HELPPpPpPpPpPp!!!! ASAP !!!

Using Coulomb's law:

Where:

Therefore:

Solve for q1:

The way in which one atom interacts with another atom is mostly influenced by the configuration of the electrons farthest from the nucleus.

Option A.

An atom can be defined as the smallest part of a substance that cannot be broken down chemically. Each atom has a nucleus (center) made up of protons (positive particles) and neutrons (particles with no charge).

The arrangement of electrons in orbitals and shells around the nucleus is referred to as the electronic configuration of the atom.

Thus, we can conclude that the way in which one atom interacts with another atom is mostly influenced by the configuration of the electrons farthest from the nucleus.

The remaining options do not fit the empty space properly, and they include;

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Answer:

Explanation:

Kinetic energy of the mass of 10 kg

= 1/2 m v² , m is mass and v is velocity .

= .5 x 10 x 20²

= 2000 J

The opposing force stops it . so work done by opposing force will be equal to this energy and it will be negative .

So energy transfer will be  - 2000 J .

= 2 kJ .

If distance travelled by mass is d , force 25 N will have a displacement of d . so work done by force of 25 N

= 25 x d

25 d = 2000

d = 80 m .

Hence system travels a distance of 80 m .

Answer:

λ = 1.86 x 10⁻⁴ m = 186 μm

Explanation:

The relationship between the wavelength and the frequency of a wave is given by the following equation:

\(c = f\lambda\\\\\lambda = \frac{c}{f}\)

where,

λ = wavelength of infrared radiation = ?

c = speed of infrared radiation = speed of light = 3 x 10⁸ m/s

f = frequency of infrared radiation = 1.61 THz = 1.61 x 10¹² Hz

Therefore,

\(\lambda = \frac{3\ x\ 10^8\ m/s}{1.61\ x\ 10^{12}\ Hz}\)

λ = 1.86 x 10⁻⁴ m = 186 μm

Answer:

Explanation:

the answer is b

Grouping data refers to the process of categorizing or organizing data based on specific criteria or attributes.

It involves grouping similar data points together to gain a better understanding of patterns, relationships, and trends within the dataset. By grouping data, you can simplify complex information and derive meaningful insights from large amounts of data. The purpose of grouping data is to create subsets or clusters that share common characteristics.

This enables easier analysis, summarization, and comparison of data within each group. Grouping can be performed on various types of data, such as numerical, categorical, or time-based data. Grouping data allows for the exploration of data at different levels of granularity.

For example, you can group sales data by region to analyze regional performance, or group customer data by demographics to identify specific customer segments. This process helps in identifying outliers, detecting patterns, and making data-driven decisions.

Common techniques for grouping data include using functions like GROUP BY in SQL or utilizing data visualization tools to create charts or graphs that illustrate the grouped data. Grouping can be applied in various fields, such as marketing, finance, healthcare, and research, to uncover insights and support decision-making processes.

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The stretch of the spring is proportional to the weight of the mass hung from it. Since the spring stretches by 5.9 cm when a 1.6 kg mass is hung from it, we can use this information to find the stretch when a 2.1 kg mass is hung from it.

The stretch of the spring is given by:

stretch = (mass x gravity x length) / (spring constant)

where mass is the mass hung from the spring, gravity is the acceleration due to gravity (9.81 m/s^2), length is the stretch of the spring, and the spring constant is a measure of the stiffness of the spring (measured in N/m).

We can rearrange this equation to solve for the stretch of the spring:

stretch = (mass x gravity x length) / (spring constant)

length = (spring constant x stretch) / (mass x gravity)

Substituting the given values, we get:

length = (spring constant x 0.059 m) / (1.6 kg x 9.81 m/s^2)

Simplifying, we get:

length = 0.236 m

Therefore, the stretch of the spring when a 2.1 kg mass is hung from it is 0.236 m.

The distance between two objects of radius 6 cm and 2 cm is zero

To find the distance between two objects with radii of 6 cm and 2 cm, we need to consider the center-to-center distance between the objects and subtract the sum of their radii.

Let's denote the radii of the objects as r1 = 6 cm and r2 = 2 cm.

The distance between the centers of the objects can be represented as d = r1 + r2. Adding the radii ensures that we account for the space occupied by both objects.

Substituting the values, we have d = 6 cm + 2 cm = 8 cm.

Now, to find the actual distance between the objects, we subtract the sum of their radii from the center-to-center distance:

Distance = d - (r1 + r2) = 8 cm - (6 cm + 2 cm) = 8 cm - 8 cm = 0 cm.

The resulting distance is 0 cm, indicating that the objects are in direct contact with each other. This means that their surfaces are touching. When the distance between two objects is zero, it implies that they are overlapping or in physical contact. In this case, since the distance is equal to 0 cm, the two objects are touching each other, with their surfaces coming into contact.

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Answer:

d. 1-proton 2-nuetron 3-electron 4-nucleus

Organelles are specialized structures within cells that perform specific functions, such as energy production, protein synthesis, and waste removal.

Some examples of organelles include mitochondria, which produce energy for the cell, and ribosomes, which are involved in protein synthesis.

The size of cells can vary widely depending on the organism and the type of cell. For example, human cells can range from 10 to 30 micrometers in diameter, while bacterial cells are typically much smaller, ranging from 1 to 5 micrometers in diameter.

In summary, organelles are specialized structures within cells that perform specific functions, and the size of cells can vary widely depending on the organism and the type of cell.

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The frequency of the wave is 0.625 waves per second, calculated by dividing the number of waves (10) by the time (16.0 seconds).

To determine the frequency of a wave, you need to divide the number of waves (in this case, 10) by the time it takes for those waves to pass a certain point (in this case, a dock) within 16.0 seconds.

Frequency is usually measured in Hertz (Hz), which represents the number of cycles or events per second. So, to find the frequency, we calculate 10 waves / 16.0 seconds = 0.625 waves per second or 0.625 Hz.

This means that every second, 0.625 waves pass by the dock, giving you the frequency of the wave.

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Answer:

12 dozen

Explanation:

Answer:

The table is proportional.

Explanation:

You would do 21/6 to get 3.5. Then 28/8 to get 3.5. After 35/10 to get 3.5. Finally 49/14 to get 3.5. If each answer (3.5) is the same than it is proportional.

hope i helped

This question is incomplete, the complete question is;

Scientists studying an anomalous magnetic field find that it is inducing a circular electric field in a plane perpendicular to the magnetic field. The electric field strength 1.5 m from the center of the circle is 7 mV/m.

At what rate is the magnetic field changing?

Answer:

the magnetic field changing at the rate of 9.33 m T/s

Explanation:

Given the data in the question;

Electric field E = 7 mV/m

radius r = 1.5 m

Now, from Faraday law of induction;

∫E.dl = d∅/dt

E∫dl = A( dB/dt )

E( 2πr ) = πr² ( dB/dt )

( 0.007 ) = (r/2) ( dB/dt )

( 0.007 ) = 0.75 ( dB/dt )

dB/dt = 0.007 / 0.75

dB/dt = 0.00933 T/s

dB/dt = ( 0.00933 × 1000) m T/s

dB/dt = 9.33 m T/s

Therefore, the magnetic field changing at the rate of 9.33 m T/s

The mass spectrometer separates ions of different masses by utilizing the relationship between the strength of the magnetic field, the accelerating voltage, the charge-to-mass ratio of the ions, and the resulting radius of the circular path

From the formula in the question;

B is a symbol for the magnetic field's intensity as it is applied to the mass spectrometer.

The accelerating voltage used to move the ions is called Vaccelm.

The charge of the ion, specifically its charge-to-mass ratio (q/m), is represented by the letter q.

The mass spectrometer may selectively alter the radius of the circular route for various ions by varying the magnetic field's intensity (B). This makes it possible to spatially segregate ions with various masses based on their various radii. The ions' locations and masses can then be measured using detectors placed along the journey.

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Answer:

B

Explanation:

Answer:

protons+neutrons= mass number, so if the mass number is 13 and protons are 6 its 13-6=7 neutrons

Explanation:

mass number: the sum of the number of protons and

neutrons in an atom

this is key as it explains that protons+neutrons= mass number, so if the mass number is 13 and protons are 6 its 13-6=7 neutrons

Answer:

0.0377

Explanation:

Trust brother

Answer:

0.0377

Explanation:

Answer:

Liter

Explanation:

Answer:

Refer to the step-by-step Explanation.

Step-by-step Explanation:

Simplify the equation with given substitutions,

Given Equation:

\(mgh+(1/2)mv^2+(1/2)I \omega^2=(1/2)mv_{_{0}}^2+(1/2)I \omega_{_{0}}^2\)

Given Substitutions:

\(\omega=v/R\\\\ \omega_{_{0}}=v_{_{0}}/R\\\\\ I=(2/5)mR^2\)\(\hrulefill\)

Start by substituting in the appropriate values: \(mgh+(1/2)mv^2+(1/2)I \omega^2=(1/2)mv_{_{0}}^2+(1/2)I \omega_{_{0}}^2 \\\\\\\\\Longrightarrow mgh+(1/2)mv^2+(1/2)\bold{[(2/5)mR^2]} \bold{[v/R]}^2=(1/2)mv_{_{0}}^2+(1/2)\bold{[(2/5)mR^2]}\bold{[v_{_{0}}/R]}^2\)

Adjusting the equation so it easier to work with.\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2=\dfrac12mv_{_{0}}^2+\dfrac12\Big[\dfrac25mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\)

\(\hrulefill\)

Simplifying the left-hand side of the equation:

\(mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\)

Simplifying the third term.

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2}\cdot \dfrac{2}{5} \Big[mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\)

\(\\ \boxed{\left\begin{array}{ccc}\text{\Underline{Power of a Fraction Rule:}}\\\\\Big(\dfrac{a}{b}\Big)^2=\dfrac{a^2}{b^2} \end{array}\right }\)

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2 \cdot\dfrac{v^2}{R^2} \Big]\)

"R²'s" cancel, we are left with:

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5}mv^2\)

We have like terms, combine them.

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{7}{10} mv^2\)

Each term has an "m" in common, factor it out.

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)\)

Now we have the following equation:

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)=\dfrac12mv_{_{0}}^2+\dfrac12\Big[\dfrac25mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\)

\(\hrulefill\)

Simplifying the right-hand side of the equation:

\(\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac12\cdot\dfrac25\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}^2}{R^2}\Big]\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\cdot\dfrac{v_{_{0}}^2}{R^2}\Big]\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15mv_{_{0}}^2\Big\\\\\\\\\)

\(\Longrightarrow \dfrac{7}{10}mv_{_{0}}^2\)

Now we have the equation:

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)=\dfrac{7}{10}mv_{_{0}}^2\)

\(\hrulefill\)

Now solving the equation for the variable "v":

\(m(gh+\dfrac{7}{10}v^2)=\dfrac{7}{10}mv_{_{0}}^2\)

Dividing each side by "m," this will cancel the "m" variable on each side.

\(\Longrightarrow gh+\dfrac{7}{10}v^2=\dfrac{7}{10}v_{_{0}}^2\)

Subtract the term "gh" from either side of the equation.

\(\Longrightarrow \dfrac{7}{10}v^2=\dfrac{7}{10}v_{_{0}}^2-gh\)

Multiply each side of the equation by "10/7."

\(\Longrightarrow v^2=\dfrac{10}{7}\cdot\dfrac{7}{10}v_{_{0}}^2-\dfrac{10}{7}gh\\\\\\\\\Longrightarrow v^2=v_{_{0}}^2-\dfrac{10}{7}gh\)

Now squaring both sides.

\(\Longrightarrow \boxed{\boxed{v=\sqrt{v_{_{0}}^2-\dfrac{10}{7}gh}}}\)

Thus, the simplified equation above matches the simplified equation that was given.  

Given data:

* The mass of the Moon is,

* The radius of the Moon is,

* The height of the Apollo 11 is,

Solution:

The period of revolution of the Apollo 11 around the Moon is,

where G is the gravitational constant,

Substituting the known values,

Thus, the value of time period is,

Thus, Apollo 11 takes 2.17 hours to complete orbit once around the Moon.

Complete question:

A person holds a 0.300 kg pomegranate at the top of a tower that is 96m high. Another person holds a 0.800 kg melon next to an open window 32m up the tower.

Calculate the gravitational potential energy of the pomegranate and melon.

Answer:

The gravitational potential energy of  pomegranate is 282.24 J

The gravitational potential energy of  melon is 250.88 J

Explanation:

Given;

mass of the  pomegranate, m₁ = 0.3 kg

height of the  pomegranate, h₁ = 96 m

mass of the melon, m₂ = 0.8 kg

height of the melon, h₂ = 32 m

The gravitational potential energy of  pomegranate is calculated as;

P.E₁ = m₁gh₁

P.E₁ = 0.3 x 9.8 x 96

P.E₁ = 282.24 J

The gravitational potential energy of  melon is calculated as;

P.E₂ = m₂gh₂

P.E₂ = 0.8 x 9.8 x 32

P.E₂ = 250.88 J

the one that answered this is correct so give him credit not me

Answer:

Complete question:

A person holds a 0.300 kg pomegranate at the top of a tower that is 96m high. Another person holds a 0.800 kg melon next to an open window 32m up the tower.

Calculate the gravitational potential energy of the pomegranate and melon.

The gravitational potential energy of  pomegranate is 282.24 J

The gravitational potential energy of  melon is 250.88 J

Given;

mass of the  pomegranate, m₁ = 0.3 kg

height of the  pomegranate, h₁ = 96 m

mass of the melon, m₂ = 0.8 kg

height of the melon, h₂ = 32 m

The gravitational potential energy of  pomegranate is calculated as;

P.E₁ = m₁gh₁

P.E₁ = 0.3 x 9.8 x 96

P.E₁ = 282.24 J

The gravitational potential energy of  melon is calculated as;

P.E₂ = m₂gh₂

P.E₂ = 0.8 x 9.8 x 32

P.E₂ = 250.88 J

the one that answered this is correct so give him credit not me

Answer:

B. Atomic number minus mass number

Explanation:

Answer:

b is correct answer

Explanation:

Answer:

D - Water

Explanation:

The tax rate you will pay is displayed in tax brackets for each category of taxable income.

Thus, For instance, in 2022, the first $10,275 of your taxable income is subject to the lowest tax rate of 10% if you are single.

Up until the maximum amount of your taxable income, the following portion of your income is taxed at a rate of 12%.

As taxable income rises, the tax rate rises under the progressive tax system. Overall, this has the result that taxpayers with higher incomes often pay a greater rate of income tax than taxpayers with lower incomes.

Thus, The tax rate you will pay is displayed in tax brackets for each category of taxable income.

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Answer:

In this case, a body of mass 5 kg kept at a height of 10 m. So the potential energy is given as 5 * 10 *10 = 500 J.

Answer:

0.667 cm

Explanation:

|F_1on3| = |F_2on3|

k×q1×q3/x^2 = k×q2×q3/(d-x)^2

q1/x^2 = q2/(d-x)^2

(d-x)^2/x^2 = q2/q1

(d-x)/x = sqrt(q2/q1)

(2 - x)/x = sqrt(4×q/q)

(2 - x)/x = 2

2 - x = 2x

2 = 3x

x = 2/3

x= 0.667 cm

Answer:

Explanation: work equals force times distance so 400x4=1600 joules

so hi the answert is probably 4 or e

Answer:

5.51 m/s2

Explanation:

HOPE THIS HELPS!!!!