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Find the valence electrons for the following elements:
1. Gallium
2. Beryllium
3. Cesium
4. Rubidium
5. Calcium
6. Mg
7. K
8. Ba
9. Sr
10. AI
11. Radon
12.1
13. Sulfur
14. O
15. Argon
16. Phosphorous
17. Se
18. Bromine
19. Fluorine
20. CI

"The percent by mass of Cl in manganese(IV) perchlorate is approximately 31.33%." Percent by mass, also known as mass percent or weight percent, is a way to express the concentration or composition of a component in a mixture or compound. It represents the ratio of the mass of the component to the total mass of the mixture or compound, expressed as a percentage.

The formula for percent by mass is:

Percent by mass = (Mass of component / Total mass of mixture or compound) × 100

In this formula, the mass of the component refers to the amount of the specific substance, and the total mass of the mixture or compound includes the masses of all the components combined.

To find the percent by mass of Cl in manganese(IV) perchlorate (Mn(ClO₄)₄), we need to calculate the mass of Cl in the compound and divide it by the total mass of the compound, then multiply by 100.

The molar mass of manganese(IV) perchlorate (Mn(ClO₄)₄) is given as 452.74 g/mol.

First, let's calculate the molar mass of Cl in the compound:

Molar mass of Cl = 35.45 g/mol (molar mass of Cl)

Next, we can calculate the mass of Cl in the compound:

Mass of Cl = Molar mass of Cl × Number of Cl atoms in the compound

= 35.45 g/mol × 4

Now, let's calculate the percent by mass of Cl:

Percent by mass of Cl = (Mass of Cl ÷ Total mass of the compound) × 100

= (35.45 g/mol × 4 ÷ 452.74 g/mol) × 100

Calculating this expression:

Percent by mass of Cl = (141.8 g ÷ 452.74 g) × 100

= 31.33%

Therefore, the percent by mass of Cl in manganese(IV) perchlorate is approximately 31.33%.

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1) Mass of aluminum powder is 2.7 g.

2) Mass of magnesium sulfate is 19.9 g.

3) Mass of calcium oxide is 14g.

4) Mass of lead 412.2 g.

1) In the thermite reaction :

2Al     +     Fe₂O₃   ----->  Al₂O₃   +   2Fe

mass of  Fe₂O₃ = 8.0 g

molar mass of   Fe₂O₃ = 159.6 g/mol

number of moles = mass / molar mass

                             = 8.0 g / 159.6 g/mol

                             = 0.050 moles

1 mole of  Fe₂O₃ react with 2 mole of Al ,

0.050  Fe₂O₃ moles react with 2 × 0.050 = 0.1moles of Al

number of moles of Al = mass / molar mass

mass of Al = no. of moles × molar mass

                 = 0.1 mol × 27 g/mol

                 = 2.7 g

Thus, the mass of aluminum powder is needed to react with 8.0 g of iron (III) oxide is 2.7 g

2) the reaction is :

MgCO₃ +   H₂SO₄  ----->   MgSO₄   +   CO₂    +   H₂O

mass of MgCO₃ = 14.0 g

no. of moles of MgCO₃ = mass / molar mass

                                      = 14 g / 84.3 g/mol

                                      = 0.166 moles

1 mole of MgCO₃  produced 1 mole of MgSO₄,

0.166 mole of MgCO₃  produced 0.166 mole of MgSO₄

mass of MgSO₄ = 120.3 g/mol

no. of moles of MgSO₄ = mass / molar mass

mass of MgSO₄ = no. of moles × molar mass

                          = 0.166 mol × 120.3 g/mol

                          = 19.9 g

Thus, mass of magnesium sulfate crystals can be made from14.0g of magnesium carbonate and an excess of dilute sulfuric acid is 19.9 g

3) the reaction is :

CaCO₃   ----->   CaO + CO₂

mass of calcium carbonate = 25 g

molar mass of CaCO₃ = 100 g/mol

no. of moles of = mass / molar mass

                         = 25 / 100

                         = 0.25 mol

0.25 moles of CaCO₃ produced 0.25 moles of CaO

molar mass of  CaO = 56 g/mol

mass of CaO = no. of moles × molar mass

                      = 0.25mol × 56 g/mol

                      = 14 g

the mass of CaO produced 14 g.

4) PbO  +   H  ----->    Pb   + H₂O

mass of PbO = 446g

no. of moles = mass / molar mass

                     = 446 g / 223.3 g/mol

                     = 1.99 mols

1.99 moles of PbO produced 1.99 moles of Pb

molar mass of Pb = 207.2 g/mol

mass of Pb = no. of moles × molar mass

                   = 1.99 mol × 207.2 g/mol

                   = 412.2 g

Thus, Lead (ii) oxide PbO, reacts with hydrogen to for lead and steam. calculate the mass of lead in formed when 446g of lead (ii) oxide is 412.2g.

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Answer:

2 option

Explanation:

please mark me brainliest and 5 star

Ester is characterized by a central carbon atom that is double-bonded to an oxygen atom, single-bonded to R, and single-boned to R prime.

It is an organic functional group composed of the following:

Thus, the structure of an ester looks like the attached image.

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Answer:

B

Explanation:

As stated in the preceding statement Square pyramidal geometry describes the molecules.

An atom is made up of a core nucleus and one or maybe more electrons with negative charge that orbit it. The positively charged, comparatively hefty protons and neutrons that make up the nucleus may be present.

The quantity of protons an atom has makes it distinct from other atoms. Consequently, a particle devoid of protons isn't just an atom. But even a single proton constitutes every atom (of hydrogen). Individual particles of something like the periodic table elements like sodium, plutonium, argon, among chlorine are examples of atoms.

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The condition for a lumped system analysis is a system that can be considered thermally homogeneous or isothermal.

In lumped system analysis, the system is modeled as a single point or lumped element that represents the entire system. This approach is valid when the system is thermally homogeneous, meaning that the temperature is uniform throughout the system. Therefore, the condition for a lumped system analysis is that the system can be considered isothermal, where the temperature remains constant.

An isotropic system is one where the physical properties are the same in all directions. This condition is not directly related to lumped system analysis, but it can be used as an assumption in certain cases, such as when modeling a spherical object. An isentropic system is one where the entropy remains constant, which is not related to the conditions necessary for lumped system analysis.

The condition for a lumped system analysis is that the system is thermally homogeneous or isothermal, meaning that the temperature is uniform throughout the system. The conditions of isotropy or isentropic do not directly relate to lumped system analysis.

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Diffraction occurs whenever a portion of a wavefront is obstructed by some opaque object.

oxygen,crabon dioxide,and glucose

Answer:

atp molecules & lactic acid

Explanation:

just did the assingment!

The right word to describe this chemical reaction is c) fusion mass converted  into energy. When two lighter nuclei come together to form a heavier nucleus, a significant quantity of energy is released. Energy is released when two hydrogen nuclei (H) combine to generate helium-4 (He) and a neutron (n).

A nuclear event called fusion occurs when two lighter atomic nuclei join forces to create a heavier nucleus. This process takes place at incredibly high pressures and temperatures, which are often encountered in star cores or in experimental fusion reactors. When there is fusion, the atomic nuclei

There is a significant quantity of energy released as they conquer their attraction to one another and combine. Deuterium and tritium, two isotopes of hydrogen, combine with lighter atoms to generate helium and unleash a tremendous amount of energy, similar to that of nuclear fusion.

the power generated by the Sun. In order to accomplish practical fusion power generation, considerable scientific and engineering obstacles must be overcome. Fusion reactions have the potential to produce a clean, abundant, and sustainable source of energy.

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Answer:

If mass remains the same while the volume of a substance changes, the density of the substance will also change.

Answer:

BELOW

Explanation:

If mass remains the same while the volume of a substance decreases the density of the substance will increase.

Answer:

Rusting is an oxidation reaction. The iron reacts with water and oxygen to form hydrated iron (III) oxide, which we see as rust. Here is the word equation for the reaction: iron + water + oxygen → hydrated iron (III) oxide

In this reaction, zinc atoms each will lose two electrons (oxidation) and become Zn 2+ ions. The two electrons that are released by zinc will be gained by the Cu 2+ ions (reduction). The Cu2+ ions become Cu atoms. Total equation: Zn (s) + CuSO 4 (aq) --> Cu (s) + ZnSO 4 (aq)

Explanation:

To calculate the freezing point and boiling point of the given solution, we'll first need to find the molality of the solution.

And then use the molal freezing point depression constant (Kf) and molal boiling point elevation constant (Kb) for water.

1. Calculate the moles of FeCl3:
FeCl3 molar mass = 1(55.85 g/mol) + 3(35.45 g/mol) = 162.2 g/mol
Moles of FeCl3 = 10.5 g / 162.2 g/mol = 0.0647 moles

2. Calculate the mass of water in kg:
Mass of water = 1.50 * 10^2 g = 150 g = 0.150 kg

3. Calculate molality (moles of solute per kg of solvent):
Molality = 0.0647 moles / 0.150 kg = 0.431 mol/kg

4. Calculate the molality including dissociation:
FeCl3 dissociates into 1 Fe³⁺ ion and 3 Cl⁻ ions, so there are 4 particles for each mole of FeCl3.
Molality with dissociation = 0.431 mol/kg * 4 = 1.724 mol/kg

5. Calculate the freezing point depression and boiling point elevation:
For water, Kf = 1.86 °C·kg/mol and Kb = 0.512 °C·kg/mol
ΔTf = Kf * molality = 1.86 °C·kg/mol * 1.724 mol/kg = 3.204 °C
ΔTb = Kb * molality = 0.512 °C·kg/mol * 1.724 mol/kg = 0.882 °C

6. Calculate the freezing point and boiling point of the solution:
Freezing point = 0 °C (normal freezing point) - ΔTf = 0 °C - 3.204 °C = -3.204 °C
Boiling point = 100 °C (normal boiling point) + ΔTb = 100 °C + 0.882 °C = 100.882 °C

The freezing point of the solution is -3.204 °C and the boiling point is 100.882 °C, assuming complete dissociation of the solute.

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Answer and Explanation:

Your mass is the same no matter where you go in the universe; your weight, on the other hand, changes from place to place. Mass is measured in kilograms; even though we usually talk about weight in kilograms, strictly speaking, it should be measured in newtons, the units of force. (according to cosmicmagazine.com)(not my writing or explanation)

Answer:

816L adicionales para mantener la concentración

Explanation:

Cuánta agua debe adicionar el cuidador para que se mantenga la concentración del desinfectante?

El desinfectante, NaClO, idealmente debe estar en una concentración de:

35.8g / 1000L = 0.0358g/L

Como el velador agregó 65g de desinfectante, la cantidad de agua necesaria es:

65g * (1L / 0.0358g) = 1816L de agua son necesarios

Asumiendo que el velador agregó 1000L, el cuidador debe agregar:

1816L - 1000L =

Answer:

Tin(IV) Hydrogen Oxalate. Alias: Stannic Hydrogen Oxalate. Formula: Sn(HC2O4)4. Molar Mass: 474.8178. :: Chemistry Applications:: Chemical Elements, Periodic Table.

Explanation:

Answer:

Sn(HC2O4)4 --> formula for Tin(IV) Hydrogen Oxalate

We are given:

Volume = 2 L

pH = 2.75

Finding the concentration required:

we know that pH is just the negative log of the hydrogen ion concentration

pH = -log[H⁺]

we are given that the pH is 2.75

2.75 = -log[H⁺]

log[H⁺] = -2.75                         [multiplying both sides by -1]

\(10^{log[H]} = 10^{-2.75}\)                      

[H⁺] = 1.78 * 10⁻³ Molar

Number of moles of Hydrogen ions:

[H⁺] = 1.78 * 10⁻³ Molar

which means that there are 1.78 * 10⁻³ moles of hydrogen ions in 1 liter solution

1.78 * 10⁻³ moles / L

multiplying and dividing by 2, we get:

3.56 * 10⁻³ moles / 2 L

Hence we need 3.56 * 10⁻³ moles of hydrogen ions  

Answer:

3.556x 10^-3mol

Explanation:

Using pH =-log [ H+], we can calculate the concentration of the hydrogen Ions.

pH =-log [ H+], pH = 2.75

2.75 = -log[H+], taking antilog of both sides

10^ — 2.75 = [H+]

[H+] =1. 778 x 10^-3M

Now that we have the concentration and also knows the volume, we can use the relation

Moles = concentration X volume

= 1. 778 x 10^-3M x 2L = 3.56x 10^-3mol

The moles of the hydrogen Ions is 3.56x 10^-3mol

when a 23.2 ml sample of a 0.334 m aqueous hypochlorous acid solution is titrated with a 0.464 m aqueous barium hydroxide solution. The pH of the sample after titration  will be 7.

The pH of a sample of aqueous hypochlorous acid solution can be determined by titrating it with aqueous barium hydroxide solution. In this case, a 23.2 ml sample of a 0.334 m aqueous hypochlorous acid solution is titrated with a 0.464 m aqueous barium hydroxide solution.

The pH of the mixture will be determined by the amount of barium hydroxide solution needed to neutralize the hypochlorous acid. As the titration progresses, the pH of the mixture will increase.

When the equivalent point is reached, the pH will be 7. At this point, the amount of barium hydroxide solution added to the sample will be equal to the amount of hypochlorous acid present in the sample. Thus, the pH of the sample after titration  will be 7.

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Complete question is :-

when a 23.2 ml sample of a 0.334 m aqueous hypochlorous acid solution is titrated with a 0.464 m aqueous barium hydroxide solution, what is the pH after titration?

Answer:

When a liquid is remained a liquid the the particles are loose but as the liquid turns into solid the particle get more compact and closer together. So in that case the liquid will have lower density.

Note: I hope you have a Fantastic day!

Answer:D. Solid

Explanation:

A. Disorganized

B. Amorphous

C. Liquid

D. Solid

At 500 K, the equilibrium constant `K_p` for the gas-phase thermal decomposition of tert-butyl chloride is 3.45.

A chemical reaction proceeds in both forward and backward directions. At some point in time, the rate of forward and backward reaction becomes equal.

At this stage, the system is said to be in a state of equilibrium. When the concentration of products and reactants no longer changes, the reaction is said to have reached equilibrium.

Constant is the term that is used for the ratio of the concentrations of products to the concentrations of reactants at equilibrium.

This ratio is also called the Equilibrium Constant `(K)`. It is only used for reversible reactions and its value changes with changes in temperature.

What is the formula of Equilibrium Constant `K_p`?Equilibrium Constant `K_p` is defined as the ratio of the partial pressures of products and reactants when the reaction reaches equilibrium.

Mathematically, it is given as:`K_p = (P_A)^a * (P_B)^b / (P_C)^c * (P_D)^d`where `A` and `B` are products and `C` and `D` are reactants. `a`, `b`, `c` and `d` are the respective coefficients in the balanced chemical equation. `P` is the partial pressure of the given substance.Given equation for the thermal decomposition of tert-butyl chloride:`(CH3)3CCl(g) ⇌ (CH3)2C=CH2(g) + HCl(g)`

The Equilibrium constant `K_p` of the given equation at 500K is given as:`K_p = 3.45`

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Answer:

ammonia molecules. Similar factors may be derived for any pair of substances in any chemical equation. Example 4.8. Moles of Reactant Required in a Reaction.

Explanation:

Answer:

1.09 moles

Explanation:

Sodium has a molar mass of 23 grams per mole. To get the number of moles of sodium, divide 25 grams by 23 grams per mole. The answer is 1.09 moles

Answer:

lithium reacts with water, forming lithium hydroxide and highly flammable hydrogen

Answer:

cold and windy

Explanation:

if its 10 degrees outside then it must be cold. then 75 mph that is very windy

Answer:

\(\large \boxed{\text{0.88 L}}\)

Explanation:

The temperature and amount of gas are constant, so we can use Boyle’s Law.

\(p_{1}V_{1} = p_{2}V_{2}\)

Data:

\(\begin{array}{rcrrcl}p_{1}& =& \text{1.34 atm}\qquad & V_{1} &= & \text{ 0.56 L} \\p_{2}& =& \text{0.85 atm}\qquad & V_{2} &= & ?\\\end{array}\)

Calculations:  

\(\begin{array}{rcl}\text{1.34 atm} \times \text{0.56 L} & =& \text{0.85 atm} \times V_{2}\\\text{0.750 L} & = & 0.85V_{2}\\V_{2} & = &\dfrac{0.750}{0.85}\\\\& = &\textbf{0.88 L}\\\end{array}\\\text{The balloon's new volume is $ \large \boxed{\textbf{0.88 L}}$}\)

The IUPAC name for the compound is 2-bromobutanal.

IUPAC (International Union of Pure and Applied Chemistry) nomenclature is a system of rules used to name organic compounds. The given compound, α-bromobutanal β-bromobutyraldehyde, can be named using the IUPAC nomenclature system.

In the first step, we need to identify the longest continuous carbon chain in the compound. In this case, the longest carbon chain contains four carbon atoms.

In the second step, we need to identify and name the functional group. In the given compound, the functional group is an aldehyde, which is denoted by the suffix "-al" or "-aldehyde."

In the third step, we assign locants or numbers to the substituents or functional groups. The substituent bromine is attached to the second carbon atom in the chain, so we indicate it as 2-bromo.

Putting it all together, the IUPAC name for the given compound is 2-bromobutanal.

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