Answers
Answer:
Yes, the shark's weight or mass is what causes the bottom string to break. The weight of the shark creates tension on the bottom string, which can cause it to snap if the tension becomes too great.
Related Questions
assume the accleration of the object is a(t) = -9.8 meters per second per second. (Neglect air resistance.)
Answers
In order to calculate the maximum height, let's use Torricelli's equation:
\(V^2=V_o^2+2\cdot a\cdot d\)Where V is the final velocity, Vo is the initial velocity, a is the acceleration and d is the distance traveled.
At the maximum height, the velocity is zero, so we have:
\(\begin{gathered} 0^2=10^2+2\cdot(-9.8)\cdot d\\ \\ -19.6d=-100\\ \\ d=\frac{-100}{-19.6}\\ \\ d=5.1\text{ m} \end{gathered}\)Since the initial height is 2 meters, the maximum height is 7.1 meters.
8. A resting stone is dropped from a very high cliff. When it has fallen 5 m, a B stone is dropped.
A. Explain how the distance between the two stones changes as they fall?
B. Determine the speed of stone B when it has traveled 5 m.
C. In a single velocity vs. time graph, sketch the graphs of the two stones when stone B has traveled 10 m. NO need to place
Answers
Answer:
A. separation is increasing at about 9.90 m/s
B. about 9.90 m/s
C. see attached
Explanation:
A. Both stones are accelerated at the same rate, so the difference in their velocities is the velocity stone A had when stone B was dropped. The distance between the stones increases linearly at that velocity, about 9.90 m/s.
__
B. The speed when accelerated from rest over some distance d can be found as ...
v = √(2dg) = √(2(5 m)(9.8 m/s²)) = 7√2 m/s
The speed of stone B at 5 meters is about 7√2 ≈ 9.90 m/s.
__
C. See the attachment for a velocity vs. time graph. Stone B has traveled 10 m when its velocity is -14 m/s
Look at each written description and equation. Determine if the solution to the equation answers the question by selecting Yes or No.
A
A long-distance athlete can run 12
kilometer in 3 minutes. How many kilometers can he run in an hour?
12 km360 hr=12×603
Yes No B
A search and rescue drone can scan 0.5 hectare in 2 minutes. How many hectares per minute can the drone scan?
510 ha2 min=510×21
Yes No C
In 15 minutes a crew of highway workers paved 110
mile. If they work at the same rate, what portion of a mile will they pave in 1 hour?
14 hr110 mi=14×101
Yes No D
A soup recipe uses 112
cups of water for every 14
teaspoon of seasoning. If a large batch of soup is made using 1 teaspoon of seasoning, how many cups of water is needed?
32 c14 tsp=32×41
Yes No
Answers
I need this answer done asap please therefore I'm rewarding a few extra points.... The question is multiple choice for Law of conservation of movement and energy
Answers
Law of conservation of momentum states "The total momentum of all objects interacting with one another remains constant, regardless of the nature of the forces between the objects".
Law of conservation of energy states "Within a closed system, the total amount of energy will remain constant". The equation derived using the Law of conservation of energy is
E =m g H
E = Energy
m = Mass
g = Acceleration
H = Height
The equation derived using the Law of conservation of momentum is
\(m_{1} u_{1} +m_{2} u_{2}\) = \(m_{1} v_{1} + m_{2} v_{2}\)
\(m_{1}\) = Mass of object 1
\(m_{2}\) = Mass of object 2
\(u_{1}\) = Initial velocity of object 1
\(u_{2}\) = Initial velocity of object 2
\(v_{1}\) = Final velocity of object 1
\(v_{2}\) = Final velocity of object 2
Therefore,
Law of conservation of momentum - The total momentum of all objects interacting with one another remains constant, regardless of the nature of the forces between the objects. Law of conservation of energy - Within a closed system, the total amount of energy will remain constant.To know more about Law of conservation of energy
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The speed of sound is measured to be 340 m/s on a certain day.
What is this in Kilometers per hour?? s/km/h=
Please help and explain how to do these types of problems in very confused!!!
Answers
Explanation:
To do this, we pick the first unit and convert
Picking m first and converting to km:
Since we're converting from a non-prefix to a prefix, we divide the value by the prefix were taking it to. In this case, kilo = 10³ which means we're going to divide our value by 1000 to convert it from m to km
340 m/s ÷ 1000 = 0.34 km/s
Now, let's convert our seconds to hour:
We'll need to calculate how many hours is equivalent to one second first;
1 hr = 60×60 seconds
X hr = 1 second
*Cross multiply*
1 × 1 = X × 60 × 60
1 = 3,600 X
X = 1 / 3,600
X = 2.778×10⁻⁴ hour
So, in the place of "1 Second", we're going to be inserting 2.778×10⁻⁴ hour instead
0.34 km / s = 0.34 km / 2.778×10⁻⁴ hour
(0.34 / 2.778×10⁻⁴) km/hour
1,224 km/h.
340 m/s = 1,224 km/h
A golf ball is hit so that it leaves the club face at a velocity of 45m/s at an angle of 40° to the horizontal. by ignoring the effect of air resistance and spin on the ball, use the information to answer the question (a) to (d).
a) Calculate the horizontal component of the velocity
b) Determine the vertical component of the velocity.
c) Find the time taken for the ball to reach its maximum height.
d) Calculate the horizontal distance travelled when the ball is at its maximum height.
Answers
Answer:a)45cos40 b)45sin40 c) 2.95 d)102
Explanation:
a) \(v_{x} = 45 cos40\)
b) \(v_{y}=45sin40\)
c) Since air resistance is negligible, the only force acting on the golf ball is gravity. Thus, its vertical acceleration is -g. We know the final velocity must be 0 m/s, because this will be when the golf ball reaches the maximum height and starts to change direction (it falls back to the ground). We also know initial velocity in the vertical direction (see part b). Thus, we can use this equation: \(v_{f} = v_{i} + at\).
\(0 m/s = 45sin40 + (-9.8m/s^2)t\\t = 2.95s\)
d) The horizontal distance traveled is dependent on (1) how long the ball is in the air and (2) what the horizontal velocity is. (1) was found in part c, and (2) was found in part a.
\(x=vt\\x=45cos40(2.95) =102m\)
A child is playing with a toy car, and it accelerates to the south from 1.2m/s to 6.3m/s. if the toy car's acceleration is 2.75m/s2, what is the amount of time that the child takes to accelerate the car? Show all your work.
Answers
Answer:
t = 1.9 s
Explanation:
By definition, acceleration is the rate of change of velocity with respect to time, which can be expressed as follows:\(a = \frac{v_{f} -v_{o} }{t_{f} - t_{o} } (1)\)
If we choose t₀ =0, ⇒ tif = tRearranging in (1), we get:\(v_{f} = v_{o} + a*t (2)\)
Solving (2) for t:\(t =\frac{v_{f}-v_{o}}{a} (3)\)
Replacing by the givens in (3):vf = 6.3 m/s
v₀ = 1.2 m/s
a = 2.75 m/s²
\(t =\frac{v_{f}-v_{o}}{a} = t =\frac{6.3m/s-1.2m/s}{2.75m/s2} = 1.9 s (4)\)
OFFERING 80+ POINTS!!!!!!!!!
Three small spheres, A, B, and C, have charges with magnitudes qA, qB, and qC, respectively.The three spheres are aligned along a straight line, as shown in the figure. At the instant shown, the net force on sphere A is zero.:
1. Which of the following statements must be true of the signs of the charges?
a. Only charges qA and qB have the same sign.
b. Only charges qA and qC have the same sign.
c. Only charges qB and qC have the same sign.
d. Charges qB and qC have different signs.
e. Charges qA, qB, and qC all have the same sign.
2. The ratio qC/qB is...
a. 9/4
b. 1/1
c. 4/9
d. 1/4
e. 1/9
3. Which of the following is true about the sign of charge qA?
a. The sign of charge qA must be the same as that of qB.
b. The sign of charge qA must be the same as that of qC.
c. The sign of charge qA must be the same as that of either qB or qC greater magnitude.
d. The sign of charge qA must be the same as that of either qB or qC lesser magnitude.
e. It is possible that qA could be either positive or negative.
OFFERING A LOT OF POINTS FOR ANSWERS AND EXPLANATIONS TO ALL THREE!!
Answers
1. Charges qB and qC have different signs.
2. The ratio qC/qB is 9/4.
3. The sign of charge qA must be the same as that of either qB or qC lesser magnitude.
What is electric force?Electric force is the attracting or repulsive interaction between any two charged things. Similar to any force, Newton's laws of motion describe how it affects the target body and how it does so.
1. As net force on qA is zero, charges qB and qC have different signs.
2. The ratio qC/qB is = (3d)²/(2d)² = 9/4.
3. As the net force on qA is zero, the sign of charge qA must be the same as that of either qB or qC lesser magnitude.
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The angle between vector A = 2.00i + 3.00j and vector B is 45.0°. The scalar product of vectors A 12) and B is 7.00. If the x-component of vector B is positive, what is vector B
Answers
Answer:
B = 2.67i - 0.53j
Explanation:
In order to find the vector B, you first take into account the following formula:
\(\vec{A}\cdot\vec{B}=ABcos\theta\) (1)
where:
A = 2.00i + 3.00j
B = ?
θ: angle between vectors A and B = 45.0°
You use the fact that the dot product between vectors A and B is 7.00.
You calculate the magnitude of A vector as follow:
\(A=\sqrt{(2.00)^2+(3.00)^2}=3.60\)
Then, you solve the equation (1) for the magnitude of B:
\(B=\frac{\vec{A}\cdot\vec{B}}{Acos\theta}=\frac{7.00}{3.60cos(45\°)}=2.74\)
Next, you can consider that the A vector is the x axis of the coordinate system, to calculate the components of B. This means that the coordinate system is rotated an angle equivalent to the angle of A respect to the x axis.
With the previous assumption you have that the components of B are:
\(B_x=Bcos\theta=(2.74)cos45\°=1.93\\\\B_y=Bsin45\°=(2.74)sin45\°=1.93\)
The vector B is:
B = 1.93i + 1.93j
Next, it is necessary to rotate again the coordinate system to its original position. For that, you calculate the angle of A:
\(\alpha=tan^{-1}(\frac{3.00}{2.00})=56.30\)
In order to calculate the real components of B, you rotate the system 56.30°, by using the following relation:
\(B_x'=B_xcos\alpha+B_ysin\alpha\\\\B_x'=1.93cos(56.30\°)+1.93sin(56.30\°)=2.67\\\\B_y'=-B_xsin\alpha+B_ycos\alpha\\\\B_y'=-1.93sin(56.30\°)+1.93cos(56.30\°)=-0.53\)
The vector B is:
B = 2.67i - 0.53j
URGENTTTT
Referring to the graph in the section header, what was his displacement between 100 and 300 seconds?
Referring to the graph in the section header, what was the runner's velocity during segment D?
Answers
The displacement of the runner according to the graph is obtained as 250 m.
What is the displacement?The term displacement has to do with the distance that is covered in a specified direction. The difference between distance and displacement is that displacement is a vector while distance is a scalar quantity.
Thus we bring the direction into play when we are talking about the displacement of the object. Now we have a graph that shows the displacement of the runner in the vertical axis and then shows the time that is taken in the horizontal axis.
Given the graph as we have it, we can be bale to pick out the following from the graph;
1) Displacement of the runner at 100 s = 500 m
2) Displacement of the runner at 300 s = 750 m
Therefore;
Displacement of the runner between 100 and 300 seconds;
750 m - 500 m = 250 m
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what are differences between an entrepreneur and an employee
Answers
What is sound waves
Answers
Sound waves are a type of mechanical wave that propagate through a medium, typically air but also other materials such as water or solids.
Characteristics of sound wavesFrequency: the frequency of a sound wave refers to the number of cycles or vibrations it completes per second and is measured in Hertz (Hz).
Amplitude: the amplitude of a sound wave refers to the maximum displacement or intensity of the wave from its equilibrium position. It represents the loudness or volume of the sound, with larger amplitudes corresponding to louder sounds and smaller amplitudes corresponding to softer sounds.
Wavelength: the wavelength of a sound wave is the distance between two consecutive points in the wave that are in phase, such as from one peak to the next or one trough to the next. It is inversely related to the frequency of the wave.
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Select all the correct answers.
When people use plastic combs on their hair, the combs become negatively charged. Which statements about this situation are true?
The comb loses electrons.
The comb gains electrons.
The hair loses electrons.
The hair gains protons.
The hair loses protons.
Answers
Answer:
so therefore, the comb gains electron and the hair losses electrons
Explanation:
It is known that electron contain a negative charge.
So, when an atom gain electrons then number of electrons within the atom increases. As a result, the atom acquires a negative charge.
But when an atom loses electrons, there will be deficiency of electrons within the atom. As a result, the atom becomes positively charged.
Hence,, when people use plastic combs on their hair, the combs become negatively charged. The situation which is true about this is the comb gains electrons and the hair loses electrons.
An object is (starting at rest) begins to plummet towards the earth. Assuming it is in a vacuum, how fast is the object traveling after 5s?
Answers
Answer:
–50.96
Explanation:
The following data were obtained from the question:
Initial velocity (Vᵢ) = 0 m/s
Acceleration (a) = – 9.8 m/s²
Time (t) = 5.2 s
Final velocity (Vբ) =.?
Acceleration is simply defined as the change of velocity with time. Mathematically, it is expressed as:
Acceleration (a) = Final velocity (Vբ) – Initial velocity (Vᵢ) /Time (t) =
a = (Vբ – Vᵢ) / t
With the above formula, we can determine how fast the object is traveling after 5 s as follow:
Initial velocity (Vᵢ) = 0 m/s
Acceleration (a) = – 9.8 m/s²
Time (t) = 5.2 s
Final velocity (Vբ) =.?
a = (Vբ – Vᵢ) / t
– 9.8 = (Vբ – 0) / 5.2
– 9.8 = Vբ / 5.2
Cross multiply
Vբ = –9.8 × 5.2
Vբ = –50.96 m/s
Therefore, the object is traveling at
–50.96 m/s
Heather and Jerry are standing on a bridge 46 m
above a river. Heather throws a rock straight down with a speed of 14 m/s
. Jerry, at exactly the same instant of time, throws a rock straight up with the same speed. Ignore air resistance. How much time elapses between the first splash and the second splash?
Answers
The time elapsed between the first splash and the second splash is approximately 0.69 seconds.
To calculate this, we consider the motion of two rocks thrown simultaneously from a bridge. Heather throws a rock straight down with a speed of 14 m/s, while Jerry throws a rock straight up with the same speed.
We use the equation for displacement in uniformly accelerated motion: s = ut + (1/2)at^2.
For Heather's rock, which is thrown downwards, the initial velocity (u) is positive and the acceleration (a) due to gravity is negative (-9.8 m/s^2). The displacement (s) is the height of the bridge (46 m).
Solving the equation, we find two possible values for the time (t): t ≈ -4.91 s and t ≈ 1.91 s.
Since time cannot be negative in this context, we discard the negative value and consider t ≈ 1.91 s as the time it takes for Heather's rock to hit the water.
For Jerry's rock, thrown upwards, we use the same equation with the same initial velocity and acceleration. The displacement is also the height of the bridge, but negative.
Solving the equation, we find t ≈ -5.68 s and t ≈ 1.22 s. Again, we discard the negative value and consider t ≈ 1.22 s as the time it takes for Jerry's rock to reach its maximum height before falling back down.
To find the time difference between the first and second splash, we subtract t ≈ 1.91 s (Heather's rock) from t ≈ 1.22 s (Jerry's rock). This gives us a time difference of approximately 0.69 seconds.
Therefore, the time elapsed between the first splash and the second splash is approximately 0.69 seconds.
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Describe the unique characteristics of fluids.
Answers
Answer:
Surface tension, capillary action, and viscosity are unique properties of liquids that depend on the nature of intermolecular interactions. Surface tension is the energy required to increase the surface area of a liquid by a given amount. The stronger the intermolecular interactions, the greater the surface tension
Is it safer for a car to decelerate quickly or slowly? And why?
Answers
Answer:
It depends on the situations. Stopping at a red light you should start decelerating slowly because if you just stop if a car is behind you they may be unprepared for your sudden stop and slam into you. Decelerating quickly when needed to like if you are about to run into a car or someone pulls out in front of you stopping quickly might be none or less damage.
Explanation:
Answer:
Hello!!! erz here ^^
Explanation:
Have you ever seen someone driving? They usually decelerate slowly for a stop signs/traffic lights... But thats the wrong way to do it, Instead you speed right past that light!
(no but seriously the guy/girl above me is correct xD)
The diagram represents a ball being kicked by a foot and rising at an angle of 30 degrees from the horizontal. The ball has a velocity of 5.0 meters per second. (Neglect Friction) If the angle between the horizontal and the direction of the 5.0 meters per second decreases from 30 degrees to 20 degrees, what is the magnitude of the horizontal component of the balls initial velocity
Answers
The magnitude of the horizontal component of the balls initial velocity if the angle between the horizontal and the direction of the 5.0 meters per second decreases from 30 degrees to 20 degrees is 4.7 m / s
cos θ = Adjacent side / Hypotenuse
θ = 20°
V = 5 m / s
Since the direction of ball makes a right angled triangle with the horizontal,
cos θ = \(V_{x}\) / V
\(V_{x}\) = cos 20° * 5
\(V_{x}\) = 0.94 * 5
\(V_{x}\) = 4.7 m / s
The formula used to solve is called as trigonometric ratios formulas. The basic formulae are:
sin θ = Perpendicular/Hypotenuse
cos θ = Base/Hypotenuse
tan θ = Perpendicular/Base
Therefore, the magnitude of the horizontal component of the balls initial velocity is 4.7 m / s
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For which of the following types of electromagnetic radiation will diffraction most likely occur as the wave passes through a classroom doorway? A) X-rays, because of their high energy. B) Visible light, because that type of electromagnetic radiation is most abundant. C) Radio waves, because of their wavelength. D) Diffraction will occur equally for all electromagnetic waves.
Answers
Option C, Because of the wavelength of radio waves and other forms of electromagnetic radiation, diffraction is most likely to occur as the wave travels through a classroom doorway.
Diffraction is the bending of waves around barriers or through apertures that are equivalent to or smaller than the wavelength of the wave.
Because radio waves have longer wavelengths than visible light and X-rays, they are more likely to diffract while passing through a similar-sized aperture, such as a classroom doorway.
Because X-rays have considerably shorter wavelengths and visible light has wavelengths in between, diffraction is less likely to occur in this scenario for these forms of electromagnetic energy. As a result, option C is the right answer.
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Different structures give compounds different properties
Answers
i don’t really know if there is supposed to be a “do” in front of the question but that’s what i found!
An ant is crawling on the sidewalk. At one moment, it is moving south a distance of 5.0 mm. It then turns southwest and crawls 4.0 mm. What is the magnitude of the ant’s displacement?
A) 8.3mm
B) 8.3cm
C) 8.3m
D) 8.3km
Answers
The correct answer is (A) 8.3mm.
The total displacement will be the vector sum of the two displacements given in the question.
let the displacement to the south represent vector A = 5mm in magnitude directed toward south.
let the displacement to the south-west represent vector B = 4mm in magnitude directed toward south-west.
The angle between vector A and vector B is 45°, the angle between south and south-west.
SO the resultant
R = vectro A + vector B
\(R=\sqrt{A^{2}+B^{2}+2ABcos(45) } \\\\R=\sqrt{25+16+40*\frac{1}{\sqrt{2} } } \\\\R=8.3mm\)
The ant's displacement is 8.3 mm in magnitude.
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When heal flows between systems Entropy
Answers
Answer: increases
Explanation:
A girl walks South at 2.7 m/s. What is the y component of her velocity
Answers
Answer:
-2.7m/s
Explanation:
...............
A body dropped over a fixed rough inclined plane of inclination 45 from height h. If after collision velocity of body becomes horizontal
then co-efficient of restitution if co-efficient of friction is 1/2
Answers
As per the given scenario, in this case, the coefficient of friction () is half and the coefficient of restitution (e) is zero.
Identify the body's starting velocity:
We may use the equation of motion to get the body's initial velocity (u)
\(v^2 = u^2 + 2as\)
\(0 = u^2 + 2(-9.8)m/s^2 * h\)
\(u^2 = 19.6h\)
u = √(19.6h)
Determine the coefficient of restitution (e):The body's initial velocity (u) and initial relative velocity (u_rel) are the same.
The body's horizontal velocity immediately following the collision, which is zero, is the final relative velocity (v_rel).
\(e = v_{rel }/ u_{rel}\)
e = 0 / u_rel = 0 / u
Now, one can investigate the forces affecting the body: When a body is on an inclined plane.
There are two main forces at work on it: the frictional force that prevents the body from moving and the gravitational force that pulls it downward (mg).
The gravitational force has two components that act perpendicular to and parallel to the inclined plane, respectively: m*g*cos(45°) and m*g*sin(45°).
Determine the conditions for the body to stop:
μ * N = m * g * sin(45°)
μ * (m * g * cos(45°)) = m * g * sin(45°)
μ * cos(45°) = sin(45°)
(1/2) * cos(45°) = sin(45°)
Simplifying further, we have:
√2 / 4 = √2 / 2
Thus, the body will come to rest following the collision if the equation is valid.
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what are the two main types of sound like soundwave
Answers
Answer:
acoustic energy and mechanical energy
Explanation:
each type of sounds has to be tackled in their own way.
a body of mass 2kg, moving with a velocity of 5m/s,collides with a stationary body of mass 0.5kg.If the two body coalesce and move off after impact, calculate their common velocity
Answers
The common velocity of the two bodies after the collision is 4 m/s.
What is the common velocity of the two bodies after the collision?The common velocity of the two bodies after the collision is calculated by applying the following equation.
m₁u₁ + m₂u₂ = v ( m₁ + m₂ )
where;
m₁ is the mass of the first objectm₂ is the mass of the second objectv is their common velocity after the collisionThe common velocity of the two bodies after the collision is calculated as;
( 2 x 5 ) + ( 0.5 x 0 ) = v ( 2 + 0.5 )
10 = 2.5v
v = 10 / 2.5
v = 4 m/s
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1. The kinetic energy of a 4,934 pound pickup truck going 55 mph is:
Provide your answer in kJ
2. A 4,992 lb car has a rolling resistance coefficient of 0.015. How much force, in lb, will it take to push this car at 30 mph?
3.The 2022 Hummer EV comes with a 212 kWh battery. How much will this battery weigh in lbs?
Answers
Answer:
1) 1256.02 kJ
2)76.20 lb
3)2336.30 lb
Explanation:
The kinetic energy of a 4,934 pound pickup truck going 55 mph is:
First, we need to convert the mass of the truck from pounds to kilograms:
4,934 lb = 2,236.17 kg
The kinetic energy is given by the formula: KE = 0.5 * m * v^2
where m is the mass of the object and v is the velocity.
Plugging in the values, we get:
KE = 0.5 * 2,236.17 kg * (55 mph)^2 = 1,256,024.47 J
Converting to kJ, we get:
KE = 1,256,024.47 J / 1000 = 1256.02 kJ
A 4,992 lb car has a rolling resistance coefficient of 0.015. How much force, in lb, will it take to push this car at 30 mph?
The force required to overcome rolling resistance is given by the formula:
F = Crr * W
where Crr is the rolling resistance coefficient and W is the weight of the car.
First, we need to convert the weight of the car from pounds to Newtons:
4,992 lb = 22,612.88 N
Plugging in the values, we get:
F = 0.015 * 22,612.88 N = 339.19 N
Converting to pounds, we get:
F = 339.19 N / 4.45 = 76.20 lb
The 2022 Hummer EV comes with a 212 kWh battery. How much will this battery weigh in lbs?
We cannot directly convert from kilowatt-hours to pounds, as they are two different units. However, we can use the energy density of the battery to estimate its weight.
Assuming an energy density of 200 Wh/kg for the battery, we can calculate the mass of the battery as:
212 kWh * 1000 Wh/kWh / 200 Wh/kg = 1060 kg
Converting to pounds, we get:
1060 kg * 2.205 lb/kg = 2336.30 lb
Imagine that you are observing the region of space where a cloud of gas and dust is beginning to collapse inward to form a star (the object that initially forms in this process is called a protostar). Will the atoms in the collapsing cloud move away from one another, move closer to one another, or stay at the same locations? 2) What physical interaction, or force, causes the atoms to behave as you described they would in Question 1?
Answers
Answer:
1. The atoms in the collapsing cloud would move closer to one another.
2. Gravity
Explanation:
1. This is because there is a force of attraction between the atoms of the collapsing cloud. Thus, the atoms in the collapsing cloud would move closer to one another.
2. This is because gravity is the force of attraction between masses. Now, the collapsing cloud of dust contains mass of atoms, and as the atoms come together due to gravity, they form a larger mass which develops into a star.
(a) The atoms in the collapsing cloud would move closer to one another.
(b) Due to the force of interaction between masses that is gravity
What is force of attraction?
(a) The atoms will come closer
This is because there is a force of attraction between the atoms of the collapsing cloud. Thus, the atoms in the collapsing cloud would move closer to one another.
(b) Due to the gravitational attraction
This is because gravity is the force of attraction between masses. Now, the collapsing cloud of dust contains mass of atoms, and as the atoms come together due to gravity, they form a larger mass which develops into a star.
Hence
(a) The atoms in the collapsing cloud would move closer to one another.
(b) Due to the force of interaction between masses that is gravity
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To demonstrate the ideas of electric current and resistivity the following experiment was conducted using a 10.0 m long 1.00 m diameter pipe. The pipe is connected to an air pump which produces high air pressure at one end. The other end of the pipe is open to the surrounding air, and the pump maintains a constant difference in air pressure between the two ends. Six hundred electrically charged ping pong balls are injected into the pipe with velocities that have random magnitudes and directions. Due to the difference in air pressure, the balls drift from the high pressure end of the pipe to the low pressure end at a speed of 2.00 cm/s. What quantity in this demonstration is analogous to electric potential in a wire connected to a battery
Answers
The air pressure is analogous to electric potential in a wire connected to a battery.
This is because an electric potential difference causes charges to move from a point of higher electric potential to point of lower electric potential.
Similarly, since the six hundred electrically charged ping pong balls move from a point in which the air pressure is higher to a point in which the air pressure is lower, this is due to the difference in pressure between the two points.
So, the air pressure is analogous to the electric potential in a wire connected to a battery.
Learn more about electric potential here:
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Which products are formed when ethane (C2H6) undergoes combustion?
A. H20 and C
B. H2 and CO2
C. H2O and CO2
D. H20, CO2, and O2
Answers
Answer:
C.
Explanation:
It is C.
\(\rm CO_2\) and \(\rm H_2O\) ,are the products are formed when ethane undergoes combustion. Option C is correct.
What is combustion?Combustion is an exothermic chemical process that creates oxidized, frequently gaseous compounds in a mixture known as smoke.
Ethane combustion is simply a combustion process in which ethane burns in the presence of oxygen. Both carbon dioxide and water vapor are produced in this process.
The chemical reaction for the ethane combustion is;
\(\rm 2C_2H_6 (g) + 7O_2 (g) ---- > 4CO_2 (g) + 6H_2O (g)\)
Hence, option C is correct.
To learn more about the combustion, refer to the link;
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