Answer:
may sagot na pala ok bye thanks sa pts
Answer:
30!
Step-by-step explanation:
sorry if its wrong but hoped it helped :D
-4(X + 3) s-2 - 2x
What is the solution?
Please explain how to solve this
The solution to the variables are x = 7 and y = 4
How to determine the solution to the variables?From the question, we have the following parameters that can be used in our computation:
Shape = Triangle
The marks on the triangles imply that
The visibly smaller triangle is an equilateral triangleThe other triangle is an isosceles triangleSo, we have the following representation
3x - 5 = 5y - 4
3x - 5 = y + 12
Substitute 3x - 5 = y + 12 in 3x - 5 = 5y - 4
y + 12 = 5y - 4
Evaluate the like terms
4y = 16
So, we have
y = 4
Substitute y = 4 in 3x - 5 = y + 12
3x - 5 = 4 + 12
So, we have
3x = 21
This gives
x = 7
Hence, the values are x = 7 and y = 4
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Why is it wrong to draw y=ln(2x-5) this way?
well because he did not do it
Notice how
2x-5 = 2x - 2*2.5 = 2(x-2.5)
This means we can replace x with x-2.5 in the second step, in the "wrong way" column.
So,
y = ln(2x)
y = ln( 2(x-2.5) )
y = ln( 2x - 2*2.5 )
y = ln( 2x - 5 )
In the second step, the x-2.5 tells the reader to shift the curve 2.5 units to the right. Therefore, the 1/2 = 0.5 would shift to 0.5+2.5 = 3 as indicated by the correct graph.
perimiter question asap answer
The perimeter of the figure is 58 m.
To find the perimeter of the given figure we can divide the figure in three rectangles.
Rectangle 1:
Perimeter= 2 (l + w)
= 2(5 + 2)
= 2 x 7
= 14 m
Rectangle 2:
Perimeter= 2 (l + w)
= 2(5 + 1)
= 2 x 6
= 12 m
Rectangle 3:
Perimeter= 2 (l + w)
= 2(14 + 2)
= 2 x 16
= 32 m
So, the perimeter of the figure is
= 14 + 12 + 32
= 58 m
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2) A company that manufactures and ships widgets has two different sizes for boxes. One size box has a volume modeled by thefunction f () = 2,3 - 500x + 3000. The other size box has a volume modeled by the function g (*) = 423 - 20z? - 240x. Write asimplified polynomial expression with terms in descending order that models the combined volume for one small box and one large box.
The company manufactures two different box sizes
\(f(x)=x^3-500x+3000\)\(g(x)=4x^3-20x^2-240x\)To combine both polynomials you have to add them f(x)+g(x)
When you do so, you have to combine "like terms" together, this is to combine the terms that have the exact same variable from each equation.
\(f(x)+g(x)=x^3-500x+3000+4x^3-20x^2-240x\)First arrange all common terms togheter and solve the operation between them:
\(\begin{gathered} x^3+4x^3-20x^2-500x-240x+3000 \\ 5x^3-20x^2-740x+3000 \end{gathered}\)please help picture included:)
Answer:
y = 75
z = 43.3
Step-by-step explanation:
To find the value of y we use the trigonometric identity Sine.
\(sin\ 30 = \frac{y}{150}\\\\y=150*sin30\\y= 75\\\)
Now to find the value of z we can use the trigonometric identity Tangent.
\(tan\ 60=\frac{y}{z}\\\\z=\frac{y}{tan\ 60}\)
We know the value of y is 75 so it becomes,
\(z=\frac{75}{1.732} \\\\z=43.3\)
Answer:
y=-150 ' z = - 468
Step-by-step explanation:
Sin angle = opp/hyp
Cos 30 = y/150
y = 150 ×( cos30)
y= - 150
Tan angles = opp / adj
Tan 60 = - 150 / Z
Z = (-150) / tan 60
Z = (-150) / 0.32
Z= - 468
-1 1/2 - (+3 1/2) - 5/8
Answer:
-5 5/8
Step-by-step explanation:
-1 1/2 - (3 1/2) - 5/8
We can break down this equation:
-1 1/2 - 3 1/2 - 5/8
Now we find common denominator:
-1 4/8 - 3 4/8 - 5/8
Now we solve:
- 1 4/8 - 3 4/8 - 5/8 = - 5 5/8
Answer:
Step-by-step explanation:
Simplify the expression.
Exact Form:
\(-\frac{45}{8}\)
Decimal Form:
− 5.625
Mixed Number Form:
\(-5\frac{5}{8}\)
please helppppppppppppppppppppppppppppp
Answer:51
Step-by-step explanation:i did this quizzie before
If f (x) = 4x^3+ 1 then what is the remainder when f (x) is divided by x - 5?
Answer:
\(\frac{6}{x-5}\)
Step-by-step explanation:
Helping in the name of Jesus.
PLEASE HELP!!
Solve the following equation for b. Be sure to take into account whether a letter is
capitalized or not.
Answer:
\(b = \frac{G^2R}{m}\)
Step-by-step explanation:
\(\frac{G^2}{b} = \frac{m}{R}\)
Cross Multiply
\(bm=G^2R\)
Divide both sides of the equation by m
\(\frac{bm}{m} = \frac{G^2R}{m}\\ \\b = \frac{G^2R}{m}\)
graph the function: f(x) = {x+1 if x<0}
{2 if 0<- x <-1 on the coordinate plane}
{x if x>1}
The graph of the function f(x) = { x + 1 } at different domain are plotted and attached
{ if x < 0 }
{ if 0 < x < 1 }
{ if x > 1 }
What is a graph?In mathematics, a graph is a visual representation or diagram that shows facts or values in an ordered way.
The relationships between two or more items are frequently represented by the points on a graph.
The graph of f(x) = x + 1 for different domain is plotted and attached
{ if x < 0 } the domain includes { -∞....-3 -2 -1}
{ if 0 < x < 1 } the domain includes { 0...0.7 0.8 0.9}
{ if x > 1 } the domain includes { 0 1 2 3 4 5...∞ }
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Recall that with base-ten blocks: 1 long 10 units, 1 flat 10 longs, and 1 block 10 flats. What is the fewest number of multibase blocks that can be used to represent the corresponding numeral in the given base?
a. 20 longs in base seven
b. 10 longs in base three
a. The answer is: The fewest number of multibase blocks required to represent 20 longs in base seven is 2 flats.
b. The answer is: The fewest number of multibase blocks required to represent 10 longs in base three is 3 flats and 1 unit.
a. To represent 20 longs in base seven, we need to find the fewest number of multibase blocks required.
In base seven, we have the following conversions:
1 long = 1 unit
1 flat = 10 units
1 block = 10 flats
To represent 20 longs, we can use 2 flats (each flat representing 10 units) and 0 units since there are no remaining units.
So, the fewest number of multibase blocks required would be 2 flats.
Therefore, the answer is: The fewest number of multibase blocks required to represent 20 longs in base seven is 2 flats.
b. To represent 10 longs in base three, we need to find the fewest number of multibase blocks required.
In base three, we have the following conversions:
1 long = 1 unit
1 flat = 3 units
1 block = 3 flats
To represent 10 longs, we can use 3 flats (each flat representing 3 units) and 1 unit since there is one remaining unit.
So, the fewest number of multibase blocks required would be 3 flats and 1 unit.
Therefore, the answer is: The fewest number of multibase blocks required to represent 10 longs in base three is 3 flats and 1 unit.
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What’s the correct answer for this?
Answer:
Answer is the first one :)
Step-by-step explanation:
√(-7-5)² + (-7-9)²
answer is 20
hope this helps
Answer:
A.
Step-by-step explanation:
In the attached file
Piper has a smart phone data plan that costs $45 per month that includes 5 GB of data, but will charge an extra $25 per GB over the included amount. How much would Piper have to pay in a month where she used 5 GB over the limit? How much would Piper have to pay in a month where she used went over by xx GB?
Answer : Piper would have to pay $170 in a month if she used 5 GB over the limit and $95 in a month if she used 2 GB.
Step-by-step explanation:
45 + 25x
45 + 25(5) = 170
45 + 25(2) = 95
mega mart sells a large 5kg cake for $2500 while a 2kg chocolate cake cost $1200 what is the cheapest price sam would payfor 10kg of cake for the party
The cheapest price Sam would pay for 10kg of cake for the party is $5000 from Mega Mart.
To find the cheapest price Sam would pay for 10kg of cake for the party, we need to compare the prices of the available cakes and determine the most cost-effective option.
At Mega Mart, a 5kg cake costs $2500.
Therefore, the price per kilogram for this cake is:
Price per kilogram at Mega Mart = $2500 / 5kg = $500/kg.
At the same time, a 2kg chocolate cake costs $1200.
So, the price per kilogram for this cake is:
Price per kilogram for the chocolate cake = $1200 / 2kg = $600/kg.
Now, let's calculate the total price for 10kg of cake from each option:
Total price at Mega Mart for 10kg = $500/kg \(\times\) 10kg = $5000.
Total price for 10kg of chocolate cake = $600/kg \(\times\) 10kg = $6000.
Comparing the two options, we see that the Mega Mart cake is the more cost-effective choice.
Sam would pay a total of $5000 for 10kg of cake from Mega Mart, whereas the chocolate cake would cost $6000 for the same quantity.
Therefore, the cheapest price Sam would pay for 10kg of cake for the party is $5000 from Mega Mart.
In summary, Sam would pay the cheapest price of $5000 to purchase 10kg of cake for the party from Mega Mart.
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On average, Nancy has noticed that 18 trucks pass by her apartment daily (24 hours). In order to find the probability that more than 4 trucks will pass her apartment in a 5-hour time period using the Poisson distribution, find the average number of trucks per 5 hours. Round your answer to three decimal places, if necessary.
Answer:
the average number of trucks per 5 hours is 3.750 trucks per 5 hours
Step-by-step explanation:
The computation of the average number of trucks per 5 hours is given below:
= Number of trucks passed ÷ time taken × given time
= 18 trucks ÷ 24 trucks × 5
= 3.750 trucks per 5 hours
Hence, the average number of trucks per 5 hours is 3.750 trucks per 5 hours
The same is to be considered by applying the above formula
can u help me with me work pls
________________________
Answer
A Linear function
________________________
B x^2
The sum of the present value of 1 paid at the end of n periods and 1 paid at the end of 2n periods is 1. Find (1 i) 2n
Answer:
\((1 + i)^{2n} = \frac{4}{(-1 \± \sqrt{5})^2}\)
Step-by-step explanation:
Using Present Value formula, we have that:
The present value at end of n period is
\(PV_1 = \frac{1}{(1 + i)^n}\)
The present value at end of 2n period is
\(PV_2 = \frac{1}{(1 + i)^{2n}}\)
\(Sum = PV_1 + PV_2\)
And
\(Sum = 1\)
So, we have:
\(PV_1 + PV_2 = 1\)
Substitute values for PV1 and PV2
\(\frac{1}{(1 + i)^n} + \frac{1}{(1 + i)^{2n}}= 1\)
Solving for:
\((1 + i)^{2n\)
\(\frac{1}{(1 + i)^n} + \frac{1}{(1 + i)^{2n}}= 1\)
This can be expressed as
\(\frac{1}{(1 + i)^n} + (\frac{1}{(1 + i)^{n}})^2= 1\)
Let
\(a = \frac{1}{(1 + i)^n}\)
So, we have:
\(a + a^2 = 1\)
Equate to 0
\(a + a^2 - 1= 0\)
\(a^2 + a - 1= 0\)
Using quadratic formula:
\(a = \frac{-B \± \sqrt{B^2 -4AC}}{2A}\)
Where A=1; B =1 and C = -1
\(a = \frac{-1 \± \sqrt{1^2 -4 * 1 * -1}}{2 * 1}\)
\(a = \frac{-1 \± \sqrt{1 +4}}{2 }\)
\(a = \frac{-1 \± \sqrt{5}}{2 }\)
Recall that:
\(a = \frac{1}{(1 + i)^n}\)
So, we have:
\(\frac{1}{(1 + i)^n} = \frac{-1 \± \sqrt{5}}{2 }\)
Invert both sides
\((1 + i)^n = \frac{2}{-1 \± \sqrt{5}}\)
Square both sides
\(((1 + i)^n)^2 = (\frac{2}{-1 \± \sqrt{5}})^2\)
\((1 + i)^{2n} = (\frac{2}{-1 \± \sqrt{5}})^2\)
\((1 + i)^{2n} = \frac{4}{(-1 \± \sqrt{5})^2}\)
Select the correct answer from each drop-down menu.
The total area of the three triangles is
square units.
The area of the figure is
square units.
The total area of the three triangles is square units is 36 and the area of the figure is square units is 60.
What is the triangle?The triangle can be defined as a three-sided polygon in geometry, and it consists of three vertices and three edges. The sum of all the angles inside the triangle is 180°.
From the figure, the area of triangles can be calculated using the:
Area = (1/2)height×base length
Area of three triangle = 1/2(4×6) + 1/2(6×4) + 1/2(4×6)
Area of three triangle = 1/2(24×3) = 36 square units
Area of the figure = area of three triangle + area of the rectangle
= 36 + 6×4
= 60 square units
Thus, the total area of the three triangles is square units is 36 and the area of the figure is square units is 60.
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Construct the graph of the direct proportion y=kx for
k=0
Of what line should I put it as? For example straight, ---------------
or up "forever" /
Welp, I think this is it?
The proportion y = kx for k = 0 will be y = 0 and construct a horizontal line passing through the origin that is the x-axis.
How to plot a graph?A graph is a diagram that shows the fluctuation of one variable in relation to one or more other variables.
In order to plot the graph, we need to find out y's values corresponding to x's value
After that, we need to substitute the values of x's and y's into the coordinate geometry.
Given the direct proportion
y = kx
Now for k = 0
y = 0 so y = 0 is a horizontal line passing through the origin that is the x-axis.
In the graph below I have attached
Black line y = 4x ( k = 4)
Red line y = x ( k = 1)
Since k is decreasing the lines are becoming horizontal.
Hence "The proportion y = kx for k = 0 will be y = 0 and construct a horizontal line passing through the origin that is the x-axis".
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Which set of angle measures can be used to construct an acute scalene triangle?
Answer:
C = 36°, 57°, 87°
Step-by-step explanation:
scalene = all angles are different.
acute = all angles are under 90°.
triangle = all angles add up to 180°.
The only option that works for this is C) 36°, 57°, 87°
2,-1,-4,-7 78TH term
Answer:
a= 2 , d= a²-a¹--> -1-2= -3
78th term
a⁷⁸= a+77d
=> 2 + 77(-3)
=> 2 + (-231)
=> -229
1. Global warming creates local problems. Projections forecast that even a moderate air temperature increase of only 1.8 °F could cause brook trout distributions to decrease dramatically. For example, such a temperature increase would take Washburn county's 19 ponds that support brook trout down to 10 ponds. What would be the percent decrease in the number of ponds that support brook trout?
The percent decrease in the number of ponds that support brook trout would be approximately 47.37%.
To calculate the percent decrease in the number of ponds that support brook trout, we need to determine the difference between the initial number of ponds and the final number of ponds, and then express that difference as a percentage of the initial number of ponds.
Initial number of ponds: 19
Final number of ponds: 10
To calculate the percent decrease, we can use the following formula:
Percent Decrease = (Difference / Initial Value) * 100
Let's apply this formula to the given data:
Difference = Initial number of ponds - Final number of ponds
Difference = 19 - 10
Difference = 9
Percent Decrease = (9 / 19) * 100
Now, let's calculate the percent decrease:
Percent Decrease = (9 / 19) * 100
Percent Decrease ≈ 47.37%
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Select the correct answer. Joel and Kevin are each putting money in a savings account to buy a new bicycle. The amount, in dollars, in Joel's savings account, x weeks after the start of the year, is modeled by function j. The amount of money in Kevin's account, at the same time, is modeled by function k. j(x) = 25 + 3x k(x) = 15 + 2x Which function correctly represents how much more money, in dollars, is in Joel's account than in Kevin's account x weeks after the start of the year? O A. (j − k)(x) = 40 + 5x (j − k)(x) = 40 + x (j-k)(x) = 10 + 5x (j-k)(x) = 10 + x O B. C. O D. Reset dtry Next
The correct answer is (j - k)(x) = 10 + x.
To find the difference in the amount of money between Joel's and Kevin's accounts, we subtract the value of Kevin's account (k(x)) from Joel's account (j(x)).
(j - k)(x) = (25 + 3x) - (15 + 2x)
= 25 - 15 + 3x - 2x
= 10 + x
This expression represents how much more money is in Joel's account compared to Kevin's account after x weeks.
Therefore, the correct function is (j - k)(x) = 10 + x.
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what is the value of 6n 2 when 3
Answer:6(3) - 2
18 - 2 = 16
Step-by-step explanation:
6(3) - 2
18 - 2 = 16
a triangular prism is 37 millimeters long and has a triangular face with a base of 42 millimeters and a height of 28 millimeters.The other two sides of the triangle are each 35 millimeters.What is the surface area of the triangular prism?
No links pls
Answer: 4145.43
Have a great day! ;)
Simplify the expression: 2(3 + 10u) =
Given the diagram below, what is
cos(45*)?
8 √2
450
Triangle not drawn to scale
O A. 1/√2
O B. 2 √2
O C. 4 √2
O D. √2
The value of cos(45°) is √2/2. The correct answer choice is D. √2.
In the given diagram, the angle labeled as 45° is part of a right triangle. To find the value of cos(45°), we need to determine the ratio of the adjacent side to the hypotenuse.
Since the angle is 45°, we can assume that the triangle is an isosceles right triangle, meaning the two legs are congruent. Let's assume the length of one leg is x. Then, by the Pythagorean theorem, the length of the hypotenuse would be x√2.
Now, using the definition of cosine, which is adjacent/hypotenuse, we can substitute the values:
cos(45°) = x/(x√2) = 1/√2
Simplifying further, we rationalize the denominator:
cos(45°) = 1/√2 * √2/√2 = √2/2
Therefore, the value of cos(45°) is √2/2.
The correct answer choice is D. √2.
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Graph that line with slope -1 passing through the point (-2,4)
Answer:
To graph the line with slope -1 passing through the point (-2,4), we can use the point-slope form of the equation of a line, which is:
y - y1 = m(x - x1)where m is the slope of the line, and (x1, y1) is the given point on the line. Substituting the given values, we get:
y - 4 = -1(x - (-2))Simplifying this equation, we get:
y - 4 = -x - 2y = -x + 2Now we can graph this line by plotting the given point (-2,4), and then using the slope of -1 to find one or more additional points on the line. We can do this by starting at the given point and then moving one unit down (since the slope is negative) and one unit to the right (since the slope is -1). This gives us the point (-1,3). We can then connect these two points to graph the line.
GRAPHICAL REPRESENTATION:|
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Write an explicit formula for an, the nth term of the sequence 30, 35, 40
Answer:
The sequence is increasing by 5 at each step. So, we can write:
a1 = 30
a2 = 30 + 5 = 35
a3 = 30 + 25 = 40
a4 = 30 + 35 = 45
a5 = 30 + 4*5 = 50
We notice that the nth term is given by:
an = 30 + (n-1)5
So, the explicit formula for the nth term is:
an = 25n + 5