Guys help me with that question I have a quiz after today and please explain what you did.

Answer:

its the first one

Step-by-step explanation:

use desmos, its great for graphing this stuff

Answer:

slope = - \(\frac{13}{28}\)

Step-by-step explanation:

calculate the slope m using the slope formula

m = \(\frac{y_{2}-y_{1} }{x_{2}-x_{1} }\)

with (x₁, y₁ ) = (17, - 6 ) and (x₂, y₂ ) = (- 11, 7 )

m = \(\frac{7-(-6)}{-11-17}\) = \(\frac{7+6}{-28}\) = - \(\frac{13}{28}\)

We are given that IQ scores are normally distributed with mean μ = 100 and standard deviation σ = 15. We want to find the probability of a random person on the street having an IQ score of less than 96.

To do this, we need to standardize the IQ score using the z-score formula:

z = (x - μ) / σ

where x is the IQ score we're interested in, μ is the mean IQ score, and σ is the standard deviation of IQ scores.

Plugging in the given values, we get:

z = (96 - 100) / 15 = -0.267

Now, we look up the probability of getting a z-score less than -0.267 in a standard normal distribution table or using a calculator. The probability is approximately 0.3944.

Therefore, the probability of a random person on the street having an IQ score of less than 96 is 0.3944 (rounded to 4 decimal places).

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Answer:

12s - 16t

Step-by-step explanation:

2(3s + t) + 2(3s - 9t)

6s + 2t + 6s - 18t

12s + 2t - 18t

12s - 16t

Answer:Perimeter of the rectangle =(12s -16t)centimeters.

Step-by-step explanation:

The perimeter of a rectangle is given as 2(l+w)

Given that  width of the  rectangle=(3s+t)centimeters. and

Length of the  rectangle=(3s-9t)centimeters.

Solving we have

Perimeter= 2(l+w)

Perimeter=2(3s+t +3s-9t)

Perimeter=2(3s+3s -9t+t)

Perimeter=2(6s-8t)

Perimeter=(12s -16t)centimeters.

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Answer:

\(\frac{1}{100}\)  

I hope this helps!

Answer:

To write .010 as a fraction you have to write .010 as numerator and put 1 as the denominator. Now you multiply numerator and denominator by 10 as long as you get in numerator the whole number.

.010 = .010/1 = 0.1/10 = 1/100

And finally we have:

.010 as a fraction equals 1/100

hope this helps:)

D. {s, t, a, i, c}

The sample space must contain outcomes which are possible to obtain in a probability. Since the word 'statistics' doesn't contain letter e(A), r(B) and l(C) thus Option D is the correct answer.

Hope this helps :)

Answer:

filthy Frank always told ppl who had anime pic where weeaboos

Answer:

Step-by-step explanation:

the perimeter of the semi-circle would be the diameter plus the circumference of half of the circle.  

They want to know the perimeter of a square using the diameter of the sem-circle as ONE side, so the perimeter of the square would be 4 times the ONE side.

We should recall:

diameter = 2 times the radius     circumference of a cirlce = 2π r

How do we find the diameter of the of the semi circle?

The perimeter of the semi circle is given as 108 cm

Perimeter of the semicirle =    2r + π r         diameter plus semi circumference

                                  108   =   r ( 2 + π)           factor out the r and solve for r

                     108 / (2 + π)   =   r                       divide both sides by ( 2 + r)

Now we know r, the perimeter of the squqre is 4 times 2r  or  8r

           perimeter of square = 8  [ 108 / (2 + π) ]               π  I used 3.14

                                             =  864 / 5.14

                                             =   168.1 cm       I got rounded to nearest tenth    

When I re-checked by work I found a few math,  logic and calculation errors.  Please re-check my answer for any more mistakes.

The sides are 20 and 21 in   right triangle.

What defines a right triangle?

The term "right triangle" refers to a triangle with an interior angle of 90 degrees.

                 The hypotenuse, the side of the right triangle that is opposite the right angle and is also its longest side, and the height and base are the two arms of the right angle.The term "right triangle" refers to a triangle with an interior angle of 90 degrees. The hypotenuse, the side of the right triangle that is opposite the right angle and is also its longest side, and the height and base are the two arms of the right angle.

29² = x²  + (x+1)²

x²+ x² +2x +1 = 841

2x² +2x -840 =0

x² + x -420 =0

(x+21)(x-20)=0

x=20

the sides are 20 and 21

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Answer:

First one is 204 the second one is 207

Step-by-step explanation:

Mutliply width* length

Answer:

x = -2

Step-by-step explanation:

Isolate the variable, x. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS.

PEMDAS is the order of operations, and stands for:

Parenthesis

Exponents (& Roots)

Multiplications

Divisions

Additions

Subtraction

~

First, subtract 7 from both sides of the equation:

6x + 7 = -5

6x + 7 (-7) = -5 (-7)

6x = -5 - 7

6x = -12

Next, isolate the variable, x, by dividing 6 from both sides of the equation:

(6x)/6 = (-12)/6

x = -12/6

x = -2

x = -2 is your answer.

~

A spontaneous reaction can occur even if the calculated ΔH is positive.

When a reaction occurs spontaneously, it means that the overall change in Gibbs free energy (ΔG) is negative. ΔG represents the energy available to do useful work, and it's calculated as follows:

ΔG = ΔH - TΔS

Where T is the temperature in Kelvin. A negative ΔG indicates that the reaction is thermodynamically favorable, while a positive ΔG means that the reaction is not favorable.

To answer this question, let's rearrange the equation for ΔG:

ΔG = ΔH - TΔS

ΔH = ΔG + TΔS

Since ΔG is negative for a spontaneous reaction, we can rewrite the equation as:

|ΔH| = -ΔG + TΔS

From this equation, we can see that if ΔH is positive, then -ΔG must be greater than TΔS. Since -ΔG is negative, then TΔS must be negative as well.

In other words, a spontaneous reaction can still occur even if it absorbs heat (ΔH is positive) as long as the increase in disorder (ΔS) is negative enough to overcome the positive ΔH.

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Yes, they can use the walkie-talkies to talk to each other.

The distance between them is given as 28.2 meters.

The horizontal and vertical distances should be considered when calculating the distance between their apartments using the three-dimensional form of the Pythagorean theorem.

This comes out as \(\sqrt((18^2 + 19^2 + 7^2))\), which equals \(\sqrt(798)\) square root meters, or, to the nearest tenth, 28.2 meters.

Since this distance is less than the 35-meter range of the walkie-talkies, communication should be possible between the two apartments.

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From the given inequality 56C + 64R < 9000, we know that the total amount of fuel the airplane can consume in C minutes of clear sky flying and R minutes of rain cloud flying combined is less than 9000 gallons.

Let's assume that the airplane consumes fuel at a rate of F gallons per minute while flying through clear skies.

Therefore, in C minutes of clear sky flying, the airplane consumes a total of CF gallons of fuel. Similarly, in R minutes of rain cloud flying, the airplane consumes a total of 64R gallons of fuel.

The total amount of fuel consumed by the airplane in C minutes of clear sky flying and R minutes of rain cloud flying is given by:

Total fuel consumed = CF + 64R

Since the airplane can't consume all its fuel during this time, we have:

CF + 64R < 9000/56

Simplifying the above inequality:

CF + 64R < 161.54

Now we know that the airplane can fly for C minutes through clear skies and R minutes through rain clouds without consuming all of its fuel. So, we can write:

CF + 64R = F(C + R)

Let's substitute this in the inequality we derived above:

F(C + R) < 161.54

Dividing both sides by C + R:

F < 161.54 / (C + R)

We don't have enough information to solve for F, but we do know that it must be less than 161.54 / (C + R).

To find out how much fuel the airplane has before takeoff, we need to know the total amount of fuel it can consume. We can find this by assuming that the airplane can fly for T minutes before running out of fuel, where T is the total flight time.

Let's assume that the airplane consumes fuel at a rate of F1 gallons per minute during the entire flight. Then, the total amount of fuel consumed during the flight is:

F1T

If we assume that the airplane flies only through clear skies during the entire flight, then we can use the given information to find out how much fuel it has before takeoff:

56C < F1T

Simplifying the above inequality:

C < F1T/56

Again, we don't have enough information to solve for F1 or T, so we can't find the exact amount of fuel the airplane has before takeoff.

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The graph that  represents the function f(x)  = |x − 1| − 3 is:

Graph B

To find out which graph can represent the given function f(x) = |x − 1| − 3, we need to look at each of the functions individually to deduce that.

The key to this is the point (1,-3) That point must be found first. C is incorrect because you are using 3 not - 3 which does not change (as C has changed it) through out the problem.

A is using (-1,-3) which makes it wrong. Also the equation is y = -abs(x-1) - 3 which is also a mistake. The given graph points upwards not downwards.

D has it's minimum point at (-1,-3) which is not correct.

We are left with b which opens upwards (correct) has it's min at (1,-3) [also correct] so the answer is

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The present age of Earl is 12 years, Robin is 24 years and Adam is 4 years old.

Let us consider the present age of Earl to be x years.

According to the given question, the present age of Robin is twice that of Earl = 2x

And since it is given that Adam is 8 years younger than Earl, then his age

= x - 8

After 6 years, the age of Earl will be x + 6

Robin's age  will be = 2x + 6

Adam's age will be = x - 8 + 6 = x - 2

According to the given question, Robin's age will be thrice the age of Adam.

Hence, 2x + 6 = 3 (x - 2)

⇒ 2x + 6 = 3x - 6     ⇒ 6 + 6 = 3x - 2x     ⇒ 12 = x

Thus, the present age of Earl is 12 years,

Robin's age = 2x = 2 x 12 = 24 years

Adam's age = x - 8 = 12 - 8 = 4 years

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The future value of $2000 at a 3% interest rate compounded annually for 3 years would be $2185.40.

The future value of $2000 at a 3% interest rate compounded annually for 3 years can be calculated using the formula:

FV = PV * (1 + r)ⁿ

where PV is the present value, r is the annual interest rate, and n is the number of compounding periods.

In this case:

FV = $2000 * (1 + 0.03)³

FV = $2000 * 1.03³

FV = $2000 * 1.0927

FV = $2185.40

So, the future value of $2000 at a 3% interest rate compounded annually for 3 years would be $2185.40.

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After considering the given data we conclude that the solution on the interval [0, 0.2] is 1.2620

To use the Euler Method to approximate the solution on the interval [0, 0.2] with step size h = 0.1 to four decimal places, we can apply the following steps:
Describe the differential equation and initial condition: \(y' = f(x, y) = 2x + y\), y(0) = 1.
Elaborating the step size h = 0.1 and the number of steps \(n = (0.2 - 0) / h = 2.\)
Initialize the variables: \(x_{0} = 0, y_{0} = 1.\)
For i = 0 to n-1, do the following:
a. Placing the slope at (xi, yi) using f(x, y) = 2x + y: \(k_{1} = f(xi, yi) = 2xi + yi\).
b. Placing the slope at \((xi + h, yi + hk_{1} )\) using \(f(x, y) = 2x + y: k_{2} = f(xi + h, yi + hk_{1} ) = 2(xi + h) + (yi + hk_{1} ).\)
c. Placing the next value of y using the  Euler Method formula: \(yi+1 = yi + h/2(k_{1} + k_{2} ).\)
d. Placing the next value of x: \(xi+1 = xi + h.\)
Rounding the final value of y to four decimal places.
Applying the above steps, we get:
\(x_{0} = 0, y_{0} = 1\)
n = 2
h = 0.1
For i = 0:
\(k1 = f(x_{0} , y_{0} ) = 2(0) + 1 = 1\)
\(k_{2} = f(x_{0} + h, y_{0} + hk_{1} ) = 2(0.1) + (1 + 0.1(1)) = 1.3\)
\(y_{1} = y_{0} + h/2(k_{1} + k_{2} ) = 1 + 0.1/2(1 + 1.3) = 1.115\)
For i = 1:
\(k_{1} = f(x_{1} , y_{1} ) = 2(0.1) + 1.115 = 1.33\)
\(k_{2} = f(x_{1} + h, y_{1} + hk_{1} ) = 2(0.2) + (1.115 + 0.1(1.33)) = 1.7965\)
\(y_{2} = y_{1} + h/2(k_{1} + k_{2}) = 1.115 + 0.1/2(1.33 + 1.7965) = 1.262\)
Hence, the approximate solution of the differential equation \(y' = 2x + y\)on the interval [0, 0.2] with step size h = 0.1 applying  Euler Method is y(0.2) ≈ 1.2620 (rounded to four decimal places).
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The test statistic for H₀: µ₁ = µ₂ and

Hₐ: µ₁ ≠ µ₂ is t = 76.5 - 78.8√ ((7.4)²/230 + (5.6)²/185). So, the correct choice for answer is option (a).

The test statistic for a two-sample is calculated by taking the difference in the two sample means and dividing by either the pooled or unpooled estimated standard error. We have a sample of first- year high school students were randomly put into either traditional math classes or math. For first sample

Sample size, n₁ = 230

sample mean, M₁ = 76.5

Standard deviations, s₁ = 7.4

For other sample,

Sample size,n₂ = 185

Sample mean, M₂ = 78.8

Standard deviations, s₂ = 5.6

Let the population means for sample first and second be µ₁ and µ₂ respectively.

The Hypothesis testing for comparison of population meas of both samples. The null and alternative hypothesis are

H₀: µ₁ = µ₂ and

Hₐ: µ₁ ≠ µ₂

Pooled standard error = √(s₁²/n₁ + s₂²/

n₂)

= √((7.4)²/230 + (5.6)²/185)

Using the test statistic for a two-sample,

t = (( M₁ - M₂ ) -( µ₁ - µ₂))/√(s₁²/n₁ + s₂²/

n₂)

= ((76.5 - 78.8) - ( µ₁- µ₂))/√((7.4)²/230 + (5.6)²/185)

t = (76.5 - 78.8)√ ((7.4)²/230 + (5.6)²/185) ( since, µ₁- µ₂ = 0)

Hence required test statistic value is option(a). There is sufficient evidence to claim that the difference in the test results zero.

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Using a trigonometric relation we will see that:

1) DE = 33.86

2) R = 20.6°.

1) We want to get DE which is the adjacent cathetus to the given angle.

Then we can use the trigonometric relation:

tan(a) = (opposite cathetus)/(adjacent cathetus).

Here we have:

a = 21°

opposite cathetus = 13

adjacent cathetus = DE.

Replacing that we get:

DE = 13/tan(21°) = 33.86

2) Now we want to get an angle.

This time we have:

Using the same trigonometric relation we get:

tan(R) = 9/24

Using the inverse tangent function:

R = Atan(9/24) = 20.6°.

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Answer:

Step-by-step explanation:

3x^2y

3(2)^2(9)

6^18= 101 559 956 668 416

Answer:

387,420,489 is the answer to the monomial.

Step-by-step explanation:

3x^2y = 3(1)^2(9) when the variables are replaced.

3(1) = 3

2(9) = 18

3^18 = 3 x 3 x 3 x 3 x 3 x 3 x 3 x 3 x 3 x 3 x 3 x 3 x 3 x 3 x 3 x 3 x 3 x 3

3 x 3 x 3 x 3 x 3 x 3 x 3 x 3 x 3 x 3 x 3 x 3 x 3 x 3 x 3 x 3 x 3 x 3 = 387,420,489

Therefore, 387,420,489 is the answer to the monomial.

Hope this helps! :D

The probability density function (PDF) for the lifetime of an electronic tube is f(x) = x ˣ exp(-x), x ≥ 0.

To determine the probability density function (PDF) for the lifetime of an electronic tube, we are given the function:

To ensure that the PDF integrates to 1 over the entire range, we need to determine the appropriate normalization constant. We can achieve this by integrating the function over its entire range and setting it equal to 1:

To solve this integral, we can integrate by parts:

Then du = dx, v = -exp(-x)

Therefore, the PDF is normalized, and the probability density function for the lifetime of an electronic tube is given by:

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The present value of the annuity at the end of year 7 is approximately $47,069.08.

To calculate the present value of an ordinary annuity, we can use the formula:

PV = PMT * [(1 - (1 + r)⁻ⁿ) / r],

where PV is the present value, PMT is the annual payment, r is the interest rate per period, and n is the number of periods.

In this case, the annual payment is $4,500, the interest rate is 8%, and the number of periods is 16. However, the payments start at the end of year 8 and continue until the end of year 23, which means there is a delay of 7 years.

Using the formula, the present value at the end of year 7 can be calculated as:

PV = $4,500 * [(1 - (1 + 0.08)⁻¹⁶) / 0.08] = $47,069.08.

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The measure of angle a is 15 degrees and this can be determined by using the properties of the isosceles triangle.

In geometry, interior angles are formed in two ways. One is inside a polygon, and the other is when parallel lines cut by a transversal. Angles are categorized into different types based on their measurements.

Given:

The following steps can be used in order to determine the measure of angle a:

Step 1 - According to the given data, it can be concluded that triangle PQR and triangle PSR are isosceles triangles.

Step 2 - Apply the sum of interior angle property on triangle PQR.

\(\angle\text{Q}+\angle\text{P}+\angle\text{R}=180\)

\(\angle\text{Q}+2\angle\text{R}=180\)

\(2\angle\text{R}=180-60\)

\(\angle\text{R}=60^\circ\)

Step 3 - Now, apply the sum of interior angle property on triangle PSR.

\(\angle\text{P}+\angle\text{S}+\angle\text{R}=180\)

\(\angle\text{S}+2\angle\text{R}=180\)

\(2\angle\text{R}=180-90\)

\(\angle\text{R}=45^\circ\)

Step 4 - Now, the measure of angle a is calculated as:

\(\angle\text{a}=60-45\)

\(\angle\text{a}=15\)

The measure of angle a is 15 degrees.

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Answer:

Last Option

All the real numbers greater than or equal to -3

Step-by-step explanation:

Range is the set of y-values that can be inputted into function f(x).

We see that our y-values range from -3 to infinity. Since -3 is closed dot, we include it in our range:

[-3, ∞) or y ≥ -3

\(\begin{array}{ccll} miles&seconds\\ \cline{1-2} 2\times 10^{5} & 1\\ 9\times 10^{7}& x \end{array} \implies \cfrac{2\times 10^{5}}{9\times 10^{7}}~~=~~\cfrac{1}{x}\implies (2\times 10^{5})x=9\times 10^{7} \\\\\\ x=\cfrac{9\times 10^{7}}{2\times 10^{5}}\implies x=\cfrac{9}{2}\times\cfrac{ 10^{7}}{10^{5}}\implies x=4.5\times 10^{7-5}\implies x=4.5\times 10^{2}\)

The half-life of radon-222 is approximately 3.84 days. We can find it in the following manner.

The half-life of a radioactive substance is the amount of time it takes for half of the initial amount of the substance to decay.

We can use the fact that the sample of radon-222 has decayed to 58% of its original amount after 3 days to determine its half-life.

Let N0 be the original amount of radon-222 and N(t) be the amount remaining after time t. We know that:

N(3) = 0.58N₀

We can use the formula for radioactive decay:

\(N(t) = N₀ * (1/2)^(t/h)\)

here h is the half-life.

Substituting in N(3) and simplifying:

\(0.58N₀ = N₀ * (1/2)^(3/h)\)

0.58 = (1/2)^(3/h)

Taking the natural logarithm of both sides:

\(ln(0.58) = ln[(1/2)^(3/h)]\)

ln(0.58) = (3/h) * ln(1/2)

h = -3 / ln(1/2) * ln(0.58)

Using a calculator, we get:

h ≈ 3.84 days

Therefore, the half-life of radon-222 is approximately 3.84 days.

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Answer:

9 3/8.

Step-by-step explanation:

multiply 3 3/4 times 2 1/2.