how does the value of g on the earth is related to the mass of the earth and its radius drive it ​

(a)

pH = 4.77

; (b)

[

H

3

O

+

]

=

1.00

×

10

-4

l

mol/dm

3

; (c)

[

A

-

]

=

0.16 mol⋅dm

-3

Explanation:

(a) pH of aspirin solution

Let's write the chemical equation as

m

m

m

m

m

m

m

m

l

HA

m

+

m

H

2

O

⇌

H

3

O

+

m

+

m

l

A

-

I/mol⋅dm

-3

:

m

m

0.05

m

m

m

m

m

m

m

m

l

0

m

m

m

m

m

l

l

0

C/mol⋅dm

-3

:

m

m

l

-

x

m

m

m

m

m

m

m

m

+

x

m

l

m

m

m

l

+

x

E/mol⋅dm

-3

:

m

0.05 -

l

x

m

m

m

m

m

m

m

l

x

m

m

x

m

m

m

x

K

a

=

[

H

3

O

+

]

[

A

-

]

[

HA

]

=

x

2

0.05 -

l

x

=

3.27

×

10

-4

Check for negligibility

0.05

3.27

×

10

-4

=

153

<

400

∴

x

is not less than 5 % of the initial concentration of

[

HA

]

.

We cannot ignore it in comparison with 0.05, so we must solve a quadratic.

Then

x

2

0.05

−

x

=

3.27

×

10

-4

x

2

=

3.27

×

10

-4

(

0.05

−

x

)

=

1.635

×

10

-5

−

3.27

×

10

-4

x

x

2

+

3.27

×

10

-4

x

−

1.635

×

10

-5

=

0

x

=

1.68

×

10

-5

[

H

3

O

+

]

=

x

l

mol/L

=

1.68

×

10

-5

l

mol/L

pH

=

-log

[

H

3

O

+

]

=

-log

(

1.68

×

10

-5

)

=

4.77

(b)

[

H

3

O

+

]

at pH 4

[

H

3

O

+

]

=

10

-pH

l

mol/L

=

1.00

×

10

-4

l

mol/L

(c) Concentration of

A

-

in the buffer

We can now use the Henderson-Hasselbalch equation to calculate the

[

A

-

]

.

pH

=

p

K

a

+

log

(

[

A

-

]

[

HA

]

)

4.00

=

−

log

(

3.27

×

10

-4

)

+

log

(

[

A

-

]

0.05

)

=

3.49

+

log

(

[

A

-

]

0.05

)

log

(

[

A

-

]

0.05

)

=

4.00 - 3.49

=

0.51

[

A

-

]

0.05

=

10

0.51

=

3.24

[

A

-

]

=

0.05

×

3.24

=

0.16

The concentration of

A

-

in the buffer is 0.16 mol/L.

hope this helps :)

The equilibrium constant of this reaction is 1.80×10-5

Given data,

pH of solution = 2.873

Number of moles of acetic acid (m) = 0.05 moles

Volume of water (V) =  500 mL = 0.5L

So, concentration (C) = m/V in lit = 0.05/0.5 = 0.1 M

Equilibrium constant ( K ) = \([CH_{3} COO-]\)×\([H+_{} ]\)/\([CH_{3} COOH]\)

Since, acetic acid is weak acid,

So, Equilibrium constant ( K ) = \([H+]^{2}\)/\([CH_{3} COOH]\)   ....(i)

As the pH = 2.873, the \([H+_{} ]\) is antilog of -2.873 or 1.34×10-3 M.

Putting the value of concentration of \(H+_{}\) and \(acetic_{} acid\) in equation (i).

Equilibrium constant ( K ) = 1.80×10-5

The acid which is partially dissociates into ions on dissolving in aqueous solution is called weak acid.

Example: \(acetic_{} acid\).

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Answer:

OA. YESS

Explanation:

They will because they are all over America.

The one factor that often most dramatically influences the rate of SN2 (substitution nucleophilic bimolecular) reactions is steric hindrance.

SN2 reactions involve the attack of a nucleophile on a substrate, which displaces a leaving group in a single step. In an SN2 reaction, the nucleophile approaches the substrate from the opposite side of the leaving group, which means that the steric hindrance of the substrate can significantly impact the reaction rate. A substrate with bulky groups attached to the carbon atom that is being attacked by the nucleophile will experience more steric hindrance and hinder the approach of the nucleophile, which slows down the reaction rate. Similarly, a substrate with a small leaving group will undergo SN2 reactions more rapidly than a substrate with a large leaving group, as the large leaving group can experience more steric hindrance. In summary, steric hindrance plays a crucial role in SN2 reactions, and a substrate with high steric hindrance will have a slower reaction rate compared to a substrate with low steric hindrance.

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Explanation:

evaporation is a process in which water starts boiling at 100 degree Celsius and from liquid state it changes to gaseous state. and it's a physical change of water

hope this helps you

have a great day :)

The solubility product constant (Ksp) is a measure of the solubility of a sparingly soluble salt. A larger Ksp value indicates a higher solubility of the salt in water.

Comparing the Ksp values given, we can see that \(PbCl_{2}\) has the largest Ksp value (1.6 x \(10^-5\) ) among the three lead salts. This means that \(PbCl_{2}\) has the highest solubility among the three salts at 25 degrees Celsius.

On the other hand, Pbi2 has a much smaller Ksp value (1.4 x 10^-8), indicating that it has a much lower solubility in water at 25 degrees Celsius. \(Pb(OH)_{2}\) has an even smaller Ksp value (1.2 x 10^-15), making it the least soluble of the three salts.

It is important to note that factors such as temperature, pressure, and pH can also affect the solubility of a salt. However, based on the given information, we can conclude that \(PbCl_{2}\) would be the most soluble of the three lead salts in water at 25 degrees Celsius.

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Explanation:

Answer:

It is a metal

Explanation:

The correct option is b, It has a hydronium ion concentration that is higher than pure water itself.

When the pH of a solution is less than 7, it indicates that the solution is acidic. The pH scale is a logarithmic scale that measures the concentration of hydronium ions (H3O+) in a solution.

A pH below 7 indicates an excess of hydronium ions compared to pure water.

In an acidic solution, the hydronium ion concentration is higher than the concentration of hydroxide ions (OH-). This is because the concentration of hydronium ions is related to the acidity of a solution, while the concentration of hydroxide ions indicates its alkalinity.

The lower the pH, the higher the concentration of hydronium ions and the lower the concentration of hydroxide ions.

Option a is incorrect because a pH less than 7 corresponds to a hydronium ion concentration greater than 1 x 10-7, which is the concentration of hydronium ions in neutral water (pH 7).

Option c is incorrect because in an acidic solution, the concentration of hydroxide ions is lower than the concentration of hydronium ions.

Option d is not necessarily true. The requirement for a buffer solution depends on the specific needs of the system and is not solely determined by the pH of the solution.

Option e is incorrect because a solution with a pH less than 7 is considered acidic, not basic. Basic solutions have a pH greater than 7.

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The pH of the resulting buffer is 4.446.

To find the pH of the resulting buffer, we need to first determine the moles of weak acid and moles of NaOH that have been added to the solution.

Moles of weak acid = (0.200 mol/L) x (0.525 L) = 0.105 mol

Moles of NaOH = (0.150 mol/L) x (0.500 L) = 0.075 mol

Next, we need to determine the moles of weak acid and moles of conjugate base (A-) in the buffer solution.

Since the weak acid is in excess, all of the NaOH will be neutralized by the weak acid to form its conjugate base.

Moles of A- = 0.075 mol

Moles of HA remaining = 0.105 mol - 0.075 mol = 0.03 mol

The initial concentration of weak acid was 0.200 M, so its initial moles were:

Initial moles of HA = (0.200 mol/L) x (0.525 L) = 0.105 mol

The final volume of the solution after mixing the two solutions together is:

Final volume = 0.500 L + 0.525 L = 1.025 L

Using the Henderson-Hasselbalch equation, we can find the pH of the resulting buffer:

pH = pKa + log([A-]/[HA])

pKa = -log(Ka) = -log(8.59×10−5) = 4.066

[A-]/[HA] = 0.075 mol/0.03 mol = 2.5

pH = 4.066 + log(2.5) = 4.446

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None of the given options are correct. This calculation suggests that the molecular weight of the gas is much larger than the options provided. It is possible that there was an error in the measurement of the density or the problem was intended to be more complex.

To calculate the molecular weight of a gas with a given density at STP, we need to use the Ideal Gas Law equation PV=nRT and rearrange it to solve for the molecular weight. At STP, the pressure (P) is 1 atm and the temperature (T) is 273.15 K.
First, we need to find the molar volume of the gas at STP, which is 22.4 L/mol. Then, we can use the density (d) and the molar volume (V) to calculate the number of moles (n) using the formula n = d/V.
n = 1.524 g/L / 22.4 L/mol = 0.068 mol
Next, we can use the formula n = m/M, where m is the mass of the gas and M is the molecular weight we want to find. Since we know the density and the molar volume, we can find the mass of the gas using the formula m = dV.
m = 1.524 g/L x 22.4 L/mol = 34.13 g/mol
Now we can plug in the values for n and m in the formula n = m/M and solve for M.
0.068 mol = 34.13 g/mol / M
M = 34.13 g/mol / 0.068 mol = 501.9 g/mol

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energy of the photon = 18 ev

energy of the atom after it absorbs the photon,

=(-20 +18) ev = -2ev

the electron moves from level n=1 to n=4.

possible energies of the emitted photons: 3.0 ev, 5.0 ev, 8.0 ev, 10 ev, 15 ev, 18 ev

An electron is a negatively charged subatomic particle that can be both sure to an atom or free.

An electron that is sure to an atom is one of the 3 number one types of particles inside the atom -- the opposite  are protons and neutrons. Collectively, electrons, protons and neutrons form an atom's nucleus.

The hydrogen atom, as an example, has simply one electron and one proton. The uranium atom, alternatively, has 92 protons, and therefore, 92 electrons.

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Answer:

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

\(volume = \frac{mass}{density} \\\)

From the question

mass of metal = 300 g

density = 7.13 g/mL

We have

\(volume = \frac{300}{7.13} \\ = 42.07573632...\)

We have the final answer as

Hope this helps you

Answer:

independent variable is how it changes how it affects something else dependent variable is something being measured

Answer: An independent variable is the variable which is changed by the scientist also called the manipulated variable. The dependent variable is the result of the action of the independent variable. it is the factor that changes due to the independent variable. It is also known as the responding variable.

Explanation

The cell potential for the given reaction at 25°C is -0.66 V, which corresponds to option (c).

The cell potential for the given electrochemical cell can be calculated using the Nernst equation:

Ecell = E°cell - (RT/nF) * ln(Q)

where:

E°cell is the standard cell potential

R is the gas constant (8.314 J/mol·K)

T is the temperature in Kelvin (25°C = 298 K)

n is the number of electrons transferred in the balanced redox reaction

F is the Faraday constant (96,485 C/mol)

Q is the reaction quotient, which is the ratio of product concentrations to reactant concentrations, each raised to their stoichiometric coefficients.

In this case, the balanced redox reaction is:

Sn(s) + 2Ag+(aq) → Sn2+(aq) + 2Ag(s)

The standard reduction potentials for the half-reactions involved can be found in tables, and the standard cell potential can be calculated as:

E°cell = E°reduction (cathode) - E°oxidation (anode)

E°cell = (+0.80 V) - (-0.14 V) (from tables)

E°cell = +0.94 V

To calculate the reaction quotient, we can use the concentrations given in the problem and the stoichiometry of the balanced reaction:

Q = [Sn2+(aq)] / [Ag+(aq)]^2

Q = (0.022 M) / (2.7 M)^2

Q = 0.000915

Now we can substitute the values into the Nernst equation and solve for Ecell:

Ecell = E°cell - (RT/nF) * ln(Q)

Ecell = +0.94 V - (8.314 J/mol·K / (2 * 96,485 C/mol) * ln(0.000915))

Ecell = -0.66 V

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The correct answer is (b) +1.01 V. The cell potential can be calculated using the Nernst equation: Ecell = E°cell - (RT/nF) ln(Q)

Nernst equation: Ecell = E°cell - (RT/nF) ln(Q), where E°cell is the standard cell potential, R is the gas constant, T is the temperature in kelvins, n is the number of electrons transferred in the balanced equation, F is the Faraday constant, and Q is the reaction quotient.

In this case, the balanced equation for the cell reaction is:

Sn(s) + 2 Ag+(aq) → Sn2+(aq) + 2 Ag(s)

The standard reduction potentials for Sn2+(aq) and Ag+(aq) are -0.14 V and +0.80 V, respectively. Thus, the standard cell potential can be calculated as:

E°cell = E°red, cathode - E°red, anode

= (+0.80 V) - (-0.14 V)

= +0.94 V

To calculate Q, we need to use the concentrations of the species in the half-cells. The concentration of Sn2+(aq) is given as 0.022 M, and the concentration of Ag+(aq) is given as 2.7 M. Thus:

Q = [Sn2+(aq)] / [Ag+(aq)]

= 0.022 / 2.7

= 0.0081

Substituting the values into the Nernst equation gives:

Ecell = E°cell - (RT/nF) ln(Q)

= +0.94 V - (0.0257/2) ln(0.0081)

= +1.01 V

Therefore, the cell potential for the given reaction is +1.01 V.

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Answer:

the answer is 4

Explanation:

i took the test and got it right and i would recommend using quizlet it has these flash cards and the answers are there you just click on the one that says your question and it will say your answer on the back. It helps with most of my test! Hope this helps (:

The molecular geometry (form) of CCl4 SF6 is identical to the configuration of the electron domains in a VSEPR.

VSEPR distinguishes between molecular geometry, which defines how the atoms in a molecule are ordered, and electron group geometry, which expresses how electron groups (bonds and nonbonding electron pairs) are arranged.

Chemistry frequently employs the valence-shell electron-pair repulsion (VSEPR) model to foretell the three-dimensional organization, or geometry, of molecules. This model accounts for the repulsion between electron pair to estimate the structure of a molecule.

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Answer:

d

because the water takes more space and weighs more in a space because marbles are bulky

Answer:

9

Explanation:

(alt + F4) might be the answer you are looking

Explanation:

I'm not exactly sure how I came up with this answer but it is for sure the answer

road transport

hope it helps...!!!

Answer:

1. road

2. It evenly

3. system, subsystem, componet

4. control

5. combustion.

Hope this is helpful

Answer:

Cobalt

Explanation:

The number of protons in an atom is called the atomic number.

Atomic number of an element is used by chemists to determine the element. The periodic table for example is based on the atomic number of elements.

Since both given elements have a proton number of 27, they are both the same element.

We simply check the periodic table for the element whose atomic number corresponds to this.

  The element here is Cobalt.

What differs between the two of them is that they are different isotopes.

The rate at which reactants change into products is known as the rate of reaction or reaction rate. It goes without saying that the rate at which chemical reactions take place varies greatly. Here the rate of the reaction increases with an increase in temperature.

The collision theory states that chemical reactions at higher temperatures produce more energy than those at lower temperatures. This is because more successful collisions will occur at high temperatures where colliding particles will have the necessary activation energy.

When the temperature increases to 100° C, the reaction between zinc and hydrogen occurs fastly to produce hydrogen chloride. Chemical reactions that are temperature-independent include those lacking an activation barrier.

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The equilibrium constant of the reaction from the calculation that has been done is 0.154

The concentrations (or partial pressures) of reactants and products in chemical equilibrium for a specific chemical reaction are related by the equilibrium constant (K), a mathematical equation. It quantifies the degree to which an equilibrium has been reached in a reaction.

We have the equation of the reaction as;

A(g) + B(g) ⇔C(g)

Thus;

Keq = 45.83/11.23 * 26.50

Keq = 0.154

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A Bronsted-Lowry acid-base is a molecule or ion that donates a hydrogen ion in a reaction.

Brainliest Please?

Answer:

acid

Explanation:

Answer:

22

Explanation:

when a cell goes through mitosis, it duplicates the amount of its subcellular structures, so it will create 2 more clones. So before it was 20, but one goes through mitosis and preduces two more daughter cells, meaning 22.

Answer:

22

Explanation:

its 22

The concentration of the original solution is 15.63 M.

The original solution concentration can be found using the formula

\(C_1V_1 = C_2V_2,\)

where \(C_1\) is the original solution concentration,

\(V_1\) is the volume of the original solution,

\(C_2\) is the concentration of the sample solution, and \(V_2\) is the volume of the sample solution.

In this case,

\(C_1\)= (2.50 M)(100.0 ml) / (16.0 ml)

\(C_1\) = 15.63 M

Therefore, the concentration of the original solution is 15.63 M.  

\(C_1V_1 = C_2V_2,\) is based on the principle of conservation of mass, which ensures that the total number of solute particles remains constant when a solution is diluted or concentrated.

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Answer:

decreases

Explanation:

More molecules have lower speeds and fewer molecules have higher speeds, and the distribution shifts toward lower speeds overall, that is, to the left.

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-SGO

CO2 - Covalent

FeCl3 - Ionic

LiBr - Ionic

C2H4 - Covalent

NaCl - Ionic

SO3 - Covalent

KCl - ionic

P2O5 - Covelent

Ionic compounds are compounds consisting of positively charged ions (cations) and negatively charged ions (anions) held together by ionic bonds. They typically have high melting and boiling points, are crystalline solids at room temperature, and are good conductors of electricity when dissolved in water or melted.

The covalent compounds on the other had are not made up of the ions and they are the ones that are not soluble in water.

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The ionization constant of H₂S is approximately 1.0 x 10⁻⁷.

The ionization constant, also known as the acid dissociation constant (Ka), is a measure of the extent to which an acid dissociates in water. It indicates the degree of ionization of an acid and is typically expressed as the equilibrium constant for the reaction between the acid and water.

In the case of H₂S (hydrogen sulfide), it is a weak acid that can partially dissociate in water to produce hydrogen ions (H⁺) and sulfide ions (HS⁻). The ionization reaction can be represented as follows:

H₂S ⇌ H⁺ + HS⁻

The ionization constant (Ka) represents the equilibrium expression for this reaction. The value of Ka determines the relative strength of the acid. For H₂S, the ionization constant is approximately 1.0 x 10⁻⁷, indicating that it is a weak acid.

This value indicates that H₂S only partially ionizes in water, with a small fraction of H₂S molecules dissociating into H⁺ and HS⁻ ions. The majority of H₂S remains in its molecular form.

It is important to note that the ionization constant can vary depending on factors such as temperature and concentration. The given approximation is a typical value at standard conditions.

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