help plz, running out of time

Answer:

23.28 g of O2.

Explanation:

We'll begin by calculating the mass of hexane. This can obtain as follow:

Volume of hexane = 10 mL

Density of hexane = 0.66 g/mL

Mass of hexane =?

Density = mass /volume

0.66 = mass of hexane /10

Cross multiply

Mass of hexane = 0.66 x 10

Mass of hexane = 6.6 g

Next, we shall write the balanced equation for the reaction. This is given below:

2C6H14 + 19O2 —> 12CO2 + 14H2O

Next, we shall determine the masses of C6H14 and O2 that reacted from the balanced equation. This can be obtained as follow:

Molar mass of C6H14 = (12.01x6) + (1.008 x 14)

= 72.06 + 14.112

= 86.172 g/mol

Mass of C6H14 from the balanced equation = 2 x 86.172 = 172.344 g

Molar mass of O2 = 16x2 = 32 g/mol

Mass of O2 from the balanced equation = 19 x 32 = 608 g

From the balanced equation above,

172.344 g of C6H14 reacted with 608 g of O2.

Finally, we shall determine the mass of O2 needed to react with 10 mL (i.e 6.6 g) of hexane, C6H14. This can be obtained as follow:

From the balanced equation above,

172.344 g of C6H14 reacted with 608 g of O2.

Therefore, 6.6 g of C6H14 will react with = (6.6 x 608)/172.344 = 23.28 g of O2.

Therefore, 23.28 g of O2 is needed for the reaction.

To find moles when given the molar mass, you can use the concept of molar mass as a conversion factor.Molar mass represents the mass of one mole of a substance, expressed in grams per mole (g/mol).

To calculate moles, divide the given mass of the substance by its molar mass. The equation is:

moles = mass / molar mass

For example, if you have 56 grams of carbon dioxide (CO2) and want to find the number of moles, you need to know the molar mass of CO2, which is approximately 44 g/mol. Using the equation above:

moles = 56 g / 44 g/mol

moles ≈ 1.27 mol

Therefore, there are approximately 1.27 moles of carbon dioxide in 56 grams.

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The electric current is  0.025 A

Electric current refers back to the go with the flow of energy in an electronic circuit and to the amount of strength flowing through a circuit. it's far measured in amperes (A). the bigger the cost in amperes, the more energy is flowing within the circuit.

Ag+ + e¯ →Ag

1F deposits 107.87 g/mol (molecular mass) of silver

1F = 96500 C

Let, 107.87 g/mol needed = 96500 C

Number of coulombs required to deposit 0.3650 g of silver =(96500/107.87) 0.3650  

Q = 326.5 C

According to Faraday’s law, Q = I x t

I = 326.5 C / (216 x 60 s) = 0.025 A

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Answer:

The structure with the ring flipped is the most stable

Explanation:

We have the  trans 1,2 - dimethylcyclohexane. With the wedge/dash structure we could not figure is this form is stable (If we do a comparison with the cis structure). But when we do a chair structure and ring flipped structure, this is easier to look.

The picture attached shows the structures, they are labeled as 1, 2 and 3, according to this problem.

In the chair structure, according to the picture below, you can see that both methyls are heading in the axial positions of the ring (One facing upward and the other downward). This is pretty stable, however, when the methyls are in those positions, the methyl position 1, can undergoes an 1,3 diaxial interactions with the hydrogens atoms (They are not drawn, but still are there), so this interaction makes this structure a little less stable that it can be.

On the other side, the ring flipped structure, we can see that both methyls are in the equatorials positions of the ring, and in these positions, it can avoid the 1,4 diaxial interactions with the hydrogens atoms, making this structure the most stable structure.

Hope this helps

The choice of solution has a concentration of 1.144 mol/kg molality.

Molarity corresponds to the moles of solvent divided by the amount of solution in litres, whereas molality is equal with the moles of solvent divided by the quantity of solvent in kilogrammes.

Since 1 mole of solute is present in 1 litre for the solution, which contains both the solute and the solvent, 1 molar aqueous solutions are more concentrated than one decays aqueous solutions.

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Answer:

An atom is the smallest particle of an element that still has the properties of that element. Atoms, in turn, are composed of subatomic particles, including negative electrons, positive protons, and neutral neutrons. The number of protons in an atom determines the element it represents.

Explanation:

The smallest possible particle of an element is a atom. The remainder is made up of a cloud of negatively charged electrons around a positively charged nucleus made up of protons and neutrons.

The smallest unit of matter that may be split without producing electrically charged particles is the atom. It is also the smallest piece of substance with chemical element-like characteristics. Electric forces, which link electrons towards the nucleus of atoms, cause them to be drawn to any positive charge.

Space makes up the majority of an atom. The remainder is made up of a cloud of negatively charged electrons around a positively charged nucleus made up of protons and neutrons. Compared to electrons, that are the smallest charged particles in nature, the nucleus is tiny and dense.  

Therefore, the smallest possible particle of an element is a atom.

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Answer:

Explanation:

The main assignment here is to provide the structure of A. But before that, let us explain briefly some certain things:

The proton NMR (1H) gives data about the quantity of non-identical protons present in the structure. The resonance frequency is seen regarding the standard compound (0 ppm), which is addressed as a chemical shift. The same protons have equal value of chemical shift.

The protons that are available in a similar environment are addressed as comparable protons and the protons with various conditions are called non-identical protons.

However, from the image below, we can see the reaction of the compound 1,3,5,7-cyclooctatetraene resulting in 2 equivalents of potassium forming an aromatic dianion.

The mole fraction of sulfuric acid in the solution is 1.78 x 10^-4.

We need to know how many moles of sulfuric acid and how many moles there are in the solution as a whole in order to figure out the mole fraction of sulfuric acid.

To begin, we must convert the sulfuric acid's mass into moles. The molar mass of sulfuric corrosive is 98.08 g/mol. As a result, the number of moles of sulfuric acid is equal to 3.4 g divided by 98.08 g/mol, or 0.0347 mol.

Next, we need to figure out how many moles are all around the solution. We can expect that the volume of the arrangement is equivalent to the volume of water added (3500 ml). Notwithstanding, we want to switch the volume from milliliters over completely to liters since the unit of mole portion is moles per liter.

As a result, the volume of the solution is 3500 ml, or 3.5 L. Based on the assumption that water has a density of 1 g/mL, the mass of water in the solution can be calculated as follows:

The molar mass of water, which is 18.02 g/mol, can be used to determine the number of moles of water: mass of water = volume of water x density of water = 3500 ml x 1 g/mL = 3500 g

The mole fraction of sulfuric acid in the solution can be calculated as follows: 3500 g x 18.02 g/mol = 194.14 mol

Mole fraction of sulfuric acid is calculated by dividing the total number of moles in the solution by the number of moles of sulfuric acid: 0.0347 mol / (0.0347 mol + 194.14 mol) = 1.78 x 10-4.

Therefore, the mole fraction of sulfuric acid in the solution is 1.78 x 10^-4.

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Answer:

C

Explanation:

because its half life is shorter than the subsequent ones

The general gas equation, commonly referred to as the ideal gas law, represents the state of a fictitious ideal gas through an equation. Here the mass of helium gas required to pressurize 86 L tank to 201 atm is 2561.8 g.

According to the ideal gas law, the sum of the absolute temperature of the gas and the universal gas constant is equal to the product of the pressure and volume of one gram of an ideal gas.

The ideal gas equation is given as:

PV = nRT

n = PV / RT

56°C = 329 K

n = 201 × 86 / 0.08206 × 329 = 640.45 mol

Molar mass of 'He' = 4.00 g / mol

Mass =  640.45 × 4.00 = 2561.8 g

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Answer:

Volume = 3.4 L

Explanation:

In order to calculate the volume of CO₂ produced when 15.2 g of CaCO₃ is heated, we need to first write out the balanced equation of the thermal decomposition of CaCO₃:

CaCO₃ (s) + [Heat] ⇒ CaO (s) + CO₂ (g)

Now, let's calculate the number of moles in 15.2 g CaCO₃:

mole no. = \(\mathrm{\frac{mass}{molar \ mass}}\)

                 = \(\frac{15.2}{40.1 + 12 + (16 \times 3)}\)

                 = 0.1518 moles

From the balanced equation above, we can see that the stoichiometric molar ratios of CaCO₃ and CO₂ are equal. Therefore, the number of moles of CO₂ produced is also 0.1518 moles.

Hence, from the formula for the number of moles of a gas, we can calculate the volume of  CO₂:

mole no. = \(\mathrm{\frac{Volume \ in \ L}{22.4}}\)

⇒ \(0.1518 = \mathrm{\frac{Volume}{22.4}}\)

⇒ Volume = 0.1518 × 22.4

                 = 3.4 L

Therefore, if 15.2 g of CaCO₃ is heated, 3.4 L of CO₂ is produced at STP.

The oxidation state of nitrogen (N) in NaNO3 is +5. option B

To determine the oxidation state of nitrogen (N) in sodium nitrate (NaNO3), we need to assign oxidation numbers to each element in the compound.

In NaNO3, we know that the sodium ion (Na+) has a +1 oxidation state because it is an alkali metal. Oxygen (O) typically has an oxidation state of -2 in compounds, and there are three oxygen atoms in NaNO3. Since the compound is neutral, the sum of the oxidation states must be zero.

Let's assume that the oxidation state of nitrogen is x. Therefore, we can set up the equation:

(+1) + x + (-2) * 3 = 0

Simplifying the equation:

+1 + x - 6 = 0

x - 5 = 0

x = +5

Therefore, the oxidation state of nitrogen (N) in NaNO3 is +5.

The oxidation state of an element indicates the number of electrons it has gained or lost in a compound. In this case, the nitrogen atom in NaNO3 has gained five electrons to achieve a stable oxidation state of +5.

It is important to note that oxidation states are formal charges and do not necessarily represent the actual distribution of electrons in a compound. They are assigned based on a set of rules and can be useful in understanding the reactivity and behavior of elements in chemical reactions.

Option B

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Answer:

x= 300m , 38s

answer is 7.9

Answer:

speed=distance/time

Explanation:

speed=300/38

=7.8947368421

to the nearest tenth=7.9

Water molecules pull the sodium and chloride ions apart, breaking the ionic bond that held them together. After the salt compounds are pulled apart, the sodium and chloride atoms are surrounded by water molecules, as this diagram shows. Once this happens, the salt is dissolved, resulting in a homogeneous solution.

hope this helps you

have a nice day:)

Answer:

ok, here is your answer

Explanation:

i am going to solve this problem by using the ICE table method which is an easy method to determine the pH of a weak base with the given data of the problem.Given:Initial volume of NH3 solution (Vi) = 75.0 mLInitial concentration of NH3 solution (Ci) = 0.200 MInitial moles of NH3 solution (Ni) = Ci x Vi = 0.200 M x 75.0 mL = 0.0150 molesKb = 1.8 x 10^-5Moles of HNO3 added (n) = 0.500 M x 17.0 mL = 0.00850 molesVolume of NH3 solution after the addition of HNO3 (Vf) = 75.0 mL + 17.0 mL = 92.0 mLConcentration of NH3 solution after the addition of HNO3 (Cf) = Ni / Vf = 0.0150 moles / 92.0 mL = 0.163 MTo find the pH after the addition of 17.0 mL of HNO3, we need to use the ICE table method.ICE table method:Initial: NH3 + H2O ⇌ NH4+ + OH-Change: -x 0 +x +xEquilibrium: 0.0150 - x 0 x xKb = [NH4+][OH-] / [NH3]1.8 x 10^-5 = x^2 / 0.163Solving for x, x = 0.00171 M[OH-] = 0.00171 M[OH-] = Kw / [H3O+] = 1.0 x 10^-14 / [H3O+][H3O+] = 5.85 x 10^-12pH = -log[H3O+]pH = -log(5.85 x 10^-12)pH = 11.23Therefore, the pH after the addition of 17.0 mL of HNO3 is approximately 11.23.

Answer:

skeletal system

Explanation:

to create and fliter blood and provide frame-work to the human body and support

Answer:

Nitrobenzene is too deactivated (by the nitro group) to undergo a Friedel-Crafts alkylation.

Explanation:

The benzene ring in itself does not easily undergo electrophilic substitution reaction. Some groups activate or deactivate the benzene ring towards electrophilic substitution reactions.

-NO2 ia a highly deactivating substituent therefore, Friedel-Crafts alkylation of nitrobenzene does not take place under any conditions.

This reaction scheme is therefore flawed because Nitrobenzene is too deactivated (by the nitro group) to undergo a Friedel-Crafts alkylation.

The answer choice that best describes this is  C. Peter's brain still received messages from his other sensory receptors, which his brain combined with stored memories in order to move through the darkness.

Here, the sensory organs in Peter's eyes, ears, nose, mouth, and internal organs are specialized organs that allow each receptor type to convey a different sensory modality to eventually integrate into a single perceptual frame.

As a result of these sensory organs, Peter will eventually go stuttering when he wakes up in the middle of the night in complete darkness. However, he was able to make his way to the bathroom without bumping into any objects in his path.

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Peter woke up in the middle of night in darkness. Without being able to see, he was able to make his way to the bathroom without running into any objects in his path.

Which of the following best describes how he is able to do this?

A. Peter's brain received visual information from sensory receptors other than his eyes, so there was no change in how his body responded to the darkness around him.

B. Peter's brain used only stored memories as input when he moved through the darkness, as all sensory receptors are directly tied to the visual system.

C. Peter's brain still received messages from his other sensory receptors, which his brain combined with stored memories in order to move through the darkness.

D. Peter's brain used only messages received from his other sensory receptors when he moved through the darkness, as the visual system is not an important part of the central nervous system.​

When hydrogen bromide (HBr) is added to 2-methylbut-2-ene ((CH3)2CCHCH3), an electrophilic addition reaction takes place, where the π bond of the alkene is broken, and the hydrogen and bromine atoms are added to the resulting carbocation.

The reaction proceeds through a Markovnikov addition, where the hydrogen atom attaches to the carbon atom with the greater number of hydrogen atoms.

In this case, the initial addition of HBr to 2-methylbut-2-ene leads to the formation of a primary carbocation, as the positively charged carbon atom only has one alkyl group attached to it. The primary carbocation is relatively unstable, and it can undergo a rearrangement to form a more stable secondary carbocation.

The major product that is typically obtained is the 2-bromo-2-methylbutane. The hydrogen atom from HBr adds to the carbon with three hydrogen atoms (the more substituted carbon), resulting in the formation of a secondary carbocation.

On the other hand, a minor product is also formed, which is 3-bromo-2-methylbutane. This product arises from the addition of HBr to the primary carbocation, which is less stable. Although the primary carbocation is less favored, it can still be formed and lead to the formation of the minor product.

In summary, the addition of HBr to 2-methylbut-2-ene yields two products: the major product is 2-bromo-2-methylbutane, resulting from the addition of HBr to the more stable secondary carbocation, and the minor product is 3-bromo-2-methylbutane, originating from the less stable primary carbocation.

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A) Calculate the lower and upper bounds of the 95% confidence interval:

Lower bound = X - ME

Upper bound = X + ME

B) you would compare the obtained mean concentration (0.101675 N) with the prepared concentration (0.1012 N) and calculate the t-value. The t-value is then compared to the critical t-value at a certain significance level (e.g., a = 0.05) and the degrees of freedom (n-1) to determine if there is a statistically significant difference.

(a) To determine the range within which you can be 95% confident that the true value falls, you can calculate the confidence interval using the obtained results.

First, calculate the mean (X) of the measured concentrations:

X = (0.1017 + 0.1019 + 0.1016 + 0.1015) / 4 = 0.101675 N

Next, calculate the standard deviation (s) of the measured concentrations:

s = sqrt(((0.1017 - X)² + (0.1019 - X)² + (0.1016 - X)² + (0.1015 - X)²) / (4 - 1))

Then, calculate the standard error of the mean (SE) using the formula:

SE = s / sqrt(n)

where n is the number of measurements (in this case, n = 4).

With the standard error, you can calculate the margin of error (ME) for a 95% confidence interval using the t-distribution. The t-value for a 95% confidence interval with 3 degrees of freedom is approximately 3.182.

ME = t * SE

Finally, calculate the lower and upper bounds of the 95% confidence interval:

Lower bound = X - ME

Upper bound = X + ME

(b) To determine if there is a statistical difference between the obtained mean concentration (0.101675 N) and the prepared concentration (0.1012 N), you can perform a t-test. The t-test compares the means of two sets of data to determine if they are significantly different from each other.

Using the formula for a two-sample t-test, you would compare the obtained mean concentration (0.101675 N) with the prepared concentration (0.1012 N) and calculate the t-value. The t-value is then compared to the critical t-value at a certain significance level (e.g., α = 0.05) and the degrees of freedom (n-1) to determine if there is a statistically significant difference.

If the calculated t-value is greater than the critical t-value, it suggests a statistically significant difference between the obtained mean concentration and the prepared concentration.

Please note that the actual calculations and interpretation may vary depending on the statistical software or method used, and it's always recommended to consult a statistician or refer to appropriate statistical references for accurate analysis.

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Answer:

can someone please do this and put the answers below !!!!

Explanation:

Explanation:

A nitrogen-containing compound that shows no absorption band at around 3400 cm^−1 and no absorption bands between approximately 1700 cm^−1 and 1600 cm^−1 is likely an amide compound.

Amides typically exhibit a characteristic absorption band in the region of 3200-3500 cm^−1 due to the N-H stretching vibration. The absence of this absorption band suggests the absence of N-H bonds, which rules out compounds like primary or secondary amines.

The absence of absorption bands between 1700 cm^−1 and 1600 cm^−1 eliminates functional groups such as carbonyl compounds (e.g., aldehydes, ketones, carboxylic acids, esters) and imines, which typically exhibit absorption in this region.

Therefore, based on the given information, it can be inferred that the compound is likely not an amine, carbonyl compound, or imine. Other classes of compounds that do not possess these characteristic absorption bands would need to be considered.

Jeremiah can arrange the materials in the following way to create a model that shows the processes by which water is cycled from a lake into the atmosphere and back to the lake

The following can be a representation of the water cycle;

Fill the glass jar with water to resemble the lake.

Put the lamp next to the jar to symbolize the sun.

Wrap the jar in plastic sheet to imitate the atmosphere.

Turn on the bulb to represent the sun warming the water.

When the water in the jar warms up and evaporates into water vapor, moisture will condense on the plastic wrap.

The water vapor will ascend and collect on the plastic wrap to represent the water vapor rising into the atmosphere.

Water vapor cools as it rises and condenses back into liquid form, as shown by the water droplets gathering on the plastic wrap.

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Answer:

i am not sure i am really just doing it for the points but yea

Explanation:

im just ok lol i wish you guys the best

Answer:

shtfu

Explanation:

Answer:

70

Explanation:

20 x 5 vials = 100mg

therefore 5 vials required each day.

Two weeks = 14 days

14 days x 5 vials = 70 vials

Answer:

I t transfers from the ocean to the air, however the current is not as warm so less energy will transfer from the current to the air making ChrisstChurch cooler than usual.