Green Frog Convenience Store supplies two types of protein bars. One protein bar has 320 calories in the 2-ounce size. How many calories are in the 3-ounce size of the bar? *

Answer:

\(\sqrt{13\\}\) ≈ 3.61

Step-by-step explanation:

The given statement is FALSE. The determinant of the sum of two matrices does not equal the sum of the determinants of the matrices.

In fact, the determinant of the sum of two matrices is generally not even equal to the sum of the determinants of the matrices.
This property does not hold true for determinants. In general, the determinant of the sum of two matrices A and B

(det(A+B)) is not equal to the sum of their individual determinants (det(A) + det(B)).

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Answer: buddy if you put it in English i can do it I’m a teacher

Step-by-step explanation:

Hi there!

We know that:

m∠WXZ = 112°

Since m∠1 is 48° greater than m∠2, we can write an expression:

m∠2 = x°

m∠1 = (x + 48)°

Since both angles sum up to m∠WXZ, we can write this as:

112° = x° + (x + 48)°

Solve for x:

112 = 2x + 48

64 = 2x

x = 32°

Answer:

x = 12

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Algebra I

Step-by-step explanation:

Step 1: Define

-2(5x - 5.5) + 8 = -9x + 2 - (-5)

Step 2: Solve for x

Answer: get smart bro

you would know it if you was smart

Step-by-step explanation:

you wont do your work, you always cheat, and you don't listen to the teacher

you need to find the answer out on your own.

P.S. i hope you have a good day :)

Answer:

IJ = 12

Step-by-step explanation:

sum the parts of the ratios, 3 + 3 + 4 = 10 parts

Divide HK by 10 to find the value of one part of the ratio.

40 ÷ 10 = 4 ← value of 1 part of ratio , then

IJ = 3 parts = 3 × 4 = 12

Using simple mathematical operations, we know that the cost of 10 cereal bars is cheaper in supermarkets which is £7.5.

An operation is a function in mathematics that transforms zero or more input values into a clearly defined output value.

The operation's arity is determined by the number of operands.

A formula would be 3x - 5 = 16, for instance.

When this equation is solved, we discover that the value of the variable x is 7.

So, we know that :

Corner shop: 5 cereal bars = £4

1 cereal bar: 4/5 = £0.8

10 cereal bars: 0.8 * 10 = £8

Supermarket: 2 cereal bars = £1.50

1 cereal bar: 1.5/2 = £0.75

10 cereal bars: 0.75 * 10 = £7.5

Therefore, using simple mathematical operations, we know that the cost of 10 cereal bars is cheaper in supermarkets which is £7.5.

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Answer:

Step-by-step explanation:

cos(2a) = cos^2(a) - sin^2(a)

cos(2a) = 2cos^(a) - 1

cos(2a) = 11/25

11/25 = 2 cos^(a) - 1             Add 1 to both sides

1 + 11/25 = 2 cos^2

25/25 + 11/25 = 2 cos^2(a)

36/25 = 2 cos^2 (a)            Divide by 2

36/50 = cos^2 (a)               Take the square root of both sides.

6/5*sqrt(2) = cos(a)            

One is given the following:

One is asked to prove the following:

In order to prove the statement above, one will need to use a trigonometric identity. In this case, the following identity is the most relevant in the proof.

\(cos(2a)=2cos^2(A)-1\)

One can manipulate this identity to suit the needs of the given problem:

\(cos(2a)=2cos^2(A)-1\)

\(cos(2a)+1=2cos^2(A)\)

\(\frac{cos(2a)+1}{2}=cos^2(A)\)

\(\sqrt{\frac{cos(2a)+1}{2}}=cos(A)\)

Now substitute the given information into this identity,

\(cos(2A)=\frac{11}{25}\)

\(\sqrt{\frac{cos(2a)+1}{2}}=cos(A)\)

Substitute,

\(\sqrt{\frac{\frac{11}{25}+1}{2}}=cos(A)\)

Simplify, remember, any number over itself equals (1) and, in order to add two fractions, they must have the same denominator.

\(\sqrt{\frac{\frac{11}{25}+1}{2}}=cos(A)\)

\(\sqrt{\frac{\frac{11}{25}+\frac{25}{25}}{2}}=cos(A)\)

\(\sqrt{\frac{\frac{36}{25}}{2}}=cos(A)\)

\(\sqrt{\frac{18}{25}}=cos(A)\)

\(\frac{3\sqrt{2}}{5}=cos(A)\)

Manipulate so that it resembles the given information; remember, any number over itself is (1), multiplying an equation by (1) doesn't change it,

\(\frac{3\sqrt{2}}{5}=cos(A)\)

\(\frac{3\sqrt{2}}{5}*\frac{\sqrt{2}}{\sqrt{2}}=cos(A)\)

\(\frac{3\sqrt{2*2}}{5*\sqrt{2}}=cos(A)\)

\(\frac{6}{5\sqrt{2}}=cos(A)\)

Answer:

B) The row conditional relative frequencies of "age 10-13" and "eat breakfast" is 74.1%

C) The row conditional relative frequencies of "age 14-17" and "skips breakfast is 66.7%

D) The column conditional relative frequencies of "eat breakfast" and "age 14-17" is 25.5%

Step-by-step explanation:

Answer:

Step-by-step explanation:

Answer: Biased

Step-by-step explanation:

It is biased because this survey is based off of opinions, of the 7th grade boys.

The correct statement among the given options is:O D. If r < 1, then lim(n → ∞) r^n = 0. This statement is known as the geometric series convergence test.

It states that if the common ratio (r) of a geometric sequence is between -1 and 1 (exclusive), then the sequence converges to 0 as n approaches infinity.

The other options are not generally true:

A. The divergence of a sequence does not necessarily imply that its limit as n approaches infinity is infinity. The limit could be any real number or even undefined.

B. The limit of a monotone sequence does not have to be the infimum or supremum of the sequence. It could be any value within or outside the range of the sequence.

C. Monotonicity and boundedness alone do not guarantee convergence. Counterexamples include oscillating sequences or sequences with limit points that are not the limit of the sequence.

Therefore, option D is the correct statement.

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Answer:

D (32, 10)

Step-by-step explanation:

30 - 5 - 5 - 5 - 5 = 10

0 + 8 + 8 + 8 + 8 = 32

Answer:

Step-by-step explanation:

the smallest value is 96.25 or rounded to the nearest whole number it is 96

what i did was put in my calculator 1540 divided by 4^2 because it is squared and has 4 sides

Answer:

0.116

Step-by-step explanation:

\((30.72*0.05)-1.42\\1.536-1.42=\\0.116\)

Your answer is 0.116

Step-by-step explanation:

A lifeline in a sequence diagram is a line that is used to represent an active object, such as a class, interface, or object, and is typically identified by a solid line.

A lifeline in a sequence diagram is a graphical element used to depict the active objects in an interaction or sequence diagram. The lifeline is typically represented as a solid line running from the top of the diagram to the bottom, which represents the object's lifetime. The lifeline is used to show the messages that are sent and received between objects, as well as the sequence in which they occur. Additionally, the lifeline is often used to represent any changes of state in the objects, such as method calls, data values, and more. By depicting the lifelines of the active objects in a sequence diagram, it is possible to gain a better understanding of the interactions between the objects, and how they are related.

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Answer:

Angel Number 1: 90

Step-by-step explanation:

As you can see the angel it is located in is a right Angel or 90 degrees angel.

Answer:

∠1

Step-by-step explanation:

Since ∠1 shares a line and vertex with ∠3, it is the angle adjacent to ∠3.

We can solve with functions exactly as we do algebraic equations. Our goal is to isolate the variable.

We're given:

\(q(x) = \dfrac{1}{2}x-3\\\\q(x) = -4\)

Solve using substitution:

\(\dfrac{1}{2}x-3=-4\)

Isolate x:

\(\dfrac{1}{2}x=-4+3\\\\\dfrac{1}{2}x=-1\\\\x=-2\)

x = -2

Addition of money spens=$274.56

Divided by 8=$274.56/8

=$34.32

Answer:

3n+4

Step-by-step explanation:

Answer:

3n+4 I believe

Step-by-step explanation:

Distributive...

2n+10-6+n

Combine Like terms

2n+n+10-6

3n+10-6

3n+4

Answer:

5(x-4)

Step-by-step explanation:

Answer:

Assuming that you're being asked to simplify the expression. If you are, then the answer is 2n - 8

Step-by-step explanation:

The required probability is 13/20.

Given that,

Number of girls = 14

Number of boys = 8

Since probability = (number of favorable outcomes)/(total outcomes)

Therefore,

The probability of selecting a boy = 8/22

                                                         = 4/11.

We have to find the probability that the second student chosen is a girl, given that the first one was a boy

Since we already know that the first student chosen was a boy,

There are now 13 girls and 7 boys left to choose from.

So,

The probability of selecting a girl as the second student = 13/20

Hence,

The probability that the second student chosen is a girl, given that the first one was a boy, is 13/20.

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The theorem states that for positive natural numbers a and n, the statements "GCD(a, n) = 1" (a and n are relatively prime), "a is not a zero divisor," and "there exists a natural number b such that ab ≡ 1 (mod n)" are all equivalent.

The theorem establishes the equivalence of three statements concerning positive natural numbers a and n. Firstly, if the greatest common divisor (GCD) of a and n is 1, it indicates that a and n are relatively prime.

This means that they have no common factors other than 1.

The second statement states that if a is not a zero divisor, then it implies that a multiplied by any nonzero element b is not equal to zero. In other words, a does not "annihilate" any nonzero element in multiplication.

Lastly, the theorem asserts that if there exists a natural number b such that ab ≡ 1 (mod n), it signifies the existence of a multiplicative inverse of a modulo n.

This means that a and n have a modular inverse, which is a natural number that, when multiplied by a, gives a remainder of 1 when divided by n.

The theorem shows that these three statements are equivalent, meaning that if one statement is true, then the other two statements will also hold.

The proof of this theorem involves establishing the logical connections between these statements and demonstrating that they are always true under the given conditions.

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10% of individuals from a cross between a heterozygous tall individual and a homozygous recessive individual will be tall.

The two alleles present at a gene locus segregate from one another during gamete production, according to Mendel's first law of segregation, and each gamete has a 50% chance of harboring any one of the two alleles.

In meiotic drive genes, the alleles can become absorbed into considerably more than 50% of the gametes if they are present in a heterozygous state, which is against the law of segregation.

Here,

90% of the gametes from a heterozygous individual with tall and short alleles contain short alleles.

If tall dominates short, then 10% of individuals from a cross between a heterozygous tall individual and a homozygous recessive individual will be tall.

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Answer:

Yes.

Step-by-step explanation:

A fraction is a part of a whole number, so yes a fraction is always less than a whole number, unless it's a mixed number. A mixed number is when there is a whole number before the fraction.

Plaz mark brainliest. I just need 2 more to raise my level.

Answer:

Yes unless the fraction is equal to a whole number or is an improper fraction

Step-by-step explanation:

A normal fraction like 2/4 is less than a whole number because a whole number is whole and a fraction is part of

Exceptions:

4/4 is a fraction but is also a whole number

any improper fraction ( a fraction not simplified)

5/4 it equals more than a whole number 1 1/4

So simplify the fraction and if it is equal to or more than a whole number you know, but if it is less than a whole number then you know it is less.

Hopefully this helped :)

The differential equation is equivalent to

                           \(\frac{dy}{dx} -\frac{3x(1-y)}{x^{2} +1}\)

If y denotes the fraction of the population who have heard the rumor, then 1 −y represents the fraction of the population who haven’t heard the rumor.

The rate of spread of the rumor (y'(t)) being proportional to the product of the fraction y of the population who have heard the rumor and the fraction who have not heard the rumor can then be rewritten as:

\(\frac{dy}{dt} =ky(1-y)\)

for some positive constant k. This is a separable differential equation, so to solve it we separate the variables

\(\frac{dy}{y(1-y)} =kdt\)

and integrate

\(\int\ \frac{dy}{y(1-y)} =\int k dt < = > ln |\frac{y}{1-y} |=kt+c\)

Exponentiating, we get

\(|\frac{y}{1-y}|=e^{kt+c}\)

Denoting ec by A, and taking into account that y ∈ (0, 1) we get

\(\frac{y}1-{y} =Ae^{kt} =\frac{Ae^{kt} }{1}\)

Adding the numerators to the denominators in the above equality of fractions we obtain

\(y=\frac{y}{(1-y)+y} =\frac{Ae^{kt} }{1+Ae^{kt} }\)

The Initial value:

\((x^{2}+1) \frac{dy}{dx} +3y(y-1)=0,y(0)=1\)

The differential equation is equal to

\(\frac{dy}{dx} -\frac{3x(1-y)}{x^2+1}\)

the initial condition of our problem is y(0) = 1, the solution must be y ≡ 1

The differential equation is equivalent to

\(\frac{dy}{dx} +\frac{3x}{x^2+1} y=\frac{3x}{x^2+1}\)

which is a linear equation, with P(x) = Q(x) =\(\frac{3x}{x^2+1}\) we have

\(\int P(x)=\frac{3}{2}\int \frac{2x}{x^2+1} dx=\frac{3}{2} ln(x^2+1)\)

It follows that the integrating factor I(x) is then

\(I(x)e^{\int P(x)dx} =e^{\frac{3}{2} ln(x^2+1)} =(x^2+1)^{\frac{3}{2} }\)

The general technique for solving linear differential equations yields

\(yI(x)=\int Q(x)I(x)dx=\int \frac{3x}{x^2+1} (x^2+1)^{\frac{3}{2} } \\\\=\int 3x(x^2+1)^{\frac{1}{2} } =(x^2+1)^{\frac{3}{2} } +C\)

Dividing by I(x) we get

\(y=1+\frac{C}{(x^2+1)^{\frac{3}{2} } }\)

The initial condition y(0) = 1 yields 1 = 1 + c, i.e. c = 0. Therefore y ≡ 1.

The differential equation is separable. We get this by separating the variables

\(\frac{dy}{y-1} -\frac{-3x}{x^2+1}\)

Integrating, we obtain

\(ln|y-1|=\frac{-3}{2} ln(x^2+1)+c\)

which yields by exponentiation

\(|y-1|=\frac{e^c}{(X^2+1)^\frac{3}{2} }\)

substituting ec by a constant A, and allowing A to also be negative or 0, we get

\(y-1=\frac{A}{(x^2+1)^\frac{3}{2} }\)

The initial condition y(0) = 1 implies that 1 − 1 = A/1 = A, hence A = 0 and          y ≡ 1

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Answer:

29.12%

Step-by-step explanation:

Given that :

A = 49

B = 50

C = 38

D = 60

E = 75

Total = (49 + 50 + 38 + 60 + 75) = 272

Pie chart % for each :

A = (49 / 272) * 360 = 64.85

B = (50 / 272) * 360 = 66.18

C = (38 / 272) * 360 = 50.29

D = (60 / 272) * 360 = 79.41

E = (75 / 272) * 360 = 99.26

Difference between C and D

(79.41 - 50.29) = 29.12%