how many coulombs are required to produce 66.7 g of aluminum metal from a sample of molten aluminum fluoride?

Answer:

eachother or different type of flower

Explanation:

Answer:

study the natural world

Answer:

C, Scientists study the natural world

Explanation:

Science studies the natural world. This includes the components of the physical universe around us like atoms, plants, ecosystems, people, societies, and galaxies, as well as the natural forces at work on those things.

In an ecosystem, the coastal area  that is rotating toward the moon is the area where  tide rising to form a high tide.

Ecosystem is defined as a system which consists of all living organisms and the physical components with which the living beings interact. The abiotic and biotic components are linked to each other through nutrient cycles and flow of energy.

Energy enters the system through the process of photosynthesis .Animals play an important role in transfer of energy as they feed on each other.As a result of this transfer of matter and energy takes place through the system .

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7.11 grams will remain in 2 years from now.

What are two radioactive substances?

Radioactive substances are substances that contain atoms with unstable nuclei, which emit radiation in the form of alpha, beta or gamma rays. Two radioactive substances are uranium and radium. Uranium is a naturally occurring element that is radioactive, meaning it releases energy in the form of radiation. Radium is a radioactive element that is produced when uranium decays. Both substances can be found in the Earth's crust and can be used to generate electricity and power nuclear reactors.

Let the decay model be N(t) = N(0) e^rt

By data, we can write 8 = 9 * e^(r * 2)

8/9 = e^(2r)

2r = ln(8/9) = -0.1178

r = -0.1178/2 = -0.0589

Amount of the substance remaining 2 years from now = 8 * e^(-0.0589 * 2) = 7.11 grams

Therefore, 7.11 grams will remain in 2 years from now.

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Answer:

it might be able to get a heading to a earth

The statement that is true about chemical nutrients in an ecosystem is : D.) They recycle within the ecosystem, being constantly reused. Therefore, option D) is the correct answer.

The nutrient cycle is vital to the ecosystem, and this is how nutrients are recycled in it. Nutrients that are considered chemical nutrients include carbon, hydrogen, oxygen, nitrogen, and phosphorus.What are chemical nutrients in an ecosystem

Chemical nutrients refer to essential elements that are found in an ecosystem's physical and chemical environment. These elements are necessary for life because they are responsible for different functions such as cell structure, the production of enzymes, and the production of hormones.

In conclusion, chemical nutrients recycle within the ecosystem, being constantly reused. Nutrient recycling helps to maintain the ecosystem's sustainability. It helps to maintain the balance of life forms within the ecosystem.

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Answer:66.3L= 66300.00cm³

Explanation:The cubic centimeters equal to the Liters multiplied by 1,000.

Answer:

66,300 cubic centimeters

Explanation:

Hope this helps! Brainliest would be much appreciated! Have a great day! :)

Answer:

Explanation:

The percent composition of a compound is the percent of total mass made up by a ... data for a reaction of iron and oxygen which produces an iron oxide compound. ... 80.0 g sample of a compound that was 20.0 g element X and 60.0 g element y then the ... How can I calculate the percent composition of water in a hydrate?

Answer:

tell me how you want

this done?

Explanation:

Answer: One formula unit of NaCl consists of one cation, whose chemical symbol is \(Na^+\) and one anion whose chemical symbol is \(Cl^-\)

Explanation:

For formation of a neutral ionic compound, the charges on cation and anion must be balanced. The cation is formed by loss of electrons by metals and anions are formed by gain of electrons by non metals.  

The cation is formed by the metal sodium which forms  \(Na^+\) and the anion is formed by non metal chlorine which forms \(Cl^-\).

For a formula unit of sodium chloride,  the charges have to be balanced , thus the valencies of ions are exchanged and the neutral compound result. Thus

\(Na^+\) and  \(Cl^-\) combine to form neutral \(NaCl\)

Answer:

4

Explanation:

I just got it right on one of the assignments in Edge2020.

Answer:

The answer is 4

Explanation:

When measuring liquids, it is important to follow certain steps to ensure accuracy. You should always check the measurement at eye level on a counter top to ensure that the measurement is accurate.

You should also hold the measuring cup in your hand when measuring to make sure that you can see the level of the liquid. Additionally, you should pour off any excess liquids, leaving the amount measured, so that the measurement is precise. However, you should not use measuring spoons for amounts larger than 1/4 cup as this can lead to inaccurate measurements. It is important to use the appropriate measuring utensil for the amount needed to ensure the recipe turns out correctly.
When measuring liquids, you should do all of the following except hold the measuring cup in your hand when measuring. It is essential to check the measurement at eye level on a countertop to ensure accuracy. Pour off any excess liquids, leaving the measured amount. For amounts smaller than 1/4 cup, it is recommended to use measuring spoons to obtain precise measurements.

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1) The reaction is homogeneous because all reactants and products are in the gas phase.

2) The reaction is heterogeneous because the reactants are in different phases.

3) The reaction is heterogeneous because the reactants are in different phases.

4) The reaction is homogeneous because all reactants and products are in the gas phase.

5) The reaction is heterogeneous because the reactants are in different phases.

A homogeneous reaction is one in which all reactants and products are in the same phase. A heterogeneous reaction is one in which the reactants are in different phases. Therefore, the answers to the questions are:

Each of the reactions was analyzed to determine whether they are homogeneous or heterogeneous reactions. The results were recorded, and it was discovered that all of the reactions are either homogeneous or heterogeneous.

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The measurement that represents the most pressure is option c. 56.4 kPa (option c).

To determine which measurement represents the most pressure among the given options, we need to compare the values in the appropriate units.

a. 513 mmHg: This measurement represents pressure in millimeters of mercury. To compare it with other units, we need to convert it to a common unit.

  1 atm = 760 mmHg

  Therefore, 513 mmHg is approximately 0.674 atm.

b. 387 torr: Torr is another unit of pressure that is equivalent to mmHg. Since 1 torr is equal to 1 mmHg, we can directly compare it to the previous value.

  Therefore, 387 torr is approximately 0.509 atm.

c. 56.4 kPa: This measurement represents pressure in kilopascals. To compare it with other units, we need to convert it to a common unit.

  1 atm = 101.325 kPa

  Therefore, 56.4 kPa is approximately 0.556 atm.

d. 0.995 atm: This measurement is already given in atmospheres, which is a common unit of pressure.

Comparing the values, we can see that option c. 56.4 kPa has the highest value, approximately 0.556 atm. Therefore, option c represents the most pressure among the given options.

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The half-cell that houses the cathode is Half-cell B. The voltage of the cell is approximately 0.0297 V.

In a concentration cell, the cathode is the half-cell with the higher concentration of electrolyte. In this case, half-cell B has a higher concentration (0.87 M) compared to half-cell A (0.13 M).

Cathode: Half-cell B

To calculate the voltage of the cell, we can use the Nernst equation:

E_cell = E° - (RT/nF) * ln(Q)

For a Sn/Sn²⁺ concentration cell, the standard cell potential E° = 0 V, as both half-cells have the same redox reaction. The reaction quotient Q = [Sn²⁺ (A)] / [Sn²⁺ (B)].

Substituting the values and considering room temperature (25°C or 298.15 K), we get:

E_cell = 0 - ((8.314 J/mol·K * 298.15 K) / (2 * 96485 C/mol) * ln(0.13 M / 0.87 M)

E_cell ≈ 0.0297 V

Voltage of cell: 0.0297 V

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The percentage of copper (Cu) in the original mixture, calculated from the given data, is 188%. None of the given options (A, B, C, or D) accurately represent the calculated percentage.

To determine the percentage of copper (Cu) in the original mixture, we can use stoichiometry and the concept of limiting reactants.

From the balanced chemical equation:

1 mole of Cu reacts with 4 moles of HNO3 to form 1 mole of Cu(NO3)2.

Given that the students added 15.0 mL of 15.8 M HNO3, we can calculate the number of moles of HNO3 added:

moles of HNO3 = (15.0 mL) * (0.0158 mol/mL) = 0.237 mol HNO3

Since the stoichiometric ratio between Cu and HNO3 is 1:4, we need four times the moles of HNO3 for a complete reaction with Cu. Therefore, the number of moles of Cu in the original mixture can be calculated as:

moles of Cu = 0.237 mol HNO3 * (1 mol Cu / 4 mol HNO3) = 0.05925 mol Cu

Now we can calculate the mass of Cu in the original mixture:

mass of Cu = moles of Cu * molar mass of Cu

mass of Cu = 0.05925 mol * 63.55 g/mol = 3.76 g Cu

Finally, we can calculate the percentage of Cu in the original mixture:

percentage of Cu = (mass of Cu / total mass of the mixture) * 100

percentage of Cu = (3.76 g / 2.00 g) * 100 = 188%

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Answer:

data given

molarity 3.2m

moles 50mol

Required volume

Explanation:

from

molarity =mole/volume

3.2=50/v

v=15.62

:.volume is15.62dm^3

Answer:

A chemical solution is defined as a homogeneous mixture of two or more substances. There are two components of chemical solution that include solute and solvent.

Solute is the component that get dissolved in another substance and solvent is the substance that dissolve solute.

For example:  carbon dioxide in water. Where carbon-dioxide is solute and water is solvent.

Utilizing several well pads can drastically minimize the quantity of well pads, access roads, pipeline routes, and production facilities, decreasing habitat disruption, negative effects on the general population, and the environmental footprint overall.

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The long-chain molecules that consist of many repeating units are called polymers. Polymers are large macromolecules composed of monomer units that are chemically bonded together in a repetitive pattern.

The repeating units, also known as monomers, are linked through covalent bonds, creating a chain-like structure.

Polymers can have various sizes and complexity, ranging from simple structures like polyethylene to highly intricate and specialized macromolecules like proteins and DNA.

It is noticed that due to their repeating nature, polymers often possess unique physical and chemical properties, making them useful in a wide range of applications, including plastics, textiles, adhesives, and biomedical materials.

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Answer:

Over a vast amount of time, millions of years, the earth gradually cooled. When the temperature dropped enough, water vapor condensed and went from a gas to liquid form. This created clouds. From these clouds, the oceans formed and the oceans absorbed a lot of the carbon dioxide in the atmosphere.

Explanation:

Answer: it attaches to the fur of an animal, and it sprouts after it falls from the animal’s fur

Explanation:

To estimate the carbon-normalized sorption coefficient, sorption coefficient, and mass of organic contaminant per mass of sorbent, we need additional information such as the organic carbon partition coefficient (Koc) and the bulk density of the soil.

Carbon-Normalized Sorption Coefficient (Koc):

The carbon-normalized sorption coefficient represents the sorption capacity of the sorbent material for the organic contaminant. It is calculated by dividing the sorption coefficient (Kd) by the organic carbon content in the soil.

Koc = Kd / % organic carbon

Sorption Coefficient (Kd):

The sorption coefficient represents the ratio of the concentration of the contaminant adsorbed onto the sorbent material to the concentration in the aqueous phase.

Kd = (mass of contaminant sorbed / mass of sorbent) / (concentration of contaminant in water)

Mass of Organic Contaminant per Mass of Sorbent:

To calculate the mass of organic contaminant per mass of sorbent, we need to know the mass of the contaminant adsorbed onto the sorbent material and the mass of the sorbent itself.

Mass of organic contaminant per mass of sorbent = mass of contaminant sorbed / mass of sorbent

To perform these calculations, we need the organic carbon partition coefficient (Koc) and the bulk density of the soil. With this information, we can estimate the sorption characteristics of hexachlorobenzene in the given scenario.

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Answer:

Hydrological plant is a process in which plants needs water to complete the process to produce glucose in the presence of CO2 ,sunlight .plants needs water to survive .

When anion undergoes aerobic decomposition, a total mass of 2.28 kg O2 is required to biodegrade 1.4 g of the substance.

To determine the mass of O2 required to biodegrade 1.4 g of the given substance, we need to first determine the molar mass of the substance. From the given formula, we can see that the anion has a molar mass of 502 g/mol.

Using the given stoichiometric coefficients, we can write the balanced equation for the aerobic decomposition of the anion:

2C18H29SO−3(aq) + 51O2(aq) → 36CO2(aq) + 28H2O(l) + 2H+(aq) + 2SO2−4(aq)

From the balanced equation, we can see that 51 moles of O2 are required to biodegrade 2 moles of the anion. Therefore, the number of moles of O2 required to biodegrade 1 mole of the anion is:

51/2 = 25.5 moles of O2

The mass of O2 required to biodegrade 1 mole of the anion is:

25.5 moles × 32 g/mol = 816 g

Therefore, the mass of O2 required to biodegrade 502 g (1.4 g × 1000/502 = 2.79 moles) of the anion is:

2.79 moles × 816 g/mol = 2279 g or 2.28 kg (rounded to two decimal places)

In summary, 2.28 kg of O2 is required to biodegrade 1.4 g of the given substance.

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The current allowed to flow , Cr₂O₇²⁻ + Cr³⁺ and MnO₄ + Mn²⁺ + H⁺ species is oxidized .

The half-reaction with the highest reduction potential value will undergo reduction, while the half-reaction with the lowest reduction potential value will undergo oxidation, according to the reduction potential values.

b. The current allowed to flow  Cr₂O₇²⁻ + Cr³⁺ and MnO₄ + Mn²⁺ + H⁺ species is reduced.

c. MnO₄⁻ + 8H⁺ + 5e⁻ → Mn²⁺ + 4H₂O,             E° = 1.51 V

Cr₂O₇²⁻ + 14H⁺ + 6e⁻ → 2Cr³⁺ + 7H₂O,           E° = 1.33 V

For a Galvanic cell, the standard cell potential will be  : E°cell > 0

E°cell = E°cathode - E°anode = + 1.51 V - 1.33 V = + 0.18 V

∴ Cathode  : MnO₄⁻ + 8H⁺ + 5e⁻ → Mn²⁺ + 4H₂O

Anode : 2Cr³⁺ + 7H₂O → Cr₂O₇²⁻ + 14H⁺ + 6e⁻

Now, multiply the reaction at the cathode with 6 and the reaction at the anode with 5.

Cathode : MnO₄⁻ + 8H⁺ + 5e⁻ → Mn²⁺ + 4H₂O] × 6

Anode :      2Cr³⁺ + 7H₂O → Cr₂O₇²⁻ + 14H⁺ + 6e⁻] × 5

Now adding the two equations, to obtain the overall reaction:

6 MnO₄⁻ +  10Cr³⁺ + 11 H₂O → 6Mn²⁺ + 5Cr₂O₇²⁻ + 22 H⁺

Given: [MnO₄⁻] = 0.10 M, [Cr³⁺] = 0.40 M, [Mn²⁺] = 0.20 M, [Cr₂O₇²⁻] = 0.30 M, [H⁺] = 0.010 M

Presently placing these given upsides of convergence of species in the above condition, we get;

Q = [ 0.20M]⁶[0.30 M]⁵ [0.010 M]²² / [ 0.40 M]¹⁰[0.10 M]⁶

                                             = 1.48 × 10 ⁻⁴¹ ≈ 1.5 × 10 ⁻⁴¹

d. The external circuit directs the battery's current away from the positive terminal and toward the negative terminal, i.e, from left to right .

e . Mn²⁺ + 4H₂O       ------ E⁰₀ = 1.51 V

Cr₂O₇²⁻ + 14H⁺ + 6e⁻

2Cr³⁺ + 7H₂O  ------ E₀ = 1.33 V

Hence,

MnO₄⁻ + 8H⁺ + 5e⁻

Mn²⁺ + 4H₂O    ------ Reduction half-reaction

2Cr³⁺ + 7H₂O

Cr₂O₇²⁻ + 14H⁺ + 6e⁻   ------Oxidation half-reaction

Balance the electrons by increasing to every half-response by a basic entire number as follows:

MnO₄⁻ + 8H⁺ + 5e⁻

Mn²⁺ + 4H₂O       x 6

2Cr³⁺ +⁺ 7H₂O

Cr₂O₇²⁺  + 14H⁺ + 6e⁻   x 5

______________________

6MnO₄⁻ + 48H⁺ + 30e⁻

6Mn²⁺ + 24H₂O    

10Cr³⁺ + 35H₂O

5Cr₂O₇²⁻ + 70H⁺ + 30e⁻

____________________________________

6MnO₄⁻ + 48H⁺ + 10Cr³⁺ + 35H₂O

6Mn²⁺ + 24H₂O + 5Cr₂O₇²⁻ + 70H⁺

Thus,

6MnO₄⁻ + 10Cr³⁺ + 11H₂O

6Mn²⁺ + 5Cr₂O₇²⁻ + 22H⁺

Both the half-responses the electrons are something very similar and are 30. As a result, the balanced reaction results in 30 electron transfers.

f. The cell potential at 250 C as read on digital voltmeter =

                     E° = 1.51 V  -- 1.33 V

                                    = 0.18 V

Electrical potential is an estimation of the capacity of a voltaic cell to deliver an electric flow. Electrical potential is ordinarily estimated in volts (V). The electrical potential difference between the two half-cells is the voltage produced by a particular voltaic cell.

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20gm of hydrogen will have highest number of hydrogen atoms.

We know that 1 mole of substance contains atoms equal to Avogadro number i.e.  \(6.022*10^{23}\)

As molar mass of hydrogen is 1gm there 1 mole of hydrogen contains 1gm of hydrogen and \(6.022*10^{23}\) hydrogen atoms

If we take 1020 hydrogen atoms then it is very less than \(6.022*10^{23}\) hydrogen atoms.

In 100gm of substance if hydrogen is 2% by mass i.e. we have 2gm of hydrogen atom  which means 2 mole of hydrogen atoms

Mass of 1 mole of water is 18gm

Thus 100 gm of water have 5.55 moles of water

In 1 mole of water we have 2 grams of hydrogen

Therefore 5.55 moles of water contains 11.11gm of water i.e. 11.11 mole of water

11.11gm of water = \(11.11* 6.022 * 10^{23}\) atoms

In 20gm of hydrogen we have 20 mole of hydrogen

               i.e. \(20* 6.022 * 10^{23}\)

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Answer:

hope it helps

Explanation:

Karamchand gandhi

Answer:

Karamchand Uttamchand Gandhi shortly known as Kaba Gandhi. He is a political figure! :) give brainliest please

Explanation:

We would need 2.635 moles of AIPO₄ to produce 168.6g of oxygen.

To calculate the number of moles of AIPO₄ required to produce 168.6g of oxygen, we need to use stoichiometry. From the balanced chemical equation, we know that 1 mole of AIPO₄ produces 2 moles of O₂. We can use the molar mass of O2 to convert the given mass of oxygen to moles:

Molar mass of O₂ = 32 g/mol

Moles of O₂ = mass of O2 / molar mass of O2

                     = 168.6 g / 32 g/mol

Moles of O₂ = 5.27 mol

Since 1 mole of AIPO₄ produces 2 moles of O₂, we can use the mole ratio to calculate the number of moles of AIPO4 needed:

Moles of AIPO₄ = Moles of O₂ / 2

Moles of AIPO₄ = 5.27 mol / 2

Moles of AIPO₄ = 2.635 mol

As a result, 2.635 moles of AIPO₄ are required to create 168.6g of oxygen.

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