How many acres are in 1 square mile? One acre is equal to 43,560 ft2.

Recall the definition of average velocity:

average v = ∆x / ∆t

The driver moves a distance of ∆x = 4.25 km = 4250 m in 2 min = 120 s, so the average velocity is

average v = (4250 m) / (120 s) ≈ 35.4 m/s

Under constant acceleration, the average velocity can also be computed by taking the average of the initial and final velocities:

average v = (initial v + final v) / 2

Solve for (final v) :

35.4 m/s = (20 m/s + final v)/2

final v ≈ 50.83 m/s

Recall the definition of average acceleration:

average a = ∆v / ∆t

Solve for a :

a = (50.83 m/s - 20 m/s) / (120 s)

a ≈ 0.257 m/s²

Answer: Insulator

Explanation:

An insulator is a material that restricts the flow of electricity or thermal energy.

Answer:

plastic or wood

Explanation:

Explanation:

(2.40 × 10⁷) × (3.10 × 10⁻⁵)

(2.40 × 3.10) × (10⁷ × 10⁻⁵)

7.44 × 10²

Rightward and downwards.  option B is the correct answer

Internal friction between the wedge and the block means that it won't affect the center of mass' motion. The external friction force exerted on the wedge by the ground causes the center of mass to shift to the right. The center of mass of a block moves downward due to the gravitational force (mg) acting on it.

Frictional Force:

When surfaces of two objects come into contact, the force called friction is what stops motion. In other words, friction weakens a machine's mechanical advantage and decreases the output to input ratio. In a car, reducing friction requires one-fourth of the energy required. Friction in the clutch and tires, however, also has an impact on how well the car can maintain its place on the road. One of the most significant occurrences in the physical universe is friction, a phenomenon that affects everything from machines to molecular structures to matches.

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Answer:

The change in storage in the reach that occurred, during the hour  = 43200 m3

The storage at the end of the hour = 129600 m3

Explanation:

Given

Storage =  3 hectare-meters

Inflow volume = 15 m3/s

Outflow volume = 20 m3/s

Storage in one hour of change

Inflow volume = 20 m3/s

Outflow volume = 20.5 m3/s

Outflow volume - Inflow volume = 0.5 m3/s = 0.5 * 24*60 * 60 = 43200 m3

Storage at the end of one hour

43200 m3 + (20-15) * 24*60 * 60 = 129600 m3

Answer:

Gravitational force related to distance because when an object is closer to the center of the earth the stronger the gravitational force is the farther an objects it from the center of the earth the weaker the gravitational force is. For example if you are on the moon there is no gravity because the gravitational force of the moon to the center of the earth is father away then for example standing on earth.

Answer:

19

Explanation:

I legit did this and it took 19.

In 2.90 seconds, a train can accelerate from 10.0 m/s to 15.0 m/s, and this train accelerates at a rate of 1.94 ms2/m/s2.

At the start of the trip, the train picks up speed as it accelerates. In the middle of the journey, it remains the same (where there is no acceleration). When the train comes to a stop, it gets smaller as it slows down.

Distance traveled by the train as a percentage of time is its speed. The time it takes for two trains to cross each other is determined by the length of the trains, say lengths a and b, and the speeds of the trains, x and y, respectively.

In 2.90 seconds, a train can accelerate from 10.0 m/s to 15.0 m/s, and this train accelerates at a rate of 1.94 ms2/m/s2.          

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Hi there!

We know that:

Force due to gravity = Mgsinθ

Force due to friction = μMgcosθ

Let the positive direction be directed in the direction of the block's acceleration, which is downward.

Thus:

ΣF = Mgsinθ - μMgcosθ

Solving for acceleration requires diving all terms by the mass, so:

a = gsinθ - μgcosθ

Substitute in given values. (g = 9.8 m/s²)

a = 9.8sin(30) - 0.3(9.8)cos(30) = 2.354 m/s²

Answer:

A. The maximum is 8cm. B. 5 pieces of wire.

Explanation:

To find each pieces' length we need to find what can divide both wires = 8cm

A. The maximum is 8cm.

The amount of pieces = 16m/8m = 2 pieces and 24m/8m = 3 pieces. 2 pieces + 3 pieces = 5 pieces of wire.

B. 5 pieces of wire.

Answer:

\(g=274\ m/s^2\)

Explanation:

Mass of the Sun, \(M=1.99\times 10^{30}\ kg\)

The radius of the Sun, \(r=6.96\times 10^8\ m\)

We need to find the acceleration due to gravity on the surface of the Sun. It is given by the formula as follows :

\(g=\dfrac{GM}{r^2}\\\\g=\dfrac{6.67\times 10^{-11}\times 1.99\times 10^{30}}{(6.96\times 10^8)^2}\\\\g=274\ m/s^2\)

So, the value of acceleration due to gravity on the Sun is \(274\ m/s^2\).

The acceleration due to gravity, in meters per second squared, on the surface of the Sun is \(296.88 \;m/s^2\).

Given the following data:

Gravitational constant = \(6.67 \times 10^{-11}\)

To calculate the acceleration due to gravity, in meters per second squared, on the surface of the Sun:

From the law of gravitational force, we have the formula:

\(g = \frac{Gm}{r^2}\)

Where:

Substituting the given parameters into the formula, we have;

\(g = \frac{6.67 \times 10^{-11} \times 1.99 \times 10^{30}}{(6.69 \times 10^8)^2} \\\\g= \frac{1.33 \times 10^{20} }{4.48 \times 10^{17}} \\\\g=296.88 \;m/s^2\)

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Answer:

The parent cell

Explanation:

Answer

Mitosis phase - The DNA in the parent cell nucleus makes a copy of itself and is then split between the two daughter cells during mitosis

Explanation

This is biology, not really physics.

a) It is the error present in the measuring instrument that causes it to register a value even when there is no input or output being measured.

b) An example of when you would have to allow for zero error is when using a measuring instrument like a vernier caliper or micrometer screw gauge.

a) Zero error refers to the deviation or discrepancy in the measurement instrument, where the indication or reading on the instrument is not zero when the quantity being measured is zero. In other words, it is the error present in the measuring instrument that causes it to register a value even when there is no input or output being measured.

Zero error can occur due to various reasons such as manufacturing defects, wear and tear, misalignment, or improper calibration of the instrument. It can be positive or negative, depending on whether the instrument reads higher or lower than the actual value.

b) An example of when you would have to allow for zero error is when using a measuring instrument like a vernier caliper or micrometer screw gauge. These instruments are commonly used to measure the dimensions of objects with high precision.

In a vernier caliper, for instance, zero error can occur when the jaws do not close perfectly when there is no object being measured. If the caliper shows a reading other than zero when the jaws are closed, it indicates the presence of zero error.

To obtain accurate measurements, the zero error needs to be accounted for and compensated. This can be done by adjusting the position of the zero on the scale or by subtracting the zero error value from the measured readings.

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Answer:

250 m/s

Explanation:

Velocity (v) = Frequency (f) × Wavelength (λ)

Velocity (v) = 25 Hz × 10 m

Calculating the multiplication:

Velocity (v) = 250 m/s

When the bus is fully loaded, the center of gravity rises to 1.73 m, and the critical angles are 35.3 degrees for the unloaded bus and 30.6 degrees for the loaded bus, respectively.

Theoretically, the body's total weight is concentrated at a location called the center of gravity.

The main distinction between the centers of mass and gravity is that the center of gravity refers to the location where the total weight of the body is balanced, whereas the center of mass refers to the location where the body's complete mass is directed.

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The tank division's total displacement from the base is approximately 75.9 miles at a bearing of W67.4S.

To calculate the total displacement of the tank division, we need to find the vector sum of the two legs of their journey.

We can see that the tank division travelled 30 miles to the west (W30) and then 70 miles to the north (N70), so their total displacement is the vector sum of these two legs.

To add vectors, we need to break them down into their horizontal and vertical components.

For the first leg, the tank division travelled 30 miles to the west, so its horizontal component is -30 (since it's to the left of the base) and its vertical component is 0 (since it didn't travel up or down).

For the second leg, the tank division travelled 70 miles to the north, so its horizontal component is 0 (since it didn't travel left or right) and its vertical component is 70 (since it travelled directly north).

Now we can add these components to get the total displacement:

Horizontal component = -30 + 0 = -30

Vertical component = 0 + 70 = 70

So the total displacement is a vector with a horizontal component of -30 and a vertical component of 70.

We can use the Pythagorean theorem to find the magnitude of this vector:

|displacement| = √((-30)² + 70²) ≈ 75.9 miles

And we can use trigonometry to find the direction of this vector:

\(\theta = tan^{-1}\dfrac{70} { -30}\)

θ ≈ -67.4°

So the tank division's total displacement from the base is approximately 75.9 miles at a bearing of W67.4S.

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If a planet has an orbital eccentricity equal to 0.70, then its orbit is

Eccentricity is a measure of how squashed an ellipse is compared to a perfect circle.

The value of eccentricity ranges from 0 to 1, where 0 represents a perfect circle and 1 represents a parabolic orbit (which is not a closed orbit).

An eccentricity of 0.70 indicates that the planet's orbit is significantly elongated and not close to a perfect circle.

Therefore, the correct answer is - A very elongated ellipse.

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The mass of the lifted object, given the height the heavy load was elevated to and average power is 1, 013.85 kg.

To calculate the mass of the lifted object, we can use the work-energy principle, which states that the work done on an object is equal to its change in gravitational potential energy.

Calculate the work done by the lifter:

Power (P) = 1.2 kW = 1200 W (converting from kilowatts to watts)

Time (t) = 25 seconds

Work (W) = Power × Time = 1200 W × 25 s = 30,000 J (joules)

Calculate the change in gravitational potential energy:

Height (h) = 12 in = 12 × 0.0254 m = 0.3048 m (converting from inches to meters)

Gravitational acceleration (g) = 9.81 m/s²

Solve for mass (m):

Since the work done is equal to the change in gravitational potential energy, we have:

30,000 J = m × 9.81 m/s² × 0.3048 m

Now, we can solve for the mass:

m = 30,000 J / (9.81 m/s² × 0.3048 m) = 1, 013.85 kg

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Force of a body is calculated by mass times acceleration.

Acceleration = Velocity/Time

= 25/5

= 5 m/s²

Now,

Force = 1000 × 5

Force = 5000 N

Hence, 5000 N force is required to stop the bus in 5 second

The force required to stop the bus is 5000 N.

Given:

Acceleration (a) can be calculated using the formula:

a = (v' - v) / t

Substituting the given values, we have:

a = (0 - 25) / 5 = -5 m/s²

The force required to stop the bus can be calculated using Newton's second law of motion:

F = ma

Substituting the mass and acceleration, we get:

F = 1000 kg * (-5 m/s²) = -5000 N

Since the force cannot be negative, the magnitude of the force required to stop the bus is 5000 N.

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The displacement of the iguana between 0 and 5 seconds is 6 m and the distance is 15 m.

The displacement of an object is the change in the position of the object.

Displacement = change in position of the iguana

Displacement = position (5 seconds) - Position (0 seconds)

Displacement = 6 m - 0 m = 6 m

This the total path covered by iguana in the first 5 seconds.

Distance = speed x time

speed = (6 - 0) / (3 - 1) = 3 m/s

Distance traveled by 0 and 5 seconds = 5 x 3 m/s = 15 m

Thus, the displacement of the iguana between 0 and 5 seconds is 6 m and the distance is 15 m.

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Answer:

A

Explanation:

Answer:

A

Explanation:

Gases in the atmosphere absorb heat.

You know when you have a blanket around you and some heat gets trapped in but some still gets out. Thats basically what it is.

Plus I got it right in multiple questions including the test!

I hope that reassured you!

Have a good night!

Answer:

Approximately \(53^{\circ}\), assuming that the upper and lower surfaces of the glass on this boat are parallel.

Explanation:

Assume that the upper and lower surfaces of the glass at the bottom of this ship are parallel. Refer to the diagram attached. The two normals would also be parallel to each other.

The following angles would be alternate interior angles between the two normals:

Since the two normals are parallel to each other, these two angles would have the same value. Let \(\theta_{\text{glass}}\) denote the value of both of these angles.

Let \(\theta_{\text{src}}\) denotes the angle at which a beam of light leaves the original medium (angle of incidence.) Let \(\theta_{\text{dst}}\) denote the angle at which this beam of light enters the new medium.

Let \(n_\text{src}\) and \(n_\text{dst}\) denote the refractive indices of the original and the new medium, respectively. By Snell's Law:

\(\begin{aligned}\frac{\sin(\theta_{\text{dst}})}{\sin(\theta_{\text{src}})} = \frac{n_{\text{src}}}{n_{\text{dst}}}\end{aligned}\).

Let \(\theta_{\text{water}}\) denote the angle at which the beam of light in this question leaves the water. Let \(\theta_{\text{air}}\) denote the angle at which this beam of light enters the air. It is given that \(\theta_{\text{water}} = 37^{\circ}\), while \(\theta_{\text{air}}\) is the value that needs to be found.

Let \(n_{\text{air}}\), \(n_{\text{water}}\), and \(n_{\text{glass}}\) denote the refractive index of air, water, and glass, respectively. By Snell's Law:

\(\begin{aligned}\frac{\sin(\theta_{\text{glass}})}{\sin(\theta_{\text{water}})} = \frac{n_{\text{water}}}{n_{\text{glass}}}\end{aligned}\).

\(\begin{aligned}\frac{\sin(\theta_{\text{air}})}{\sin(\theta_{\text{glass}})} = \frac{n_{\text{glass}}}{n_{\text{air}}}\end{aligned}\).

Thus:

\(\begin{aligned} & \frac{\sin(\theta_{\text{air}})}{\sin(\theta_{\text{water}})} \\ =\; & \frac{\sin(\theta_{\text{glass}})}{\sin(\theta_{\text{water}})}\times \frac{\sin(\theta_{\text{air}})}{\sin(\theta_{\text{glass}})} \\ =\; & \frac{n_{\text{water}}}{n_{\text{glass}}}\times \frac{n_{\text{glass}}}{n_{\text{air}}} \\ =\; & \frac{n_{\text{water}}}{n_{\text{air}}}\end{aligned}\).

Since \(\theta_{\text{water}} = 37^{\circ}\):

\(\begin{aligned} & \sin(\theta_{\text{air}})\\ =\; & \sin(\theta_{\text{water}}) \times \frac{\sin(\theta_{\text{air}})}{\sin(\theta_{\text{water}})} \\ =\; & \sin(\theta_{\text{water}})\times \frac{n_{\text{water}}}{n_{\text{air}}} \\ =\; & \sin(37^{\circ}) \times \frac{1.33}{1.0} \\ \approx \; & 0.800 \end{aligned}\).

Therefore:

\(\begin{aligned}\theta_{\text{air}} &= \arcsin(\sin(\theta_{\text{air}})) \\ & \approx \arcsin(0.800) \\ &\approx 53^{\circ} \end{aligned}\).

In other words, this beam of light would leave the glass at approximately \(53^{\cic}\) from the normal.

Answer:

To determine the height to which the ball rises before it reaches its peak, we need to know the initial velocity of the ball and the acceleration due to gravity. Let's assume the initial velocity of the ball is v and the acceleration due to gravity is g.

The time it takes for the ball to reach its peak is one-half the total hang-time, or 1/2 * 6.25 s = 3.125 s.

The height to which the ball rises can be calculated using the formula:

height = v * t - (1/2) * g * t^2

Substituting in the values we know, we get:

height = v * 3.125 s - (1/2) * g * (3.125 s)^2

To solve for the height, we need to know the value of v and g. Without more information, it is not possible to determine the height to which the ball rises before it reaches its peak.

Explanation:

Answer:

Approximately \(47.9\; {\rm m}\) (assuming that \(g = 9.81\; {\rm m\cdot s^{-2}}\) and that air resistance on the baseball is negligible.)

Explanation:

If the air resistance on the baseball is negligible, the baseball will reach maximum height at exactly \((1/2)\) the time it is in the air. In this example, that will be \(t = (6.25\; {\rm s}) / (2) = 3.125\; {\rm s}\).

When the baseball is at maximum height, the velocity of the baseball will be \(0\). Let \(v_{f}\) denote the velocity of the baseball after a period of \(t\). After \(t = 3.125\; {\rm s}\), the baseball would reach maximum height with a velocity of \(v_{f} = 0\; {\rm m\cdot s^{-1}}\).

Since air resistance is negligible, the acceleration on the baseball will be constantly \(a = (-g) = (-9.81\; {\rm m\cdot s^{-2}})\).

Let \(v_{i}\) denote the initial velocity of this baseball. The SUVAT equation \(v_{f} = v_{i} + a\, t\) relates these quantities. Rearrange this equation and solve for initial velocity \(v_{i}\):

\(\begin{aligned}v_{i} &= v_{f} - a\, t \\ &= (0\; {\rm m\cdot s^{-1}}) - (-9.81\; {\rm m\cdot s^{-2}})\, (3.125\; {\rm s}) \\ &\approx 30.656\; {\rm m\cdot s^{-1}}\end{aligned}\).

The displacement of an object is the change in the position. Let \(x\) denote the displacement of the baseball when its velocity changed from \(v_{i} = 0\; {\rm m\cdot s^{-1}}\) (at starting point) to \(v_{t} \approx 30.656\; {\rm m\cdot s^{-1}}\) (at max height) in \(t = 3.125\; {\rm s}\). Apply the equation \(x = (1/2)\, (v_{i} + v_{t}) \, t\) to find the displacement of this baseball:

\(\begin{aligned}x &= \frac{1}{2}\, (v_{i} + v_{t})\, t \\ &\approx \frac{1}{2}\, (0\; {\rm m\cdot s^{-1}} + 30.565\; {\rm m\cdot s^{-1}})\, (3.125\; {\rm s}) \\ &\approx 47.9\; {\rm m}\end{aligned}\).

In other words, the position of the baseball changed by approximately \(47.9\; {\rm m}\) from the starting point to the position where the baseball reached maximum height. Hence, the maximum height of this baseball would be approximately \(47.9\; {\rm m}\!\).

This question is incomplete, the complete question is;

A gong makes a loud noise when struck. The noise gradually gets less and less loud until it fades below the sensitivity of the human ear. The simplest model of how the gong produces the sound we hear treats the gong as a damped harmonic oscillator. The tone we hear is related to the frequency f of the oscillation, and its loudness is proportional to the energy of the oscillation.

If the loudness drops to 90 % of its original value in 5.0 s , what is the time constant of the damped oscillation

Answer: the time constant of the damped oscillation is 47.44s

Explanation:

Given that;

t = 5.0s

Lets say Ao is the amplitude of initial loudness and later A(t) = 0.9 Ao

EXPRESSION for amplitude is  A(t) = Ao e^-t / T

t is time while T is time constant

so

0.9Ao = Ao e^-t / T  

0.9 = e^ -t/T

So we take the natural log of both the sides

ln (0.9) = -t/T

-0.1054 =  -t/T

0.1054 =  t/T

WE now substitute our value of t

0.1054 =  t/T

0.1054T =  5.0

T = 5 / 0.1054

T = 47.44s

therefore the time constant of the damped oscillation is 47.44s

Answer:

In an adiabatic process we have

pV γ = const..

This explains that the pressure is a function of volume, p ( V ) ,

So can be written as:

p ( V ) × V γ = p 0 V γ 0 ,

or p ( V ) = p 0 V 0 / V γ

= p 0 V 0 / V ^(7 / 5)

Answer:

\(0.4x40 \div 0.2 = 80\)

8N

For a longitudinal wave, the compression region, is the one represented by the densely packed particles with high pressure and the region with loosely packed particles is called rarefaction. Hence, the first part is C he dense region and the second one with some space between the dots is labeled as R.

Longitudinal waves are a type of mechanical waves passing through a medium. Unlike electromagnetic waves, they cannot be passed through vacuum.

In a longitudinal wave, the oscillation of particles is along the direction of wave propagation. The wave is composed of high pressure regions and low pressure regions called compressions and rarefactions respectively.

The regions where, particles are densely packed and shows the thick dote are labelled as compressions and the regions where, some space between particles are labeled as rarefactions.

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The correct answer is 5828.675 J.

Given combined mass 4kg and mass of bullet 150gm=0.150kg.

Total mass= 4+0.150=4.150kg

Velocity=53 m/s

Kinetic energy = \(\frac{1}{2} *m*v^{2}\) =0.5*4.150*\(53^{2}\) =5828.675 J

Kinetic energy is a type of power that an item or particle possesses as a result of motion. When an item undergoes work—the transfer of energy—by being subjected to a net force, it accelerates and consequently obtains kinetic energy. A moving object or particle's kinetic energy, which depends on both mass and speed, is one of its characteristics. Any combination of motions, including translation (or travel along a path from one location to another), rotation about an axis, and vibration, may be used as the type of motion.

A body's translational kinetic energy is equal to  \(\frac{1}{2} *m*v^{2}\) , or one-half of the product of its mass, m, and square of its velocity, v.

a trolley and a sandbag have a combined mass of 4 kg. a bullet with a mass of 150 gram is fired towards the trolley and is lodged in the sand bag immediately after the Collision, on the trolley and sandbag in combination with the bullet, move backwards at 53 metre per second calculate the kinetic energy of the trolley , with the sandbag and bullet ,directly after the Collision ​

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The law of conservation of matter stated that during a chemical reaction, the amount of matter stays the same. Thus, option B is correct.

Matter can be changed into other forms either by physical or chemical changes. But through any of these changes matter remains constant. The amount of matter present before the chemical reaction will remain the same after the chemical reaction. Thus, the matter can neither be created nor destroyed.

The law of conservation of matter is defined as the law of conservation of mass. Hence, in a system, the mass or matter remains conserved, before and after the chemical reaction and it was given by Antonie Lavoisier.

The law of conservation of matter states that during a chemical reaction, the amount of matter remains the same. Thus, the ideal solution is option B.

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