how long does it take the star and planet to complete one orbit around their center of mass?

The theoretical values of nodal voltages using Kirchhoff's Laws can be used in the analysis of an electrocardiogram (ECG) to identify potential cardiac abnormalities and diagnose specific heart conditions by providing important information about the electrical activity of the heart.

The ECG measures the electrical activity of the heart by detecting the changes in voltage that occur during each heartbeat. The electrical activity of the heart can be modeled using Kirchhoff's Laws, which describe how current and voltage behave in an electrical circuit. Abnormalities in the electrical activity of the heart can be detected by analyzing the ECG waveform and comparing it to the theoretical values of nodal voltages.

To know more about Kirchhoff's Laws, here

brainly.com/question/30400751

#SPJ4

--The complete Question is, How can the theoretical values of nodal voltages using Kirchhoff's Laws be used in the analysis of an electrocardiogram (ECG) to identify potential cardiac abnormalities and diagnose specific heart conditions? --

Larry's average speed, in km/h, can be calculated by dividing the total distance he ran by the time taken.

Average speed is a measure of the overall rate at which an object covers a certain distance. It is calculated by dividing the total distance traveled by the total time taken. The average speed is a scalar quantity, meaning it only has magnitude and no direction. It represents the overall "average" rate at which an object moves without considering the specific details of its motion. Larry ran 4 kilometers in 30 minutes. To calculate the average speed, we convert the time from minutes to hours by dividing it by 60. So, 30 minutes is equal to 0.5 hours.

Average speed = Total distance / Time taken

Average speed = 4 km / 0.5 hours

Dividing 4 km by 0.5 hours, we get:

Average speed = 8 km/h

Therefore, Larry's average speed is 8 km/h.

To know more about average speed, click here https://brainly.com/question/27851466

#SPJ11

because the in falling matter has some angular momentum that is why matter falling towards a white dwarf, neutron star, or black hole in a binary system form an accretion disk.

The mass falls toward the central body, causing conservation of angular momentum to enhance the orbital speed. As a result, a rotating disc is created by the falling materials.

what is Angular momentum?

Angular momentum is any rotating object's characteristic determined by moment of inertia times angular velocity. It is a characteristic of rotating bodies determined by the sum of their moment of inertia and angular velocity.

The mass, motion, and distance of an object's mass from the centre of rotation all affect angular momentum, also known as spin.

Therefore, because the in falling matter has some angular momentum that is why matter falling towards a white dwarf, neutron star, or black hole in a binary system form an accretion disk.

To learn more about the Angular momentum

here: https://brainly.com/question/26889176

#SPJ4

The velocity of a golf ball with a mass of 47 g and the kinetic energy of a golf ball is measured to be 143 J is 2.44 m/s.

The kinetic energy is the energy obtained when the body is in motion. The kinetic energy equals half of the product of mass and the square of the velocity of the object. The velocity is a vector quantity that defines the speed with a particular direction and the unit of velocity is m/s. The unit of kinetic energy is Joule (J).

From the given,

the mass of a golf ball = 47 g = 0.047 kg

the kinetic energy = 143 J

the velocity of a golf ball =?

K.E = 1/2 (mv²) where m is the mass and v is the velocity.

v² = 143×2 / 0.047

   = 286 / 0.047

  = 6085.10

v² = 6085.1

v = √6

  = 2.44

v = 2.44 m/s.

Thus, the velocity of a golf ball is 2.44 m/s.

To learn more about Kinetic energy:

https://brainly.com/question/10703928

#SPJ1

Answer:

50m; 0m/s.

Explanation:

Given the following data;

Initial velocity = 20m/s

Acceleration, a = - 4m/s²

Time, t = 5secs

To find the displacement, we would use the second equation of motion;

\( S = ut + \frac {1}{2}at^{2}\)

Substituting into the equation, we have;

\( S = 20*5 + \frac {1}{2}*(-4)*5^{2}\)

\( S = 100 + (-2)*25\)

\( S = 100 - 50\)

Displacement, S = 50m

Next, to find the final velocity, we would use the third equation of motion;

\( V^{2} = U^{2} + 2aS \)

Where;

Substituting into the equation, we have;

\( V^{2} = U^{2} + 2aS \)

\( V^{2} = 20^{2} + 2(-4)*50 \)

\( V^{2} = 400 - 400\)

\( V^{2} = 0\)

Final velocity, V = 0m/s

Therefore, the displacement of the bus is 50m and its final velocity is 0m/s.

Answer:

the answer to this question is A globular cluster

(A) nearly the same as his weight

When the Jackie Chan of acceleration hit the ground, he had two different kinds of power. There are two types of acceleration: rotational acceleration and linear acceleration.

The tension in the string and the frictional force between the rope and the Jackie Chan create the angular acceleration. On the other hand, linear acceleration is caused by the disparity between Jackie Chan's weight and the rope's tension.

The downward linear acceleration would be less than the acceleration brought on by gravity if the tension in the rope were similar to Jackie Chan's weight. Therefore, Jackie Chan's acceleration would be substantially less than g only if the tension in the rope is comparable to his weight.

learn more about linear acceleration here

https://brainly.com/question/15411328

#SPJ4

Answer:

I'm just going to tell you the information you need but not the answer so you can learn from the problem.

Explanation:

So he was at 248 km mark and traveled 99 km to get to the 149km mark. Then he turns around to go back 18 km to the 167 km mark. That is all the information you need to complete the question I recommend drawing it out in your notes.

The scaling law for volume displacement, v(t, p), in terms of scaling exponents aₜ and aₚ is given by v(t, p) = aᵥ / (∂G/∂(λₐ⋅t)).

The scaling law for v(t, p) in terms of aₜ and aₚ, we can start with the given expression for the Gibbs energy scaling function:

λG(t, p) = G(λₐ⋅t, λₐ⋅p)   ---(1)

We differentiate this equation with respect to pressure (p) while treating t as a constant:

∂(λG)/∂p = (∂G/∂p)⋅(∂(λₐ⋅p)/∂p)

The derivative of λₐ⋅p with respect to p is λₐ. Now, using the relation v = (∂p/∂G), we can rewrite the above equation as:

v(t, p) = (∂p/∂G) = (∂(λG)/∂p) / (∂(λₐ⋅p)/∂p) = (∂G/∂p) / λₐ

Since G is a function of λₐ⋅t and λₐ⋅p, we can express ∂G/∂p as:

∂G/∂p = (∂G/∂(λₐ⋅p))⋅(∂(λₐ⋅p)/∂p)

Plugging this back into the equation for v(t, p), we get:

v(t, p) = (∂G/∂(λₐ⋅p)) / (λₐ⋅(∂(λₐ⋅p)/∂p))

Now, substitute the scaling function λG(t, p) from equation (1) into the above equation:

v(t, p) = (∂(λG)/∂(λₐ⋅p)) / (λₐ⋅(∂(λₐ⋅p)/∂p))

Simplifying further, we obtain:

v(t, p) = (∂(G(λₐ⋅t, λₐ⋅p))/∂(λₐ⋅p)) / (λₐ⋅(∂(λₐ⋅p)/∂p))

Using the chain rule of differentiation, we can rewrite the numerator as:

∂(G(λₐ⋅t, λₐ⋅p))/∂(λₐ⋅p) = (∂G/∂λₐ⋅t)⋅(∂(λₐ⋅t)/∂(λₐ⋅p))

Since (∂(λₐ⋅t)/∂(λₐ⋅p)) = (∂t/∂p), we can further simplify the expression:

v(t, p) = (∂G/∂λₐ⋅t) / (λₐ⋅(∂t/∂p))

Introduce the volume displacement scaling factor aᵥ as:

v(t, p) = aᵥ⋅(∂G/∂λₐ⋅t) / (λₐ⋅(∂t/∂p))

Comparing this equation with the desired form v(t, p) = aₜ⋅(∂t/∂p), we can conclude that:

aₜ = aᵥ / (∂G/

To know more about scaling law refer here

https://brainly.com/question/54881645#

#SPJ11

Graph 1 shows the increasing speed.

Graph 2 shows the sitting still.

Graph 3 shows the constant speed.

The speed-time graph is described in such a way that speed is always plotted on the vertical axis and time is always plotted on the horizontal which gives the speed of a particle accelerating at time 0, u at time t represents the speed up to v.

For uniformly varying speed the speed-time graph will be a straight line while the acceleration in the graph is given by the slope of the graph. The distance covered by a moving body in a given time can be calculated from the speed time graph.

Like in above given example, graph 1 shows the increasing as it is increasing with time, graph 2 shows the sitting still position as time is increasing but distance is constant and graph 3 shows the constant speed as with time equal distance increases.

Thus, Graph 1 shows the increasing speed.

Graph 2 shows the sitting still.

Graph 3 shows the constant speed.

Learn more about Speed-time graph, here:

https://brainly.com/question/16825120

#SPJ2

I would think the answer would be c

Answer:

bc we play when we are bored and some people use it as a tradition to play on thanksgiving

Answer:

If you went to work your trap muscles you don't need a ton of fancy gym equipment. Here are four trapezius exercises you can perform using your own body.

a) The mass of the piston is not given, so it cannot be determined.

b) The final volume of the refrigerant is 0.0194 m³.

c) The work done by the refrigerant during the expansion process is -28.5 kJ.

d) The heat transfer during the process is -5.35 kJ, which means heat is leaving the refrigerant.

a) The mass of the piston is not given in the problem statement, so it cannot be determined without additional information.

b) The final volume of the refrigerant can be determined using the ideal gas law. At the initial state, the pressure is 140 kPa and the temperature is 273 K. At the final state, the pressure is 95.9 kPa and the temperature is 251 K. Using the ideal gas law, the final volume is

c) The work done by the refrigerant during the expansion process can be determined using the formula W = -∫PdV, where P is the pressure and V is the volume. Since the process is reversible and adiabatic, we can use the ideal gas law to obtain the relationship \(PV^{y}\) = constant, where γ is the ratio of the specific heats. Since the process is isentropic, the entropy change is zero and the polytropic exponent is the same as the ratio of specific heats. Thus, we have

d) The heat transfer during the process can be determined using the first law of thermodynamics, which states that

Q = W + ΔU,

where ΔU is the change in internal energy of the refrigerant. Since the process is adiabatic,

Q = 0, and we have

ΔU = W. Thus, the heat transfer during the process is -5.35 kJ, which means heat is leaving the refrigerant.

To learn more about heat transfer, here

https://brainly.com/question/31065010

#SPJ4

A train travels at a speed of 24 m/s. Then it slows down uniformly at 0.065 m/s² until it stops the distance does the train travel while slowing down are 4430.75 m.

Distance measures length. For example, the gap of a street is how lengthy the street is. In the metric gadget of size, the maximum not unusualplace devices of distance are millimeters, centimeters, meters, and kilometers.

Read more about distance:

https://brainly.com/question/2854969

#SPJ1

Answer:

v = 134.06 m/s

Explanation:

Given that,

Radius of a circular track is 1,835 m

Time required to complete one lap around a perfectly circular track is 86 seconds

We need to find the car's velocity. Velocity is equal to,

v=d/t

On circular path,

\(v=\dfrac{2\pi r}{t}\\\\v=\dfrac{2\pi \times 1835}{86}\\\\v=134.06\ m/s\)

So, car's velocity is 134.06 m/s.

Answer:

when light goes from one medium to another, refraction is taken place. refraction is the bending of light. and the center part of the bending is called the reflected angle. the index of refraction is the measure of the bending of a ray of light when passed from one medium into another. the refracted angle is the angle between a refracted ray and the normal drawn at the point of incidence to the interface at which refraction occur.

Explanation:

I think I got all of the definitions. you can use the definitions to help you understand what you write about.

The electric field created by a point charge is given by the equation E = k * (Q / \(r^{2}\)).The charge of object A is -1.11 × \(10^{-9}\) C (option b).

In this case, the electric field at point P is 40.0 N/C directed to the south. Since the field is directed towards the south, the charge of object A must be negative. Plugging the given values into the equation, we have:

40.0 N/C = (9 × \(10^{9}\) N \(m^2/C^2\)) * (Q / (0.250 \(m)^2)\)

Simplifying the equation, we can solve for Q:

Q = (40.0 N/C) * (0.250 \(m)^2\) / (9 × 10^9 N \(m^2/C^2)\)

Calculating the expression, we find Q ≈ -1.11 × \(10^{-9}\) C. Therefore, the charge of object A is approximately -1.11 × \(10^{-9}\) C, which corresponds to option b.

Learn more about electric field here ;

https://brainly.com/question/11482745

#SPJ11

Answer:

Explanation:

According to ohm's law, V = IR where;

V is the supply voltage (in volts)

I is the current supplied (in amperes)

R is the resistance (in ohms)

Initially, I = 2A, hence V = 2*R;

V = 2R .................... 1

If the resistance in the circuit decreases to one-fourth of its original amount while the voltage remains constant, then the new resistance will be expressed as R₂ = 1/4 R and V₂ = V

Substituting the new conditions into the ohms law formula, we will have;

V₂ = I₂R₂

I₂ is the resulting new current

V = I₂ (1/4 R)

V = I₂ * R/4

V = I₂R/4 ...... 2

Substituting equation 1 into 2 we will have;

2R = I₂R/4

2 = I₂/4

cross multiply

I₂ = 4*2

I₂ = 8A

Hence the resulting new current is 8A

You were approximately 5.72 meters away from the second baseman. The vertical drop or distance between point A and point B was approximately 0.4576 meters.

To determine the distance between you (the shortstop) and the second baseman, we can use the formula for horizontal distance (d) traveled by an object moving at a constant horizontal velocity:

d = v * t

where:

- d is the horizontal distance traveled,

- v is the horizontal velocity of the ball,

- t is the time taken.

Given that the horizontal velocity (v) is 13 m/s and the time (t) is 0.44 s, we can calculate the horizontal distance (d) as follows:

d = 13 m/s * 0.44 s = 5.72 meters

So, you were approximately 5.72 meters away from the second baseman.

To find the vertical drop or the distance between point A and point B, we need to calculate the vertical component of the ball's motion. Since the ball is thrown horizontally, it will experience a constant vertical acceleration due to gravity.

The formula to calculate the distance (d) traveled vertically in free fall is:

d = 1/2 * g * t²

where:

- d is the vertical distance traveled,

- g is the acceleration due to gravity (approximately 9.8 m/s²),

- t is the time taken.

Given that the time (t) is 0.44 s, we can calculate the vertical distance (d) as follows:

d = 1/2 * 9.8 m/s² * (0.44 s)² = 0.4576 meters

So, the vertical drop or the distance between point A and point B is approximately 0.4576 meters.

To know more about vertical drop,

https://brainly.com/question/29192968#

#SPJ11

Answer: 2.67 m

Explanation:

k = Spring constant = 1.5 N/m

g = Acceleration due to gravity = 9.81 m/s²

l = Unstretched length

Frequency of SHM motion is given by

Frequency of pendulum is given by

Given in the question

The frequency of a simple pendulum made by hanging an apple from a long spring is half the bounce frequency.

Let the mass of the apple be m = 1.02 N, and the force constant of the spring be k = 1.50 N/m. When the apple is hanging from the spring, the restoring force on the apple is given by F = -kx, where x is the displacement from the equilibrium position.

According to Hooke's law, this force is directly proportional to the displacement and acts in the opposite direction. Therefore, the apple undergoes simple harmonic motion (SHM) with a period T = 2π√(m/k).

Now, when the apple is displaced and released from a small angle, it behaves as a simple pendulum. The period of a simple pendulum is given by T' = 2π√(l/g), where l is the length of the pendulum and g is the acceleration due to gravity.

Since the angle is small, the length of the spring does not change significantly, so we can assume that the length of the simple pendulum is the same as the unstretched length of the spring. Therefore, T' = 2π√(l/g) ≈ 2π√(k/mg), where g = 9.81 m/s² is the acceleration due to gravity.

The frequency of the bounce motion is given by f = 1/T, and the frequency of the pendulum motion is given by f' = 1/T'. From the above equations, we get:

f' = 1/T' = 1/(2π) √(mg/k) = 1/(2π) √(1.02*9.81/1.50) Hz

f = 1/T = 1/(2π) √(k/m) = 1/(2π) √(1.50/1.02) Hz

Therefore, the frequency of the simple pendulum is half the bounce frequency, as given in the problem statement.

To know more about simple pendulum refer here:

https://brainly.com/question/14759840#

#SPJ11

Answer:

Explanation:

The initial vertical velocity is 540sin55° = 442.342103... 442 m/s

The initial horizontal velocity is 540cos55° = 309.731275... 310 m/s

In the real world, both initial velocities would be reduced by air resistance and vertical velocity will be altered by gravity.

The Tip Speed Ratio (TSR) is the ratio of the speed of the wind turbine blade to the wind speed. It is defined as the speed of the blade tips divided by the wind speed and is represented by λ.

The Tip speed ratio is defined as the ratio of the wind speed at the tips of the turbine blades to the wind speed. The ratio is used to compare the performance of various wind turbines. The performance of the wind turbine is directly related to the tip speed ratio. This ratio is important as it helps in determining the amount of energy that can be harvested from the wind.

It is also important because it is used to measure the efficiency of a wind turbine. The higher the tip speed ratio, the more efficient the turbine is in capturing the energy from the wind.b) The operation of the wind turbine is optimized when the tip speed ratio changes. The tip speed ratio can be changed by altering the rotational speed of the blades, the length of the blades, or the wind speed. When the tip speed ratio is optimized, the wind turbine can operate at its maximum efficiency.

To know more about Speed Ratio visit:

https://brainly.com/question/33059348

#SPJ11

just ask safari

Explanation:

Answer:

8.45m/s = recoil speed

Explanation:

Momentum = mass • velocity

9.8kg • 88.03m/s = 102.1kg • recoil speed

862.694kg•m/s = 102.1kg • recoil speed

divide both sides by 102.1kg

8.45m/s = recoil speed

If you are keeping the speed constant and increasing the radius then the centripetal acceleration would decrease. An example of this would be driving a curve with an increasing radius (a spiral) at a constant speed. To understand why to remember that acceleration is the rate of change of velocity.

Answer:

241,274.32 inches

Explanation:

How far will he travel if the rear wheel makes 1200 revolutions on the road?

Since the rear wheel makes one revolution in the distance of a circumference of a circle, C with diameter, d = 16 inches

C = πd²/4

So, the distance, travelled in 1200 revolutions is D = 1200 × C = 1200πd²/4

Substituting d = 16 into D, we have

D = 1200πd²/4

D = 1200π(16)²/4

D = 76800π

D = 241,274.32 inches

A. The average drift speed of the electrons in the wire is  1.19 x \(10^{-3}\)cm/s.

B. The time it would take an electron to travel 8.84 m is 7.43 x \(10^{5}\)sec

(A) To find the average drift speed of electrons in a wire, we can use the equation:

I = nAvq

Where:
I is the current in Amperes
n is the electron density in electrons per \(cm^{3}\)
A is the cross-sectional area of the wire in \(cm^{2}\)
v is the average drift velocity of electrons in cm/s
q is the charge of an electron, which is 1.6 x \(10^{-19}\) Coulombs

First, we need to find the cross-sectional area of the wire. The formula for the area of a circle is:

A = π\(r^{2}\)

Where:
A is the area of the circle
r is the radius of the circle

Given that the wire diameter is 1.63 mm, we can find the radius by dividing it by 2:

r = 1.63 mm / 2 = 0.815 mm = 0.0815 cm

Now, we can calculate the area:

A = \(π(0.0815 cm)^{2}\) = 0.0209 \(cm^{2}\)

Next, we can rearrange the equation to solve for v:

v = I / (nAq)

Given that the current is 20 A and the electron density is 8.47 x \(10^{24}\)electrons per \(cm^{3}\), we can substitute these values into the equation:

v = 20 A / (8.47 x \(10^{24}\) electrons per cm^3 * 0.0209 cm^2 * 1.6 x \(10^{-19}\) C)

Simplifying the expression:

v = 1.19 x \(10^{-3}\) cm/s

Therefore, the average drift speed of electrons in the 14 gauge wire carrying a maximum current of 20 A is approximately 1.19 x \(10^{-3}\) cm/s.

(B) To calculate the time it would take for an electron to travel a distance of 8.84 m, we can use the formula:

t = d / v

Where:
t is the time in seconds
d is the distance in meters
v is the average drift velocity of electrons in meters per second

Given that the distance is 8.84 m and the average drift velocity is 1.19 x 10^-3 cm/s, we need to convert the velocity to meters per second:

v = 1.19 x \(10^{-3}\) cm/s * 0.01 m/cm = 1.19 x \(10^{-5}\) m/s

Now, we can substitute the values into the formula:

t = 8.84 m / 1.19 x \(10^{-5}\)m/s

Simplifying the expression:

t = 7.43 x \(10^{5}\)s

Therefore, it would take approximately 7.43 x \(10^{5}\) seconds for an electron to travel a distance of 8.84 m.

Know more about distance here:

https://brainly.com/question/26550516

#SPJ8