help heating curve iron
at what temperature does the substance begins to boil
at what temperature does a substance begin to melt
at what temperature is a substance for a liquid and a gas
at what temperature is the substance both a solid and a liquid​

In the given reaction, the limiting reactant is C₆H₆ (benzene).

To determine the limiting reactant as well as calculate the mass of HCl produced, compare the moles of each reactant.

The number of moles for each reactant:

Molar mass of Cl₂ = 35.5 g/mol + 35.5 g/mol = 71 g/mol

Moles of Cl₂ = mass of Cl₂ / molar mass of Cl₂

                     = 45 g / 71 g/mol

                     = 0.634 moles of Cl₂

Molar mass of C₆H₆ (benzene) = 12 g/mol + 6(1 g/mol) = 78 g/mol

Moles of C₆H₆ = mass of C₆H₆ / molar mass of C₆H₆

                        = 45 g / 78 g/mol = 0.577 moles of C₆H₆

Determine the stoichiometry between Cl₂ and HCl:

Cl₂ + C₆H₆ → C₆H₅Cl + HCl

Here, we can see that 1 mole of Cl₂ produces 1 mole of HCl.

Thus, the limiting reactant is C₆H₆ (benzene).

Calculate the mass of HCl produced:

Molar mass of HCl = 1 g/mol + 35.5 g/mol = 36.5 g/mol

Moles of HCl produced = moles of C₆H₆ = 0.577 moles

Mass of HCl produced = moles of HCl produced × molar mass of HCl

Mass of HCl produced = 0.577 moles × 36.5 g/mol

                                     ≈ 21.04 g

Therefore, approximately 21.04 grams of HCl will be produced.

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One of the most widely used explosophores—functional groups that give a compound its explosive properties—in the world is the nitro group. Also strongly electron-withdrawing is the nitro group. This property allows for the possibility of acidic C-H bonds that are alpha to the nitro group (nearby).

The silver-mirror appearance that develops at the end of the reaction serves as a marker for the Nitro group. Tollen's reagent is used to heat hydroxylamine even more. Heating causes hydroxylamine to oxidize into the appropriate nitroso compound and reduce Tollen's reagent to metallic silver.

The prefix "nitro" is added to the name of the matching alkane or arene to create the name of any nitro compound.

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question:-

What type of group is nitro group?

Answer:

the SI unit of force. It is equal to the force that would give a mass of one kilogram an acceleration of one metre per second per second, and is equivalent to 100,000 dynes.

Answer:

A newton is a unit of force

Answer:

0.5 g/L.

Explanation:

Hello,

In this case, for this solubility problem, we can write for the lead (II) fluoride:

\(PbF_2(s)\rightleftharpoons Pb^{2+}(aq)+2F^-(aq)\)

And the equilibrium expression is:

\(Ksp=[Pb^{2+}][F^-]^2\)

Whereas Ksp of lead (II) fluoride is 3.3x10⁻⁸. In such a way, we can write the equilibrium expression in terms of the molar solubility \(x\) as follows:

\(Ksp=(x)(2x)^2=3.3x10^{-8}\)

Hence, solving for \(x\) we find:

\(x=\sqrt[3]{\frac{3.3x10^{-8}}{4} }\\\\x=2.02x10^{-3}M\)

Moreover, since the molar mass of lead (II) fluoride is 245.2 g/mol, the solubility turns out:

\(2.02x10^{-3}\frac{molPbF_2}{L}*\frac{245.2gPbF_2}{1molPbF_2}\\ \\0.5\frac{g}{L}\)

Best regards.

Answer:

westrosol( it may not be correct)

Answer:

The correct option is (3).

Explanation:

The ideal gas equation is given by :

\(PV=nRT\\\\V=\dfrac{nRT}{P}\)

The pressure of ideal gas is directly proportional to temperature and inversely proportional to its volume.

We can say that the volume of a 1.00-mole sample of an ideal gas will decrease when the pressure increases and the temperature decreases.

The volume of the idea gas decrease when pressure increases and the temperature decreases. Thus option C is correct.

The ideal gas equation can be given as:

PV = nRT

The equation in terms of pressure and temperature when n=1 can be written as:

Volume = \(\rm \dfrac{RT}{P}\)

Accordingly, the volume has been directly proportional to the temperature and has been inversely proportional to the pressure.

Thus, with the decrease in volume, there has been an increase in pressure and a decrease in temperature.

Thus, option C is correct.

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Answer:

CH4 (g) and O2 (g) are both in the gaseous state, while CO2 (g) and H2O (g) are also in the gaseous state.

In the above reaction, the reactants are in the gaseous state, and the products formed are also in the gaseous state.

Every compound in a chemical reaction can be in any state of matter like solid, liquid, or gas. In the reaction of methane and oxygen, the initial state of the reactants is in the gaseous form. The chemical reaction of methane and oxygen is given by the equation CH4 (g) + 2 O2 (g) -> CO2 (g) + 2 H2O (g).Here, methane and oxygen are the reactants, and carbon dioxide and water are the products. Methane (CH4) and oxygen (O2) react together in the presence of a spark or heat to produce carbon dioxide (CO2) and water (H2O).In the reaction, the methane gas combines with oxygen gas, which causes the release of heat energy and forms carbon dioxide gas and water vapor. Methane gas is a colorless and odorless gas that burns cleanly and is one of the primary components of natural gas.

The oxygen gas required for the reaction is available in the atmosphere. Carbon dioxide is a colorless gas with a faint odor and taste and is a significant component of the Earth's atmosphere. Water is a colorless, odorless, and tasteless liquid that is essential to life.The state of matter of every compound in a chemical reaction can change depending on the conditions in which the reaction occurs. For instance, a substance that is in the solid state at a lower temperature may melt into a liquid or boil into a gas at a higher temperature. Similarly, a liquid may freeze into a solid or vaporize into a gas under different conditions.

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Answer:  \(H_2PO_4\) and \(H_3PO_4\)

Explanation:

According to the Bronsted-Lowry conjugate acid-base theory, an acid is defined as a substance which looses donates protons and thus forming conjugate base and a base is defined as a substance which accepts protons and thus forming conjugate acid.

For the given reaction:

\(H_2PO_4^-+H_2O\rightleftharpoons H_3PO_4+OH^-\)

Here, \(H_2O\) is loosing a proton, thus it is considered as an acid and after losing a proton, it forms \(OH^-\) which is a conjugate base.

Similarly , \(H_2PO_4^-\) is gaining a proton, thus it is considered as an base and after gaining a proton, it forms \(H_3PO_4\) which is a conjugate acid.

Thus \(H_2PO_4\) and \(H_3PO_4\) is a conjugate acid-base pair in the reaction represented by the equation below

The Bronsted-Lowry conjugate acid-base hypothesis defines an acid as a substance that loses protons and donates them to another chemical to produce conjugate base, and a base as a substance that takes protons to generate conjugate acid.

Thus, a proton is being lost, making it an acid, and once a proton is lost, a conjugate base is formed. Similar to that, is gaining a proton, making it a base, and then it produces a conjugate acid after gaining a proton.

The Brnsted-Lowry hypothesis, often known as the proton theory of acids and bases, is an independent theory of acid-base reactions that was put forth in 1923 by Johannes Nicolaus Brnsted and Thomas Martin Lowry.

This theory's central idea is that when an acid and a base interact, the acid creates its conjugate base and the base creates its conjugate acid by exchanging a proton (the hydrogen cation, or H+).

Thus, The Bronsted-Lowry conjugate acid-base hypothesis defines an acid as a substance that loses protons and donates them to another chemical to produce conjugate base, and a base as a substance that takes protons to generate conjugate acid.

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Rough ER is connected to the nuclear membrane and is responsible for the synthesis and processing of proteins.

The rough endoplasmic reticulum (ER) is a network of membrane-bound sacs and tubules that is studded with ribosomes on its surface. These ribosomes are responsible for protein synthesis. The rough ER is connected to the nuclear membrane because it receives instructions for protein synthesis from the DNA in the nucleus. This connection allows for the efficient transfer of genetic information from the nucleus to the rough ER.

Once the ribosomes on the rough ER synthesize proteins, the rough ER is also involved in the processing and modification of these proteins. It helps in folding the newly synthesized proteins into their functional three-dimensional shapes and also adds various modifications such as glycosylation (the addition of sugar molecules) or signal sequences that target the proteins to specific locations within or outside the cell.

After processing, the proteins may be transported to other parts of the cell or exported to the cell membrane or extracellular space. The connection between the rough ER and the nuclear membrane ensures a coordinated flow of genetic information and protein synthesis, allowing the cell to efficiently carry out its functions.

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Answer:

Explanation:

The drinks that were put into cooler A have lower temperatures than the drinks that were put into cooler B.

As heat flows from high temperature to low temperature until it reaches equilibrium, more heat flows from the drinks to ice in cooler B than the heat flows from the drinks to ice in cooler A.

Thus, most of the ice in cooler B is melted as heat is transferred to the ice that results in its phase change.

The soft drinks in cooler B had higher thermal energy than the soft drinks in cooler A. Therefore, greater thermal energy flowed from the drinks in cooler B to ice, causing it to melt faster.

When the soft drinks are placed in ice, thermal energy flows from the object having a higher temperature to the object at a lower temperature until thermal equilibrium is achieved between the two bodies.

Note that the temperature difference between the soft drinks in cooler B and ice is much higher compared to the temperature difference between the soft drinks in cooler A and ice.

The reason behind this is that the soft drinks in cooler A were kept in a refrigerator for 8 hours while the soft drinks in cooler B were kept at room temperature for 8 hours.

When both groups of soft drinks were added to different coolers with the same 1.5 kg of ice, thermal equilibrium was attained in both cases.

The soft drinks in cooler B  transferred more energy to the ice in four hours causing it to melt faster compared to the amount of energy transferred to it by the soft drinks in cooler B. The energy between the soft drinks in cooler A and ice were minimal hence the soft drinks in cooler A still remained ice after 4 hours.

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Learn more:

The answer responses to  the structures shown in the diagram are:

A. chromosomes

C. They would be the same.

B. They are in pairs because each one comes from a different parent.

The chromosomes are in pairs because humans have a diploid number of chromosomes, meaning they have two sets of chromosomes, one inherited from each parent.

The nucleus is important in eukaryotic cells and has many important parts that help the cell work properly. There are some parts inside cells called the nuclear membrane, nucleoplasm, nucleolus, and chromatin. Chromatin is made up of DNA and other proteins.

Every part of a person's body has the same genes, but the way they are organized can be different in different types of cells. The chromosomes in our skin cells might not be the same as the chromosomes in our muscle cells, even if they come from the same person.

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Identify the structures shown.

A. chromosomes

B. mitochondria

C. nuclei

D. vacuoles

C

Describe how the structures from this cell would compare to the structures in the nucleus of another body cell from the same person.

A. There would be longer.

B. They would be shorter.

C. They would be the same.

D. They would be different.

Describe how the structures from this cell would compare to the structures in the nucleus of another body cell from the same person.

A. There would be longer.

B. They would be shorter.

C. They would be the same.

D. They would be different.

Explain why the structures are in pairs.

A. They aren't in pairs.

B. They are in pairs because each one comes from a different parent.

C. This cell is making a copy of itself.

D. The cell always has 2 copies in case 1 is damaged.

The liquid substance used in the laboratory for dissolving dry mortar on floor flies is hydrochloric acid.

Hydrochloric acid is a strong acid that can dissolve many materials, including dry mortar.

Hydrochloric acid also known as muriatic acid or sulfuric acid, are commonly used to dissolve hardened mortar or concrete residues.

To use hydrochloric acid to dissolve dry mortar, you will need to mix the acid with water in a ratio of 1 part acd to 10 parts water.

You should then apply the mixture to the dry mortar using a brush or spray botle.

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Let's balance

Moles of laughing gas

2 moles need 3 mol O_2

1 mol needs= 1.5mol O_2

moles of O_2.

#2

Moles Of O_2

Moles of smog

Mass

2N₂O + 3O₂ ⇒ 4NO₂

mol N₂O = 9 g : 44 g/mol = 0.205

mol O₂ = 3/2 x 0.205 = 0.3075

mass O₂ = 0.3075 x 32 g/mol = 9.84 g

=================================

mol O₂ = 7.5 g : 32 g/mol = 0.234

mol NO₂ (smog) = 4/3 x 0.234 = 0.312

mass NO₂ = 0.312 x 46 g/mol = 14.352 g

Answer:

a) 2f

B)CIO3+na

c)2NO2(g)

d)HSO3(h)

Explanation:

The sign of entropy depends on the number of gaseous substance in the system. In the first reaction, the number of gaseous particles increase in the product hence, randomness increases and thereby entropy is positive.

Entropy is a thermodynamic quantity which measures the randomness of the system. As the disorder in the system increases, the entropy increases and the entropy change is said to be positive in sign.

In the first reaction, in the product side, 2 moles of gaseous substance is formed, which increases the randomness, hence, entropy change is positive.

In the second reaction, the more ordered solid state is getting into less ordered aqueous state. Hence, S is positive.

For the third reaction, the number of moles of gas decreases from 3 to 2. Hence S is negative. For the last reaction, there is no change in number of moles or state of substance and no change in S.

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Answer:The balanced equation of Mg(s) + 2HCl(aq) ==> MgCl2(aq) + H2(g) does NOT tell you how many moles of Mg or H2 are present.  It only tells you the MOLE RATIO of the reactants and products.  Thus, 1 mole Mg reacts with 2 moles HCl to produce 1 mole of hydrogen gas.

Explanation:The balanced equation of Mg(s) + 2HCl(aq) ==> MgCl2(aq) + H2(g) does NOT tell you how many moles of Mg or H2 are present.  It only tells you the MOLE RATIO of the reactants and products.  Thus, 1 mole Mg reacts with 2 moles HCl to produce 1 mole of hydrogen gas.

Here, the limiting reactant is Mg. The number of moles of Mg is 0.019 and that of HCl is 0.134. The number of moles of H2 produced is 0.019.

The limiting reactant in a reaction is the reactant which is fewer in moles and thus, determine the yield of the reaction. In the given reaction, two moles of HCl reacts with one mole of magnesium metal.

Given the mass of Mg = 0.475 g

atomic mass = 24 g/mol

no.of moles  = 0.475 /24 = 0.124

volume of HCl = 0.124 L

molarity = 1.08 M

number of moles  = molarity × volume = 0.134

The limiting reactant here is magnesium. One  mole of  Mg reacts with 2 moles of HCl giving 1 mole of hydrogen gas. Then 0.019 moles will give 0.019 moles of hydrogen gas.

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At equilibrium, the number of moles of \(Cl_2\) (g) will be 0.2025 mol.

1: Write the balanced chemical equation:

\(C_O\)(g) + \(Cl_2\)(g) ⟶ \(C_OCl_2\)(g)

2: Set up an ICE table to track the changes in moles of the substances involved in the reaction.

Initial:

\(C_O\)(g) = 0.3500 mol

\(Cl_2\)(g) = 0.05500 mol

\(C_OCl_2\)(g) = 0 mol

Change:

\(C_O\)(g) = -x

\(Cl_2\)(g) = -x

\(C_OCl_2\)(g) = +x

Equilibrium:

\(C_O\)(g) = 0.3500 - x mol

\(Cl_2\)(g) = 0.05500 - x mol

\(C_OCl_2\)(g) = x mol

3: Write the expression for the equilibrium constant (Kc) using the concentrations of the species involved:

Kc = [\(C_OCl_2\)(g)] / [\(C_O\)(g)] * [\(Cl_2\)(g)]

4: Substitute the given equilibrium constant (Kc) value into the expression:

1.2 x \(10^3\) = x / (0.3500 - x) * (0.05500 - x)

5: Solve the equation for x. Rearrange the equation to obtain a quadratic equation:

1.2 x \(10^3\) * (0.3500 - x) * (0.05500 - x) = x

6: Simplify and solve the quadratic equation. This can be done by multiplying out the terms, rearranging the equation to standard quadratic form, and then using the quadratic formula.

7: After solving the quadratic equation, you will find two possible values for x. However, since the number of moles cannot be negative, we discard the negative solution.

8: The positive value of x represents the number of moles of \(Cl_2\)(g) at equilibrium. Substitute the value of x into the expression for \(Cl_2\)(g):

\(Cl_2\)(g) = 0.05500 - x

9: Calculate the value of \(Cl_2\)(g) at equilibrium:

\(Cl_2\)(g) = 0.05500 - x

\(Cl_2\)(g) = 0.05500 - (positive value of x)

10: Calculate the final value of \(Cl_2\) (g) at equilibrium to get the answer.

Therefore, at equilibrium, the number of moles of \(Cl_2\) (g) will be 0.2025 mol.

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Answer:

26%

Explanation:

The percent mass of potassium chloride in a solution is to be considered as the 26%.

Since

mass percent = (mass of solute / total mass of solution ) *100 %

Also,

mass of potassium chloride =25.00g

volume of water= 70.00 ml

Now

mass of solution = mass of solute + mass of solvent

= 25.00 + 70.0

= 95g

Now

mass percent = (mass of solute / total mass of solution ) * 100 %

= (25/95) * 100

= 26.31%

= 26%

Hence, The percent mass of potassium chloride in a solution is to be considered as the 26%.

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Answer:

d. the conjugate base.

Explanation:

The general reaction of a weak acid, HA, with a strong base YOH, is:

HA + YOH → A⁻ + H₂O + Y⁻

Where A⁻ is the conjugate base of the weak acid and Y⁻ usually is a strong electrolyte.

That means after he complete reaction you don't have weak acid nor strong base, just conjugate base that will be in equilibrium with water, thus (Strong electrolyte doesn't change pH:

A⁻ + H₂O ⇄ HA + OH⁻

As the equilibrium is producing OH⁻, the pH of the solution is being affected for the conjugate base

Right option:

Answer:1. metyletevinyl

4. (Z)-3-hydroxypropenal

Explanation:

Answer:

If by gas you mean oxygen it is O.

When the air around you is densely packed, it means the pressure is high.

The atmospheric pressure is directly proportional to air density.

When the air around a place is densely packed, it is an indication of high atmospheric pressure.

On the other hand, if the air around is loosely packed, it means the atmospheric pressure is also low.

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Answer:

No, your missing some bonds

Answer:

Explanation:

Formula for pH of a buffer solution

pH = pKa + log ( moles of sodium benzoate / moles  of benzoic acid)

pKa of benzoic acid = 4.2

Volume of solution is 1.5 L .

moles of sodium benzoate = .29 x 1.5 = .435 moles

moles of benzoic acid  = 1.5 x .34 = .51 moles

Addition of HCl will reduce concentration of salt and increase concentration of acid

moles of sodium benzoate after addition of HCl =  .435 - .054 = .381  moles

moles of benzoic acid  =  .51 + .054  = .564 moles

resultant pH = 4.2 + log ( .381 / .564 )

= 4.2 + log .6755

= 4.029

concentration of H⁺ or H₃O⁺ = \(10^{ - 4.029 }\)

= 9.35 X 10⁻⁵ M .

The concentration of the solution after adding 0.054 mol HCl to the final volume is \(9.35 \times 10^-^5 M .\)

Concentration is the amount of substance present in a specific place.

Calculate the moles of sodium benzoate

The mass of sodium benzoate is 0.29 M

The final volume is 1.5 L

0.29 × 1.5 = 0.435 moles

Now, moles of HCl after adding HCl

0.435 – 0.054 = 0.381  

Moles of benzoic acid

0.51 + 0.054  = 0.564 moles

By the formula of pH

pH = pKa + log ( mol of bezoate / mol of benzoic acid)

pKa value is 4.2

Putting the values

\(4.2 + log \dfrac{0.381}{0.564} \\\\4.2 + log 0.6755\\\\log = 4.029\)

The concentration of H+ is \(10^-^4^.^0^2^9\) = \(9.35 \times 10^-^5 M .\)

Thus, the concentration is \(9.35 \times 10^-^5 M .\)

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In a pond, the biotic factors include:

The abiotic factors are:

Biotic factors are the living components of an environment whose activities affect the environment.

Biotic factors include plants, animals, bacteria, fungi, etc,

Abiotic factors are the non-living components of an environment that affect the environment.

Biotic and abiotic factors interact with each other.

In a pond, the biotic factors include:

The abiotic factors include:

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we would need 2625.13 grams (or 2.62513 kilograms) of NaCl.

To calculate the mass of NaCl required to produce a 26.4 mol/L solution with a 1.7 L volume, we need to use the formula that relates the mass of solute, moles of solute, and molarity:Molarity (M) = moles of solute / liters of solution Rearranging this formula, we get:moles of solute = Molarity (M) x liters of solutionWe can use this formula to find the moles of NaCl needed:moles of NaCl = 26.4 mol/L x 1.7 L = 44.88 molNow, we can use the molar mass of NaCl to convert from moles to grams. The molar mass of NaCl is 58.44 g/mol:mass of NaCl = moles of NaCl x molar mass of NaClmass of NaCl = 44.88 mol x 58.44 g/mol = 2625.13 gTo produce a 26.4 mol/L solution with a 1.7 L volume.

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A container with a volume of nitrogen gas is filled to 1.50 atm of pressure and 23°C of temperature. Compute the amount of gas in moles led with as at 2.91 moles is 18.87 liters.

The three gas laws that make up the combined gas law, also known as a general gas equation, are Charle's law, Boyle's law, and Gay-Lussac law. The law shows the link between temperature, volume, and pressure for a given amount of gas.

PR/T=V

V= 2.91×150/23

V=18.87liters

According to Boyle's Law, gas volume increases as pressure lowers. Charles' Law states that a gas expands as its temperature rises. Also, according to Avogadro's Law, a gas's volume increases as its concentration does.

Either the total amount of gaseous substance or the number of gas moles.

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Answer:

Loam soil* is soil composed of equal parts sand, silt, and clay.

Explanation:

Answer:

Combustion, a chemical reaction between substances, usually including oxygen and usually accompanied by the generation of heat and light in the form of flame.

Explanation:

Hope this helps!! :))