Help me question 5 ASAP

Answer:

Equilibrium constant expression for \(\rm 2\; H^{+}\, (aq) + {CO_3}^{2-}\, (aq) \rightleftharpoons H_2CO_3\, (aq)\):

\(\displaystyle K = \frac{\left(a_{\mathrm{H_2CO_3\, (aq)}}\right)}{\left(a_{\mathrm{H^{+}}}\right)^2\, \left(a_{\mathrm{{CO_3}^{2-}\, (aq)}}\right)} \approx \frac{[\mathrm{H_2CO_3}]}{\left[\mathrm{H^{+}\, (aq)}\right]^{2} \, \left[\mathrm{CO_3}^{2-}\right]}\).

Where

Explanation:

The equilibrium constant expression of a (reversible) reaction takes the form a fraction.

Multiply the activity of each product of this reaction to get the numerator.\(\rm H_2CO_3\; (aq)\) is the only product of this reaction. Besides, its coefficient in the balanced reaction is one. Therefore, the numerator would simply be \(\left(a_{\mathrm{H_2CO_3\, (aq)}}\right)\).

Similarly, multiply the activity of each reactant of this reaction to obtain the denominator. Note the coefficient "\(2\)" on the product side of this reaction. \(\rm 2\; H^{+}\, (aq) + {CO_3}^{2-}\, (aq)\) is equivalent to \(\rm H^{+}\, (aq) + H^{+}\, (aq) + {CO_3}^{2-}\, (aq)\). The species \(\rm H^{+}\, (aq)\) appeared twice among the reactants. Therefore, its activity should also appear twice in the denominator:

\(\left(a_{\mathrm{H^{+}}}\right)\cdot \left(a_{\mathrm{H^{+}}}\right)\cdot \, \left(a_{\mathrm{{CO_3}^{2-}\, (aq)}})\right = \left(a_{\mathrm{H^{+}}}\right)^2\, \left(a_{\mathrm{{CO_3}^{2-}\, (aq)}})\right\).

That's where the exponent "\(2\)" in this equilibrium constant expression came from.

Combine these two parts to obtain the equilibrium constant expression:

\(\displaystyle K = \frac{\left(a_{\mathrm{H_2CO_3\, (aq)}}\right)}{\left(a_{\mathrm{H^{+}}}\right)^2\, \left(a_{\mathrm{{CO_3}^{2-}\, (aq)}}\right)} \quad\begin{matrix}\leftarrow \text{from products} \\[0.5em] \leftarrow \text{from reactants}\end{matrix}\).

In dilute solutions, the equilibrium constant expression can be approximated with the concentrations of the aqueous "\((\rm aq)\)" species. Note that all the three species here are indeed aqueous. Hence, this equilibrium constant expression can be approximated as:

\(\displaystyle K = \frac{\left(a_{\mathrm{H_2CO_3\, (aq)}}\right)}{\left(a_{\mathrm{H^{+}}}\right)^2\, \left(a_{\mathrm{{CO_3}^{2-}\, (aq)}}\right)} \approx \frac{\left[\mathrm{H_2CO_3\, (aq)}\right]}{\left[\mathrm{H^{+}\, (aq)}\right]^2\cdot \left[\mathrm{{CO_3}^{2-}\, (aq)}\right]}\).

One important chemical reaction in our daily life is the process of cellular respiration, which occurs in living organisms to produce energy in the form of ATP.

The reaction involves the breakdown of glucose, a type of sugar, into carbon dioxide and water, and the release of energy in the process. The general equation for cellular respiration is,

\(C_{6} H_{12} O_{6}\) + \(6O_{2}\) → \(6CO_{2}\) + \(6H_{2}O\) + energy (ATP)

This reaction occurs continuously in our cells, providing the energy needed for various cellular activities and bodily functions. Without cellular respiration, we would not be able to survive.

Another important application of chemical reactions in daily life is in the production of food. Cooking food involves various chemical reactions, including the breakdown of complex carbohydrates and proteins into simpler molecules, the caramelization of sugars, and the Maillard reaction between amino acids and reducing sugars. These reactions help to create the flavor, aroma, and texture of the food we eat.

In addition, chemical reactions are also used in the production of many consumer products, such as cleaning agents, cosmetics, and pharmaceuticals. The chemical reactions involved in these products are carefully designed and controlled to ensure their effectiveness and safety for use.

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Answer:

33.58 Moles

Explanation:

7.3 L  *  4.6 M / L  = 33.58 Moles

Answer:

A neutron is a subatomic particle with no charge and is found in the nucleus of an atom.

An atom is the smallest particle of an element that retains its identity in a chemical reaction.

Explanation:

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Answer:

See below.

Explanation:

Neutron is a subatomic particle which has a neutral charge and forms the nucleus of the atom.

Atom is the smallest unit of matter which composes solids, liquids, gases, and plasma.

Answer:

Solid

Explanation:

Cus its solid, take a brick for example. It's hard and has no space unlike liquid or gas.

In the ideal gas law, the temperature of the hydrogen gas determined if the volume and pressure of the gas is known.

The ideal gas law states that the pressure of ideal gas is directly proportional to the absolute temperature of the gas.

PV = nRT

where;

The temperature of the gas is determined as follows;

\(T = \frac{PV}{nR}\)

Thus, we can conclude that in the ideal gas law, the temperature of the hydrogen gas determined if the volume and pressure of the gas is known.

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There are two surrounding atoms and no lone pair of electrons in the nitrogen-centered nitrous oxide molecule. The valence shell of the nitrogen atom has 5 electrons, while the molecule has 2 nitrogen atoms. Thus, nitrogen atoms contribute 10 electrons.

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The enthalpy change of the reaction C(diamond) → C(graphite) is -2.9 kJ.

The given information is ΔHrxn for the reaction C(diamond) → C(graphite) can be calculated with the given equations:Equations:  C(diamond) + O2(g) → CO2(g) ΔH = −395.4 kJ  2 CO2(g) → 2 CO(g) + O2(g) ΔH = 566.0 kJ  C(graphite) + O2(g) → CO2(g) ΔH = −393.5 kJ  2 CO(g) → C(graphite) + CO2(g) ΔH = −172.5 kJThe required reaction can be obtained by adding the equations (1) and (4), as follows:C(diamond) + O2(g) + 2CO(g) → C(graphite) + 3CO2(g)Addition of the two equations (1) and (4) results in a reaction whose products are C(graphite) and CO2.

To get the final equation that involves only the required reactants and products, the equation (2) should be added, which consumes CO2 and produces O2, as shown below:C(diamond) + O2(g) → CO2(g)  ΔH = −395.4 kJ [eq. (1)]  2 CO(g) → C(graphite) + CO2(g)  ΔH = −172.5 kJ [eq. (4)]  2 CO2(g) → 2 CO(g) + O2(g)  ΔH = 566.0 kJ [eq. (2)]  C(diamond) + O2(g) + 2CO(g) → C(graphite) + 3CO2(g)  ΔHrxn=ΣΔHf(products)−ΣΔHf(reactants)  ΔHrxn=[(3 mol CO2)(-393.5 kJ/mol) + (1 mol C(graphite))(0 kJ/mol)] − [(1 mol C(diamond))(0 kJ/mol) + (1 mol O2)(0 kJ/mol) + (2 mol CO(g))(−172.5 kJ/mol)] − [(2 mol CO2)(566.0 kJ/mol)]  ΔHrxn=−2.9 kJ.

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The total mass of the products is 40 grams (Option C).

In 1789, Antoine Lavoisier discovered that mass is neither created nor destroyed in chemical reactions. This is now known as Lavoisier's law of conservation of mass. In other terms, the sum of the masses of the reactants is equal to the sum of the masses of the products. So, in this case, the total mass of the products must be 40 grams as well.

The total mass of the products is 40 grams.

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Answer:

here is a diagram of Bohr's sulfur.

Answer:

Which answer would represent 0.001 moles?

Answer:

Sugar

Explanation:

Glucose is a carbohydrate. Carbohydrates are mainly used for quick energy inside cells, but they also play an important role in cell structure and communication. Carbohydrates are macromolecules called polysaccharides, meaning they are made of many sugars.

Answer:

we know that it originally came from an animal, likely a bat. At this time, there is no evidence that animals play a significant role in spreading the virus that causesd

Explanation:

Answer:

THE VIRUS DIDNT COME FROM NO BAT!

Explanation:

THE VIRUS STARTED IN CHINA IN A LAB AND CHINA DIDNT EVEN TELL THE USA ABOUT IT THEY HIT IT FROM US. WHEN CHINESE PEOPLE WERE TRAVELING TO THE USA IT SPREADED.

When two iron bars at different temperatures are placed in thermal contact, the rate of heat exchange can vary depending on whether the system is isolated or open.

If the iron bars were placed in thermal contact in an open system instead of an isolated system, the results would be different due to the exchange of energy with the surroundings. In an open system, energy can be transferred between the system and the surroundings, typically in the form of heat.

When the iron bars are in thermal contact, heat will flow from the hotter bar to the cooler bar until they reach thermal equilibrium. In an open system, the heat transferred from the hotter bar will not be retained within the system but will instead be dissipated into the surroundings. Similarly, the cooler bar will absorb heat from the surroundings. This continuous exchange of heat with the surroundings will affect the rate of temperature change in the bars.

In the given scenario, where the room temperature is 25°C, when the iron bars are in contact, the hotter bar at 200°C will lose heat to the surroundings, and the cooler bar at 120°C will absorb heat from the surroundings. This heat exchange with the surroundings will slow down the rate at which the bars reach thermal equilibrium.

Therefore, in an open system, after 30 minutes of thermal contact, the iron bars may not reach the exact temperature of 160°C as they did in the isolated system. The final temperature of the bars would depend on the rate of heat exchange with the surroundings and the difference in temperature between the bars and the surroundings.

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Step 1 - The interaction between proteins (receptors) and molecules

Proteins and molecules interact according to their geometry. Therefore, a molecule can interact with a protein only if it has the proper geometry or molecular shape.

The molecular shape thus determines whether a molecule will be able to interact with the receptor.

Step 2 - Answering the exercise

The answer is therefore molecular shape

Answer: molecular shape

Answer:

Combustion

Explanation: Because a reactant is reacting with O2.

Answer: B. Safety goggles must be worn during all laboratory activities.

The first undiscovered remedy is barium chloride.

Option b is correct.

Explanation and Response: The flame of potassium, often known as a lilac flame, is violet or light purple in color. Remember that different elements can create similar colors, thus flame tests are not always reliable.

Avoid contact with mucous membranes, eyes, and skin as copper(II) chloride is mildly poisonous. Body tissue irritant lithium chloride is used. In order to prevent trashcan fires, rinse the wooden splints before throwing them in the trash. Put on chemical-resistant gloves, an apron, splash goggles, and other protective gear.

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The molarity of the solution is equal to 0.500M.

To calculate the molarity of a solution, one must use the value of the amount of moles and the volume, so that:

                                                 \(M = \frac{mol}{v}\)

So, applying the values ​​given in the question we have:

                                         \(M = \frac{1mol}{2L}\)

                                       \(M = 0.5mol/L\)

So, the molarity of the solution is equal to 0.500M.

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Answer:

I beleive its sedimentary and minerals

Answer:

They all contain switches

Answer: D. they all contain resonators.

Explanation:

Answer:

let's summarize the caution as we are given with human projection. We have to tell them stances where staggered confirmation is not the lowest in energy. Okay, so let's see that. Are there any instances that which conforms tiger is not the lowest energy. Okay, so the lowest energy is what then happened? The lowest in energy already happens on living. Honestly, when, when it happens the lowest in energy only happens when the bulky groups are at 1 80 degree with each other. When it happens when bulky, bulky, bulky groups are at 1 80 degree. Okay, When they are, for example, when the bulky groups are in this way At 180°, then it is Louis Why? Because repulsion are very less repulsion very less. Got it. So we have to tell when it is not the lowest so far not the lowest instance. These bulky groups should be together. So if they either make of angle of 60° or 300° together, suppose this is a bulky group one and this is a bulky group two and okay, so if it makes a 60 degree or 300 degree then this um have the highest energy Or has the energy is not lowest in it. Why? It is not lowest in it Because at 300° or 60°. Why? Because the pulsations are very high repulsion. Are you ready? Hi. So by looking at the humans projection we can conclude that when the if the bulky group parrot 1, 80 degree be considered as the lowest energy. And if they are at 300 or 60 degree or close to each other, republicans are higher and they are not in lowest energy.

The temperature of the gas in Kelvin, after its volume is reduced to 2,450 mL, is approximately 143.27 K.

To determine the temperature of the gas in Kelvin after its volume is reduced, we can use the combined gas law, which relates the initial and final conditions of pressure, volume, and temperature for a given amount of gas.

The combined gas law equation is:

(P₁ * V₁) / T₁ = (P₂ * V₂) / T₂

Where P₁ and P₂ are the initial and final pressures, V₁ and V₂ are the initial and final volumes, T₁ is the initial temperature in Kelvin, and T₂ is the final temperature in Kelvin.

Given that the initial volume V₁ is 3,480 mL, the initial temperature T₁ is -70.0 °C (which needs to be converted to Kelvin), and the final volume V₂ is 2,450 mL, we can substitute these values into the equation.

To convert -70.0 °C to Kelvin, we add 273.15 to it, resulting in T₁ = 203.15 K.

Now we can solve for T₂:

(T₂ * V₁) / T₁ = V₂

T₂ = (V₂ * T₁) / V₁ = (2,450 mL * 203.15 K) / 3,480 mL

Simplifying the equation, we find:

T₂ ≈ 143.27 K

Therefore, the temperature of the gas in Kelvin, after its volume is reduced to 2,450 mL, is approximately 143.27 K.

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The volume of the gas at STP would be 23.93 liters.

The volume of gas at STP (Standard Temperature and Pressure), we need to use the Ideal Gas Law, which states that PV = nRT, where P is pressure, V is volume, n is the number of moles of gas, R is the gas constant, and T is temperature. First, we need to calculate the number of moles of gas in the initial sample. We can use the formula n = PV/RT, where P is the initial pressure, V is the initial volume, R is the gas constant, and T is the initial temperature.
n = (2.31 atm) x (25.15 L) / [(0.0821 L atm/mol K) x (201 + 273.15 K)]
n = 1.067 moles

Now, we can use the molar volume of gas at STP, which is 22.4 L/mol, to calculate the volume of gas at STP.
V = n x 22.4 L/mol
V = 1.067 moles x 22.4 L/mol
V = 23.93 L
Therefore, the volume of the gas at STP would be 23.93 liters.

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The most reactants in the system are the oxygen molecules while the least reactants in the system is carbon sulfide. As such carbon sulfide is the limiting reactant.

We know that when we talk about a chemical reaction, what we are referring to is the interaction that is able to occur between the reactants and the products that are found in the system. We know that when we write down a chemical reaction, the species that are combined are the species that we can find on the left hand side and they are called the reactants. The species that we obtain in the reaction are the species that we can find on the right hand side and they are called the products of the reactions.

If we look at the reaction as it has been shown, we can see that there are ten oxygen molecules and three carbon sulfide molecules that were initially present in the system as we can see here. The entire reaction equation is given as; CS₂(g)+30₂(g) → CO₂(g) +2 SO₂(g).

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The statement "when a bottle of soda was opened, bubbles rapidly appeared in the liquid and were given off at the surface" can be categorized as an observation.

Observation refers to the act of noticing or perceiving something through the senses. In this case, the statement describes a specific event that was directly observed: the opening of a bottle of soda and the rapid appearance of bubbles in the liquid, which were then given off at the surface. This observation describes a phenomenon that can be witnessed and measured.

The appearance of bubbles when a bottle of soda is opened is a well-known and predictable occurrence. It can be explained by the principles of gas solubility and pressure.

The soda contains dissolved carbon dioxide (CO2) under high pressure, which is responsible for the carbonation. When the bottle is opened, the sudden release of pressure causes the dissolved CO2 to come out of solution, forming bubbles. These bubbles then rise to the surface and are released into the air.

While this statement captures an observed phenomenon, it does not propose a general principle or provide a comprehensive explanation of the underlying mechanisms. Therefore, it does not qualify as a law or theory, but rather as an observation based on direct sensory perception.

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