How long does a dream typically last near the end of the sleep cycle, just before waking?
A.
about 5 minutes
B.
about 15 minutes
C.
about 30 minutes
D.
about 50 minutes
pleaseeeee hurryy

Answer:

Approximately \(79\; {\rm m\cdot s^{-2}}\).

Explanation:

Apply unit conversion and ensure that angular velocity \(\omega\) is in radians per second. The angular displacement of each revolution is \(2\, \pi\) radians. Therefore:

\(\begin{aligned} \omega &= \frac{2.0\; \text{revolution}}{1\; {\rm s}} \\ &= \frac{2.0\; \text{revolution}}{1\; {\rm s}} \, \frac{2\, \pi}{1\; \text{revolution}} \\ &= (4.0\, \pi)\; {\rm s^{-1}} \\ &\approx 12.566\; {\rm s^{-1}}\end{aligned}\).

The clothes in this laundry machine are in a centripetal motion. The radius of the motion is \(r = 0.50\; {\rm m}\), and the angular velocity of the clothes is \(\omega \approx 12.566\; {\rm s^{-1}}\). The acceleration of the clothes will be:

\(\begin{aligned}a &= \omega^{2} \, r \\ &\approx (12.566\; {\rm s^{-1}})^{2} \, (0.50\; {\rm m}) \\ &\approx 79\; {\rm m\cdot s^{-2}}\end{aligned}\).

Answer:

A convex mirror is curved outwards, and concave mirror is curved inwards. The fundamental difference between them is that the reflective surface of a concave mirror is inside the sphere and that of a convex mirror is outside.

The ratio of their speeds before the collision is 0.

In an inelastic collision, the two objects stick together and move as one object after the collision. We can apply the principle of conservation of momentum to solve this problem.

Before the collision, the total momentum of the system is given by:

Total momentum before collision = (mass of object 1 * velocity of object 1) + (mass of object 2 * velocity of object 2)

Since both objects are initially at rest, their velocities are 0. Therefore, the total momentum before the collision is also 0.

After the collision, the two objects stick together and move with a common velocity. Let's denote this common velocity as V.

The total momentum after the collision is given by:

Total momentum after collision = (mass of combined object * velocity of combined object)

Since the two objects stick together, the mass of the combined object is the sum of the masses of the individual objects, i.e., (2m + 10m) = 12m.

The total momentum after the collision is therefore 12mV.

According to the principle of conservation of momentum, the total momentum before the collision is equal to the total momentum after the collision. Therefore:

0 = 12mV

Since the velocity V is zero (objects are at rest after the collision), we can conclude that the ratio of their speeds before the collision is:

Velocity of object 1 / Velocity of object 2 = 0

So, the ratio of their speeds before the collision is 0.

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Answer:

Explanation:

lll

Answer:

Unbalanced

Explanation:

Hussein is pushing 2 N harder.

Answer:

True

Explanation:

It is true that. A technician can be electrocuted when working on HEVs or EVs, therefore the correct answer is option A

An EV stands for an electric vehicle. Electric vehicles (EVs) are autos that are powered totally or partially by electricity. Electric cars are extremely cost-effective to run because they have fewer moving parts to maintain and use little to no fossil fuels (petrol or diesel).

When evaluating its environmental impact, every factor must be taken into consideration. Considering that EVs have a minimal overall environmental impact, this suggests that the severity of these production emissions decreases.

Recycling is one strategy for lowering the lifespan emissions of electric vehicles. Again, incorrect assumptions can be refuted by facts.

Thus, That is accurate. The correct response is option A because a technician could electrocute themselves while working on HEVs or EVs.

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Answer:

REFLECTED, ECHOES.

Explanation:

204.7 J is the work done on the system which loses energy in its surroundings while a piston expands against an external pressure of 2. 35 atm.

The work done by the piston can be calculated using the formula:

work = -\(P_{ext}\) × ΔV

where \(P_{ext}\) is the external pressure, and ΔV is the change in volume. The negative sign indicates that work is done on the system.

Substituting the given values, we get:

= -2.35 atm × (1.318 L - 0.455 L)

= -2.35 atm × 0.863 L

= -2.02 L atm

1 L atm = 101.325 J

Therefore, the work done by the piston is:

work = -2.02 L atm × (101.325 J/L atm)

work = -204.7 J

The negative sign indicates that work is done on the system, which means that the system loses energy to the surroundings.

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To determine the length of the hanging cable with the given shape, we need to calculate the arc length of the curve over the given range.

The arc length formula for a function y=f(x) over an interval [a, b] is given by the integral of the square root of (1 + [f'(x)]^2) with respect to x, integrated from a to b.

In this case, the given function for the shape of the cable is y = 15 cosh(x/15), and we need to find the length of the cable over the interval -20 < x < 20.

First, let's find the derivative of the function y = 15 cosh(x/15). The derivative of cosh(x) is sinh(x), and since we have x/15 in the argument, the derivative becomes sinh(x/15).

Now, we can set up the integral for the arc length:

L = ∫[a,b] √(1 + [f'(x)]^2) dx

L = ∫[-20,20] √(1 + sinh^2(x/15)) dx

To evaluate this integral, we can use a numerical method or software. For simplicity, let's use numerical integration with an appropriate step size.

Using numerical integration, the length of the cable is approximately 91.82 feet.

Note: The arc length formula is derived from calculus, specifically the fundamental theorem of calculus. Integrating the square root of the sum of squares of the derivatives of the function gives us the total length of the curve.

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Two types of errors that can occur when measuring the length of an object are systematic errors and random errors. Systematic errors can be minimized by calibrating measuring instruments and ensuring proper alignment. Random errors can be reduced by taking multiple measurements and calculating the average value.

There are two types of errors that can occur when measuring the length of an object: systematic errors and random errors.
1. Systematic errors: These errors occur consistently and affect all measurements in the same way. They are usually caused by equipment calibration issues or incorrect measurement techniques. Systematic errors can be minimized by:
- Calibrating the measuring instrument regularly to ensure accurate readings.
- Using the appropriate measuring technique, such as aligning the object properly with the measuring device.
- Taking multiple measurements and averaging the results to reduce the impact of any systematic error.
2. Random errors: These errors are unpredictable and can occur due to various factors, such as human error or environmental conditions. Random errors can be minimized by:
- Taking multiple measurements and calculating the average, which helps to reduce the effect of random errors.
- Using a measuring instrument with high precision, as it reduces the likelihood of random errors.
- Ensuring consistent environmental conditions during measurements, such as stable temperature and lighting.
It's important to note that no measurement can be completely free from error.

However, by minimizing systematic and random errors, we can increase the accuracy and reliability of our measurements. Regular calibration, proper technique, and multiple measurements are key strategies to minimize errors when measuring the length of an object.

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To determine the number of half-lives that have elapsed, we need to compare the ratio of 14C to 14N atoms found in the hip bone fragment.

The ratio of 1 14C atom for every 31 14N atoms suggests that the hip bone fragment contains a smaller amount of 14C compared to the expected ratio found in a living organism. Since 14C undergoes radioactive decay with a half-life of approximately 5730 years, we can calculate the number of half-lives that have elapsed by observing how many times the ratio needs to double to reach the expected ratio.

In this case, if the expected ratio is 1:1, then the observed ratio of 1:31 would require five doublings to reach 1:1. Therefore, approximately five half-lives have elapsed since the death of the organism from which the hip bone fragment originated.

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Answer:

each resistor draws 1/3 of an amp or 0.33333 amps

Explanation:

V = I * R

V = 10 volts

R = 30 ohms

10 = I * 30       Divide by 30

10/30 = I

I = 0.33333

Inelastic collision and a host of other factors causes the loss of energy.

Kinetic energy of an object is the energy that it possesses due to motion.

It can be defined as the work needed to accelerate a body of a given mass from rest to its stated velocity. When it has gained this energy during its acceleration, the body maintains this kinetic energy unless its speed changes.

In an inelastic collision which is the case of ball X and Y, the kinetic energy of the system is not conserved. The energy that you find lost has been dissipated as other forms of energy. This can be heat, friction, vibrational energy transferred to atoms of the colliding particles, energy lost to deform the atomic structure etc.

In conclusion, the inelastic collision nature of the two balls results in the loss of energy through different forms.

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the engery from the microwave is asorbed by the potato

The intensity level 35m away from the speaker would be approximately 103 dB.

The relationship between distance and sound intensity is given by the inverse square law. According to the inverse square law, the intensity of sound decreases as the square of the distance from the source increases.

In this case, the sound level at a distance of 5.0m from the speaker is given as 120 dB. We can use this information to calculate the intensity at that distance using the formula:

IL1 - IL2 = 10 * log10(I2/I1)

Where IL1 is the initial intensity level, IL2 is the final intensity level, I1 is the initial intensity, and I2 is the final intensity.

We can rearrange the formula to solve for the final intensity:

I2 = I1 * 10^((IL2 - IL1)/10)

Plugging in the values, I1 = 10^((120 - 0)/10) = 10¹², and I2 = 10^(103/10) ≈ 1.995 x 10¹⁰.

Now, applying the inverse square law, we can calculate the intensity level at a distance of 35m:

IL2 = 10 * log10(I2/((35/5)² * I1))

= 10 * log10((1.995 x 10¹⁰)/((35/5)² * 10¹²))

≈ 103 dB

Therefore, the intensity level 35m away from the speaker would be approximately 103 dB.

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In comparison to a galaxy and a planet, a star is heavier. an accurate comparison of the cosmological masses of various objects.

A galaxy has a mass that is between that of a moon and that of a planet. A planet has more mass than a star, which has less mass than a galaxy. The stars need a lot of mass to maintain nuclear fusion, which requires resulted in the production of each.

Planets and stars, solar systems, galaxies, and the cosmos are some key concepts to keep in mind in the following order: smallest to largest. Each phrase is a part of the following.

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Answer:

clockwise is 2.5 Nm

Anticlockwise is 0.25 F Nm.

Explanation:

Moment is equal to force × distance

5 units of mass are Kilogram, Gram, Milligram  ,Microgram ,Ton

Kilogram (kg)

Gram (g)

Milligram (mg)

Microgram (µg)

Ton (metric ton or t)

depending on the context, other units of Mass is a measure of the amount of matter in an object. It is a scalar quantity, meaning it only has magnitude and no direction.

Mass is typically measured in grams (g), kilograms (kg), or ounces (oz) depending on the system of units used. such as ounce (oz), pound (lb), stone (st) and others may also be used.

Mass is a measure of the amount of matter in an object. It is a scalar quantity, meaning it only has magnitude and no direction.

Mass is typically measured in grams (g), kilograms (kg), or ounces (oz) depending on the system of units used.

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Answer:

9 meters

Explanation:

Assuming this question is asking for the change in position, the way to approach such a problem is multiplying VELOCITY by TIME when velocity is constant.

Velocity = 3 m/s, Time = 3s.

3m/s * 3s = 9m

1. The law of corresponding states that at the same reduced conditions (expressed in terms of reduced temperature and pressure), different gases will exhibit similar behavior in terms of their compressibility factor (Z). This law allows gases to be compared and studied based on their reduced properties rather than their individual molecular characteristics.

2. Real gases may behave as ideal gases under conditions of low pressure and high temperature. When the pressure is low and the intermolecular forces between gas molecules are weak, the gas molecules are far apart and their volume becomes negligible. Additionally, at high temperatures, the kinetic energy of the gas molecules is significant, leading to increased randomness and less interaction between the molecules.

1. The law of corresponding states establishes a relationship between the behavior of different gases by comparing their reduced properties. The reduced temperature (Tr) is the actual temperature divided by the critical temperature (Tc), and the reduced pressure (Pr) is the actual pressure divided by the critical pressure (Pc). By plotting Z, the compressibility factor, against Pr and Tr, gases of different compositions can be compared on a single graph. The law states that gases with similar values of Z at the same reduced conditions will exhibit similar behavior, indicating a deviation from ideal gas behavior.

2. Real gases deviate from ideal gas behavior due to intermolecular forces and the finite volume of gas molecules. However, under certain conditions, these deviations become negligible, and the gas behaves as an ideal gas. When the pressure is low, the gas molecules are far apart, and their volume is relatively small compared to the available space. This reduces the impact of intermolecular forces and makes the gas behave similarly to an ideal gas. Similarly, at high temperatures, the kinetic energy of gas molecules overcomes the attractive forces between them, resulting in less interaction and a closer approximation to ideal gas behavior.

3. a. In the saturation envelope of a mixture of methane (10%) and ethane (90%), the envelope represents the range of conditions (temperature and pressure) at which the mixture exists as a vapor and liquid in equilibrium. Due to the difference in molecular properties, the saturation envelope for this mixture will be different from that of pure methane or ethane. The composition of the mixture influences the temperature and pressure ranges at which the transition from vapor to liquid occurs.

  b. In the saturation envelope of a mixture of ethane (50%) and pentane (50%), the composition of the mixture plays a significant role. The saturation envelope for this mixture will exhibit a different temperature and pressure range compared to the individual components. The presence of different molecules alters the intermolecular interactions and leads to changes in the phase transition behavior.

4. The five main processes during the processing of natural gas are:

  a. Exploration and Production: This involves locating and extracting natural gas reserves from the earth.

  b. Gathering and Transportation: Natural gas is collected from multiple wells and transported via pipelines or liquefied natural gas (LNG) carriers to processing plants or distribution points.

  c. Processing and Treatment: Natural gas goes through various processes to remove impurities, such as water, sulfur compounds, and other contaminants.

  d. Storage: Natural gas may be stored in underground facilities or LNG tanks for later use or transportation.

  e. Distribution and Utilization: Natural gas is distributed through pipelines to residential, commercial, and industrial consumers for various applications such as heating, cooking, and electricity generation.

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Define the following: 1. Law of corresponding states. (2 marks) 2. Under what conditions the real gas may behave as an ideal gas. (2 marks) 3. Please explain qualitatively, the difference between the saturation envelope of the following mixtures: (4 marks) a. Methane and ethane, where methane is 10% and ethane is 90%. b. Ethane and pentane, where ethane is 50% and pentane is 50%. 4. List down the five main processes during the processing of natural gas. (2 marks)

d) less massive than the Sun. A protostar that will eventually turn into a star like the Sun is formed from a cloud of gas and dust that collapses under its own gravity.

As it collapses, it heats up and becomes more luminous, but it is still much smaller and less massive than the Sun. Over time, the protostar will continue to contract and heat up until it reaches a point where the conditions in its core are sufficient to initiate nuclear fusion. A protostar that will eventually turn into a star like the Sun is formed from a cloud of gas and dust that collapses under its own gravity.  a protostar that will eventually turn into a star like the Sun is significantly  At this point, it will become a true star, but it will still be smaller and less massive than the Sun.

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20.74 W/m^2 is the intensity of an electromagnetic wave with a peak electric field strength of 125 v/m

Intensity is given by:

I = 0.5×c×e0×E^2

Using given values:

c = 3.0×10^8 m/sec

e0 = 8.85×10^-12

E = 125 V/m

I = 0.5×3×10^8×8.85×10^-12×125^2

I = 20.74 W/m^2

The Intensity of an electromagnetic wave per unit area (power is defined as energy per unit time), where the area is measured on a plane perpendicular to the direction of propagation, determines the intensity of the electromagnetic wave.

Larger surface areas are covered by the light energy as it travels farther between surfaces. The magnetic and electric fields may exert greater forces and hence have higher intensities the greater their size.

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Given,

The initial height of the soccer ball, h₁=6 ft

The initial velocity of the ball, u=96 ft/s

The acceleration due to gravity, g=-32 ft/s

When the ball reaches the maximum height, its velocity will reduce to zero.

Thus the velocity of the ball when it is at its maximum height is v=0 ft/s

From the equation of motion,

Where h₂ is the total height covered by the ball from its initial height to reach its maximum height.

On substituting the known values,

Thus the maximum height reached by the ball is,

Thus the maximum height reached by the ball is 150 ft.

Answer: (a) The length of the wire with a diameter of 0.15m and 15-ohm resistance is 15.77 m

(b) There is no voltage drop in the resistor but there is a voltage drop of 2 V in the wire

Explanation:

The expression for resistance is R = xL/A,  where R is resistance, x is Resistivity, L is the length of the wire and A is the area

Rearranging the equation we get, L = RA/x

The area of a cross-section is A = \(\pi\)(D/2)^2

D in our case is equal to 0.15 x 10^-3 m

x in our case is equal to 1.68 x 10^-8 omega m

Putting all these values in the equation we get L to be equal to 15.77 m

For the second part using our equation V = IR, we can figure out there will be no voltage drop across the resistor but there will be a voltage drop across the wire by 2 V

That is due to the new resistor being added in a series connection and using that information we can find out the current in the wire, as the current stays the same across resistors in a series connection we can find out the voltage in each resistor using our equation V = IR

Subtracting it from the initial voltage through the wire will give us the change i.e. of 2 V

a. To determine the final dilution, we need to multiply the individual dilution factors. In this case, the dilution factors are \(1/2\), \(1/4\), and \(1/8\). So the final dilution factor is \( (1/2) \times (1/4) \times (1/8) = 1/64 \).

The final dilution refers to the overall dilution achieved after a series of successive dilutions. It is the cumulative effect of all the individual dilution factors applied in the dilution process.

b. The reported concentration is \(4 \mathrm{mg/dL}\). Since the final dilution factor is \(1/64\), we need to divide the reported concentration by the dilution factor to obtain the actual concentration of the original sample.

Actual concentration = Reported concentration / Dilution factor

Actual concentration = \(4 \mathrm{mg/dL} \) / \(1/64\) = \(256 \mathrm{mg/dL}\).

Therefore, the final dilution is \(1/64\) and the reported concentration of the original sample is \(256 \mathrm{mg/dL}\).

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Answer:

uxjdkddoedlkfkkllllllllo

Answer:

R=V/I

R= 2

Explanation:

R = 10V/5A

R = 2ohms

To find the absolute value of the charge density in the wire, we can use the formula:

The diameter of the wire is given as 1.628 mm, so the radius is half of that:

Next, we can calculate the charge density using the given current value:

The diameter of a circle, in geometry, is the straight line segment that passes through the center and connects any two points on the circle, or, in modern usage, diameter means the length of the line segment. For example, if the radius of a circle is 4 cm, then the diameter is 4 cm x 2, or 8 cm. If the circumference is known, divide by π to get the diameter. The diameter is the unit of measurement on the circle, the diameter itself is the straight line that connects the two outermost points of the circle and passes through the center of the circle.

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Answer:

v=28.28m/s t=14.14s average velocity =2m/s

Explanation:

Starting at rest the initial velocity is 0 substituting that in the first equation of motion v=u+atgives the final velocity but we first have to determine the time using the third equation of motion which is s=ut+1/2at^2 and then do the substitution. Average velocity is the determined by adding the initial and final velocity then divide it by 2

Explanation:

μ = coefficient of friction.

F = Frictional force = 12N

R = Normal reaction = mg = Weight = 240N

m = mass

g = acceleration due to gravity ≈ 9.8ms—²

μ = F/R

μ = 12/240

μ = ¹/20

μ = 0.05

The wavelength of the standing wave created in the string is 31.2 cm.

The speed of the transverse wave on a string will be given by:

v = sqrt(T/μ)

where T is tension in the string and μ is linear mass density of the string (mass per unit length). We can find the linear mass density of the string by dividing the mass of the string by its length:

μ = m/ℓ

where m is mass of the string and ℓ is its length.

Substituting the given values, we get:

μ = 13.1 g / 1.97 m = 6.64 × 10⁻³ kg/m

The frequency of the fourth harmonic of the string is given by:

f = 4v/λ

where λ is wavelength of the standing wave.

We can find v by using the formula for speed and the given values of T and μ:

v = sqrt(T/μ) = sqrt(9.51 N / 6.64 × 10⁻³ kg/m)

= 70.3 m/s

Substituting the values of v and f into the formula for wavelength, we get:

λ = 4v/f = 4(70.3 m/s) / f

So we just need to find the frequency of the fourth harmonic. The frequency of the nth harmonic of a string is given by:

f_n = nv/2ℓ

where n is the harmonic number and ℓ is the length of the string. So for the fourth harmonic, we have:

f_4 = 4v/2ℓ = 2v/ℓ = 2(70.3 m/s) / 1.97 m

= 142 Hz

Substituting this value into the formula for wavelength, we get:

λ = 4(70.3 m/s) / (142 Hz)

= 31.2 cm

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