How long will it take a shell fired from a cliff at an initial velocity of 800 m/s at an angle 30.

Answer:

When you squeeze a bottle that has a balloon attached to its opening, the pressure inside the bottle increases. This increased pressure will cause the air molecules inside the bottle to move closer together, which in turn will cause the balloon to inflate.

If you continue to squeeze the bottle, the pressure inside the bottle will continue to increase, and the balloon will continue to inflate. However, if you squeeze the bottle too hard, the balloon may burst due to the excess pressure.

When you release the pressure on the bottle, the air molecules inside the bottle will spread out again, causing the pressure to decrease. As a result, the balloon will deflate back to its original size.

Doubly charged baryons, such as the Δ⁺⁺ as well as Doubly charged mesons are known to exist. Thus the give statement is True.

Mesons, which are particles composed of a quark and an antiquark, can have charges of either +1 or -1. The charge of a meson is determined by the charges of its constituent quark and antiquark. Baryons, on the other hand, are particles made up of three quarks.

Doubly charged baryons, such as the Δ⁺⁺, have been observed and confirmed to exist. Similarly, mesons can also have different combinations of quarks, including doubly charged quarks. This means that doubly charged mesons also exist. For example, a doubly charged meson could be formed by a doubly charged quark and an antiquark with a charge of -1. These mesons play an important role in particle physics and are studied extensively to better understand the fundamental properties of matter.

In conclusion, it is true that doubly charged mesons exist. Doubly charged mesons exist alongside doubly charged baryons. They are particles composed of a quark and an antiquark, and their charge is determined by the charges of their constituent quark and antiquark. These mesons are an important area of study in particle physics and contribute to our understanding of the fundamental properties of matter.

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To determine the position u of the mass at any time t, we can use the equation of motion for a mass-spring system without damping:n m * u''(t) + k * u(t) = 0

m = 2 lb / (32.2 ft/s^2) = 0.062 lb·s^2/ft

The spring constant k can be determined using Hooke's law:

k = F / x

where F is the force exerted by the mass and x is the displacement. In this case, the force F is the weight of the mass, and the displacement x is 6 in:

k = (2 lb) / (6 in) = (2 lb) / (6 in) * (1 ft/12 in) = 0.111 lb/ft

The equation of motion now becomes:

0.062 * u''(t) + 0.111 * u(t) = 0

To solve this second-order linear homogeneous differential equation, we assume a solution of the form u(t) = A * cos(ωt + φ).

Substituting this assumed solution into the equation of motion, we get:

-0.062 * A * ω^2 * cos(ωt + φ) + 0.111 * A * cos(ωt + φ) = 0

-0.062 * ω^2 + 0.111 = 0

Solving for ω, we get:

ω = sqrt(0.111 / 0.062) = 2.258 rad/s

From ω, we can determine the frequency f and period T:

f = ω / (2π) = 2.258 / (2π) ≈ 0.359 Hz

T = 1 / f ≈ 2.786 s

The amplitude A is determined by the initial conditions. When the mass is pulled down an additional 3 in (0.25 ft) and released, it reaches its maximum displacement, so A = 0.25 ft.

Therefore, the position u of the mass at any time t is given by:

u(t) = 0.25 * cos(2.258t)

To draw the graph of u(t), plot the position u on the y-axis and time t on the x-axis, using the equation u(t) = 0.25 * cos(2.258t). The graph will be a cosine wave with an amplitude of 0.25 ft.

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Answer:

a = 1.49m/s²

Explanation:

Find the diagram attached  

According to Newton's second law of motion

\sum Fx = ma

Fm - Ff = ma

Fm is the moving force

Ff is the frictional force

Fm = Wsin theta

Ff = μR = μWcos theta

Wsin theta - μWcos theta = ma

W is the weight = 50.1 * 9.8 = 490.98N

theta is the angle of inclination = 27.2°

μ is the coefficient of friction = 0.343

m is the mass = 50.1kg

a is the acceleration  

Substitute into the formula as shown;

Wsin theta - μWcos theta = ma

490.98sin27.2° - 0.343(490.98)cos 27.2° = 50.1a

224.423 - 149.78 = 50.1a

74.64 = 50.1a

a = 74.64/50.1

a = 1.49m/s²

Hence the acceleration of the block is a = 1.49m/s²

The image is approximately 9.33 cm away from the mirror, on the object's side.

To determine the image location formed by a converging mirror, we can use the mirror equation:

1/f = 1/d_o + 1/d_i

where:

f is the focal length of the mirror,

d_o is the object distance (distance of the object from the mirror), and

d_i is the image distance (distance of the image from the mirror).

In this case, the focal length (f) is given as 7 cm, and the object distance (d_o) is 4 cm.

Plugging in the values into the mirror equation:

1/7 = 1/4 + 1/d_i

To find the image distance (d_i), we can solve for it:

1/d_i = 1/7 - 1/4

1/d_i = (4 - 7) / (4 * 7)

1/d_i = -3 / 28

Taking the reciprocal of both sides:

d_i = 28 / -3

d_i ≈ -9.33 cm

The negative sign indicates that the image formed by the converging mirror is virtual and located on the same side as the object.

Therefore, the image is approximately 9.33 cm away from the mirror, on the object's side.

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Answer:

yes

Explanation:

because it is a diverging mirror

The factors that can change the pattern observed on a screen during Young's double-slit experiment are given below:1. Width of the slit. 2. Distance between slits. 3. Distance between slits and screen. 4. Wavelength of the incident light. 5. Refractive index of the medium.

The factors that can change the pattern observed on a screen during Young's double-slit experiment are given below:

1. Width of the slit. The width of the slit can influence the diffraction pattern that is observed on a screen. When the width of the slit decreases, the central maximum of the diffraction pattern becomes broader, and the intensity of the secondary maxima reduces.

2. Distance between slits. The distance between the slits in the double-slit experiment also affects the pattern on the screen. The distance between the slits is equal to the spacing between the maxima. If the spacing between the slits decreases, the distance between the maxima decreases, and vice versa.

3. Distance between slits and screen. The distance between the slits and the screen is also a factor that can affect the diffraction pattern. When the distance increases, the spacing between the maxima becomes wider, and the intensity of the maxima decreases.

4. Wavelength of the incident light. The wavelength of the incident light is another factor that affects the diffraction pattern on the screen. When the wavelength increases, the spacing between the maxima increases, and vice versa.

5. Refractive index of the medium. The refractive index of the medium in which the light travels can also influence the diffraction pattern observed on a screen.

When the refractive index of the medium changes, the position of the maxima changes as well. These are the factors that can change the pattern observed on a screen during Young's double-slit experiment.

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#1

True

All metals attract magnets

#2

Yes true

Away from magnetic field if you place something it won't attract that

#3

False

Its only possible in case of electromagnetic force fields .

#4

False

Electromagnetic force field

#5

True

The speeds are average and accelerated if pace explained his speed was 38km/h and fastest speed was 60km/h.

Pace was first moving at 38 km/h which was considered as  his average speed yet the fastest speed he went was 60 km/h so he accelerated up.

The average speed of a body in any  particular time interval is the distance covered by the body in that time interval divided by time. So if a particle covers a certain distance s in a time Time 1 to Time 2, then the average speed of the body is. In linear motion average speed is same as average displacement as distance and displacement in linear motion is same.

average speed=total distance travelled/total time taken

Now, talking about the accelerated speed which is highest speed attained by the object in its whole journey. Accelerated speed is variable in nature it regularly decrease or increase in small span of time.

Hence, correct speed are average, accelerated.

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(Complete question) is:

Pace left home at 8 AM to spend the day at an amusement park. He arrived at the park, which was 150 km from his house, at 10 AM. Pace explained that his speed was 38 km/h, which was a/an (accelerated / directional / instantaneous / average) speed, but the fastest speed he went was 60 km/h, which was a/an (directional / instantaneous / accelerated / average) speed.

The difference in mass between the smaller nuclei that fuse together and the newly formed heavier nucleus, called mass defect.

A tangible body's mass is the amount of matter it possesses. It's also a metric of inertial, or the resistance to velocity when a net force is exerted.

When two small, light nuclei collide and fuse to form a larger nucleus, this is known as nuclear fusion.

One helium nucleus has a mass that is less than the sum of four hydrogen nuclei.

The missing mass, also known as a mass defect, is transformed to energy and radiates outward.

Thus, the difference in mass between the smaller nuclei that fuse together and the newly formed heavier nucleus, called mass defect.

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The density of the object is 5911.94 kg/m³

An object's buoyancy is the upward force produced by a fluid in opposition to the weight of a partly or totally submerged object.

The buoyancy = weight of the object - weight in water

= 15 N - 13N

= 2 N

The buoyancy force can also be determined by using the expressed:

\(\mathbf{F_B = Volume (V) \times density ( \rho) \times g}\)

\(\mathbf{2 = Volume (V) \times788 \ kg/m^3 \times9.8 }\)

\(\mathbf{ Volume (V) = \dfrac{2}{ 788 \ kg/m^3 \times9.8 }}\)

volume (v) = 2.589 × 10⁻⁴m³

Recall that:

The mass of an object can be estimated by using the formula:

Weight = mass × gravity

mass = Weight / gravity

mass = 15/9.8

mass = 1.5306 kg

The density of the object can now be calculated using the relation

Density = mass/volume

Density = 1.5306 kg / 2.589 × 10⁻⁴m³

Density = 5911.94 kg/m³

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I understand that finals can be a stressful and overwhelming time. However, it's important to stay calm and focused so you can do your best. One of the most important things you can do is to start studying early and make a plan. Break down your study material into manageable chunks and set goals for each study session. Be sure to give yourself breaks and take care of your physical and mental health during this time.

Another helpful tip is to engage in active studying techniques, such as practicing with past exams or reviewing notes with a study group. This will help you better retain the information and identify any areas that need more attention. Additionally, try to stay organized by keeping track of deadlines and creating a schedule for each task. This can help you avoid last-minute cramming and reduce stress.

Lastly, remember to prioritize self-care during this time. Get enough sleep, eat healthy, and engage in stress-reducing activities such as meditation or exercise. It's important to take care of your well-being so you can perform your best during finals.

In summary, stay calm, make a plan, engage in active studying, stay organized, and prioritize self-care. Good luck with your finals!

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The process used in fire investigation to determine if and where electrical circuits were energized at the time of the fire is live circuit analysis.

This is a technique in which investigators use specialized equipment to measure the voltage and amperage levels of electrical circuits in the building. Live circuit analysis is conducted once the electrical power supply is re-established on-site for investigating the fire's origin and cause. It involves checking electrical outlets, appliances, and other devices that might have been connected to electrical circuits in the building.

This process is vital for determining whether an electrical fault or malfunction caused the fire and identifying the responsible parties for negligence. In summary, the live circuit analysis is a standard fire investigation procedure that can determine the presence and location of electrical faults that led to a fire. The technique provides insights for experts to reconstruct the origin and causes of the fire to prevent future tragedies.

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1) Frequency

2) I dont know this one sorry

Answer:14.8

Explanation:

Trust me

The distance will be = 14.85 m

A region around a charged particle or object within which a force would be exerted on other charged particles or objects.

given :

Charge (q)= 2.45*\(10^{-6}\) C

Electric field (EF) =  100 N/C

to find = ? distance (r)

Electric field = 1/4π∈o * (q/\(r^{2}\))

         100      = 9 * \(10^{9}\) *  ( 2.45*\(10^{-6}\) / \(r^{2}\))

          \(r^{2}\) = 220.5

          r= \(\sqrt{220.5}\)

          r = 14.85 m

The distance will be = 14.85 m

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When an engineering team reaches the stage of iterating to improve the solution in the engineering design process, there are various activities that the team might be doing. One of the most crucial activities at this stage of the design process is testing. Here are a few things that an engineering team might do to test and improve the solution:

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The armature speed is given in rpm, so we need to convert it to revolutions per second by dividing it by 60. The result is the terminal voltage of the generator, the terminal voltage of the given generator will be approximately 1.458 (no units).

To calculate the terminal voltage of the given 2 kW, 4 pole DC generator, we can use the formula:
Terminal Voltage = (Pole Flux × Armature Speed × Number of Conductors per Slot × Number of Parallel Paths)/(60 × Number of Poles)
Given:
\(Pole Flux = 0.05 Wb\)
\(Armature Speed = 1750 rpm\)
\(Number of Conductors per Slot = 4\)
\(Number of Parallel Paths = 1 (since it's a lap wound armature)\)
\(Number of Poles = 4\)

Plugging in the values into the formula:
\(Terminal Voltage = (0.05 × 1750 × 4 × 1)/(60 × 4)\)
Simplifying:
\(Terminal Voltage = 0.05 × 1750 × 4 × 1/240\)
\(Terminal Voltage = 350/240\)
\(Terminal Voltage = 1.458\)

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Answer:

A generator is a device that converts mechanical energy into electrical energy by rotating a coil of wire in a magnetic field.

The magnitude of the electric field on the surface of the rod, Esurface, can be expressed in terms of lambda (linear charge density), r0 (distance from the center of the rod to the surface), and ε0 (electric constant) as lambda r0 / (2ε0).

To rewrite the expression for the magnitude of the electric field on the surface of the rod, Esurface, in terms of lambda (linear charge density), r0 (distance from the center of the rod to the surface), and ε0 (electric constant or permittivity of free space), we can start by recalling the initial expression: Esurface = ρo r0 / (2ε0).

In this expression, ρo represents the charge density of the rod. However, instead of using charge density ρo, we want to express the electric field in terms of lambda (linear charge density), which is defined as the charge per unit length of the rod.

We can relate ρo and lambda by considering a small length element dl on the rod. The charge within this element can be expressed as dq = λ dl, where λ is the linear charge density. Therefore, we have ρo = λ / dl.

Now, let's rewrite the expression for Esurface in terms of lambda. Substituting the value of ρo in the initial expression:

Esurface = (λ / dl) * r0 / (2ε0)

Since we want to express Esurface in terms of lambda, we need to eliminate dl. The length element dl can be related to the radius r0 and the infinitesimal angle dθ subtended by dl at the center of the rod. It can be written as dl = r0 dθ.

Substituting this value into the expression for Esurface:

Esurface = (λ / (r0 dθ)) * r0 / (2ε0)

= λ / (2ε0 dθ)

Now, we can express dθ in terms of lambda, r0, and 0. Recall that for a uniformly charged rod, the total charge Q is given by Q = λL, where L is the total length of the rod. The angle dθ can be related to dl and L through the equation dθ = dl / r0 = λ dl / (r0 λ) = dl / (r0 L) = dL / (r0 L).

Substituting this value into the expression for Esurface:

Esurface = λ / (2ε0 dθ)

= λ / (2ε0 (dL / (r0 L)))

= λ r0 L / (2ε0 dL)

Finally, we can simplify the expression by noting that L / dL is the definition of lambda (linear charge density). Therefore, we can rewrite the expression as:

Esurface = lambda r0 / (2ε0)

Thus, the magnitude of the electric field on the surface of the rod, Esurface, can be expressed in terms of lambda (linear charge density), r0 (distance from the center of the rod to the surface), and ε0 (electric constant) as lambda r0 / (2ε0).

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(A) 0x7f0000 and (B) 0x7f0000 Explanation:The value of the variable a in both cases is 0x7f0000, which is equivalent to the decimal number 8126464. Because a << 12 shifts the bits of a to the left by 12 positions, the resulting value is 0x7f0000 in both cases.

However, there is a difference between the two implementations. In (a), the integer value of a is defined by using the int keyword, which means that a is a 32-bit signed integer, while in (b), the integer value of a is defined by using the byte keyword, which means that a is an 8-bit signed integer.

Therefore, if the value of a is greater than 127, which is the maximum value that can be stored in a byte variable, the result will be different.

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According to Jean Piaget, unrealistic idealism often occurs in adolescence as a result of egocentrism. The inability to distinguish between self and others is referred to as egocentrism.

The inability to distinguish between self and others is referred to as egocentrism. It is, more precisely, the incapacity to effectively assume or comprehend any viewpoint other than one's own.

Egocentrism may be present in every stage of life, including childhood, adolescence, and maturity.

Hence option B is correct. According to Jean Piaget, unrealistic idealism often occurs in adolescence as a result of egocentrism.

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Answer:

got it right⬇️✅

First, we shall determine the equivalent of R₂ and R₃. Details below:

R = (R₂ × R₃) / (R₂ + R₃)

R = (9 × 3) / (9 + 3)

R = 2.25 Ω

Now, we shall determine the equivalent resistance, Rₜ for the circuit. Details below:

Rₜ = R₁ + R

Rₜ = 2 + 2.25

Equivalent resistance (Rₜ) = 4.25 Ω

The total current, Iₜ can be obtained as follow:

Current = Voltage / resistance

Iₜ = 34 / 4.25

Total current (Iₜ) = 8 A

Voltage in series connection are different.

V₁ is in series connection with the total voltage of V₂ and V₃. Thus, it's value can be obtained as follow:

V = IₜR₁

V₁ = 8 × 2

V₁ = 16 V

Voltage in parallel connection is the same through out the circuit.

Thus, V₂ and V₃ are in parallel connection. Thus we can obtain their value as follow:

V₂ = V₃ = IₜR

V₂ = V₃ = 8 × 2.25

V₂ = V₃ = 18 V

We can obtain I₁ as shown below:

I₁ = V₁ / R₁

I₁ = 16 / 2

current 1 (I₁) = 8 A

We can obtain I₂ as shown below:

I₁ = V₂ / R₂

I₂ = 18 / 9

current 2 (I₂) = 2 A

We can obtain I₃ as follow:

I₃ = V₃ / R₃

I₃ = 18 / 3

current 3 (I₃) = 6 A

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Answer:

Explanation:

Given:

m = 5·10⁻²⁷ kg

V₁ = 2·10⁵ m/s

V₂ = 4·10⁵ m/s

D = 10cm = 0.10m

_______________

a - ?

The change in kinetic energy is equal to the work:

Ek₂ - Ek₁ = F·D

m·V₂² / 2 - m·V₁² / 2 = F·D

(m/2)·(V₂² - V₁²)  = F·D

Force:

F = (m/2)·(V₂² - V₁²) / D

F =   m·(V₂² - V₁²) / (2·D)

F = (5·10⁻²⁷)·( (4·10⁵)² - (2·10⁵))/ (2·0.10) ≈ 3·10⁻¹⁴ N

Answer:

1201 lbs

Explanation:

Given that in mammals, the weight of the heart is approximately 0.5% of the total body weight.

Let the weight of the heart of a mammal be H

And the weight of the total body be B

The linear model that can gives the heart weight in terms of the total body weight will be:

H = 0.005B

B.) To find the weight of the heart of a whale whose weight is 2.402 × 105 lbs, substitute the whole weight in the formula.

H = 0.005 × 2.402 × 10^5

H = 1201 lbs

Therefore, the weight of the heart of the whale is 1201 lbs

Answer:

Colour of any object is by the colour of light it reflects i.e if white light is incident on the object,it will reflect blue color.so it will appear blue.But if red light is incident on it,it will not reflect that and absorb it.so as it will not reflect any light it will appear black.

Explanation:

Hypotheses are related to theories in the following way: a wide range of hypotheses is used to create a theory (option A).

Hypothesis is a tentative conjecture explaining an observation, phenomenon or scientific problem that can be tested by further observation or experimentation.

On the other hand, theory is a coherent statement or set of ideas that explains observed facts or phenomena and correctly predicts new facts or phenomena not previously observed.

The relationship between the two is that a theory is an hypothesis confirmed by observation or experiment.

Therefore, hypotheses are related to theories in the following way: a wide range of hypotheses is used to create a theory.

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Wind, water, and gravity, temperature changes, and pressure changes are all causes of physical weathering.

Pressure is a measure of the force exerted per unit area. It is a physical quantity that is used to describe the intensity of a force distributed over a surface. In other words, it refers to the amount of force applied to an object or substance divided by the area over which the force is applied. Pressure can be measured in a variety of units, such as pascals (Pa), pounds per square inch (psi), atmospheres (atm), and torr. The most common unit of pressure in everyday life is probably psi or atm, while in scientific contexts, the SI unit pascal is often used. Pressure is an important concept in many fields of science and engineering. It plays a critical role in fluid dynamics, thermodynamics, and mechanics, among others. Understanding how pressure works is important in a variety of applications, such as designing hydraulic systems, measuring blood pressure, predicting weather patterns, and analyzing the behavior of gases.

Here,

Physical weathering, also known as mechanical weathering, is the breakdown of rocks into smaller pieces without any change in their chemical composition. Wind, water, and gravity can all cause physical weathering by physically breaking rocks into smaller pieces. Temperature changes and pressure changes can also cause physical weathering by causing rocks to expand and contract, which can lead to cracks and fissures.

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