Answer:
please send the pic again it is not clear
Given the functions f(x)=(1/x-3)+1 and g(x) = (1/1+4)+3
Which statement describes the transformation of the graph of function f onto the graph of function g?
O The graph shifts 2 units right and 7 units down.
O The graph shifts 7 units left and 2 units up.
O
e graph shifts 7 units right and 2 units down.
O The graph shifts 2 units left and 7 units up.
The statement that describes the transformation of the graph of function f onto the graph of function g is: The graph shifts 2 units right and 7 units down.
To determine the transformation of the graph of function f onto the graph of function g, we compare the two functions f(x) and g(x) and observe the changes in the equations.
The function f(x) = (1/x - 3) + 1 represents a reciprocal function that is shifted vertically 1 unit up and horizontally 3 units to the right. The reciprocal function is reflected about the line y = x.
The function g(x) = (1/(1 + 4)) + 3 simplifies to g(x) = 4 + 3 = 7, which is a constant function representing a horizontal line at y = 7.
By comparing the equations, we can see that the transformation from f(x) to g(x) involves the following changes:
The term 1/x in f(x) is replaced by the constant 1/(1 + 4) in g(x), resulting in a vertical shift of 7 units up.
The term -3 in f(x) is replaced by 3 in g(x), resulting in a vertical shift of 3 units up.
The +1 in f(x) is replaced by +3 in g(x), resulting in an additional vertical shift of 2 units up.
Therefore, the overall transformation is a shift of 2 units to the right and 7 units down.
Hence, the correct statement is: The graph shifts 2 units right and 7 units down.
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HELP, END OF SCHOOL YEAR, 30 POINTS Unit 9 lesson 15 astronomy unit test answers I ONLY HAVE ONE MORE DAY
1 As evidence supporting the Big Bang theory, what does the redshift of light from galaxies indicate?
The universe is mainly hydrogen.
The universe is 13.8 billion years old.
The universe is cooling off.
The universe is expanding.
2 Which evidence supports the idea that Cosmic Microwave Background radiation is a remnant of the Big Bang?(1 point)
Its temperature is uniform.
Its mass fluctuates greatly.
Its temperature fluctuates greatly.
Its mass is uniform.
3 Which of these items provide evidence supporting the Big Bang theory? Select the two correct items.(1 point)
rate of star formation
composition of matter in the universe
sizes and shapes of distant galaxies
cosmic background radiation
4 How does the change in the temperature of the universe provide evidence for universe expansion that supports the Big Bang Theory?(1 point)
The universe is warming which, according to the Big Bang Theory, is expected to happen as the cosmos disperses.
The universe is warming which, according to the Big Bang Theory, is expected to happen as the cosmos accumulates.
The universe is cooling which, according to the Big Bang Theory, is expected to happen as the cosmos accumulates.
The universe is cooling which, according to the Big Bang Theory, is expected to happen as the cosmos disperses.
5 How does weak background radiation coming from every direction in the sky support the Big Bang Theory?(1 point)
It provides evidence of the universe's increasing mass.
It provides evidence of universe expansion.
It provides evidence of universe contraction.
It provides evidence of the universe's decreasing mass.
6 Which statements describe ways that nuclear fission is different than nuclear fusion? Select the two correct answers.(1 point)
Nuclear fission is used to produce electricity at nuclear power plants.
Nuclear fission involves one large atom splitting into two smaller atoms.
Nuclear fission takes place in the nucleus of an atom.
Nuclear fission releases a huge amount of energy.
7 Blueshift is observed when(1 point)
a distant luminous object travels rapidly away from an observer.
a distant luminous object travels rapidly towards an observer.
a luminous object travels alongside an observer.
a luminous object is stationary compared to an observer.
8 Which statements about nuclear fusion are false? Select the two correct answers.(1 point)
The fuel for nuclear fusion is often uranium.
Nuclear fusion is used to generate electricity at nuclear power plants.
Nuclear fusion releases large amounts of energy.
Nuclear fusion takes place in the cores of stars.
9 Which of the following statements provide evidence to support the big bang theory? Select the two correct answers.
The ratios of hydrogen and helium in the universe match those of the early universe.
The universe began as a very high density singularity.
Dark matter makes up the majority of matter in the galaxy.
Small spiral galaxies become larger elliptical galaxies when they collide.
10 Which represents a correct match between ideas related to the formation of the universe? Select the two correct answers.(1 point)
accelerating expansion — dark energy
structures forming in the early universe — dark matter
greatest percent of mass of universe — dark matter
glowing nebulae — dark energy
11 How is dark energy related to the theory of the Big Bang?(1 point)
It causes the expansion of the universe to accelerate.
It causes the universe to expand.
It seeded the formation of galaxies and star clusters.
It causes the spinning of galaxies.
Answer:
1. The Universe is Expanding
2. It’s temperature is it’s uniform
3. Cosmic background radiation
4. I will give a hint for this one, since I don’t know, the hint is the universe is cooling.
5. It provides evidence of universe expansion.
6. Sorry I don’t know the rest
Explanation:
The universe is the collection of every item in space and time as well as the contents of those items
The correct options are as follows;
1. The universe is expanding
2. Its temperature is uniform
3. Composition of matter in the universe, cosmic background radiation
4. The universe is cooling which, according to the Big Bang Theory, is expected to happen as the cosmos disperses
5. It provides evidence of universe expansion
6. Nuclear fission involves one large atom splitting into two smaller atoms
Nuclear fission takes place in the nucleus of an atom
7. A distant object travels rapidly towards an observer
8. The fuel in nuclear fusion is often uranium
Nuclear fusion is used to generate electricity at nuclear power plants
9. The universe began as a very high density singularity
Dark matter makes up majority of the universe
10. Acceleration expansion — Dark energy
Structure forming in the early universe — Dark matter
11. It causes the expansion of the universe to accelerate
The reasons for selecting the above options are as follows;
1. The universe is expanding
The redshift of light from galaxies indicates that that are moving away
2. Its temperature is uniform
The uniform temperature of the microwave background suggest a common source
3. Composition of matter in the universe, cosmic background radiation
The matter present in the universe are characteristically similar in their origins
The cosmic background provides evidence of the existence of a singularity
4. The universe is cooling which, according to the Big Bang Theory, is expected to happen as the cosmos disperses
Based on the Big Bang Theory, the temperature of the universe is reducing as the universe expands, compared to the initial temperature
5. It provides evidence of universe expansion
The background radiation coming from a single source as the rest of the universe is expected to spread throughout the universe
6. Nuclear fission involves one large atom splitting into two smaller atoms
Nuclear fission takes place in the nucleus of an atom
Nuclear fusion involves the joining of small atoms to form a larger atom
7. A distant object travels rapidly towards an observer
The redshift is the opposite, indicating that the object is moving further away
8. The fuel in nuclear fusion is often uranium
Nuclear fusion is used to generate electricity at nuclear power plants
Nuclear fusion usually consists of joining small atoms together. It has not been used for commercial energy production
9. The universe began as a very high density singularity
According to the Big Bang Theory, the universe started from the dense, high temperature singularity
Dark matter makes up majority of the universe
10. Acceleration expansion — Dark energy
Dark energy causes expansion
Structure forming in the early universe — Dark matter
Dark matter is instrumental to the formation of structures in the universe
11. It causes the expansion of the universe to accelerate
Dark energy is seen as the cause of the accelerating expansion of the universe
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In the United States, household electric power is provided at a frequency of 60 HzHz, so electromagnetic radiation at that frequency is of particular interest. On the basis of the ICNIRP guidelines, what is the maximum intensity of an electromagnetic wave at this frequency to which the general public should be exposed
Answer:
the maximum intensity of an electromagnetic wave at the given frequency is 45 kW/m²
Explanation:
Given the data in the question;
To determine the maximum intensity of an electromagnetic wave, we use the formula;
\(I\) = \(\frac{1}{2}\)ε₀cE\(_{max\)²
where ε₀ is permittivity of free space ( 8.85 × 10⁻¹² C²/N.m² )
c is the speed of light ( 3 × 10⁸ m/s )
E\(_{max\) is the maximum magnitude of the electric field
first we calculate the maximum magnitude of the electric field ( E\(_{max\) )
E\(_{max\) = 350/f kV/m
given that frequency of 60 Hz, we substitute
E\(_{max\) = 350/60 kV/m
E\(_{max\) = 5.83333 kV/m
E\(_{max\) = 5.83333 kV/m × ( \(\frac{1000 V/m}{1 kV/m}\) )
E\(_{max\) = 5833.33 N/C
so we substitute all our values into the formula for intensity of an electromagnetic wave;
\(I\) = \(\frac{1}{2}\)ε₀cE\(_{max\)²
\(I\) = \(\frac{1}{2}\) × ( 8.85 × 10⁻¹² C²/N.m² ) × ( 3 × 10⁸ m/s ) × ( 5833.33 N/C )²
\(I\) = 45 × 10³ W/m²
\(I\) = 45 × 10³ W/m² × ( \(\frac{1 kW/m^2}{10^3W/m^2}\) )
\(I\) = 45 kW/m²
Therefore, the maximum intensity of an electromagnetic wave at the given frequency is 45 kW/m²
The generator in a purely inductive AC circuit has an angular frequency of 363 rad/s. If the maximum voltage is 169 V and the inductance is 0.0937 H, what is the rms current in the circuit
Answer:
The rms current in the circuit is 3.513 A
Explanation:
Given;
angular frequency of the inductor, ω = 363 rad/s
maximum voltage of the inductive AC, V₀ = 169 V
Inductance of the inductor, L = 0.0937 H
Inductive reactance is given by;
\(X_L = 2\pi f L= \omega L\)
\(X_L = 363 *0.0937\\\\X_L = 34.0131 \ ohms\)
The rms voltage is given by;
\(V_{rms} = \frac{V_o}{\sqrt{2} } \\\\V_{rms} =\frac{169}{\sqrt{2} } \\\\V_{rms} = 119.5 \ V\)
The rms current in the circuit is given by;
\(I_{rms} = \frac{V_{rms}}{X_L} \\\\I_{rms} = \frac{119.5}{34.0131} \\\\I_{rms} = 3.513 \ A\)
Therefore, the rms current in the circuit is 3.513 A
halp me please i will give brainly
Answer: It should be the 3rd option down!
Explanation:
Answer: C
Explanation:
Explain how a transistor behaves as a switch
Answer:
With a zero signal applied to the Base of the transistor it turns “OFF” acting like an open switch and zero collector current flows. With a positive signal applied to the Base of the transistor it turns “ON” acting like a closed switch and maximum circuit current flows through the device.
Explanation:
please give me brainlist and follow
A transistor is a semiconductor device that can function as an electronic switch, controlling the flow of current between its two main terminals.
It has three terminals: the emitter, the base, and the collector. In the context of a common bipolar junction transistor (BJT), here's how it behaves as a switch:
BJT Basics:
A BJT comes in two types: NPN (Negative-Positive-Negative) and PNP (Positive-Negative-Positive). For simplicity, let's consider the NPN type. In an NPN transistor, the emitter is made up of an N-type semiconductor, the base is a P-type semiconductor, and the collector is an N-type semiconductor.
Operating Regions:
A transistor has three operating regions: cutoff, active, and saturation.
Cutoff Region: When no current flows from the collector to the emitter. The transistor is effectively "off" in this state.
Active Region: When the transistor is operating as an amplifier, allowing a controlled current flow between the collector and emitter based on the current flowing into the base terminal.
Saturation Region: When the transistor is fully turned on, and maximum current flows from the collector to the emitter. The transistor is effectively "on" in this state.
Switching Operation:
To use a transistor as a switch, we configure it to work in either the cutoff or saturation region. The active region is avoided because it allows variable current flow, which is not desired for a switch.
a. NPN Transistor as a Switch:
To turn the NPN transistor "ON" (saturation), a small current is passed from the base to the emitter (IB). This current allows a larger current to flow from the collector to the emitter (IC).
To turn the NPN transistor "OFF" (cutoff), no current is allowed to flow into the base terminal (IB = 0). Consequently, no significant current flows from the collector to the emitter, and the transistor behaves as an open switch.
b. PNP Transistor as a Switch:
The PNP transistor works similarly but in the opposite direction. To turn it "ON" (saturation), a small current flows from the emitter to the base (IB). This enables a larger current to flow from the emitter to the collector (IC).
To turn the PNP transistor "OFF" (cutoff), the current flowing into the emitter is restricted (IB = 0), causing the transistor to behave as an open switch.
Applications:
Transistors used as switches find applications in digital logic circuits, microcontrollers, and other electronic devices. They play a crucial role in controlling the flow of current through various components, enabling or disabling functionalities as needed.
It's essential to note that when using transistors as switches, care should be taken to ensure that the base current (IB) and collector current (IC) remain within safe operating limits to prevent damage to the transistor and the circuit. Proper resistors or other current-limiting mechanisms are often employed to control these currents.
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Calculate Time
d
12. A vehicle drives a distance of 26000 m at a speed of 65m/s, calculate the time taken for
this journey.
13. A train travels at a speed of 16 m/s and travel a distance of 3200 m, calculate the time it
takes the train to complete this journey.
urs 14. Calculate the time it takes to travel a distance of 672 km at a speed of 96 km/h.
15. A beetle travels at a speed of 0.09 m/s, it travels a distance of 1.08 m before it is caught
in a jar. Calculate the time taken for the beetle to run.
16. Carlisle is a distance of 35 miles away from Lockerbie. If I travelled at a constant speed
5147
deudate the time takon for this journey
12. The time taken for the journey is 400 s
13. The time taken for the train is 200 s
14. The time taken is 7 h
15. The time taken for the beetle is 12 s
16. The time taken for the journey is 0.0068 h
How do i determine the time taken?The time taken in each case as given by the question can be obtain as follow:
12. The time taken for the journey
Distance traveled = 26000 mSpeed = 65 m/s Time taken =?Time taken = Distance / Speed
Time taken = 26000 / 65
Time taken = 400 s
13. The time taken for the train
Distance traveled = 3200 mSpeed = 16 m/s Time taken =?Time taken = Distance / Speed
Time taken = 3200 / 16
Time taken = 200 s
14. The time taken to travel
Distance traveled = 672 kmSpeed = 96 Km/h Time taken =?Time taken = Distance / Speed
Time taken = 672 / 96
Time taken = 7 h
15. The time taken for the beetle
Distance traveled = 1.08 mSpeed = 0.09 m/s Time taken =?Time taken = Distance / Speed
Time taken = 1.08 / 0.09
Time taken = 12 s
16. The time taken for the journey
Distance traveled = 35 milesSpeed = 5147 mile per hourTime taken =?Time taken = Distance / Speed
Time taken = 35 / 5147
Time taken = 0.0068 h
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14. The liquid in the tube has a density of 13,600 kilograms per cubicmeter. The atmospheric pressure is 1.013 x 10^5 newtons persquare meter. The pressure P is most nearly(a) 1.05 x 10^5 pa(b) 1.25 x 10^5 Pa(c) 1.33 x 10^5 pa(d) 1.47 x 10^5 Pa
Given,
The density of the liquid,ρ=13600 kg/m^3
The atmospheric pressure, P₁=1.013×10⁵
The difference between the height of the liquid in the column, h=0.240 m
The pressure P is given by,
\(P=P_1+g\rho h\)Where g is the acceleration due to gravity.
On substituting the known values,
\(P=1.013\times10^5+9.8\times13600\times0.240=1.33\times10^5\text{ Pa}\)Hence pressure, P=1.33×10⁵ Pa
1.
Which of the follow
following
cannot be zero?
A. Distance B. Displacement
" Velocity D. Acceleration
C.
A vibrating object produces periodic waves with a wavelength of 53 cm and a frequency of 15 Hz. How fast do these waves move away from the object?
Answer:
v = 7.95 m/s
Explanation:
Given that,
Wavelength of a wave, \(\lambda=53\ cm=0.53\ m\)
Frequency of a wave, f = 15 Hz
We need to find the speed of the wave. The speed of a wave is given by :
\(v=f\lambda\\\\v=15\ Hz\times 0.53\ m\\\\v=7.95\ m/s\)
So, the wave move with a speed of 7.95 m/s.
Compare and contrast the solar eclipse seen in this video to a lunar eclipse.
Answer: sadly, I can’t see the video. However, a lunar eclipse happens when the moon is hidden by the earth’s shadow. A solar eclipse occurs when the moon casts a shadow on the earth.
Explanation: I’m not completely sure if this is what you were looking for, but I hope it helps anyway.
A train travels with a constant speed of 20.0m/s for 8.00s. Determine all unknowns and answer the following question(s).
Answer: Since the train travels with a constant speed, it does not experience any acceleration. The magnitude of the train's acceleration is 0 m/s^2.
The distance the train travels during this time can be calculated using the formula d = vt, where d is the distance, v is the velocity, and t is the time. Plugging in the values given, we have:
d = 20.0 m/s * 8.00 s = <<20*8=160>>160 m
Therefore, the train traveled a distance of 160 meters during this time.
1. What is the chemical name of the following chemical symbols?
Be
Nel
Mg
Na
Answer:
Na sodium
Mg magnesium
Be beryllium
Explanation:
Nel is not any element it is wrong
problem 1
A train starts at rest, accelerates with constant acceleration a for 5minutes,then travels at constant speed for another 5minutes,and the decelerates with a.suppose it travels a distance of 10km in all find a
problem 2
A ball is dropped from a height of 10m.At the same time, another ball is thrown vertically upwards at an initial speed of 10m/sec.How high above the ground will the two balls collide
problem 3
find the resultant of the two velocity vectors and also, find the angle that the resultant makes with the vector
The constant acceleration of the train is 50/9 m/s².
The two balls will collide at a height of approximately 10.204 meters above the ground.
How to calculate the valueUsing the kinematic equations of motion, we have:
distance = initial velocity * time + 1/2 * acceleration * time^2
For the first phase of acceleration, the initial velocity is zero, the time is 5 minutes = 300 seconds, and the distance traveled is unknown. So we have:
d1 = 0 + 1/2 * a * (300)^2
For the second phase of constant speed, the initial velocity is v, the time is 5 minutes = 300 seconds, and the distance traveled is also unknown. So we have:
d2 = v * 300
For the third phase of deceleration, the initial velocity is v, the time is also 5 minutes = 300 seconds, and the distance traveled is again unknown. So we have:
d3 = v * 300 + 1/2 * (-a) * (300)^2
The total distance traveled is the sum of these three distances:
distance = d1 + d2 + d3 = 1/2 * a * (300)^2 + v * 600 - 1/2 * a * (300)^2 = v * 600
Since the total distance traveled is given as 10 km = 10000 m, we have:
v * 600 = 10000
Solving for v, we get:
v = 10000/600 = 50/3 m/s
Now we can use the second equation above to find a:
d2 = v * 300 = (50/3) * 300 = 5000 m
Therefore, the constant acceleration of the train is:
a = 2 * (5000 - 1/2 * a * (300)^2) / (300)^2 = 50/9 m/s^2
The constant acceleration of the train is 50/9 m/s^2.
Problem 2: The height of the first ball dropped is given as 10m. Let's assume the height of the collision point is h meters above the ground.
Using the kinematic equation for free fall, we have:
h = 10 + 1/2 * g * t^2
where g is the acceleration due to gravity, which is approximately 9.81 m/s^2, and t is the time it takes for the second ball to reach the collision point after being thrown upwards.
The initial upward velocity of the second ball is 10 m/s, and we know that at the collision point, its velocity will be zero, since it will have reached its maximum height and will be momentarily at rest before falling back down.
Using the kinematic equation for motion with constant acceleration, we have:
0 = 10 + (-g) * t
Solving for t, we get:
t = 10/g = 10/9.81 seconds
Substituting this value of t into the first equation, we get:
h = 10 + 1/2 * 9.81 * (10/9.81)^2
Simplifying, we get:
h = 10.204 m
The two balls will collide at a height of approximately 10.204 meters above the ground.
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creating a system to effectively solve problems can help you out in many ways. what are some benefits you would like to see in your own life as you begin to apply the 4 step problem solving process you read about this week
Creating a system to effectively solve problems is important as it helps an individual or organization to accomplish the goals and objectives.
The 4 step problem solving process is an important approach for effective problem-solving.The 4 step problem solving process involves the following steps:Identifying the problemGathering information and analyzing the problemIdentifying possible solutionsEvaluating and selecting the best solution to the problem.Some of the benefits that one would like to see in their own life as they begin to apply the 4 step problem solving process are as follows:1. Better decision-making skills: The 4 step problem solving process helps individuals to make better decisions in their personal and professional lives. The process helps an individual to evaluate all possible solutions before choosing the best solution to the problem.2. Effective time management: The 4 step problem solving process helps an individual to solve problems quickly and efficiently, leading to effective time management. It helps an individual to focus on the important aspects of the problem and make quick decisions.3. Improved communication: The 4 step problem solving process involves gathering information, analyzing the problem, and identifying solutions. It also involves communicating with others to get more information or to help evaluate solutions.
Effective communication skills are important in this process, and this can be improved through practicing the 4 step problem solving process.4. Improved problem-solving skills: The 4 step problem solving process helps individuals to develop better problem-solving skills, which is important in both personal and professional life. It helps an individual to think critically and creatively to identify the best possible solutions to a problem. This skill can be useful in various situations, including work, school, and personal relationships.
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How did earth change about 2.5 billion years ago when many organisms began using photosynthesis to make food
A. The amount of oxygen in the atmosphere increased
B. Mass extinctions occurred
C. The oceans became larger
D. Rainfall increased
A plastic rod of length d = 1.5 m lies along the x-axis with its midpoint at the origin. The rod carries a uniform linear charge density λ = 2.5 nC/m. The point P is located on the positive y-axis at a distance y0 = 15 cm from the origin. The z-axis points out of the screen. Integrate your correct choice in part (b) over the length of the rod and choose the correct expression for the y-component of the electric field at point P.
Answer:
Explanation:
Let the plastic rod extends from - L to + L .
consider a small length of dx on the rod on the positive x axis at distance x . charge on it = λ dx where λ is linear charge density .
It will create a field at point P on y -axis . Distance of point P
= √ x² + .15²
electric field at P due to small charged length
dE = k λ dx x / (x² + .15² )
Its component along Y - axis
= dE cosθ where θ is angle between direction of field dE and y axis
= dE x .15 / √ x² + .15²
= k λ dx .15 / (x² + .15² )³/²
If we consider the same strip along the x axis at the same position on negative x axis , same result will be found . It is to be noted that the component of field in perpendicular to y axis will cancel out each other . Now for electric field due to whole rod at point p , we shall have to integrate the above expression from - L to + L
E = ∫ k λ .15 / (x² + .15² )³/² dx
= k λ x L / .15 √( L² / 4 + .15² )
b) The length of the rod:
\(E = \int\limits dx . k \lambda .15 / (x^2 + .15^2 )^{1/2} dx\\\\E= \frac{k \lambda * L}{0.15} \sqrt{( L^2 / 4 + .15^2 )\)
Given:
d = 1.5 mλ = 2.5 nC/m
Let the plastic rod extends from - L to + L .Consider a small length of dx on the rod on the positive x axis at distance x . charge on it = λ dx where λ is linear charge density .It will create a field at point P on y -axis.
Distance of point P =\(\sqrt{x^2 + 0.15^2}\)
How to calculate Electric Field?E.F at P due to small charged length\(dE = \frac{ k \lambda x.dx}{(x^2 + .15^2 )}\)
Its component along Y - axis = dE cosθ where θ is angle between direction of field dE and y axis
\(= \frac{dE x .15 }{\sqrt{x^2 + .15^2} }\\\\= \frac{k \lambda dx .15}{(x^2 + .15^2 )^{1/2}}\)
If we consider the same strip along the x axis at the same position on negative x axis , same result will be found . We can say that the component of field in perpendicular to y axis will cancel out each other.
Now for electric field due to whole rod at point p , we shall have to integrate the above expression from - L to + L
\(E = \int\limits dx . k \lambda .15 / (x^2 + .15^2 )^{1/2} dx\\\\E= \frac{k \lambda * L}{0.15} \sqrt{( L^2 / 4 + .15^2 )}\)
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2. Which of the diagrams shows the least gravitational force between the two objects?
a. I
b. II
c. III
d. IV
Which of the diagrams shows the least gravitational force between the two objects?
Options :-a. I
b. II
c. III
d. IV
Answer :- Option D . IV Explanation :- Gravitational force directly proportional to both the masses and in 4th and 3th case we have least mass of 2 on both side which is less than 10 in 2 cases Gravitational force is inversely proportional to square of the distance between the masses and in case 1st and 4th we have more distance than in 2nd and 3th . we know larger the distance lesser will be the forceFrom above observation we can conclude that gravitational force is least in 4th case because we have less mass on both side and we have more distance between the 2 masses that others with same mass .
How strong is the repulsive force exerted on two point charges that each carry 1.0 E-6 C of negative charge and are 0.30 meters apart?
Coulomb's Constant is 9.0 E9 N*m2/C2
Remember to identity all of your data, write the equation, and show your work.
F = Kq₁q₂/(r)²
K is a constant
R is the distance between them
F = 9.0 E9 × 1.0 E-6 × 1.0 E-6/(0.30)²
= 9.0E-3/0.30² = 9.0E-3/0.09 = 0.1 N
The electrostatic force of repulsion between two charges can be determined using Coulomb's law of electrostatic force. The force of repulsion between the point charges of magnitude 1 ×10 ⁻⁶ C separated by 0.30 m is 0.1 N.
What is Coulomb's law of electrostatic forces?According Coulomb's law of electrostatic forces, the force between two charges q1 and q2 separated by a distance of r meters is given by the expression:
F = K q1 q2/r²
Where, K is Coulomb's Constant equal to 9.0 ×10⁹ Nm²/C²
Given q1 = q2 = 1 ×10 ⁻⁶ C
r = 0.30 m
k = 9.0 ×10⁹ Nm²/C².
Then the electrostatic force of repulsion between the two point charges is calculated as follows:
F = 9.0 ×10⁹ Nm²/C² × 1 ×10 ⁻⁶ C × 1 ×10 ⁻⁶ C/ (0.30 m )²
= 0.1 N.
Therefore, the repulsive force exerted on two point charges that each carry 1.0 E-6 C of negative charge and are 0.30 meters apart is 0.1 N.
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A steam engine takes in superheated steam at 270 °C and discharges condensed steam from its cylinder at 50 °C. The engine has an efficiency of 30%, and taken in 50 kJ from the hot steam per cycle. If a Carnot engine takes in the same amount of heat per cycle and operates at these temperatures, the work it can turn into is most likely to be:a) 15 kJ. b) 20 kJ. c) 10 kJ. d) 50 kJ.
Answer:
b) 20 kJ
Explanation:
Efficiency of carnot engine = (T₁ - T₂ ) / T₁ Where T₁ is temperature of hot source and T₂ is temperature of sink .
T₁ = 270 + 273 = 543K
T₂ = 50 + 273 = 323 K
Putting the given values of temperatures
efficiency = (543 - 323) / 543
= .405
heat input = 50 KJ
efficiency = output work / input heat energy
.405 = output work / 50
output work = 20.25 KJ.
= 20 KJ .
SuperPointParticleDog is playing tug of war with two other dogs, Isaac and Newton. Isaac is pulling with a force of 255 N, 13 degrees North of East on one rope attached to a ball. Newton is pulling with a force of 156 N, 34 degrees South of East on another rope attached to the ball. If the ball is moving with constant momentum toward SuperPointParticleDog, what is the East/West component of her force on the ball?
The East/West component of SuperPointParticleDog's force on the ball is -115.7 N. (Westward).
How to explain tje informationIsaac's force:
Magnitude: 255 N
Angle: 13 degrees North of East
x-component: 255*cos(13) = 245.1 N (Eastward)
y-component: 255*sin(13) = 58.1 N (Northward)
Newton's force:
Magnitude: 156 N
Angle: 34 degrees South of East
x-component: 156*cos(34) = 129.4 N (Westward)
y-component: 156*sin(34) = 86.5 N (Southward)
Now we can add the x- and y-components of the forces to find the net force:
Net force:
x-component: 245.1 N - 129.4 N = 115.7 N (Eastward)
y-component: 58.1 N - 86.5 N = -28.4 N (Southward)
The net force has an Eastward component of 115.7 N. Therefore, the East/West component of SuperPointParticleDog's force on the ball is -115.7 N. (Westward).
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Can an object have momentum in space?
Answer: Objects in space can have momentum space because momentum depends on mass and velocity. Unlike other quantities, like weight, mass does not change if an object is on space or on Earth.
Explanation: Because momentum depends on mass and velocity and unlike other quantities, like weight, mass does not change if an object is on space or on Earth.
A beam of light from a laser illuminates a glass how long will a short pulse of light beam take to travel the length of the glass.
Answer:
The time of short pulse of light beam is \(2.37\times10^{-9}\ sec\)
Explanation:
Given that,
A beam of light from a laser illuminates a glass.
Suppose, the length of piece is \(L=25.21\times10^{-2}\ m\)
Index of refraction is 2.83.
We need to calculate the speed of light pulse in glass
Using formula of speed
\(v=\dfrac{c}{\mu}\)
Put the value into the formula
\(v=\dfrac{3\times10^{8}}{2.83}\)
\(v=1.06\times10^{8}\ m/s\)
We need to calculate the time of short pulse of light beam
Using formula of velocity
\(v=\dfrac{d}{t}\)
\(t=\dfrac{d}{v}\)
Put the value into the formula
\(t=\dfrac{25.21\times10^{-2}}{1.06\times10^{8}}\)
\(t=2.37\times10^{-9}\ sec\)
Hence, The time of short pulse of light beam is \(2.37\times10^{-9}\ sec\)
slowly increase the amplitude of the sine wave from fgen until the voltage signal starts clipping (ie, the peaks flatten). note the amplitude of the clipping. sketch the shape of the waveform and explain what is happening (hint: read the background section on buffer circuits)
The amplitude of the sine wave will increase until the voltage signal starts to clip. This is when the waveform starts to flatten and look more like a square wave with clipped tops and bottoms.
What is amplitude?Amplitude is a measure of the strength or intensity of a wave or signal. It is usually measured as the peak value of a waveform, or the maximum absolute value of a signal over a given period of time. Amplitude is used to describe the size of a wave, or the intensity of a sound. Amplitude affects the loudness of sound, and is an important factor in the quality of a sound.
This is happening because the voltage is exceeding the capabilities of the buffer circuit in the fgen. The buffer circuit is designed to amplify and maintain the shape of the input signal, but when the signal exceeds its capability, it is unable to maintain the shape, resulting in clipping.
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what are the factors affecting center of mass in an object
IS EARTH PLANET FALT OF ROUNDED?
Explanation:
Falt isn't a size. I guess you were trying to spell flat. No, the earth isn't flat. instead, it is round.
Answer:
Earth is round. But the map shows you flat.
Where do magnetic fields occur?
Answer:
The Magnetosphere and MagnetsExplanation:
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According to the National Geographic, "Earth’s magnetic field dominates a region called the magnetosphere, which wraps around the planet and its atmosphere. Solar wind, charged particles from the sun, presses the magnetosphere against the Earth on the side facing the sun and stretches it into a teardrop shape on the shadow side. The magnetosphere protects the Earth from most of the particles, but some leak through it and become trapped. When particles from the solar wind hit atoms of gas in the upper atmosphere around the geomagnetic poles, they produce light displays called auroras. These auroras appear over places like Alaska, Canada and Scandinavia, where they are sometimes called “Northern Lights.” The “Southern Lights” can be seen in Antarctica and New Zealand. The magnetic field is the area around a magnet that has magnetic force. All magnets have north and south poles."
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22. A 15-volt battery is connected to a 3.0-ohm resistor, as shown.How much power is used by the resistor?(a) 8.3 W(b) 15 W(c) 45 W(d) 75 W
Given voltage of the battery is,
\(V=15\text{ volt}\)The value of the resistance is,
\(R=3\text{ ohm}\)Thus, the power in terms of voltage and resistance is,
\(P=\frac{V^2}{R}\)Substituting the known values,
\(\begin{gathered} P=\frac{15^2}{3} \\ P=75\text{ W} \end{gathered}\)Thus, the power used by resistor is 75 W.
Hence, the d option is the correct answer.
why can't a transformer operate on a DC signal
Answer:
Transformers do not allow DC input to flow through. This is known as DC isolation. This is because a change in current cannot be generated by DC
Explanation:
Hope this helps
Answer:
a change in current cannot be generated by DC;
since Ethanol has a heat capacity of 0.614 cal/g °C. If 50 g of ethanol has a temperature of 30ºC and a piece of hot Copper is added to the ethanol causing the temperature to increase to 70ºC. What is the amount of heat absorbed by the ethanol?
This question involves the concepts of heat capacity, temperature, and heat.
The heat absorbed by ethanol is "1228 cal".
HEAT CAPACITYThe heat capacity of a substance is defined as the amount of heat absorbed by a unit amount of that substance for a degree rise in temperature. Mathematically,
\(Q = mc\Delta T\)
where,
c = heat capacity = 0.614 cal/g.°Cm = mass of ethanol = 50 gΔT = change in temperature = 70°C - 30°C = 40°CQ = amount of heat absorbed = ?Therefore,
Q = (50 g)(0.614 cal/g°C)(40° C)
Q = 1228 cal
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