how does speed measure​

The final velocity of the 25.8 g marble after the collision is 16.15 cm/s.

The velocity of the 25.8 g marble after the collision is calculated as follows;

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

where;

The final velocity of the 25.8 g marble after the collision is calculated as;

( 25.8 x 21 ) + ( 12.4 x 13.8 ) = ( 12.4 x 23.9 ) + ( 25.8v )

712.92 = 296.36 + 25.8v

25.8v = 416.56

v = 416.56 / 25.8

v = 16.15 cm/s

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Answer:

v₀ₓ = 63.5 m/s

v₀y = 54.2 m/s

Explanation:

First we find the net launch velocity of projectile. For that purpose, we use the formula of kinetic energy:

K.E = (0.5)(mv₀²)

where,

K.E = initial kinetic energy of projectile = 1430 J

m = mass of projectile = 0.41 kg

v₀ = launch velocity of projectile = ?

Therefore,

1430 J = (0.5)(0.41)v₀²

v₀ = √(6975.6 m²/s²)

v₀ = 83.5 m/s

Now, we find the launching angle, by using formula for maximum height of projectile:

h = v₀² Sin²θ/2g

where,

h = height of projectile = 150 m

g = 9.8 m/s²

θ = launch angle

Therefore,

150 m = (83.5 m/s)²Sin²θ/(2)(9.8 m/s²)

Sin θ = √(0.4216)

θ = Sin⁻¹ (0.6493)

θ = 40.5°

Now, we find the components of launch velocity:

x- component = v₀ₓ = v₀Cosθ  = (83.5 m/s) Cos(40.5°)

v₀ₓ = 63.5 m/s

y- component = v₀y = v₀Sinθ  = (83.5 m/s) Sin(40.5°)

v₀y = 54.2 m/s

The net force of the object using the free body diagram above is 12N, right (option D).

Net force is defined as the sum of all the forces acting on an object. Net force can accelerate a mass. Some other force acts on a body either at rest or motion.

The net force is a term used in a system when there is a significant number of forces.

Fnet = F¹+ F² + F³….+ Fn

Where;

F¹, F², F³…Fn are the forces acting on a body

According to this question, a stationary object is given with forces 8N and 10N acting rightward, then force 6N acting leftward.

Fnet = (8 + 10) - 6

Fnet = 18 - 6 = 12N

Therefore, the net force is 12N to the right because it is an unbalanced force.

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When the teacher asked the student to make words out of the jumbled word gzeysktqix, the student was being tested on his ability to unscramble words. Unscrambling words is the process of taking a word or series of letters that are out of order and rearranging them to form a word that makes sense.

When trying to unscramble a word, it is important to look for any patterns that can help identify smaller words within the jumbled letters. This can help make the process easier and quicker. For example, in the jumbled word gzeysktqix, one might notice that the letters "sktqix" appear together.

This could indicate that these letters could potentially form a word. By looking at the remaining letters, one could notice that the letters "g", "z", "e", and "y" could also form smaller words. After some rearranging, the letters can be unscrambled to form the words "sky", "zig", "sex", and "yet". These are just a few examples, as there are likely many other words that can be formed from this jumbled word.

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According to Doerbecker and Ernst (1996) and Francart et al. (2011), interaural time difference (ITD) and interaural level difference (ILD) are the two primary auditory cues used by binaural hearing. The delay between each ear is known as ITD.

What technique best localizes sound between the two ears?

Rayleigh's view of horizontal sound localization has come to be known as the “duplex” theory: that sound localization at low frequencies relies on differences in phase at the two ears, or ITDs, and that high-frequency localization relies on interaural differences in sound level (ILDs).

What two variables affect sound localization?

The variation in the loudness of the sound in each ear and the time it took for the sound to reach each ear are two elements that affect how the sound is localized.

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The distance between two objects of radius 6 cm and 2 cm is zero

To find the distance between two objects with radii of 6 cm and 2 cm, we need to consider the center-to-center distance between the objects and subtract the sum of their radii.

Let's denote the radii of the objects as r1 = 6 cm and r2 = 2 cm.

The distance between the centers of the objects can be represented as d = r1 + r2. Adding the radii ensures that we account for the space occupied by both objects.

Substituting the values, we have d = 6 cm + 2 cm = 8 cm.

Now, to find the actual distance between the objects, we subtract the sum of their radii from the center-to-center distance:

Distance = d - (r1 + r2) = 8 cm - (6 cm + 2 cm) = 8 cm - 8 cm = 0 cm.

The resulting distance is 0 cm, indicating that the objects are in direct contact with each other. This means that their surfaces are touching. When the distance between two objects is zero, it implies that they are overlapping or in physical contact. In this case, since the distance is equal to 0 cm, the two objects are touching each other, with their surfaces coming into contact.

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Since the electron and proton are charged particles, they will experience a force due to their mutual Coulombic attraction. The direction of the force on each particle will be opposite to the direction of the other particle.

Since the electron is negatively charged and the proton is positively charged, the force on the electron will be in the direction of the proton (to the right), and the force on the proton will be in the direction of the electron (to the left).

Since the electron has a much smaller mass than the proton, it will experience a larger acceleration in response to the force. This means that the electron will accelerate to the right, in the direction of the proton.

Answer:

The velocity of the box is related to the angular velocity of the spool, which is given by the equation:

v = r * ω

where r is the radius of the spool and ω is the angular velocity of the spool. The angular velocity of the spool, in turn, is related to the torque applied to the spool by the tension in the string, which is given by the equation:

τ = I * α

where τ is the torque, I is the moment of inertia of the spool, and α is the angular acceleration of the spool.

The tension in the string is equal to the weight of the box, which is given by:

T = m * g

Putting all of these equations together, we can solve for the time it takes for the box to reach the floor. Here's how:

First, we can find the angular acceleration of the spool using the torque equation:

τ = I * α

T = m * g = τ

m * g = I * α

α = (m * g) / I

α = (35.30 kg * 9.81 m/s^2) / 4.00 kg*m^2

α = 86.53 rad/s^2

Next, we can find the angular velocity of the spool using the kinematic equation:

ω^2 = ω_0^2 + 2 * α * θ

where ω_0 is the initial angular velocity (which is zero), θ is the angle through which the spool has turned (which is equal to the distance the box has fallen divided by the radius of the spool), and ω is the final angular velocity (which is what we want to find). Solving for ω, we get:

ω^2 = 2 * α * θ

ω = sqrt(2 * α * θ)

ω = sqrt(2 * 86.53 rad/s^2 * (3.50 m / 0.10 m))

ω = 166.6 rad/s

Finally, we can find the time it takes for the box to reach the floor using the equation:

v = r * ω

v = 0.10 m * 166.6 rad/s

v = 16.66 m/s

t = d / v

t = 3.50 m / 16.66 m/s

t = 0.21 s

A beaver runs at a speed of 2.0 m/s with 45 J of kinetic energy, then the mass is approximately 1.74 kg, and this can be calculated by using the  kinetic energy (KE) of an object that is KE = (1/2) ×m × \(v^2\).

KE = (1/2) ×m × \(v^2\).

where m= mass of the object, v=its velocity.

The beaver runs at a speed of 2.0 m/s with 45 J of kinetic energy. Substituting these values into the above equation

45 J = (1/2) ×m × \((2.0 m/s)^2\)

Simplifying this equation:

45 J = (1/2) × m × 4.0\(m^2/s^2\)

45 J = 2 m × 2 \(m^2/s^2\)

45 J = 4 \(m^3/s^2\)

\(m^3\) = 45 J / 4 \(s^2\)

\(m^3\) = 11.25 kg×\(m^2/s^2\)

Taking the cube root of both sides to solve for mass,

m = (11.25 kg×\(m^2/s^2)^(^1^/^3^)\)

m = 1.74 kg (rounded to two decimal places)

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Answer:

228.23m

Explanation:

Vy=59sin70=55.44m/s

x=V0t+1/2at^2

0=55.44t-4.9t^2

t=11.31s

Vx=59cos70=20.18m/s

Range=20.18*11.31=228.23m

Answer:

Seconds

Explanation:

Hope it helps you in your learning process.

The rate of flow of charge (per second) through a conductor is called electric current.

S. I unit of electric current is Ampere (named after French Physicist Andre Marie Ampere)

Answer:

hanglider

Explanation:

i made something for this exact experiment in highschool, got first place, when people go sky divining they use a specific king of parachute because the design is supposed to slow the fall and give them a chance to make a safe landing, it also matters what you carry the egg in so something cushioned since it is an egg, use the fabric and cut the paper bag to make the kind of parachute i mentioned before

Given:

The resistance of the resistors, R₁=4 Ω

And R₂=3 Ω

And R₃=5 Ω

The current in the circuit is I=0.1 A

To find:

The potential difference in the circuit.

Explanation:

All the resistors are connected in series with the battery. The equivalent resistance of the resistors connected in the series is given by,

On substituting the known values,

From Ohm's law, the potential difference of the circuit is directly proportional to the current in the circuit.

Thus,

On substituting the known values,

Final answer:

The potential

Answer:

a). 1.28333 seconds

b). 186.66 seconds

Explanation:

a). Given :

Distance between the earth and the moon, d = \($3.85 \times 10^8$\) m

Speed of the radio waves, c = \($3 \times 10^8$\) m/s

Therefore the time required for the voice of Neil Armstrong to reach the earth via radio waves is given by :

\($t=\frac{d}{c}$\)

 \($=\frac{3.85 \times 10^8}{3 \times 10^8}$\)

 = 1.28333 seconds

b). Distance between Mars and the earth, d = \($5.6 \times 10^{10}$\) m

   Speed of the radio waves, c = \($3 \times 10^8$\) m/s

So, the time required for his voice to reach earth is :

\($t=\frac{d}{c}$\)

 \($=\frac{5.6 \times 10^{10}}{3 \times 10^8}$\)

 = 186.66 seconds

Answer:

This problem involves the concept of a random walk, which is a mathematical model of a path consisting of a succession of random steps.

The question asks for the distance, R(n), from the center of a star after n steps of a photon, assuming a 2D random walk.

The random walk in two dimensions has a step length of A_i and the direction of the steps is uniformly distributed in [0, 2π). The change in position after each step can be written in Cartesian coordinates (Δx, Δy), where Δx = A_i cos(θ_i) and Δy = A_i sin(θ_i).

The displacement from the center after n steps is given by the vector sum of all the individual steps. This vector sum can be written in terms of its Cartesian coordinates, (X, Y), where X = Σ Δx and Y = Σ Δy. This sum over n random vectors is itself a random variable. The net displacement R(n) from the center of the star after n steps is given by the magnitude of the net displacement vector:

R(n) = √(X² + Y²)

Because each step is independent and has a random direction, the expected value of the cosine and sine for any step is zero. This means that the expected values of X and Y are both zero.

However, the mean square displacement is not zero. Because the steps are independent, the mean square displacement in each direction is additive. For a 2D random walk:

<X²> = Σ <(Δx)²> = n <(A cos θ)²> = n A²/2

<Y²> = Σ <(Δy)²> = n <(A sin θ)²> = n A²/2

Because <X²> = <Y²>, we can write:

<R²> = <X²> + <Y²> = n A²

So, the root mean square distance (the square root of the mean square displacement) after n steps is:

R(n) = √(<R²>) = √(n) * A

Therefore, the distance R(n) that the photon is expected to be from the center of the star after n steps grows as the square root of the number of steps, with each step having a length A. Please note that this result holds for a 2D random walk. A real photon in a star would be performing a 3D random walk, which would have slightly different characteristics.

The time it takes for blood to travel from the aorta to the capillaries is 20 seconds. This can be calculated using the equation: t = v₁ - v₂ / a , where v₁ is the initial velocity (10 cm/s), v₂ is the final velocity (0.5 mm/s), and a is the acceleration (0.4 cm/s²). Therefore, t = 10 cm/s - 0.5 mm/s / 0.4 cm/s² = 20 s.

The cart starts from rest at the top of a 100 m high hill.

The track is frictionless, so all initial gravitational potential energy will convert to kinetic energy.

The gravitational potential energy at the top is: PE = mgh

PE = (mass of cart) x (gravitational field strength) x (height)

= mc x g x 100

= mc x 10 x 100 = mc x 1000 Joules (assuming g = 10 m/s^2)

All this potential energy converts to kinetic energy at the bottom:

KE = 1/2mv^2

KE = PE

1/2mv^2 = mc x 1000

v = sqrt(2 x 1000/m) = sqrt(2000/m)

For the cart to clear the top of the circular loop of radius r, its velocity must be:

v >= 2πr/T

where T is the time period of one revolution.

Equating the velocity equations from step 4 and 5:

sqrt(2000/m) >= 2πr/T

Solving for the maximum radius r:

r <= (m/2000) x (T x sqrt(2000/m))^2

= (m/2000) x (T x sqrt(2000))

= mT^2/2000

So the maximum radius of the loop that the cart can clear without slipping is directly proportional to the mass of the cart and the square of the time period of one revolution.

the kinetic energy of an object that has a mass of 30 kilograms and moves with a velocity of 20 m/s is  6,000 J. Option C is correct answer.

The kinetic energy of an object that has a mass of 30 kilograms and moves with a velocity of 20 m/s can be calculated by using the formula:

K.E = 1/2 mv²

Where, K.E = Kinetic energy of the objectm = Mass of the objectv = Velocity of the object

Putting the given values in the above formula:

K.E = 1/2 mv²K.E = 1/2 × 30 kg × (20 m/s)²K.E = 1/2 × 30 × 400K.E = 6000 joules

The correct answer is C.

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Answer:

Different Kinds of Atoms

Description. Atoms are made of tiny particles called protons, neutrons and electrons. ...  

Stable. Most atoms are stable. ...  

Isotopes. Every atom is a chemical element, like hydrogen, iron or chlorine. ...  

Radioactive. Some atoms have too many neutrons in the nucleus, which makes them unstable. ...  

Ions. ...  

Antimatter.

Explanation:

Answer:

\(\huge\boxed{\sf P.E. = 39.2\ Joules}\)

Explanation:

Given Data:

Mass = m = 4 kg

Acceleration due to gravity = g = 9.8 m/s²

Height = h = 1 m

Required:

Potential Energy = P.E. = ?

Formula:

P.E. = mgh

Solution:

P.E. = (4)(9.8)(1)

P.E. = 39.2 Joules

\(\rule[225]{225}{2}\)

Hope this helped!

Answer:

confounding cause they had exposure to many programmes

Answer:

Confounding should be your answer please mark brainliest

Answer: It takes 12 N of force to pull the wagon.

Explanation:

Answer:

software calculator is a calculator that has been implemented as a computer program, rather than as a physical hardware device. They are among the simpler interactive software tools, and, as such, they: Provide operations for the user to select one at a time.

Answer: The calculator is a compact portable device that performs mathematical calculations. Some calculators also allow easy text editing and programming. It's also a programming software that simulates a portable calculator. Calculator applications help you make basic math calculations without leaving your screen.

Answer:

\(a=-0.001388\ m/s^2\)

Explanation:

Given that,

Initial speed of a train, u = 2.5 m/s

Finally, it reaches the station, v = 0 (at rest)

Time, t = 30 minutes = 1800 s

Acceleration is equal to the rate of change of velocity. So,

\(a=\dfrac{v-u}{t}\\\\a=\dfrac{0-2.5}{1800}\\\\a=-0.001388\ m/s^2\)

So, its acceleration is \(0.001388\ m/s^2\).

Answer:

Explanation:

The light coming from source will be falling on the periphery of the mirror at an angle of θ where

tanθ = .17 / .72

= 17 / 72

angle of reflection will also be θ . The reflected light will fall on the ceiling at a distance d from a point just above the point where the incident light falls .

d / 2.8 = tanθ

d = 2.8 x 17 / 72

= .66 m

radius of the circular spot on the ceiling

= .66 + .17

= .83 m

diameter = 2 x .83

= 1.66 m

The flat circular radius of 0.170m is lying on the floor and is dorecly inthe center of the mirror and has a height of 0.702m and is a small light source.

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Answer:

24 m/s

Explanation:

V=Vi+at

given initial velocity is 0, acceleration is 2 and time is 12 sec

find final velocity by plugging in the variables into the equation above.

V=0+2x12=24m/s

Answer:

19

Explanation:

I legit did this and it took 19.