Help would be greatly appreciated

Answer:

the point the mass of an object will increase when traveling at relativistic speeds

Explanation:

m = m0/((1 - v2/c2))1/2

m0 = the mass measured at rest relative

m = the mass measured by the observers on the other reference frame.

v = the speed of the object

c = the speed of light in a vacuum

Answer:

John applied a force of approximately \(795\; {\rm N}\) (on average, rounded) on Lucy.

John slows down to a stop after approximately another \(5.37\; {\rm s}\).

(Assuming that \(g = 9.81\; {\rm N\cdot kg^{-1}}\).)

Explanation:

Assuming that the surface is level. The normal force on Johnny will be equal to the weight of Johnny: \(N(\text{John}) = m(\text{John})\, g\). Similarly, the normal force on Lucy will be equal to weight \(N(\text{Lucy}) = m(\text{Lucy})\, g\).

Multiply normal force by the coefficient of kinetic friction to find the friction on each person:

\(f(\text{John}) = \mu_{k}\, N(\text{John}) = \mu_{k}\, m(\text{John})\, g\).

\(f(\text{Lucy}) = \mu_{k}\, N(\text{Lucy}) = \mu_{k}\, m(\text{Lucy})\, g\).

Again, because the surface is level, the net force on each person after the first \(1.0\; {\rm s}\) will be equal to the friction. Divide that the net force on each person by the mass of that person to find acceleration:
\(\displaystyle a(\text{John}) = \frac{\mu_{k}\, m(\text{John})\, g}{m(\text{John})} = \mu_{k}\, g\).

\(\displaystyle a(\text{Lucy}) = \frac{\mu_{k}\, m(\text{Lucy})\, g}{m(\text{Lucy})} = \mu_{k}\, g\).

(Note that the magnitude of acceleration is independent of mass and is the same for both John and Lucy.)

\(a = \mu_{k}\, g= (0.2)\, (9.81\; {\rm m\cdot s^{-2}}) = 1.962\; {\rm m\cdot s^{-2}}\).

In other words, after the first \(1\; {\rm s}\), both John and Lucy will slow down at a rate of \(1.962\; {\rm m\cdot s^{-2}}\).

To find the speed of Lucy immediately after the first \(1.0\: {\rm s}\), multiply this acceleration by the time \(t = 8.0\; {\rm s}\) it took for Lucy to slow down to \(0\; {\rm m\cdot s^{-1}}\):

\(\begin{aligned}& (8.0\; {\rm s})\, (1.962\; {\rm m\cdot s^{-2}}) \\ =\; & (8.0)\, (1.962)\; {\rm m\cdot s^{-1}} \\ =\; & 15.696\; {\rm m\cdot s^{-1}}\end{aligned}\).

Thus, in the first \(1.0\; {\rm s}\), Lucy accelerated (from \(0\; {\rm m\cdot s^{-1}}\)) to \(15.696\; {\rm m\cdot s^{-1}}\).

The average acceleration of Lucy in the first \(1.0\; {\rm s}\) would be \((15.696) / (1) = 15.696\; {\rm m\cdot s^{-2}}\). Multiply this average acceleration by the mass of Lucy to find the average net force on Lucy during that \(1.0\; {\rm s}\):

\(\begin{aligned}F_{\text{net}}(\text{Lucy}) &= m(\text{Lucy})\, a \\ &= (45)\, (15.696)\; {\rm N} \\ &= 706.320\; {\rm N}\end{aligned}\).

This net force on Lucy during that \(1.0\; {\rm s}\) is the combined result of both the push from Johnny and friction:

\(F_{\text{net}}(\text{Lucy}) = F(\text{push}) - f(\text{Lucy})\).

Since \(f(\text{Lucy}) = \mu_{k}\, N(\text{Lucy}) = \mu_{k}\, m(\text{Lucy})\, g\):

\(\begin{aligned}F(\text{push}) &= F_{\text{net}}(\text{Lucy}) + f(\text{Lucy}) \\ &= F_{\text{net}}(\text{Lucy}) + \mu_{k}\, m(\text{Lucy})\, g \\ &= (706.320) \; {\rm N}+ (0.2)\, (45)\, (9.81)\; {\rm N} \\ &= 706.320\; {\rm N} + 88.290\; {\rm N} \\ &=794.610\; {\rm N}\end{aligned}\).

In other words, Johnny would have applied a force of \(794.610\; {\rm N}\) on Lucy.

By Newton's Laws of Motion, when Johnny exerts this force on Lucy in that \(1.0\; {\rm s}\), Lucy would exert a reaction force on Johnny of the same magnitude: \(794.610\; {\rm N}\).

Similar to Lucy, the net force on Johnny during that \(1.0\; {\rm s}\) will be the combined effect of the push \(F(\text{push})\) and friction \(f(\text{John}) = \mu_{k}\, m(\text{John})\, g\):

\(\begin{aligned}F_{\text{net}}(\text{John}) &= F(\text{push}) - f(\text{John}) \\ &= F(\text{push}) - \mu_{k}\, m(\text{John})\, g\\ &= 794.610\; {\rm N} - (0.2)\, (65)\, (9.81)\; {\rm N} \\ &= 667.080\; {\rm N}\end{aligned}\).

Divide net force by mass to find acceleration:

\(\begin{aligned}\frac{667.080\; {\rm N}}{65\; {\rm kg}} \approx 10.2628\; {\rm m\cdot s^{-2}}\end{aligned}\).

In other words, Johnny accelerated at a rate of approximately \(10.5406\; {\rm m\cdot s^{-2}}\) during that \(1.0\; {\rm s}\). Assuming that Johnny was initially not moving, the velocity of Johnny right after that \(1.0\; {\rm s}\!\) would be:

\((0\; {\rm m\cdot s^{-1}}) + (10.2628\; {\rm m\cdot s^{-2}})\, (1.0\; {\rm s}) = 10.2628\; {\rm m\cdot s^{-1}}\).

After the first \(1.0\; {\rm s}\), the acceleration of both John and Lucy (as a result of friction) would both be equal to \(a = \mu_{k}\, g= (0.2)\, (9.81\; {\rm m\cdot s^{-2}}) = 1.962\; {\rm m\cdot s^{-2}}\). Divide initial velocity of Johnny by this acceleration to find the time it took for Johnny to slow down to a stop:

\(\displaystyle \frac{10.2628\; {\rm {m\cdot s^{-1}}}}{1.962\; {\rm m\cdot s^{-2}}} \approx 5.23\; {\rm s}\).

Answer:

John applied a force of approximately \(795\; {\rm N}\) (on average, rounded) on Lucy.

John slows down to a stop after approximately another \(5.37\; {\rm s}\).

(Assuming that \(g = 9.81\; {\rm N\cdot kg^{-1}}\).)

Explanation:

Assuming that the surface is level. The normal force on Johnny will be equal to the weight of Johnny: \(N(\text{John}) = m(\text{John})\, g\). Similarly, the normal force on Lucy will be equal to weight \(N(\text{Lucy}) = m(\text{Lucy})\, g\).

Multiply normal force by the coefficient of kinetic friction to find the friction on each person:

\(f(\text{John}) = \mu_{k}\, N(\text{John}) = \mu_{k}\, m(\text{John})\, g\).

\(f(\text{Lucy}) = \mu_{k}\, N(\text{Lucy}) = \mu_{k}\, m(\text{Lucy})\, g\).

Again, because the surface is level, the net force on each person after the first \(1.0\; {\rm s}\) will be equal to the friction. Divide that the net force on each person by the mass of that person to find acceleration:
\(\displaystyle a(\text{John}) = \frac{\mu_{k}\, m(\text{John})\, g}{m(\text{John})} = \mu_{k}\, g\).

\(\displaystyle a(\text{Lucy}) = \frac{\mu_{k}\, m(\text{Lucy})\, g}{m(\text{Lucy})} = \mu_{k}\, g\).

(Note that the magnitude of acceleration is independent of mass and is the same for both John and Lucy.)

\(a = \mu_{k}\, g= (0.2)\, (9.81\; {\rm m\cdot s^{-2}}) = 1.962\; {\rm m\cdot s^{-2}}\).

In other words, after the first \(1\; {\rm s}\), both John and Lucy will slow down at a rate of \(1.962\; {\rm m\cdot s^{-2}}\).

To find the speed of Lucy immediately after the first \(1.0\: {\rm s}\), multiply this acceleration by the time \(t = 8.0\; {\rm s}\) it took for Lucy to slow down to \(0\; {\rm m\cdot s^{-1}}\):

\(\begin{aligned}& (8.0\; {\rm s})\, (1.962\; {\rm m\cdot s^{-2}}) \\ =\; & (8.0)\, (1.962)\; {\rm m\cdot s^{-1}} \\ =\; & 15.696\; {\rm m\cdot s^{-1}}\end{aligned}\).

Thus, in the first \(1.0\; {\rm s}\), Lucy accelerated (from \(0\; {\rm m\cdot s^{-1}}\)) to \(15.696\; {\rm m\cdot s^{-1}}\).

The average acceleration of Lucy in the first \(1.0\; {\rm s}\) would be \((15.696) / (1) = 15.696\; {\rm m\cdot s^{-2}}\). Multiply this average acceleration by the mass of Lucy to find the average net force on Lucy during that \(1.0\; {\rm s}\):

\(\begin{aligned}F_{\text{net}}(\text{Lucy}) &= m(\text{Lucy})\, a \\ &= (45)\, (15.696)\; {\rm N} \\ &= 706.320\; {\rm N}\end{aligned}\).

This net force on Lucy during that \(1.0\; {\rm s}\) is the combined result of both the push from Johnny and friction:

\(F_{\text{net}}(\text{Lucy}) = F(\text{push}) - f(\text{Lucy})\).

Since \(f(\text{Lucy}) = \mu_{k}\, N(\text{Lucy}) = \mu_{k}\, m(\text{Lucy})\, g\):

\(\begin{aligned}F(\text{push}) &= F_{\text{net}}(\text{Lucy}) + f(\text{Lucy}) \\ &= F_{\text{net}}(\text{Lucy}) + \mu_{k}\, m(\text{Lucy})\, g \\ &= (706.320) \; {\rm N}+ (0.2)\, (45)\, (9.81)\; {\rm N} \\ &= 706.320\; {\rm N} + 88.290\; {\rm N} \\ &=794.610\; {\rm N}\end{aligned}\).

In other words, Johnny would have applied a force of \(794.610\; {\rm N}\) on Lucy.

By Newton's Laws of Motion, when Johnny exerts this force on Lucy in that \(1.0\; {\rm s}\), Lucy would exert a reaction force on Johnny of the same magnitude: \(794.610\; {\rm N}\).

Similar to Lucy, the net force on Johnny during that \(1.0\; {\rm s}\) will be the combined effect of the push \(F(\text{push})\) and friction \(f(\text{John}) = \mu_{k}\, m(\text{John})\, g\):

\(\begin{aligned}F_{\text{net}}(\text{John}) &= F(\text{push}) - f(\text{John}) \\ &= F(\text{push}) - \mu_{k}\, m(\text{John})\, g\\ &= 794.610\; {\rm N} - (0.2)\, (65)\, (9.81)\; {\rm N} \\ &= 667.080\; {\rm N}\end{aligned}\).

Divide net force by mass to find acceleration:

\(\begin{aligned}\frac{667.080\; {\rm N}}{65\; {\rm kg}} \approx 10.2628\; {\rm m\cdot s^{-2}}\end{aligned}\).

In other words, Johnny accelerated at a rate of approximately \(10.5406\; {\rm m\cdot s^{-2}}\) during that \(1.0\; {\rm s}\). Assuming that Johnny was initially not moving, the velocity of Johnny right after that \(1.0\; {\rm s}\!\) would be:

\((0\; {\rm m\cdot s^{-1}}) + (10.2628\; {\rm m\cdot s^{-2}})\, (1.0\; {\rm s}) = 10.2628\; {\rm m\cdot s^{-1}}\).

After the first \(1.0\; {\rm s}\), the acceleration of both John and Lucy (as a result of friction) would both be equal to \(a = \mu_{k}\, g= (0.2)\, (9.81\; {\rm m\cdot s^{-2}}) = 1.962\; {\rm m\cdot s^{-2}}\). Divide initial velocity of Johnny by this acceleration to find the time it took for Johnny to slow down to a stop:

\(\displaystyle \frac{10.2628\; {\rm {m\cdot s^{-1}}}}{1.962\; {\rm m\cdot s^{-2}}} \approx 5.23\; {\rm s}\).

Answer:

t = 1.33 seconds

Explanation:

Given that,

The mass of the ball, m = 5 kg

Initial speed, u = 8 m/s

Final speed, v = 12 m/s

Force, F = 15 N

We need to find the time for long the force is applied. Let the time be t. The force is given by :

\(F=\dfrac{m(v-u)}{t}\\\\t=\dfrac{m(v-u)}{F}\\\\t=\dfrac{5\times (12-8)}{15}\\\\=1.33\ s\)

So, the force is applied for 1.33 seconds.

For the display in the children's science museum, we want to demonstrate the physics of a solid sphere rolling down a hill and around a loop-the-loop. The sphere has a radius of 0.123 m and starts at rest at the top of the hill. As it rolls down the track, it gains kinetic energy and rotational energy. However, in order to make it around the loop without falling, the sphere needs to have a minimum speed of 16 m/s at the top of the loop.

To create the display, we can use a model of the hill and loop made out of foam or other materials. We can then place the solid sphere at the top of the hill and give it a gentle push to start it rolling down the track. As it gains speed, it will start to rotate and pick up rotational energy as well. Once the sphere reaches the loop, it needs to have enough kinetic energy to make it around the loop without falling. This means it needs to be moving at a minimum speed of 16 m/s at the top of the loop. We can use a sensor or other measurement device to determine the speed of the sphere as it approaches the loop, and adjust the starting position or initial push as needed to ensure it reaches the minimum speed. Overall, this display will be a great way to teach children about the concepts of kinetic and rotational energy, as well as the physics of rolling and looping objects.

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For the distance you'll have to make a right triangle and solve for the missing side (x). Since the plane isn't traveling directly in the east direction it wont be exactly the m/s multiplied by one hour.

3. 1 hr = 3600s.

d = Vt = 163.7m/s * 3600s = 589,320m.

The engine's efficiency is 16.21%. During one cycle a car's engine undergoes combustion and absorbs 475 J and expels 398 J as heat.

WQH=1 TCTH for efficiency. Naturally, these temperatures are in degrees Kelvin, thus for instance, the efficiency of a Carnot engine with a hot reservoir of boiling water and a cold reservoir of ice cold water will be 1(273/373)=0.27, or little more than 25% of the heat energy is converted into productive work.

Even the most effective heat engines have limited efficiency; it is often far below 50%. It follows that the energy that heat engines waste by dissipating into the environment is a significant loss of energy.

engine's efficiency = \(\frac{475-398}{475} *100%\)

engine's efficiency = \(\frac{77}{475} *100%\)

engine's efficiency = 0.1621*100

engine's efficiency = 16.21%

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Occupant kinematics is referred to as the study of the motion of occupants inside of a vehicle during a crash or accident.

This refers to an incident which occurs unintentionally and suddenly thereby causing different types of harm and damage.

Occupant kinematics involves studying the motion of occupants in a crash and it is used in different types of investigations in other to know the main cause of death. It is also used in vehicle designs so as to produce safer ways and materials used in them so as to reduce the risk of serious harm to the body.

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The maximum RPM that a vinyl record can have before a piece of Swiss cheese slides off is approximately 0.0428 RPM.

In order to calculate the maximum RPM that a vinyl record can have before a piece of Swiss cheese slides off, we need to use the coefficient of static friction between the cheese and the record. The coefficient of static friction is a value that represents the ratio of the force of friction to the normal force.

The equation for the force of friction is given by:
friction = coefficient of static friction × normal force

The normal force is the force that is perpendicular to the surface and is equal to the weight of the object. So the weight of the cheese is 0.25 kg * 9.8 m/s^2 = 2.45 N . We know that the coefficient of static friction is 0.35, so we can plug these values into the equation to find the force of friction:
friction = 0.35 × 2.45 N = 0.855 N

The centripetal force is the force that keeps an object moving in a circular path. It is given by the equation:
centripetal force = m × v² / r
Where m is the mass of the object, v is the velocity, and r is the radius. To find the maximum RPM, we need to find the point at which the force of friction is equal to the centripetal force.

As the radius of the record is not specified, we can consider that it is equal to 1m.So we can put all this information together and write an equation:
0.855 N = 0.25 kg × v² / 1m
Solving for v, we get:
v = √(0.855 N ×1m / 0.25 kg)
v = √(3.42) m/s

To convert this velocity to RPM, we need to divide by the circumference of the record, which is 2πr, so:
RPM = v / (2πr) = v / (2π)
RPM = √(3.42) / (2π) = √(3.42) / (6.28) = 0.27 / 6.28 = 0.0428

So the maximum RPM that a vinyl record can have before a piece of Swiss cheese slides off is approximately 0.0428 RPM.

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Answer:

The answer is A

Explanation:

Solids vibrate in a fixed arrangiment, so to find which is a solid look for the one that vibrates in a fixed arrangiment.

According to the forces of attraction, the question which would best identify model is in solid phase is which model shows the molecules vibrating in a fixed arrangement?

Forces of attraction  is a force by which atoms in a molecule  combine. it is basically an attractive force in nature.  It can act between an ion  and an atom as well.It varies for different  states  of matter that is solids, liquids and gases.

The forces of attraction are maximum in solids as  the molecules present in solid are tightly held while it is minimum in gases  as the molecules are far apart . The forces of attraction in liquids is intermediate of solids and gases.

The physical properties such as melting point, boiling point, density  are all dependent on forces of attraction which exists in the substances.

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A direct circuit is so called because it is a circuit that has only one uninterrupted path for the electric current to flow from the power source (the battery) to the load (the light bulb).

A circuit is an electrical network or system that allows the flow of electrical current. It is composed of components such as resistors, capacitors, inductors, switches, and transistors, which are connected to each other by conductive wires or traces. The components in a circuit are arranged in a way that allows electrons to flow through the circuit in a controlled manner. A circuit may have multiple paths for electrons to travel, allowing it to be used for multiple purposes. Circuit diagrams are used to represent the physical layout of a circuit, showing how the components are connected. A circuit can be used for a variety of applications such as powering a device, controlling a system, or providing a signal. Circuits are also used to create integrated circuits that are used in modern electronics.

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Answer: true

Explanation: A coin falls faster than a feather on earth because the coin has more mass than the feather so gravity pulls harder on the coin than the feather.

Answer:

Because the feather has more AIR RESISTANCE FORCE than the coin....in a vacuum they would fall at the same rate (no air to provide resistance)

Explanation:

Answer:

Condensation on AC vents occurs when warm, humid air comes into contact with the cool surfaces of the vents. This phenomenon is similar to what happens when water droplets form on the outside of a cold glass on a hot day. The main causes of condensation on AC vents are:

Explanation:

Temperature difference: Air conditioning systems lower the temperature of indoor spaces, creating a significant temperature difference between the cold AC vents and the surrounding air. When warm, humid air from the room comes into contact with the cold surface of the vents, the moisture in the air condenses into water droplets.

High humidity: Humidity refers to the amount of moisture present in the air. Higher humidity levels mean that the air is holding more moisture. When the indoor humidity is high, and the AC vents are cooler than the dew point temperature (the temperature at which air becomes saturated and condensation occurs), condensation is more likely to form on the vents.

Inadequate insulation: Poor insulation or improper installation of air conditioning ductwork can lead to condensation issues. If the cool air from the ducts escapes into unconditioned spaces, such as attics or crawl spaces, the temperature difference can cause condensation to form on the vents.

Vent blockage: Blocked or restricted vents can disrupt the airflow from the AC system, resulting in lower temperatures near the vents. This can increase the likelihood of condensation forming on the vent surfaces.

Improper AC sizing: If the air conditioning system is oversized for the space it is cooling, it may cool the air too quickly, leading to shorter cycles and less dehumidification. This can result in higher humidity levels and increased condensation on the vents.

Given:

Two resistors each of resistance R = 60 ohms are connected in parallel.

To find the equivalent resistance of the parallel portion.

Explanation:

The equivalent resistance of the parallel circuit can be calculated by the formula

On substituting the values, the equivalent resistance of the parallel circuit will be

Thus, the equivalent resistance of the circuit is 30 ohms.

Answer:

friction

air drag

every thing that opposes the motion affects kinetic energy

Explanation:

kinetic energy is a energy which is increase with increase in motion and potential energy is energy stored while the object is at rest

potential energy ∝ 1/(kinetic energy)

as kinetic energy increases potential energy decreases

Answer:

C is corret answer okay

Answer:

its all of the above.

Explanation:they all have potential energy but they get it in different ways.

V1 = Vo . This results in the conventional equation Vo = Vidt, where Vo is the integral output signal and Vi is indeed the signal input to the integrator.

Naturally, any coefficient with friction larger than 0.141—which is the minimum number for—will prevent the car from slipping.Keep in mind that the frictional force is orthogonal to the velocity.However, it is still moving in the direction needed to counteract the motion that'd happen in the absence of friction.

Yes.Because the adhesion forces between molecules are stronger when the formular is substantially polished, frictional force increases.In this situation, the friction coefficient will be higher than one.

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Answer:

Explanation:

To find the increase in total internal energy, we first need to find the kinetic energy of the sledgehammer before it hits the spike. We can use the formula:

KE = (1/2) * m * v^2

where KE is the kinetic energy, m is the mass, and v is the velocity.

Plugging in the values, we get:

KE = (1/2) * 2.50 kg * (65 m/s)^2

KE = (1/2) * 2.50 kg * 4225 m^2/s^2

KE = 5212.5 J

Next, we need to find the amount of energy that is converted to internal energy. Since one third of the kinetic energy is converted to internal energy, we can multiply the kinetic energy by 1/3 to find this value:

E = 1/3 * 5212.5 J

E = 1737.5 J

Finally, we need to find the total internal energy increase by adding the energy converted to internal energy to the initial internal energy of the hammer and spike. Since the initial internal energy is zero, the total internal energy increase is simply the energy converted to internal energy:

Total internal energy increase = 1737.5 J

Therefore, the total internal energy increases by 1737.5 J when the sledgehammer hits the spike.

Answer: 5 km/hr

Explanation:

speed= distance divided by time

20/4

= 5 km/hr

Answer: yes i think

Explanation:

Answer:

Yes?

Explanation:

Dhdhdhdhdhdhjddjdj

Answer:

You have to click "Tap me to Toggle Through Answer Options"

Explanation:

Im pretty sure.

Answer:

the top with the largest radius because the radius of curvature is inversely proportional to the angular velocity

Explanation:

Angular and linear velocity are related

         v = w r

         w = v / r

Therefore, if the linear velocity of the two is the same, the one with the smaller radius has the higher angular velocity.

When reviewing the answers, the correct one is:

the top with the largest radius because the radius of curvature is inversely proportional to the angular velocity

The top that has a smaller angular velocity is D. the top with the larger radius because the radius of curvature is directly proportional to the angular velocity.

It should be noted that the top that has a higher angular velocity will be the top with the smaller radius because the radius of curvature is inversely proportional to the angular velocity

On the other hand, since the two spinning tops have different radii while both have the same linear instantaneous velocities at their edges, then the top that has a smaller angular velocity is the top with the larger radius because the radius of curvature is directly proportional to the angular velocity.

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Answer:

Classical physics viewed light as a wave.

Explanation:

because classical physics describes light as waves

The number of revolutions the tire makes during this motion, assuming that no slipping occurs is 54 and the final angular speed of a tire in revolutions per second is 12.2 revolutions per second.

Given Data

Initial speed (u) = 0, Final speed (v) = 22.5 m/s, Time (t) = 8.95 s, Diameter of tire (d) = 58.6 cm = 0.586 m, Radius of tire (r) = d/2 = 0.293 m(a)

Number of revolutions the tire makes during this motion: The circumference of the tire is given as:

Circumference = πd = 3.14 x 0.586 = 1.84 m

Since there is no slipping, the distance covered by the car in 8.95 s is given by: d = ut + 1/2 at²,

Where acceleration (a) = (v - u)/t = 22.5/8.95 = 2.51 m/s²

Therefore, d = 0 x 8.95 + 1/2 x 2.51 x (8.95)² = 100 m

The number of revolutions of the tire during the motion can be given by the ratio of the distance covered by the circumference of the tire.

Revolutions = Distance covered/Circumference = 100/1.84 = 54.35 or 54 revolutions (approx.)

(b) The final angular speed of a tire in revolutions per second:

We can use the following formula to find the angular speed of the tire:

v = ωr

Where, v = final velocity, ω = angular velocity, and r = radius of the tire

So, ω = v/r = 22.5/0.293 = 76.8 rad/s

Number of revolutions per second = 76.8/2π = 12.23 or 12.2 revolutions per second (approx.)

Thus, the number of revolutions the tire makes during this motion, assuming that no slipping occurs is 54 and the final angular speed of a tire in revolutions per second is 12.2 revolutions per second.

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Work is characterized as the resultant action when a force moves an object in the force's direction.

It is clear what the word "force" means. The terms "push" and "pull" are perfectly acceptable at this level to describe forces. An object does not have a force inside of it or within it. Another object applies a force to the first.

When two items come into contact with one another physically and interact, these kinds of forces are involved. Frictional, tensional, normal, air resistance, applied, and spring forces are examples of the several types of contact forces.

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The zonular fibers, a group of minuscule fibrous strands, hold the ciliary body to the lens. This add-on is essential

What exactly minuscule  is tiny?

The definition of tiny. (Page 1 of 2) lowercase letter 1 2a: one of a number of cursive writing types that emerged in the ancient and medieval periods and included small, simpler forms. B: This kind of a letter.

Is our understanding of the effects of any occurrence minimal?

Or possibly tiny, like the daydreams we think and pray will keep us safe. It should be clear that compared to the full range of repercussions leading till the of history, our understanding of the impact of any given event is extremely limited.

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Answer:

A crossroads of trade is a place where many trade routes converge, often leading to the exchange of goods and ideas between different cultures. Historically, cities and towns located at crossroads of trade have been important centers of commerce and cultural exchange. For example, the ancient city of Alexandria in Egypt was a crossroads of trade between Europe, Africa, and Asia, and played a key role in the exchange of goods and ideas between these regions. In modern times, cities such as Dubai and Singapore have become important crossroads of trade due to their strategic location and well-developed infrastructure for transportation and logistics.

Answer:

false plz mark brainliest

Answer:

I think it is Cinder Cone volcano.

The magnitude of the magnetic field produced by a long straight wire is proportional to the current passing through the wire and inversely proportional to the distance from the wire. The regions the net magnetic field is zero is Option D.

To determine in which region the net magnetic field is zero, we can use the right-hand rule. First, we consider each pair of wires individually:

1. Pair A: The currents in both wires are in the same direction, so the magnetic fields produced by each wire add together. Using the right-hand rule, we can see that the net magnetic field points upwards between the wires, downwards to the left of both wires, and downwards to the right of both wires. Therefore, the net magnetic field is zero on the left of both wires (option A).

2. Pair B: The currents in both wires are in opposite directions, so the magnetic fields produced by each wire cancel each other out in the region between the wires. Using the right-hand rule, we can see that the net magnetic field points upwards to the left of both wires and downwards to the right of both wires. Therefore, the net magnetic field is zero between the two wires (option B).

3. Pair C: The currents in both wires are in the same direction, so the magnetic fields produced by each wire add together. Using the right-hand rule, we can see that the net magnetic field points upwards to the left of both wires and downwards to the right of both wires. Therefore, the net magnetic field is not zero in any of the given regions (option D).

4. Pair D: The currents in both wires are in opposite directions, so the magnetic fields produced by each wire cancel each other out in the region between the wires. Using the right-hand rule, we can see that the net magnetic field points upwards to the left of both wires and downwards to the right of both wires. Therefore, the net magnetic field is not zero in any of the given regions (option D).

5. Pair E: The currents in both wires are in opposite directions, so the magnetic fields produced by each wire cancel each other out in the region between the wires. Using the right-hand rule, we can see that the net magnetic field points upwards to the left of both wires and downwards to the right of both wires. Therefore, the net magnetic field is not zero in any of the given regions (option D).

Therefore, the answers are:
Pair A - option A
Pair B - option B
Pairs C, D, and E - option D.

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