how does thunder and lighting occurs​

One second later its speed in meters per second is approximately a. 40 m/s.

Given that a heavy object is moving upward at 50 meters per second, we need to determine its speed one second later. To do this, we will consider the effects of gravity on the object's motion.

Gravity exerts a force on the object which causes it to decelerate. On Earth, the acceleration due to gravity is approximately 9.8 meters per second squared (m/s²) acting downwards. As the object is moving upwards, the gravitational force will reduce its speed by 9.8 m/s every second.

After one second, the object's speed will be reduced by 9.8 m/s. Therefore, the new speed can be calculated as follows:

Initial speed - deceleration due to gravity = New speed
50 m/s - 9.8 m/s = 40.2 m/s

Based on the available options, the closest approximation to the object's speed after one second is 40 m/s (option a).

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Answer:

51.02m

Explanation:

KE = 1/2mv2

Where k.e = 250J

mass = 0.5 kg

g = 9.8 m/s2

250= 1/2×0.5×v^2

250= 0.5×0.5×v^2

250= 0.25v^2

v^2 = 250/0.25

v^2 = 1000

v =√1000

v = 31.62m/s

v^2= u^2-2gh........... (1)

Since the object will stop at it highest point, hence it final velocity there will be zero and since it is moving up against the gravity g= -9.8m/s^2. That was why the formula in equation 1 has a negative sign

From h = u^2/2g

Where v = 31.62m/s

g = 9.8m/s^2

H = (31.62m/s)^2/9.8×2

H= 1000/19.6

= 51.02m

Hence the height of it travelling will be

51.02m

Answer:

a = 30 m/s²

Explanation:

Given: 250 kg, 7500N    

To find: Acceleration (a)    

Solution: To find the acceleration (A), divide the force by the weight  

A = F ÷ m

=  7500 ÷  250

= 30 m/s²

Newtons are derived units, equal to 1 kg-m/s². In other words, a single Newton is equal to the force needed to accelerate one kilogram one meter per second squared.

Answer:

It has producer-consumer relationship with sugar-maple trees because it gets food from the trees.

Explanation:

The mourning bird is primarily a seed eater and not an insect eater. Since it is a seed eater, it will directly from the sugar-maple tree which is the producer.

In an ecosystem, the producers are plants which can trap energy directly from the sun during photosynthesis. This energy is passed on to the consumers.

Hence, the mourning bird has producer-consumer relationship with sugar-maple trees because it gets food from the trees.

Answer:

Option C. vi = 0

Explanation:

An object held at a particular height above the ground is considered to be at rest. If the object is release from that height, the initial velocity (vi) is considered to be zero since the object is at rest or at a stand still position.

Thus,

Initial velocity (vi) = 0

The moon doesn't fall toward the Earth like apples do because it is in a state of constant freefall, known as orbit. This is due to the balance between the force of gravity pulling the moon towards the Earth and the moon's own inertia.

The moon doesn't fall toward the Earth like apples do because it is in a state of constant freefall, known as orbit. The moon orbits around the Earth due to the force of gravity. Gravity is the force of attraction between two objects with mass. In this case, the Earth's gravity pulls the moon towards it, but the moon also has its own motion called inertia. Inertia is the tendency of an object to resist changes in its motion.

When the moon was formed, it was already moving forward with a certain velocity. As it falls towards the Earth due to gravity, it also moves forward, resulting in a curved path known as an orbit. This balance between the gravitational force and the moon's inertia keeps it in a stable orbit around the Earth.

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Answer:

12

Explanation:

----------------............

The statement that is true about an orbit with an eccentricity of almost 1 is:

C) The orbit is a very long and narrow ellipse.

The eccentricity of an orbit is a measure of how elongated or stretched out the shape of the orbit is. The eccentricity of an orbit ranges from 0 to 1, with 0 representing a perfectly circular orbit and 1 representing a highly elongated or eccentric orbit.

When the eccentricity is almost 1, it indicates that the orbit is highly elongated or stretched out. This means that the orbit is no longer close to being circular but takes on the form of a long and narrow ellipse. The closer the eccentricity is to 1, the more elongated the orbit becomes. Therefore, option C, stating that the orbit is a very long and narrow ellipse, is the correct statement for an orbit with an eccentricity of almost 1.

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Answer:

c: long and thin resistor.

Explanation:

The resistance of a resistor is given by:

R = ρ*L/A

where:

R = resistance

ρ = resistivity (depends on the material)

L =  length of the material

A = cross-sectional area of the material

We can see that the length is on the numerator, which means that if we increase the length, then the resistance is increased.

We also can see that the cross-sectional area is on the denominator, then if we increase the area (for example, with a ticker resistor) the resistance decreases.

Then if we want to maximize the resistance, we need to have a long and thin resistor, so the correct answer is c.

Answer:

34º

Explanation:

The computation of the angle of refraction in the glass for this ray is shown below:

Given that

the angle of incidence of another red ray is 65º

And, n_1 = 1

n_2 = 1.62

According to shell law

n_1 sin \(\theta\)_1 = n_2 sin \(\theta\)_r

sin \(\theta\)_r = 1 sin 65÷ 1.62

= 0.559

\(\theta\)_r  = sin^-1 (0.559)

= 34º

Answer:

acceleration = - 150 m/s^2

distance = 9 miles.

Explanation:

initial speed, u = 60 mph

time, t = 12minutes = 0.2 hour

final speed, v = 30 mph

Let the acceleration is a and the distance is s.

By the first equation of motion

v = u + at

30 = 60 + a x 0.2

a = - 150 m/s^2

Let the distance is s.

Use third equation of motion is

\(v^2 = u^2 + 2 a s \\\\30^2 = 60^2 + 2 \times 150\times s\\\\s = 9 miles\)

Answer: B. Gravity Energy

Explanation: To summarize, potential energy is the energy that is stored in an object due to its position relative to some zero position. An object possesses gravitational potential energy if it is positioned at a height above (or below) the zero height.

created when sound is formed from vibrations that cause pressure changes in the surrounding air. it is called a sound wave

Sound is a mechanical wave that results from the back-and-forth vibrations of the particles of the air medium through which the sound wave is moving.

These vibrations in the air are caused by the vibration of the objects that generate the sound. If a sound wave is moving from left to right through the air, then particles of air will be displaced both rightward and leftward as the energy of the sound wave passes through it.

The motion of the particles is parallel to the direction of the energy transport. This is what characterizes sound waves in air as longitudinal waves.

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Answer:

B. radio waves

Explanation:

Trust me It's correct

The voltmeter reads 154 volts when using a 22-turn coil, as each turn multiplies the voltage by the number of turns.

When using a single thick copper wire connected to a voltmeter around a region of time-varying magnetic flux, the voltmeter reads 7 volts.

However, when you replace that single wire with a coil containing 22 turns, the voltage reading increases due to the additive effect of the induced voltage in each turn.

This is based on Faraday's law of electromagnetic induction.

So, with 22 turns, the total voltage induced in the coil is 22 times the voltage of a single turn.

Thus, the voltmeter would read 22 x 7 volts = 154 volts when using a 22-turn coil.

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Explanation:

The object is not moving, because the distance is a constant value regardless of the time value.

The wavelength of the radiation produced by a microwave oven operating at 2.10 GHz is approximately 14.3 centimeters, which is equivalent to 143 millimeters.

The wavelength of an electromagnetic wave can be calculated using the formula: wavelength = speed of light/frequency. In this case, the frequency is given as 2.10 GHz, which can be converted to hertz by multiplying by 10^9 (since 1 gigahertz = 10^9 hertz). So, the frequency becomes 2.10 × 10^9 Hz. The speed of light in a vacuum is approximately 3.00 × 10^8 meters per second. Using the formula mentioned earlier, we can calculate the wavelength as follows: wavelength = (3.00 × 10^8 m/s) / (2.10 × 10^9 Hz) Simplifying the equation, we find: wavelength ≈ 0.143 meters. To convert this to nanometers, we multiply by 10^9 since 1 meter is equal to 10^9 nanometers: wavelength ≈ 0.143 × 10^9 nanometers. These yields: wavelength ≈ 143 nanometers.

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Answer:

Velocity = Displacement by time

Explanation:

Answer:

The formula to calculate velocity =distance(s) ÷ time taken(t)

To determine the new volume of the gas when the temperature and pressure change, we can use the combined gas law equation, which relates the initial and final states of a gas:

(P₁ * V₁) / (T₁) = (P₂ * V₂) / (T₂)

Given:

Initial pressure (P₁) = 110 kPa

Initial temperature (T₁) = 30 °C = 30 + 273.15 K

Initial volume (V₁) = 2 L

Final pressure (P₂) = 440 kPa

Final temperature (T₂) = 80 °C = 80 + 273.15 K

New volume (V₂) = ?

Substituting the given values into the combined gas law equation, we have:

(110 * 2) / (30 + 273.15) = (440 * V₂) / (80 + 273.15)

Simplifying the equation further, we can solve for V₂:

(220 / 303.15) = (440 * V₂) / (353.15)

Now, we can calculate the new volume by rearranging the equation:

V₂ = (220 / 303.15) * (353.15 / 440)

By performing the calculations, we can find the value of V₂, which represents the new volume of the gas after the change in temperature and pressure.

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Answer:

THey near 225 MPH at 'Dega

Explanation:

Answer:

5.0 kg

Explanation:

use the equation; (m1v1i) + (m2v2i) = (m1v1f) + (m2v2f)

Answer:

Weight is what you get when a certain amount of gravity is acting on that mass, and something, like the surface of a planet, is resisting that action. In space, when falling freely, there's nothing resisting the pull of gravity so weight disappears. Mass however stays.

hope this helps u

Explanation:

A child sleds down a steep, snow-covered hill with an acceleration of 2.82m/s squared. if her initial speed is 0.0 m/s and her final speed is 15.5 m/s, It takes the child 5.50 seconds to travel from the top of the hill to the bottom.

We can use the following kinematic equation to solve this problem:

v^2 = u^2 + 2as

Where:

v is the final speed

u is the initial speed

a is the acceleration

s is the distance traveled

We are given u = 0.0 m/s, a = 2.82 m/s^2, and v = 15.5 m/s. We need to find s.

Rearranging the equation gives:

s = (v^2 - u^2) / (2a)

Substituting the values gives:

s = (15.5^2 - 0.0^2) / (2 x 2.82) = 74.47 m

Now, we can use another kinematic equation to find the time taken:

v = u + at

Where t is the time taken.

Substituting the values gives:

15.5 = 0.0 + 2.82t

Solving for t gives:

t = 15.5 / 2.82 = 5.50 seconds

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1.38 horsepower (approx.) would have to be applied by the pump if there were no friction losses.

To solve this problem, we can use Bernoulli's equation, which states that the total energy of a fluid is constant at any point along a streamline. This equation can be written as:

\(P/ρ + v^2/2 + g*h = constant\)

where P is the pressure, ρ is the density of the fluid, v is the velocity of the fluid, g is the acceleration due to gravity, and h is the height above some reference point.

We can apply Bernoulli's equation at point A in the suction pipe and point B in the discharge pipe to find the difference in pressure between the two points:

At point A:

\(P1/ρ + v1^2/2 + g*h1 = constant\)

where P1 is the pressure at point A, ρ is the density of water, v1 is the velocity of water in the suction pipe (which we assume to be negligible), g is the acceleration due to gravity, h1 is the height of point A above some reference point (which we can take to be the same as point B).

At point B:

\(P2/ρ + v2^2/2 + g*h2 = constant\)

where P2 is the pressure at point B, v2 is the velocity of water in the discharge pipe (which is given as 2.0 m/s), and h2 is the height of point B above the same reference point as point A.

Since the two points are at the same height (h1 = h2), we can simplify the equations to:

\(P1/ρ = P2/ρ + v2^2/2\)

Substituting the given values, we get:

\(-40,000/1000 = 400,000/1000 + 2^2/2\)

Simplifying and solving for P1, we get:

P1 = 89,000 Pa

Now, we can calculate the power (in watts) required by the pump using the following equation:

\(P = Qρg*ΔH\)

where Q is the flow rate, ρ is the density of water, g is the acceleration due to gravity, and ΔH is the difference in height between point A and point B.

To calculate the flow rate, we can use the continuity equation, which states that the mass flow rate of a fluid is constant at any point along a streamline. This equation can be written as:

\(Q = A1v1 = A2v2\)

where A1 and A2 are the cross-sectional areas of the suction and discharge pipes, respectively.

We can use the formula for the area of a circle to find the cross-sectional areas of the pipes:

\(A1 = π*(200/2)^2 = 31,416 mm^2A2 = π*(150/2)^2 = 17,671 mm^2\)

Substituting the given values, we get:

\(Q = A1v1 = A2v2Q = 31,4160.0 = 17,6712.0Q = 35,342 mm^3/s = 0.035342 m^3/s\)

Now, we can substitute the calculated values into the power equation:

\(P = QρgΔHP = 0.03534210009.813P = 1.03 kW\)

Finally, we can convert the power to horsepower by dividing by 746:

P = 1.03 kW = 1.38 horsepower (approx.)

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In conclusion, in most cases, motor vehicles are permitted to turn right on a red light after a complete stop and when the intersection is clear. However, it is crucial to consult local traffic laws and regulations to ensure compliance and to be aware of any exceptions or specific requirements that may apply.

According to the given information, turning right on a red light is permitted after a stop and when the intersection is clear. In general, this rule applies to motor vehicles, such as cars, trucks, and motorcycles. However, the specific vehicles permitted to turn right on a red light may vary depending on the jurisdiction and local traffic laws.
To illustrate, let's consider an example where a driver approaches a red traffic light and intends to make a right turn. If the driver comes to a complete stop, checks for oncoming traffic, and ensures there are no pedestrians crossing the intersection, they are generally allowed to proceed with the right turn.
It's important to note that this rule may not apply to all types of vehicles. For instance, large commercial vehicles or buses may have specific regulations or restrictions on turning right on a red light due to their size or potential impact on traffic flow.
In conclusion, in most cases, motor vehicles are permitted to turn right on a red light after a complete stop and when the intersection is clear. However, it is crucial to consult local traffic laws and regulations to ensure compliance and to be aware of any exceptions or specific requirements that may apply.

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Answer:

  a = -1,33 m / s²

Explanation:

This problem is kinematic in one dimension, let's use the equations

         v = v₀ + a t

         v₀ = v - at

          x = v₀ t + ½ a t²

we substitute the first in the second equation

         x = (v-at) t + ½ a t²

         x -v t = a t² (1 + ½)

         a = (x -vt) / t² (1.5)

we calculate

         a = (100 - 30 10) / 10² (1.5) =-200 / 150

         a = -1,33 m / s²

Aquifers are an example of geosphere and hydrosphere interacting.

The geosphere refers to the solid part of the Earth, including the rocks, minerals, and landforms. Aquifers are underground layers of porous rock or sediment that hold and transmit water. They are a component of the geosphere.

The hydrosphere is the part of the Earth that includes all water in various forms, such as oceans, lakes, rivers, and groundwater. Aquifers are underground reservoirs of water that store and supply groundwater, which is an integral part of the hydrosphere.

Therefore, aquifers illustrate the interaction between the geosphere and the hydrosphere, as they involve the movement and storage of water within the Earth's subsurface layers.

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