Answer:
2.5385 mol
Explanation:
do a quick conversion : 1 grams gold = 0.0050770041918285 mole using ...powered by AnyClip. 1 ... 500 grams gold to mol = 2.5385 mol
120 j 60 with an inductive reactance of 60 ohms. a capacitor bank of a capacitive reactance of 60 ohms is connected in parallel to the load. total reactive power supplied by the load is:
The total reactive power supplied by the load is dependent on the voltage and can be determined using the formula Q = V^2 / X, where X is the impedance of the load.
To find the total reactive power supplied by the load, we need to calculate the impedance of the load. Given that the load has an inductive reactance of 60 ohms and the capacitor bank has a capacitive reactance of 60 ohms, these two reactances cancel each other out when connected in parallel. Therefore, the total impedance of the load is equal to the resistance of the load, which is 120 ohms.
Reactive power (Q) can be calculated using the formula
Q = V^2 / X, where V is the voltage and X is the impedance.
Since the voltage is not given in the question, we cannot calculate the exact value of the reactive power. However, we can conclude that the total reactive power supplied by the load is directly proportional to the impedance and the square of the voltage.
In summary, the total reactive power supplied by the load is dependent on the voltage and can be determined using the formula Q = V^2 / X, where X is the impedance of the load.
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Converting from moles of one compound into moles of another compound in a chemical equation will require the:________
The answer is stoichiometric coefficient.
The stoichiometric coefficient is the number written in front of atoms, ions, and molecules in a chemical reaction to balance the number of elements.
What is stoichiometric coefficient?
For a reaction aA+bB→cC+dD, a,b,c,d are the stoichiometric coefficients.Now, these coefficients signify that a moles of A and b moles of B react to give c moles of C and d moles of D.So, if we have moles of reactants that take part in the reaction, then the number of moles of product formed can be calculated using stoichiometric coefficient.To learn more about stoichiometric coefficient visit:
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1. Explain why the ionization constant, Ka, for H2SO4 is larger than the ionization constant for H2SO3.
In the case of H2SO4 (sulfuric acid) and H2SO3 (sulfurous acid), the difference in their ionization constants can be attributed to the difference in their chemical structures and properties such as Number of ionizable hydrogen atoms,Strength of the oxyacid and Stability of resulting ions.
The ionization constant (Ka) is a measure of the extent to which an acid dissociates or ionizes in water. It represents the equilibrium constant for the dissociation reaction of an acid in water, where a higher value of Ka indicates a stronger acid.
Number of ionizable hydrogen atoms: Sulfuric acid (H2SO4) has two ionizable hydrogen atoms, while sulfurous acid (H2SO3) has only one ionizable hydrogen atom.
The presence of more ionizable hydrogen atoms in H2SO4 allows for more opportunities for ionization and the generation of hydronium ions (H3O+), contributing to a higher Ka value.
Strength of the oxyacid: Sulfuric acid is a stronger acid than sulfurous acid. The presence of additional oxygen atoms in sulfuric acid enhances its acidity and facilitates ionization.
The more electronegative oxygen atoms in H2SO4 draw electron density away from the hydrogen atoms, making them more acidic and easily dissociable.
In contrast, sulfurous acid has fewer oxygen atoms, resulting in weaker acidity and a lower propensity for ionization.
Stability of resulting ions: The stability of the ions formed upon ionization can also influence the ionization constant.
In the case of sulfuric acid, the sulfate ion (SO4^2-) formed after ionization is a highly stable species due to its symmetrical structure and resonance stabilization.
This stability contributes to the favorable dissociation of H2SO4 and a higher Ka value. On the other hand, the sulfite ion (SO3^2-) formed after the ionization of sulfurous acid is less stable, leading to a lower Ka value.
Considering these factors, the ionization constant (Ka) for H2SO4 is larger than the ionization constant for H2SO3. Sulfuric acid is a stronger acid with more ionizable hydrogen atoms and more favorable ionization characteristics, leading to a higher extent of dissociation and a larger Ka value compared to sulfurous acid.
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Please help with this
1. Double-Replacement reactions
2. Decomposition
3. Combustion
4. Syntesis
5. Single replacement
Further explanationGiven
Chemical equations
Required
Type of reaction
Solution
1. 2AgNO₃ + MgCl₂ ⇒ 2AgCl + Mg(NO₃)₂
Double-Replacement reactions. Happens if there is an ion exchange between two ion compounds in the reactant
2. 2KBr⇒2K +Br₂
Decomposition
Single compound breaks down in to 2 or more products
3. C₃H₈ + 5O₂ ⇒ 4H₂O + 3CO₂
Combustion
Hydrocarbon and Oxygen reaction and form water and carbon dioxide
4. NaO + H₂O ⇒ NaOH
Syntesis
2 or more reactants combine to form a single product
5. Zn + CuCl₂ ⇒ZnCl₂ + Cu
Single replacement
One element replaces another element from a compound
Part A Determine whether each of the preceding is exothermic or endothermic Drag the items into the appropriate bins. Reset Help exothermic endothermio Part B Indicate the sign of Δ H Drag the items into the appropriate bins. Reset Help positive negative Constants I Periodic Table Determine whether each of the following is exothermic or endothermic and indicate the sign of A H a. natural gas burning on a stove b. isopropyl alcohol evaporating from skin c. water condensing from steam
Natural gas burning on a stove is exothermic, isopropyl alcohol evaporating from skin is endothermic, and water condensing from steam is exothermic.
What is the difference between exothermic and endothermic reactions?a. natural gas burning on a stove: exothermic, negative ΔH (heat is released)
During the burning of natural gas, energy is released in the form of heat and light. This is an exothermic process as heat is being released to the surroundings, and the value of ΔH is negative.
b. isopropyl alcohol evaporating from skin: endothermic, positive ΔH (heat is absorbed)
During the evaporation of isopropyl alcohol from the skin, energy is required to overcome the intermolecular forces holding the liquid together and allow the molecules to escape into the air. This is an endothermic process as heat is being absorbed from the surroundings, and the value of ΔH is positive.
c. water condensing from steam: exothermic, negative ΔH (heat is released)
During the condensation of water from steam, energy is released as the water vapor loses heat and transitions back to a liquid state. This is an exothermic process as heat is being released to the surroundings, and the value of ΔH is negative.
exothermic processes release heat to the surroundings, resulting in a negative value for ΔH, while endothermic processes absorb heat from the surroundings, resulting in a positive value for ΔH.
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PLEASE HELP HELP ME. THIS IS DUE TODAY PLEASE
Answer:
C
Explanation:
cause i'm smart
Answer:
D
Explanation:
Because it says tree roots breaking rocks into smaller rocks.
Hope this helped!
how many moles are in 32.3g of calcium phosphate
Answer: the formula mass of calcium phosphate [Ca3(PO4)2] is 310.177 amu, so its molar mass is 310.177 g/mol. This is the mass of calcium phosphate that contains 6.022 × 1023 formula units.
Answer: 310.177
For each of the following pairs of compounds, choose which will elute faster in a TLC experiment (i. E. , which compound will have a larger Rf value). Explain what factors led to your choice. 6 pt a. Naphthalene or 1-Bromonaphthalene Choice Explanation: 1-Bromonaphthalene is more polar than Naphthalene. If polarity is higher, its Rf value will be less which means that molecule will travel less distance (lower Rf value) during a TLC experiment
In a TLC experiment, the compound with the larger Rf value will elute faster. In the case of naphthalene and 1-bromonaphthalene, the 1-bromonaphthalene will elute faster and have a larger Rf value.
This is because 1-bromonaphthalene is more polar than naphthalene. Polar compounds have a stronger attraction to the polar stationary phase (such as the silica gel in TLC plates) and will interact more with it, resulting in a lower Rf value.
Naphthalene, on the other hand, is less polar and will have a weaker interaction with the stationary phase, allowing it to travel further and have a higher Rf value.
The polarity of a compound is determined by the presence of functional groups or atoms that create an uneven distribution of charge or electronegativity. In this case, the bromine atom in 1-bromonaphthalene increases its polarity compared to naphthalene, leading to a stronger interaction with the stationary phase.
In summary, the 1-bromonaphthalene will elute faster in a TLC experiment and have a larger Rf value compared to naphthalene due to its higher polarity resulting from the presence of a bromine atom.
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Do the atoms in a mixture have a set ratio?
which phenomenon that goes unexplained by lewis structures is solved by applying molecular orbital theory?
Molecular Orbital Theory is used to explain phenomena that cannot be explained by Lewis Structures, such as the delocalization of electrons, the formation of molecular orbitals, and the stabilization of molecules.
Exploring the Benefits of Molecular Orbital Theory for Understanding Chemical BondingMolecular Orbital Theory provides a more elaborate description of chemical bonding than Lewis Structures by taking into account the wave-like nature of electrons. It uses quantum mechanics to explain the behavior of electrons in molecules, and the formation of molecular orbitals from the overlap of atomic orbitals. Molecular Orbital Theory also accounts for delocalization of electrons, which occurs when electrons spread across more than one atom, as well as the stabilization of molecules, which is the process of molecules forming more stable bonds. These phenomena, which cannot be explained by Lewis Structures, are solved by applying Molecular Orbital Theory.
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reviewe the first karyotype you assembled. how does the position of the centromere change among the different chromosome
A chromatid's centromere is the area that divides it into two arms. The kinetochore, which connects to the spindle fibres' microtubules, is located around the location of the duplicated chromosome. It aids in the correct division of chromosomes.
The centromere, which is located in the centre, separates the chromosome into two equal arms. Chromosome sub-metacentric or submedian centromere: The centromere is located closer to one end of the chromosome or a little off-center on each chromosome.
The four types of chromosomes—metacentric, submetacentric, acrocentric, and telocentric—are differentiated by the position of the centromere. As was already established, the centromere is easily pictured as the most condensed area of a mitotic chromosome.
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The complete question is:
How does the position of the centromere change among the different chromosome?
what are a few examples of what energy is?
✅Energy exists in many different forms✅
Examples of these are: light energy, heat energy, mechanical energy, gravitational energy, electrical energy, sound energy, chemical energy, nuclear or atomic energy and so on. Each forms can be converted or changed into the other forms.
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Question: What is the coefficient for OH−(aq) when MnO4−(aq) + Fe2+(aq) → Mn2+(aq) + Fe3+(aq) is balanced in basic aqueous solution?
In the balanced equation for the reaction\(MnO_{4}^-(aq) + Fe_{2} ^+(aq) -- > Mn_{2}^+(aq) + Fe_{3}^+(aq)\) in basic aqueous solution, the coefficient for OH−(aq) is 4.
To balance the given equation in basic aqueous solution, we need to ensure that the number of atoms of each element is equal on both sides of the equation and that the overall charge is balanced. Here's how the equation is balanced:
First, we balance the atoms other than hydrogen and oxygen. The equation becomes:
\(MnO_{4}^-(aq) + 5Fe_{2} ^+(aq)+8H_{2}O(l) -- > Mn_{2}^+(aq) +5 Fe_{3}^+(aq)\)
Next, we balance the oxygen atoms by adding water molecules (H2O):
\(MnO_{4}^-(aq) + 5Fe_{2} ^+(aq)+8H_{2}O(l) -- > Mn_{2}^+(aq) +5 Fe_{3}^+(aq)+4H_{2}O(l)\)
Now, we balance the hydrogen atoms by adding OH−(aq) ions:
\(MnO_{4}^-(aq) + 5Fe_{2} ^+(aq)+8H_{2}O(l) -- > Mn_{2}^+(aq) +5 Fe_{3}^+(aq)+4H_{2}O(l)+4OH^-(aq)\)
Therefore, in the balanced equation, the coefficient for OH−(aq) is 4. This balances the hydrogen atoms and ensures that the equation is balanced in basic aqueous solution.
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Which energy level has the most energy available to it?
4
3
2
1
A photon with a = 122 nm can excite an electron in hydrogen from n=1 to n=2. Which of the following statements are true?
A) A photon with wavelength 244 nm can be used to excite the electron from n=1 to n=2.
B) A photon with wavelength 61 nm can be used to excite the electron from n=1 to n=2.
C) A photon with wavelength 94 nm can be used to excite the electron from n=1 to n=2.
D) None of the above
None of the above.
The energy difference between two energy levels in the hydrogen atom is given by the equation:
ΔE = E₂ - E₁ = -R_H(1/n₂² - 1/n₁²)
where ΔE is the energy difference, E₂ and E₁ are the energy levels, R_H is the Rydberg constant, and n₂ and n₁ are the principal quantum numbers.
In this case, the photon with a wavelength of 122 nm can excite the electron from n=1 to n=2. To determine if other photons can also excite the electron to the same level, we can use the equation:
λ = c / ν
where λ is the wavelength, c is the speed of light, and ν is the frequency of the photon.
Using the given wavelength values, we can calculate the corresponding frequencies and then determine if the energy difference matches the required energy to excite the electron from n=1 to n=2.
Calculating the frequencies and energy differences for the given wavelengths, we find:
For 244 nm:
ν = c / λ = (3.00 x 10^8 m/s) / (244 x 10^(-9) m) ≈ 1.23 x 10^15 Hz
ΔE = E₂ - E₁ = -R_H(1/n₂² - 1/n₁²) = -R_H(1/2² - 1/1²) = -R_H(1/4 - 1) = 3/4 R_H
For 61 nm:
ν = c / λ = (3.00 x 10^8 m/s) / (61 x 10^(-9) m) ≈ 4.92 x 10^15 Hz
ΔE = E₂ - E₁ = -R_H(1/n₂² - 1/n₁²) = -R_H(1/2² - 1/1²) = -R_H(1/4 - 1) = 3/4 R_H
For 94 nm:
ν = c / λ = (3.00 x 10^8 m/s) / (94 x 10^(-9) m) ≈ 3.19 x 10^15 Hz
ΔE = E₂ - E₁ = -R_H(1/n₂² - 1/n₁²) = -R_H(1/2² - 1/1²) = -R_H(1/4 - 1) = 3/4 R_H
Conclusion:
None of the calculated energy differences match the required energy difference to excite the electron from n=1 to n=2, which is 3/4 R_H. Therefore, none of the given wavelengths can be used to excite the electron from n=1 to n=2.
None of the above statements are true. The given wavelengths cannot be used to excite the electron from n=1 to n=2 in hydrogen.
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What is reduced in the reaction below?
2H2 + 02 → 2H20
A. H20
B. 02
C. Reduction does not occur.
D. H2
SUBMIT
Answer:
\({ \underline{ \sf{O _{2} \: is \: reduced}}}\)
Explanation:
Reduction means when a reactant loses oxygen or gains hydrogen.
In the equation:
Hydrogen molecule, it neither gains nor loses hydrogen, but it gains oxygen. so :
\({ \sf{H _{2} \: is \: excluded}}\)
Oxygen molecule loses one oxygen atom, and gains four hydrogen atoms, hence it is reduced.
It is estimated that the total amount of oxygen (O₂) contained in BIFs is equivalent to 6.6% of the oxygen present in the modern atmosphere. This is quite impressive given that the atmosphere during Archaean and early Proterozoic times was largely devoid of oxygen! Therefore, this reflects the photosynthetic efficiency of the early biosphere, coupled with its operation over long periods of time. Knowing that the mass of the modern atmosphere is 5.01×10¹⁸ kg, of which 21% is oxygen, what is the mass (in kilograms) of oxygen contained within BIFs?
_____ ×10¹⁶ kg of O₂ contained in BIF deposits
Knowing that the molecular mass of O₂ is 32 g/ mole (0.032 kg/ mole ), how many moles of O₂ are contained within BIFs?
____ ×10¹⁸ moles of O₂ contained in BIF deposits
Now, let us think about iron (Fe). The total mass of BIF's globally is estimated at 5.0×10¹⁷ kg, wherein iron accounts for approximately 35% by mass. The atomic mass of iron is 55.8 g/mole(0.0558 kg/mole). What is the total mass of iron in BIFs in kilograms and moles?
_____ ×10¹⁷ kg of Fe contained in BIF deposits
_____ ×10¹⁸ moles of Fe contained in BIF deposits
Finally, take the values you have computed in units of moles, and express them as the molar ratio of iron (Fe) to oxygen (O₂) of BIFs. You can do this by dividing both sides of the ratio by the larger number (Fe in this case).
FeO₂=1 _____
Your calculated ratio above should fall between the Fe: O₂ molar ratios of both Hematite (1:0.75) and Magnetite (1:0.67). Which molar ratio is your calculated value closest to (meaning which iron component, Hematite or Magnetite, is the more dominate in BIFs)?
The calculated molar ratio of iron to oxygen in BIFs is 1.452.
Comparing this ratio to the molar ratios of Hematite (1:0.75) and Magnetite (1:0.67), we can see that the calculated value of 1.452 is closest to the Hematite molar ratio of 1:0.75. Therefore, Hematite is the more dominant iron component in BIFs.
To calculate the mass of oxygen contained within BIFs, we'll use the given information:
Total mass of the modern atmosphere = 5.01×10¹⁸ kg
Percentage of oxygen in the modern atmosphere = 21%
Mass of oxygen contained within the modern atmosphere = (5.01×10¹⁸ kg) × (0.21) = 1.051×10¹⁸ kg
Percentage of oxygen contained in BIFs = 6.6% (given)
Mass of oxygen contained within BIFs = (6.6% of 1.051×10¹⁸ kg) = 6.6/100 × 1.051×10¹⁸ kg = 6.9166×10¹⁶ kg
Therefore, the mass of oxygen contained within BIFs is 6.9166 × 10¹⁶ kg.
To calculate the number of moles of oxygen contained within BIFs, we'll use the molecular mass of O₂:
Molecular mass of O₂ = 0.032 kg/mole
Number of moles of oxygen contained within BIFs = (Mass of oxygen in BIFs) / (Molecular mass of O₂)
= (6.9166×10¹⁶ kg) / (0.032 kg/mole) = 2.1614375 × 10¹⁸ moles
Therefore, the number of moles of oxygen contained within BIFs is 2.1614375 × 10¹⁸ moles.
Next, let's calculate the mass of iron in BIFs:
Total mass of BIFs = 5.0×10¹⁷ kg
Percentage of iron in BIFs = 35%
Mass of iron contained within BIFs = (35% of 5.0×10¹⁷ kg) = 35/100 × 5.0×10¹⁷ kg = 1.75×10¹⁷ kg
To calculate the number of moles of iron contained within BIFs, we'll use the atomic mass of iron:
Atomic mass of iron = 0.0558 kg/mole
Number of moles of iron contained within BIFs = (Mass of iron in BIFs) / (Atomic mass of iron)
= (1.75×10¹⁷ kg) / (0.0558 kg/mole) = 3.1367419 × 10¹⁸ moles
Therefore, the number of moles of iron contained within BIFs is 3.1367419 × 10¹⁸ moles.
Finally, let's calculate the molar ratio of iron to oxygen in BIFs:
Molar ratio of iron to oxygen = (Number of moles of iron) / (Number of moles of oxygen)
= (3.1367419 × 10¹⁸ moles) / (2.1614375 × 10¹⁸ moles)
≈ 1.452
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When selecting a photometric technique that is more sensitive to a low concentration of analyte, a laboratory director compares absorbance measuring devices against those that measure fluorescence intensity. Which technique is considered more sensitive in its measurements and why
When selecting a photometric technique that is more sensitive to a low concentration of analyte, a laboratory director compares absorbance measuring devices against those that measure fluorescence intensity. Fluorescence spectroscopy is considered more sensitive in its measurements.
Spectro-fluorometer works on the above mentioned principle...
It uses a beam of light to excite the electrons from the given material which cause the emission of light from that matter.The emitted light is then brought towards a filter and onto a detector for measurement and identification of the changes in molecules of a sample material.Fluorometry is sensitive technique because light of particular wavelength is required as electrons are getting excited from ground state to emit the light and shows particular results which helps to know the sample material.Learn more about spectroscopy here..
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initially, your lungs contain 2.3 l of air at 1.05 atm. if you expand your lungs to 2.6 l, what is the new pressure inside your lungs?
If you expand your lungs to 2.6 l, the new pressure inside your lungs is 0.9346 atm.
The new pressure inside your lungs can be determined by using the Boyle's Law equation: P₁V₁ = P₂V₂. This equation relates the initial pressure and volume of a gas to the final pressure and volume of the same gas.
In this case, the initial pressure (P₁) is 1.05 atm, the initial volume (V₁) is 2.3 L, and the final volume (V₂) is 2.6 L. We need to find the final pressure (P₂).
Plugging in the given values into the equation:
P₁V₁ = P₂V₂
(1.05 atm)(2.3 L) = P2(2.6 L)
Dividing both sides by 2.6 L to isolate P₂:
P₂ = (1.05 atm)(2.3 L) / (2.6 L)
P₂ = 0.9346 atm
Therefore, the new pressure inside your lungs is 0.9346 atm.
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what is the minimum personal protective equipment (ppe) needed in the chemistry laboratory?
The minimum personal protective equipment (ppe) are glasses, gloves and protective coat
Personal Protective Equipment that is appropriate when working with laboratory. Gloves and lab coats are the simplest and most reliable types of safety equipment when there is a good chance that a splash will occur.
Labs do not allow open-toe footwear or sandals. Lab coats, aprons, or protective suits should be worn even if there is just a slight possibility of coming into contact with a very dangerous substance.
Use of specialist protective clothing is necessary to avoid skin contamination during exposures to strong acids.
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The minimum personal protective equipment (PPE) needed in a chemistry laboratory includes safety goggles, lab coat, gloves, and closed-toed shoes.
What is personal protective equipment (PPE)?PPE refers to all the equipment that someone can use to reduce workplace hazards to worker health and safety. In the chemistry laboratory it is very important to use personal protective equipment because people will be handling different substances and implements that may represent a danger to the safety of the people on site.
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What is the density of the continental crust?
Answer: Getting into the technicalities, the continental crust has a density of around 3.0 g/cm3 compared to 2.6 g/cm3 of the continental crust. In addition, the continental crust is much thicker than the oceanic crust.
Explanation:
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What do u mean by electronic configuration? What are basic requirements while writing electronic configuration of an element (atom) ?
The basic requirement while writing the electronic configuration of an element (atom) is its atomic number.
Explanation:
The electronic configuration of an element is the distribution of its electrons in different energy levels around the atomic nucleus.It only requires an atomic number of an element to write its electronic configuration.The atomic number is equal to the number of protons in an atom and that is equal to the number of electrons.And the filling of electrons is done according to the Aufbau principle, the electrons will be first filled in the atomic orbitals with lower orbital energy before filling the atomic orbital with higher energy.The sequence of the atomic orbitals from lower energy to higher energy is:\(1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, 4d, 5p, 6s, 4f, 5d, 6p, 7s, 5f, 6d...\)
For example:
The atomic number of gallium is 31, its electronic configuration will be:
\([Ga]=1s^2 2s^2 2p^63s^2 3p^6 4s^2 3d^{10} 4p^1\)
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Help please! I'll give brainliest to the most helpful answer :)
Answer:
synthesis d
Explanation:
did that at my school
After benzocaine is mixed with hydrochloric acid, it will be _______ and soluble in the ________.
After benzocaine is mixed with hydrochloric acid, it will be 4-aminobenzoic acid and soluble in the water.
Benzocaine, sold beneath the counter emblem called Orajel amongst over-the-counters, is an ester nearby ones over the counter normally used as a topical ache reliever or in cough drops. it's a far over-the-counter lively factor in many ones over counter ointments consisting of merchandise for oral ulcers.
Benzocaine is used to relieve aches and itching resulting from conditions that include sunburn or different minor burns, insect bites or stings, poison ivy, poison oak, poison sumac, minor cuts, or scratches.
Benzocaine is a local over-the-counter used in pain manage management, and it's far over-the-counter ester neighborhood ones over-the-counter elegance of medication. This pastime describes over-the-counter symptoms, actions, and contraindications for benzocaine as a valuable agent in coping with ache control.
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Which of the following terms is a chemical substance made of a single type of atom that cannot be broken down into a simpler substance?
A- nucleus
B- molecule
C- Compound
D- Element
pentanitrogen heptachloride formula
Answer:
Explanation:
this is the answer hope it helps!(:
The chemical formula of pentanitrogen heptachloride is N₅Cl₇ as it has 5 nitrogen atoms and 7 chlorine atoms.
What is chemical formula?
Chemical formula is a way of representing the number of atoms present in a compound or molecule.It is written with the help of symbols of elements. It also makes use of brackets and subscripts.
Subscripts are used to denote number of atoms of each element and brackets indicate presence of group of atoms. Chemical formula does not contain words. Chemical formula in the simplest form is called empirical formula.
It is not the same as structural formula and does not have any information regarding structure.It does not provide any information regarding structure of molecule as obtained in structural formula.
There are four types of chemical formula:
1)empirical formula
2) structural formula
3)condensed formula
4)molecular formula
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Which observation about the rock best supports this classification?
a. The rock is composed of several minerals.
b. The rock contains fragments of other rocks.
c. The rock has a vesicular texture.
d. The rock shows distorted and stretched pebbles.
The observation about the rock best supports this classification is the rock contains fragments of other rocks. Therefore, option B is correct.
What is the best way to classify a rock ?The classification of rocks is according to two criteria, i.e., texture and composition. The texture is refer with sizes and shapes of mineral grains and other constituents in a rock. These factors are controlled by the process which produced the rock.
Rocks are classified according to their properties such as mineral and chemical composition, permeability, texture of the constituent particles, and particle size. These physical characteristics are the result of the processes that produce the rocks.
Thus, The observation about the rock best supports this classification is the rock contains fragments of other rocks, option B is correct.
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A 4.5-cm-diameter, 0.50-mm-thick spherical plastic shell holds carbon dioxide at 2.0 atm pressure and 25∘C. CO2 molecules diffuse out of the shell into the surrounding air, where the carbon dioxide concentration is essentially zero. The diffusion coefficient of carbon dioxide in the plastic is 2.5×10−12 m2/s What is the diffusion rate in molecules/s of carbon dioxide out of the shell? Express your answer in molecules per second. Part B If the rate from part A is maintained, how long in hours will it take for the carbon dioxide pressure to decrease to 1.0 atm ? The actual rate slows with time as the concentration difference decreases, but assuming a constant rate gives a reasonable estimate of how long the shell will contain the carbon dioxide. Express your answer in hours.
The diffusion rate of carbon dioxide out of the shell can be calculated using Fick's first law of diffusion, which states that the diffusion rate is proportional to the diffusion coefficient, the surface area, and the concentration difference.
First, we need to calculate the surface area of the shell:
The diameter of the shell is given as 4.5 cm, so the radius is half of that, which is 2.25 cm.
The surface area of a sphere is given by the formula A = 4πr^2.
Plugging in the radius, we get A = 4π(2.25 cm)^2 = 63.59 cm^2.
Next, we need to calculate the concentration difference:
The carbon dioxide concentration inside the shell is given as 2.0 atm, while the concentration outside the shell is essentially zero. The concentration difference is therefore 2.0 atm - 0 atm = 2.0 atm.
Now we can calculate the diffusion rate using the formula diffusion rate = diffusion coefficient * surface area * concentration difference. Plugging in the given values, we get diffusion rate = (2.5×10^(-12) m^2/s) * (63.59 cm^2) * (2.0 atm) = 3.18×10^(-9) cm^3·atm/s.
To convert this to molecules per second, we need to use Avogadro's number, which is 6.022×10^23 molecules/mol. Since carbon dioxide has a molar mass of approximately 44 g/mol, we can convert the diffusion rate to molecules per second by multiplying it by Avogadro's number and dividing by the molar mass of carbon dioxide. The molar mass of carbon dioxide is 44 g/mol = 44000 mg/mol.
diffusion rate (in molecules/s) = (3.18×10^(-9) cm^3·atm/s) * (6.022×10^23 molecules/mol) / (44000 mg/mol) = 4.34×10^14 molecules/s.
So, the diffusion rate of carbon dioxide out of the shell is 4.34×10^14 molecules/s.
For Part B, we can use the diffusion rate from Part A to calculate the time it takes for the carbon dioxide pressure to decrease to 1.0 atm.
The initial pressure is 2.0 atm and the final pressure is 1.0 atm.
Since the rate is constant, we can use the formula time = (final pressure - initial pressure) / diffusion rate.
Plugging in the values, we get time = (1.0 atm - 2.0 atm) / (4.34×10^14 molecules/s) = -2.3×10^(-15) s.
To convert this to hours, we divide by 3600 s/hour and take the absolute value to get time = |(-2.3×10^(-15) s) / (3600 s/hour)| = 6.4×10^(-19) hours.
So, it will take approximately 6.4×10^(-19) hours for the carbon dioxide pressure to decrease to 1.0 atm, assuming a constant diffusion rate.
Learn more about Fick's first law of diffusion:
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BASIC CHEM I DONT THINK ITS THAT HARD IM JUST BAD
PLEASE HELP ME. URGENT
copper (II) sulphate reacts with iron metal
name the;
reactant and the state:
product and the state:
word equation:
balanced formula:
type of reaction:
Agriculture: Copper (II) sulfate is used as a fungicide to control plant diseases, while iron metal is used as a nutrient for plants.
Fe + CuSO4 Reaction.
Reactant and state: Copper (II) sulphate, solid (CuSO4.5H2O)
Product and state: Iron (II) sulphate, solid
(FeSO4) and Copper metal, solid (Cu)
Word equation: Iron metal + Copper (II) sulphate sulphate - Copper metal + Iron (II)
Balanced formula: Fe + CuSO4 Cu + FeSO4
Type of reaction: This is a single displacement or substitution reaction, where iron replaces copper in the copper sulfate compound.
ChatGPT
what are the the examples of amphoteric oxide
Answer:
Many metals (such as zinc, tin, lead, aluminium, and beryllium) form amphoteric oxides or hydroxides. Amphoterism depends on the oxidation states of the oxide. Al2O3 is an example of an amphoteric oxide.
Answer:
Lead (II) oxide and zinc (II) oxide