Help pleaseeeeeeeeeeeeeeeeeeeeee

(a)the common ratio = 2

(b)the 6th term​ = 64

How to find the common ratio and 6th term ?

        Here, the common ratio = r

                   the first term = a = 2

(a)the common ratio

\(a +ar^{2} = 10\\\\2(1+r^{2} ) = 10\\\\(1+r^{2} ) = 5\\\\r^{2} =4\\\\r = 2\)

The common ratio (r) = 2

(b)the 6th term​

\(a_{n}=ar^{n-1} \\\\a_{6}=ar^{6-1} \\\\a_{6} =2(2^{5} )\\\\a_{6}=64\)

Thus ,the 6th term​ = 64

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Answer:

D. x>5

Step-by-step explanation:

\(3x + 2 < 4x - 3 \\ = 3x - 4x < - 3 - 2 \\ = - x < - 5 \\ = x > 5\)

The inverse of the function → f(x) = 2x + 5  is → f⁻¹(x) = (x/2) - (5/2).

Inverse of a function can be calculated by following the steps mentioned below -

According to the question, the equation given is as follows

y = f(x) = 2x + 5

y = 2x + 5

Replace 'y' with 'x', we get -

x = 2y + 5

Now, solve for y -

2y = x - 5

y = (x/2) - (5/2)

Replace 'y' with f⁻¹(x) -

f⁻¹(x) = (x/2) - (5/2)

Hence, the inverse of the function → f(x) = 2x + 5  is → f⁻¹(x) = (x/2) - (5/2).

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Answer:

he spent 2hours 50minutes snowboarding

the time he spent skiing and snowboarding minus the time he skied

5hours minus 2hours 10minutes

Answer:

6%

Step-by-step explanation:

Solving our equation

r = 1200 / ( 2000 × 10 ) = 0.06

r = 0.06

converting r decimal to a percentage

R = 0.06 * 100 = 6%/year

The interest rate required to

accumulate simple interest of $ 1,200.00

from a principal of $ 2,000.00

over 10 years is 6% per year.

The simplified form of the given expression, 6 × 10⁻³ / 8 × 10⁻⁶, is 3/4  × 10³

From the question, we are to simplify the given expression

The given expression is

6 × 10⁻³ / 8 × 10⁻⁶

Simplifying the expression

6 × 10⁻³ / 8 × 10⁻⁶

This can be written as

6/8 × 10⁻³/10⁻⁶

Reduce the fraction

3/4  × 10⁻³/10⁻⁶

Apply the division law of indices

3/4  × 10⁻³ ⁻ ⁽⁻⁶⁾

3/4  × 10⁻³ ⁺ ⁶

3/4  × 10³

Hence, the value is 3/4  × 10³

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What is the question?

The equation of the parabolic arc that accomplishes this task is:

y = (-k/256)(x - 16)² + k.

In which k is the maximum height of the arc.

The equation of a quadratic function, of vertex (h,k), is given by:

y = a(x - h)² + k

In which a is the leading coefficient.

For this problem, the arc has these following characteristics:

The road under the arc is 20 feet wide with a 6-foot sidewalk on both sides of the road, hence it's total length is of 20 + 2 x 6 = 32 feet, and the peak of the arc will be at h = 16.

Hence:

y = a(x - 16)² + k.

The height is of 0 at x = 0 and x = 32, hence:

0 = 256a + k.

a = -k/256

y = (-k/256)(x - 16)² + k.

In which k is the maximum height of the arc.

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Answer:

The answer should be 13.928

Step-by-step explanation:

You do A square + B square = C square

The inverse of f(x) = x^(7/9) using exponential notation is f(x) = x^(9/7)

An inverse function in mathematics is a function that "undoes" another function.

In other words, if f(x) yields y, then y entered into the inverse of f yields the output x.

An invertible function is one that has an inverse, and the inverse is represented by the symbol f⁻¹.

The given function is of the form

f(x) = x^(7/9), this is equivalent to ⁹√x⁷

say f(x) = y, then

f(x) = y = x^(7/9)

y = x^(7/9)

solving for the inverse, of y = x^(7/9)

y = x^(7/9)

y^(9/7) = x

interchanging the letters

y = x^(9/7)

hence the inverse function is solved to be f⁻¹(x) = x^(9/7)

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The value of x from the venn diagram if P(T | V) = 1/5 is 16

From the question, we have the following parameters that can be used in our computation:

The venn diagram

From the venn diagram, we have the following probability values

P(T | V) = (x - 4)/(3x + x - 4)

Evaluate the like terms

So, we have

P(T | V) = (x - 4)/(4x - 4)

From the question, we have

P(T | V) = 1/5

This means that

(x - 4)/(4x - 4) = 1/5

When evaluated, we have

x = 16

Hence, the value of x is 16

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By differentiation rules, the expression for the derivative of the function h(x) = u(x)^v(x), where u(x) = x² + 4 and v(x) = 5 · x is h'(x) = [(x² + 4)^(5 · x)] · [[(5 · x) / (x² + 4)] · (2 · x) + ㏑ (x² + 4) · 5].

In this question we find a differentiation rule for a function of the form h(x) = u(x)^v(x). Herein we find a function whose components are u(x) = x² + 4 and v(x) = 5 · x. First, determine the derivatives of u(x) and v(x):

u'(x) = 2 · x, v'(x) = 5

Second, substitute in the expression of the differentiation rule:

h'(x) = [u(x)^v(x)] · [[v(x) / u(x)] · u'(x) + ㏑ [u(x)] · v'(x)]

h'(x) = [(x² + 4)^(5 · x)] · [[(5 · x) / (x² + 4)] · (2 · x) + ㏑ (x² + 4) · 5]

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1. It is false that when non-Standard unit used is small few unit's are

needed .

2. Objects with different shapes can have the same volume. True

3. Length, width and height and multiplied to find volume of a rectangular prism. True

4. It is false that volume is measured in square unit.

5. It is true that Volume is a measure of the amount of space inside an object.

6. The formula for volume of a rectangular prism is V = l × w × h. True

7. It is true that Standard units give a consistent and accurate measure of a container.

8. It is false that Non-Standard units cannot be used to measure volume.

9. Volume is measured in cubic units. True

Volume can be defined as the amount of space inside and object. the object can be in different form such as cone, rectangular prism, cylinder and many other shapes. Even though shapes are different, It is possible for different shapes or objects to have the same volume when measure.

Measurement of volume can be through standard measurement and non standard measurements such as a cup of rice. However, for consistency and the sake of accuracy, it is advisable to always use standard measurements of volume where possible to avoid error that may occur in non standard measurement. The acceptable and recognized unit of volume is cubic meter (\(m^3\)).

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Answer:

10.5 mph

Step-by-step explanation:

To find the constant of proportionality in miles per hour, we need to divide the distance (in miles) by the time (in hours) for each of the two runs, and then take the average of the two rates.

For Monday's run:

Rate = Distance / Time = 21 miles / 3 hours = 7 miles per hourFor Wednesday's run:Rate = Distance / Time = 10 1/2 miles / 1 1/2 hours = (21/2) miles / (3/2) hours = 14 miles per hour

To find the average rate, we add the two rates and divide by 2:Average rate = (7 miles per hour + 14 miles per hour) / 2 = 10.5 miles per hour

Therefore, the constant of proportionality in miles per hour is 10.5. This means that Ashley runs at an average rate of 10.5 miles per hour during her training.

To solve the savings plan balance, we have to calculate the interest for 19 months. The formula for calculating interest for compound interest is given below:$$A = P \left(1 + \frac{r}{n} \right)^{nt}$$where A is the amount, P is the principal, r is the rate of interest, t is the time period and n is the number of times interest compounded in a year.

The given interest rate is 11% per annum, which will be converted into monthly rate and then used in the above formula. Therefore, the monthly rate is $r = \frac{11\%}{12} = 0.0091667$.

The monthly payment is $PMT = $250. We need to find out the amount after 19 months. Therefore, we will use the formula of annuity.

$$A = PMT \frac{(1+r)^t - 1}{r}$$where t is the number of months of the plan and PMT is the monthly payment. Putting all the values in the above equation, we get:

$$A = 250 \times \frac{(1 + 0.0091667)^{19} - 1}{0.0091667}$$$$\Rightarrow

A = 250 \times \frac{1.0091667^{19} - 1}{0.0091667}$$$$\Rightarrow

A =250 \times 14.398$$$$\Rightarrow A = 3599.99$$

Therefore, the savings plan balance after 19 months with an APR of 11% and monthly payments of $250 is $3599.99 (approx).

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Answer:

Step-by-step explanation:

In the Intermediate Phase of mathematics education, one topic that demonstrates a hierarchical and logical progression in patterns, functions, and algebra is the concept of "Linear Equations."

The topic of Linear Equations in the Intermediate Phase builds upon the foundation laid in earlier grades and serves as a stepping stone towards more advanced algebraic concepts. Here is an overview of the topic sequence and content area spread for Linear Equations:

Introduction to Variables and Expressions:

Students are introduced to the concept of variables and expressions, learning to represent unknown quantities using letters or symbols. They understand the difference between constants and variables and learn to evaluate expressions.

Solving One-Step Equations:

Students learn how to solve simple one-step equations involving addition, subtraction, multiplication, and division. They develop the skills to isolate the variable and find its value.

Solving Two-Step Equations:

Building upon the previous knowledge, students progress to solving two-step equations. They learn to perform multiple operations to isolate the variable and find its value.

Writing and Graphing Linear Equations:

Students explore the relationship between variables and learn to write linear equations in slope-intercept form (y = mx + b). They understand the meaning of slope and y-intercept and how they relate to the graph of a line.

Systems of Linear Equations:

Students are introduced to the concept of systems of linear equations, where multiple equations are solved simultaneously. They learn various methods such as substitution, elimination, and graphing to find the solution to the system.

Word Problems and Applications:

Students apply their understanding of linear equations to solve real-life word problems and situations. They learn to translate verbal descriptions into algebraic equations and solve them to find the unknown quantities.

The content area spread for Linear Equations includes concepts such as variables, expressions, equations, operations, graphing, slope, y-intercept, systems, and real-world applications. The progression from simple one-step equations to more complex systems of equations reflects a logical sequence that builds upon prior knowledge and skills.

By following this hierarchical progression, students develop a solid foundation in algebraic thinking and problem-solving skills. They learn to apply mathematical concepts and procedures in a systematic and logical manner, paving the way for further exploration of patterns, functions, and advanced algebraic topics in later phases of mathematics education.

The maximum price you can offer for a home is approximately $82,352.94 for a 17% down payment.

To determine the maximum price you can offer for a home, you need to calculate 17% of the total price, which will be your down payment of $14,000.

Let's assume the maximum price you can offer for the home is P dollars.

According to the given information, the down payment requirement is 17% of the total price. So, we can set up the following equation:

\(0.17P = $14,000\)

To solve for P, divide both sides of the equation by 0.17:

P = $14,000 / 0.17

Calculating this expression, we find:

P ≈ $82,352.94

Therefore, the maximum price you can offer for a home in order to have enough money for the 17% down payment is approximately $82,352.94.

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The size of the largest interior angle of the field is 69.86°

The law of cosines relates the lengths of the sides of a triangle to the cosine of one of its angles.

Given that, a triangular field has boundaries of lengths 170m, 195m and 210m, we need to find the size of the largest interior angle of the field,

We know that, angle opposite to the largest side is largest,

Therefore,

The largest angle is opposite is 210 m side, (say c)

Using the cosine rule,

210² = 170²+195²-2(170)(195)cosC

CosC = 170²+195²-210² / 2(170)(195)

CosC = 22825 / 66300

CosC = 0.344268477

C = 69.86°

Hence, the size of the largest interior angle of the field is 69.86°

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Answer:

1.8

Step-by-step explanation:

Using the cross product for the proff of Pythagoras theorem, the correct step is

By the cross product property, AB² =  BC multiplied by BD

The cross product property is typically used to solve equations with two values, where the product of the extremes (the outer terms) is equal to the product of the means (the inner terms).

For the similar triangles, the ratio is as follows

BD / BA = BA / BC

BA² = BD * BC

and AB = BA, hence

BA² = BD * BC

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The fraction of the class that is sophomores is \(35/43\).

The fraction of the class that is sophomores, divide the number of sophomores by the total number of students in the class.

Number of sophomores = 35

Total number of students = 43

Fraction of sophomores = (Number of sophomores)/(Total number of students Fraction of sophomores)

Fraction of sophomores  \(= 35 / 43\)

Therefore, the fraction of the class that are sophomores is = \(35/43\).

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Steps to solve:

-2x > -6

~Divide -2 to both sides

x < 3

Best of Luck!

\(\framebox{\parbox[t][1.0cm]{4.50cm}{\addvspace{0.2cm} \centering $ \;\; \,x<3 \;\; \;\; $ } }\\\)

Step-by-step explanation:

\(-2x>-6\)

To solve this inequality, you must first divide(both sides of the inequality).

\(\frac{-2x}{-2} >\frac{-6}{-2}\)

Now we got an answer!

\(x<3\)

Hope this helps!

Let's call the amount invested in the 4% account "x". According to the problem, Jolene invested twice as much in the 4% account, so the amount invested in the 9% account is "2x".

To calculate the interest earned on each account, we use the formula:

Interest = Principal × Rate × Time

For the 4% account, the interest earned is:

0.04 * x * 1 = 0.04x

For the 9% account, the interest earned is:

0.09 * 2x * 1 = 0.18x

The sum of the interest earned on both accounts is given as $5899:

0.04x + 0.18x = 5899

Combining like terms, we get:

0.22x = 5899

Solving for x, we get:

x = 26813.64

Jolene invested $26813.64 in the 4% account and twice as much in the 9% account, which is:

2x = 2 * 26813.64 = 53627.28

Therefore, Jolene invested $26813.64 at 4% and $53627.28 at 9%.

Answer:

it is probably 1.884 cm andd it is accurate

Answer:

-8 is less than k is less than -2

Step-by-step explanation:

I think we are trying to find k

-50 is less than 7k+6 is less than -8

-6                           -6                     -6

-56 is less than 7k is less than -14

-56/7 is less than 7k/7 is less than -14/7

-8 is less than k is less than -2

Hope this helps!

Answer:

Step-by-step explanation:

-50 - 6 < 7k < -8-6

 -56 < 7k < -14

   -8 < k < -2

Answer: 45.5 miles

Step-by-step explanation: divide182 by 4

Answer:

182/4=45.5

the bus travels 45.5 miles in 1 hour

I hope this helps!!

Step-by-step explanation:

Answer:

D. \( = \frac{b}{a} \)

Step-by-step explanation:

Given:

\( \frac{b^{-2}}{ab^{-3}} \)

Required:

Assuming a ≠ 0, b ≠ 0, find the expression equivalent to the given expression.

SOLUTION:

\( \frac{b^{-2}}{ab^{-3}} \)

Recall the exponent rule =>  \( \frac{x^{a}}{x^{b}} = x^{a - b} \)

Applying the exponent rule, we would have:

\( \frac{b^{-2 -(-3)}}{a} \)

\( = \frac{b^{-2 + 3}}{a} \)

\( = \frac{b^{1}}{a} \)

\( = \frac{b}{a} \)

Thus, the equivalent expression of \( \frac{b^{-2}}{ab^{-3}} \) = \( \frac{b}{a} \)

Answer:

d

Step-by-step explanation: