How far from a 6.50 µC point charge will the potential be 250 V?
_____. m
At what distance will it be 5.00 ✕ 102 V?
_____. m

Answer ideal mechanical advantage

Hey there mate :)

Even if two persons are given the same work load, the speed of the work done gets different by the energy of those persons.

No one is sure that he/she can complete the work within the time. He may or may not.

Also, the physical characteristics makes the work different. If one person has so much power to work all day, the other person may not have.

Therefore, even if two persons do the same amount of work , they may have different power.

Answer:

Easy

Explanation:

A; lowe than

Answer:

Normative

Explanation:

It is normal occurance but not unnatural

50.545 degrees with a positive x-axis and a weight of 133.909 pounds. the direction and strength of these forces' combined effect

A modest but significant amount of a certain characteristic is present in anything if it has a degree of that attribute. However, their salaries do provide them some freedom. There is some cause for cautious optimism.

Degree (Celsius) (Celsius) Temperature readings are frequently made in degrees Celsius. Degrees Celsius are denoted by the sign °C. By designating 0°C as the freezing point of water and 100°C as its boiling point, the Celsius scale is produced.

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Rey must cut a length of wire equal to approximately 487.5 meters.

To determine the length of wire needed, we can use the formula for the resistance of a wire:

R = (ρ * L) / A

where R is the desired resistance, ρ is the resistivity of the material, L is the length of the wire, and A is the cross-sectional area of the wire.

The diameter of the wire is given as 0.184 mm, so we can calculate the radius (r) and the cross-sectional area (A) of the wire:

r = 0.184 mm / 2 = 0.092 mm = 9.2 x 10^(-5) m

A = π * r^2

Next, we substitute the given resistance (R = 2.91 Ω) and resistivity (ρ = 6.44 x 10^(-8) Ω-m) into the formula:

2.91 Ω = (6.44 x 10^(-8) Ω-m * L) / A

Solving for L, we have:

L = (2.91 Ω * A) / (6.44 x 10^(-8) Ω-m)

Substituting the value of A, we get:

L = (2.91 Ω * π * (9.2 x 10^(-5) m)^2) / (6.44 x 10^(-8) Ω-m)

Calculating the value, we find:

L ≈ 487.5 meters

Therefore, Rey must cut a length of wire approximately equal to 487.5 meters to create the needed coil.

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Answer:

both are subject to a person's interpretation.

Answer:

it is a subject to a person's interpretation.

Explanation:

i hope this helps!

Answer:

-47.04

Explanation:

Divide 12 m by 2.5 m/s which equals 4.8s

And then use 4.8s to multiply it with -9.8

4.8(-9.8)= -47.04 m/s

Hope this helped!! :)

The initial height of the pumpkin is 23.52m and the final vertical velocity of the pumpkin is 47.04 m/s.

Initial horizontal speed, u = 2.5 m/s

horizontal distance covered , d = 12m

So the time taken is:

t = d/u

t = 12/2.5 s

t = 4.8s

Now, the initial vertical speed, v = 0

So the vertical distance traveled by the pumpkin will be equal to the initial height of the pumpkin:

s = vt + ¹/₂gt²

s = 0.5 × 9.8 × 4.8 m

s = 23.52m

Final vertical velocity:

v' = v + gt

v' = 9.8 × 4.8 m/s

v' = 47.04 m/s

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Using the Newton Laws, the acceleration of the object is 2.67m/s²

Based on the problem, we can draw the diagram as below to help our understanding.

From the information provided we know that:

F = 50 N (horizontal pull)

W = 75 N

f = 30 N (friction force)

From the picture, we could focus first on the X-axis, where the horizontal force and the friction force work on the object. We would apply the second law of Newton for this axis since there is movement happening within this axis.

∑Fx = m.a

F - f = m.a

50 - 30 = m.a

m.a = 20N ... (i)

Next, we will focus on the Y-axis. In this axis neutral force and weight are working but not resulting to any movement within the axis. ence, we will be applying the first law of Newton:

∑F = 0

N - W = 0

N = W

N = 75N ... (ii)

Since we know that weight is the result of multiply between mass and gravity, we could find the mass of the object by assuming the gravity is 10m/s²

W = m.g

75 = m (10)

m = 7.5kg ... (iii)

We could subtitute the equation (iii) into equation (i) to find the acceleration of the object:

m.a = 20N

(7.5) a = 20N

a = 2.67m/s²

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Answer: Energy is removed when the nucleus is formed.

Explanation: when the protons and neutrons come together to form a nucleus, energy is lossed when forming the nucleus. This energy has mass, which is removed from the total mass of the original particles.

Answer:the nucleus has less mass, because matter is converted into binding energy

Explanation: Apex

The given statement 'A positive magnification means the image is inverted compareed to the object' is false. Because when the image is virtual and erect then magnification is taken as positive.

Groundwater is a part of the geosphere realm, which refers to the solid Earth.

The geosphere includes all of the land, rocks, and minerals that make up the Earth's crust, mantle, and core. Groundwater is water that is stored beneath the Earth's surface in rock formations called aquifers, which are part of the geosphere.

Groundwater is an important resource for drinking water, irrigation, and industrial use, and it plays a critical role in many natural systems, such as the water cycle and the formation of landscapes such as caves, sinkholes, and canyons.

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Leptons and quarks are both subatomic particles that make up the matter in the universe. Leptons are elementary particles that do not interact via the strong nuclear force, which holds the nucleus of an atom together. Examples of leptons include electrons, muons, and neutrinos. Quarks, on the other hand, are elementary particles that do interact via the strong nuclear force. There are six types of quarks: up, down, charm, strange, top, and bottom.

Force carrier particles, also known as gauge bosons, are particles that mediate the fundamental forces of nature. There are four known fundamental forces: electromagnetism, gravity, the strong nuclear force, and the weak nuclear force. Each of these forces is carried by a different type of force carrier particle. For example, photons are the force carrier particles for electromagnetism, while gluons are the force carrier particles for the strong nuclear force. The weak nuclear force is carried by three particles: the W+, W-, and Z bosons. Finally, while the graviton is theorized to be the force carrier particle for gravity, it has not yet been directly detected.

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Pressing a lever in the box's corner is the sole method to get rid of the shocks. The rat picks up pressing the lever quite quickly. This is an illustration of negative reinforcement.

The technique of negative reinforcement can be applied to aid in teaching particular actions.

When something unpleasant or uncomfortable is taken away in response to a stimulus, this is known as negative reinforcement.

Target behavior should gradually grow better with the hope that the unpleasant item will go away.

A rat is placed in an environment where the floor gives the rat small electric shocks. The only way to get rid of the shocks is to press a lever in the corner of the box.

The rat quickly learns to press the lever. This is an example of  negative reinforcement

Hence the given condition is an example of negative reinforcement.

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The long time will decrease the velocity which will equally decrease the impulse applied to your knee.

The impulse experienced by an object is the change in momentum of the object.

J = ΔP = m(v - u)

where;

v = distance / time

when time of fall becomes 3 times long, the final velocity becomes 3 times smaller

Since the velocity will be reduced, the impulse applied to your knee will decrease as well.

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The provided text contains information about the microscopic structures and crystal diagrams of dental plaster, dental stone, and die stone. It also mentions the gauging water ratios and procedures for manipulating and pouring compound impressions using these materials.

The text describes the microscopic structure of dental plaster, which consists of fibrous aggregates of fine cupotal with capitany pares. Dental stone is described as having prior crystals in the form of mods, while die stone is characterized by its cuboidal shape.

The crystal diagrams are mentioned for each material: Dental plaster, dental stone, and die stone.

The text then outlines three different demonstrations, each with a specific aim and gauging water ratio. The demonstrations involve studying the manipulation of dental plaster, dental stone, and die stone, as well as pouring compound impressions using these materials. The procedures for each demonstration are provided.

To learn more about the manipulation of dental plaster, dental stone, and die stone, as well as the pouring of compound impressions, further information can be explored in dental textbooks or dental laboratory manuals.

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The characteristic impedance of the two 1-oz cu lands 100 mils in width that are located on opposite sides of a 47-mil glass epoxy board is approximately 47.4 ohms.

The characteristic impedance (Z0) of a transmission line depends on the geometry of the line and the dielectric constant of the material between the conductors. The formula for the characteristic impedance of a microstrip transmission line is:

Z0 = (87.3 + 100*(w/h)ln(4w/h)) * (h/w)

where w is the width of the trace, h is the height of the substrate, and ln is the natural logarithm.

Assuming a standard FR-4 epoxy substrate with a dielectric constant of 4.5, and using the formula above with w = 100 mils (0.1 inch) and h = 47 mils (0.047 inch), we get:

Z0 = (87.3 + 100*(0.1/0.047)ln(40.1/0.047)) * (0.047/0.1) = 47.4 ohms

Therefore, the characteristic impedance of the two 1-oz cu lands 100 mils in width that are located on opposite sides of a 47-mil glass epoxy board is approximately 47.4 ohms.

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An object's mass, rather than its weight is used to indicate the amount of matter it contains because weight is defined as the amount of force due to an existing field (In most cases, gravitational field) that is experienced by the body. The weight of the same body can be different in different environments it's observed.

However, the mass of the body is the exact measure of the amount of matter contained in a body. Which is constant, regardless of the environment, or conditions the body is observed.

Hence, for real-world calculations and experimentation, the mass of the body is considered to represent the amount of matter it contains rather than its weight.

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Answer:

the higher up an object is, the more potential energy it has

Explanation:

Copernicus's model of the universe differs from Ptolemy's because Copernicus believed the Sun is at the center of the universe and majority of the bodies in the universe revolves around the Sun.

The universe is defined as the open place that contains the planets, stars, galaxies, and all other forms of matter and energy.

There are different models of the universe including which contains the Copernicus's model and Ptolemy's model.

The Copernicus's model of the universe differs from Ptolemy's because Copernicus believed the Sun is at the center of the universe and majority of the bodies in the universe revolves around the Sun.

While the Ptolemy's model of the universe differs from the Copernicus's model because Ptolemy believed that the Earth is at the center of the universe and everything in the universe revolves around the Earth.

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Answer:

B). Rarefaction :) _____

the arrow points to the rarefactions

The forces acting on me are static frictional force and reaction force of the book. The forces acting on the book moving with a constant speed are Applied force and Kinetic frictional force.

Forces acting on me are

The book at rest, will have a static frictional force. So when I push the book, these forces will act on me. According to Newton's third law of motion, when I apply a certain amount of force on the book, the book will exert the equal amount of force on me.

Forces acting on the book are

The book when moving at constant velocity will have zero net force, because according to Newton's second law of motion, force is directly proportional to acceleration. If the velocity is constant, acceleration will be zero and net force will also be zero. Since the book is moving on a table, a kinetic frictional force will act on the book to resist the movement of the book.

Therefore,

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Answer:

is

Explanation:

e

The energy discharged by a capacitor can be calculated using the formula E = 1/2CV²,

where E is the energy in joules, C is the capacitance in farads, and V is the voltage across the capacitor.

In this question, we are given that the capacitance of the capacitor is 1,000 uF,

which is equal to 0.001 F.

The capacitor is charged up to 300 volts and then discharged completely,

so the voltage across the capacitor during discharge is also 300 volts.

Using the formula E = 1/2CV² and plugging in the given values,

we get:

E = 1/2(0.001)(300)²E = 1/2(0.001)(90,000)E = 45 Joules

Therefore, the amount of energy discharged by the capacitor is 45 Joules.

Answer: Option c. 45.

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Answer:

Explanation:

In chemistry, the term transition metal has three possible definitions: The IUPAC definition defines a transition metal as "an element whose atom has a partially filled d sub-shell, or which can give rise to cations with an incomplete d sub-shell".

Answer:

Transition elements (also known as transition metals)

Explanation:

are elements that have partially filled d orbitals. IUPAC defines transition elements as an element having a d subshell that is partially filled with electrons, or an element that has the ability to form stable cations with an incompletely filled d orbital.

1)The strength of the magnetic field for particle 1 will be 2.8 T.

2)The magnitude of the magnetic force exerted on the particle will be 0.12 N.

It is the type of field where the magnetic force is obtained. With the help of a magnetic field. The magnetic force is obtained it is the field felt around a moving electric charge.

The given data in the problem is;

q₁ has a charge = 2.7 μc

v₁ is the velocity of particle 1 = 1 773 m/s.

F is magnetic force = 5.75 × 10–3 n,

q₂ has a charge of 42.0 μc

v₂ is the velocity of 1.21 × 103 m/s.

\(\rm F_{B2}\)   is the magnitude of the magnetic force exerted on particle 2=?

The megnetic force for case 1 is found as;

\(\rm F_{B1}= qvB SIN \alpha_1 \\\\ 5.75 \times 10^{-3} =2.7 \times 10^{-6}\times 773 \times B sin 90^0 \\\\ B=\frac{5.75 \times 10^{-3}}{2.7 \times 10^{-6} \timesd 773 \times sin 90^0} \\\\ B=2.8 \ T\)

The megnetic force for case 2 is found as;

\(\rm F_{B2} = q_2v_2bsin \alpha_2 \\\\ 42\times 10^{-6} \times 1.21 \times 10^3 \times 2.8 \times sin 55^0 \\\\ F_{B2}=0.12 T\)

Hence the value of the megnetic force exerted on particle 2 will be 0.00122 T.

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Answer:

last one and second one

Explanation:

Particle q1 has a charge of 2.7 μC and a velocity of 773 m/s. If it experiences a magnetic force of 5.75 × 10–3 N, what is the strength of the magnetic field?

2.8

T

In the same magnetic field, particle q2 has a charge of 42.0 μC and a velocity of 1.21 × 103 m/s. What is the magnitude of the magnetic force exerted on particle 2?

0.12

N

The work done by the force field on a particle that moves along the parabola is 7/3 + (e²-e)/2

The work done is defined as the magnitude of the displacement d multiplied by the force component acting in the direction of the displacement.

Work done = \(\int\limits^0_C {F} \, dr\)

dr = dxi  + dyj

Given,

F(x,y) = x²i + yeˣj

Work done =   \(\int\limits^0_C\)(x²i + yeˣj)×(dxi  + dyj)

=   \(\int\limits^0_C\)x²dx + yeˣdy

As, C: x = y² + 1

y = \(\sqrt{x-1}\)

dy = \(\frac{dx}{2\sqrt{x-1} }\)

Now substitute the values of y and dy:

Work done =   \(\int\limits^0_C\)x²dx + \(\sqrt{x-1e^{x} }\) × \(\frac{dx}{2\sqrt{x-1} }\)

=  \(\int\limits^0_C\)x² + ¹/₂ eˣ dx

Now, work done = \(\int\limits^1_2 {x^{2} }\) +  ¹/₂ eˣ dx

= [x³/3 + ¹/₂ eˣ]²₁

= [2³/3 + ¹/₂ e²] - [1³/3 + ¹/₂ e¹]

= 8/3 + ¹/₂ e² - 1/3 + e/2

= 7/3 + (e²-e)/2

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Complete question is as follows:

Find the work done by the force field F(x,y) = x²i + yeˣj on a particle that moves along the parabola x=y²+1 from (1, 0) to (2, 1)