How is Science involved in the way a firework works?

molar solubility of PbBr2 in 0. 500 M KBr solution is 4S3 = 6.60 x 10–6 . PbBr2 ionizes as Pb2+ + 2Br-, molar solubility of PbBr2 in a 0. 500 M Pb(NO3)2 solution is 0.0181 moles/lit..

If molar solubility of PbBr2 is “S”, then solubility of Pb2+ is also “S” but that of Br- would be “2S”. Ksp = [Pb2+] [Br-]2 = (S) (2S)2 = 4S3 = 6.60 x 10–6 4S3 = 6.6 x 10–6,this gives Solubility S = 1.181 x 10–2 = 0.0181 moles/lit. solid's solubility (usually referred to as its molar solubility) is expressed as the concentration of the "dissolved solid" in a saturated solution. This would simply be the concentration of Ag+ or Cl- in the saturated solution for a simple 1:1 solid like AgCl. The other way to express solubility is through molar solubility, which is defined below. It is the number of moles of solute in one litre of saturated solution and is abbreviated with a lower case's'. It is expressed in moles per litre, also known as molarity.

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The solutes in an aqueous solution of KF in order of increasing concentration are : Lowest concentration: K+ (aq),H+ (aq),OH- (aq),F- (aq),Highest concentration: HF (aq)

In an aqueous solution of KF, K+ ions come from the dissociation of KF, but KF is a strong electrolyte and dissociates almost completely, so the concentration of K+ ions is relatively high. H+ ions are present in water due to the self-ionization of water, but their concentration is relatively low. OH- ions are also present due to the self-ionization of water, but their concentration is lower than that of H+ ions. F- ions come from the dissociation of KF, so their concentration is higher than that of OH- ions. HF is a weak acid that partially dissociates in water, resulting in a higher concentration of HF compared to the other ions in the solution.

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Newton’s Law .Use your knowledge of Newton’s Laws to complete the calculations. 1) F = 0.98 N 2) F = 3.9 N 3) F = 6.86 N 4) F = 10.78 N 5) F = 24.5 N 6) F = 49 N 7) F = 80.36 N.

Newton's law : F = ma

where, F = force

m = mass

a = acceleration due to gravity = 9.8 m/s²

1) mass = 0.10 kg ,

F = ma

F = 0.10 kg ×  9.8 m/s²

F = 0.98 N

2) mass = 0.40 kg

F = ma

F = 0.40 kg ×  9.8 m/s²

F = 3.9 N

3) mass = 0.70 kg

F = ma

F =  0.70 kg ×  9.8 m/s²

F = 6.86 N

4) mass = 1.1 kg

F = ma

F = 1.1 kg ×  9.8 m/s²

F = 10.78 N

5) mass = 2.5 kg

F = ma

F = 2.5 kg ×  9.8 m/s²

F = 24.5 N

6) mass = 5.0 kg

F = ma

F = 5.0 kg ×  9.8 m/s²

F = 49 N

7) mass = 8.2 kg

F = ma

F = 8.2 kg ×  9.8 m/s²

F = 80.36 N

Thus, Newton’s Law .Use your knowledge of Newton’s Laws to complete the calculations. 1) F = 0.98 N 2) F = 3.9 N 3) F = 6.86 N 4) F = 10.78 N 5) F = 24.5 N 6) F = 49 N 7) F = 80.36 N.

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Based on the given information and the densities provided in the table, the unknown element in the alloy is most likely Beryllium. option(a)

To identify the unknown element in the alloy, we need to compare the density of the alloy with the densities of the elements listed in the table.

The density of the alloy can be calculated using the given information. We know that 10.0 grams of the alloy has a volume of 4.20 cm³. Density is defined as mass divided by volume, so we can calculate the density of the alloy as:

Density = Mass / Volume = 10.0 g / 4.20 cm³ ≈ 2.38 g/cm³

Now, we compare the calculated density of the alloy (2.38 g/cm³) with the densities listed in the table. From the given options, the closest density is that of aluminum, which is 2.70 g/cm³. The alloy's density is lower than the density of aluminum, which means it must contain an element with a lower density than aluminum.

The unknown element in the alloy is most likely Beryllium (option A) with a density of 1.85 g/cm³. The combination of 62% aluminum and 38% beryllium in the alloy would result in a density close to the calculated value of 2.38 g/cm³. option(a)

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Direct contact between objects causes conduction or heat transfer. The heat is transferred inside the fluid during convection. Heat transfer in radiation happens by electromagnetic waves without the use of particles.

First, ascertain whether the two things are in contact. If they are, conduction is how heat is transferred between them. Determine whether there is a fluid medium, such as a liquid or gas, connecting the items if they are not in contact.

Evidence of heat transport is apparent. Convection is the phenomenon that causes the air to shimmer over radiators. Conduction is the phenomenon that causes you to feel warm when you place your hand on a spoon that has been sitting in a hot bowl of soup (radiation).

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The average atomic mass of uranium is 237.97 amu based on its three common isotopes.

Isotopes are the different forms of the same element. In considering the abundance of different isotopes of uranium for the calculation of its average atomic mass, the formula below is used.

Average atomic mass = summation of [(percent abundance /100)*atomic mass]

With the given three common isotopes of uranium, the calculated value of average atomic mass is shown below.

Average atomic mass= (0.01/100)(234 amu) + (0.71/100)(235 amu) + (99.28/100)(238 amu)

Average atomic mass=237.97 amu

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Answer:

Coductivity

Explanation:

Because heat conducts to them!

ANSWER

2Ba + 2HBr → 2BaBr + H2

2BiCl3 + 3H2S → Bi2S3 + 6HCl

Br2 + 2KI → I2 + 2KBr

4Fe + 3O2 → 2Fe2O3

Answer:

\(3Mg _{(s)} + N _{2(g)} → Mg_{3} N _{2(s)}\)

\(Ba _{(s)} + 2HBr_{(g)} → BaBr _{2(s)} + H _{2(g)}\)

\(2BiCl_{3(s)} + 3H_{2} S _{(g)} → Bi _{2} S _{ 3(g)} + 6HCl _{(g)} \\ \)

\(Br_{2(g)} + 2KI _{(g)} → I _{2(g)} +2 KBr _{(g)}\)

\(4Fe_{(s)}+ 3O_{2(g)} → 2Fe_{2} O _{3(s)} \)

Answer:

79.8g/dm³

Explanation:

As you can see, the solution in the problem contains 0.5 moles of copper sulfate per dm³. To solve this question we must convert these moles to grams using its molar mass (Molar mass CuSO4 = 159.609g/mol) as follows:

0.5mol CuSO4/dm³ * (159.609g/mol) =

Answer

We have the following chemical reaction:

We can see that the equation is balanced because we have the same number of each atom in both sides of the equation.

Now, as we can see in the equation, for every mol of Zn that reacts it is needed 2 moles of HCl. Therefore we can calculate the moles of HCl needed in total as follows:

So the answer is: there are needed 5.8 mol.

Answer:

C2H6 + 7/2O2 ....... 2CO2 + 3H2O

Answer: Does adding salt to water make the water boil faster that if salt is not added?

Explanation:

The scientific question for the boiling water experiment could be: "What is the effect of increasing temperature on the boiling point of water?"

This question aims to investigate how temperature influences the boiling point of water. By conducting the experiment and analyzing the results, scientists can gain a better understanding of the relationship between temperature and the physical state change of water from liquid to vapor.

The question focuses on a specific variable (temperature) and its impact on the boiling process, allowing for a targeted investigation and potential insights into the behavior of water under different conditions.

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We are given the following information:
- The silver atom is oscillating in simple harmonic motion
- Frequency of oscillation = 10^12 Hz
- Mole weight of silver = 108 g/mol
- Avogadro's number = 6.02 × 10^23 atoms/mol

First, let's find the mass of a single silver atom:
mass of one atom = (Mole weight of silver) / (Avogadro's number)
mass of one atom = (108 g/mol) / (6.02 × 10^23 atoms/mol) = 1.79 × 10^-22 g

Now we can convert the mass to kg:
mass of one atom = 1.79 × 10^-22 g × (1 kg / 1000 g) = 1.79 × 10^-25 kg

In simple harmonic motion, the angular frequency (ω) can be related to the given frequency (f) as follows:
ω = 2πf
ω = 2π(10^12 Hz) = 6.283 × 10^12 rad/s

The force constant (k) can be related to the mass (m) and angular frequency (ω) using the formula:
k = mω^2

Now, plug in the values for mass and angular frequency:
k = (1.79 × 10^-25 kg) × (6.283 × 10^12 rad/s)^2 = 706.6 N/m

So, the force constant of the bonds connecting one silver atom with the other is approximately 706.6 N/m.

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True. In a mass spectrometer, analytes need to be ionized before they can enter the mass filter. Ionization is a crucial step that converts neutral molecules into charged ions, enabling their separation and analysis based on their mass-to-charge ratio.

In a mass spectrometer, the ionization process is essential for the analysis of analytes. Analytes are typically introduced into the mass spectrometer as a vapor or gas. The ionization step involves converting these neutral analyte molecules into charged ions. This is achieved through various ionization techniques such as electron impact ionization, chemical ionization, electrospray ionization, or matrix-assisted laser desorption/ionization (MALDI).

Ionization is necessary because the mass spectrometer operates by manipulating charged particles. Once the analyte molecules are ionized, they can be accelerated and directed into the mass filter. The mass filter then separates the ions based on their mass-to-charge ratio, allowing for the detection and measurement of individual ions. By analyzing the mass spectrum generated, valuable information about the composition, structure, and quantity of the analytes can be obtained. Therefore, the ionization step is a crucial prerequisite for the successful operation of a mass spectrometer.

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Answer: sulfur dioxide

Explanation:

Answer:

I think is the last one!!!! punnet square ⬜

Solution is the term which best describes mixture A which was made by mixing different components together but has only one phase.

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we need to use the Beer-Lambert law, which states that the change in absorbance is proportional to the concentration of the absorbing species and the path length of the sample.

The equation for the Beer-Lambert law is: A = εcl.
where A is the absorbance, ε is the molar absorptivity (a constant for a given absorbing species), c is the concentration, and l is the path length. We can rearrange this equation to solve for the concentration: c = A/(εl).

In this case, we are looking for the change in concentration of NADPH (c), given the change in absolute absorbance per second (A) from the DHFR functional assay analysis. We don't have the value of ε or l, but we can assume that they are constant throughout the experiment.

So, we can plug in the values we do have and solve for c: c = A/(εl) = 0.0035/(εl), We are not given the values of ε or l, but we don't need them to answer the question. We are looking for the change in concentration (Δc) of NADPH, so we can rewrite the equation as: Δc = ΔA/(εl), where ΔA is the change in absorbance per second. Plugging in the values we have: Δc = 0.0035/(εl).

We don't know the value of ε or l, but we can use the answer choices to eliminate some possibilities. We know that the change in concentration will be in units of micromoles per milliliter per minute (umol/ml/min). The only answer choice that has the correct units is: Δc = 0.000034 umol/ml/min.

Therefore, the change in concentration of NADPH is 0.000034 umol/ml/min if the change in absolute absorbance per second from the DHFR functional assay analysis was 0.0035.

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Answer:

D

Explanation:

2-bromopropanoic acid is optically active because it contains chiral carbon bonded with 4 different atom ( CH3,H,COOH,Br).

Answer:

Xe that is xenon

Explanation:

Xe that is xenon

Answer:

B. 2

Explanation:

A single bond contains 2 shared electrons.

Given example is that of ethane

Answer:

The answer is B. 2

In order to answer the question first we must write the atomic number of each element:

Zirconium (Zr): 40

Cadmium (Cd): 48

Iridium (Ir): 77

Iron (Fe): 26

Then, we have to complete the distribution of electrons in each orbital for each atom:

The first 4 levels have the following distribution:

Level1: 1s

Number of electrones: 2

Level 2: 2s, 2p

Number of electrones 8 (2 in the s orbital and 6 in the p orbitals).

Level3: 3s, 3p, 3d

Number of electrones 18 (2 in the s orbital, 6 in the p orbital and 10 in the d orbitals)

Level 4: 4s, 4p, 4d, 4f

Number of electrones 32 (2 in the s orbital, 6 in the p orbitals, 10 in the d orbitals and 14 in the f orbitals)

The order in which the orbitlas are completed depends on the energy of each level. For example the 4s orbitals will be completed before the 3d orbitals because their energy is lower.

The order is as follows:

1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, 4d, 5p...

Now, knowing the atomic number we can answer the question:

For Zirconium (total 40 electrones):

2 electrones are predicted in the 4d orbital

For Cadmium (total 48 electrones):

10 electrones are predicted in the 4d orbital

For iridium, as it has an atomic number higher than Cadmium we can predict tha it also complets the 4d orbital, then it has also 10 electrones in it.

For iron (total 26 electrones)

Iron has no electrones in the 4d orbitals

Based on the balanced equation, if we have 0.08 moles of Iron (Fe), we can conclude that 0.08 moles of Hydrogen (H₂) will be formed as well.

First we need to balance the chemical equation for the reaction involving Iron (Fe) and Hydrogen (H).

The reaction will be between Fe and HCl (hydrochloric acid) to produce hydrogen gas (H₂) and iron chloride (FeCl₂):

Fe + 2HCl → FeCl₂ + H₂

From the balanced equation, we can see that for every 1 mole of Fe reacted, 1 mole of H₂ is formed. Therefore, if we have 0.08 moles of Fe, we can conclude that 0.08 moles of H₂ will be formed as well.

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Answer:

4

Explanation:

To determine the value of 'n' for the cell reaction, we can use the relationship between the standard emf (E°), the equilibrium constant (K), and the number of moles of electrons transferred (n) in the balanced cell reaction.

The Nernst equation provides a direct relationship between the standard emf and the equilibrium constant:

E = E° - (RT/nF) * ln(K)

Where:

E is the cell potential at a given temperature,

E° is the standard emf at 298 K,

R is the ideal gas constant (8.314 J/(mol*K)),

T is the temperature in Kelvin,

n is the number of moles of electrons transferred,

F is Faraday's constant (96,485 C/mol), and

ln denotes the natural logarithm.

Since the standard emf (E°) is given as 0.115 V and the equilibrium constant (K) is given as 6.85 x 10^5, we can substitute these values into the Nernst equation.

0.115 V = E° - (8.314 J/(mol*K)) * (298 K/n) * ln(6.85 x 10^5)

Now we can solve this equation to find the value of 'n'.

First, let's simplify the equation:

0.115 V = E° - (2.475/n) * ln(6.85 x 10^5)

Next, we rearrange the equation to isolate the term containing 'n':

(2.475/n) * ln(6.85 x 10^5) = E° - 0.115 V

Now, divide both sides of the equation by ln(6.85 x 10^5):

2.475/n = (E° - 0.115 V) / ln(6.85 x 10^5)

Finally, multiply both sides of the equation by 'n' and rearrange to solve for 'n':

n = 2.475 / [(E° - 0.115 V) / ln(6.85 x 10^5)]

By plugging in the given values for E° and K, you can calculate the value of 'n' for the cell reaction.

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The pressure of 0.0158 mole of methane in a 0.275 L flask at 27 °C is approximately 4.42 atm.

To calculate the pressure of the methane in the flask, we can use the ideal gas law equation:

PV = nRT

Where:

P = Pressure (in atm)

V = Volume (in liters)

n = Number of moles

R = Ideal gas constant (0.0821 L·atm/(mol·K))

T = Temperature (in Kelvin)

First, let's convert the temperature from Celsius to Kelvin:

T(K) = T(°C) + 273.15

T(K) = 27 + 273.15

T(K) = 300.15 K

Now we can substitute the given values into the ideal gas law equation:

P * 0.275 = 0.0158 * 0.0821 * 300.15

Solving for P:

P = (0.0158 * 0.0821 * 300.15) / 0.275

P ≈ 4.42 atm

Therefore, the pressure of 0.0158 mole of methane in a 0.275 L flask at 27 °C is approximately 4.42 atm.

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Answer:

234.6

Explanation:

In order to calculate the pH of a salt solution generated from a weak acid and a weak base using a single ice chart, a few things must be true.

Firstly, the weak acid and weak base must react to form a salt and water. This is important because the salt will affect the pH of the solution. Secondly, the acid and base must be of equal strength.

If one is stronger than the other, the resulting solution will either be acidic or basic, depending on which is stronger. Finally, the initial concentrations of the acid and base must be known,

as well as the equilibrium constant of the acid-base reaction. With this information, the single ice chart can be used to determine the concentrations of all species in the solution at equilibrium, which can then be used to calculate the pH of the solution.

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