Answer:
46.6028 Miles
Step-by-step explanation:
If you're looking for the amount of miles they'd traveled, this is the exact amount. If you're looking for your answer in Kilometers, they'd travel 70 km total.
35 km/hr x 2 = 75 km total
Hope this helped! If it didn't let me know what you need help solving.
Cam used 2/3 of the flour from a 5-lb bag to make all of her holiday cookies. How much flour, in pounds, is left in the bag?
Answer:
3.3lbs
Step-by-step explanation:
5 x 2/3 = 3.3
Find the constants m and b in the linear function f(x)=mx+b so that f(7)=9 and the straight line represented by f has slope −3.
m=
b=
To find the constants m and b in the linear function f(x) = mx + b, we can use the given conditions f(7) = 9 and a slope of -3.
The value of f(7) represents the y-coordinate of the point on the line when x = 7. So, substituting x = 7 into the equation, we get 9 = 7m + b.
The slope of a linear function is given by the coefficient of x, which in this case is -3. So, we have m = -3.
Now, we can substitute the value of m into the equation obtained from f(7). We get 9 = 7(-3) + b, which simplifies to 9 = -21 + b.
Solving for b, we find b = 30.
Therefore, the constants for the linear function f(x) = mx + b that satisfy the given conditions are m = -3 and b = 30.
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I think its kinda easy but the I couldn't answer for positive
|x^3-1|-7=0
The solution to the equation is x = 2
How to determine the solution to the equationFrom the question, we have the following parameters that can be used in our computation:
|x^3-1|-7=0
Add 7 to both sides
So, we have
|x^3-1| = 7
Remove the absolute bracket
x^3 - 1 = 7
So, we have
x^3 = 8
Take tge cube roots of both sides
x = 2
Hence, the solution is 2
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certain standardized math exams have a mena of 120 and a standarad deviation of 20. of the students who take this exam. what percent could you expect to score betwen 60 amd 120
After finding the z score, total 49.865% you could expect to score between 60 and 120.
Math exams mean(μ) = 120
Math exams standard deviation(σ) = 20
We have to determine the percent you could expect to score between 60 and 120.
The area total included to the left of any score or value is indicated in the Z-score table (x). The top row and the first column of the Z-table represent the Z-values, while all of the numbers in the middle represent the areas.
P(60 < x < 120) = P((60 - 120)/20 < (x - μ)/σ < (120 - 120)/20)
Simplifying
P(60 < x < 120) = P((-60)/20 < (x - μ)/σ < 0/20)
P(60 < x < 120) = P(-3 < Z < 0)
We can write this as
P(60 < x < 120) = P(Z > -3) - P(Z < 0)
P(60 < x < 120) = 0.99865 - 0.5
P(60 < x < 120) = 0.49865
P(60 < x < 120) = 49.865%
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help me pls it’s not too much!
is y = 17 − 20x a function
Answer:
Yes, it is a linear function.
A greengrocer buys 20 cases of oranges at a cost of $15 per case. Each case contains 10 kg of oranges. If he sells the oranges at $4/kg, how many kilograms must he sell before he makes a profit? If he sells all the oranges what will be his profit?
Answer:greengrocer should Dell 17 kg before profit. 500$ profit
Step-by-step explanation:
How many terms are in (3x^2-3)(3x^2+3)
The number of terms in the expression given is; 2.
How many term are in the expression given?It follows from the task content that the expression given is; (3x^2-3)(3x^2+3).
It therefore follows the converse of law regarding difference of two squares that the expression given can be rewritten as;
= 9x⁴ -9
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Validation of the model and answering the question "what are my options" occur in the ___ phase of the IDC.
A. choice
B. design
C. intelligence
D. implantation
Validation of the model and answering the question "what are my options" occur in the design phase of the IDC (Intelligence, Design, and Choice) framework.
The IDC framework is a decision-making process that consists of three phases: Intelligence, Design, and Choice. Each phase corresponds to a specific set of activities and objectives.
In the intelligence phase, the focus is on gathering information, identifying the problem or decision to be made, and understanding the factors and variables involved. This phase involves data collection, analysis, and exploration to gain insights and knowledge about the problem domain.
In the design phase, the emphasis is on developing and evaluating potential options or solutions to address the problem or decision at hand. This phase involves creating models, prototypes, or simulations to represent the problem and exploring different alternatives.
Validation of the model is an important aspect of this phase to ensure that the proposed solutions align with the problem requirements and objectives.
The question "what are my options" is a fundamental question that arises during the design phase. It implies the exploration and generation of various possible choices or solutions that can be evaluated and compared.
Therefore, the design phase of the IDC framework encompasses the activities of validating the model and answering the question "what are my options." It involves refining and testing potential solutions to make informed decisions in the subsequent choice phase.
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A group of 75 math students were asked whether they
like algebra and whether they like geometry. A total of
45 students like algebra, 53 like geometry, and 6 do
not like either subject.
Algebra vs. Geometry
Likes Algebra
Does Not
Like Algebra
Total
Likes
Geometry
Mark this and return
a
3
53
Does Not
Like Geometry
b
6
e
Total
45
P
75
What are the correct values of a, b, c, d, and e?
a 16, b = 29, c = 22, d = 30, e = 24
a = 29, b = 16, c = 30, d = 22, e = 24
a 16, b = 29, c = 24, d = 22, e = 30
H
a = 29, b = 16, c = 24, d = 30, e = 22
The correct values for a, b, c, d, and e are a = 16, b = 29, c = 24, d = 22, and e = 30 for group of 75 students on asking whether they like Algebra or Geometry.
For the values of a, b, c, d, and e, we can use the information provided in the table. Let's break it down step-by-step:
We are given that a total of 75 math students were surveyed. Therefore, the total number of students should be equal to the sum of the students who like algebra, the students who like geometry, and the students who do not like either subject.
75 = 45 (Likes Algebra) + 53 (Likes Geometry) + 6 (Does Not Like Either)
Simplifying this equation, we have:
75 = 98 + 6
75 = 104
This equation is incorrect, so we can eliminate options c and d.
Now, let's look at the information given for the students who do not like geometry. We know that a + b = 6, where a represents the number of students who like algebra and do not like geometry, and b represents the number of students who do not like algebra and do not like geometry.
Using the correct values for a and b, we have:
16 + b = 6
b = 6 - 16
b = -10
Since we can't have a negative value for the number of students, option a is also incorrect.
The remaining option is option e, where a = 29, b = 16, c = 24, d = 22, and e = 30. Let's verify if these values satisfy all the given conditions.
Likes Algebra: a + c = 29 + 24 = 53 (Matches the given value)
Does Not Like Algebra: b + d = 16 + 22 = 38 (Matches the given value)
Likes Geometry: c + d = 24 + 22 = 46 (Matches the given value)
Does Not Like Geometry: b + e = 16 + 30 = 46 (Matches the given value)
All the values satisfy the given conditions, confirming that option e (a = 29, b = 16, c = 24, d = 22, and e = 30) is the correct answer.
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What is the value of f(4) when f(x) = -3x^2 + 30x + 22
Answer:
94
Step-by-step explanation:
Which of the following is a solution to 2sin^2x+sinx-1=0?
A. 45 degrees
B. 200 degrees
C. 240 degrees
D. 270 degrees
E. 330 degrees
Answer
\(x = \frac{\pi }{6} + 2\pi n, \frac{5\pi }{6} + 2\pi n, \frac{3\pi }{2} + 2\pi n\), for any integer n
Answer:
D or 270°
Step-by-step explanation:
2sin^2x+sinx-1
2sin^2(270°)+sin(270°)-1=0
by considering the curve traced by the parametrisation z(t) = t 2 it3 with −1 ≤ t ≤ 1, show why the condition that z ′ (t) never vanishes is necessary to ensure that smooth curves have no cusps.
To ensure that smooth curves have no cusps, we need to require that z'(t) never vanishes. This condition ensures that the tangent line to the curve changes smoothly and continuously as we move along the curve, without any abrupt changes in direction that would create cusps.
To understand why the condition that z'(t) never vanishes is necessary to ensure that smooth curves have no cusps, we first need to understand what a cusp is. A cusp is a point on a curve where the tangent line changes direction abruptly, creating a sharp point or corner in the curve.
Now, let's consider the curve traced by the parametrization z(t) = t^2it^3 with -1 ≤ t ≤ 1. To determine whether this curve has any cusps, we need to calculate the derivative of z(t) with respect to t:
z'(t) = 2it^3 + 3t^2i
If we set z'(t) equal to zero and solve for t, we get:
2it^3 + 3t^2i = 0
t^2(2i t + 3i) = 0
This equation has two solutions: t = 0 and t = -3/2i. These are the points on the curve where z'(t) vanishes.
At t = 0, the curve passes through the origin, which is a smooth point. However, at t = -3/2i, the curve has a cusp. To see why, we can look at the behavior of z(t) near this point.
As t approaches -3/2i from either side, the magnitude of t^2 increases without bound, while the magnitude of t^3 remains constant. This means that z(t) approaches infinity along a straight line with slope -3/2i. In other words, the curve has a sharp corner or cusp at this point.
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Help me find the area here! 6th grade math
63 cm2
hope it helps
you
63 CM answer
Given (x – 7)2 = 36, select the values of x. x = 13 x = 1 x = –29 x = 42
The values of x that satisfy the equation are x = 13 and x = 1. The other two options, x = -29 and x = 42, are not solutions to the equation.
What is equation?A mathematical statement proving the equality of two expressions is known as an equation. The left-hand side (LHS) and the right-hand side (RHS), which are commonly joined by the equal sign (=), make up this structure.
Many mathematical operations, such as addition, subtraction, multiplication, division, exponents, and roots, can be used in equations. Finding the variable value or variables that make an equation true is the aim when solving an equation.
Based on their degree, or the highest power of the variable in the equation, equations can be categorized. A quadratic equation, for instance, has a degree of 2, while a linear equation has a degree of 1. Moreover, the number of solutions to an equation can be used to categorize it.
Starting with the equation:
(x – 7)^2 = 36
Taking the square root of both sides, we get:
x – 7 = ±6
Solving for x in each case, we get:
x – 7 = 6, which gives x = 13
or
x – 7 = -6, which gives x = 1
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Below is the table of values for
the following function.
f(x)=x²-3x - 4
XX
Y
-3 -2 -1 0 1
2
14 6 0 -4 -6 -6
3
-4
4
0
Identify the ordered pairs of the zeroes.
(4,0); ([?], [])
The ordered pairs of the zeroes for the function f(x) = x² - 3x - 4 are (-1, 0), (4, 0), and (0, -4).
To identify the ordered pairs of the zeroes of the function f(x) = x² - 3x - 4, we need to find the values of x for which f(x) equals zero. In other words, we are looking for the x-intercepts or the points where the graph of the function crosses the x-axis.
Looking at the table of values provided, we can see that f(x) equals zero for x = -1, x = 4, and x = 0. These are the x-values corresponding to the points where the function crosses the x-axis.
Now, let's write the ordered pairs of the zeroes:
For x = -1, f(-1) = (-1)² - 3(-1) - 4 = 1 + 3 - 4 = 0. Therefore, the ordered pair of the zero x = -1 is (-1, 0).
For x = 4, f(4) = (4)² - 3(4) - 4 = 16 - 12 - 4 = 0. Thus, the ordered pair of the zero x = 4 is (4, 0).
For x = 0, f(0) = (0)² - 3(0) - 4 = 0 - 0 - 4 = -4. However, in the given table, there seems to be an error in the corresponding y-value for x = 0, which is listed as 3. The correct ordered pair for x = 0 should be (0, -4) instead of (0, 3).
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is 3+5(9+2n)equal to48+5n
Determine, if the vectors 0 1 0 1 are linearly independent or not. Do these four vectors span R4? (In other words, is it a generating system?) What about C4?
The vector v1 = (0, 1, 0, 1) is linearly independent.
The four vectors v1, v2, v3, and v4 span R4.
The four vectors v1, v2, v3, and v4 span C4.
The vector 0 1 0 1 is a vector in R4, which means that it has four components.
We can write this vector as:
v1 = (0, 1, 0, 1)
To determine if this vector is linearly independent, we need to check if there exist constants c1 such that:
c1 v1 = 0
where 0 is the zero vector in R4.
If c1 is nonzero, then we can divide both sides by c1 to get:
v1 = 0
But this is impossible since v1 is not the zero vector.
Therefore, the only solution is c1 = 0.
This shows that v1 is linearly independent.
Now, we need to check if the four vectors v1, v2, v3, and v4 span R4. To do this, we need to check if every vector in R4 can be written as a linear combination of v1, v2, v3, and v4.
One way to check this is to write the four vectors as the columns of a matrix A:
A = [0 1 1 1; 1 0 1 1; 0 0 0 0; 1 1 1 0]
Then we can use row reduction to check if the matrix A has a pivot in every row. If it does, then the columns of A are linearly independent and span R4.
Performing row reduction on A, we get:
R = [1 0 0 -1; 0 1 0 -1; 0 0 1 1; 0 0 0 0]
Since R has a pivot in every row, the columns of A are linearly independent and span R4.
Therefore, the four vectors v1, v2, v3, and v4 span R4.
Finally, we need to check if the four vectors v1, v2, v3, and v4 span C4. Since C4 is the space of complex vectors with four components, we can write the four vectors as:
v1 = (0, 1, 0, 1)
v2 = (i, 0, 0, 0)
v3 = (0, i, 0, 0)
v4 = (0, 0, i, 0)
We can use the same method as above to check if these vectors span C4.
Writing them as the columns of a matrix A and performing row reduction, we get:
R = [1 0 0 0; 0 1 0 0; 0 0 1 0; 0 0 0 1]
Since R has a pivot in every row, the columns of A are linearly independent and span C4.
Therefore, the four vectors v1, v2, v3, and v4 span C4.
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The given vector 0 1 0 1 has two non-zero entries. To check if this vector is linearly independent, we need to check if it can be expressed as a linear combination of the other vectors. However, since we are not given any other vectors, we cannot determine if the given vector is linearly independent or not.
As for whether the four vectors span R4, we need to check if any vector in R4 can be expressed as a linear combination of these four vectors. Again, since we are only given one vector, we cannot determine if they span R4.
Similarly, we cannot determine if the given vector or the four vectors span C4, as we do not have any information about other vectors. In conclusion, without additional information or vectors, we cannot determine if the given vector or the four vectors are linearly independent or span any vector space.
The given set of vectors consists of only one vector, (0, 1, 0, 1), which is a single non-zero vector.
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A city bus driver says the number of miles to gallons of gas for his bus can be represented by the ratio 12 : 4. How many miles can the bus travel on 1 gallon of gas?
Answer:
The bus can travel 3 miles with 1 gallon of gas
Step-by-step explanation:
Hope this helps!
Eleven less than seven times a number is five more than six time the number. What is the number?
Answer:
Thus, the number is equal to x =16 the Answer 16 Basically
which distance metric would best describe this: how far apart
are two binary vectors of the same length ? justify your
answer?
The Hamming distance metric is the best metric for describing how far apart two binary vectors of the same length are. The reason for this is that the Hamming distance is a measure of the difference between two strings of the same length.
Its value is the number of positions in which two corresponding symbols differ.To compute the Hamming distance, two binary strings of the same length are compared by comparing their corresponding symbols at each position and counting the number of positions at which they differ.
The Hamming distance is used in error-correcting codes, cryptography, and other applications. Therefore, the Hamming distance metric is the best for this particular question.
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how do you solve -3 + 5 +6g =11 - 3g?
Final Answer: \(g = 1\)
Steps/Reasons/Explanation:
Question: How do you solve \(-3 + 5 +6g = 11 - 3g?\)
Step 1: Simplify \(-3 + 5 + 6g\) to \(6g + 2\).
\(6g + 2 = 11 - 3g\)
Step 2: Subtract \(2\) from both sides.
\(6g = 11 - 3g - 2\)
Step 3: Simplify \(11 - 3g - 2\) to \(-3g + 9\).
\(6g = -3g + 9\)
Step 4: Add \(3g\) to both sides.
\(6g + 3g = 9\)
Step 5: Simplify \(6g + 3g\) to \(9g\).
\(9g = 9\)
Step 6: Divide both sides by \(9\).
\(g = 1\)
~I hope I helped you :)~
Jami went to have a manicure that cost $25. She wanted to tip the technician 20% and
tax is 5.75. How much did she spend total for the manicure .
7 grade work
Answer: $35.75
Step-by-step explanation:
1) $25 for the manicure
2) $25*(0.20) = $5 for the tip
3) $5.75 for the tip
$25 + $5 + $5.75 for the total
$35.75 total
1. Please answer the following questions in detail:
a) What are the major differences between Normal and Log-normal
distribution?
b) How do you select which one would fit better to your
data?
The Normal distribution is symmetric and ranges from negative to positive infinity, while the Log-normal distribution is skewed and only takes positive values. To select the better fit for data, consider characteristics (positivity and skewness favor Log-normal, symmetry favors Normal), hypothesis testing, visualization, and statistical tests.
Let's analyze each section separately:
a) The major differences between the Normal and Log-normal distributions are:
Normal Distribution: The Normal distribution, also known as the Gaussian distribution, is a symmetric probability distribution that is defined by its mean (μ) and standard deviation (σ). It follows a bell-shaped curve and is often used to model naturally occurring phenomena. The range of values extends from negative infinity to positive infinity.
Log-normal Distribution: The Log-normal distribution is a skewed probability distribution that arises when the logarithm of a random variable follows a normal distribution. It is characterized by its parameters mu (μ) and sigma (σ) of the underlying normal distribution. Unlike the Normal distribution, the Log-normal distribution only takes positive values.
b) Selecting which distribution fits the data better depends on the nature of the data and the research question at hand. Here are a few considerations:
1. Data Characteristics: If the data consists of positive values and the distribution appears to be skewed, the Log-normal distribution might be more appropriate. On the other hand, if the data is symmetric and unbounded, the Normal distribution may be a better fit.
2. Hypothesis Testing: If you have a specific hypothesis to test or a theoretical justification for choosing one distribution over the other, it is advisable to use that distribution.
3. Visualization: Plotting the data and comparing it to the shapes of the Normal and Log-normal distributions can provide visual insights into which distribution aligns better with the data.
4. Statistical Tests: Statistical tests such as the Kolmogorov-Smirnov test or the Anderson-Darling test can be used to assess the goodness-of-fit for each distribution and determine which one provides a better fit to the data.
In summary, selecting the appropriate distribution involves considering the characteristics of the data, the research question, and statistical tests. Visualization and hypothesis testing can further aid in determining the best fit distribution.
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How do you find the coordinates of two points given an equation?
To find the coordinates of two points given an equation, you can substitute different values of x into the equation and solve for y, or by using the symmetry property of the equation.
The first method to find the coordinates of two points is to substitute different values of x into the equation and solve for y. Once you have the coordinates of the two points, you can use them to graph the equation and further analyze the function.
For example, if the equation is y = 2x + 1, you can substitute x = 0 and x = 1 into the equation to find the coordinates of the two points. Substituting x = 0 gives y = 2(0) + 1 = 1, so the first point is (0,1). Substituting x = 1 gives y = 2(1) + 1 = 3, so the second point is (1,3).
Another way to find the coordinates of two points is by using the symmetry property of the equation. For example, if the equation is y = -x^2 + 4x -3, you can substitute x = -1 and x = 1 into the equation and solve for y.
In conclusion, finding the coordinates of two points given an equation involves substituting different values of x into the equation and solving for y, or by using the symmetry property of the equation.
The coordinates of the two points will be used to graph the equation and further analyze the function.
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Can anyone help me out on this, please? I'll mark you brilliant. :)
try 22
Step-by-step explanation: Maybe it could work, hope it. helps,
Khan?
Find the absolute value of -0.02
Select the expression that can be used to find the volume of this rectangular prism.
A.
(
6
×
3
)
+
15
=
33
i
n
.
3
B.
(
3
×
15
)
+
6
=
51
i
n
.
3
C.
(
3
×
6
)
+
(
3
×
15
)
=
810
i
n
.
3
D.
(
3
×
6
)
×
15
=
270
i
n
.
3
The correct expression to find the volume of a rectangular prism is D. (3 × 6) × 15 = 270 in.3.
What is expression?Expression is a word, phrase, or gesture that conveys an idea, thought, or feeling. It is an outward representation of an emotion, attitude, or opinion. Expressions can be verbal, physical, or written. They can also take the form of art, music, or dance. Expression is used to communicate and express emotions, thoughts, and ideas. It can be a powerful tool to create a connection with others and build relationships.
The correct expression to find the volume of a rectangular prism is D. (3 × 6) × 15 = 270 in.3. This expression involves multiplying the length, width, and height of the rectangular prism in order to calculate the total volume. In this case, the length is 3, the width is 6, and the height is 15. If these values are multiplied together, the result is 270 in.3, which is the total volume of the rectangular prism.
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Find the test statistic t0 for a sample with n = 12, = 30.2, s = 2.2, and α = 0.01 if H0 : µ = 28. Round your answer to three decimal places.
The test statistic t0 is 5.291 (rounded to three decimal places).
To find the test statistic t0, we can use the formula:
t0 = (x - µ) / (s / √n)
where x is the sample mean, µ is the population mean (under the null hypothesis), s is the sample standard deviation, and n is the sample size.
Substituting the given values, we get:
t0 = (30.2 - 28) / (2.2 / √12)
t0 = 5.291
Since this is a one-tailed test with a significance level of 0.01, we need to compare t0 with the critical value from the t-distribution table with 11 degrees of freedom (n-1) and a one-tailed α of 0.01.
Looking at the table, we find the critical value to be 2.718. Since t0 is greater than the critical value, we can reject the null hypothesis and conclude that the sample mean is significantly greater than the population mean at a 0.01 level of significance.
Therefore, the test statistic t0 is 5.291 (rounded to three decimal places).
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plz help and plz with an explination
don't make fun of me bc I just put random answers
Answer:
from Ron to Bill from Bill to John the ball traveled about 80 yd
Step-by-step explanation:
Ron 30 yd from John
Bill 40 yd away from John
Bill 10 yd away from John