How can a small boy balance a big boy
on asea- saw ? Show with a diagram​

Total emmisivity is 0.3706

and absorptivity is 0.833

Irradiation, I = 3000W / m2

reflection, Ir = 500W / m2

uniform temperature, T = 700 k

emissive power E = 5045 W / m2

Total emmisivity,

e = E / 5.67 x 10^-8 (T^4)

e= 5045 / 5.67 x  10^-8 x 700^4

e= 0.3706

absorptivity,

∝ = Iabs / I = I -Ir / I

∝ = 3000-500 / 3000

= 1 - 500 / 3000

∝ = 1 - 1/6

∝ = 0.833

Emissivity is described as the ratio of the energy radiated from a material's surface to that radiated from an ideal emitter, referred to as a blackbody, on the identical temperature and wavelength and underneath the equal viewing conditions.

It's miles a dimensionless range among zero (for an excellent reflector) and 1 (for an ideal emitter).

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If the student replaced the water in the calorimetry device with an ice bath at 0°C, the experimental results would differ in several ways:

Temperature Change: Instead of measuring the change in temperature of the water, the student would measure the change in temperature of the ice bath. As heat is transferred from the surroundings to the ice bath, the ice will melt and the temperature of the ice bath will increase until it reaches 0°C. The temperature change observed in the experiment would be different from that of the water bath.
Heat Capacity: The heat capacity of the ice bath would be different from that of the water bath. Ice has a lower heat capacity than water, meaning it requires less heat energy to raise its temperature. This would affect the amount of heat absorbed or released during the reaction and lead to different experimental results.
Enthalpy Change: The enthalpy change calculated from the experiment would be specific to the reaction being studied. However, the enthalpy change determined using an ice bath would be based on the heat exchange with the ice bath, rather than the water bath. The enthalpy change values would differ due to the different heat capacities and temperature changes involved.
Overall, using an ice bath instead of a water bath would result in different temperature changes, heat capacities, and enthalpy change values in the experimental results.

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The maximum orbital angular momentum for an electron in a hydrogen atom with a principal quantum number of 26 is 25.

To calculate the magnitude of the maximum orbital angular momentum Lmax for an electron in a hydrogen atom for states with a principal quantum number of 26, we can use the formula Lmax = n - 1, where n is the principal quantum number.

Therefore, for n = 26, Lmax = 26 - 1 = 25.

This means that the maximum orbital angular momentum for an electron in a hydrogen atom with a principal quantum number of 26 is 25. This value is significant because it determines the possible energy levels of the electron in the hydrogen atom and therefore, the spectral lines emitted by the atom.

The hydrogen atom is a simple atomic system with only one electron orbiting a single proton. The magnitude of the maximum orbital angular momentum for an electron in a hydrogen atom depends on the principal quantum number, which determines the energy of the electron and the size of its orbit.

the maximum orbital angular momentum for an electron in a hydrogen atom with a principal quantum number of 26 is 25.

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A transverse wave is when the particles oscillate in a direction perpendicular to the direction the wave travels. This means that the particles move up and down, or side to side, as the wave passes through them.

This type of wave is commonly seen in phenomena such as water waves, electromagnetic waves, and seismic waves. One example of a transverse wave is a wave on a rope. If you hold onto a rope and create a wave by moving your hand up and down, the wave will move along the rope in a direction perpendicular to the movement of your hand. The particles of the rope will oscillate up and down as the wave passes through them. Another example of a transverse wave is light. Light waves are made up of electric and magnetic fields that oscillate perpendicular to the direction of the wave. This is why light can be polarized, meaning the electric field oscillates in a particular direction. In summary, a transverse wave is one in which particles oscillate perpendicular to the direction of the wave. This type of wave is commonly seen in a variety of natural and man-made phenomena and plays an important role in fields such as physics and engineering.

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When working through these problems, think about the heat in terms of movement of the molecules of water.

Heat is transferred from the water to the surroundings --- water molecules slowing down.

Heat is transferred to the water from the surroundings --- water molecules heating up.

Heat transfer is the transfer of energy due to the difference of temperature between two different places. The main discussion in heat transfer is how the energy in heat can move places and the rate of transfer under certain conditions. Heat transfer includes the processes of inflow and outflow of heat. In industrial processes, heat transfer is used to achieve the required temperature in the industrial process and maintain the required temperature throughout the process.

Heat transfer from one object to another can occur by conduction, convection, and radiation. The determinant of heat transfer is the temperature difference. The direction of heat transfer starts from a medium with a high temperature to a medium with a lower temperature. Heat transfer can occur with a single process or multiple processes.

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The momentum associated with a photon having an energy equal to the electron rest energy is 0.511 MeV/c. The wavelength is 2.43pm and the frequency of the corresponding radiation is 1.24×10^20Hz

(a) The rest energy of an electron is given by E=mc^2

Thus the momentum of the photon is given as:

p = E/c = mc^2/c = mc where m is mass of electron = 9.11x10-31kg

p = 9.11x10-31x3x10^8 = 2.73x10-21kgm/s = 0.511 MeV/c

(b) the wavelength (λ) = h/p where h is planck's constant = 6.63×10−34Js

λ = 6.63×10−34/2.73x10-21 = 2.43×10−12m = 2.43pm

(c) the frequency of the corresponding radiation f =c/λ

f = 3x10^8/ 2.43×10−12 = 1.24×10^20Hz

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While lighting the rocket you should ensure D) decreasing the length of the stick

When lighting fireworks, avoid holding them in your hand or placing any part of your body over them. Don't carry fireworks in your pocket since the friction could set them off; instead, use eye protection. Keep pyrotechnics away from flammable objects, such as brush, leaves, and dwellings.

The continuous smoke from cracker explosions may sting or wet the eyes. Because bottle rockets are thought to be the riskiest cracker type, it's crucial to avoid them, keep a safe distance from the burning crackers, wear safety goggles, and avoid wearing contact lenses while popping crackers.

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Option B: 35°C. In the isolation of bacteria by dilution lab, the temperature at which you incubate your plates will depend on the type of bacteria you are trying to isolate.

However, the most commonly used temperature for incubating bacterial plates is 35°C (Celsius). This temperature is suitable for most mesophilic bacteria, which are bacteria that grow best at moderate temperatures, between 20°C to 45°C. In the isolation of bacteria by dilution lab, the purpose is to determine the number of bacteria in a sample by diluting it and then growing the bacteria on nutrient agar plates. To do this, the agar plates need to be incubated at a suitable temperature to promote bacterial growth. ncubating the plates at a temperature that is too low or too high may result in poor or no bacterial growth, which can affect the accuracy of the results. Therefore, it is important to ensure that the plates are incubated at the appropriate temperature for the type of bacteria being tested.

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The weight of a person on the planet Pluto with mass 85 kg is 52.36 N.

What is Pluto?

Pluto is a dwarf planet in the Kuiper belt, a ring of planets beyond Neptune's orbit. The ninth-largest and tenth-most massive object known to exist, it orbits the Sun directly. The largest trans-Neptunian object by volume, it is only slightly larger in mass than Eris. Like other Kuiper belt objects, Pluto is substantially smaller than the inner planets and is primarily made of ice and rock. The moon of Earth is only one-sixth the mass and one-third the volume of Pluto.

At first, lets calculate the acceleration due to gravity at Pluto:

The formula to calculate the acceleration due to gravity is:

\(a_g = G \times \frac{m}{r^2}\)

where, a = acceleration due to gravity, m = mass, r = radius, G = gravitational constant

The mass is 1.303 x 10^22 kg

The radius is 1.1883 x 10^6 m

G is 6.67408 x 10^-11 m^3/kg•s²

So

a = 6.67408 x 10^-11 m^3/kg•s^2 • 1.303 x 10^22 kg / (1.1883 x 10^6 m)^2

a = 8.69632624 x 10^11 m^3/s^2 / 1.41205689 x 10^12 m^2

a = 6.1586 x 10^-1 m/s² or 0.616 m/s²

Now, lets calculate the weight:

w = ma

where, w = weight, m = mass

putting the values in question, we get,

w = 85 (0.616)  

w = 52.36 N

Note: Some correction in the value of mass and radius needs to be done in the question.

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The ideal gas law is given by PV=nRT where P is the pressure of the gas, V is the volume of the gas, n is the amount of substance, R is the ideal gas constant, and T is the absolute temperature.

For this question, we want to calculate the internal energy of the neon gas.The internal energy of a gas is given by U = (3/2) nRT where n is the amount of substance, R is the ideal gas constant, and T is the absolute temperature.

From the given information, we know that the container has a volume of V = (17.0 cm)^3 = 4913 cm^3 and contains two times Avogadro's number of neon atoms, which is equal to n = 2N_A.

We also know that the temperature of the gas is T = 30.0 + 273 = 303 K.Substituting these values into the equation for the internal energy, we get:U = (3/2) nRT = (3/2) × 2N_A × R × 303= 3N_A × R × 303 joules/moleSince the value of R is 8.31 J/(mol·K),

we can calculate the internal energy of the neon gas as follows:U = 3N_A × R × 303 = 3 × 6.022 × 10^23 × 8.31 × 303 J/mol= 4.02 × 10^27 J

The internal energy of the neon gas in the sealed cubic container is 4.02 × 10^27 J.

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Answer:

Abiotic referfers to non-living and biotic factors are living or once living

Explanation:

Answer:

Assess what information you are given. Use this method if you know:

the total distance covered by one person or vehicle; and

the total time it took that person or vehicle to cover the distance.

Explanation:

Hope this helps! I might be wrong, so tell me if I am

Answer:

Average speed can be calculated by dividing the total distance the object travels by the total amount of time it takes to travel that distance.

Explanation:

This is as much as I can help you, i don't know much else on how to do that ;w; sorry

Ultra = X-ray

Explanation:

how are things going to paint the roof for beginners painting and decorating the whole house so I'm going away with a few sports mates for a couple nights for beginners but will have a look painting at a time and see what is going to be Strong enough

The warm water of the lake transfers heat to the alligator through conduction.

Ectothermic animals like alligators depend on outside heat sources to maintain body temperature. By taking a sunbath or relocating to places with warmer or colder air or water temperatures, alligators may regulate their body temperature. Ectothermic, or cold-blooded, alligators experience temperature changes in response to their surroundings. Alligators are forced to actively regulate their body temperature as a result, searching out locations that are both warm and cool enough for them. Alligators may lay in the sun with their jaws open to allow heat to escape while they enjoy the Florida sunshine as it becomes too hot over 92°. Alligators will move very little during the day and become more active at night if the temperature is too high.

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Answer:

2

Explanation:

I took the test and got it correct

Answer:

2

Explanation:

The plane's speed is 450 miles per hour, and the wind speed is 50 miles per hour. This is determined by solving the equations derived from the distances and times of the flight with and against the wind.

Let's assume the speed of the plane (without considering the wind) is P, and the speed of the wind is W.

When flying into a headwind, the effective speed of the plane is reduced by the wind speed. So the equation for the outbound flight is:

P - W = 2000 miles / 5 hours

P - W = 400 miles per hour (mph)  ---(Equation 1)

When flying with a tailwind, the effective speed of the plane is increased by the wind speed. So the equation for the return flight is:

P + W = 2000 miles / 4 hours

P + W = 500 miles per hour (mph)  ---(Equation 2)

Now we have a system of two equations (Equation 1 and Equation 2) with two variables (P and W). We can solve this system to find the values of P and W.

Adding Equation 1 and Equation 2 together, we eliminate the variable W:

(P - W) + (P + W) = 400 mph + 500 mph

2P = 900 mph

P = 450 mph

Substituting the value of P back into Equation 1 or Equation 2, we can solve for W:

450 mph - W = 400 mph

W = 450 mph - 400 mph

W = 50 mph

Therefore, the plane's speed is 450 mph and the wind speed is 50 mph.

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normal force=mass*gravitational force

normal force=40*0

normal force=40

Answer:

Newton's second law of motion is F = ma, or force is equal to mass times acceleration.

Shield Volcanoes are formed from basaltic lava.

The largest volcanoes on Earth that truly resemble volcanoes are shield volcanoes (i.e. not counting flood basalt flows). The most well-known examples are the shield volcanoes of Hawaii.

The lava that is released from shield volcanoes is nearly always basalt, which is a particularly fluid type of lava. Because of this, these volcanoes are not steep (a fluid that easily runs downhill cannot be piled up). Shield volcano eruptions are low-explosivity fountaining that creates cinder cones and spatter cones at the vent; however, 90% of the volcano is lava rather than pyroclastic material.

Shield volcano eruptions are only explosive if water somehow gets into the vent. Due to the high rates of magma supply, shield volcanoes form; the lava is hot and has not changed much since it was formed.

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The term that best describes the distance of 74.0 cm from a patient's eye, at which they cannot clearly see any object, is the "near point". The correct option is c.

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Answer:

precise

Explanation:

im pretty sure

For the 100 litre open-topped tank:

a) To find an equation that gives the amount of salt remaining in the tank after t seconds, consider the rate at which salt enters and leaves the tank.

The initial amount of salt in the tank is 100 L × 80 g/L = 8000 g.

Rate of salt entering the tank:

The fresh water entering the tank at 10 L/sec has a salt concentration of 0 g/L. Therefore, the rate of salt entering the tank is 0 g/sec.

Rate of salt leaving the tank:

The excess water running out over the top at 10 L/sec carries away salt with a concentration of 80 g/L. Therefore, the rate of salt leaving the tank is 80 g/sec.

Rate of change of salt in the tank:

The rate of change of salt in the tank is given by the difference between the rate of salt entering and leaving the tank:

dS/dt = 0 - 80 = -80 g/sec

b) To find how much salt is left in the tank after one minute (60 seconds), integrate the rate equation from t = 0 to t = 60:

∫dS = ∫(-80) dt

ΔS = -80t + C

Since the initial amount of salt is 8000 g (at t = 0), solve for the constant C:

8000 = -80(0) + C

C = 8000

Therefore, the equation for the amount of salt remaining in the tank after t seconds is:

S(t) = -80t + 8000

Substituting t = 60 seconds:

S(60) = -80(60) + 8000

S(60) = 3200 g

c) After 100 L of brine has flowed out over the top of the tank, the remaining volume of salt water in the tank is 100 L (initial volume) - 100 L (flowed out) = 0 L. Therefore, there is no salt left in the tank.

d) To find when half of the salt in the tank has flowed out over the top,  set S(t) = 0.5 × initial amount of salt:

0.5 × 8000 = -80t + 8000

-80t = 8000 - 4000

-80t = 4000

t = -4000 / -80

t = 50 seconds

Therefore, half of the salt in the tank will have flowed out over the top after 50 seconds.

e) To find when the tank contains salt water at a concentration of 5 g/L, set S(t) = V(t) × 5, where V(t) is the volume of water in the tank at time t:

V(t) × 5 = -80t + 8000

V(t) = (-80t + 8000) / 5

V(t) = 100 L (initial volume) - 10 L/sec × t (rate of water leaving the tank):

100 - 10t = (-80t + 8000) / 5

Multiplying both sides by 5:

500 - 50t = -80t + 8000

30t = 7500

t = 250 seconds

Therefore, the tank will contain salt water at a concentration of 5 g/L after 250 seconds.

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Answer: Most likely purple

Explanation:

Answer:

Purple?

Explanation:

I'm confused what you are asking.

Answer:

Speed is the time rate at which an object is moving along a path, while velocity is the rate and direction of an object's movement.

Answer:

Speed is the time rate at which an object is moving along a path, while velocity is the rate and direction of an object's movement.

Explanation:

Answer:9.81 m/s2.

Explanation:

If a 2 kg object is falling at 3 m/s, at what rate is gravity working on the object ? The object is falling at 3 m/s. Gravity is working on the object at a rate of 9.81 m/s2.

Volume of the balloon occupy in the instant before it bursts is 7.39 litres and can be find out by boyle's law.

Boyle’s law:

This law gives the relationship between initial and final pressure and volumes for an ideal gas.

Initial condition

Let the volume of the balloon is V1=2.00 L

And, the initial pressure is P1=1.75 atm

Final condition

Let the volume of balloon before it bursts is V2

final pressure is P2=360 mmHg

                                =360/760 atm

                                =0.7368 atm
                           (1atm=760mmHg)

Now, according to boyle’s law

P1V1=P2V2

V2=P1V1/P2

V2=1.75*2.00/0.47368 L

V2=1.39L

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Slumped area only supports grassy vegetation and no trees can be grow on it.

A slump is a form of mass wasting that occurs when a rock layer moves at a short distance down a slope, this type of area is called slumped area. The speed of the mass movement at slumped area is slow i.e. few cm per year or meter per year.

There are no trees growing in the slumped area because trees required fixed land but the land moves at the slumped area so we can conclude that slumped area only supports grassy vegetation and no trees can be grow on it.

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Answer:

The grassy vegetation in the slumped soil indicates slow movement of material, and it appears recently enough that trees have not had time to establish themselves.

Explanation:

It likely moved gradually over a period ranging from days to years. Grassy vegetaion has been able to establish on the surface without any breaks or open soil visible, this is evidence of the gradual movement.

The amount of lateral strain in a tension member can be calculated using Poisson's ratio.

To calculate the lateral strain, we can use the equation: ε_lateral = -ν * ε_longitudinal

Where:

ε_lateral = Lateral strain

ν = Poisson's ratio

ε_longitudinal = Longitudinal strain

Poisson's ratio (ν) is a material property that describes the ratio of lateral strain to longitudinal strain when a material is subjected to an axial load. It is defined as the negative ratio of the transverse strain to the longitudinal strain.

Calculating the lateral strain involves determining the longitudinal strain, which can be calculated using the equation:ε_longitudinal = ΔL / L

Where:

ε_longitudinal = Longitudinal strain

ΔL = Change in length of the tension member

L = Original length of the tension member

Once the longitudinal strain is calculated, we can use Poisson's ratio to determine the lateral strain by multiplying the longitudinal strain by the negative value of Poisson's ratio.

It is important to note that the lateral strain is typically very small compared to the longitudinal strain in a tension member, especially for materials with a low Poisson's ratio.

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We can conclude that θ > 30° for total internal reflection to occur and prevent light from entering medium 1.

When light travels through different media, it experiences refraction, which is the bending of light due to the change in its speed. In this case, light is traveling from medium 3 (n3 = 3.00) to medium 2 (n2 = 2.00) at an angle θ. If no light enters medium 1 (n1 = 1.00), it indicates that the light is undergoing total internal reflection at the interface between medium 2 and medium 1.

Total internal reflection occurs when the angle of incidence (θ) is greater than the critical angle (θc). The critical angle can be calculated using Snell's Law, given by:

sin(θc) = n1 / n2

In this case, sin(θc) = 1.00 / 2.00 = 0.5, so θc ≈ 30°. Therefore, we can conclude that θ > 30° for total internal reflection to occur and prevent light from entering medium 1.

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