How many cubic miles are 8.48E+08 gallons of water? The density of water at ambient conditions is 1.000 g/mL.

Answer:

The correct answer is "transferred; unequally shared; equally shared".

Explanation:

Ionic bonding occurs when a positively charged atom (cation) interacts with a negatively charged atom (anion). In ionic bonding, the cation transfers its electron to the anion. In polar covalent bonding, electrons are unequally shared. This means that the electrons spend more time in an atom than the other, which gives partial positive and negative charges to the atoms. On the other hand in nonpolar covalent bonding, the electrons are equally shared and no charges are created.

Answer:

Do you mean Tennessine?

Explanation:

It's in the 7th period, and has the shorthand of Rn. And it's 5 into the row.

Answer:

Three objects with kinetic energy

A ball rolling down the street

Moving Car

Bullet

Law of Conservation of Energy states that the total energy of an isolated system remains constant; it is said to be conserved over time.

Though technically there are limitless forms of both types of energy, officially there's five types of kinetic energy: radiant, thermal, sound, electrical and mechanical and potential energy adds gravitational, nuclear, and elastic.

Answer: ΔH for the dissolution of \(NH_4NO_3\) is +26.0205 kJ/mol

Explanation:

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

\(Q=m\times C\times \Delta T\)

Q = Heat released by solution  = ?

C = heat capacity = \(4.18J/g^0C\)

Initial temperature of water  = \(T_i\) = \(25.008^0C\)

Final temperature of water  = \(T_f\)  = \(23.348^0C\)

Change in temperature ,\(\Delta T=T_f-T_i=(23.348-25.008)^0C=-1.66^0C\)

Putting in the values, we get:

\(Q=75.0g\times 4.18J/g^0C\times -1.66^0C=-520.41 J\)

As heat released by water is equal to heat absorbed by dissolution of \(NH_4NO_3\)  

\(\text{Moles of}NH_4NO_3=\frac{\text{given mass}}{\text{Molar Mass}}=\frac{1.60g}{80g/mol}=0.02mol\)  

Enthalpy change for 0.02 moles of \(NH_4NO_3\) = 520.41 J

Enthalpy change for  1 mole of \(NH_4NO_3\) = \(\frac{520.41}{0.02}\times 1=+26020.5J=+26.0205kJ\)

ΔH for the dissolution of \(NH_4NO_3\) is +26.0205 kJ/mol

(a)  The mass percent of HCl in the solution is approximately 36.1%.

(b)  The molality of HCl in the solution is approximately 15.5 mol/kg.

(c)  The mole fraction of HCl in the solution is approximately 0.218.

(a) To calculate the mass percent of HCl, we need to determine the mass of HCl in a given volume of the solution.

Given: Concentration of HCl = 11.8 M

Density of the solution = 1.190 g/mL

First, we need to calculate the mass of the solution. Since density is mass per unit volume, the mass of 1 mL of the solution is 1.190 g.

Next, we need to calculate the mass of HCl in 1 mL of the solution. Since the concentration is given in moles per liter (M), and the molar mass of HCl is 36.46 g/mol, we can calculate the mass of HCl in 1 mL as follows:

Mass of HCl = concentration × volume × molar mass

          = 11.8 mol/L × 0.001 L × 36.46 g/mol

          = 0.430 g

Now, we can calculate the mass percent of HCl using the following formula:

Mass percent = (mass of solute ÷ mass of solution) × 100

           = (0.430 g ÷ 1.190 g) × 100

           ≈ 36.1%

(b) The molality of HCl is calculated by dividing the moles of solute (HCl) by the mass of the solvent (water) in kilograms.

Since the density of the solution is given as 1.190 g/mL, the mass of 1 mL of the solution is 1.190 g. However, we need to consider the density of the solvent (water) to calculate the mass of water in the solution.

Assuming the density of water is 1 g/mL, the mass of water in 1 mL of the solution is (1.190 g - 0.430 g) = 0.760 g.

To calculate the molality of HCl, we need to convert the mass of water to kilograms:

Mass of water (kg) = 0.760 g ÷ 1000 = 0.000760 kg

The molality (m) is calculated using the formula:

Molality = (moles of solute ÷ mass of solvent in kg)

        = (11.8 mol/L × 0.001 L) ÷ 0.000760 kg

        ≈ 15.5 mol/kg

(c) The mole fraction (X) of HCl is calculated by dividing the moles of HCl by the total moles of all components in the solution.

To calculate the mole fraction, we need to consider the volume of the solution and convert it to liters.

Given: Concentration of HCl = 11.8 M

Volume of the solution = 1 mL

Volume of the solution (L) = 1 mL ÷ 1000 = 0.001 L

To calculate the mole fraction of HCl, we need to calculate the moles of HCl and the moles of water (solvent) in the solution.

Moles of HCl = concentration × volume

            = 11.8 mol/L × 0.001 L

            = 0.0118 mol

Moles of water = mass of water ÷ molar mass of water

             = 0.760 g ÷ 18.015 g/mol (molar mass of water)

             = 0.0422 mol

Total moles in the solution = moles of HCl + moles of water

                           = 0.0118 mol + 0.0422 mol

                           = 0.054 mol

Mole fraction of HCl = moles of HCl ÷ total moles

                   = 0.0118 mol ÷ 0.054 mol

                   ≈ 0.218

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Based on the information provided, we have a reaction between hydrogen iodide (HI) gas and hydrogen gas (H₂) to form iodine gas (I₂). The equilibrium is represented by the equation:

2HI(g) = H₂(g) + I₂(g)

The concentration values given in the table correspond to the concentrations of H₂ and HI at different times.

a) From t=0 s to t=5 s: Without the specific graph mentioned in Figure 7.10, it is difficult to provide a precise explanation of the physical situation in the container during this time period. However, based on the equilibrium reaction given, we can make some general observations. At the start (t=0 s), the concentrations of H₂ and HI may be high. As time progresses, the reaction proceeds, and the concentrations of H₂ and HI may decrease while the concentration of I₂ increases. The specific behavior will depend on the rate of the forward and reverse reactions.

b) External factor altered at t=5 s: To bring about a change in the shape of the graph at t=5 s, some external factor must have been altered. The most likely factor is the total pressure within the container. Since the reaction involves gases, changes in pressure can affect the equilibrium position. However, according to the information given, a change in pressure will not affect equilibrium in this case since the number of moles of gas is the same on both sides of the equation. Therefore, if the shape of the graph changes at t=5 s, some other external factor, such as temperature or the addition of a catalyst, must have been altered.

c) Calculation of K at t=3 s: The equilibrium constant (K) can be calculated at any given time using the concentrations of the reactants and products. However, the concentrations of H₂ and HI at t=3 s are not provided in the information given. Without the necessary data, it is not possible to calculate K at t=3 s.

Lastly, the statement "1 dm³ COCI, decomposes" seems incomplete. If you provide additional information or clarify the question, I'll be happy to assist you further.

Answer: i think its empirical

Explanation:

Answer:

Mineral A is harder than mineral B

Answer:

Option 4

Explanation:

Hydrochloric acid is a strong one, that gives protons to medium. It can be dissociated as this:

HCl  →  H⁺  + Cl⁻

M means Molarity. It is a sort of concentration that indicates the moles of solute in 1L of solution.

M = moles / volume (L)

We can also say M = mmoles / mL of solution

M . mL = mmoles

0.453 M . 62.85mL = 28.5 mmoles

If we divide by 1000 → 28.5 mmol . 1 mol / 1000 mmol = 0.0285

Answer:

4 hours a day

Explanation:

240/60=4

The chemical element in group one that is also a member of period 2 is lithium.

The chemical element in group one that is also a member of period 2 is lithium therefore, the element referred to here is lithium. Group 1 has only one valence electron. If we add one to 23, we will have 24 and the element is chromium.

For question three, the focus is on period 5, five groups to the previous answer will give us the element molybdenum. The atomic number of Mo is 42 and its mass number 96 hence it has 54 neutrons. The element that has atomic number 54 is Xe.

The element that has atomic mass 43 which is reversal of the atomic number of the former answer is scandium.

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The following are categorized into polar or nonpolar molecules:

a) Beryllium chloride (BeCl₂) is a nonpolar molecule. The Be-Cl bond is polar due to the electronegativity difference between beryllium and chlorine, but the molecule is linear with the two polar bonds pointing in opposite directions, resulting in a net dipole moment of zero.

b) Hydrogen sulphide (H₂S) is a polar molecule. The H-S bond is polar due to the electronegativity difference between hydrogen and sulfur, and the molecule has a bent shape, resulting in a net dipole moment that is not zero.

c) Sulphur trioxide (SO₃) is a nonpolar molecule. The S-O bonds are polar due to the electronegativity difference between sulfur and oxygen, but the molecule is trigonal planar with the three polar bonds pointing in different directions, resulting in a net dipole moment of zero.

d) Water (H₂O) is a polar molecule. The H-O bond is polar due to the electronegativity difference between hydrogen and oxygen, and the molecule has a bent shape, resulting in a net dipole moment that is not zero.

e) Trichloromethane (CHCl₃) is a polar molecule. The C-Cl bonds are polar due to the electronegativity difference between carbon and chlorine, and the molecule has a tetrahedral shape, resulting in a net dipole moment that is not zero.

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The pH of a 0.250 M solution of HOC6H5 is 2.92 and HCN is 5.96

a. HOC6H5, or benzoic acid, is a weak acid that partially dissociates in water to form H+ and C6H5COO- ions. The dissociation reaction is

HOC6H5 ⇌ H+ + C6H5COO-

To determine the pH of a 0.250 M solution of benzoic acid, we need to calculate the concentration of H+ ions in solution. The equilibrium expression for the dissociation reaction is:

Ka = [H+][C6H5COO-]/[HOC6H5]

where Ka is the acid dissociation constant for benzoic acid. The value of Ka for benzoic acid is 6.5 × \(10^-5.\)

We can assume that the initial concentration of H+ ions in the solution is zero. At equilibrium, let x be the concentration of H+ ions in solution and 0.250 - x be the concentration of C6H5COO- ions in solution. Then:

Ka = x(0.250 - x)/0.250

Solving for x, we get:

x = 1.21 × \(10^-3\) M

the pH of a 0.250 M solution of benzoic acid is:

pH = -log[H+] = -log\((1.21 × 10^-3)\) = 2.92

b. HCN, or hydrocyanic acid, is also a weak acid that partially dissociates in water to form H+ and CN- ions. The dissociation reaction is:

HCN ⇌ H+ + CN-

To determine the pH of a 0.250 M solution of HCN, we need to calculate the concentration of H+ ions in solution. The equilibrium expression for the dissociation reaction is:

Ka = [H+][CN-]/[HCN]

where Ka is the acid dissociation constant for HCN. The value of Ka for HCN is 4.9 ×\(10^-10\).

We can assume that the initial concentration of H+ ions in the solution is zero. At equilibrium, let x be the concentration of H+ ions in solution and 0.250 - x be the concentration of CN- ions in solution. Then:

Ka = x(0.250 - x)/0.25

Solving for x, we get:

x = 1.1 × \(10^-6\) M

pH :- -log[H+] = -log\((1.1 × 10^-6)\)

= 5.96

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Answer:

When HCl (hydrochloric acid) and KOH (potassium hydroxide) are neutralized, they react to form water (H2O) and a salt (KCl). The balanced equation is:

HCl + KOH → KCl + H2O

In this reaction, one mole of HCl reacts with one mole of KOH to form one mole of water and one mole of KCl.

During titration of HCl with KOH, the point at which the reaction is complete is called the equivalence point. At the equivalence point, the moles of H+ ions and OH- ions are equal in the titration mixture.

Since one mole of HCl reacts with one mole of KOH, and H+ ions are present in HCl and OH- ions are present in KOH, the number of moles of H+ ions will be equal to the number of moles of OH- ions at the equivalence point.

Therefore, at the equivalence point, the number of moles of H+ ions will be equal to the number of moles of OH- ions in the titration mixture when HCl is exactly neutralized by KOH.

When the HCl is neutralized by KOH, the equivalence point is reached. During titration, the amount of HCl is determined using a basic solution of known concentration.

It is possible to calculate the amount of KOH required for complete neutralization if the initial concentration of the HCl solution is known. The balanced chemical equation for the reaction between HCl and KOH is:HCl + KOH → KCl + H2OThe stoichiometry of the reaction indicates that one mole of HCl reacts with one mole of KOH to produce one mole of H2O. Thus, the number of moles of H+ ions is equal to the number of moles of OH- ions when the equivalence point is reached.In an acid-base reaction, the number of moles of hydrogen ions (H+) produced by the acid is equal to the number of moles of hydroxide ions (OH-) produced by the base. When the HCl is exactly neutralized by the KOH, the number of moles of H+ ions is equal to the number of moles of OH- ions in the titration mixture.

This is due to the balanced chemical equation for the reaction, which shows that one mole of HCl reacts with one mole of KOH to produce one mole of water (H2O).Thus, at the equivalence point, the number of moles of H+ ions is equal to the number of moles of OH- ions. This is the point at which all of the HCl has reacted with the KOH. After the equivalence point, the excess KOH will react with the H2O to produce OH- ions, resulting in a basic solution.

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The volume of water needed to prepare the solution given the data is 2.16 L

This is defined as the mole of solute per unit litre of solution. Mathematically, it can be expressed as:

Molarity = mole / Volume

Mole = mass / molar mass

Mole of CaCO₃ = 756 / 100.1

Mole of CaCO₃ = 7.55 moles

Volume = mole / molarity

Volume = 7.55 / 3.5

Volume = 2.16 L

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Answer:

What is the average height of a human?

5.6 ft.

5.2 ft.

Human/Height

Image result for Give me an example of an average. For instance, "the average height of a person is about 5 foot 6 inches

However, the actual global average height of a woman is only 159.5 cm (5 ft 2.8 in) and the average height of a man is 171 cm (5 ft 7.3 in). Therefore, the height difference between men and women globally is about 4.5 inches or 12 centimeters.

Explanation:

Answer:1.8 moles Fe and 2.7 moles CO2

Explanation:

Answer:

1.8 moles Fe and 2.7 moles CO2

Mercury and carbon two electrodes can't be used with an inactive or inert material.

The electrode is the element which is used to complete the electric circuit in welding. Some time electrode is connected with the positive terminal and sometimes with a negative terminal, it depends on the requirement of the welding process.

Inert electrode is an electrode that serves only as a source or sink for electrons without playing a chemical role in the electrode reaction. Precious metals, mercury, and carbon are typically used as inert electrodes.

Therefore, neither of the two electrodes can be used with an inactive or inert material.

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Answer:

Bar Graphs

Explanation:

Answer: Scatterplot

Explanation:

Answer:

"At the top of the first and tallest hill, your potential energy is at its highest it will ever be on this ride. As you begin to descend, your potential energy decreases until it's all gone at the bottom of the hill." The shorter the hill the roller coaster climbs, the greater its kinetic energy.

Answer:

Metals are malleable : They can be bent and shaped without breaking. This is because they consist of layers of atoms that can slide over one another when the metal is bent, hammered or pressed.

Explanation:

Pure iron is a bright silvery white metal which oxidizes (rusts) rapidly in moist air or in water containing dissolved oxygen. It is soft, malleable, and ductile, and is strongly magnetic (ferromagnetic).

Question 1 : the empirical formula for the compound is CBr₄.

Question 2 : the molecular formula for the compound is CBr₄.

To determine the empirical formula and molecular formula of the compound, we need to analyze the given percentage composition and molecular weight. Let's go through the process step by step:

Empirical Formula:

The percentage composition by mass states that the compound contains 3.622% carbon and 96.38% bromine. We can assume a 100g sample of the compound to simplify the calculations.

Mass of carbon = (3.622/100) * 100g = 3.622g

Mass of bromine = (96.38/100) * 100g = 96.38g

Next, we need to find the moles of each element. We can use their atomic masses to convert the masses to moles.

Atomic mass of carbon (C) = 12.01 g/mol

Atomic mass of bromine (Br) = 79.90 g/mol

Moles of carbon = Mass of carbon / Atomic mass of carbon = 3.622g / 12.01 g/mol ≈ 0.3017 mol

Moles of bromine = Mass of bromine / Atomic mass of bromine = 96.38g / 79.90 g/mol ≈ 1.205 mol

To find the simplest whole-number ratio between the elements, we divide both moles by the smallest number of moles (0.3017 mol in this case):

Moles of carbon (C) = 0.3017 mol / 0.3017 mol = 1

Moles of bromine (Br) = 1.205 mol / 0.3017 mol ≈ 4

Therefore, the empirical formula for the compound is CBr₄.

Molecular Formula:

Given that the molecular weight (molar mass) of the compound is 331.6 amu, we need to compare it with the empirical formula weight.

Empirical formula weight = (Atomic mass of carbon × Number of carbon atoms) + (Atomic mass of bromine × Number of bromine atoms)

= (12.01 amu × 1) + (79.90 amu × 4) = 12.01 amu + 319.6 amu = 331.61 amu

The molecular weight is very close to the empirical formula weight, indicating that the empirical formula represents the molecular formula as well. Therefore, the molecular formula for the compound is also CBr₄.

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Answer:

\(\Delta G=-675.38 \frac{kJ}{mol}\)

Explanation:

Hello!

In this case, for this problem, it is possible to use the thermodynamic definition of the Gibbs free energy:

\(\Delta G=\Delta H-T\Delta S\)

Whereas G, H and S can be assumed as constant over T; thus, we can calculate H at 135.4 °C:

\(\Delta H=\Delta G+T\Delta S\\\\\Delta H=-775.41\frac{kJ}{mol}+(135.4+273.15)K*(0.81791\frac{kJ}{mol*K} )\\\\\Delta H=-441.58\frac{kJ}{mol}\)

Now, we can calculate the Gibbs free energy at 12.7 °C as shown below:

\(\Delta G=-441.58\frac{kJ}{mol} -(12.7+273.15)K*0.81791\frac{kJ}{mol*K}\\\\\Delta G=-675.38 \frac{kJ}{mol}\)

Best regards!

Between genes A and B, there is a wider separation or distance than between genes C and D.

The chance of recombination is 50% when the genes are distant from one another or on different chromosomes. In this instance, the two loci's allele inheritance is independent. Recombination frequency less than 50% indicates a connection between the two loci.

A illness that is passed from parent to kid may be linked to one or more genes with certainty thanks to genetic mapping. Moreover, mapping can reveal which chromosome a gene is located on and where exactly it is located on that chromosome.

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Using the prefix method for covalent compounds, the names of the given compounds are shown below:

LIF: Lithium fluoride

Cl2O7: Dichlorine heptoxide

N2O3: Dinitrogen trioxide

SF6: Sulfur hexafluoride

Na3PO4: Sodium phosphate

A covalent bond is  described as a chemical bond that involves the sharing of electrons to form electron pairs between atoms.

The properties of covalent compounds includes:

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Answer:

17 reactions

Explanation:

Answer:

D . They are found in moist environments.

Explanation:

Nonvascular plants do not have a xylem or phloem, roots, stems, or leaves. Because these plants lack water-conducting tissues, they fail to achieve the structural complexity and size of most vascular plants and have evolved in habitats which allow their survival and reproduction.

The plant body that is most obvious in non-vascular plants are the the gametophyte generation. The gametophte gemeration is haploid.

The non-vascular plants grow in moist environments. It is due to lack of vascular tissue that requires to maintain close contact with water to prevent desiccation. Nonvascular plants are plants that do not have any special internal pipelines or channels to carry water and nutrients. Instead, nonvascular plants absorb water and minerals directly through their leaflike scales. Nonvascular plants are usually found growing close to the ground in damp, moist places. Non-vascular plants thrive in damp conditions since they don't need to rely on roots to acquire enough water.

Answer:

n = 0.045 mol.

Explanation:

Hello there!

In this case, according to the given problem, we can firstly set up the ideal gas equation as shown below:

\(PV=nRT\)

Thus, as we are asked to calculate the moles, we proceed as follows:

\(n=\frac{PV}{RT}\)

Therefore, we plug in the given data to obtain:

\(n=\frac{760mmHg*\frac{1atm}{760mmHg}*1.0L}{0.08206\frac{atm*L}{mol*K}*273K} \\\\n=0.045mol\)

Best regards!