Solution
Harry buys 3 granola bars for $5. Sidnee buys 9 granola bars for $15.
\(\begin{gathered} y=kx \\ \end{gathered}\)Where
x=3
y=5
k is the proportionality
\(\begin{gathered} 5=3k \\ divide\text{ both sides both sides} \\ \frac{5}{3}=\frac{3k}{3} \\ \\ k=\frac{5}{3} \\ \\ k=1.6667 \\ \end{gathered}\)The constant proportionality is
\(1.6667\)New York City is 2.727272.% of the United States' population. NYC's population is 9 million people. What is the population of the United Sates?
The population of US is 330 million approx.
What is percent?A percentage is a figure or ratio that can be stated as a fraction of 100. If we need to calculate the percentage of a number, we must divide it by its full value and then multiply it by 100. As a result, the percentage is one part in one hundred. "Per 100" is short for "per percent." The number "%" is used to symbolize it.
Given
population of new york = 2.727272% population of US
population of new york = 9 million
population of US = 1/2.727272% of new york
population of US = 36.6666 x 90,00,000
population of US = 33,00,00,087.9 = 330 million approx
Hence population of US is approx 330 million.
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In the xy-plane, line / passes through the origin and is perpendicular to the line with equation 5x - 2y = 8.
Which of the following could be an equation of line /?
Answer:
\(ac - bd\)
Step-by-step explanation:
\(ac - bd \)
At a basketball game, for every 2 baskets team A scored, team B scored 5 baskets. The ratio of the number of baskets scored by team A to the number of baskets for team B is choices: 2 to 3, 2 to 5, 3 to 2, 5 to 2
The ratio of the number of baskets scored by team A to the number of baskets by team B is 2: 5. Then the correct option is B.
In a basketball game, team B scored 5 baskets for every 2 that team A scored.
The utilization of two or more additional numbers that compares is known as the ratio.
Assume that Team A scored two baskets while Team B netted five.
The problem statement states that for every two baskets Team A scored, Team B scored five. This may be expressed as the ratio shown below:
Ratio = 2x : 5x
Ratio = 2: 5
Thus, the correct option is B.
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Good morning can somebody help me out the answer choice are
A.56.4 degrees
B.40.0 degrees
C. 13.3 degrees
D. 33.6 degrees
Answer:
Option D
Step-by-step explanation:
Measure of adjacent side = 20
Measure of Hypotenuse = 24
Since, measures of adjacent side and Hypotenuse have been given in the question, cosine ratio will be applied to find the measure of angle x.
cos(x) = \(\frac{\text{Adjacent side}}{\text{Hypotenuse}}\)
cos(x) = \(\frac{20}{24}\)
x = \(\text{cos}^{-1}(0.833)\)
= 33.55°
≈ 33.6°
Option D is the answer.
how many ping pong balls do you need if you want to arrange them in the shape of an equilateral triangle with 23 rows
-5(1/6-8) = 40 - х + 1/6х
w/ solutions pleasee thanks
The value of x in the equation -5(1/6-8) = 40 - х + 1/6х is 1
What are algebraic equations?An algebraic equation can be defined as a mathematical statement in which two expressions are set equal to each other. The algebraic equation usually consists of a variable, coefficients and constants.
The algebraic equation -5(1/6-8) = 40 - х +( 1/6)х has one variable which is x.
Firstly, we open the parentheses
-5/6 +40 = 40-x+(1/6) x
multiplying through by 6
-5+240 = 240-6x +x
collecting like terms
-5+240-240 = -5x
- 5 = -5x
divide both sides by -5
x= -5/-5
x= 1
therefore the value of x is 1
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Which expression is equivalent to -3(2x-2) – (x+3)?
Answer:
-7x+3
Step-by-step explanation:
Answer:
Step-by-step explanation:10x+15+2+x
11x+17
Step-by-step explanation:
brainliest please
On January 1, 2019, Concord Corp. signs a contract to lease nonspecialized manufacturing equipment from Stone Inc. Concord agrees to make lease payments of $47,500 per year. Additional information pertaining to the lease is as follows:
1. The term of the noncancelable lease is 3 years, with a renewal option at the end of the lease term. Payments are due every January 1, beginning January 1, 2019.
2. The fair value of the manufacturing equipment on January 1, 2019, is $150,000. The equipment has an economic life of 7 years.
3. Concord guarantees that the equipment will have a residual value of $15,000 at the end of the lease term. Concord considers it probable that it will have to pay $5,000 cash at the end of the lease terms to satisfy this residual value guarantee.
4. Concord Corp. depreciates similar assets using the straight-line method.
5. Concord’s incremental borrowing rate is 12% per year; Stone’s implicit interest rate is 10% and known by Concord.
6. Concord pays $2,500 per year for maintenance of the equipment and $1,000 in property taxes directly to the applicable third party.
Required:
1. Next Level Examine and evaluate each capitalization criteria and determine what type of lease this is for Concord.
2. Prepare a table summarizing the lease payments and interest expense.
3. Prepare journal entries for Concord for the entire lease period. Assume that the equipment has a fair value of $11,500 at the end of the 3-year lease term.
Gain on Residual of Right-of-Use Asset ..................................... 1,500.00
How to solveThe lease is a finance lease since at least one of the classification criteria is met.
*Present value = Lease payments × PV factor for 3 payments at 10% + (asset and liability) Guaranteed residual value × PV factor for single sum at 10%
= ($47,500 × 2.735537) + ($15,000 × 0.751315)
= $129,938.01 + $11,269.73
= $141,207.74
aThe amount of the capital lease obligation is the PV of the lease payments ($129,938.01) plus PV of the amount expected to be paid due to the residual value guarantee ($3,756.58 = $5,000 × 0.751315)
*Adjusted for $0.01 rounding error
3.
2019
Jan. 1 Right-of-Use Asset ...................................................... 133,694.59
Lease Liability ................................................................................ 133,694.59
1 Lease Liability ............................................................. 47,500.00
Cash ................................................................................................ 47,500.00
Dec. 31 Interest Expense ......................................................... 8,619.46
Lease Liability ................................................................................ 8,619.46
31 Maintenance Expense ............................................. 2,500.00
Property Tax Expense ................................................... 1,000.00
Cash ......................................................................................... 3,500.00
31 Amortization Expense ............................................... 44,564.86
Right-of-Use Asset
[133,694.59 ÷ 3] .......................................................................... 44,564.86
2020
Jan. 1 Lease Liability ............................................................. 47,500.00
Cash ................................................................................................ 47,500.00
Dec. 31 Interest Expense ......................................................... 4,731.41
Lease Liability ................................................................................ 4,731.41
31 Insurance Expense .................................................... 2,500.00
Property Tax Expense .................................................... 1,000.00
Cash ................................................................................................ 3,500.00
31 Amortization Expense ............................................... 44,564.86
Right-of-Use Asset ......................................................................... 44,564.86
2021
Jan. 1 Lease Liability ............................................................. 47,500.00
Cash ................................................................................................ 47,500.00
Dec. 31 Interest Expense ......................................................... 454.54
Lease Liability ................................................................................ 454.54
31 Insurance Expense .................................................... 2,500.00
Property Tax Expense .................................................... 1,000.00
Cash ................................................................................................ 3,500.00
31 Amortization Expense ............................................... 44,564.86
Right-of-Use Asset ......................................................................... 44,564.86
31 Lease Liability ............................................................. 5,000.00
Cash ................................................................................................ 3,500.00
Gain on Residual of Right-of-Use Asset ..................................... 1,500.00
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Find x. (The picture has the info)
Answer:
X=5
Step-by-step explanation:
3x+9 is twice of 12 (24). 24-9=15, and 3*5=15, so x=5.
I need help on this please answer all three of them median range and mode
Answer:
1. median :- 82. mean :- 403. mode. :- 7Step-by-step explanation:
❣️(◍Jess bregoli◍)❣️#keep learning!!Determining the Value of an Unknown
What is the value of n in the equation --(2n + 4) + 6 = -9 + 4(2n + 1)?
The value of n in the given equation is 1.
Define Algebraic Expression
In mathematics, an expression that includes variables, constants, and algebraic operations is known as an algebraic expression (addition, subtraction, etc.)
Given equation,
-1/2 (2n + 4) + 6 = -9 + 4(2n + 1)
Now, solve for n
first, solve the brackets
-1/2 * 2n + (-1/2) * 4 + 6 = -9 + 4*2n + 4 * 1
-n - 2 + 6 = -9 + 8n + 4
Solve the constants on both the sides,
-n + 4 = 8n - 5
Now, take out n value one side and constant terms other side
-n - 8n = -5 - 4
-9n = -9
Cancel out -9 from both the sides,
n = 1
Hence, the value of n in the given equation is 1.
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17. It takes one minute to fill (3/7) th of a vessel. What is the time taken in
minutes to fill the whole of the vessel?
Answer:
Given that 1minute =3/7of the vessel
let the time taken in minutes to fill the whole of the vessel be' x' minute.
1min =3/7
xmin =whole vessel =1=7/7
=3x/7=1=x=7/3=2.3min=2min.3sec
20. There is a number x sum that x2 is irrational but x is rational. Then x can be
(a) √5102.0 (£)
(b) √2
(c) 3/2
(d) 4/5
The correct answer is 3/2. In this case, x = 3/2, and its square, (3/2)^2 = 9/4, is rational. x satisfies the given condition.option (c)
To explain further, we need to understand the properties of rational and irrational numbers.
A rational number can be expressed as a fraction of two integers, while an irrational number cannot be expressed as a fraction and has non-repeating, non-terminating decimal representations.
In the given options, (a) √5102.0 (£) and (b) √2 are both irrational numbers.
Their squares, (√5102.0)^2 and (√2)^2, would also be irrational, violating the given condition. On the other hand, (d) 4/5 is rational, and its square, (4/5)^2 = 16/25, is also rational.
Option (c) 3/2 is rational since it can be expressed as a fraction. Its square, (3/2)^2 = 9/4, is rational as well.
Therefore, (c) 3/2 is the only option where x is rational, but its square is irrational, satisfying the condition mentioned in the question.
In summary, the number x that satisfies the given condition, where x^2 is irrational but x is rational, is (c) 3/2.option (c)
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what are3 rations equivalent to 8:5
Answer:
16:10
4:2.5
64:40
Step-by-step explanation:
hope this helps
For the statement, find the constant of variation and the variation equation.
y varies directly as the cube of x; y = 4 when x = 2
Answer:
see explanation
Step-by-step explanation:
given y varies directly as x³ then the equation relating them is
y = kx³ ← k is the constant of variation
to find k use the condition y = 4 when x = 2 , then
4 = k × 2³ = 8k ( divide both sides by 8 )
\(\frac{4}{8}\) = k , that is
k = \(\frac{1}{2}\)
y = \(\frac{1}{2}\) x³ ← equation of variation
log 3 + log 6
this expression is equivalent to the log of what number?
The equivalent logarithmic value of the given expression log 3 + log 6 is equal to logarithm of 18.
The expression is equal to,
log 3 + log 6
By using the law of multiplication we have,
Log A + Log B = Log ( A × B )
Using the properties of logarithms, we can simplify the expression and get the equivalent logarithm number ,
Substitute the value of A = 3 and value of B = 6 in the formula we have,
log 3 + log 6
= log (3 × 6)
= log 18
Therefore, the expression log 3 + log 6 is equivalent to the logarithm of 18.
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2x+ for x=5 help me with this
Answer:
10
Step-by-step explanation:
Please only 10% of people are smart to answer this
Answer:
it's the one highlighted in orange
Step-by-step explanation:
I hope this helps with your question :)
Which of the following angles are shown in the drawing?
The angle from the options given that is shown in the drawing is: D. <LIJ.
What is an Angle?An angle is a geometric figure that is formed by two rays that share the same endpoint, called the vertex. The rays are called the sides of the angle, and the endpoint is called the vertex.
In the drawing given, IJ and LI are two segments that have a common endpoint called vertex I.
Points L, I, and J forms an angle whose vertex is at I, as shown in the image given. Thus, the angle shown in the drawing is: D. ∠LIJ.
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Which shows the mixed number for 13/3?
4 1/3 or
1 3/3 or
4 2/3
Answer:
Answer vary :
4 1/3
Step-by-step explanation:
A tank weighs 5.6kg when it 1/4 filled with water.If it weighs 10.4kg when it is full ,what will be it's weight when it is empty.
Answer:
4 kg
Step-by-step explanation:
so 1.6 * 4 is 6.4 so you just double check if you want
4 + 1.6 which is 1/4 of 6.4 will be 5.6 (matches with the question)
4 + (1.6*4) (indicates it's full) = 10.4( also Matches with the question)
there is another way by setting up an equation. let me know in comments if you want to see it that way
If tank weighs 5.6kg when it 1/4 filled with water. If it weighs 10.4kg when it is full , then weight when it is empty is 0.93kg
What is Equation?Two or more expressions with an Equal sign is called as Equation.
Given,
A tank weighs 5.6kg when it 1/4 filled with water
Tank weighs 10.4kg when it is full
We need to find the weight when it is empty.
Let weight of the tank “x” and the weight of the water in the full tank “y”.
From the problem statements, we deduce the following equations:
x + y/4 = 5.6kg => x = 5.6kg - y/4
x + y = 10.4kg => y = 10.5kg - x
y = 10.5kg - (5.6kg - y/4)
3y/4 = 4.9
Thus y = 6.53kg; x = 0.93kg
Hence, weight of the tank when it is empty is 0.93kg.
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The population of a city was 10,000 in 2010. The population increase at an annual rate of 2.5% per year. Is the growth model function that represents the population of the city linear?
Answer:
The growth model that represents the population of this city is not linear--it is exponential:
\(f(t) = 10000( {1.025}^{t} )\)
\(t = 0 \: represents \: 2010\)
Michael is cutting a 100-yard ribbon into pieces 3.4 yards long. He says that an inequality that represents his project is 3.4x 100. Explain what this statement means, in words, and what each part of the inequality represents
Answer:
\(3.4x\le 100\)
Step-by-step explanation:
Given that,
Michael is cutting a 100-yard ribbon into pieces 3.4 yards long.
Michael says that an inequality that represents his project is 3.4x 100.
Let Michael cuts the ribbon in x no of variables. It is given as :
3.4x is the total length of all the pieces together
i.e.
3.4x is less than or equal to 100.
The required equation that represents the given scanario is :
\(3.4x\le 100\)
Answer:
Step-by-step explanation:
Sample Response: The variable, x, is the number of pieces of ribbon Michael cuts. Since each piece is 3.4 yards long, 3.4x is the total length of all the pieces together. This total length cannot be more than the 100 yards of ribbon he has, so 3.4x must be less than or equal to 100.
I have 23 hundredths and 12 tenths. Who am I? Convince by using Base 10 Blocks
Answer:
1.43
Step-by-step explanation:
12 tenths ⇒ 1.2
23 hundredths ⇒ 0.23
0.23 + 1.2 = 1.43
A ship is anchored off a long straight shoreline that runs north and south. From two observation points
miles apart on shore, the bearings of the ship are
and
. What is the distance from the ship to each of the observation points? Round each answer to the nearest tenth of a mile.
The distance from the north most ship to the observation is
miles.
The distance from the south most ship to the observation is
miles.
The distance from the north most ship to the observation is 2.9 miles and the distance from the south most ship to the observation is 9.9 miles.
The bearing is defined as the angle measured clockwise from the north direction. A ship is anchored off a long straight shoreline that runs north and south.
From two observation points miles apart on shore, the bearings of the ship are 52 degrees and 134 degrees respectively. To find the distance from the ship to each of the observation points, we can use trigonometry.
Let's call the distance from the north observation point to the ship x, and the distance from the south observation point to the ship y. The bearings from the north and south observation points can be drawn as follows:
[asy]
unitsize(1cm);
pair O = (0,0), N = (-2,0), S = (2,0), A = (-2,1), B = (2,-1);
draw(O--N--A,Arrow);
draw(O--S--B,Arrow);
\(label("$52^\circ$", N + 0.3*dir(52), NE);\)
\(label("$134^\circ$", S + 0.3*dir(134), SE);\)
draw(O--A--B--cycle,dashed);
\(label("$x$", (N+A)/2, W);\)
\(label("$y$", (S+B)/2, E);\)
[/asy]
We can use the tangent function to find x and y, since we have the angle and opposite side.
From the north observation point, we have:
\($$\tan(52^\circ) = \frac{x}{2}$$$$x = 2\tan(52^\circ) \approx 2.95$$\)
From the south observation point, we have:
\($$\tan(134^\circ) = \frac{y}{2}$$$$y = 2\tan(134^\circ) \approx 9.88$$\)
Therefore, the distance from the north most ship to the observation is 2.9 miles and the distance from the south most ship to the observation is 9.9 miles.
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\sin ^ { 2 } \frac { 3 \pi ^ { c } } { 4 } + 2 \tan ^ { 2 } \frac { 3 \pi ^ { c } } { 4 } - \sec ^ { 2 } \frac { 3 \pi ^ { c } } { 4 } - \cos ^ { 2 } \frac { 3 \pi ^ { c } } { 4 }
Step-by-step explanation:
The simplified expression is {3\tan^2\frac{3\pi^c}{4}}
in the right triangle AB, mc=90, a=4, and sinA=1/2. what is the length of the hypotenuse?
Given:
In a right angle triangle ABC, \(m\angle C=90^\circ , a=4\) and \(\sin A=\dfrac{1}{2}\).
To find:
The length of the hypotenuse.
Solution:
It is given that \(m\angle C\), so opposite side of this angle is the hypotenuse, i.e., c.
In a right angle triangle,
\(\sin \theta=\dfrac{Perpendicular}{Hypotenuse}\)
In the given triangle,
\(\sin A=\dfrac{a}{c}\)
Substituting the given values, we get
\(\dfrac{1}{2}=\dfrac{4}{c}\)
By cross multiplication, we get
\(1\times c=4\times 2\)
\(c=8\)
Therefore, the length of the hypotenuse is 8 units.
Calculate the value of the expression-6(-5-4)-4(-3-2)=
Answer:
74
Step-by-step explanation:
-6(-5-4) - 4(-3-2)
30 + 24 + 12 + 8
= 54 + 12 + 8
= 66 + 8
= 74
You are currently getting 26 sales opportunities per day and closing 64% of them
Multiply the percentage by the total opportunities:
26 x 0.64 = 16.64
You are closing roughly 17 sales per day.
Help me with this one please
a) The vertex of function 1 is given as follows: (-2.8).
b) The vertex of function 2 is given as follows: (2,5).
c) The function with the larger maximum value is given as follows: Function 1.
How to obtain the vertex of a quadratic function?The standard definition of a quadratic function is given as follows:
y = ax² + bx + c.
Hence the coefficients for the function 1 are given as follows:
a = -3, b = -12, c = -4.
The x-coordinate of the vertex is defined as follows:
x = -b/2a
Then:
x = -12/6
x = -2.
The y-coordinate of the vertex is given as follows:
f(-2) = -3(-2)² -12(-2) - 4
f(-2) = 8.
The vertex is the turning point of a quadratic function, where it changes from increasing to decreasing or vice versa, hence for function 2 it is given at (2,5).
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