Horsepower is defined as ______.
A. power applied over the distance of an English horserace track
B. the mechanical advantage gained by using a typical horse
C. the mass of a horse divided by the time it takes the horse to run 100 meters
D. a specific amount of power (550 ft-lb/s)

Answer: KE=.5mv^2

KE=.5(7.62)(7.5)^2

KE=.5(7.62)(56.25)

KE=.5(428.625)

KE=214.3125 J of KE

Explanation:

Given:

As we know,

→ \(K.E = \frac{1}{2} mv^2\)

By substituting the values, we get

          \(= \frac{1}{2}\times 762\times (7.5)^2\)

          \(= \frac{1}{2}\times 7.62\times 56.25\)

          \(= \frac{1}{2}\times 428.625\)

          \(= 214.32 \ J\)

Thus the response above is appropriate.

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Answer:

372.94 km

d= st

= (64.3 km/h)(5.8h)

=372.94 km

Answer:

The electrical field in the region between the plates is 10,000 V/m.

Explanation:

Given;

potential difference between the two parallel plates, V = 100 V

distance between the two parallel plates, d = 1 cm = 0.01 m

The electrical field in the region between the plates is given as;

E = V / d

where;

E is the electrical field in the region between the plates

E = (100) / (0.01)

E = 10,000 V/m

Therefore, the electrical field in the region between the plates is 10,000 V/m.

Answer:

1) If a cell or battery is used, the key in the circuit should be left open so as not to drain the battery or cell.

2) Also, leaving the key closed causes current to flow through the circuit, which also causes the temperature of the circuit to increase. Since the resistance of most metals increases with an increase in temperature, the resistance of the circuit will increase, which will then affect the integrity of the whole experiment.

(a) For a machine with 100% efficiency, the output work is equal to input work.

(b) For a machine with less than 100% efficiency, the output work is less than the input work.

The efficiency of a machine indicates how well its input work is converted to useful output work.

It is a major factor determines the usefulness of a machine and is the fraction or percentage of the output energy divided by the input energy.

Mathematically, the formula for efficiency of a machine is given as;

E = output work / input work  x 100%

For an ideal machine, the output energy (work) is equal to the input energy (work), and the efficiency of this ideal machine will be 100%.

Thus, a machine with 100% efficiency has not friction in the moving parts and the output work is equal to input work

In a real situation, friction always exists and the efficiency of a machine cannot be 100%.

A machine with less than 100% efficiency, some input work or energy in the machine is used to overcome friction and the output work is less than the input work.

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a) The acceleration for an automobile driver is 22.23 m / s².

b) The acceleration for a bicycle rider will be zero.

Acceleration of any object is defined as the variation in the speed of the object with the variation of time. Acceleration is a vector term and to define it we require both the magnitude and the direction. The unit of acceleration can be m / sec², miles / sec², etc.

Given that An automobile driver increases the speed at a constant rate from 20 km/h to 46 km/h in 0.90 min. A bicycle rider speeds up at a constant rate from rest to 26 km/h in 0.90 min.

The acceleration for an automobile driver,

a = change in velocity / Time

a = ( 40 - 20 ) / 0.90

a = 22.23 m / s²

The acceleration of bicycle rider:-

a = change in velocity/time

a = ( 26 - 26 ) / 0.90

a = 0 m/s²

Hence, the acceleration for an automobile driver is 22.23 m / s² and he acceleration for a bicycle rider will be zero.

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Taking into account the definition of kinetic energy, the velocity of the object with a kinetic energy of 250 J and a mass of 32 kg is 3.95 m/s².

Kinetic energy is the energy possessed by a body or system due to its movement.

Kinetic energy is defined as the amount of work necessary to accelerate a body of a certain mass and in a position of rest, until it reaches a certain speed. Once the final speed is reached, the amount of kinetic energy accumulated will remain constant, that is, it will not vary, unless another force acts on the body again.

Kinetic energy is represented by the following expression:

Ec = 1/2×m×v²

Where:

In this case, you know:

Replacing in the definition of kinetic energy:

250 J = 1/2× 32 kg×v²

Solving:

250 J÷ (1/2× 32 kg) = v²

15.625 J÷kg = v²

√15.625 J÷kg = v

3.95 m/s² = v

Finally, the velocity of the object is 3.95 m/s².

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The syllogisms constructed from the given statements are valid, except for the one syllogism identified as invalid.

Categorical syllogisms are logical arguments that involve two premises and a conclusion, all of which are categorical statements. These statements are formed using categorical propositions that involve classes or categories of objects or concepts.

Let's examine the given statements and identify the valid and invalid syllogisms:

All mumbling is murmuring: This statement indicates that the class of mumbling is entirely contained within the class of murmuring. It can be represented as "All M is M."

All mumbling is nonsensical: This statement suggests that the class of mumbling is entirely nonsensical. It can be represented as "All M is N."

No murmuring is sensical: This statement implies that there is no overlap between the class of murmuring and the class of sensical. It can be represented as "No M is S."

Now, let's construct the syllogisms using these statements:Syllogism 1:

Premise 1: All M is Mumbling

Premise 2: All Mumbling is Nonsensical

Conclusion: Therefore, All M is Nonsensical

This syllogism is valid because it follows the form of the categorical syllogism, where the conclusion is a valid inference based on the premises.

Syllogism 2:

Premise 1: All Mumbling is Murmuring

Premise 2: No Murmuring is Sensical

Conclusion: Therefore, No M is Sensical

This syllogism is also valid as it follows the form of the categorical syllogism, where the conclusion is a valid inference based on the premises.

Syllogism 3:

Premise 1: All Mumbling is Nonsensical

Premise 2: No Murmuring is Sensical

Conclusion: Therefore, No Mumbling is Murmuring

This syllogism is valid as it follows the form of the categorical syllogism, where the conclusion is a valid inference based on the premises.

Invalid Syllogism:

Premise 1: All Mumbling is Murmuring

Premise 2: All Mumbling is Nonsensical

Conclusion: Therefore, All Murmuring is Nonsensical

This syllogism is invalid. It commits the fallacy of undistributed middle, where the middle term (Mumbling) is not properly distributed in either premise, leading to an invalid conclusion.

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Hi there!

Centripetal acceleration can be written as:

\(a_c = \frac{v^2}{r}\)

v = tangential velocity (m/s)

r = radius (m)

Plug in the given values:

\(a_c = \frac{65^2}{0.35} = \boxed{12071.43 \text{ m}/s^2}}}\)

The centripetal acceleration vector ALWAYS points towards the CENTER POINT of the barrel.

Answer:

a) F= 0,19  [N]   according to problem statement

b) F = 0,19*10⁹ [N]  using the right value of K

Explanation:

The force between two electric charges is according to Coulomb´s law is:

F = K * q₁*q₂ / d²    where  q₁  and q₂ are the charges on body one and body 2 respectively, d is the distance between the two bodies and K is a constant  K = 8,988100*10⁹ N.m²/C². The problem establishes to use        K = 8,988100 N.m²/C².

NOTE: To value of is :  K = 8,988100*10⁹ N.m²/C². I am going to solve the problem using K = 8,988100 N.m²/C² if that information was an error, all we need to get the right answer is multiply the result by 10⁹

Then:

F = 8,988100 * 1,2* 0,36 / (4,5)²     [ N*m²/C² ] * [ C*C*/m²]

F = 3,882859/ 20,25  [N]

F= 0,19  [N]

The force is of repulsion since the two charges are positive and in the direction of the straight line which passes through the centers of the bodies

Answer:

» Force is 200,000 Newtons

Explanation:

\({ \tt{force = \frac{impulse}{time} }} \\ \\ { \tt{force = \frac{20000}{0.1} }} \\ \\ { \tt{force = 200000 \: newtons}}\)

The electromagnetic radiations are composed of electromagnetic waves which are formed when an electric field comes in contact with the magnetic field. The radio waves are one of them.

The RADAR is radio detection and ranging which is a detection system used to find out the distance, angle and velocity of objects. It sends the electromagnetic waves to wireless devices and observes objects around the world.

The radio waves and microwaves are used for satellite communication. Radio waves transmit TV programmes and radio programmes whereas the microwaves are used in mobile phones.

Thus the radio waves are used in both RADAR and satellite communication.

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Answer:

233.33°F

Explanation:

(385K - 273.15) * 9/5 + 32 = 233.33°F

If a wave has an amplitude of 0.0800 m and is moving 7.33 m/s. The

wavelength of the wave is 1.69m.

The wavelength of a wave can be determined using the equation:

Wavelength = velocity / frequency

To determine the frequency we need to calculate the reciprocal of the time it takes for one complete oscillation.

frequency = 1 / time

frequency = 1 / 0.230

frequency ≈ 4.35 Hz

Substitute the values into the wavelength equation:

wavelength = velocity / frequency

wavelength = 7.33 / 4.35

wavelength ≈ 1.69m

Therefore the wavelength of the wave is approximately 1.69 meters.

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Given that the fundamental frequency of the string is f = 200 Hz

We have to find the second overtone frequency.

The second overtone frequency can be calculated by the formula

Substituting the value, the frequency of the second overtone is

Thus, the second overtone frequency is 600 Hz.

Answer:

Direction and Size both are required .

Answer:

C and D I think.

Have a good day:)

Answer:

Explanation:

English alphabets numbered fro 1 to 26

and the numbers 1 to10 so they are written in roman numbers as

1 - I

2 - II

3 - III

4 - IV

5 -V

6 - VI

7 -VII

8 - VIII

9 - IX

10 -X

11 - XI

12 - XII

13 - XIII

14 - XIV

15 - XV

16 - XVI

17 - XVII

18 - XVIII

19 - XIX

20- XX

21 - XXI

22 - XXII

23 - XXIII

24 - XXIV

25 - XXV

26 - XXVI  

1 mole of nitrogen atoms moving at 35.0 m/s possesses approximately 27.8 joules of energy.

To calculate the energy possessed by 1 mole of nitrogen atoms moving at 35.0 m/s, we need to consider both the kinetic energy and the molecular mass of nitrogen.

The kinetic energy (KE) of an object is given by the equation KE = 1/2 * m * v^2, where m is the mass and v is the velocity.

The molar mass of nitrogen (N₂) is approximately 28.0134 g/mol, which can be converted to kilograms by dividing by Avogadro's number (6.022 × 10^23). This gives us a mass of approximately 4.65 × 10^(-26) kg for one nitrogen atom.

Plugging in the values, we have KE = 1/2 * (4.65 × 10^(-26) kg) * (35.0 m/s)^2.

Evaluating the equation, we find that the kinetic energy possessed by one nitrogen atom is approximately 4.62 × 10^(-23) joules.

Since we are considering 1 mole of nitrogen atoms, we need to multiply this value by Avogadro's number to get the energy possessed by 1 mole. Avogadro's number is 6.022 × 10^23, so the total energy is approximately 2.78 × 10^1 joules, or 27.8 J.

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These waves are traveling at the same speed.  The wave with the highest frequency is option C, "A wave frequency with line crossing in the middle."

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two objects colliding inelastically in one dimension. Kinetic friction is not conserved, but momentum is. (a) Two equal-mass objects initially move in the same direction.

What does physics mean when it refers to friction?

The force preventing sliding against one another of hard substrates, fluid sheets, and material components is known as friction. There are various kinds of friction: ... Friction between two surfaces causes kinetic energy from moving surfaces to be converted into infrared radiation

What does kinetic friction look like?

In the case of static friction or kinetic friction, the force of tension is always applied to counteract actual or potential movement between the contacting materials. A bent stone sliding all along ice, for instance, encounters a kinetic force that slows it down.

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\( \small\bf \: let \: the \: distance \: of \: the \: man \: from \: the \: cliff \: be \: x\)

\( \small\bf \: thus \: time \: taken \: by \: sound \: to \: hit \: the \: cilff \: and \: return = \frac{2x}{v} = 1\)

\( \bf \to \: x = \frac{320}{2} m = 160m\)

\( \small \bf \: thus \: the \: distance \: between \: the \: cliffs \: = 160m \times 2 = 320m\)

Answer:

2.2

Explanation:

input force is 35 N and the output force is 77 N.

Mechanical advantage = output force / input force

Mechanical advantage = 77 N / 35 N

Mechanical advantage = 2.2

The Normal force = 302.63 N

Friction Force = 115 N

u*Normal force= friction,

u= 0.38,

N= 115/0.38

Therefore, the Normal force = 302.63 N

Mass is a fundamental feature of matter that quantifies the amount meaningful in an object. It is typically calculated in units of kilograms (kg) or grams (g). Mass is various from weight, that depends on the gravitational force pursuing an object, while mass debris constant although gravity.

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Answer:

a. 273 K b. 90.1 K c. 5.26 atm d. 0.33 atm

Explanation:

For isothermal expansion PV = constant

So, P₁V₁ = P₂V₂ where P₁ = initial pressure of gas = 1 atm (standard pressure), V₁ = initial volume of gas, P₂ = final pressure of gas and V₂ = final volume of gas,

So, P₁V₁ = P₂V₂

P₂ = P₁V₁/V₂

Since V₂/V₁ = 0.19,

P₂ = P₁V₁/V₂

P₂ = 1 atm (1/0.19)  

P₂ = 5.26 atm

For an adiabatic expansion, PVⁿ = constant where n = ratio of molar heat capacities = 5/3 for monoatomic gas

So, P₂V₂ⁿ = P₃V₃ⁿ where P₂ = initial pressure of gas = 5.26 atm, V₂ = initial volume of gas, P₃ = final pressure of gas and V₃ = final volume of gas,

So, P₂V₂ⁿ = P₃V₃ⁿ

P₃ = P₂V₂ⁿ/V₃ⁿ

P₃ = P₂(V₂/V₃)ⁿ

Since V₃ = V₁ ,V₂/V₃ = V₂/V₁ = 0.19

1/0.19,

P₃ = P₂(V₂/V₃)ⁿ

P₃ = 5.26 atm (0.19)⁽⁵/³⁾

P₃ = 5.26 atm × 0.0628

P₃ = 0.33 atm

Using the ideal gas equation

P₃V₃/T₃ = P₄V₄/T₄ where P₃ = pressure after adiabatic expansion = 0.33 atm , V₃ = volume after adiabatic expansion, T₃ = temperature after adiabatic expansion  P₄ = initial pressure of gas = P₁ = 1 atm , V₄ = initial volume of gas = V₁ and T₄ = initial temperature of gas = T₁ = 273 K (standard temperature)

P₃V₃/T₃ = P₄V₄/T₄

T₃ = P₃V₃T₄/P₄V₄    

T₃ = (P₃/P₄)(V₃/V₄)T₂

Since V₃ = V₄ = V₁ and P₄ = P₁

V₃/V₄ = 1 and P₃/P₄ = P₃/P₁

T₃ = (P₃/P₁)(V₃/V₄)T₂

T₃ = (0.33 atm/1 atm)(1)273 K  

T₃ = 90.1 K

So,

a. The highest temperature attained by the gas is T₁ = 273 K

b. The lowest temperature attained by the gas = T₃ = 90.1 K

c. The highest pressure attained by the gas is P₂ = 5.26 atm

d. The lowest pressure attained by the gas is P₃ = 0.33 atm

The vectors addition permits locating the perfect result for the sum of the two vectors in option B).  See attached and the vector is directed to the right and up.

Vector addition is the operation of adding or extra vectors together into a vector sum. The so-known as parallelogram regulation gives the rule for vector addition of or greater vectors. for two vectors and, the vector sum is received via placing them head to tail and drawing the vector from the loose tail to the unfastened head.

A vector is an amount or phenomenon that has impartial residences: importance and direction. The time period also denotes the mathematical or geometrical representation of the sort of quantity. Examples of vectors in nature are velocity, momentum, force, electromagnetic fields, and weight.

Vectors are used in technological know-how to describe something that has a direction and a magnitude. they're commonly drawn as pointed arrows, the length of which represents the vector's importance

Disclaimer: your question is incomplete, please see below for the complete question.

The image shows the complete question.

Which vector is the sum of vectors à and b?

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Answer:

Explanation:

Energy = \(6AT^4\)

therefore,

\(\frac{E_1}{E_2} = \frac{T_1^4}{T_2^4}\)

where \(E_2 = 2E_1\)

therefore,

\(\frac{E_1}{2E_1} = \frac{(500+273)^4}{T_2^4}\\\\T_2 = 919.257k\\\\T_2 = 646.257^oC\)

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Answer:

Answer is C                                

Explanation:

I just did it E2020

A free body diagram with three force vectors, the first pointing south labeled F Subscript g Baseline, the second pointing northeast labeled F Subscript T Baseline and the third pointing northwest labeled F Subscript T. Thus option C is correct.

Free body diagram is defined as a drawing of an interesting object with all of its surroundings removed and the forces at work on the subject's body clearly depicted.

It is also defined as a diagram that reduces the loads and moments acting on a component or system of components.

Free body diagrams are streamlined depictions of an object and the force vectors operating on it in a problem. Since the diagram will depict this body without its surroundings, it is "free" of its environment.

Thus, a free body diagram with three force vectors, the first pointing south labeled F Subscript g Baseline, the second pointing northeast labeled F Subscript T Baseline and the third pointing northwest labeled F Subscript T. Thus option C is correct.

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Answer:

False

Explanation:

includess lighting and powerful winds over 50Mph,creates hail and causes flash flooding and also tornadoes