Help me pleaseeeeeeeeee

The mean absolute deviation for the given dataset of 3, 6, 3.8, 3.2, and 3.4 is approximately 0.996. This means that, on average, each data point in the dataset deviates from the mean by approximately 0.996.

The mean absolute deviation (MAD) measures the average distance between each data point and the mean of the dataset. To find the MAD, you need to follow these steps:

1. Calculate the mean of the dataset by adding up all the numbers and dividing the sum by the total number of data points. In this case, the dataset consists of the following numbers: 3, 6, 3.8, 3.2, and 3.4. Adding them up gives us a sum of 19.4. Dividing this sum by 5 (since there are 5 data points) gives us a mean of 3.88.

2. Find the absolute deviation for each data point by subtracting the mean from each data point and taking the absolute value. For example, for the first data point, 3, the absolute deviation would be |3 - 3.88| = 0.88. Repeat this step for all the data points.

3. Calculate the mean of the absolute deviations by adding up all the absolute deviations and dividing the sum by the total number of data points. In this case, the absolute deviations are: 0.88, 2.12, 0.72, 0.68, and 0.58. Adding them up gives us a sum of 4.98. Dividing this sum by 5 gives us a mean of 0.996.

So, the mean absolute deviation for the given dataset is approximately 0.996.


The mean absolute deviation helps us understand how much each data point varies from the mean of the dataset. By calculating the absolute deviation for each data point and finding the average, we can determine the typical amount of variation in the dataset.


The mean absolute deviation for the given dataset of 3, 6, 3.8, 3.2, and 3.4 is approximately 0.996. This means that, on average, each data point in the dataset deviates from the mean by approximately 0.996.

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There are exactly φ(n) primitive nth roots of unity, where φ is the Euler totient function.

To show that this is a primitive nth root of unity, we need to show that it is not a power of any other nth root of unity. Let k be a positive integer such that

=> \((e^{2\pi ik/n})^n = 1.\)

Then, \(e^{2\pi ik} = 1\), so k must be an integer multiple of n. But if k = mn for some integer m, then

=> \((e^{2\pi ik/n}) = (e^{2\pi im})^{n/m} = 1^{n/m} = 1,\)

which contradicts our assumption that \(e^{2 \pi ik/n}\) is an nth root of unity. Therefore, e^(2πi/n) is a primitive nth root of unity.

For n = 1, there is only one root of unity, namely 1 itself. It is also a primitive root of unity, since it cannot be written as a power of any other root of unity.

For n = 2, there are two roots of unity, namely 1 and -1. Both of these are primitive roots of unity, since neither can be written as a power of the other.

For n = 3, there are three roots of unity, namely 1, \(e^{2 \pi i/3}\), and \(e^{-2 \pi i/3}\). The latter two are primitive roots of unity, since neither can be written as a power of the other or of 1.

For n = 4, there are four roots of unity, namely 1, i, -1, and -i. The primitive roots of unity are \(e^{ \pi i/2}\) and \(e^{ -\pi i/2}\), which cannot be written as powers of each other or of 1, i, or -1.

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Answer:

-9

Step-by-step explanation:

I have made it in above picture

hope it helps

The intensity of the light at 5ft from the bulb is 17.8 lumens while at 15ft from the bulb is 1.97 lumens.

The formula for the intensity of light in lumens is given by:

I = 445/x²

where I is the intensity of light in lumens and x is the distance of light from the bulb in feet.

(a) The intensity of light at 5 feet from the bulb The intensity of light at a distance of 5 feet from the bulb is given by putting the value of

x = 5.I = 445/5²

= 17.8

lumens(b) The intensity of light at 15 feet from the bulb

The intensity of light at a distance of 15 feet from the bulb is given by putting the value of

x = 15.

I

= 445/15²

= 1.97 lumens

The intensity of the light at 5ft from the bulb is 17.8 lumens while at 15ft from the bulb is 1.97 lumens.

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The amount at the end of 30 days, when interest compounded daily is found as $982.53.

The formula for calculating the compound interest is;

A = P(1 + r/100n)∧nt

Where,

Now put the values in the formula.

A = 980(1 + 3.1/3000)∧30(1/12)

A = 980(1.0025)

A= 982.53

Thus, the amount at the end of 30 days, when interest compounded daily is found as $982.53.

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The complete question is-

Mrs.smith deposits $980 in a saving account that pays 3.1% interest compounded daily. Calculate the total amount for 30 days.

Answer: The answer is: 6

Step-by-step explanation: I have my ways ;>

Have a nice day!

-Sunny

Answer:

nomelase pero será chida la imagen que tienes

Given:

m = 10

The line passes through the point (6,2).

To find:

The equation of line in the standard form.

Solution:

If a line passes through the point \((x_1,y_1)\) with slope m, then the equation of line is

\(y-y_1=m(x-x_1)\)

The line passes through the point (6,2) and m = 10. So, the equation of line is

\(y-2=10(x-6)\)

\(y-2=10x-60\)

\(y-10x=-60+2\)

\(-10x+y=-58\)

Therefore, the correct option is A.

The estimated median price of a single-family home in Charleston/No. Charleston in the 1st Quarter of 2008 is $201,048. If the median price continues to decrease at the same rate for the next two years, the estimated median price of a single-family home in the 1st Quarter of 2011 would be $144,458.

(a) To estimate the median price of a single-family home in the 1st Quarter of 2008, we need to calculate the original price before the 8.15% decrease. Let's assume the original price was P. The price after the decrease can be calculated as P - 8.15% of P, which translates to P - (0.0815 * P) = P(1 - 0.0815). Given that the end of 1st Quarter of 2009 median price was $184,990, we can set up the equation as $184,990 = P(1 - 0.0815) and solve for P. This gives us P ≈ $201,048 as the estimated median price of a single-family home in the 1st Quarter of 2008.

(b) If the median price of a single-family home falls at the same rate for the next two years, we can calculate the price for the 1st Quarter of 2011 using the estimated median price from the 1st Quarter of 2009. Starting with the median price of $184,990, we need to apply an 8.15% decrease for two consecutive years. After the first year, the price would be $184,990 - (0.0815 * $184,990) = $169,805.95. Applying the same percentage decrease for the second year, the price would be $169,805.95 - (0.0815 * $169,805.95) = $156,012.32. Therefore, the estimated median price of a single-family home in the 1st Quarter of 2011 would be approximately $144,458.

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Answer:

x = 2.25

8:6

So, 8/6 = 4/3 or 1.33333333 (decimal multiplier)

Therefore, 8 divided by 4/3 = 6.

Then, we could also do 3 divided by 4/3= 9/4 or 2.25.

2.25 x 4/3 = 3.

Answer:

x= 2.25

Step-by-step explanation:

Have a great and blessed day

Answer:

\(V=2080m^3\)

Step-by-step explanation:

The volume formula for triangular prism is  \(V=\frac{1}{2}bhl\)

\(V=\frac{1}{2}(26)(20)(8)\)

\(V=\frac{1}{2}(4160)\)

\(V=2080\)

Hope this helps

Answer:

The answer is 2080m^3

Step-by-step explanation:

The formula for volume of a prism is 1/2 x length x width x height

Hope it helps :)

Answer:

30 ft

Step-by-step explanation:

\(C=\frac{n^2}{5} +175\\\\355=\frac{n^2}{5} +175\\\\180=\frac{n^2}{5}\\\\n^2=900\\\sqrt{n^2} =\sqrt{900} \\n=30\)

Answer:

Step-by-step explanation:

confused

Answer:

Step-by-step explanation:

t=0

If you replace t with zero -9=-9(0+1)

0+1=1 and -9(1)=-9

so t=0

Answer:

C

Step-by-step explanation:

a) Describing the following ordinary differential equations -1. y′′−exy′+exy=0 The equation is of the form  

y″ + p(x)y′ + q(x)y = 0,

where p(x) = -ex and q(x) = ex.

The differential equation is a second-order homogeneous linear equation.-2.

y′′+xy′−sin(x)y=0 The equation is of the form y″ + p(x)y′ + q(x)y = 0, where p(x) = x and q(x) = -sin(x).

The differential equation is a second-order homogeneous linear equation.-3. - y′′+xy′−sin(x)y=−x

The equation is of the form y″ + p(x)y′ + q(x)y = g(x), where p(x) = x and q(x) = -sin(x).

The differential equation is a second-order nonhomogeneous linear equation.-4. y′′+exy′+cos(x)y=0

The equation is of the form y″ + p(x)y′ + q(x)y = 0, where p(x) = ex and q(x) = cos(x).

The differential equation is a second-order homogeneous linear equation.b) Method to solve the following initial value problem

- y′′+47​y′−7y=0, y(0)=−3, y′(0)=1

To solve the given initial value problem, we need to apply the method of finding the characteristic equation. Once we find the characteristic equation, we can apply the corresponding algorithm to find the solution of the differential equation. The characteristic equation is given by r² + 4r - 7 = 0. On solving the equation we get

r = -2 + √11 and r = -2 - √11.

Therefore, the solution to the differential equation is given by

\(y(x) = c_1 e^{r_1 x} + c_2 e^{r_2 x}\), where r₁ = -2 + √11 and r₂ = -2 - √11.

Using the initial conditions, y(0) = -3 and y'(0) = 1, we get the values of constants as

\(c_1 = \dfrac{2 + \sqrt{11}}{e^{\sqrt{11}}}\) and\(c_2 = \dfrac{2 - \sqrt{11}}{e^{-\sqrt{11}}}\).

Thus, the solution of the given initial value problem is\(y(x) &= \dfrac{2 + \sqrt{11}}{e^{\sqrt{11}}} e^{r_1 x} + \dfrac{2 - \sqrt{11}}{e^{-\sqrt{11}}} e^{r_2 x} \\\).

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(a) Example question: "How often do you look at social media while doing schoolwork?

(b) Sofie can select a simple random sample of students by using a random number generator to assign a unique identification number to each student in the online high school.

(c) The sample for Sofie's research is the 32 completed surveys she received. These surveys represent the responses of a subset of the population. The population, in this case, refers to all the students at the online high school.

(d) If Sofie uses only the completed surveys, she can conclude that approximately 50% (16 out of 32) of the students who completed the survey reported using social media while doing schoolwork.

(a) Please select one of the following options: never, rarely, occasionally, frequently, or always."

(b) She can then use the random number generator again to select a specific number of students from the entire population of students, ensuring that each student has an equal chance of being selected. For example, if there are 500 students in total and Sofie wants a sample size of 50, she can generate 50 random numbers and select the corresponding students based on their identification numbers.

(d) However, it is important to note that this conclusion is specific to the sample of completed surveys and cannot be generalized to the entire population of high school students.

To make an inference about the percent of all high school students who use social media while doing schoolwork, Sofie would need a larger and more representative sample that covers a wider range of students in the online high school.

Additionally, she should consider potential biases in the sample, such as non-response bias if the students who chose not to complete the survey have different social media usage patterns compared to those who did respond.

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Answer:

x^2 + 10x + 20

Step-by-step explanation: When you multiply binomials, you are practically taking each term and multiplying it with others until you are out of combinations. However, when the product is represented in standard form, it requires the terms to be set within a specific order that prompts the term at the highest order/power placed on the furthest left side of the expression. The first term x^2 can be referred to as a term of the second power, 10x is seen as one to the first power (x^1 = 1st), and 20 as 0, since it is a constant.

Given:

Then:

For the answer of factors of expression (12 + 54), in the form of a(b + c), where a is the GCF of 12 and 54 is equals to 6( 2 + 9).

In math, to factor a number means to express it as a product of (other) whole numbers, called its factors. For example, if 7x5 = 35, 7 and 5 are both factors. The divisors that give the remainder to be 0 are the factors of the number. We have an expression of numbers, 12 + 54. We have to write this expression in form of a( b + c), where a is GCF of 12 and 54. Now, we can write the factors of 12 and 54 are 12 = 2×2×3

54 = 2×3 ×3×3

The greatest common factor, GCF of 12 and 54 is 2×3 = 6. So, 12 + 54 = 6× 2 + 6×9

Taking out the common factor 6 from above expression, 6( 2 + 9) which is required form a( b + c). Hence, required expression is 6( 2 + 9).

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Answer:

The context that could not be modeled by an exponential function is "A car depreciates at a rate of 3.7% per year." Exponential functions are typically used to model situations involving growth or decay that occur at a constant rate over time. In this case, the rate of depreciation of the car is decreasing over time, so it cannot be modeled by an exponential function. A linear function or a more complex model may be more appropriate.

Answer:

x = 11

Step-by-step explanation:

the area (A) of a trapezium is calculated as

A = \(\frac{1}{2}\) h (b₁ + b₂ )

where h is the perpendicular height between the bases b₁ and b₂

here h = 4 , b₁ = x , b₂ = 6 and A = 34 , then

\(\frac{1}{2}\) × 4 × (x + 6) = 34

2(x + 6) = 34 ( divide both sides by 2 )

x + 6 = 17 ( subtract 6 from both sides )

x = 11

Answer:

C (37, 77)

Step-by-step explanation:

\(291=2(145)+3\\\\291=290+3\\\\\boxed{291\neq 293}\)

Option A is not a solution.

\(163=2(78)+3\\\\163=156+3\\\\\boxed{163\neq 159}\)

Option B is not a solution.

\(77=2(37)+3\\\\77=74+3\\\\\boxed{77=77}\)

Option C is a solution.

Hope this helps.

Answer:

C

Step-by-step explanation:

To determine which point is a solution, substitute the x- coordinate into the equation and if the value is equal to the y- coordinate then it is a solution

A (145, 291 )

y = 2(145) + 3 = 290 + 3 = 293 ≠ 291 ← not a solution

B (78, 163 )

y = 2(78) + 3 = 156 + 3 = 159 ≠ 163 ← not a solution

C (37, 77 )

y = 2(37) + 3 = 74 + 3 = 77 ← solution to the equation

Answer:

9000 milliliters are in 9 liters

Step-by-step explanation:

multiply the volume value by 1000

Answer:

9 meters , i believe so-

Step-by-step explanation: