Kim's window store made a mosaic for the community center. The mosaic had an 8 x 8 array of different color square tiles. If each tile is 2 2/3 ft long, what is the area of the whole mosaic?
The area of the whole mosaic is 455.11 square feet
Calculating the area of the whole mosaic? From the question, we have the following parameters that can be used in our computation:
Mosaic had an 8 x 8 array of different color square tiles. Each tile is 2 2/3 ft longThe area of the whole mosaic is calculated as
Area = Area of the array * the square of each length
using the above as a guide, we have the following:
Area = 8 * 8 * (2 2/3)²
Evaluate
Area = 455.11
Hence, the area of the whole mosaic is 455.11 square feet
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for a chi square goodness of fit test, we can use which of the following variable types? select all that apply. for a chi square goodness of fit test, we can use which of the following variable types? select all that apply. nominal level ordinal interval level ratio level
For a chi-square goodness-of-fit test, we can use variables of nominal level and ordinal level.
For a chi-square decency of-fit test, we can utilize the accompanying variable sorts:
Niveau nominal: a variable that has no inherent order or numerical value and is made up of categories or labels. Models incorporate orientation (male/female) or eye tone (blue/brown/green).
Standard level: a category of a natural order or ranking for a variable. Even though the categories are in a relative order, their differences might not be the same. Models incorporate rating scales (e.g., Likert scale: firmly deviate/dissent/impartial/concur/emphatically concur) or instructive accomplishment levels (e.g., secondary school recognition/four year certification/graduate degree).
In this manner, for a chi-square decency of-fit test, we can utilize factors of ostensible level and ordinal level.
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in a correlational study on the relationship between caffeine consumption and heart disease in police officers, the fact that the officers could not be randomly assigned to high and low caffeine groups suggests the results may be due to:
Confounding variables can affect the relationship between caffeine consumption and heart disease in a correlational study of police officers. Controlling for these variables is necessary to accurately assess the relationship.
The fact that the officers in the study could not be randomly assigned to high and low caffeine groups suggests that the results of the study may be due to confounding variables. A confounding variable is a third variable that is correlated with both the independent variable (in this case, caffeine consumption) and the dependent variable (in this case, heart disease). If a confounding variable is present, it can make it difficult to determine the true relationship between the independent and dependent variables.
For example, if the officers who consume more caffeine also have other unhealthy habits (such as smoking or eating unhealthy diets) that increase their risk of heart disease, it may be difficult to determine the true effect of caffeine on heart disease. In this case, the unhealthy habits would be the confounding variable, and controlling for these variables would be necessary to accurately assess the relationship between caffeine consumption and heart disease.
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Determine+the+percentile+indicating+the+bottom+ranking+20%.+in+other+words,+what+is+the+dollar+number+that+defines+where+the+lowest+values+fall.
The dollar number that defines where the lowest values falls is
20% percentile value =$20
This is further explained below.
What is the dollar number that defines where the lowest value falls?Generally, Now we need to determine the 20th percentile ($20). It indicates that we need to locate a dollar amount that marks the point at which the 20 % data has a value lower than that number.
i=(p/100)*n
Where i is the position of p^th
percentile when the data is presented in ascending order.
i=20/100*50
i=1000/100
i=10
Therefore
n=50
p=20
In conclusion, the 10th position for given data is 20,
Therefore, 20% percentile value =$20
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A student takes a 15-question, multiple-choice exam with two choices for each question and guesses on each question. Assume the variable is binomial. Round the intermediate and final answers to three decimal places. Find the probability of guessing at least 11 out of 15 correctly.P(guessing at least 11 out of 15 correctly) =
The probability of guessing at least 11 out of 15 questions correctly is 0.059.
How to find the probability of guessing at least 11 out of 15 correctly?The probability of guessing any one question correctly is 1/2, and the probability of guessing any one question incorrectly is also 1/2.
Since each question is an independent trial with only two possible outcomes, this situation can be modeled using a binomial distribution with n = 15 (the number of trials) and p = 1/2 (the probability of success on each trial).
To find the probability of guessing at least 11 out of 15 correctly, we need to calculate the probability of guessing 11, 12, 13, 14, or 15 questions correctly, and then add these probabilities together.
Using the binomial probability formula, we can calculate the probability of guessing exactly k questions correctly as:
P(X = k) = (nCk) * p^k * (1-p)^(n-k)
where nCk is the binomial coefficient, which represents the number of ways to choose k items from a set of n items.
For k = 11, we get:
P(X = 11) = (15C 11) * (1/2)¹¹ * (1/2)¹⁵⁻¹¹ = 0.042
For k = 12, we get:
P(X = 12) = (15 C 12) * (1/2)¹² * (1/2)¹⁵⁻¹²= 0.014
For k = 13, we get:
P(X = 13) = (15 C 13) * (1/2)¹³ * (1/2)¹⁵⁻¹³ = 0.003
For k = 14, we get:
P(X = 14) = (15C14) * (1/2)¹⁴ * (1/2)¹⁵⁻¹⁴ = 0.000
For k = 15, we get:
P(X = 15) = (15C15) * (1/2)¹⁵ * (1/2)¹⁵⁻¹⁵= 0.000
To find the probability of guessing at least 11 out of 15 correctly, we add these probabilities together:
P(guessing at least 11 out of 15 correctly) = P(X >= 11) = P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) + P(X = 15) = 0.059
Therefore, the probability of guessing at least 11 out of 15 questions correctly is 0.059.
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What set does this belong to
Choice A) Real Numbers
Choice F) Rational Numbers
===============================================
Explanation:
Any number you encounter so far in your math class is a real number, assuming your teacher hasn't covered complex numbers yet. So -7/16 is a real number.
It is also a rational number. Rational numbers are of the form p/q where p and q are integers. The value of q cannot be zero. Since it is rational, that means it's not irrational.
Since -7/16 = -0.4375 has a fractional or decimal part, it is not a whole number, integer, or natural number. Those numbers only deal with values that don't have any fractional parts.
if PAID 24 DOLLARS FOR 4 MOVIE TICKETS HOW MUCH WOULD IT BE FOR 12?
Answer:
36 dollars!
Step-by-step explanation:
24 divided by 4 is 6
4 times 3=12
3 times 12 = 36
hopes this helps! :)
Given point M and plane α such that M ∉ α. MO is perpendicular to plane α. MP and MQ are inclined to α which make 30° and 60° with plane α, respectively. Find the length of PQ in terms of
MO if ∠POQ = 120°
The length of PQ in terms of MO if ∠POQ = 120° is PQ = -x * √3/3.
Let MO = x.
Since MO is perpendicular to plane α, MP and MQ form right angles with MO.
Using the Pythagorean Theorem, we have:
MP = x * tan(30°) = x * √3/3
MQ = x * tan(60°) = x * √3
Since ∠POQ = 120°, we have:
PQ = MP * 2 * cos(120°)
= 2 * x * √3/3 * -1/2
= -x * √3/3
Therefore, the length of PQ in terms of MO is PQ = -x * √3/3.
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5(2 + 3) = ? for easy points
Answer:25
Step-by-step explanation:
Answer:
25
Step-by-step explanation:
because you have to multiply to get the parentheses off.
What is the value of the expression 12 x (-1.6)
Answer: -19.2
Step-by-step explanation:
a coach is measuring the times of her runners. the runners complete their runs in 31.3 sec, 41.05 sec, and 42.015 sec. are these numbers discrete or continuous?
The numbers 31.3 sec, 41.05 sec, and 42.015 sec represent continuous data since time measurements can take on any value within a given range. Therefore, these numbers are not discrete but continuous.
The numbers, 31.3 sec, 41.05 sec, and 42.015 sec, represent the times taken by the runners to complete their runs. In this case, the numbers are continuous.
Continuous data refers to measurements that can take any value within a certain range or interval. In the context of measuring time, it is possible to have infinitely many possible values between any two given points. For example, between 31.3 sec and 31.31 sec, there can be an infinite number of additional decimal places.
Discrete data, on the other hand, consists of values that are separate and distinct with no intermediate values possible. Discrete data is typically based on counting or whole numbers, such as the number of runners or the number of wins in a competition.
In this scenario, the times of the runners are measured using a continuous scale, where the smallest unit of time can be divided further into smaller increments. Therefore, the times of the runners, 31.3 sec, 41.05 sec, and 42.015 sec, are considered continuous data.
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Please help with number 2!
Answers:
D'' = (1, -3)
E'' = (1, -1)
F'' = (3, -1)
G'' = (3, -4)
A diagram is shown below.
========================================================
Explanation:
The center of dilation is point E, which means this point does not move when the dilation is applied. Every other point will move.
As your diagram indicates, segment DE is 4 units long. If we apply the scale factor 1/2, then D'E' will be half as long meaning D'E' = 2. So point D' is 2 units above point E at (1,3)
Point F is 4 units away from point E. The scale factor 1/2 will bring F closer to E leading to segment F'E' = 2. So we'll start at E and move 2 units to the right to land on F ' (3, 1)
From F to G is 6 units, which cuts in half to 3. So from F' to G' is 3 units telling us we start at F ' (3, 1) and go up three units to get go G ' (3, 4)
So far we have
D ' = (1, 3)
E ' = (1, 1) ... fixed point doesn't move
F ' = (3, 1)
G ' = (3, 4)
-------------
From here we'll apply the reflection over the x axis rule which says
\((x,y) \to (x, -y)\)
the x coordinate stays the same, and the y coordinate flips from positive to negative (or vice versa).
Based on what was mentioned for D', E', F' and G', we get the following
D'' = (1, -3)
E'' = (1, -1) .... this point does move now
F'' = (3, -1)
G'' = (3, -4)
Points E' and E'' are in different locations because all fixed points in this reflection are along the mirror line y = 0 (aka the x axis). In other words, if E was on the x axis, then it would not move if we applied this reflection.
Check out the diagram below see a visual summary of what happened. Note how the red points moved in closer to point E (since the distances from the center E have been cut in half) compared to the blue counterparts.
Determine the nature of the roots: 2x^(2) +8x +3=0 a. two distinct real solutions c. cannot be determined b. no real solutions d. a unique real solution
Answer:
a
Step-by-step explanation:
Given a quadratic equation in standard form ax² + bx + c = 0 (a ≠ 0 )
Then the discriminant b² - 4ac determines the nature of the roots.
• If b² - 4ac > 0 then 2 real and distinct roots
• If b² - 4ac = 0 then 2 real and equal roots
• If b² - 4ac < 0 then no real roots
Given
2x² + 8x + 3 = 0 ← in standard form
with a = 2, b = 8, c = 3 , then
b² - 4ac = 8² - (4 × 2 × 3) = 64 - 24 = 40
Since b² - 4ac > 0 then 2 real and distinct roots → a
Answer:
a
Step-by-step explanation:
What is the radius of the circle with equation x² y² 1?
The radius of the circle with equation x² +y² =1 is 1.
The radius of a circle is the separation between any two points on its circumference. R or r is typically used to indicate it. This amount is significant in practically all formulas involving circles. A circle's radius can also be used to calculate its surface area and circumference.
To see this, we can rewrite the equation in the standard form for the equation of a circle: (x-h)² + (y-k)² = r², where (h,k) is the center of the circle and r is the radius.
In this case, we have:
x² + y² = 1
This can be rewritten as:
(x-0)² + (y-0)² = 1
Thus, the radius of the circle is 1.
The complete question is;-
What is the radius of the circle with the equation x² +y²= 1?
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Help fast!! What is the exact volume of the cylinder?
36
324
54
18 in
Answer:
V = 54 pi in ^3
Step-by-step explanation:
The volume of a cylinder is given by
V = pi r^2 h where r is the radius and h is the height
V = pi (3)^2 * 6
V = pi (9) *6
V = 54 pi in ^3
Let T = {0, 1, 2}. A string x ∈ Tn is said to be balanced if the sum of the digits is an integer multiple of 3.
(a) Show a bijection between the set of strings in T6 that are balanced and T5. Explain why your function is a bijection.
(b) How many strings in T6 are balanced?
a) f is a bijection between the set of balanced strings in \(T^6\) and the set of strings in\(T^5.\) b) the total number of balanced strings in T6 is 727 + 192 + 192 = 1111.
Let x ∈ T6 be a balanced string. We define the function f : T6 → T5 by removing the last digit of x. That is, f(x) is the string obtained from x by deleting the sixth digit. It is clear that f(x) is a string in T5.
To show that f is a bijection, we need to show that it is both injective and surjective.
Injective: Suppose f(x) = f(y) for some x, y ∈ T6. Then x and y differ only in their last digit. Since the sum of the digits of x and y are both multiples of 3, their last digits must be congruent modulo 3. But the only way for two digits in T to be congruent modulo 3 is if they are the same. Therefore, x and y are identical except for their last digit, so x = y, and f is injective.
Surjective: Let y ∈ T5 be an arbitrary string. We define x ∈ T6 by adding a digit to the end of y such that the sum of the digits of x is a multiple of 3. We can always find such a digit, since adding any digit from T will either leave the sum unchanged or change it by 1 modulo 3. Therefore, f(x) = y, and f is surjective.
Since f is both injective and surjective, it is a bijection.
b) To count the number of balanced strings in T6, we note that there are three cases to consider: the sum of the digits is 0 mod 3, 1 mod 3, or 2 mod 3.
Case 1: The sum is 0 mod 3. In this case, we must choose six digits from {0, 1, 2} such that their sum is a multiple of 3. We can choose any combination of digits from {0, 1, 2} except for all 0's or all 2's. There are 3^6 - 2 = 727 cases in this case.
Case 2: The sum is 1 mod 3. In this case, we must choose five digits from {0, 1, 2} such that their sum is 2 mod 3, and then add a sixth digit that is 2 mod 3. There are (3 choose 2) * 2^5 = 192 cases in this case.
Case 3: The sum is 2 mod 3. In this case, we must choose five digits from {0, 1, 2} such that their sum is 1 mod 3, and then add a sixth digit that is 1 mod 3. There are (3 choose 2) * 2^5 = 192 cases in this case.
Therefore, the total number of balanced strings in T6 is 727 + 192 + 192 = 1111.
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Meghan made $458 in her last paycheck if she would like to save at least $175 of it, how much can she spend
Answer:
283
Step-by-step explanation:
458-175=283
and you have your answer.
Which equation is correct?
which equation is correct? a. tanx=1/secx b.sinx=1/cosx c.cscx=1/sinx d.cosx=1/cotx
Answer:
Step-by-step explanation:
csc and sin are inverses of one another, therefore, c is the correct statement.
the number of cars one sees passing by the local playground in an afternoon is modeled using a poisson distribution with mean 25. the proportion of black cars in the stream is 1/5. the color of the cars is independent of the number of cars that drive by. what is the probability that exactly 5 black cars and exactly 10 non-black cars drive by in a particular afternoon?
The probability that exactly 5 black cars and exactly 10 non-black cars drive by in a particular afternoon is approximately 0.00167.
The probability that exactly 5 black cars and exactly 10 non-black cars drive by on a particular afternoon is
\($$P(X_b=5,X_{nb}=10)=\frac{e^{-\lambda}\lambda^{5}}{5!}\cdot\frac{e^{-\lambda}\lambda^{10}}{10!}\cdot\frac{1}{5^{5}}\cdot\frac{4}{5}^{10}$$\), where \($X_b$\) are the number of black cars and \($X_{nb}$\) the number of non-black cars passing by the playground in the afternoon. Since the color of the cars is independent of the number of cars that drive by, we can model the number of black and non-black cars using two separate Poisson distributions with means
\($\lambda_b = \frac{1}{5}\cdot25=5$ and $\lambda_{nb}=25-5=20$\), respectively.
Plugging in the values and simplifying, we get:
\($$P(X_b=5,X_{nb}=10)=\frac{e^{-5}5^{5}}{5!}\cdot\frac{e^{-20}20^{10}}{10!}\cdot\frac{1}{5^{5}}\cdot\frac{4^{10}}{5^{10}}\approx 0.00167$$\)
Therefore, the probability that exactly 5 black cars and exactly 10 non-black cars drive by in a particular afternoon is approximately 0.00167.
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Brigid is picking strawberries at the Pick-Your-Own Farm. Her goal is to pick 5 bushels of strawberries. She has already picked 1
1
2
bushels, and she picks at a rate of
5
8
bushel per hour. The scenario is represented as
5
8
h + 1
1
2
= 5, where h is the number of hours she picks. How many more hours will it take Brigid to fill 5 bushels of strawberries?
2 and StartFraction 3 Over 16 EndFraction hours
2 and StartFraction 3 Over 16 EndFraction hours
5 and three-fifths hours
10 and two-fifths hours
Answer:
We can start by isolating the variable "h".
5 8 h + 1 1 2 = 5
Subtracting 11/2 from both sides:
5 8 h = 5 - 1 1 2
Simplifying:
5 8 h = 8 1 2
Dividing both sides by 5/8:
h = 8 1 2 ÷ 5 8
Converting the mixed number to an improper fraction:
h = (8 x 8 + 1) ÷ 5 8
h = 65/8
Now, we can convert this fraction to a mixed number:
h = 8 1/8
Brigid has already picked for 8 1/8 hours, so the amount of time needed to pick the remaining strawberries is:
5 - (1 1/2 + 5/8 x 8) = 5 - (3 5/8) = 1 3/8
Therefore, Brigid still needs to pick for 1 3/8 hours to fill 5 bushels of strawberries. The answer is 1 and 3/8 hours or 2 and 3/16 hours (if simplified).
Step-by-step explanation:
7 a 96 cm long line segment is divided into 3 parts in the ratio 2:9:5 . what is the length of the smallest part?
The length of the smallest part of the line segment is 12 cm.
The line segment of length 96 cm is divided into 3 parts with the ratio of 2:9:5. The given ratio is a part-to-whole ratio. We can find the lengths of the parts by applying the formula:
Part = Whole × Ratio
Part 1 = 96 cm × (2/16)
= 12 cm
Part 2 = 96 cm × (9/16)
= 54 cm
Part 3 = 96 cm × (5/16)
= 30 cm
Therefore, the length of the smallest part of the line segment is 12 cm.
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(a) Cells were transferred to microcarriers (250 μm in diameter, 1.02 g/cm3 in density). ) and cultured in a stirred tank Incubate 50 liters (height = 1 m) in the machine, and after the culture is complete, it is to be separated by sedimentation. The density of the culture medium without microcarriers is 1.00 g/cm3 , the viscosity is 1.1 cP. cells completely Find the time required for settling.
(b) G force (relative centrifugal force) for particles rotating at 2,000 rpm save it The distance from the axis of rotation to the particle is 0.1 m.
The the time required for settling is 4 seconds and G force for particles rotating at 2000 rpm is 833 G.
The time required for settling can be found by applying Stokes' Law, which relates the settling velocity of a particle to the particle size, density difference between the particle and the medium, and viscosity of the medium.
The equation for settling velocity is:
v = (2gr²(ρp - ρm))/9η where:
v is the settling velocity
g is the acceleration due to gravity
r is the radius of the particleρ
p is the density of the particle
ρm is the density of the medium
η is the viscosity of the medium
The density of the microcarrier is given as 1.02 g/cm³.
The density of the medium without microcarriers is 1.00 g/cm³.
The difference in densities between the microcarriers and the medium is therefore:
(1.02 - 1.00) g/cm³ = 0.02 g/cm³
The radius of the microcarrier is given as 125 μm, or 0.125 mm.
Converting to cm:
r = 0.125/10 = 0.0125 cm
The viscosity of the medium is given as 1.1 cP.
Converting to g/cm-s:
η = 1.1 x 10^-2 g/cm-s
Substituting these values into the equation for settling velocity and simplifying:
v = (2 x 9.81 x (0.0125)^2 x 0.02)/(9 x 1.1 x 10^-2) ≈ 0.25 cm/s
The settling velocity is the rate at which the microcarrier will fall through the medium. The height of the tank is given as 1 m.
To find the time required for settling, we divide the height of the tank by the settling velocity:
t = 1/0.25 ≈ 4 seconds
Therefore, it will take approximately 4 seconds for the microcarriers to settle to the bottom of the tank.
The G force for particles rotating at 2000 rpm can be found using the following formula:
G force = (1.118 x 10^-5) x r x N² where:
r is the distance from the axis of rotation to the particle in meters
N is the rotational speed in revolutions per minute (RPM)
Substituting r = 0.1 m and N = 2000 RPM into the formula:
G force = (1.118 x 10^-5) x 0.1 x (2000/60)² ≈ 833 G
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rewrite 1/4 books over 1/3 hour as a unit rate. A. 1 1/3 bookss/hour B. 1/12 books/hour C. 3/4 books/hour D. 12 books/hour
Answer:
The Answer would be option C. 3/4 books per hour
Step-by-step explanation:
You would flip 1/3 to 3/1 which makes it a whole number. then multiply
1/4 and 3.
Therefore your answer is 3/4
I hope this helped you,
NEED HELP!!! ill give brain points. Explain or show why Priya's conclusion is incorrect.
pls answer the following question circled in red
this question is asking how to compare linear functions (algebra 1)
Answer:
yes Priya's conclusion is incorrect
Step-by-step explanation:
x square will always be greater than the actual value of x
but in this expression
f (x ) = 10 * x²
g (x) = 3 * 2raise to the power x
priya's conclusion is incorrect because in the other expression the power of x is increasing exponentially so eventually g(x) will be greater than f(x)
as for x = 10
f(x) = 10 * 10² = 1000
g(x) = 3 * 2raise to power 10 = 3 * 1024 = 3072
Find the sum of the first 20 terms of the arithmetic series 53,46,39,32...
The answer can be found by assuming that we have an arithmetic progression that stars in 53 with a common difference of 7. The equation for the sum of an arithmetic progression up to n terms is given by:
\(s_n=\frac{n}{2}(2a+(n-1)d)\)Where, for this case
\(a=53\text{ , }n=20\text{ and }d=7\)So, applying the equation with these data, we obtain:
\(\begin{gathered} s_{20}=\frac{20}{2}(2(53)+(20-1)7) \\ s_{20}=10(106+19(7)) \\ s_{20}=10(106+19(7))=10(239)=2390 \end{gathered}\)Thus, the sum up to 20 terms of the given series is 2390.
HELP!Find each percent change. Use a calculator and round answer to the nearest tenth as needed. State if it is an increase or decrease. 88 to 20
A.22.7% decrease
B.14.2% decrease
C.77.3% decrease
D.340% decrease
Answer:
C. 77.3% decrease
Step-by-step explanation:
To calculate the percent change, we can use the formula:
percent change = (new value - old value) / old value * 100
Plugging in the values, we get:
percent change = (20 - 88) / 88 * 100 = -68 / 88 * 100 = -0.772727 * 100 = -77.3
Since the new value is lower than the old value, this is a decrease, and the answer is -77.3, or 77.3% decrease.
YALL REMEMBER PRODIGY AND ROOTBEER FLOATS OMGGGGG
Answer:
omg the last time i played that was in 3rd grade!!!!
Step-by-step explanation:
The student council at Summerfield High School is making T-shirts to sell for a fundraiser, at a price of $11 apiece. The costs, meanwhile, are $10 per shirt, plus a setup fee of $141. Selling a certain number of shirts will allow the student council to cover their costs. What will the costs be? How many shirts must be sold?
Answer:
$1551 needed to cover the costs and 141 shirts will be sold.
Step-by-step explanation:
If a shirt costs $10 and the council is selling the shirt for $1 more ($11), after selling 141 shirts, they would have made a profit of $1*141=$141. Since there is also a setup fee of $141, the profit would actually be $0. This is when the costs are covered.
C = 10s + 141 (C is cost and s in no. of shirts sold)
s = 141
C = 141*10 + 141 = 1551
Hope this helps!
Answer the questions below. Be sure to mark all answers that apply.
Answer:
Part A: Only 460 is divisible by 2
Part B: 385, and 460 are divisible by 5
Part C: Only 460 works for this one
52 students are going on a skiing trip. 28 have skied before, 30 have snowboarded before while 12 have done neither. How many have done both sports before?use a Venn diagram.
Answer:
18
Step-by-step explanation:
see attached