How do you solve A=6,500(1+0.12)^2.6

Answer:

I hope that helps!

x = -4

Answer:

  d)  1/(4e)

Step-by-step explanation:

You want the value of the limit of 1/4f(x)^(1/x) as x approaches -1, where f(x) = x^2·e^(x^2).

The function is continuous and defined at x=-1, so the limit can be evaluated directly.

  \(\lim=\dfrac{1}{4}((-1)^2\cdot e^{(-1)^2})^{(1/-1)}=\dfrac{1}{4}(1\cdot e^1)^{-1}=\boxed{\dfrac{1}{4e}}\)

The hotel should order 39000 bars of soap if the hotel goes through on an average of 750 soaps each week.

In everyday terms, an average is one number chosen to represent a list of numbers; it is often the sum of the numbers divided by the number of numbers in the list (the arithmetic mean).

Average is calculated by dividing the sum of the data by the frequency of the data.

Average=sum ÷ frequency

For example if the average of the data set {1,2,3,5,10}=(1+2+3+5+10)÷5=21÷5=4.2

Now for the given question average is given as 750 bars of soap.

We know that there are 52 weeks in a year.  ∴ frequency=52

Hence sum of all the averages will give the total number of soap ordered by the hotel in a year.

Sum=average × frequency

or, sum=750 × 52

or, sum=39000 bars of soap.

hence the hotel orders 39000 bars of soap in one year.

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Answer:

only god knows

Step-by-step explanation:

because they didn't give us an answer on how many text messages anyone sent

The bank reconciliation shows an adjusted bank balance of Br.5,301.42 and an adjusted ledger balance of Br.4,173.83.

To prepare the bank reconciliation and journal entry for ABC Company based on the given information, we need to compare the transactions recorded in ABC's ledger with the transactions shown in the bank statement. Here's the bank reconciliation:

1. Bank Statement Balance:

Cash on deposit at July 31: Br.4,964.47

2. Adjusted Bank Balance:

Bank Statement Balance: Br.4,964.47

3. Deposit not on the statement: + Br.410.90

(Adjusted Bank Balance: Br.5,375.37)

Erroneously charged check: + Br.79

(Adjusted Bank Balance: Br.5,454.37)

Outstanding checks:

Check 801: - Br.100.00

Check 888: - Br.10.25

Check 890: - Br.294.50

Check 891: - Br.205.00

(Adjusted Bank Balance: Br.4,844.62)

4. Incorrectly charged check: + Br.90

(Adjusted Bank Balance: Br.4,934.62)

5. Collection of interest-bearing note: + Br.500

(Adjusted Bank Balance: Br.5,434.62)

6. Interest earned: + Br.24.75

(Adjusted Bank Balance: Br.5,459.37)

7. Incorrectly recorded check: - Br.90

(Adjusted Bank Balance: Br.5,369.37)

8. Collection fee: - Br.5.00

(Adjusted Bank Balance: Br.5,364.37)

9. NSF check: - Br.50.25

(Adjusted Bank Balance: Br.5,314.12)

10. Service charge: - Br.12.70

(Adjusted Bank Balance: Br.5,301.42)

Adjusted Ledger Balance:

Bank Balance in ABC's Ledger: Br.4,173.83

Reconciled Bank Balance: Br.5,301.42

Reconciled Ledger Balance: Br.4,173.83

Journal Entry:

To record the bank reconciliation, we make the following journal entry:

Debit: Cash (Ledger Balance adjustment) - Br.5,301.42

Credit: Cash (Bank Statement Balance adjustment) - Br.4,964.47

Credit: Miscellaneous Income/Expense - Br.336.95 (the difference between the two balances)

This journal entry ensures that the ledger balance matches the reconciled bank balance by adjusting for the discrepancies identified during the reconciliation process.

The journal entry reflects the necessary adjustments to reconcile the two balances, with a debit to Cash (Ledger Balance adjustment), a credit to Cash (Bank Statement Balance adjustment), and a credit to Miscellaneous Income/Expense to account for the difference.

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Deciding if each statement about a and b is true or false.

a)False

b)True

c)True

d)False

Given:

The quotient of a and b is negative.

a.

If quotient is negative means the dividend or divisor any one is negative so when the quotient b+a is always negative so given statement is false.

b.

The product ab is always negative because if the quotient is negative means either a or b is negative so ab is negative.

So given statement is true.

c.

Either a or b must be negative is true because if no element a or b is not negative we cannot produce a negative quotient hence either a or b must be negative.

d.

The quotient -a+b is negative is false because if the quotient is negative the values of a and b is one positive and one negative the positive number that is b greater than -a in that case the statement is false.

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The five-number summary is: 41, 56, 65, 67, 69.

The box plot that represents the data is: option B.

Correct statement for the shape of the distribution is: B. the distribution is skewed to the left.

The five-number summary is a five data value that describes the distribution of a data set, which include: lower and upper quartiles, minimum and maximum values, and the median of the data.

The five-number summary is used to construct a box plot.

Given the data, 65, 56, 67, 68, 66, 66, 67, 69, 48, 57, 59, 68, 59, 41, 44, the five-number summary for the data is:

This means that the box plot that will represent this data will have a box that ranges between 56 and 67, and the data at both whiskers will be 41 and 69, while the data at the point where the vertical line divides the box would be 65.

Thus, the box plot that represents the data is: option B.

The median is closer to the right of the third quartile/upper quartile, therefore: B. the distribution is skewed to the left.

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Based on the net present value profile, Project H has a higher NPV than Project E.

To compare the net present value (NPV) of Project E and Project H, we need to calculate the present value of cash flows for each project and determine which one has a higher NPV. The cash flow patterns for the two projects are as follows:

Project E:

Initial investment: -$100,000

Cash flows for Year 1: $40,000

Cash flows for Year 2: $50,000

Cash flows for Year 3: $60,000

Project H:

Initial investment: -$120,000

Cash flows for Year 1: $60,000

Cash flows for Year 2: $50,000

Cash flows for Year 3: $40,000

To calculate the present value of cash flows, we need to discount them using an appropriate discount rate. The discount rate represents the required rate of return or the cost of capital for the company. Let's assume a discount rate of 10%.

Using the formula method, we can calculate the present value (PV) of each cash flow and sum them up to obtain the NPV for each project:

For Project E:

PV = $40,000/(1 + 0.10)^1 + $50,000/(1 + 0.10)^2 + $60,000/(1 + 0.10)^3

PV = $36,363.64 + $41,322.31 + $45,454.55

PV = $123,140.50

For Project H:

PV = $60,000/(1 + 0.10)^1 + $50,000/(1 + 0.10)^2 + $40,000/(1 + 0.10)^3

PV = $54,545.45 + $41,322.31 + $30,251.14

PV = $126,118.90

Using the financial calculator method, we can input the cash flows and the discount rate to calculate the NPV directly. By entering the cash flows for each project and the discount rate of 10%, we find that the NPV for Project E is approximately $123,140.50 and the NPV for Project H is approximately $126,118.90.

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Answer:

B)  -1,-4,-7,-10,........

The first five terms

-1,-4,-7,-10,........

Step-by-step explanation:

Explanation:-

Given that the explicit rule

           \(a_{n} = -3n +2\)

Put n=1  

   ⇒ a₁ = -3(1) +2

       a₁  = -1

Put n=2

⇒  a₂ = -3(2)+2

      a₂ = -6+2

     a₂  = -4

Put n=3

  a₃ = -3(3)+2

  a₃ = -9+2

 a₃ = -7

Put n=4

a₄ = -3(4)+2

a₄ = -12+2

a₄ =-10

The first five terms

-1,-4,-7,-10,........

Answer:

20

Step-by-step explanation:

20 percent of 40 is 5

so 20 is d answer

Answer: The answer is -4

If you use the chips to help illustrate your point, here's a good way to explain it:

Let's say that there are five -1 chips and one +1 chip. In order to use chips, you would have to subtract the chips from each other. Put a -1 chip and a +1 chip together and then take them away (as to subtract them). This would leave you with four -1 chips, thus giving you your answer.

Hope this helps!

Answer:

when two different signs are in numbers if +or_ you I'll substruct or +or+ you I'll added ok

Solution :

The test is distributed normally with mean of 72.8 and the standard deviation of 7.3

Finding numerical limits for the D grade.

D grade : Scores below the top 80% and above the bottom 10%.

Let the bottom limit for D grade be \($D_1$\) and the top limit for D grade be \($D_2$\).

First find the bottom numerical limit for a D grade is :

\($P(X<D_1)= 0.10$\)

\($P(X\leq D_1)= 0.10$\)

\($P\left(\frac{X-\mu}{\sigma} \leq \frac{D_1-\mu}{\sigma}\right) = 0.10$\)

\($P\left(Z \leq \frac{D_1-72.8}{7.3}\right) = 0.10$\)    ..........(1)

From (1)

\($\frac{D_1 - 72.8}{7.3} = -1.28$\)

\($D_1 = -1.28(7.3)+72.8$\)

      = 63.45

       ≈ 64

Now the top numerical limit for D grade :

\($P(X>D_2)= 0.80$\)

\($1-P(X\leq D_2)= 0.80$\)

\($P(X\leq D_2)= 1-0.80$\)

\($P(X\leq D_2)= 0.20$\)

\($P\left(\frac{X-\mu}{\sigma} \leq \frac{D_2-\mu}{\sigma}\right) = 0.20$\)

\($P\left(Z \leq \frac{D_2-72.8}{7.3}\right) = 0.20$\)    ..........(2)

From (2)

\($\frac{D_2- 72.8}{7.3} = -0.84$\)

\($D_12= -0.84(7.3)+72.8$\)

      = 66.668

       ≈ 67

Therefore, the numerical limit for a D grade is 64 to 67.

Yes, 7/56 and 6/48 are proportional because 7×48 = 56×6. Therefore, the correct answer is option B.

Given that, a truck needs 7 gallons of fuel to travel 56 miles.

The truck travel 48 miles with 6 gallons of fuel.

Here, the proportion is

7:56::6:48

We know that, the proportion is product of extremes = product of means

7×48 = 56×6

336 = 336

Therefore, the correct answer is option B.

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Answer:

ya the equation divides y as a function of x

The numbered spot at which all the runners will be next to one another is spot 19.

Least Common Multiple is the meaning of the acronym LCM. The lowest number that may be divided by both numbers is known as the least common multiple (LCM) of two numbers. It may also be computed using two or more real numbers.

Starting with the runner on the outside track, the provided parameters are;

The runner covered n₁ = 5 places on the outside track, which is the number of spaces.

Next, the inner runner will traverse n₂ spaces, which equals one space.

The following inner runner will cover n₃ = 3 spaces.

The subsequent runner will traverse n₄ = 2 spaces.

The Lowest Common Multiple, or LCM, of all the runners' speeds or the total number of spaces they cover in the same amount of time, determines where all the runners will be placed next to one another.

LCM(5, 1, 3, 2) = 30 is the LCM of 5, 1, 3, and 2.

Time = 30/ = 6

Consequently, when the first runner has covered 30 places, we have;

Six time units have been expended.

The runner comes to a stop at position 30- (30 -19) = Position 19.

First runner's new destination is Spot 19.

The distance covered simultaneously by runner 2 is 6 x 1 = 6.

The distance covered by two runners running simultaneously equals six spaces.

Second runner's new position: 6 spaces plus spot 13 equals spot 19.

The combined distance covered by the three runners is 6 x 3 = 18.

The distance runner 3 covers 18 spaces simultaneously.

Third runner's new position: 18 spaces + Spot 1 = 19 spaces

Runner 4 covers a distance of 6 x 2 = 12 at the same time.

Distance runner 4 journeys equals 12 spaces

Runner 4's new position is now 12 spaces Plus Spot 7 = Spot 19.

Therefore, all the runners will be next to one another is spot 19.

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Answer:

8

Step-by-step explanation:

a+6=14

a=14-6

a=8

Therefore

8+6=14

The 46th term of the sequence is 324.

We have,

To find the 46th term of the sequence, we need to determine the pattern or rule that generates the terms.

Since the difference between consecutive terms is a constant value of 7, we know that this is an arithmetic sequence with a common difference

of 7.

To find the 46th term, we can use the formula for the nth term of an arithmetic sequence:

a(n) = a(1) + (n - 1) d

where a(1) is the first term, d is the common difference, and n is the term number we want to find.

Using the given information, we have:

a(1) = 9

d = 7

n = 46

Plugging these values into the formula, we get:

a (46) = 9 + (46 - 1)7

a (46) = 9 + 45 (7)

a(46) = 9 + 315

a(46) = 324

Therefore,

The 46th term of the sequence is 324.

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The amount of dry ingredients used in the cake recipe is approximately 7 cups.

To find the total amount of dry ingredients used in the cake recipe, we need to add up the amounts of flour, sugar, and cocoa.

3 ½ cups of flour is equal to 3 cups plus 0.5 cups, or 3 cups and 8 ounces.

2 ⅔ cups of sugar is equal to 2 cups plus 0.67 cups, or 2 cups and 10.72 ounces.

1 ¾ cups of cocoa is equal to 1 cup plus 0.75 cups, or 1 cup and 12 ounces.

Adding these amounts together, we get:

3 cups and 8 ounces + 2 cups and 10.72 ounces + 1 cup and 12 ounces = 6 cups and 14.72 ounces

To the nearest cup, this is equal to 7 cups.

Therefore, the amount of dry ingredients used in the cake recipe is approximately 7 cups.

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Answer:

game show The Price is Right, four contestants are asked to guess the price of a television set. Play starts with the leftmost player, and each player's guess must be different from the guess of the previous players. The person who comes closest to the real price, without going over it, wins the television set.

c.) Six thousand players each pasy $10,000 to enter

The variance of Billy's grades obtained from his test scores is 15.76

The variance is a measure of variability or spread a dataset. The variance can be calculated from the sum of the square of the differences of the data points from the mean divided by the number or count of the data points.

The variance of Billy's test scores can be calculated by finding the mean or the average of the scores, then finding the sum of the squares of the differences of each score from the mean as follows;

The mean score = (89 + 88 + 93 + 90 + 81)/5 = 88.2

The square of the differences of the values from the mean can be calculated as follows;

(89 - 88.2)² = 0.64, (88 - 88.2)² = 0.04, (93 - 88.2)² = 23.04, (90 - 88.2)² = 3.24, and (81 - 88.2)² = 51.84

The sum of the square of the differences is therefore;

0.64 + 0.04 + 23.04 + 3.24 + 51.84 = 78.8

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Answer:

I think its D

Step-by-step explanation:

The dot starts on -2 and decreases so the answer would = -2 or be less than -2 :)

Yes, the ordered pair (4, 7) is a solution of the equation y = 5x - 13.

A linear equation is an algebraic equation of degree one. In general, the variable or the variables(in the case of a linear equation in two variables) the variables are x and y.

To conclude if the ordered pair (4, 7) is a solution of the equation

y = 5x - 13  or not we have to substitute the value of x and check what is the corresponding y value.

So, y = 5x - 13.

At x = 5,

y = 5(4) - 13.

y = 20 - 13.

y = 7.

∴ When x = 4 the corresponding y value is 7 so the given ordered pair

(4, 7) satisfies this condition.

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For part a, you can use a chi-squared test to determine whether the variance in the sample exceeds the maximum acceptable variance in the population.

The null hypothesis for this test is that the variance in the sample is equal to or less than the maximum acceptable variance, and the alternative hypothesis is that the variance in the sample is greater than the maximum acceptable variance.

To perform the test, you need to first calculate the chi-squared statistic, which is given by:

X² = (n-1) * s² / σ²

where n is the sample size (in this case, 15), s is the sample standard deviation (in this case, 0.014 inches), and σ is the maximum acceptable variance (in this case, 0.0001 inches).

Plugging in the values, you get:

X² = (15-1) * .014² / .0001² = 27.44

Next, you need to determine the degrees of freedom for the test. In this case, the degrees of freedom is equal to the sample size minus 1, so the degrees of freedom is 14.

With the chi-squared statistic and the degrees of freedom, you can look up the p-value in a chi-squared table or use a chi-squared calculator to determine the p-value. The p-value is the probability of observing a chi-squared statistic as large or larger than the one you calculated, assuming the null hypothesis is true.

If the p-value is less than the significance level (in this case, .10), then you can reject the null hypothesis and conclude that the variance in the sample exceeds the maximum acceptable variance. In this case, the p-value is between 0.01 and 0.025, so you can reject the null hypothesis and conclude that the variance in the sample exceeds the maximum acceptable variance.

For part b, you can use a t-test to construct a 90% confidence interval estimate of the variance in the population. The confidence interval is an interval estimate of the true variance in the population, and the 90% confidence level means that there is a 90% probability that the true variance in the population falls within the confidence interval.

To construct the confidence interval, you first need to calculate the standard error of the variance, which is given by:

SE = s / √(n-1)

where s is the sample standard deviation and n is the sample size. Plugging in the values, you get:

SE = 0.014 / √(15-1) = 0.0041

Next, you need to determine the t-value for the confidence interval. The t-value is based on the degrees of freedom and the confidence level. With 14 degrees of freedom and a 90% confidence level, the t-value is 1.76.

With the standard error and the t-value, you can construct the confidence interval as follows:

Lower bound = s² - t * SE = .014² - 1.76 * 0.0041 = 0.00012 inches

Upper bound = s² + t * SE = .014² + 1.76 * 0.0041 = 0.00042 inches

Therefore, the 90% confidence interval estimate of the variance of the ball bearings in the population is .00012 to .00042 inches.

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Answer: x=18

im assuming that this is a right angle

so if it is then that means the total of the angle should be 90 degrees. so 2x+3x should be equal to 90. Just combine like terms to get that 5x=90 and then isolate the variable (divide by 5 on both sides) so x ends up equaling 18.

so x=18