Tectonic plates are large segments of the Earth's crust that move slowly. Suppose one such plate has an average speed of 8.8 cm per year. (a) What distance does it move in 35 seconds at this speed (note that your answer should be in meters while your given speed is in cm/year)? (b) How many miles will the plate move in one million years at this speed?
Answer:
Jun 29, 2016 · Tectonic plates are large segments of the Earth’s crust that move slowly. Suppose that one such plate has an average speed of 4.0 cm/year. (a) What distance does it move in 1.0 s at this speed? (b) What is its speed in kilometers per million years?
Explanation:
Two students are canoeing on a river. While heading
upstream, they accidentally drop an empty bottle overboard. They
then continue paddling for 2 hours, reaching a point 2.5 km
farther upstream. At this point they realize that the bottle is
missing and, driven by ecological awareness, they turn around
and head downstream. They catch up with and retrieve the bottle
(which has been moving along with the current) 4.0 km downstream
from the turnaround point. (a) Assuming a constant paddling effort
throughout, how fast is the river flowing? (b) What would the canoe
speed in a still lake be for the same paddling effort?
The speed of the river flowing is 3.75 km/h, and the canoe speed in a still lake for the same paddling effort is 3.6 km/h (approximately).
The distance between the two points upstream and downstream is equal to the distance traveled by the empty bottle. Hence, the distance traveled by the bottle = distance traveled by canoeists = 4 km.Total distance traveled = distance upstream + distance downstreamTotal distance traveled = 2.5 + 4 = 6.5 kmTotal time taken = 2 hours upstream + (4/6) hours downstream (since they are covering 4 km in downstream with the current flowing downstream)Total time taken = 3.67 hours upstream + downstreamFrom the definition of speed, the speed upstream is given by:Speed upstream = distance/time upstreamSpeed upstream = 2.5/2Speed upstream = 1.25 km/hSimilarly, the speed downstream is given by:Speed downstream = distance/time downstream Speed downstream = 4/(4/6)Speed downstream = 6 km/hThe speed of the canoe in still water is given by the average of the upstream and downstream speeds:Speed in still water = (1.25 + 6)/2Speed in still water = 3.625 km/h or 3.6 km/h (approximately).
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Which condition can a food worker have, but would be allowed to continue to work?
A headache
An infected burn
Diarrhea
Answer:
headache
Explanation:
how does the rocket engine work?
Answer:
The vacuum of space
Heat management problems
The difficulty of re-entry
Orbital mechanics
Micrometeorites and space debris
Cosmic and solar radiation
The logistics of having restroom facilities in a weightless
Explanation:
find a vector(s) of length √15m in the x-z plane that is perpendicular to the vector A= (2i+3j+k) m
The vector that is perpendicular to the original vector is vector B = (√3 i - 2√3 k )
What is the vector that is perpendicular to the original vector?The vector that is perpendicular to the original vector is calculated as follows;
Let the vector = B = (xi + 0j + zk)
The dot product of A and B must be equal to zero.
A . B = (2i + 3j + k) . (xi + 0j + zk)
A.B = 2x + z = 0
2x = - z
The product of the vector must be √15 and it is calculated as;
√ (x² + z²) = √15
x² + z² = 15
Substitute the value of x for z;
x² + (-2x)² = 15
x² + 4x² = 15
5x² = 15
x² = 15/5
x² = 3
x = √3
z = - 2x
z = -2√3
The vector B = (√3 i - 2√3 k )
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How is the plot of output of dc generator different from the plot of output for an ac generator
The key difference between the two types of generators is that DC generators produce a constant and unidirectional output while AC generators produce a varying and alternating output.
How does the AC and DC generator works ?The output of a DC generator produces a steady, unidirectional current that flows in one direction. The plot of its output voltage versus time would be a straight line with no fluctuations or changes in direction.
On the other hand, an AC generator produces an alternating current that changes direction periodically, usually at a fixed frequency. The plot of its output voltage versus time would be a sinusoidal waveform with a repeating pattern of positive and negative values.
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If 2 particles are in phase that means they have the exact same pattern of _______________.
Answer:the shape
Explanation:
Answer:
oscillation Explanation: If two particles having the same phase it must either two consecutive troughs or two consecutive crests.What is revolution?
A. The motion of an object along a curved path
B. The spinning of an object on its axis
C. The orbit of a satellite around a central body
D. The motion of two objects around each other
Answer:
A. the motion of an object along a curved path
Two cars (A) and (B) travel in straight line. The distance of (A) from the starting point is given as a function of them be aA(t)=pt+qt2, with p=2.60ms−1 and q=1.20ms−2. The distance of (B) from the starting point is xB(t)=rt2−st3 are r=2.80ms−2 and s=0.20ms−3. Answer the following questions,
At what time (s) are the cars at the same point ?
At approximately 2.81 seconds the cars are at the same point. aA(t) is a linear function and xB(t) is a parabolic function.
Functions aA(t) and xB(t) describes the motion of two cars and both functions give the distance of each car from the starting point as a function of time, t.
aA(t) is a linear function and the components of the functions are constant velocity (p) and acceleration (q).
xB(t) is a parabolic function with components constant acceleration (r) and a component for constant jrk (s).
To find the time when the two cars are at the same location, we must first make the two distance expressions equal and then solve for t.
That is pt + qt² = rt² - st³
Now we have to solve this for t, we get
t = (-p + (p² + 4qr)^1/2) / (2q)
Now add the values for p,q,r,s to solve the equation
t = (-2.6 + (2.6² + 4 × 1.2 × 2.8)^0.5) / (2 × 1.2) = approximately 2.81 seconds.
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there are three basic rules of electric charge
The three basic rules for the electric charge are like charges repel each other, unlike charges attract each other and the charges in the system are constant. The unit of charge is coulomb (C).
Electric charge is of two types and they are positive and negative charges. The negative charge is free electrons and the positive charges are the holes in the conductors. The basic rules are, two positive charges repel each other and two negative charges repel each other and they are called like charges.
One positive and one negative charge attract each other and hence they are unlike charges. The attractional force and repulsion force increase with a decrease in the distance of separation. The charges remain constant in the system and it is called as law of conservation of charges in the system.
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A car moves from rest with an acceleration of 0.2ms
Find its velocity when it has moved a
distance of 50m
From the problem we notice that the question
does not involver. Therefore, the required equation
is)
Explanation:
Given:
Δx = 50 m
v₀ = 0 m/s
a = 0.2 m/s²
Find: v
The problem does not involve time. Therefore, the required equation is:
v² = v₀² + 2aΔx
Plug in values and solve:
v² = (0 m/s)² + 2 (0.2 m/s²) (50 m)
v = 4.47 m/s
The velocity of the car when it has moved a distance of 50 meters is approximately 4.47 m/s.
To find the velocity of the car when it has moved a distance of 50 meters, we can use the following equation of motion:
v² = u² + 2as
Where:
v = final velocity
u = initial velocity (which is 0 in this case as the car starts from rest)
a = acceleration
s = distance traveled
Plugging in the values into the equation:
v² = 0² + 2(0.2)(50)
v² = 0 + 20
v² = 20
Taking the square root of both sides:
v = √20
v = 4.47 m/s
Therefore, the velocity of the car when it has moved a distance of 50 meters is approximately 4.47 m/s.
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Please help. Incomplete/Irrelevant answers will be reported.
Fred is on the way to work. He left his house at 6:30 am. By 6:50, he was 30 minutes away from work and had already travelled 15 miles.
A) At this pace, how many more miles will Fred need to drive? How many miles did Fred drive in total?
B) Now assume Fred ran into traffic and will only get into his work at 7:50 am. What is the average speed of his path from home to work?
The time that Fred taken to cover a distance of 15 miles is 20 minutes or 0.3 hours. For next 30 minutes, he will cover a distance of 22.5 miles. Then the total distance he traveled is 37.5 miles.
What is average speed ?The average speed of a moving body is the measure of the distance covered per unit time. The common unit of speed is m/s. Other units are miles/hr., ft./s, km.hr etc.
Given, that within 20 minutes, Fred travels 15 miles. He have to drive 30 minutes more. Then the distance covered within next 30 minutes is :
(30× 15)/20 = 22.5 miles.
Thus in total Fred have to drive 22.5 + 15 = 37.5 miles.
If Fred reaches the office by 7.50 am the total time he taken from 6.30 am is 1.33 hr .
Then average speed = 37.5 miles/1.33 hr = 28 miles/h
Therefore, the average speed of Fred is 28 miles/hour.
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Calculate the mass of a car traveling at 35 m/s and has a kinetic energy of 76,562.5 J (Include units
We will have the following:
\(76562.5J=\frac{1}{2}m(35m/s)^2\Rightarrow m=125kg\)So, the mass of the object is 125 kg.
Calculate Time
d
12. A vehicle drives a distance of 26000 m at a speed of 65m/s, calculate the time taken for
this journey.
13. A train travels at a speed of 16 m/s and travel a distance of 3200 m, calculate the time it
takes the train to complete this journey.
urs 14. Calculate the time it takes to travel a distance of 672 km at a speed of 96 km/h.
15. A beetle travels at a speed of 0.09 m/s, it travels a distance of 1.08 m before it is caught
in a jar. Calculate the time taken for the beetle to run.
16. Carlisle is a distance of 35 miles away from Lockerbie. If I travelled at a constant speed
5147
deudate the time takon for this journey
12. The time taken for the journey is 400 s
13. The time taken for the train is 200 s
14. The time taken is 7 h
15. The time taken for the beetle is 12 s
16. The time taken for the journey is 0.0068 h
How do i determine the time taken?The time taken in each case as given by the question can be obtain as follow:
12. The time taken for the journey
Distance traveled = 26000 mSpeed = 65 m/s Time taken =?Time taken = Distance / Speed
Time taken = 26000 / 65
Time taken = 400 s
13. The time taken for the train
Distance traveled = 3200 mSpeed = 16 m/s Time taken =?Time taken = Distance / Speed
Time taken = 3200 / 16
Time taken = 200 s
14. The time taken to travel
Distance traveled = 672 kmSpeed = 96 Km/h Time taken =?Time taken = Distance / Speed
Time taken = 672 / 96
Time taken = 7 h
15. The time taken for the beetle
Distance traveled = 1.08 mSpeed = 0.09 m/s Time taken =?Time taken = Distance / Speed
Time taken = 1.08 / 0.09
Time taken = 12 s
16. The time taken for the journey
Distance traveled = 35 milesSpeed = 5147 mile per hourTime taken =?Time taken = Distance / Speed
Time taken = 35 / 5147
Time taken = 0.0068 h
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the diagram at right shows a person sitting in a chair riding on a ferris wheel. the chair is attached to the wheel by a rod. the ferris wheel turns with constant speed the mass of the person is two times that of the chair
The ranking of the boy's location in the ferris wheel ridding motion above comparing his felt weight from the highest to the lowest is 1, 2 and 4 tie, 3.
The correct answer choice is option c.
The correct image is attached.
Understanding the weight felt by the boy ferris wheel ridding.In motion above by the boy, the boy feels he weighs the greatest at location 3 among all the location simply because there is a force known as centripetal force which technically acts upward at that point which makes more weight be felt among all.
However, at the locations 2 and 4, the force actually was acting side ways, which would still not affect the weight from 3 in the circular movement. And at location, the weight felt feels the lowest among all.
In conclusion, the locations of the boy on a ferris wheel ridding from the greatest is highest to the lowest is 1, 2 and 4 tie, 3.
Complete question:
The diagram above represents a Ferris wheel-a circular ride that rotates in a vertical circle with seats where people sit. The numbers correspond to a seat in four difference places as the Ferris wheel rotates.
Imagine a boy sitting in this seat riding the ride with the Ferris wheel rotating in the direction shown (at constant speed). Rank the locations according to how much the boy would feel like he weighs,greatest first.
a. 1, 2, 3, 4
b. 1 and 3 tie, 2 and 4 tie.
c. 1, 2 and 4 tie, 3
d. 4, 3, 2, 1.
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when would a swimmer have the most potential energy due to her position
Answer: A
Explanation:
A swimmer have the most potential energy due to her position.When he is sitting on the highest diving board at the pool.
What is potential energy?The potential energy is the due to the virtue of the position and the height. The unit for the potential energy is joule.
The potential energy is found as;
\(\rm PE = mgh\)
The potential energy is mainly depending upon the height of the object.
When the swimmer is at the highest position, the height is maximum. Therefore, the potential energy is also maximum.
Hence, a swimmer have the most potential energy due to her position.When he is sitting on the highest diving board at the pool.
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A baseball and a golf ball have the same momentum. The kinetic energy of the baseball is ________ the golf ball.
Answer:
The kinetic energy of the baseball is GREATER than the golf ball.
Explanation:
a) A bus of mass 760 kg requires 120 m to reach certain velocity value Vf. Ignore friction and drag forces and assume the bus engine exerts a constant forward force F. When the bus is towing a 330-kg small car, how long distance needed to reach same Vf? b) If the Vf of the bus is 28 m/s, what is the tension in the tow cable between bus and small car?
Answer:
Given : A bus of mass 760 kg requires 120 m to reach certain velocity value Vf.
the bus engine exerts a constant forward force F.
To Find : When the bus is towing a 330-kg small car, how long distance needed to reach same Vf?
Solution:
V² - U² = 2aS
V = Vf
U = 0
S = 120 m
=> Vf² - 0 = 2a(120)
=> Vf² = 240a
m = 760 kg
Force = F
F = ma
=> F =760 a
=> a = F/760
Vf² = 240F/760
Case 2 :When the bus is towing a 330-kg small car,
m = 760 + 330 = 1090 kg
a = F/1090
Vf² = 2aS
=> 240F/760 = 2 (F/1090) S
=> S = 120 x 1090 /760
=> S = 172.1 m
172.1 m distance needed to reach same Vf
Explanation:
answer the question in the picture
The option that represents what the magnetic field look like above the North pole is an arrow that decreases as we go up and points up (E)
How to explain the informationThe magnetic field lines of a magnet point away from the north pole and towards the south pole. The field lines are strongest at the poles and weaken as you move away from the poles.
So, the arrow that represents the magnetic field above the north pole will be pointing up, but it will become smaller and smaller as you go up.
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You are asked to compare an experimental value of 2.90N to the accepted value of 2.78N. What is the percentage error between these two values
The percentage error is between the two values 4.32%.
What is percentage errror?Percent error is the difference between experimented value and the accepted value in comparison to the actual value and is expressed as a percentage.
To calculate the percentage error between the two values, we use the formula below.
Formula:
E(%) = [(Fe-Fa)/Fa]100.......... Equation 1Where:
E(%) = Percentage errorFe = Experimented valueFa = Accepted valuesFrom the question,
Given:
Fe = 2.90 NFa = 2.78 NSubstitute these values into equation 1
E(%) = [(2.90-2.78)/2.78]100E(%) = (0.12/2.78)100E(%) = 4.32%Hence, the percentage error is 4.32%.
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If you increase the frequency of a sound wave four times, what will happen to its speed?
А
The speed will increase four times.
B.
The speed will decrease four times,
C. The speed will remain the same.
D.
The speed will increase twice.
E.
The speed will decrease twice.
A woman of mass 55 kg stands on the rim of a frictionless merry-go-round of radius 2.0m and rotational inertia 1250 kg-m2 that is not moving. She throws a rock of mass 350g horizontally in a direction that is tangent to the outer edge of the merry-go-round. The speed of the rock, relative to the ground, is 2.0m/s. Afterward, what are (a) the angular speed of the merry-go-round and (b) the linear speed of the woman
Answer:
a) \(\omega=9.10*10^{-4}rad/sec\)
b) \(V=1.8217*10^{-3}\)
Explanation:
From the question we are told that:
Mass of woman \(M_w=55kg\)
Radius of merry go round \(r=2.0m\)
Rotational inertia \(i= 1250 kg-m2\)
Mass of rock \(M_r=350g \approx 0.350kg\)
Speed of rock \(V_r=2.0m/s\)
Tangent angle to the outer edge \(\theta=1\)
a)
Generally the equation for conservation of momentum is mathematically given by
\(M_r(ucos\theta)r=(I+M_wr^2)\omega\)
\(0.350(2.0cos1)(2.0)=(1250+(55)(2.0)^2)\omega\)
\(1.3998=1470\omega\\\omega=\frac{1.339}{1470}\)
\(\omega=9.10*10^{-4}rad/sec\)
b)
Generally the equation for linear speed V is mathematically given by
\(V=r\omega\\V=2.0*9.10*10^{-4}\)
\(V=1.8217*10^{-3}\)
A 0.32 kg toy mouse was on a couch that is 0.35m high. A car picks up the mouse and puts it in a nearby bookcase that is 2.85m high. How much work did the cat do?
A 0.32 kg toy mouse was on a couch that is 0.35 m high, a car picks up the mouse and puts it in a nearby bookcase that is 2.85 m high, and the car did 7.84 J of work.
What is the significance of the work done in the calculation?The work done by the car is calculated by ΔPE = mgh ,
(here the m=mass(0.32 kg)
g = acceleration(9.8 \(m/s^2\))
h= change in height (2.85 m - 0.35 m = 2.50 m)
ΔPE = 0.32 kg x 9.8 \(m/s^2\) x 2.50 m = 7.84 J
Hence, a 0.32 kg toy mouse was on a couch that is 0.35 m high, a car picks up the mouse and puts it in a nearby bookcase that is 2.85 m high, and the car did 7.84 J of work.
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anaerobic transmission is when you touch a contaminated surface true or false
Anaerobic transmission is when you touch a contaminated surface is a false statement.
What is anaerobic respiration?Anaerobic organisms are the living things that can survive and grow where there is no oxygen in the surrounding environment so we can conclude that Anaerobic transmission is when you touch a contaminated surface is a false statement.
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answer and solution to this question
Frequency= 30 Hz, Period= 0.0333 s, Wave Number=15.708 rad/m, Wave Function= y(x, t) = 0.05 sin(15.708x - 94.248t), Transverse displacement= -0.013 m, Time= 0.297 s.
How to calculate the frequency?(a) To find the frequency (f), we can use the equation: wave speed = frequency x wavelength. Rearranging this equation, we get:
frequency = wave speed / wavelength
Substituting the given values, we get:
frequency = 12 m/s / 0.4 m = 30 Hz
Therefore, the frequency of the wave is 30 Hz.
To find the period (T), we can use the equation:
period = 1 / frequency
Substituting the frequency value we just calculated, we get:
period = 1 / 30 Hz = 0.0333... s (rounded to four decimal places)
Therefore, the period of the wave is approximately 0.0333 s.
To find the wave number (k), we can use the equation:
wave number = 2π / wavelength
Substituting the given values, we get:
wave number = 2π / 0.4 m = 15.708 rad/m (rounded to three decimal places)
Therefore, the wave number of the wave is approximately 15.708 rad/m.
(b) The wave function for a transverse wave on a string is given by:
y(x, t) = A sin(kx - ωt + φ)
where A is the amplitude, k is the wave number, x is the position of the point on the string, t is the time, ω is the angular frequency, and φ is the phase constant.
We already know the values of A, k, and ω from the previous calculations. To find φ, we can use the given initial condition: "at t = 0 end of the string has zero displacement and is moving upward". This means that y(0,0) = 0 and ∂y/∂t(0,0) > 0. Substituting these conditions into the wave function, we get:
0 = A sin(0 + φ)
∂y/∂t = -Aω cos(0 + φ)
Since sin(0 + φ) = sin(φ) = 0 (because sin(0) = 0), we get:
φ = nπ, where n is an integer
Since cos(0 + φ) = cos(φ) = 1 (because cos(0) = 1) and ∂y/∂t(0,0) > 0, we get:
n = 0 or 2
Therefore, the possible values of φ are 0 or 2π.
Substituting the values of A, k, ω, and φ, we get:
y(x, t) = 0.05 sin(15.708x - 94.248t)
Therefore, the wave function describing the wave is:
y(x, t) = 0.05 sin(15.708x - 94.248t)
(c) To find the transverse displacement of a wave at x = 0.25 m and t = 0.15 s, we can use the wave function we just found:
y(0.25, 0.15) = 0.05 sin(15.708(0.25) - 94.248(0.15))
y(0.25, 0.15) ≈ -0.013 m (rounded to three decimal places)
Therefore, the transverse displacement of the wave at x = 0.25 m and t = 0.15 s is approximately -0.013 m.
(d) To find how much time must elapse from the instant in part (c) until the point at x = 0.25 m has zero displacement,
From part (c), we know that the transverse displacement of the wave at x = 0.25 m and t = 0.15 s is approximately -0.013 m. We need to find the time it takes for this point to return to zero displacement.
We can use the wave function we found in part (b) and set y(0.25, t) = 0:
0 = 0.05 sin(15.708(0.25) - 94.248t)
Since sin(θ) = 0 when θ = nπ (where n is an integer), we get:
15.708(0.25) - 94.248t = nπ
Solving for t, we get:
t = (15.708(0.25) - nπ) / 94.248
To find the smallest positive value of t that satisfies this equation, we need to use the smallest positive value of n that makes the right-hand side of the equation positive (because we want to find the time it takes for the point at x = 0.25 m to return to zero displacement, which happens after the point has completed a full cycle). We can see from the equation that n must be an even integer to make the right-hand side positive. The smallest even integer greater than zero is 2. Substituting n = 2, we get:
t = (15.708(0.25) - 2π) / 94.248
t ≈ 0.297 s (rounded to three decimal places)
Therefore, the time it takes for the point at x = 0.25 m to return to zero displacement is approximately 0.297 s.
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. A ball weighs 120g on the earth surface,
i) What is its mass on the surface of the moon? 1mk
Answer:
WEIGHT ON MOON IS 0.2004N
Explanation:
mass of the body=120g=\(\frac{120}{1000}\)kg=0.12kg (we will convert g into kg)
gravity on moon=1.67m/s²( to find the mass of anybody on another we should know its gravity)
as we know that (from the formula of weight)
weight=mass×gravity
w=mg
w=0.12kg²×1.67m/s²
w=0.2004N
A food processor draws 8.47 A of current when connected to a potential difference of 110 V.
a. What is the power consumed by this appliance?
b. How much electrical energy is consumed by this food processor monthly (30 days) if it is used on average of 10.0 min every day?
c. Assume that the price of electrical energy is 7.00 $/kWh. What is the monthly cost of using this food processor?
2. The electric meter in a house indicates that the refrigerator consumes 70.0 kWh in a week.
a. What is the power consumption of the refrigerator?
b. Assuming it is connected to a potential difference of 120 V , how much current does the refrigerator draw?
3. The heating element of an electric broiler dissipates 2.8 kW of power when connected to a potential difference of 120 V.
a. What is the resistance of the element?
b. How much current does the broiler draw? Use two ways to find out, and verify your answer.
Answer:
i want the answer
Explanation:i want the answer
a. The power consumed by this appliance is 931.7W
b. The electrical energy is consumed by this food processor monthly (30 days) if it is used on average of 10.0 min every day is 4.65kWh
c. The monthly cost of using this food processor is 32.55 $
What is power?
The rate of consumption of energy is power. it is given by the product of potential difference(V) and current(I)
a. P = VI
here V = 110V . I = 8.47 A
P = 110 x 8.47 = 931.7W
hence power consumed is 931.7 W
b. electrical energy consumed by this food processor monthly (30 days) if it is used on average of 10.0 min every day is
E = P/t
Here, P = 931.7 W = 0.93kW
t = 10 x 30 = 300 min = 5 h
So, E =0.93 x 5 = 4.65 kWh
hence electrical energy consumed is 4.65kWh
c. The monthly cost of using the food processor is
given ,
Cost of one unit is 7.00$
Cost of 4.65 unit will be 7.0 x 4.65 = 32.55$
monthly cost of using the food processor is 32.55$
2.
a. Power consumption of refrigerator is 416 W
P = E/t
Here, E = 70 kwh . t = 1 week = 168 h
So, P= 70/168 = 0.416 kW = 416 W
b. Current drawn by the refrigerator is 3.46A
P = VI
Here, V = 120V, P = 416 W
So, I = P/V = 416/120 = 3.46 A
3.
a. The resistance of the element is 5.14 Ω
b. Current drawn by the boiler is 23,33A
What is resistance?Resistance is the hindrance caused in the flow of current
a. The resistance is given by \(R = v^{2} / P\)
here V = 120V , P = 2.8kW = 2800W
R = (120 x 120)/ 2800 = 5.14Ω
Hence Resistance of the boiler is 51.4Ω
b. V = IR so, I = V /R
Here, V = 120V , R = 5.14Ω
So, I = 120/51.4 = 23.33 A
Hence current drawn by the boiler is 23.33A
The alternate way to find the current is by using formula
P = VI
I = P/V
Since, P = 2800W, V = 120V
So, I = 2800/120 =23.33 A
Hence Current comes out to be the same from both the method which verifies the answer .
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A force of 570 N keeps a certain ideal spring stretched at a distance of 0.700 m.
A). What is the potential energy of the spring when it is stretched 0.700 m?
B). What is its potential energy when it is compressed 8.00 cm?
Answer:
399j and 456j
Explanation:
(a)spring energy= force * distance
spring energy=570 * 0.700= 399 joules
(b) convert 8.00 cm to m we have 0.08m
E =f * s
E=570 *0.08= 456j
The potential energy of the spring when it is stretched 0.700 m would be 199.5 Joules, and the potential energy when it is compressed 8.00 cm would be 2.60 Joules.
What is the spring constant?The spring constant is used to define the stiffness of the spring, the greater the value of the spring constant stiffer the spring and it is more difficult to stretch the spring.
The mathematical relation for calculating the spring constant is as follows
F = - Kx
As given in the problem, if a force of 570 N keeps a certain ideal spring stretched at a distance of 0.700 m.
k = 570 / 0.7
k = 814.28 N / m
The potential energy stored in spring when it is stretched 0.700 m
E = 1/2 kx²
=0.5×814.28×0.7²
= 199.5 Joules
The potential energy stored in spring when it is stretched 8 cm
E = 1/2 kx²
=0.5×814.28×0.08²
=2.60 Joules
Thus, the potential energy of the spring when it is stretched 0.700 m would be 199.5 Joules, and the potential energy when it is compressed 8.00 cm would be 2.60 Joules.
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Consider as a system the gas in a vertical cylinder; the cylinder is fitted with a piston on which a number of small weights are placed. The initial pressure is 200 kPa, and the initial volume of the gas is 0.04 m3 . (a) Let a Bunsen burner be placed under the cylinder, and let the volume of the gas increase to 0.1 m3 while the pressure remains constant. Calculate the work done by the system during this process. (b) Consider the same system and initial conditions, but at the same time that the Bunsen burner is under the cylinder and the piston is rising, remove weights from the piston at a rate such that, during the process, the temperature of the gas remains co
Answer:
Explanation:
a ) At constant pressure , work done = P x Δ V
= 200 x 10³ x ( .1 - .04 )
= 12 x 10³ J .
b )
At constant temperature work done
= n RT ln v₂ / v₁
= PV ln v₂ / v₁
= 200 x 10³ x .04 ln .1 / .04
8 x 10³ x .916
= 7.33 x 10³ J .
Calculate the quantity of heat energy which must be transferred to 2.25 kg of brass to raise its temperature from 20°C to 240°C if the specific heat of brass is 394 J/kgK.
The quantity of heat energy that must be transferred to 2.25 kg of brass to raise its temperature from 20 °C to 240 °C is 195030 J
How do i determine the quantity of heat energy?First, we shall list out the given parameters from the question. This is shown below:
Mass of brass (M) = 2.25 Kg Initial temperature of brass (T₁) = 20 °CFinal temperature of brass (T₂) = 240 °CChange in temperature of brass (ΔT) = 240 - 20 = 220 °CSpecific heat capacity of brass (C) = 394 J/kgKQuantity of heat energy (Q) =?The quantity of heat energy that must be transferred can be obtained as follow:
Q = MCΔT
= 2.25 × 394 × 220
= 195030 J
Thus, we can conclude quantity of heat energy that must be transferred is 195030 J
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