Answers
Answer:
F=2496 N
Explanation:
Given that,
Mass of SUV, m = 1600 kg
Initial speed, u = 0
Final speed, v = 25 m/s
Distance, d = 200 m
We need to find the net force. Firstly, let's find acceleration using equation of motion.
\(v^2-u^2=2ad\\\\a=\dfrac{v^2-u^2}{2d}\\\\a=\dfrac{(25)^2-(0)^2}{2\times 200}\\\\a=1.56\ m/s^2\)
Net force, F = ma
\(F=1600\times 1.56\\\\F=2496\ N\)
So, the net force is 2496 N.
The amount of net force that will be required to accelerate a 1600kg SUV from rest to a speed of 25 m/s in a distance of 200m is 2500N
HOW TO CALCULATE NET FORCE:
The net force of a body can be calculated by multiplying its mass by acceleration. However, the acceleration of this SUV needs to be calculated using the following equation of motion:v² - u² = 2asa = v² - u²/2sWhere:
a = acceleration (m/s²)v = final velocity (m/s)u = initial velocity (m/s)s = distance (m)a = 25² - 0²/2(200)a = 625/400a = 1.563m/s²Since a = 1.563m/s²
F = 1600 × 1.563F = 2500NTherefore, the amount of net force that will be required to accelerate a 1600kg SUV from rest to a speed of 25 m/s in a distance of 200m is 2500N.Learn more at: https://brainly.com/question/18031807?referrer=searchResults
Related Questions
Magnets on the tracks
How can levitating trains support the claim that magnetic fields exist between objects exerting magnetic force on each other even when there is no physical contact?
Answers
Answer:
Explanation: They levitate sort of because when to opposite forces of magnets cant go together they repelIn a skate park, you are trying to determine how to get the most speed at the bottom of the ramp. If the ramp is 4.5 m high, and you start at the top of the ramp with an initial velocity of 1.5m/s, how fast will you be rolling at the bottom of the ramp, given there is no friction. Use conservation of energy to solve.
Answers
Answer:
If you have an initial velocity of 1.5m/s and the ramp height is 4.5, and an extreme fart is initiated at the bottom of the ramp exerting an didditional upward force, and the smell of the fart causes you to begin flailing, and everyone running from you causes an additional wind force, then you would be rolling at a speed of 3 m/s given there is no friction. :)
Particles in the gaseous state move
than particles in the liquid state?
Answers
If the 100 g mass is replaced by a 200 g mass, which variables in Tnet = la change, and which
remains constant? Justify your answer.
Answers
The moment of inertia (I) will changes and net torque (Tnet) will also change, while the angular acceleration (a) remains constant.
What is the changed variable in the equation?The formula for net torque acting on an object is given as;
T(net) = Ia
where;
a is the angular accelerationI is the moment of inertiaT(net) is the net torqueThe moment of inertia of an object is given as;
I ∝ MR²
where;
M is the massR is the radius of the objectSo mass, M changes, the moment of inertia (I) changes and net torque will also change, while the angular acceleration remains constant.
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An aseroid with a mass of 8.4x10^8 kg and a planet with a mass of 6.2x10^23 kg come close to each other by a distance of 8x10^5 m. what is the force of gravity that the asteroid and the planet have on each other ?
Answers
So, the force of gravity that the asteroid and the planet have on each other approximately
\( \boxed{\sf{5.43 \times 10^{10} \: N}} \)
IntroductionHi ! Now, I will help to discuss about the gravitational force between two objects. We already know that gravitational force occurs when two or more objects interact with each other at a certain distance and generally orbit each other to their center of mass. For the gravitational force between two objects, it can be calculated using the following formula :
\( \boxed{\sf{\bold{F = G \times \frac{m_1 \times m_2}{r^2}}}} \)
With the following condition :
F = gravitational force (N)G = gravity constant ≈ \( \sf{6.67 \times 10^{-11}} \) N.m²/kg²\( \sf{m_1} \) = mass of the first object (kg)\( \sf{m_2} \) = mass of the second object (kg)r = distance between two objects (m)Problem SolvingWe know that :
G = gravity constant ≈ \( \sf{6.67 \times 10^{-11}} \) N.m²/kg²\( \sf{m_1} \) = mass of the first object = \( \sf{8.4 \times 10^8} \) kg.\( \sf{m_2} \) = mass of the second object = \( \sf{6.2 \times 10^{23}} \) kg.r = distance between two objects = \( \sf{8 \times 10^5} \)What was asked :
F = gravitational force = ... NStep by step :
\( \sf{F = G \times \frac{m_1 \times m_2}{r^2}} \)
\( \sf{F = 6.67 \times 10^{-11} \times \frac{8.4 \cdot 10^8 \times 6.2 \cdot 10^{23}}{(8 \times 10^5)^2}} \)
\( \sf{F = \frac{347.374 \times 10^{-11 + 8 + 23}}{64 \times 10^10}} \)
\( \sf{F \approx 5.43 \times 10^{20 - 10}} \)
\( \boxed{\sf{F \approx 5.43 \times 10^{10} \: N}} \)
ConclusionSo, the force of gravity that the asteroid and the planet have on each other approximately
\( \boxed{\sf{5.43 \times 10^{10} \: N}} \)
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. Acylinder contains 1 mole of oxygen at
a temperature of 27 °C. The cylinder
is provided with a frictionless piston
which maintains a constant pressure
of 1 atm on the gas. The gas is heated
until its temperature rises to 127 °C.
(a) How much work is done by the
piston in the process?
(b) What is the increase in internal
energy of the gas?
(c) How much heat was supplied
to the gas?
(C = 7.03 calmol-¹°C¯¹;
R = 1.99 calmol-¹°C-¹;
1cal = 4.184 J)
Answers
a}The work is done by the piston in the process is 199 cal.
b) The increase in internal energy of the gas is 703 cal
c) The heat was supplied to the gas is 3771 J
(a) To calculate the work done by the piston, we can use the formula:
Work = P * ΔV
Where P is the constant pressure and ΔV is the change in volume. Since the pressure is constant, the work done is given by:
Work = P * (\(V_2 - V_1\))
Since the amount of gas is constant (1 mole), we can use the ideal gas law to calculate the initial and final volumes:
PV = nRT
\(V_1 = (nRT_1) / P_1\)
\(V_2 = (nRT_2) / P_2\)
Here, n is the number of moles (1 mole), R is the gas constant (1.99 cal/mol·°C), T1 is the initial temperature (27 °C + 273 = 300 K), T2 is the final temperature (127 °C + 273 = 400 K), and P1 and P2 are the initial and final pressures, respectively (both 1 atm).
Substituting the values into the equation, we have:
V1 = (1 mol * 1.99 cal/mol·°C * 300 K) / (1 atm) ≈ 597 cal
V2 = (1 mol * 1.99 cal/mol·°C * 400 K) / (1 atm) ≈ 796 cal
Therefore, the work done by the piston is:
Work = 1 atm * (796 cal - 597 cal) = 199 cal
(b) The increase in internal energy of the gas can be calculated using the equation:
ΔU = n * C * ΔT
Where ΔU is the change in internal energy, n is the number of moles (1 mole), C is the molar heat capacity (7.03 cal/mol·°C), and ΔT is the change in temperature (127 °C - 27 °C = 100 °C).
Substituting the values into the equation, we have:
ΔU = 1 mol * 7.03 cal/mol·°C * 100 °C = 703 cal
(c) The heat supplied to the gas can be calculated using the equation:
Q = ΔU + Work
Substituting the values calculated in parts (a) and (b), we have:
Q = 703 cal + 199 cal = 902 cal
Since 1 cal = 4.184 J, the heat supplied to the gas is:
Q = 902 cal * 4.184 J/cal ≈ 3771 J
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the wheel in fig. 10-30 has eight equally spaced spokes and a radius of 30 cm. it is mounted on a fixed axle and is spinning at 2.5 rev/s. you want to shoot a 20-cm-long arrow parallel to this axle and through the wheel without hitting any of the spokes. assume that the arrow and the spokes are very thin. (a) what minimum speed must the arrow have? (b) does it matter where between the axle and rim of the wheel you aim? if so, what is the best location?
Answers
To pass through the wheel without hitting any of the spokes, the arrow must have a speed that is at least equal to the speed of the wheel at the rim. Therefore, the minimum speed the arrow must have is 188.5 cm/s.
Thus, aim towards the wheel's rim, where it's traveling fastest.
What minimum speed must the arrow have?Generally, To answer this question, we need to consider the speed of the wheel at different points along its radius.
For (a), we can consider the case where the arrow is aimed at a point on the rim of the wheel. At this point, the wheel is moving at its maximum speed, which is equal to the speed of the wheel multiplied by the circumference of the wheel. The circumference of a circle is equal to 2 * pi * r, where r is the radius of the circle. Therefore, the speed of the wheel at the rim is 2.5 rev/s * 2 * pi * 30 cm = 188.5 cm/s.
For (b), it does matter where between the axle and rim of the wheel you aim. If you aim at a point closer to the rim, the wheel will be moving faster at that point, and the arrow will need to have a higher speed to pass through the wheel without hitting any of the spokes. On the other hand, if you aim at a point closer to the axle, the wheel will be moving slower at that point, and the arrow will not need to have as high of a speed to pass through the wheel without hitting any of the spokes.
The best location to aim would be at a point where the speed of the wheel is equal to the speed of the arrow. This will allow the arrow to pass through the wheel without hitting any of the spokes and without having any extra speed to spare. To find this point, we can set the speed of the arrow equal to the speed of the wheel at a particular point along the radius and solve for that point.
The speed of the wheel at a particular point along the radius is equal to the speed of the wheel at the rim multiplied by the radius of the wheel at that point divided by the radius of the wheel at the rim. This can be expressed as:
speed(r) = speed(rim) * r / rim
where r is the radius of the wheel at the point where the arrow is aimed and rim is the radius of the wheel at the rim.
Setting the speed of the arrow equal to the speed of the wheel at a particular point and solving for r, we get:
r = speed(arrow) * rim / speed(rim)
Substituting the known values, we get:
r = 188.5 cm/s * 30 cm / 188.5 cm/s
r = 30 cm
This means that the best location to aim is at the rim of the wheel, where the wheel is moving at its maximum speed.
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Calculate the net force on the particle q1.
Answers
Answer:
-12.1
Explanation:
i’m almost sure this is it, i’m checking my old answers
if not let me know and i’ll give you some more answers
How much force is needed to accelerate an object with a mass of 90 kg at a rate of 1.2 ms
Answers
If the frequency of an oscillator is 9.4 Hz, calculate the tie period T
Answers
The period, T = 0.106 seconds
Explanation:The frequency, F = 9.4 Hz
Let the period be represented by T
The relationship between frequency and period is given as:
\(T=\frac{1}{F}\)Substitute F = 9.4 Hz into the relationship above
\(\begin{gathered} T=\frac{1}{9.4} \\ T=0.106\text{ seconds} \end{gathered}\)Therefore, the period, T = 0.106 seconds
Swim 2km at 3km/h. Run at 12km/h for 1 ½ hours. Cycling 55km at 30 km/h. What is the mean overall speed.
Answers
Answer:
t1 = S1 / V1 = 2 km / 3 km/hr = 2/3 hr where S1 = 2 km
S2 = 12 km/hr * 3/2 hr = 18 km where t2 = 3/2 hr
t3 = S3 / V3 = 55 km / 30 km/hr = 11/6 hr where S3 = 55 km
T = t1 + t2 + t3 = 4/6 + 9/6 + 11 / 6 = 24/6 = 4 hrs
S = S1 + S2 + S3 = 2 + 18 + 55 = 75 km
V = S / T = 75 km / 4 hrs = 18.75 km/hr for the average speed
Please help me
Explain why driver age 16-18 are most likely to be involved in traffic accidents
Answers
Answer:Lack of experience.
Explanation:
Research from the CDC points to a few key reasons teen drivers are likely to be involved in car accidents: Lack of experience. Teen drivers have triple the fatal crash risk of older drivers, in part because they do not have the skills to recognize and avoid road hazards.
(Figure 1) shows a thin liquid film bounded on the right side by a sliding wire that is attached to a spring with spring constant 0.50 N/m. The spring is stretched by 1.3 cm. What is the liquid's surface tension in mN/m?
Answers
The liquid's surface tension in N/m is determined as 0.25 N/m.
What is surface tension?
Surface tension is defined as the property of the surface of a liquid that allows it to resist an external force, due to the cohesive nature of its molecules.
Mathematically, the formula for surface tension of a liquid is given as;
γ = F/L
γ = F/2x
where;
F is the applied forcex is the extension of the springγ is the surface tensionFrom Hooke's law, the force applied on an elastic material is directly proportional to the extension of the material.
F = kx
where;
k is the spring constantx is the extension of the springThe final equation for the surface tension of the liquid film becomes;
γ = F/2x
γ = kx/2x
γ = k/2
γ = (0.5 N/m) / 2
γ = 0.25 N/m
Thus, the surface tension of a liquid depends on the applied force and length of the liquid surface.
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In which circuit would ammeter A shows the greatest current?
Answers
In the circuit with two 10Ω resistors in parallel, ammeter A would show the greatest current. This is because, in a parallel circuit, the total resistance is lower than in a series circuit, which means that the current can flow more easily.
In this case, the two 10Ω resistors in parallel create a total resistance of 5Ω (1/Rtotal = 1/10 + 1/10 = 2/10, Rtotal = 10/2 = 5), while in the series circuit,https://brainly.com/question/11409042?referrer=searchResults the total resistance would be 20Ω (10 + 10). Ohm's law states that the current is directly proportional to the voltage and inversely proportional to the resistance, so the circuit with lower resistance will allow for greater current flow.
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--The complete Question is, In which circuit would ammeter A show the greatest current: a circuit with one 6V battery and two 10Ω resistors in parallel or a circuit with one 6V battery and two 10Ω resistors in series? --
The same amount of thermal energy was added to two equal masses of Aluminum and Iron. The specific heat of Aluminum is double the specific heat of iron. If the temperature of the Aluminum's mass changes by /\T, what is the change in the Iron's mass temperature?
Answers
Answer:
it is double the temperature change of iron
If and object undergoes a change in momentum of 12 kg*m/s over a 10
second interval, what was the force exerted?
Answers
The magnitude of the force exerted on this object is 1.2 Newton.
Given the following data:
Change in momentum = 12 Kgm/s.Time = 10 seconds.What is impulse?In Science, the impulse that is experienced by an object is always equal to the change in momentum of the object, due to the force acting on an object.
Mathematically, impulse is given by this formula:
\(Impulse = change\;in\;momentum\\\\Force \times time = m \Delta V\)
Substituting the given parameters into the formula, we have:
\(Force \times 10=12\\\\Force =\frac{12}{10}\)
Force = 1.2 Newton.
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What is A rounded to the nearest tenth?
A
HHHHHHHHHHH
14
14.2 14.4
14.6
14.8
15
14.1 14.3 14.5 14.7 14.9
What is A rounded to the nearest one?
Answers
Answer: B
Explanition:
What is the relationship between the energy differences of energy levels in an atom and the light emitted by the atom?
The energy difference is directly proportional to the frequency of emitted light.
O The energy difference is directly proportional to the square of frequency of emitted light.
O The energy difference is inversely proportional to the square of frequency of emitted light.
O The energy difference is inversely proportional to the frequency of emitted light. I’m
Answers
The energy difference is directly proportional to the frequency of emitted light."
The correct option is A.
What is the relationship between the energy differences in energy levels in an atom and the light emitted by the atom?The relationship between the energy differences in energy levels in an atom and the light emitted by the atom is described by the Planck-Einstein equation, which relates the energy of a photon of light to its frequency:
E = hν,
where E is energy, h is Planck's constant, and ν is frequency.
When an electron in an atom drops from a higher energy level to a lower energy level, it emits a photon of light with a frequency proportional to the energy difference between the two levels. Therefore, the energy difference between the energy levels is directly proportional to the frequency of the emitted light.
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If the elastic component was removed what would be true of the vicious component?
Answers
If the elastic component of a viscoelastic material were completely removed, the material would behave purely as a viscous fluid.
The term viscous component is generally used to describe the behavior of viscoelastic materials, which exhibit both elastic and viscous properties.
The viscous component in that type of material refers to the portion of the deformation brought on by viscous forces, which are forces that oppose the motion and are related to the deformation's velocity.
A viscoelastic substance would act solely as a viscous fluid if the elastic component were fully removed.
Given that only the rate of deformation would depend on the material's deformation and not the total amount of deformation, it would be wholly caused by viscous forces.
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Can someone explain what is loss of seismic energy ?
Answers
Answer:
Seismic attenuation describes the energy loss experienced by seismic waves as they propagate. It is controlled by the temperature, composition, melt content, and volatile content of the rocks through which the waves travel.
Explanation:
A plane is cruising at 100 m/s when suddenly the pilot turnsthe engines up to full throttle. After traveling 2.0 km, the jet ismoving with a speed of 200 m/s. What is the jet’s acceleration asit speeds up?
Answers
The acceleration of the jet when it speeds up = 7.5 m/s²
Explanation:The initial speed, u = 100 m/s
Distance travelled, s = 2. km
s = 2 x 1000m
s = 2000 m
Final speed, v = 200 m/s
The acceleration is found by using the equation of motion below
\(v^2=u^2+2as\)Substitute v = 200 m/s, u = 100 m/s, s = 2000 m
\(\begin{gathered} 200^2=100^2+2\times a\times2000 \\ 40000=10000+4000a \\ 4000a=30000 \\ a=\frac{30000}{4000} \\ a=7.5m/s^2 \end{gathered}\)The acceleration of the jet when it speeds up = 7.5 m/s²
What do you buy from the power company?
only energy*
electrons and energy
only electrons
Answers
Answer:
From the power source we have to buy only energy.
Explanation:
Energy is released when an electron loses potential energy as a result of the transfer from higher state to lower state.
Electricity is the movement of electrons between atoms and it doesn't means we can isolate the electrons from the atom and sell it. It remains the part of atom and hence only energy can be purchase form the power company.
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The work done when a force moves a body through a distance of 15m is 1800j. What is the value of the force applied
Answers
Answer:
120 Newtons.
Explanation:
Work(Joules) = Force(Newtons) × Distance(Meters)
If we need to find the Force, the equation changes.
To find Force, you have to divide the Work done from the Distance. Have a look at the picture above.
The first P-wave of an earthquake travels 5600 kilometers from the epicenter and arrives at a seismic station at 10:05 a.m. At what time did this earthquake occur?
Ahhhhhh I have a Regent's test in 2 hours and I don't know how to solve this type of question! Any help would be appreciated.
Anyone know what the steps to do this are? I dont even need an answer, just how to get to it. Thank you!
Answers
The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.
The p-waves travel with a constant velocity of 7 km/s
The time can be calculated by using the formula
t = d / v
where
T1 = 10:05 a.m
d is the distance they take to travel from the epicenter
v is the speed of the p-waves
On average, the speed of p-waves is
v = 7 km/s
d = 5600 km (given)
Substituting the values in the formula;
t = d / v
t = 5600 ÷ 7
t = 800 seconds
Converting into minutes,
t = 800 ÷ 60
t = 13.3
≈ 13 mins
T1 - 13 mins = T2
10:05 - 13 mins = 9.52 am
It means the earthquake occurred prior 13 minutes, that is at 9.52 am.
Therefore, the earthquake occurred at 9.52 am.
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What are the two main processes carried out by the excretory system?
Answers
This is the path which one body follows around another body in space.
Answers
Answer:
Pls ezplain your question more
Explanation:
Answer:
orbit is the answer
Suppose that you changed the area of the bottom surface of the friction cart without changing its mass, by replacing the Teflon slab with one that was smaller but thicker. The contact area would shrink, but the normal force would be the same as before. Would this change the friction force on the sliding cart
Answers
Answer:
in this case the weight of the vehicle does not change , consequently the friction force should not change
Explanation:
The friction force is a macroscopic manifestation of the interactions of the molecules between the two surfaces, this force in the case of solid is expressed by the relation
fr = μ N
W-N= 0
N = W
as in this case the weight of the vehicle does not change nor does the Normal one, consequently the friction force should not change
Rectangular frames are easy to build but can get pulled out of shape. What are two solutions to this problem?
Answers
Answer: Rectangular frames are easy to make but can get pulled out of shape. so if the sides are still attached , then the figure formed is parallelogram. useing the given measurement use the formula of a parallelogram.
formula : A = BASE X HEIGHT
Explanation:
A jar of tea is placed in sunlight until it reaches an equilibrium temperature of 33.1 ◦C . In an attempt to cool the liquid, which has a mass of 185 g , 90.3 g of ice at 0.0 ◦C is added. At the time at which the temperature of the tea is 26.3 ◦C , find the mass of the remaining ice in the jar. The specific heat of water is 4186 J/kg · ◦ C . Assume the specific heat capacity of the tea to be that of pure liquid water. Answer in units of g.(2 significant digits pls)
Answers
90.1 g of ice are still present in the container. Calculating the heat received by the ice to melt and the heat lost by the tea is necessary until it reaches an equilibrium temperature of 33.1 ◦C .
How do you calculate the amount of heat needed to melt ice?Consider how much energy is required to melt one kilogramme of ice at zero degrees to produce one kilogramme of water at zero degrees. The energy required to melt one kilogramme of ice is determined by Q = mLf = (1.0 kg)(334 kJ/kg) = 334 kJ using the equation for a change in temperature.
In order to calculate how much heat is gained by the ice melting, we must first calculate how much heat is lost by the tea as it cools from 33.1 °C to 0.0 °C.
Tea loses the following amount of heat: q1 = m1CT1 = 0.185 kg) (4186 J/kg C) (33.1 C - 0.0 C) = 26298.93 J.
Heat required for ice to melt is given by the formula: q2 = m2Hf = (0.0903 kg)(333.55 kJ/kg) = 30062.56 J
We may set q1 = q2 to get the mass of ice still present because the system is in thermal equilibrium:
m2 = q2/Hf = 333.55 kJ/kg / 30062.56 J = 0.0901 kg
Finally, we round the mass to two significant digits and convert it to grammes:
m2 = 90.1 g
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A piston-cylinder device initially contains 50 L of liquid water at 40°C and 200 kPa. Heat is transferred to the water at constant pressure until the entire liquid is vaporized. (a) What is the mass of the water? (b) What is the final temperature? (c) Determine the total enthalpy change. (d) Show the process on a T-v diagram with respect to saturation lines.
Answers
(a) The mass of water is approximately 49.65 kg. (b) The final temperature of the water vapor will be 120°C. (c) The total enthalpy change is approximately 277,956 kJ. (d) Diagram shown below.
(a) To determine the mass of the water, we need to know its density at the given conditions. The density of water changes with temperature and pressure. At 40°C and 200 kPa, the density of water is approximately 993 kg/m³.
Since we have 50 L of water, we need to convert it to cubic meters:
50 L = 0.05 m³
Now we can calculate the mass of water:
Mass = Density * Volume
Mass = 993 kg/m³ * 0.05 m³
Mass ≈ 49.65 kg
Therefore, the mass of water is approximately 49.65 kg.
(b) To find the final temperature, we need to consider the phase change from liquid to vapor. At constant pressure, the temperature will remain constant until all the liquid water has vaporized. This temperature is called the saturation temperature.
We can determine the saturation temperature at 200 kPa using a steam table or other relevant data sources. Let's assume that the saturation temperature is 120°C.
Therefore, the final temperature of the water vapor will be 120°C.
(c) To calculate the total enthalpy change, we need to consider the energy required to heat the water from its initial temperature to the saturation temperature, as well as the energy required for the phase change from liquid to vapor.
The enthalpy change during heating can be calculated using the formula:
ΔH1 = Mass * Specific Heat Capacity * ΔT1
Where:
Mass = 49.65 kg (from part a)
Specific Heat Capacity = specific heat capacity of water at constant pressure = 4.18 kJ/(kg·°C)
ΔT1 = final temperature - initial temperature = 120°C - 40°C = 80°C
ΔH1 = 49.65 kg * 4.18 kJ/(kg·°C) * 80°C
ΔH1 ≈ 165,938 kJ
The enthalpy change during phase change can be calculated using the formula:
ΔH2 = Mass * Latent Heat of Vaporization
Where:
Mass = 49.65 kg (from part a)
Latent Heat of Vaporization = energy required to vaporize 1 kg of water = 2257 kJ/kg
ΔH2 = 49.65 kg * 2257 kJ/kg
ΔH2 ≈ 112,018 kJ
The total enthalpy change is the sum of ΔH1 and ΔH2:
Total Enthalpy Change = ΔH1 + ΔH2
Total Enthalpy Change ≈ 165,938 kJ + 112,018 kJ
Total Enthalpy Change ≈ 277,956 kJ
Therefore, the total enthalpy change is approximately 277,956 kJ.
(d) The process can be shown on a T-v (temperature-volume) diagram with respect to saturation lines. In this case, the process starts at the initial temperature and pressure (40°C, 200 kPa), and moves along the constant pressure line until reaching the saturation temperature (120°C). Then, the process follows the saturation line until the entire liquid is vaporized.
Here is a simplified representation of the process on a T-v diagram:
|
Saturation | |
Line | |
| |
| |
| |
| |
| |
| |
Initial |-----------------------------| Final
| |
| |
| |
| |
| |
|
This diagram is a rough representation and does not accurately reflect specific volume values or scale. It simply illustrates the general process from initial conditions to the final state along the constant pressure and saturation lines.
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