how did you differentiate the statements
describing standard normal distribution from those involving tdistribution?

Answer:

Step-by-step explanation:

50(0.975)^30

= 23.39 Round if necessary to 23.40

The amount of Ib of chromium will be 23.40 if one type of chromium has a radioactive decay rate of 2.5% per day.

It is defined as the factor that represents the increase and decrease in value by that factor. For the growth add one as a decimal and for the decay subtract one as a decimal.

It is given that:

One type of chromium has a radioactive decay rate of 2.5% per day.

y = 50(0.975)×

y = 50(0.975)³⁰

= 23.39

= 23.40

Thus, the amount of Ib of chromium will be 23.40 if one type of chromium has a radioactive decay rate of 2.5% per day.

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Answer:

653.91 squared or 326.955 not squared

Step-by-step explanation:

We have a hyponuse of 26 and one leg of 4.7 and we are trying to figure out the missing leg!

The first step is

A^2 + B^2 = C^2

2 step

4.7^2 + B^2 = 26^2

3 step

4.7 x 4.7 =  22.09  and 26 x 26 = 676

4 step

22.09 + B^2 = 676

5 step

676 - 22.09 = 653.91

6 step

Answer

653.91 squared or 326.955 not squared!

hope this helps

Answer:

the answer is 96 it's 12 x 8

Answer:

EASY 96

Step-by-step explanation:

just add all sides together 12+12+12+12+12+12+12+12=96

out of 500 people 200 like baseball and 120 people like to play game baseball/softball

suppose 48 out of every 120 people like baseball/softball.

of the people who like baseball/softball, 3 out of 5 play the game.

if you ask 500 people,

how many would you expect play baseball/softball

it means 40% like baseball and 60% like to play game

if there are 500 people

then 500 *(40/100)=200

thus 200 people like baseball

and 200*(60/100)=120

Hence 120 people to play game

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We have 390 and we want to find the number thart multiplied by it, will result in 390,000

If we count how many zeros of diffrence between 390 and 390,000 we have, we will notice that:

Therefore, the solution should be 1,000 because:

390 * 1,000 = 390,000

This is the solution we are looking for. Correct answer is B.

The inequality that represents Rita saving money from the second option is 0.059x < 0.49 + 0.019x

From the question, we have the following parameters that can be used in our computation:

These statements can be represented as

Option 1: y = 0.49 + 0.019x

Option 2: y = 0.059x

Where y is the total amount and x is the number of minutes

When she saves money, we have

Option 2 < Option 1

Substitute the known values in the above equation, so, we have the following representation

0.059x < 0.49 + 0.019x

Hence, the inequality is 0.059x < 0.49 + 0.019x

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Suppose a person lost 10 pounds in a month. This z-score tells you that x = 10 is 2.5  standard deviations to the right of the mean 5 pounds.

To verify that the z-score when x = 10 pounds is z = 2.5, we can use the formula:

z = (x - μ) / σ

where x is the value of the random variable, μ is the mean, and σ is the standard deviation.

Plugging in the given values, we have:

z = (10 - 5) / 2 = 2.5

This confirms that the z-score when x = 10 pounds is z = 2.5.

To determine what the z-score tells us about the location of x = 10 pounds relative to the mean, we can use the definition of a z-score:

z = (x - μ) / σ

Rearranging the formula, we have:

x = μ + zσ

So, when z = 2.5 and σ = 2, we have:

x = μ + 2.5(2) = μ + 5

This tells us that x = 10 pounds is 5 pounds above the mean. Since the z-score is positive, x = 10 pounds is to the right of the mean.

Therefore, the z-score tells us that x = 10 is 2.5 standard deviations to the right of the mean of 5 pounds.

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The best conclusion for her to come to: D. this could easily happen with a fair coin after only 3 flips.

A fair coin can be defined as an idealized type of coin that has an equal probability of revealing both heads and tails when randomly tossed.

This ultimately implies that, the best conclusion for her to come to is that this could easily happen with a fair coin after only 3 flips considering 2 of the three coins come up tails.

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Answer:8

Step-by-step explanation: plug in 0 for y then solve

Answer:

-0.80

1.66

0.26

2.56

-0.50

Step-by-step explanation:

The values are the probability values either to the right or left of a given z - value ;

The Z - values could be obtained using the standard normal distribution table or a calculator :

Using the Z probability calculator ;

Area to the left of z is 0.2119

1.)

P(z < z) = 0.2119

z = - 0.8

2.)

Area between - z and z = 0.9030

Area to the left of z = 0.9030 plus

Area to the right of z = (1 - 0.9030) / 2 = 0.097/2 = 0.0485

(0.9030 + 0.0485) = 0.9515

P(z < z) = 0.9515

z = 1.66

3.)

Area between - z and z = 0.2052

Area to the left of z = 0.2052 plus

Area to the right of z = (1 - 0.2052) / 2 = 0.7948/2 = 0.3974

(0.2052 + 0.3974) = 0.6026

P(z < z) = 0.6026

z = 0.26

D.)

The area to the left of z is .9948

P(Z < z) = 0.9948

z = 2.562

E.)

The area to the right of z is .6915.

P(Z < z) = 1 - 0.6915

P(Z < z) = 0.3085

z = - 0.5

Answer:

y > -1

Step-by-step explanation:

8y+9 > 1

   -9    -9

8y > -8

/8    /8

y > -1

Answer:

whole numbers: 0

integers: -9

natural: 4 & 100

rational: 1.44 & 1/2

irrational: √17, √29, √60, & π (pie)

The correct formula that defines an arithmetic sequence is option d) tn = 5n + 14.

An arithmetic sequence is a sequence of numbers in which the difference between consecutive terms remains constant. In other words, each term can be obtained by adding a fixed value (the common difference) to the previous term.

In option a) tn = 5 + 14, the term does not depend on the value of n and does not exhibit a constant difference between terms. Therefore, it does not represent an arithmetic sequence.

Option b) tn = 5n² + 14 represents a quadratic sequence, where the difference between consecutive terms increases with each term. It does not represent an arithmetic sequence.

Option c) tn = 5n(n+14) represents a sequence with a varying difference, as it depends on the value of n. It does not represent an arithmetic sequence.

Option d) tn = 5n + 14 represents an arithmetic sequence, where each term is obtained by adding a constant value of 5 to the previous term. The common difference between consecutive terms is 5, making it the correct formula for an arithmetic sequence.

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The value of the discriminant for the equation -5x^2 - x + 1 = 0 is 21.

A quadratic equation is an algebraic equation of the second degree in x. The quadratic equation in its standard form is ax2 + bx + c = 0, where a and b are the coefficients, x is the variable, and c is the constant term.

To find the discriminant of a quadratic equation in the form ax^2 + bx + c = 0, we use the formula:

Discriminant (D) = b^2 - 4ac

For the given equation -5x^2 - x + 1 = 0, we have a = -5, b = -1, and c = 1. Plugging these values into the discriminant formula, we get:

D = (-1)^2 - 4(-5)(1)

D = 1 + 20

D = 21

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Answer:

19,500 people

Step-by-step explanation:

20% of 25,000 is 5,000.

Add 5,000 to 25,000 - this will give you 30,000. That is a 20% increase.

65% of 30,000 is 19,500, thus there are 19,500 people in the stadium.

The correct expression that represents the statement "Budweiser is bland if either Heineken is balanced or Foster's is refreshing" is option (c) B-(HVF).

Option (c) B-(HVF) represents the logical statement "Budweiser is bland (B) if not (-(HVF)) either Heineken is balanced (H), Foster's is refreshing (F), or both."

The statement states that Budweiser is bland if either Heineken is balanced or Foster's is refreshing. In logical terms, this can be represented as "Budweiser is bland if (Heineken is balanced) or (Foster's is refreshing)."

The expression B-(HVF) captures this logic. The '-' symbol denotes the negation or "not" operator. So, -(HVF) means "not (Heineken is balanced and Foster's is refreshing)."

The expression B-(HVF) states that Budweiser is bland if not both Heineken is balanced and Foster's is refreshing. This aligns with the given statement and correctly represents the logical relationship between Budweiser's blandness and the conditions related to Heineken and Foster's.

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\(\angle AQO + \angle OQB = 120^\circ$, so $\boxed{\theta = 60^\circ}$\) is the solution.

Let's first draw a diagram to visualize the problem:

Since \($\triangle ABC$\) is isosceles, we have \($\angle BAC = \angle BCA = \theta$\) and \($\angle ABC = 180^\circ - 2\theta$\). Let O be the center of the circle, and let D and E be the points of tangency of the tangents through A and C, respectively.

Since \($AD$\) and \($CE$\) are tangents to the circle, we have \($OD \perp AD$\) and \($OE \perp CE$\). Since \($AO$\) and \($CO$\) are radii of the circle, we have \($AO \perp BC$\) and \($CO \perp AB$\).

Therefore, \($OD \parallel CO$\) and \($OE \parallel AO$\). It follows that \($\angle DOB = \angle COB = \theta$\), and \($\angle EOA = \angle AOB = \theta$\).

Thus, \($\angle DOA = \angle EOC = \theta$\), and \($\angle AOE = \angle DOC = \theta$\).

Now, consider the quadrilateral \($AODE$\). Since \($\angle AOE = \angle DOA = \theta$\), we have \($\angle OAE = \angle ODE = 90^\circ - \theta$\). Similarly, \($\angle OCE = \angle OED = 90^\circ - \theta$\). Since \($\triangle ABC$\) is isosceles, we have \($AB = BC$\), so \($AD = EC$\).

It follows that \($\triangle AOD \cong \triangle CEO$\) by SAS congruence.

Therefore, \($AO = CO$\), so \($\triangle AOB$\) and \($\triangle COB$\) are congruent by SAS congruence.

Thus, \($AB = BC$\), so \($\triangle ABC$\) is equilateral.

Therefore, \($\theta = 60^\circ$\).

Finally, since \($\angle AOB = \theta = 60^\circ$\), we have \($\frac{1}{2}\angle APB = \theta = 60^\circ$\), so \($\angle APB = 120^\circ$\).

Therefore, \($\angle APQ = \angle BPQ = \frac{1}{2}(180^\circ - \angle APB) = 30^\circ$\). Since \($\triangle APQ$\) is isosceles, we have \($\angle QAP = \angle QPA = \frac{1}{2}(180^\circ - \angle APQ) = 75^\circ$\).

Therefore, \($\angle AQP = \angle BQP = 105^\circ$\), so \($\angle AQB = 2\angle BQP = 210^\circ$\).

Thus, \($\angle AQO = \frac{1}{2}(360^\circ - \angle AQB) = 75^\circ$\), and \($\angle OQB = \frac{1}{2}(180^\circ - \angle AQB) = 45^\circ$\).

Therefore, \(\angle AQO + \angle OQB = 120^\circ$, so $\boxed{\theta = 60^\circ}$\) is the solution.

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Answer:

70g+74

Step-by-step explanation:

Answer:

= 70g + 74

Step-by-step explanation:

10 (7 + 7g) + 4

= 10(7g + 7) + 4

= 70 + 70g + 4

= 70g + 74

Answer: 3*10⁻⁴.

Step-by-step explanation:

\(\displaystyle\\2,1*10^{-5}\div7*10^{-2}=\\\frac{2,1*10^{-5}}{7*10^{-2}}=\\ \frac{2,1}{7}*10^{-5-(-2)}=\\ 0,3*10^{-5+2}=\\0,3*10^{-3}=\\3*10^{-4}.\)

\(\huge\underline{\underline{\boxed{\mathbb {SOLUTION:}}}}\)

▪ \(\longrightarrow \sf{\dfrac{2.1 \times {10}^{5} }{7 \times {10}^{ - 2} } }\)

First, rewrite the numerator in such a way that the coefficient 2.1 becomes 21:

\(\small\longrightarrow \sf{\dfrac{21 \times {10}^{ - 6} }{7 \times {10}^{2} } }\)

Divide the coefficient:

\(\small\longrightarrow \sf{21 \div 7=3}\)

Divide the base by subtracting the exponents of the base 10.

\(\small\longrightarrow \sf{-6(-2) \Longrightarrow -6+2=-4}\)

\(\leadsto\) Hence, the quotient of the given expression has a coefficient of 3 and the exponent of the base 10 is -4.

\(\small\longrightarrow \sf{3 \times 10^{-4}}\)

\(\huge\underline{\underline{\boxed{\mathbb {ANSWER:}}}}\)

\(\large \bm{The \: \: quotient \: \: is \: \: 3 \times {10}^{ - 4} .}\)

Answer:

An absolute value equation has no solution if the absolute value expression equals a negative number since an absolute value can never be negative. You can write an absolute value inequality as a compound inequality. This holds true for all absolute value inequalities. You can replace > above with ≥ and < with ≤.

Step-by-step explanation:

hope this helps!

Answer: -absolute value inequalities work two ways, not 1

-if it's greater than anything less than 0, then the solution is all real numbers

- if it's less than zero, there is no solution

-dividing by -1 flips the sign

Step-by-step explanation:

These are just some of the rules that I know

Answer:

3^2+2^2=13

\( \sqrt{13} \)

= 3.60555

Step-by-step explanation:

prove me wrong

Moving on to step 20, you need to take a screenshot issues of the tools menu. This can usually be accessed by clicking on the "Tools" option in the menu bar of the program or application you are using.

To take a  of the tools menu in step 20, you can follow these steps:Open the tools menu in the desired application or software.Press the "Print Screen" (PrtSc) button on your keyboard. This will capture a screenshot of your entire screen.

Open an image editing software or any program that allows you to paste imagesPaste the screenshot by pressing "Ctrl" + "V" on your keyboard.Save the image in your desired format.

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When there are precisely two outcomes of a trial that are mutually exclusive, the binomial distribution is used.

A discrete distribution is the binomial distribution. It is a probability distribution that is frequently utilised. It is then designed to represent a variety of distinct phenomena that appear in business, social sciences, natural sciences, and medical research.

The probability of achieving a specific number of successes, such as successful basketball shots, out of a fixed number of trials can be determined using the binomial distribution. To determine discrete probabilities, we use the binomial distribution.

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Answer:

The answer is A

Step-by-step explanation:

(2*38)=76

(2*2)=4

The exact value of sin(x/2) is (sqrt(1 - cos x) )/2 and the exact value of tan(x/2) is sin x / (1 + cos x), where x is the angle in radians.

Given that sin x = 5/13 and x is in the second quadrant, we can use the Pythagorean identity to find cos x. We have:

sin^2 x + cos^2 x = 1

Substituting sin x = 5/13, we get:

(5/13)^2 + cos^2 x = 1

Solving for cos x, we get:

cos x = -12/13

Now we can substitute cos x = -12/13 into the formulas for sin(x/2) and tan(x/2) to get:

sin(x/2) = sqrt(1 - cos x)/2 = sqrt(1 + 12/13)/2 = sqrt(25/26)/2 = (5/2)sqrt(2/13)

tan(x/2) = sin x / (1 + cos x) = (5/13) / (1 - 12/13) = -5

Therefore, the exact values of sin(x/2) and tan(x/2) are (5/2)sqrt(2/13) and -5, respectively.

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We can use the half-angle formulas to find the exact values of sin x/2 and tan x/2. In this case, we have:

sin(x/2) = ±√[(1 - cos x) / 2]

tan(x/2) = sin x / (1 + cos x)

First, we need to find cos x, since it is not given directly. We know that x is in quadrant 2, which means that the sine is positive and the cosine is negative. We can use the Pythagorean identity to find cos x:

sin^2 x + cos^2 x = 1

cos^2 x = 1 - sin^2 x

cos x = -√(1 - sin^2 x)

Plugging in sin x = 5/13, we get:

cos x = -√(1 - (5/13)^2) = -12/13

Now we can use the half-angle formulas:

sin(x/2) = ±√[(1 - cos x) / 2]

sin(x/2) = ±√[(1 + 12/13) / 2]

sin(x/2) = ±√(25/26)

Since x is in quadrant 2, we know that sin x/2 is positive. Therefore, we have:

sin(x/2) = √(25/26) = 5/√26

Next, we can use the formula for tangent:

tan(x/2) = sin x / (1 + cos x)

tan(x/2) = (5/13) / (1 - 12/13)

tan(x/2) = (5/13) / (1/13)

tan(x/2) = 5

Therefore, the exact values of sin x/2 and tan x/2 are:

sin(x/2) = 5/√26

tan(x/2) = 5

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Using differentials, the maximum error in the viscosity of a fluid moving through a tube can be estimated to be approximately 8.07e-3 Pa s given the tube's length, radius, pressure, and flow rate, along with their respective uncertainties.

We can use the formula for the differential of a function of several variables to estimate the maximum error in the viscosity η:

dη ≈ ∂η/∂r * dr + ∂η/∂p * dp + ∂η/∂v * dv

where ∂η/∂r, ∂η/∂p, and ∂η/∂v are the partial derivatives of η with respect to r, p, and v, respectively. We can calculate these partial derivatives as follows:

∂η/∂r = π/2 * p * r^3 / v

∂η/∂p = π/8 * r^4 / v

∂η/∂v = -π/8 * p * r^4 / v^2

Plugging in the given values and their uncertainties, we get:

dr = 0.00025 meters

dp = 2000 pascals

dv = 0.375e-9 m^3 per unit time

r = 0.003 meters

p = 2e5 pascals

v = 0.375e-9 m^3 per unit time

∂η/∂r ≈ (π/2) * (2.0e5) * (0.003)^3 / (0.375e-9) ≈ 3.84e-3 Pa s/m

∂η/∂p ≈ (π/8) * (0.003)^4 / (0.375e-9) ≈ 4.26e8 Pa s^2/m^4

∂η/∂v ≈ -(π/8) * (2.0e5) * (0.003)^4 / (0.375e-9)^2 ≈ -2.06e-21 Pa s^2/m^4

Now we can plug these values into the formula for dη:

dη ≈ (3.84e-3 * 0.00025) + (4.26e8 * 2000) + (-2.06e-21 * 0.375e-9)

≈ 8.07e-3 Pa s

Therefore, the maximum error in the viscosity η is approximately 8.07e-3 Pa s.

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