how many dog are gone after 7 are at the vet

Answer:

Northern Hemisphere

Step-by-step explanation:  

The tilt's orientation with respect to space does not change during the year; thus, the Northern Hemisphere is tilted toward the sun in June and away from the sun in December, as illustrated in the graphic below.

Answer:

ThThe southern hemisphere

Step-by-step explanation:

The value of x in the triangle is 17.

The exterior angle theorem states that the measure of an exterior angle is equal to the sum of the measures of the two remote interior angles of the triangle.

Using the exterior angle theorem, we can find the value of x in the triangle as follows:

m∠BHY = (2x + 7)°

m∠HBY = (8x - 18)°

m∠NYB = (4x + 91)°

Therefore,

2x + 7 + 8x - 18 = 4x + 91

10x - 11 = 4x + 91

10x - 4x = 91 + 11

6x = 102

divide both sides by 6

x = 102 / 6

x = 17

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Answer: Cumulative frequency distribution

Step-by-step explanation: Not entirely sure but I believe you are looking for this definition based on the question. Hope this helps :)

Answer:

20

Step-by-step explanation:

70-50 is 20

Answer: 51 degrees

Step-by-step explanation:

Angle sum of a triangle: 180 degrees

78 + 51 = 129

180 - 129 = 51

Willard should interpret the 95% prediction interval for percent potassium when nitrogen is 18 ppm as a range of values within which the true value of percent potassium is likely to fall with a 95% probability.

Specifically, the prediction interval (0.87%, 1.02%) suggests that if Willard were to measure the percent potassium in a large number of soil samples with a nitrogen level of 18 ppm and calculate the prediction interval for each sample, then 95% of the prediction intervals would contain the true value of percent potassium.

The lower and upper limits of the prediction interval correspond to the lower and upper bounds of the plausible range for percent potassium, given the observed nitrogen level. In this case, the interval (0.87%, 1.02%) indicates that Willard can be 95% confident that the true value of percent potassium for a soil sample with nitrogen level 18 ppm falls between 0.87% and 1.02%. However, it is important to note that the prediction interval is based on statistical assumptions and may not capture all sources of uncertainty or variability in the data. Therefore, it is important to interpret the prediction interval with caution and in the context of the specific statistical model and assumptions used to derive it.

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Answer:

12/6 simplified to lowest terms is 2/1.

Step-by-step explanation:

Divide both the numerator and denominator by the HCF

12 ÷ 6

6 ÷ 6

Reduced fraction:

12/6 simplified to lowest terms is 2/1.

Answer: 2:1

Step-by-step explanation:

12:6

Both left and right can be divided by 6, like a fraction, reduce.

= 2:1

The intuition behind these results is that the parameters and saving rate chosen in this scenario do not allow for sustained economic growth and positive steady-state levels of output and consumption per worker. The economy lacks the necessary capital accumulation to drive productivity and increase output and consumption.

To solve the questions, we'll use the Solow model and the given parameters.

Given:

Per worker output: y = 3k

Saving rate: s = 40% = 0.4

Population growth rate: n = 7% = 0.07

Depreciation rate: δ = 15% = 0.15

(a) Steady-state level of capital-labor ratio (k*) and output per worker (y*):

In the steady state, investment is equal to saving, so (d + n)k = sy.

Since d + n = δ + n, we have (δ + n)k = sy.

Setting the investment equal to saving and substituting the given values:

(0.15 + 0.07)k = 0.4(3k)

0.22k = 1.2k

0.22k - 1.2k = 0

-0.98k = 0

k* = 0 (steady-state capital-labor ratio)

Substituting k* into the output per worker equation:

y* = 3k* = 3(0) = 0 (steady-state output per worker)

(b) Steady-state consumption per worker (c*):

In the steady state, consumption per worker is given by c* = (1 - s)y*.

Substituting the given values:

c* = (1 - 0.4)(0) = 0 (steady-state consumption per worker)

(c) Measures to increase consumption per worker at the golden-rule level of capital (kG = 46.49):

To increase consumption per worker at the golden-rule level of capital, the saving rate (s) should be decreased. By reducing the saving rate, more resources are allocated to immediate consumption rather than investment, resulting in higher consumption per worker.

(d) Steady-state level of capital-labor ratio (k*), output per worker (y*), and consumption (c*) with a saving rate of 55%:

In this case, the saving rate (s) is 55% = 0.55.

Using the same approach as in part (a), we can calculate the steady-state capital-labor ratio:

(δ + n)k = sy

(0.15 + 0.07)k = 0.55(3k)

0.22k = 1.65k

0.22k - 1.65k = 0

-1.43k = 0

k* = 0 (steady-state capital-labor ratio)

Substituting k* into the output per worker equation:

y* = 3k* = 3(0) = 0 (steady-state output per worker)

Substituting the given values into the consumption per worker equation:

c* = (1 - 0.55)(0) = 0 (steady-state consumption per worker)

In this case, the government policy should be the same as in part (c) since both cases result in a steady-state capital-labor ratio, output per worker, and consumption per worker of 0.

(e) Intuition behind the differences in levels of variables:

The differences in the levels of variables between (a), (b), and (d) can be explained as follows:

In (a), with the given parameters and a saving rate of 40%, the steady-state capital-labor ratio, output per worker, and consumption per worker are all 0. This means that the economy is not able to accumulate enough capital to sustain positive levels of output and consumption per worker.

In (b), the steady-state consumption per worker is also 0, as the economy is not producing any output per worker to consume.

In (d), even with an increased saving rate of 55%, the steady-state levels of capital-labor ratio, output per worker, and consumption per worker remain at 0. This indicates that the saving rate alone cannot overcome the lack of initial capital to generate positive levels of output and consumption per worker.

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Answer: 4 boxes

Step-by-step explanation: 6 caramel chocolates and 9 milk chocolates in each box.

Answer:

GIVE ME MY RAMEN

Step-by-step explanation:

3.

add like terms

30 + 7k = 100

100-30 = 70

70 divided by 7k = 10

k = 10

4. add the z's together

2z - 6 -2 = -10

+ 6 + 2

-10 will be -2 now since we dragged the -6 and -2 to the other side

2z = -2

z = -1

5. 3.2x - 1.7x = 1.5x

1.5x + 5.5 = 10

10 would be 4.5 since we dragged 5.5 to the other side so it would be 10 - 5.5

3.2x = 5.5

x = 1.71875

6.

3/4x - 1/4x = 2/4x

14 - 3 = 11

2/4x = 11

x = 22

Answer: D/ 6.

Step-by-step explanation: First, you have to do division to find out how many minutes = 1 nautical mile.

378 divided by 21= 18.

Then, you would do 108 divided by 18, to find out the answer; 6.

To double check your work, get the answer you got and multiply it by the minutes per mile which is 18.

18 x 6 = 108.

Therefore, it will be 6 nautical miles in 108 minutes.

Answer:

Step-by-step explanation:

We are given the sequence

\(15, 29, 49, 75, 107\\15->29 = 14\\29 -> 49 = 20\\49->75 = 26\\75 -> 107 = 32\\14, 20, 26, 32\\14 -> 20= 6\\20 -> 26 = 6\\26 -> 32 = 6\\\\6, 6, 6\\6->6 = 0\)

Since we had to find the differences twice, it is a second degree polynomial

\(y = an^2 + bn + c\\plugging \: in \: n = 1, 2, 3...\\the \: sequence \: is \\a+b+c, 4a + 2b + c, 9a + 3b + c...\\the \: diff \: under \: is \\3a + b, 5a + b, 7a + b...\\the \: diff \: under \: is \\2a, 2a, 2a...\\so, \\2a = 6\\a = 3\\3(3) + b = 14\\b = 5\\\\a +b + c = 15\\3 + 5 + c = 15\\c = 7\\\)

so,

\(y = 3n^2 + 5n + 7\)

The slope between two points A and B is given by the formula:

Replace the coordinates of the given points (1,1) and (-4,-3) to find the slope between those two points:

Plot the points (1,1) and (-4,-3). Then, draw the line through them:

Notice that the line goes up by 4 units for each 5 units that it goes to the right. This confirms that the slope is 4/5.

Therefore, the value of the slope of the line that passes through the points (1,1) and (-4,-3) is 4/5.

Answer:

\(\boxed{85}\)

Step-by-step explanation:

Sum of 38 and -87:

=> 38 + (-87)

=> 38 - 87

=> -49

Subtraction of -134 from -49:

=> -49 - (-134)

=> -49 + 134

=> 85

Answer:

aₙ = -2(2)^(n-1)

Step-by-step explanation:

Step-by-step explanation:

A quadratic equation can be constructed from their roots,

\((x - p)(x - q)\)

where p and q are the roots.

Here the roots are

\(2 - \sqrt{3} \)

and

\(2 + \sqrt{3} \)

So we have

\((x - (2 - \sqrt{3} ))(x - (2 + \sqrt{3} ))\)

\( {x}^{2} - 2x - x \sqrt{3} - 2x + x \sqrt{3} + 4 - 3\)

\( {x}^{2} - 4x + 1 = 0\)

So our answer is x^2

\( {x}^{2} - 4x + 1 = 0\)

The future value of an annuity of $500 per year for 12 years, with an interest rate of 5%, can be calculated using the future value of an ordinary annuity formula. The future value is approximately $7,005.53.

To calculate the future value of an annuity, we can use the formula:

FV = P * [(1 + r)^n - 1] / r

Where:

FV is the future value of the annuity,

P is the annual payment,

r is the interest rate per compounding period,

n is the number of compounding periods.

In this case, the annual payment is $500, the interest rate is 5% (or 0.05), and the number of years is 12. As the interest is compounded annually, the number of compounding periods is the same as the number of years.

Plugging the values into the formula:

FV = $500 * [(1 + 0.05)^12 - 1] / 0.05

= $500 * [1.05^12 - 1] / 0.05

≈ $500 * (1.795856 - 1) / 0.05

≈ $500 * 0.795856 / 0.05

≈ $399.928 / 0.05

≈ $7,998.56 / 100

≈ $7,005.53

Therefore, the future value of the annuity of $500 per year for 12 years, with a 5% interest rate, is approximately $7,005.53.

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You must use the t-distribution table when working problems when the population standard deviation (σ) is not known and the sample size is small (n<30). General Correct Rule: If σ is not known, then using t-distribution is correct. If σ is known, then using the normal distribution is correct.

Normal distribution, also known as the Gaussian distribution, is a probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean.

In graphical form, the normal distribution appears as a "bell curve".

The normal distribution is the proper term for a probability bell curve.

In a normal distribution the mean is zero and the standard deviation is1. It has zero skew and a kurtosis of 3.

Normal distributions are symmetrical, but not all symmetrical distributions are normal.

The t-distribution describes the standardized distances of sample means to the population mean when the population standard deviation is not known, and the observations come from a normally distributed population.

Therefore,

You must use the t-distribution table when working problems when the population standard deviation (σ) is not known and the sample size is small (n<30). General Correct Rule: If σ is not known, then using t-distribution is correct. If σ is known, then using the normal distribution is correct.

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Answer:

\(x = \frac{5}{3} \\\\\)

Step-by-step explanation:

To solve this problem, we need to go over an important fact:

To solve equations, we need to understand that it's like a see-saw. If you put something on one side of the see-saw, it will tip over. To preserve balance on the see-saw, you would but the same weight on the other side too. The same goes for equations. Whatever you do to one side of the equation, you do on the other.

So, we have the equation:

\(x + \frac{7}{3} = 4\)

We want to solve for the variable x. Or, we want to get x by itself on one side of the equation, preferably the left because it's already there. This means we get rid of the \(\frac{7}{3}\) term. To do that, we subtract \(\frac{7}{3}\) on the left side. But, we don't want the "see-saw" to tip over. So, we subtract \(\frac{7}{3}\) on the right side, like so:

\(x + \frac{7}{3} - \frac{7}{3} = 4 - \frac{7}{3}\)

\(\frac{7}{3} - \frac{7}{3}\) is 0. But, \(4 - \frac{7}{3}\) is trickier. We use common denominators to help us:

\(x = \frac{12}{3} - \frac{7}{3}\)

Simplify, and we get:

\(x = \frac{5}{3} \\\\\)

The answer is that the bird is gaining weight faster when it is weighing 40 grams.

The given problem is a differential equation problem with initial conditions and

\(\frac{dB}{dt}\) = \(\frac{1}{5}\) (100-B)

where B(t) is the solution to the differential equation with initial condition as B(0)=20g.

Now, \(\frac{dB}{dt}\)  at B=40 is    \(\frac{1}{5}\)(60)=12 and at B=70,

\(\frac{dB}{dt}\)  is    \(\frac{1}{5}\)(100-70)= 6.

Since \(\frac{dB}{dt}\) is greater when B=40, therefore the bird gains weight faster when it is weighing 40 grams.

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Step-by-step explanation:

\( {5}^{2} = {x}^{2} + {x}^{2} \\ {5}^{2} = {x}^{4} \\ 5 = \sqrt{ {x}^{4} } \\ 5 = {x}^{2} \\ x = \sqrt{5} =2.236068\\ \)

Answer:

-2

Step-by-step explanation:

The y-intercept of the line is -2

Answer:

-2

Step-by-step explanation:

because  the line is on the -2 on the y axis

The ordered pairs of the given rational function are:

(-2, -5¹/₂), (-1, -5²/₃),(0, -1), (1, -5),(-1,

In mathematics, an ordered pair (a, b) is a pair of objects. The order in which objects appear in pairs is important.

The ordered pair (a, b) is different from the ordered pair (b, a) unless a = b. (By contrast, the unordered pair {a, b} corresponds to the unordered pair {b, a}.)  

We are given a rational function as:

f(x) = -3x + (2/(x - 2))

Now, to get the ordered pair, we can use different values of x and find the corresponding value of y.

Thus:

At x = 0, we have:

f(x) = -3(0) + (2/(0 - 2))

f(x) = -1

At x = 1, we have:

f(x) = -3(1) + (2/(1 - 2))

f(x) = -5

At x = -1, we have:

f(x) = -3(-1) + (2/(-1 - 2))

f(x) = -5 - 2/3

= -5²/₃

At x = -2, we have:

f(x) = -3(-2) + (2/(-2 - 2))

f(x) = -5 - 1/2 = -5¹/₂

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Given that the z-score of science is 2.25, the proportion of values greater than this is calculated as,

From the Standard Normal Distribution Table,

Substitute this value,

Thus, 0.0122 proportion of the normal distribution corresponds to z-score values greater than the child’s z-score on the science test.

The total number of ways in which different telephone numbers are possible in city  is  6561.

Permutation -

It relates to a mathematical process that determines the number of possible arrangements of a given set.

Now, according to the question:

The first three digits are fixed, we have to select the next four digits.

A total number of available telephone numbers is increased by selecting

Thus,

= 9×9×9×9

= 6561

Total number of ways in which different telephone numbers are possible in city are 6561.

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The coordinates of M, P and Q in terms of a and b are \(M = \frac{1}{2}\cdot a + \frac{1}{2}\cdot b\), \(P = \frac{3}{4}\cdot a + \frac{1}{4}\cdot b\) and \(Q = \frac{1}{8}\cdot a - \frac{1}{8}\cdot b\), respectively.

In this question we are going to use definitions of vectors and product of a vector by a scalar. Based on the information given on statement, we have the following vectorial formulas:

Location of M

\(\overrightarrow{AM} = \frac{1}{2}\cdot \overrightarrow{AB}\)

\(\vec M - \vec A = \frac{1}{2}\cdot \vec B - \frac{1}{2}\cdot \vec A\)

\(\vec M = \frac{1}{2}\cdot \vec A +\frac{1}{2}\cdot \vec B\)

\(M = \frac{1}{2}\cdot a + \frac{1}{2}\cdot b\)

Location of P

\(\overrightarrow{AP} = \frac{1}{2}\cdot \overrightarrow{AM}\)

\(\vec P - \vec A = \frac{1}{2}\cdot \vec M - \frac{1}{2}\cdot \vec A\)

\(\vec P = \frac{1}{2}\cdot \vec A +\frac{1}{2}\cdot \vec M\)

\(\vec P = \frac{3}{4}\cdot \vec A + \frac{1}{4}\cdot \vec B\)

\(P = \frac{3}{4}\cdot a + \frac{1}{4}\cdot b\)

Location of Q

\(\overrightarrow{QM} = \frac{1}{2}\cdot \overrightarrow{PM}\)

\(\vec M - \vec Q = \frac{1}{2}\cdot \vec M - \frac{1}{2}\cdot \vec P\)

\(\vec Q = \frac{1}{2}\cdot \vec P - \frac{1}{2}\cdot \vec M\)

\(\vec Q = \frac{1}{2}\cdot \left(\frac{3}{4}\cdot \vec A + \frac{1}{4}\cdot \vec B\right) -\frac{1}{2}\cdot \left(\frac{1}{2}\cdot \vec A + \frac{1}{2}\cdot \vec B\right)\)

\(\vec Q = \frac{1}{8}\cdot \vec A -\frac{1}{8}\cdot \vec B\)

\(Q = \frac{1}{8}\cdot a - \frac{1}{8}\cdot b\)

The coordinates of M, P and Q in terms of a and b are \(M = \frac{1}{2}\cdot a + \frac{1}{2}\cdot b\), \(P = \frac{3}{4}\cdot a + \frac{1}{4}\cdot b\) and \(Q = \frac{1}{8}\cdot a - \frac{1}{8}\cdot b\), respectively.

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Answer:

Adult ticket = $4,5

Student ticket = $3

.

Step-by-step explanation:

Let say adult ticket is x and student ticket is y. so we get:

→ 8x + 13y = 75 (×5) 40x + 65y = 375

→ 10x + 9y = 72 (×4) 40x + 36y = 288

.

Eliminate both equations

40x + 65y = 375

40x + 36y = 288    

29y = 87

\(y = \frac{87}{29}\)

\(y = 3\)

.

Substitute the value of y to one of equations

\(10x + 9(3) = 72\)

\(10x + 27 = 72\)

\(10x = 72 - 27\)

\(10x = 45\)

\(x = \frac{45}{10}\)

\(x = 4,5\)

.

Happy to help :)

Answer:

iwiwjjwjwjwjbba abaha ajajaj ajaj

Step-by-step explanation:

wjis sisi sjaijs aibaia aihwoh ha ajj w