Answer:
\(x = \frac{-3}{2} \\or \\x = -\frac{3}{2}\\or\\-1.5\)
Step-by-step explanation:
2x = -3
divide 2 from both sides
\(x = \frac{-3}{2} \\\\or \\x = -\frac{3}{2}\)
Answer:
x=-1.5
Step-by-step explanation:
1. Divide on both sides to get the x alone; -3 divided by 2 is -.15 or -3/2
During a walk, walkers discover a car that has fallen to the bottom of a 20m high vertical cliff. It is 10m from the foot of the cliff. The police investigation reveals that the braking marks (perpendicular to the edge) start at 7.5m from the upper (horizontal) edge of the cliff and that the acceleration (braking!) was -5m/s. The chief sergeant concludes an accident. Calculate the speed of the car before the start of braking and the duration of the driver's anxiety (braking & fall).After the calculation, I got t1 from cliff = 2 sec, I got the Vf from the baking = 5m/s, I need to find V0 before baking (using this formula = d=v0t+1/2at^2),
Given, Height of the cliff = 20 m Distance of the car from the foot of the cliff = 10 m.
The time taken by the car to fall from the cliff can be found using the formula:
\(`h = (1/2) g t^2`\)
Where h is the height of the cliff, g is the acceleration due to gravity and t is the time taken by the car to fall from the cliff.
Substituting the given values,`20 = (1/2) × 9.8 × t^2`
Solving for t, `t = sqrt(20/4.9)` = 2.02 s
Let the initial velocity of the car be V0 and the time taken for the car to come to rest after applying brakes be t1.
Distance covered by the car before coming to rest can be found using the formula: `\(s = V0t1 + (1/2) (-5) t1^2\)`
Where s is the distance covered by the car before coming to rest.
Simplifying the above equation,\(`2.5 = V0 t1 - (5/2) t1^2`\)
Substituting the given values,`5 = V0 - 5 t1`
Solving the above two equations,\(`V0 = 32.5/2 t1`\)
Simplifying the above equation,`V0 = 16.25 t1`
Substituting the value o\(f t1,`V0 = 16.25 × 2` = 32.5 m/s\)
Therefore, the speed of the car before the start of braking is 32.5 m/s.
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Where in the xy-plane are the points with x > 0 and y? 0?*
A. Quadrant |
B. Quadrant II
C. Quadrant III
D. Quadrant IV
A bag contains 10 red marbles, 7 white marbles, and 8 blue marbles. You draw 3 marbles out at random, without replacement. Give all answers as a decimal rounded to four places. a) What is the probability that all the marbles are red? The probability that all the marbles are red is b) What is the probability that exactly two of the marbles are red? The probability that exactly two of the marbles are red is c) What is the probability that none of the marbles are red? The probability of picking no red marbles is
a) The probability that all the marbles drawn are red is ≈ 0.3130.
The total number of marbles in the bag is 10 + 7 + 8 = 25. To select 3 red marbles, we have 10 red marbles to choose from initially, then 9 for the second draw, and 8 for the third draw (since we are drawing without replacement).
The total number of favorable outcomes is given by the product of these numbers: 10 * 9 * 8 = 720.
The total number of possible outcomes is the number of ways to select any 3 marbles from the 25 available: C(25, 3) = 25! / (3!(25-3)!) = 25! / (3!22!) = (25 * 24 * 23) / (3 * 2 * 1) = 2300.
Therefore, the probability that all the marbles drawn are red is: 720 / 2300 ≈ 0.3130.
b) The probability that exactly two of the marbles drawn are red is ≈ 1.7609.
To have exactly two red marbles, we can consider three different cases:
1. Red-Red-Non-red: There are 10 ways to choose the first red marble, 9 ways to choose the second red marble, and 15 ways to choose the non-red marble (7 white + 8 blue). So the number of favorable outcomes is 10 * 9 * 15 = 1350.
2. Red-Non-red-Red: Similarly, there are 10 * 15 * 9 = 1350 favorable outcomes.
Non-red-Red-Red: Again, there are 15 * 10 * 9 = 1350 favorable outcomes.
The total number of favorable outcomes for exactly two red marbles is the sum of these three cases: 1350 + 1350 + 1350 = 4050.
The total number of possible outcomes remains the same: C(25, 3) = 2300. Therefore, the probability that exactly two of the marbles drawn are red is: 4050 / 2300 ≈ 1.7609.
c) The probability of picking no red marbles is ≈ 0.1978.
In this case, we need to select all 3 marbles from the non-red marbles, which are the 7 white marbles and 8 blue marbles. The number of favorable outcomes is given by: C(15, 3) = 455.
The total number of possible outcomes remains the same: C(25, 3) = 2300. Therefore, the probability of picking no red marbles is: 455 / 2300 ≈ 0.1978.
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Suppose that grade point averages of undergraduate students at one university have a bell-shaped distribution with a mean of 2.61 and a standard deviation of 0.45. Using the empirical rule, what percentage of the students have grade point averages that are at least 3.96?
Approximately 0.3% of the students have grade point averages that are at least 3.96.
To determine the percentage of students who have grade point averages that are at least 3.96, we can use the empirical rule (also known as the 68-95-99.7 rule) in conjunction with the given mean and standard deviation of the distribution.
The empirical rule states that for a bell-shaped (normal) distribution:
Approximately 68% of the data falls within one standard deviation of the mean.
Approximately 95% of the data falls within two standard deviations of the mean.
Approximately 99.7% of the data falls within three standard deviations of the mean.
In this case, we want to find the percentage of students who have grade point averages greater than or equal to 3.96. To do this, we need to calculate the z-score corresponding to the GPA of 3.96, and then determine the percentage of data that falls to the right of that z-score.
The z-score formula is:
z = (x - μ) / σ
Where:
x is the value we want to find the z-score for (3.96 in this case),
μ is the mean (2.61),
σ is the standard deviation (0.45).
Calculating the z-score for 3.96:
z = (3.96 - 2.61) / 0.45 ≈ 2.99
Now, let's interpret the z-score:
A z-score of 2.99 indicates that the GPA of 3.96 is approximately 2.99 standard deviations above the mean.
Using the empirical rule, we know that approximately 99.7% of the data falls within three standard deviations of the mean. Since 3.96 is more than three standard deviations above the mean, the percentage of students with GPAs at least 3.96 can be estimated as the percentage of data beyond three standard deviations.
Considering the right tail of the distribution, we can estimate the percentage using the complement of the percentage within three standard deviations. Thus, the percentage of students with GPAs at least 3.96 is approximately:
100% - 99.7% = 0.3%
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The percentage of students with grade point averages that are at least 3.96 is approximately 0.3%.
Give that:
The value o 3.96,
The mean: μ = 2.61,
Standard deviation: σ = 0.45.
To use the empirical rule, to assume that the grade point averages follow a normal distribution.
The empirical rule, also known as the 68-95-99.7 rule, provides approximate percentages of data within certain standard deviations from the mean in a normal distribution.
According to the empirical rule:
Approximately 68% of the data falls within one standard deviation of the mean.
Approximately 95% of the data falls within two standard deviations of the mean.
Approximately 99.7% of the data falls within three standard deviations of the mean.
To find the percentage of students with grade point averages that are at least 3.96, which means to find the percentage of data that falls above this value.
Step 1: Calculate the z-score for 3.96:
Z = (X - μ) / σ
Z = (3.96 - 2.61) / 0.45 ≈ 2.98
Step 2: Find the percentage of data that falls beyond this z-score. Since we are looking for values greater than 3.96, we look at the percentage beyond 2.98 (which is approximately three standard deviations above the mean).
According to the empirical rule, approximately 99.7% of the data falls within three standard deviations of the mean. This means that approximately 100% - 99.7% = 0.3% of the data falls beyond three standard deviations from the mean.
So, the percentage of students with grade point averages that are at least 3.96 is approximately 0.3%.
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how many different positive integer factors does (64)(81)(125) have?.
The product (64)(81)(125) has 140 different positive integer factors.
To find the number of positive integer factors of the product (64)(81)(125), we first need to determine the prime factorization of each number.
64 = 2^6 (as it is 2 multiplied by itself 6 times)
81 = 3^4 (as it is 3 multiplied by itself 4 times)
125 = 5^3 (as it is 5 multiplied by itself 3 times)
Now, let's consider the product (64)(81)(125) = (2^6)(3^4)(5^3). To find the number of different positive integer factors, we use the formula:
(Number of factors of the first prime + 1) * (Number of factors of the second prime + 1) * (Number of factors of the third prime + 1)
In our case, the formula would be:
(6 + 1) * (4 + 1) * (3 + 1) = 7 * 5 * 4
Calculating the result, we get:
7 * 5 * 4 = 140
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how far is 18 from -14 on a number line
Answer:
32
Step-by-step explanation:
add the absolute value of -14 and 18
Can someone please help me out with this. Pls don't just say A, B, C, or D, like i need explanation pls. I am begging you, I cannot fail this
Answer:
-2, 1, and 3 only
Step-by-step explanation:
Because if You look at the graph..
Use a trigonomic ratio to find the value of x
The value of side x in of the right triangle is 4.8 unit.
What is the value of x?The figure is in the image is a right triangle.
Given that;
Angle θ = 40°Adjacent to angle θ = xOpposite to angle θ = 4To determine the value of x, we use trigonometric ratio
Tangent = Opposite / Adjacent
tan( 40 ) = 4 / x
x = 4 / tan( 40 )
x = 4.8
Therefore, the measure of side x is 4.8 units.
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PLEASSSSEE HURRRRY HELLPP
Answer:
I believe your answer for 11. is B! And for 12 its E and C! 13 I think its D I'm not sure though!
a high school has 44 players on the football team. the summary of the players' weights is given in the box plot. approximately, what is the percentage of players weighing less than or equal to 229 pounds?
Approximately 62.5% of the 44 players or 27.75 players, weigh less than or equal to 229 pounds.
Given the information from the box plot, we can estimate the percentage of players weighing less than or equal to 229 pounds. First, we need to find the number of players by dividing the summary of weights by the weight of one player: 44 players. Next, we can estimate the number of players weighing less than or equal to 229 pounds by finding the percentage of the data that is below 229 pounds and multiplying it by the total number of players. Based on the quartiles given in the box plot, we know that 50% of the data is below 214 pounds and 75% of the data is below 253 pounds. We can estimate that approximately 62.5% of the data is below 229 pounds by taking the average of these two values: (50% + 75%) / 2 = 62.5%. So, approximately 62.5% of the 44 players, or 27.75 players, weigh less than or equal to 229 pounds
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Complete Question
a high school has 44 players on the football team. the summary of the players' weights is given in the box plot. approximately, what is the percentage of players weighing less than or equal to 229 pounds?
The box Plot, the minimum weight is 154 pounds. The first quartile Q1 is 159 which 25% of the data. The second Quartile Q2 is 214 which 50% of the data. The third Quartile Q3 is 253 which is 75% and the maximum weight is 268.
Central conservative forces: (a) Consider the force F= r2kr^ : Is this force conservative? Is it central? If it is conservative find the potential energy V(r). For full marks you need to justify your answer and explain any assumptions that you make.
The force F = r^2k(r^) is not conservative because its curl is nonzero. The force is central because it depends only on r and acts along the radial direction. Since it is not conservative, there is no potential energy function V(r) associated with this force
To determine whether the force F = r^2k(r^) is conservative and central, let's analyze its properties.
A force is conservative if it satisfies the condition ∇ × F = 0, where ∇ is the gradient operator. In Cartesian coordinates, the force can be written as F = Fx i + Fy j + Fz k, where Fx, Fy, and Fz are the components of the force in the x, y, and z directions, respectively. The curl of F is given by:
∇ × F = (∂Fz/∂y - ∂Fy/∂z)i + (∂Fx/∂z - ∂Fz/∂x)j + (∂Fy/∂x - ∂Fx/∂y)k.
Calculating the components of F = r^2k(r^):
Fx = 0, since there is no force component in the x-direction.
Fy = 0, since there is no force component in the y-direction.
Fz = r^2kr^.
Taking the partial derivatives, we have:
∂Fz/∂x = ∂/∂x (r^2kr^) = 2rkr^2(∂r/∂x) = 2rkr^2(x/r) = 2xkr^3.
∂Fz/∂y = ∂/∂y (r^2kr^) = 2rkr^2(∂r/∂y) = 2rkr^2(y/r) = 2ykr^3.
Substituting these values into the curl equation, we get:
∇ × F = (2ykr^3 - 2xkr^3)k = 2k(r^3y - r^3x).
Since the curl of F is not zero, ∇ × F ≠ 0, we conclude that the force F = r^2k(r^) is not conservative.
Now let's determine if the force is central. A force is central if it depends only on the distance from the origin (r) and acts along the radial direction (r^).
For F = r^2k(r^), the force is indeed central because it depends solely on r (the magnitude of the position vector) and acts along the radial direction r^. Hence, it can be written as F = Fr(r^), where Fr is a function of r.
Since the force is not conservative, it does not possess a potential energy function. In conservative forces, the potential energy function V(r) can be defined, and the force can be expressed as the negative gradient of the potential energy, i.e., F = -∇V. However, since F is not conservative, there is no potential energy function associated with it.
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PLEASE HURRY FAST ASAP I WILL GIVE BRINLIEST BUT IT HAS TO BE RIGHT!
A group of students was asked about the number of times they had been water-skiing. The data is shown in the histogram.
A histogram titled Water Skiing Trips. The x-axis is labeled Number of Times Water Skiing and has intervals of 1 to 5, 6 to 10, 11 to 15, 16 to 20, and 21 to 25. The y-axis is labeled Frequency and starts at 0 with tick marks every 1 units up to 6. There is a shaded bar for 1 to 5 that stops at 1, for 6 to 10 that stops at 2, for 11 to 15 that stops at 5, for 16 to 20 that stops at 4, and for 21 to 25 that stops at 3.
Which of the following best describes the spread of the data? Explain its meaning in this situation.
The spread of the data in the histogram is uneven or skewed to the right.
What is a histogram?A histogram is a graphical representation of data used to display the distribution of values in a dataset, showing data in bins or intervals along the horizontal axis.
The data distribution in the histogram is uneven or tilted to the right. This suggests that there are fewer students who have gone water skiing less frequently (1 to 5 trips) and more students who have gone water skiing more frequently (11 to 15 trips). The frequency is greatest between 11 and 15 visits, which is reflected by the largest bar in the histogram.
In given problem, the skewed distribution of the given data shows that there are more no. of the students doing water-skiing regularly than those who are doing it less frequently.
This might imply that there is a group of students who are more experienced or enthusiastic about water skiing, and they have gone on more excursions than other students who have gone on less trips. It also implies that the majority of students fall within the 11 to 15 trip period, which might imply a common pattern or trend in the data.
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The best description of the spread of the data is that it is skewed or unevenly distributed.
What is a histogram?A histogram is a graphical representation of data used to display the distribution of values in a dataset, showing data in bins or intervals along the horizontal axis.
Based on the given histogram, the data is not evenly distributed across the five intervals. The majority of students have been water-skiing between 11 and 15 times, with a frequency of 5. There are fewer students who have been water-skiing between 16 and 20 times, with a frequency of 4, and even fewer students who have been water-skiing between 21 and 25 times, with a frequency of 3.
The spread of the data refers to how far apart the values in the dataset are from each other. In this case, the data is not evenly spread across the different intervals. The values in the dataset are more concentrated in the interval of 11 to 15, and less concentrated in the intervals of 1 to 5 and 21 to 25. This indicates that the majority of students have been water-skiing a similar number of times, while fewer students have been water-skiing either a lot or a little.
Therefore, the best description of the spread of the data is that it is skewed or unevenly distributed.
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The complete question is:
A group of students was asked about the number of times they had been water-skiing. The data is shown in the histogram.
A histogram titled Water Skiing Trips. The x-axis is labeled Number of Times Water Skiing and has intervals of 1 to 5, 6 to 10, 11 to 15, 16 to 20, and 21 to 25. The y-axis is labeled Frequency and starts at 0 with tick marks every 1 units up to 6. There is a shaded bar for 1 to 5 that stops at 1, for 6 to 10 that stops at 2, for 11 to 15 that stops at 5, for 16 to 20 that stops at 4, and for 21 to 25 that stops at 3.
Which of the following best describes the spread of the data? Explain its meaning in this situation?
In the United States of America, the Dollar is the main currency. A
dollar is equal to 10 dimes and a dime is equal to 10 cents. Shilpa has
23.20 US dollars in her purse. Which of the following could she have?
Answer:
(if im not wrong) she has 2320cents / 232 dimes
Step-by-step explanation:
1$=10dimes=100cents
therefore, 23.20$=23.20dimes=232dimes=2320cents
i dont know man i hope its right
A bag contains 9 red, 6 green, 3 blue, and 2 yellow balls of the same size. A student chooses a colour and then draws a ball from the bag. If she draws a ball of her choice of colour she wins, if not the teacher wins. Who do you think will be the winner after 24 rounds, the student or the teacher
Answer:
the teacher will win becasue there are less numbers of colors to choose from one of the catagories then there are in total.
Step-by-step explanation:
PLEASE HELP ME For a-d choose yes or no to tell whether the fraction is equivalent to 4.05… A 405/99 B 401/99 C 81/33 D 802/198
B
Because you multiply the denominator by four and see if its close enough than multiply ot by .05
Which of the following is NOT a property of the linear correlation coefficient r? Choose the correct answer below.
A. The value of r measures the strength of a linear relationship. B. The value of r is not affected by the choice of x or y. C. The linear correlation coefficient r is robust. That is, a single outlier will not affect the value of r. D. The value of r is always between - 1 and 1 inclusive.
The statement that is NOT a property of the linear correlation coefficient r is "C.
The linear correlation coefficient r is robust. That is, a single outlier will not affect the value of r."
Correlation coefficient r measures the strength of a linear relationship between two variables. It is the degree to which two variables are related to each other.
The value of the correlation coefficient r is always between -1 and 1 inclusive. The value of r is not affected by the choice of x or y. Hence, the statement B is true.
The correlation coefficient r is not always robust. That is, a single outlier can affect the value of r and can make it appear weaker than it actually is.
Therefore, statement C is not true.The main answer to the question is C.
The linear correlation coefficient r is not robust. It can be affected by a single outlier that can make it appear weaker than it actually is. that explains the properties of linear correlation coefficient r:
Linear correlation coefficient r is a statistical tool used to measure the strength of the linear relationship between two variables. The value of r can range from -1 to +1, and it is used to determine how well one variable predicts the other variable.
The properties of r include its ability to measure the strength of the linear relationship, its independence from the choice of x or y, and its robustness.
The value of r measures the strength of the linear relationship between two variables. The closer the value of r is to -1 or +1, the stronger the linear relationship is between the two variables.
A value of r = 0 indicates that there is no linear relationship between the two variables.The value of r is not affected by the choice of x or y.
This means that it does not matter which variable is labeled as x or y when calculating the correlation coefficient. The resulting value of r will be the same regardless of the labels assigned to the variables.
The linear correlation coefficient r is not always robust. A single outlier can affect the value of r and make it appear weaker than it actually is.
Therefore, it is important to examine the scatterplot of the data to identify any outliers before calculating the correlation coefficient.Finally, the value of r is always between -1 and 1 inclusive. If r = -1, it indicates a perfect negative linear relationship between the two variables. If r = +1, it indicates a perfect positive linear relationship between the two variables. If r = 0, it indicates that there is no linear relationship between the two variables.
Therefore, we can conclude that statement C is not a property of the linear correlation coefficient r.
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-7(-w-1)-2 simplest form
The graph of which function has a y-intercept of 3?
5
4
3
4
-5 -4 -3 -2 -1
2
2
4
5
x
I PT 9
Terrance is designing a garden. He drew this diagram of his garden. Pose a problem using mixed numbers that can be solved using his diagram.
Answer: 2
Step-by-step explanation:
In a Poisson distribution, μ = 4.20. (Round your answers to 4 decimal places.)
What is the probability that x = 0?
What is the probability that x > 1?
In the Poisson distribution, the probability that x = 0 is 0.0150.
The probability that x > 1 is 0.9220.
How to find the probability that x = 0 and x > 1 in a Poisson distribution?The Poisson probability mass function is given by:
P(x; μ) = e^(-μ) * (μ^x)/ x!
where x is the number of events, and μ is the average number of events in a given interval.
For this problem, μ = 4.20.
To find the probability that x = 0, we plug in x = 0 and μ = 4.20:
P(x= 0) = e^(-4.20) * (4.20^0) / 0!
= e^(-4.20) * 1 / 1
= 0.0150
To find the probability that x > 1, we need to use the complement rule. That is:
P(x > 1) = 1 - P(x ≤ 1)
To find P(x ≤ 1), we can use the Poisson cumulative distribution function:
P(x ≤ 1) = P(x=0) + P(x=1)
= [e^(-4.20) * (4.20^0) / 0!] + [e^(-4.20) * (4.20^1) / 1!]
= 0.0150 + 0.0630
= 0.0780
Therefore,
P(x > 1) = 1 - P(x ≤ 1) = 1 - 0.0780 = 0.9220
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Please help me, write the step by step explanation plz?
Answer:
i think the answer is 171,500 i don't know i am trying.
Step-by-step explanation:
first you multiply 35 times 3 you will get 85,750 then you multiply 10 times 2 you will 20 and multiply both of them and you will get 171,500.
d) The given pie chart shows the composition of different materials in a type of cloth in percent. i) Calculate the percentage of each material found in the cloth. ii) Calculate the weight of each material contained by a bundle of 50 kg of cloth. Cotton 90° Nylon 54° Polyester 144° Others 72°
In a bundle of 50 kg of cloth, the weight of each material is:
Cotton: 12.5 kg
Nylon: 7.5 kg
Polyester: 20 kg
Others: 10 kg
To calculate the percentage of each material found in the cloth, we need to convert the given angles in the pie chart into percentages.
i) Calculating the percentage of each material:
Cotton: 90° / 360° * 100% = 25%
Nylon: 54° / 360° * 100% = 15%
Polyester: 144° / 360° * 100% = 40%
Others: 72° / 360° * 100% = 20%
Therefore, the percentage of each material found in the cloth is:
Cotton: 25%
Nylon: 15%
Polyester: 40%
Others: 20%
ii) To calculate the weight of each material contained in a bundle of 50 kg of cloth, we need to multiply the percentage of each material by the total weight.
Weight of Cotton = 25% * 50 kg = 0.25 * 50 kg = 12.5 kg
Weight of Nylon = 15% * 50 kg = 0.15 * 50 kg = 7.5 kg
Weight of Polyester = 40% * 50 kg = 0.40 * 50 kg = 20 kg
Weight of Others = 20% * 50 kg = 0.20 * 50 kg = 10 kg
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Suppose that a category of world class runners are known to run a marathon (26 miles) in an average of 146 minutes with a standard deviation of 11 minutes. Consider 49 of the races. Let x = the average of the 49 races. Part (a) two decimal places.) Give the distribution of X. (Round your standard deviation to two decimal places)Part (b) Find the probability that the average of the sample will be between 144 and 149 minutes in these 49 marathons. (Round your answer to four decimal places.) Part (c) Find the 80th percentile for the average of these 49 marathons. (Round your answer to two decimal places.) __ min Part (d) Find the median of the average running times ___ min
(a)The distribution of X (the average of the 49 races) follows a normal distribution with mean 146 minutes and standard deviation 11 minutes. (b)The probability of the average of the sample being between 144 and 149 minutes is 0.5854.(c)The 80th percentile for the average of these 49 marathons is 157.2 minutes.(d) The median of the average running times is 146 minutes.
Part(a) The distribution of X (the average of the 49 races) follows a normal distribution with mean 146 minutes and standard deviation 11 minutes. Part (b) The probability that the average of the sample will be between 144 and 149 minutes in these 49 marathons can be calculated using the z-score formula: z = (x - mean)/standard deviation
For x = 144, z = (144 - 146)/11 = -0.18
For x = 149, z = (149 - 146)/11 = 0.27,using the z-score table, the probability of the average of the sample being between 144 and 149 minutes is 0.5854 (0.4026 + 0.1828).
Part (c) The 80th percentile for the average of these 49 marathons can be calculated using the z-score formula: z = (x - mean)/standard deviation, For the 80th percentile, z = 0.84 (from z-score table). Therefore, x = 146 + (0.84 * 11) = 157.2 minutes. Part (d) The median of the average running times is 146 minutes. The median is the midpoint of the data which means half of the data is above the median and half of the data is below the median. Therefore, the median of the average running times is equal to the mean.
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Can someone check to see if I got this right?!??
Answer:
yes!
Step-by-step explanation:
hi, that is correct. 3800 is a constant, meaning it is consistent and the initial height of the plane before it starts its descent.
Calculate the area of the figure.
HELP
Answer:
Step-by-step explanation:
A=bh A=7*8 A=56units^2
Answer:
34
Step-by-step explanation:
i think its 34
What is the measure of ABC?
A 44°
B 88°
C 176°
D 92°
Answer: C) 44 degrees
Step-by-step explanation:
44
Which number is closest to total deaths resulting from ladder misuse each year?
Select the best answer:
a. More than 1,000
b. More than 300
c. Less than 100
d. More than 600
Option C is correct. Less than 100 is closest to total deaths resulting from ladder misuse each year.
According to the Consumer Product Safety Commission (CPSC), on average, approximately 300 people die each year in the United States from falls involving ladders.
However, not all of these deaths are due to ladder misuse. In fact, the number of deaths resulting specifically from ladder misuse is likely to be lower. It is estimated that a significant portion of ladder-related fatalities are caused by factors such as overreaching, misusing the ladder, or failing to follow proper safety guidelines.
To reduce the number of deaths and injuries resulting from ladder misuse, it is important to follow safety guidelines and to choose the right ladder for the job, taking into consideration factors such as height, weight, and stability.
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which graph shows the solution to the system of linear equations?
y=-1/3x+1
y=-2x-3
y = -1/3x + 1
y = -2x - 3
We can compare the equations to the graphs and see which graph represents the intersection point of the two equations.
The first equation, y = -1/3x + 1, has a negative slope (-1/3) and a y-intercept of 1.
The second equation, y = -2x - 3, also has a negative slope (-2) and a y-intercept of -3.
Based on the slopes and y-intercepts, we can identify the correct graph by finding the point where the two lines intersect.
Unfortunately, since the graphs are not provided, I am unable to determine which specific graph shows the solution to the system of linear equations. I recommend referring to the graph representation of the equations and identifying the intersection point to determine the correct graph.
Please help , I need help thanks
these are the questions there are five , I need this today
I will give out brainlist
The solution to the inequality problem is represent by the graph attached below.
Graph of InequalitiesTo solve this problem we simply need to use a graphing a calculator to plot the graph of the two inequalities. The points of intersection represents the solution of the graph.
The broken purple line represents the first inequality and the second straight line represents the second inequality.
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can someone help? (look at image)
Answer:
n (-3,0) m (-4,4) l (0,3)
Step-by-step explanation:
I have bad eyesight but I think this is correct