third, in 1865, Johann Josef Loschmidt first estimated the number of molecules in a cubic centimetre of a gas under normal conditions as 1.83 × 1018. Fourth, in 1881, August Horstmann first introduced the concept of gram-molecular weight in the sense of today’s mole concept into chemistry and, in 1900, Wilhelm Ostwald first used the term mole instead of the term ‘gram-molecular weight’. Lastly, in 1889, Károly Than first determined the gram-molecular volume of gases under normal conditions as 22,330 cm3. Accordingly, the first value for Avogadro’s number in science history should be 4.09 × 1022 molecules/gram-molecular weight, which is calculated by multiplying Loschmidt’s 1.83 × 1018 molecules/cm3 by Than’s 22,330 cm3/gram-molecular weight. Hence, Avogadro is the originator of the ideas of the mole and the number 6.022 × 1023 mol−1, Horstmann first introduced the mole concept into science/chemistry, and Loschmidt and Than are the scientists who first calculated Avogadro’s number. However, in the science research literature, it is widely expressed that the mole concept was first introduced into chemistry by Ostwald in 1900 and that Avogadro’s number was first calculated by Jean Baptiste Perrin in 1908. As a result, in this study, it is particularly emphasised that Horstmann first introduced the mole concept into science/chemistry and the first value of Avogadro’s number in the history of science was 4.09 × 1022 molecules/gram-molecular weight and Loschmidt and Than together first calculated this number.

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Answer:

78878

Explanation:

0.044moles are in 0.75 g of ammonia. 2.6 ×10²² are molecules.  Ammonia is a colorless gas with a strong odor.

Ammonia is indeed an inorganic nitrogen and hydrogen chemical with the formula NH3. Ammonia is a colorless gas with a strong odor that is a stable binary hydride as well as the simplest pnictogen hydride.

It is a frequent nitrogenous waste, especially among aquatic creatures, and it considerably contributes to the nutritional demands of terrestrial life by acting as a forerunner to 45% of the world's food as well as fertilizers.

mole = 0.75/17.03=0.044moles

molecules = 0.044× 6.022×10²³

                =2.6 ×10²²  

Therefore, 0.044moles are in 0.75 g of ammonia. 2.6 ×10²²  are molecules.

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the element is nitrogen

5+2=7

Water is an unique substance. The following is false regarding water is

(b) Each water molecule engages in four H-bonds with its neighboring water molecules.

While it is true that water molecules are capable of forming hydrogen bonds with their neighboring water molecules, not every water molecule engages in four hydrogen bonds. In liquid water, the average number of hydrogen bonds per water molecule is less than four due to constant molecular motion and the disruption of some hydrogen bonds. However, in ice, each water molecule forms four stable hydrogen bonds with its neighboring water molecules, which contributes to the unique properties of ice.

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The overall charge of an ion is determined by how many electrons it has gained or lost. A negative overall charge results from an atom gaining electrons.

Atoms that lose an electron change into positive ions, often known as cations. Atoms transform into negative ions, or anions, when they pick up electrons.

If the charge is negative, the atomic number is increased by the charge. If it's negative, the ion has picked up electrons. The total number of electrons can be calculated by multiplying the atomic number by the charge. Protons are less numerous than electrons in this instance.

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Answer: C: Sodium donates an electron to chlorine.

Explanation:

Sodium wants to lose an electron and chlorine wants to gain an electron to become stable. This is because of their place in the periodic table, sodium being on the very left edge and chlorine on the very right (noble gasses dont count as they are stable to begin with)

Therefore sodium will donate to chlorine so they both become stable with an ionic bond. (another way to tell its ionic is the very large difference in electronegativity)

When table salt forms, sodium donates an electron to chlorine resulting in the formation of bond which is formed when the electronic configurations become stable.

Electronic configuration is defined as the distribution of electrons which are present in an atom or molecule in atomic or molecular orbitals.It describes how each electron moves independently in an orbital.

Knowledge of electronic configuration is necessary for understanding the structure of periodic table.It helps in understanding the chemical properties of elements.

Elements undergo chemical reactions in order to achieve stability. Main group elements obey the octet rule in their electronic configuration while the transition elements follow the 18 electron rule. Noble elements have valence shell complete in ground state and hence are said to be stable.

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The ΔH for the given gas phase reaction is -4 kJ/mol, indicating an exothermic reaction where heat is released.

To calculate ΔH (enthalpy change) for the gas phase reaction NH3(g) + Cl2(g) → NH2Cl(g) + HCl(g), we need to subtract the sum of the bond energies of the reactants from the sum of the bond energies of the products.

The given bond energies are as follows:

N-H = 389 kJ/mol

N-Cl = 201 kJ/mol

H-Cl = 427 kJ/mol

Cl-Cl = 243 kJ/mol

In the reactants:

NH3 contains three N-H bonds and Cl2 has one Cl-Cl bond.

In the products:

NH2Cl contains two N-H bonds and one N-Cl bond, and HCl has one H-Cl bond.

Calculating the bond energy changes:

Reactants:

3(N-H) + 1(Cl-Cl) = 3(389 kJ/mol) + 1(243 kJ/mol) = 1167 kJ/mol + 243 kJ/mol = 1410 kJ/mol

Products:

2(N-H) + 1(N-Cl) + 1(H-Cl) = 2(389 kJ/mol) + 1(201 kJ/mol) + 1(427 kJ/mol) = 778 kJ/mol + 201 kJ/mol + 427 kJ/mol = 1406 kJ/mol

ΔH = (sum of bond energies of products) - (sum of bond energies of reactants)

ΔH = 1406 kJ/mol - 1410 kJ/mol = -4 kJ/mol

Therefore, the ΔH for the given gas phase reaction is -4 kJ/mol, indicating an exothermic reaction where heat is released.

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Answer:

This is true

Explanation:

a) mass of NaCl is 29.25 g.

a) To prepare a 1-L salt solution having a concentration of 0.5M NaCl, the mass of NaCl required can be calculated as follows:

Formula

Mass of NaCl = Concentration × Volume × Formula weight

The formula weight of NaCl is equal to (23+35.5) = 58.5 g/mol.

Mass of NaCl = (0.5 mol/L) × (1 L) × (58.5 g/mol) = 29.25 g

b) The balanced equation for the precipitation reaction between NaCl and AgNO3 is:

AgNO3 + NaCl → AgCl + NaNO3

Mass of AgNO3 added to the solution = 1 mg = 1 × 10-3 g

Moles of AgNO3 added to the solution = (1 × 10-3 g)/(AgNO3's molar mass of 169.9 g/mol)

= 5.89 × 10-6 mol

This is the limiting reagent, so it will completely react with NaCl.

Moles of NaCl used in the reaction = Moles of AgNO3 added to the solution = 5.89 × 10-6 mol

Moles of NaCl remaining after the reaction = Moles of NaCl

initially present - Moles of NaCl used in the reaction

Moles of NaCl initially present = Molarity of NaCl × Volume of the solution

Moles of NaCl initially present = (0.5 mol/L) × (1 L) = 0.5 mol

Moles of NaCl remaining after the reaction = 0.5 mol - 5.89 × 10-6 mol = 0.5 mol

The mass of AgCl(s) formed can be calculated using the stoichiometric ratio of AgNO3 to AgCl.

Moles of AgCl formed = Moles of AgNO3 used in the reaction

Moles of AgCl formed = Moles of AgNO3 added to the solution = 5.89 × 10-6 mol

Mass of AgCl formed = Moles of AgCl × Molar mass of AgCl

Mass of AgCl formed = (5.89 × 10-6 mol) × (143.3 g/mol)

Mass of AgCl formed = 8.44 × 10-4 g

Concentration of Na+ in the final solution = (0.5 mol - 5.89 × 10-6 mol) ÷ 1 L

= 0.5 mol/L

Concentration of Cl- in the final solution = (0.5 mol - 5.89 × 10-6 mol) ÷ 1 L

= 0.5 mol/L

Concentration of Ag+ in the final solution = 5.89 × 10-6 mol ÷ 1 L

= 5.89 × 10-6 M

Concentration of NO3- in the final solution = 5.89 × 10-6 mol ÷ 1 L

= 5.89 × 10-6 M

Ppm of Na+ in the final solution = (0.5 mol - 5.89 × 10-6 mol) ÷ 1 L × 23 g/mol × 106 ppm

Ppm of Cl- in the final solution = (0.5 mol - 5.89 × 10-6 mol) ÷ 1 L × 35.5 g/mol × 106 ppm

Ppm of Ag+ in the final solution = 5.89 × 10-6 mol ÷ 1 L × 108 g/mol × 106 ppm

Ppm of NO3- in the final solution = 5.89 × 10-6 mol ÷ 1 L × 62 g/mol × 106 ppm

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Answer: lightbulb, lamp, nightlight

Explanation:

The equation that represents the formation reaction of CH3OH(l) is (a) C(g) + 2H2(g) + ½O2(g) → CH3OH(l).

The formation reaction of a compound is the reaction in which the compound is formed from its constituent elements in their standard states. In the case of CH3OH, the constituent elements are carbon (C), hydrogen (H), and oxygen (O). The standard states for each element are:

Carbon (C): solid graphite

Hydrogen (H): gas

Oxygen (O): gas

To form CH3OH, one carbon atom, four hydrogen atoms, and one oxygen atom are required.

However, the oxygen atom must be present in the form of O2 gas, since it is in its standard state. Thus, the correct equation for the formation reaction of CH3OH is:

C(g) + 2H2(g) + ½O2(g) → CH3OH(l)

This equation shows that one molecule of CH3OH is formed from one molecule of carbon gas, two molecules of hydrogen gas, and half a molecule of oxygen gas.

Note that the equation is balanced, meaning that the number of atoms of each element is the same on both the reactant and product sides of the equation.

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Answer:

Yes

Explanation:

Because if you multiply it with waffles you get salad

Answer:

Yes. The mass number of an atom is the total number of protons and neutrons in its nucleus. Atoms of different elements usually have different mass numbers, but they can be the same.

Explanation:

The number of protons in the nucleus of the atom is equal to the atomic number. The number of electrons in a neutral atom is equal to the number of protons. The number of neutrons is equal to the difference between the mass number of the atom and the atomic number.

1. Complex A will have a lower coordination number than Complex B. 2. Complex B will have a higher electron density around the central metal cation than Complex A. 3. Complex A will have a higher dipole moment than Complex B. 4. Complex B will have a higher ligand field strength than Complex A.


Based on your question and the terms provided, the following statements are true regarding the coordination complexes A and B:

1. Complex A will have higher ionic character due to the presence of chloride ligands, while complex B will have a more covalent character due to the presence of CO ligands.

2. Complex A will likely have a higher crystal field splitting energy (Δ) because chloride ligands are weak field ligands, while CO ligands are strong field ligands in complex B.

3. The color of the two complexes may differ due to different ligands affecting the d-orbital electron transitions.

4. The stability of complex B is generally higher than complex A because CO ligands form stronger bonds with the central metal cation compared to chloride ligands.

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The number-weighted average molecular weight of this polymer sample is 2,000 g/mol.

To calculate the number-weighted average molecular weight of a polymer, you need to divide the total molecular weight of the sample by the number of polymer molecules.

Number-weighted average molecular weight (Mn) = Total molecular weight / Number of polymer molecules

In this case, the total molecular weight of the polymer sample is 2,000,000 g/mol, and there are 1,000 polymer molecules.

Mn = 2,000,000 g/mol / 1,000 molecules

Mn = 2,000 g/mol

Therefore, the number-weighted average molecular weight of this polymer sample is 2,000 g/mol.

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The volume would be three times the original volume is the correct answer.

The volume would be three times the original volume because a reaction produced 3 moles of gas from 1 mole of gaseous reactants. The ratio between reactants and products are 1:3 which shows that three times increase occur in the volume between reactant and products.

So we can conclude that the volume would be three times the original volume is the correct answer.

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The molarity of the nitric acid solution is approximately 21.44 M.

To find the molarity of the nitric acid solution, we need to use the formula:

Molarity (M) = moles of solute / volume of solution (in liters)

First, we need to determine the moles of nitric acid in the solution. To do this, we'll use the equation:

moles = mass / molar mass

The molar mass of HNO₃ is calculated as follows:

H = 1.01 g/mol

N = 14.01 g/mol

O = 16.00 g/mol (x3, as there are three oxygen atoms in HNO₃)

Molar mass of HNO₃ = 1.01 + 14.01 + (16.00 × 3) = 63.01 g/mol

Next, we'll calculate the mass of the nitric acid in the solution:

mass = volume × density

Given density = 1.35 g/mL and volume = 33.7 mL, we can calculate the mass as follows:

mass = 33.7 mL × 1.35 g/mL = 45.495 g

Now, we can calculate the moles of nitric acid:

moles = 45.495 g / 63.01 g/mol ≈ 0.722 mol

Finally, we can calculate the molarity using the moles of nitric acid and the volume of the solution in liters:

Molarity = 0.722 mol / (33.7 mL / 1000) L ≈ 21.44 M

Therefore, the molarity of the nitric acid solution is approximately 21.44 M.

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The resulting volume of the tire would be 1.1 L

According to this law, the volume of a given gas is directly proportional to its temperature, provided that the pressure remains constant.

The law can be presented mathematically as;  

\(\dfrac{V_1}{T_1} =\dfrac{V_2}{T_2}\)

In this case, V1 = 1.0 L, T1 = 22 °C (295 K), T2 = 52 °C (325 K).

\(V_2=\dfrac{V_1T_2}{T_1}\)V

\(V_2=\dfrac{1\times 325}{295}=1.1\ L\)

Hence the final volume of the tire will be 1.1 L

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Answer:

A 3s orbital is at a greater average distance from the nucleus than a 2s orbital

Explanation:

As the principal quantum number n increases, the distance of the orbital from the nucleus increases. Hence if we consider the 2s and 3s orbitals, it is easy to see that the 3s orbital is at a greater distance from the nucleus than the 2s orbitals.

This is clearly seen when we plot the radial distribution against the distance from the nucleus. This enables us to visualize the region in space in which an electron may be found.

Answer:

0.5474

Explanation:

3.22 x 0.17

     \/

322 x 17 = 5,474

[] There are four places "after" the decimal in 3.22 and 0.17 combined, meaning we move the decimal to the right four times in our current answer

-> 5,474 becomes 0.5474

Have a nice day!

     I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

- Heather

Answer:0.55

Explanation:

3.22 × 0.17 calculated with significant figures is 0.55, which has 2 sig figs and 2 decimals. There are 2 steps to calculate 3.22 × 0.17 with sig figs. 0.55 rounded to 1 sig figs is 0.6.

Cody's vehicle accelerates by 3 m/s2 (northward) in the 15 seconds it takes to go from 0 m/s to 45 m/s (northward).

Newton's second law, which states that the force acting on a body is equal to the mass of the body, is the fundamental equation of motion in classical mechanics acceleration an of its center of mass, or F = ma.

When the final velocity is 45 m/s (northward), the beginning velocity is 0 m/s, and the time is 15 seconds, we can calculate the acceleration using the formula acceleration = (final velocity - initial velocity) / time.

When these values are added to the formula, we obtain:

acceleration = (45 m/s - 0 m/s) / 15

acceleration = 3 m/s² (northward).

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