HELP PLEASE HELP MEMEEE

Answer:

Step-by-step explanation:

b/c they end up in the same place but take different ways of getting there...  90 + 270 adds up to a full circle of 390 so b/c one goes in the positive direction and one goes in the negative, the both get to the same location, :)

Answer:

a=2

Step-by-step explanation:

1) The first iteration, n, turns out to be (x1, y1) = ( , ).

2) If the second iteration, n, is (x2, y2) = ( , ).

To find the values of (x1, y1) and (x2, y2), we need additional information or the specific steps of the gradient method applied in MATLAB. The gradient method is an optimization algorithm that iteratively updates the variables based on the gradient of the function. Each iteration involves calculating the gradient, multiplying it by the learning rate (λ), and updating the variables by subtracting the result.

3) After s many iterations (and perhaps changing the value of λ to achieve convergence), it is obtained that the minimum is found at the point (xopt, yopt) = ( , ).

To determine the values of (xopt, yopt), the number of iterations (s) and the specific algorithm steps or convergence criteria need to be provided. The gradient method aims to reach the minimum of the function by iteratively updating the variables until convergence is achieved.

4) The value of the minimum, once the convergence is reached, will be determined by evaluating the function at the point (xopt, yopt). The specific value of the minimum is missing and needs to be provided.

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the complete question is:

Matlab The Gradient Method Was Used To Find The Minimum Value Of The Function North F(X,Y)=(X^2+Y^2−12x−10y+71)^2 Iterations Start At The Point (X0,Y0)=(2,2.6) And Λ=0.002 Is Used. (The Number Λ Is Also Known As The Size Or Step Or Learning Rate.) 1)The First Iteration N Turns Out To Be (X1,Y1)=( , ) 2)If The Second Iteration N Is (X2,Y2)=( ,

Matlab

The gradient method was used to find the minimum value of the function north

f(x,y)=(x^2+y^2−12x−10y+71)^2 Iterations start at the point (x0,y0)=(2,2.6) and λ=0.002 is used. (The number λ is also known as the size or step or learning rate.)

1)The first iteration n turns out to be (x1,y1)=( , )

2)If the second iteration n is (x2,y2)=( , )

3)After s of many iterations (and perhaps change the value of λ to achieve convergence), it is obtained that the minimum is found at the point (xopt,yopt)=( , );

4)Being this minimum=

The z-score for this truck is -1.182.

To calculate the z-score for a truck that traveled 42 thousand miles in the last year, we use the formula:

z = (x - μ) / σ

where x is the distance traveled by the truck, μ is the mean distance traveled by all trucks in the fleet, and σ is the standard deviation of the distances traveled by all trucks in the fleet.

Plugging in the values given in the problem, we get:

z = (42 - 55) / 11 = -1.182

Therefore, the z-score for this truck is -1.182.

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the position function is s(t) = -1/2 * \(e^{(-2t)}\) + 2t + 5/2.

To find the position function, we need to integrate the velocity function with respect to time and apply the initial condition.

The velocity function is given as v(t) = \(e^{(-2t)}\) + 2.

To find the position function, we integrate the velocity function with respect to time:

s(t) = ∫ v(t) dt

Integrating\(e^{(-2t)}\) gives us -1/2 * \(e^{(-2t)}\), and integrating 2 gives us 2t:

s(t) = -1/2 * \(e^{(-2t)}\) + 2t + C

To determine the constant of integration (C), we apply the initial condition s(0) = 2:

s(0) = -1/2 * \(e^{(-2 * 0) }\)+ 2 * 0 + C

2 = -1/2 * 1 + C

2 = -1/2 + C

C = 2 + 1/2

C = 5/2

Substituting the value of C back into the position function, we get:

s(t) = -1/2 \(* e^{(-2t)}\) + 2t + 5/2

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Answer:

14÷2=7

7 is your answer. hope this helps

Ashley and her sister decide to split the cost of dinner , which is $14 . How much will each sister pay?

$7

look at the attached picture :)

Answer:

18.8

Step-by-step explanation:

Circumference

The number of reactions per second required to produce a power output of 28 depends on the specific reaction and its energy conversion efficiency.

To determine the number of reactions per second necessary to achieve a power output of 28, we need additional information about the reaction and its efficiency. Power output is a measure of the rate at which energy is transferred or converted. It is typically measured in watts (W) or joules per second (J/s).

The specific reaction involved will determine the energy conversion process and its efficiency. Different reactions have varying conversion efficiencies, meaning that not all of the input energy is converted into useful output power. Therefore, without knowledge of the reaction and its efficiency, it is not possible to determine the exact number of reactions per second required to achieve a power output of 28.

Additionally, the unit of measurement for power output (watts) is related to energy per unit time. If we have information about the energy released or consumed per reaction, we could potentially calculate the number of reactions per second needed to reach a power output of 28.

In summary, without more specific details about the reaction and its energy conversion efficiency, we cannot determine the exact number of reactions per second required to produce a power output of 28.

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Answer: Exact Form:

m

=

31

12

Decimal Form:

m

=

2.58

¯

3

Mixed Number Form:

m

=

2

7

12

Step-by-step explanation:

Ubiquitin attaches to a target protein via a lysine/serine covalent bond.

Ubiquitin is a small protein that plays a crucial role in the regulation of protein degradation and signaling within cells. It attaches to target proteins through a process called ubiquitination. This process involves the formation of a covalent bond between the C-terminal glycine residue of ubiquitin and the lysine or serine residue of the target protein.

The attachment of ubiquitin to a target protein occurs in a series of steps. First, an activating enzyme (E1) activates ubiquitin by forming a high-energy thioester bond with its C-terminal glycine residue. Then, the activated ubiquitin is transferred to a conjugating enzyme (E2). Finally, a ligase enzyme (E3) recognizes the target protein and facilitates the transfer of ubiquitin from the E2 enzyme to the lysine or serine residue of the target protein, forming a covalent bond.

This covalent attachment of ubiquitin to the target protein acts as a signal for various cellular processes, such as protein degradation by the proteasome or alterations in protein localization and function. The specificity of ubiquitin attachment is determined by the interaction between the E3 ligase and the target protein, as well as the recognition of specific lysine or serine residues within the target protein.

Overall, the attachment of ubiquitin to a target protein via a lysine/serine covalent bond is a crucial mechanism for regulating protein function and cellular processes.

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Stochastic processes in finance are modeled using a formula such as the Geometric Brownian Motion equation, which is used to predict the random variations in asset prices and inform investor decisions.

Stochastic processes in finance are processes that are randomly determined, with the outcomes being uncertain. These processes are used to model financial markets, and are useful for forecasting future price movements. These processes are usually modeled using a formula, such as the Geometric Brownian Motion (GBM) equation:

dS = μSdt + σSdz

Where dS is the change in the price of an asset over a short time period, μ is the drift term (expected rate of return), S is the current price of the asset, dt is the time period, σ is the volatility, and dz is a random variable.

This equation is used to model the random variations of an asset’s price, and can be used to predict future price movements. By understanding the GBM equation and its parameters, investors can make more informed decisions when trading financial instruments.

Stochastic processes in finance are modeled using a formula such as the Geometric Brownian Motion equation, which is used to predict the random variations in asset prices and inform investor decisions.

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Complete question

What is the Geometric Brownian Motion equation and how is it used in stochastic processes in finance?

Answer:

Step-by-step explanation:

urmom

(×+y)^2 = x^2 + y^2+ 2xy

= 106+ 2×24

=106+48

=154

2×154 = 308

Answer:

20

Step-by-step explanation:

the answer your looking for is 20

Answer:

15/4

Step-by-step explanation:

\(t=\frac{\frac{5}{2} }{\frac{2}{3} } =\frac{(5)(3)}{(2)(2)} =\frac{15}{4}\)

I hope this help you

Answer:

4x+22

Step-by-step explanation:

distribute 4(x+4)

it would become 4x+16+6

16+6 = 22

4x+22

Answer: 3. Tan; 4. 4.76; 5. 12

Step-by-step explanation: First question: SOH CAH TOA; if you draw a picture with the given information you know the Opposite and Adjacent sides to the upper left angle, or OA which is also Tan according to Soh Cah Toa. Second question: Use inverse tan(1/12) to solve. Third question: Same idea as the last question but use inverse sin(1/5)

(a) The population proportion of success is given as 53%. This means that 53% of the population is expected to have a successful outcome from the flu shot.

To calculate the population proportion of success, we are given that the flu vaccine is effective for 53% of patients administered the shot. This means that 53% (or 0.53) of the entire population is expected to have a successful outcome from the flu shot.

(b) The mean of the sampling distribution of the sample proportion is also 53%.

The mean of the sampling distribution of the sample proportion can be calculated using the same population proportion of success, which is 53%. The sampling distribution represents the distribution of sample proportions if multiple samples of the same size are taken from the population. Since the mean of the sampling distribution is equal to the population proportion, the mean in this case is also 53%.

(c) The standard deviation of the sampling distribution of the sample proportion is approximately 0.017.

To calculate the standard deviation of the sampling distribution of the sample proportion, we use the formula:

\(\sigma = \sqrt{\frac{p \cdot q}{n}}\)

where σ represents the standard deviation, p is the population proportion of success (0.53), q is the complement of p (1 - p, which is 0.47), and n is the sample size (85).

Plugging in the values, we get:

\(\sigma = \sqrt{\frac{0.53 \cdot 0.47}{85}}\)

Calculating this expression, we find:

\(\sigma \approx \sqrt{\frac{0.0251}{85}} \approx \sqrt{0.000295} \approx 0.0171\)

Rounding this value to three decimal places, the standard deviation of the sampling distribution of the sample proportion is approximately 0.017.

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The expected value of n ( a random variable that corresponds to your net winnings in dollars ) is :

-$4.83

To find the expected value of n, we need to calculate the product of each possible outcome (1, 2, 3, 4, 5, 6) with its corresponding probability and sum them up.

The probability of each outcome is equal since each outcome is equally likely. Therefore, the probability of each outcome is 1/6.

Using this information, we can calculate the expected value of n as follows:

Expected value of n = (1/6)($1)^2 + (1/6)($2)^2 + (1/6)($3)^2 + (1/6)($4)^2 + (1/6)($5)^2 + (1/6)($6)^2 - $20

Expected value of n = (1/6)(1) + (1/6)(4) + (1/6)(9) + (1/6)(16) + (1/6)(25) + (1/6)(36) - $20

Expected value of n = 15.17 - $20

Expected value of n = -$4.83

Therefore, the expected value of n is -$4.83. This means that on average, you are expected to lose $4.83 for every game you play.

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The probability is approximately 0.543. To calculate the probability that a student is both a junior and a chemistry major,

we can use the concept of intersection and the formula for the probability of independent events.

Given:

Total number of students in the class = 46

Number of juniors = 25

Number of chemistry majors = 28

Number of students who are neither junior nor chemistry major = 5

The probability that a student is both a junior and a chemistry major can be calculated as follows:

P(Junior and Chemistry major) = P(Junior) * P(Chemistry major)

Since the events "being a junior" and "being a chemistry major" are not independent (as the number of juniors who are chemistry majors may vary), we need to adjust the probability calculation.

We can find the number of students who are both juniors and chemistry majors by finding the minimum number between the number of juniors and the number of chemistry majors:

Number of students who are both juniors and chemistry majors = min(25, 28) = 25

Now, we divide this number by the total number of students to get the probability:

P(Junior and Chemistry major) = 25 / 46 ≈ 0.543

Therefore, the probability that a randomly selected student is both a junior and a chemistry major is approximately 0.543.

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a) To find the elements of the set \(XY\), we need to concatenate each element of \(X\) with each element of \(Y\  b) To list the elements of \(X^*\) of length 4 or less, we need to consider all possible combinations of elements from \(X\) with repetition.

Since the maximum length is 4, we can have elements with lengths 1, 2, 3, or 4. The elements of \(X^*\) are:

where ε represents the empty string.

c) To provide a regular expression for \(X^*\), we can represent the elements of \(X^*\) using the alternation operator \(+\). The regular expression for \(X^*\) is:

This regular expression matches any combination of elements from \(X\) including the empty string.

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Answer:

The the compound ineterest is $2205

Step-by-step explanation:

5/100 * 2000 = 100

2000 + 100 = 2100

5/100 * 2100 = 105

2100 + 105 = 2205

Hence the the compound ineterest is $2205

Answer: 50 feet

Step-by-step explanation: it went 40 feet to get to the surface of the water then it went and extra 10 feet above water so 40+10=50

Answer:

Do you have a photo or picture of this question, I don't want to give you the incorrect answer because something was missing.

Answer: a = 8;  b = 15;  c = 17

Step-by-step explanation:

c = b + 2  and c = 2a + 1

b = c − 2 and a =  \(\frac{c-1}{2}\)

​

c² = b² + a²  

\(c^{2} = (c-2)^{2} + \frac{c-1}{2}\\\)

\(c^{2}= \frac{4 (c-2)^{2}+(c - 1)^{2} }{4}\)

\(4c^{2}={4 (c^{2} + 4 -4c)+c ^{2} + 1-2c\)

\(4c^{2}={4 c^{2} + 16 -16c)+c ^{2} + 1-2c\)

\(c^{2}-18c+17=0\)

\(c(c -17)-1(c-17)=0\)

​\((c -1)(c-17)=0\)

c = 1 or c = 17

If c = 1 then b = 1 - 2 = -1, that's not possible

So x = 17

b = 17 - 2 = 15

a = \(\frac{17-1}{2} = 8\)

Length sides of the triangle are 17 cm, 15 cm and 8 cm.

I saw some of this on a site but I want to make sure its correct so we're gonna apply the pythagorean theory and see if its correct.

\(a^{2} + b^{2} = c^{2} \\8^{2} + 15^{2} = 17^{2} \\64 + 225 = 289\\289 = 289\\\)

This shows that this is correct.

Hope this helped! Again, some of this was from a site, not from me.

The average size of family farm in salem village has a direct connection with the salem witch trials simply because the farm itself also exist or in confined with the same village

And for a whatever issues affect a village also affect its entities including the farm land

However some few causes of witch trials in the village as of that time include:

A family refers to a group of people which are related by blood

So therefore, the average size of family farm in salem village has a direct connection with the salem witch trials simply because the farm itself also exist or in confined with the same village

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Answer:

opposite operation

Step-by-step explanation:

divide 35 by 5 so x=7

Answer: B.

Step-by-step explanation:

There is a \(\frac{3}{8}\) chance of you picking out a green candy. Since there are a total of 8 candies, your denominator is 8. Out of 8, there are 3 green candies.

And out of 160 candies, you have an unknown amount of green candies that you need to find. (x)

Answer:

circumference of a circle = 2*π*10,5=66cm

Step-by-step explanation:

Answer:

I think the answer is C 66 cm