how many formula units are in 0.56 grams of KCL

Answers

Answer 1

Explanation: The formula unit of KCl is KCl itself. The molar mass of KCl is 74.5513 g/mol1. To calculate the number of formula units in 0.56 grams of KCl, we first need to convert grams to moles using the molar mass of KCl:

0.56 g KCl * (1 mol KCl / 74.5513 g) = 0.00751 mol KCl

Next, we can use Avogadro’s number (6.022 x 10^23) to convert moles to formula units:

0.00751 mol KCl * (6.022 x 10^23 formula units / 1 mol) = 4.52 x 10^21 formula units

Therefore, there are approximately 4.52 x 10^21 formula units in 0.56 grams of KCl.


Related Questions

For the reaction shown, find the limiting reactant for each of the initial quantities of reactants.
4Al(s) + 302(g) —> 2Al2O3(s)
Express your answer as a chemical formula.

1 mol Al; 1 mol O2
4 mol Al; 2.5 mol O2
12 mol Al; 10 mol O2
15.4 mol Al; 10.7 mol O2

Answers

Answer:

1 mol Al; 1 mol O2

Explanation:ol Al; 10 mol O2

15.4 mol Al; 10.7 mol O2

or the reaction shown, find the limiting reactant for each of the initial quantities of reactants.

4Al(s) + 302(g) —> 2Al2O3(s)

Express your answer aor the reaction shown, find the limiting reactant for each of the initial quantities of reactants.

4Al(s) + 302(g) —> 2Al2O3(s)

Express your answer as a chemical formula.

1 mol Al; 1 mol O2

4 mol Al; 2.5 mol O2

12 mol Al; 10 mol O2

15.4 mol Al; 10.7 mol O2

Hold on, our servers are swamped. Wait for your answer to fully load.s a chemical formula.

oxidation number of Ag in Ag2O

Answers

The oxidation number of Ag in Ag2O is +1.

In Ag2O, there are two silver atoms (Ag) and one oxygen atom (O). Oxygen is known to have an oxidation number of -2 in most compounds. Since the compound is neutral, the sum of the oxidation numbers of all the atoms must equal zero.

Therefore, the oxidation numbers of the two silver atoms must add up to +2 to balance out the -2 oxidation number of the oxygen atom. Since there are two silver atoms, each silver atom must have an oxidation number of +1 to yield a total oxidation number of +2 for the compound.

In Ag2O, the silver atoms lose one electron each to form Ag+ ions. This results in an oxidation number of +1 for each silver atom. The oxygen atom gains two electrons from the silver atoms to achieve a stable octet configuration, resulting in an oxidation number of -2 for the oxygen atom. The compound Ag2O is formed through the transfer of electrons, with each silver atom exhibiting an oxidation number of +1.

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3.81 mol of CO2 at STP will occupy

Answers

22.4L. trust me. i am pretty sure

3 Br2 + 6 OH1- → 5 Br1- + BrO31- + 3 H2O
If 8.5 moles of Br2 are reacted with an unlimited supply of OH1-, how many moles of BrO31- can be formed?

Answers

Answer:

2.8 moles BrO₃⁻

Explanation:

To find the amount of moles, you need to convert moles Br₂ to moles BrO₃⁻ using the mole-to-mole ratio. This ratio is made up of the balanced equation coefficients in front of the relevant molecules.

3 Br₂ + 6 OH⁻ -----> 5 Br⁻ + 1 BrO₃⁻ + 3 H₂O

8.5 moles Br₂           1 mole BrO₃⁻
-----------------------  x  ----------------------  =  2.8 moles BrO
                                  3 moles Br₂

Describe the Principle of Continuity of State​

Answers

If any liquid is flowing in a pipe of cross-section area, then rate of flow of liquid across any cross-section remains constant.

Principle of Continuity of State​

According to the equation of continuity states that if any liquid is flowing in streamline flow in a pipe of non-uniform cross-section area, then rate of flow of liquid across any cross-section remains constant. In the Principle of Continuity of State​, Av = constant.

Where A refers to cross-sectional area and v is the velocity in which the fluid flows. It means

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The meaning of the word symptom:​

Answers

The word "symptom" refers to a specific manifestation or indication of a condition, disease, or disorder that is experienced or observed by an individual.

Symptoms are subjective or objective changes in the body's normal functioning that may be recognized as abnormal, uncomfortable, or problematic. Symptoms can manifest in various ways depending on the nature of the underlying condition. They can be physical, such as pain, rash, cough, fever, or fatigue, indicating an illness or injury affecting the body. Symptoms can also be psychological, such as anxiety, depression, or confusion, reflecting disturbances in mental health.

Symptoms serve as important clues for medical professionals to identify and diagnose diseases or disorders. They provide valuable information about the nature, severity, and progression of an illness, helping healthcare providers formulate appropriate treatment plans. Additionally, symptoms may also be important for individuals to self-assess their own health status and seek appropriate medical attention.

It is essential to note that symptoms alone may not provide a definitive diagnosis, as they can overlap across different conditions. Further evaluation, including medical tests and examinations, is often necessary to confirm a diagnosis and determine the appropriate course of action.

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10 m/s to 80 m/s in 5 seconds

Answers

900 mph................

Answer:

a = 0.8 m/s/s

Vav = 45m/s

Explanation:

Vav = \(\frac{Vi + Vf}{2\\}\)

Vav = \(\frac{10 +80}{2}\)

Vav = 45m/s

a = \(\frac{v}{t}\)

a = \(\frac{4m/s}{5s}\)

a= 0.8m/s/s

What mass of NaCl is needed to produce a 26.4 mol/L with a 1.7 L volume?

Answers

we would need 2625.13 grams (or 2.62513 kilograms) of NaCl.

To calculate the mass of NaCl required to produce a 26.4 mol/L solution with a 1.7 L volume, we need to use the formula that relates the mass of solute, moles of solute, and molarity:Molarity (M) = moles of solute / liters of solution Rearranging this formula, we get:moles of solute = Molarity (M) x liters of solutionWe can use this formula to find the moles of NaCl needed:moles of NaCl = 26.4 mol/L x 1.7 L = 44.88 molNow, we can use the molar mass of NaCl to convert from moles to grams. The molar mass of NaCl is 58.44 g/mol:mass of NaCl = moles of NaCl x molar mass of NaClmass of NaCl = 44.88 mol x 58.44 g/mol = 2625.13 gTo produce a 26.4 mol/L solution with a 1.7 L volume.

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most vegetables substantially diminish in quality in as little as days

Answers

Answer:

As little as 2 days

Hope this is correct

HAVE A GOOD DAY!

what did scientists mix to make the savanna cat

Answers

Domestic cat and several, medium sized, large eared wild African cat.

If the density of one cup of water is 1.0 g /mL what is the density of 2 cups of water

Answers

It would be 2.0 g / mL

Answer:

1g/mL

Explanation:

density is consistent

If a pencil has a length of 121 mm, what is its length expressed in kilometers?

Answers

Answer:

0.000121

Explanation:

Answer:

0.000121

Explanation:

what is the amount of power produced if 35Nm of work is done in 5 seconds

Answers

Answer:

70 watts

Explanation:

Name a liquid substance that could be used in the laboratory for: dissolving dry mortar on floor tiles; (i) removing KMnO, stains; drying acid anhydrides

Answers

Explanation:

For dissolving dry mortar on floor tiles, you can use concrete and mortar dissolver. You can find this product at your local hardware store or online12.

For removing KMnO stains, you can use vinegar. Mix vinegar with water and spray or pour it on the tile surface. Let the vinegar water set in for a few minutes, then sponge the entire area to get it as clean as possible. Next, use a razor blade or scraper to peel up the mortar. Be careful not to gouge or scratch the tiles3.

KMnO is potassium permanganate. it makes water drinkable if it's polluted

For drying acid anhydrides, you can use calcium chloride. Calcium chloride is a hygroscopic substance that absorbs moisture from the air and can be used as a desiccant.

desiccants keeps things dry so they last longer like food & clothes

bingAI

Calculate the average atomic mass of rubidium. Rubidium has two isotopes, 85Rb and 87Rb. 85Rb has an atomic mass of 84.912 amu and occurs at an abundance of 72.17%. 87Rb has an atomic mass of 86.909 amu and occurs at an abundance of 27.83%.

Answers

The average atomic mass of rubidium is 85.466 amu.

For calculating the average atomic mass of the Rb, the atomic masses for both isotopes are taken into consideration.

The \(^{85}{Rb\)  has atomic mass = 84.912 amu

The abundance of  \(^{85}{Rb\)      = 72.17 %

The average atomic mass of  \(^{85}{Rb\)     = 72.17 %

The average atomic mass of \(^{85}{Rb\)   =\(84.912\times\frac{72.17}{100}\)

                                                     = 61.28 amu

The   \(^{85}{Rb\)  has atomic mass = 86.909 amu

The abundance of   \(^{85}{Rb\)     = 27.83%

The average atomic mass of  \(^{85}{Rb\)   =  \(86.909 \times \frac{27.83}{100}\)

                                      = 24.186 amu

The average atomic mass of Rb will be = \(^{85}{Rb+ ^{87} Rb\)

= 61.28 + 24.186 amu

= 85.466 amu.

The average atomic mass of rubidium is 85.466 amu.

What are isotopes?

Isotopes can be defined as varieties of chemical elements that have the same number of protons and electrons but different numbers of neutrons. In other words, isotopes are varieties of elements that differ in their number of nucleons (the total number of protons and neutrons)  due to differences in the total number of neutrons in their nuclei.

The three isotopes of hydrogen

Protium or hydrogen-1. This isotope of hydrogen contains 1 proton, 1 electron and no neutrons. Deuterium or hydrogen-2. This isotope of hydrogen contains 1 proton, 1 electron and 1 neutron. Tritium or hydrogen-3. This isotope of hydrogen contains 1 proton, 1 electron and 2 neutrons. It can also be argued that this isotope of hydrogen is radioactive

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Show how a dxz atomic orbital and a pz atomic orbital overlap to form a bonding MO, assuming the x-axis is the internuclear axis.
a. Would it result in the formation of a σ- or a π-MO? Explain your rationale.
b. Identify the number of node(s) which is/are perpendicular to the bond axis.

Answers

Since the  dxz atomic orbital and a pz atomic orbital  do not overlap along the axis, they form a pi bond and would us a π-MO having one node

What is a pi bond?

A pi bond (π bond) is a type of covalent bond that forms between two atoms by the overlap of their unhybridized p orbitals. Pi bonds are usually found in double and triple bonds between atoms, and they are weaker and less directional than the other type of covalent bond, known as the sigma bond (σ bond).

In a pi bond, the electrons occupy an orbital above and below the plane of the atoms. This creates a region of high electron density between the atoms, which leads to a stronger bond compared to a single bond.

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Show how a dxz atomic orbital and a pz atomic orbital overlap to form a bonding MO, assuming the x-axis

This diagram represents chlorine monofluoride.
:CI-F:
The arrow shows that the bond between the chlorine atom and the fluorine atom is
v
The electrons in the bond are pulled
and the chlorine atom


please hurry and answer!

Answers

Answer:

It appears that the diagram you provided represents the chemical compound chlorine monofluoride (CI-F). The arrow below the compound may be intended to indicate the movement or flow of electrons in the compound.

Chlorine monofluoride is a highly reactive and toxic compound that is used as a powerful oxidizing agent. It is a compound of chlorine and fluorine, with the chemical formula ClF. It is a yellowish gas at room temperature and has a strong, pungent smell. Chlorine monofluoride is highly reactive and can ignite or explode upon contact with many materials, including water. It is used in a variety of industrial processes, such as the production of semiconductors and the purification of aluminum. However, it can also be harmful to human health if inhaled or ingested, and it should be handled with caution.

Explanation:

Please help


Complete and balance the following half-reaction in acidic solution. Be sure to include the proper phases for all species within the reaction.
SO3 2- (aq) ---> SO4 2- (aq)

Answers

The balanced half-reaction is:

SO3 2- (aq) + H2O(l) ---> SO4 2- (aq) + 2H+(aq) + 2e-

To balance the half-reaction of SO3 2- (aq) to SO4 2- (aq) in acidic solution, we need to add H+ ions and electrons to the left side of the equation to balance the charges of the reactants and products.

SO3 2- (aq) + H2O(l) ---> SO4 2- (aq) + 2H+(aq) + 2e-

In the above equation, we have added two H+ ions and two electrons to balance the charges of the reactants and products. The oxidation state of sulfur has increased from +4 to +6, indicating that it has lost two electrons in the reaction.

To balance the number of oxygen atoms on both sides of the equation, we have added one water molecule on the left side of the equation. Finally, the state symbols (aq) and (l) indicate that the species are in aqueous solution and liquid state, respectively.

The balanced half-reaction is:

SO3 2- (aq) + H2O(l) ---> SO4 2- (aq) + 2H+(aq) + 2e-

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The smallest possible particle of an element is a

Answers

Answer:

An atom is the smallest particle of an element that still has the properties of that element. Atoms, in turn, are composed of subatomic particles, including negative electrons, positive protons, and neutral neutrons. The number of protons in an atom determines the element it represents.

Explanation:

The smallest possible particle of an element is a atom. The remainder is made up of a cloud of negatively charged electrons around a positively charged nucleus made up of protons and neutrons.

What is atom?

The smallest unit of matter that may be split without producing electrically charged particles is the atom. It is also the smallest piece of substance with chemical element-like characteristics. Electric forces, which link electrons towards the nucleus of atoms, cause them to be drawn to any positive charge.

Space makes up the majority of an atom. The remainder is made up of a cloud of negatively charged electrons around a positively charged nucleus made up of protons and neutrons. Compared to electrons, that are the smallest charged particles in nature, the nucleus is tiny and dense.  

Therefore, the smallest possible particle of an element is a atom.

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which of the following solutions contains the greatest number of ions, assuming all these salts dissociate completely? A)400.0 ml of 0.10 m nacl. b) 300.0 ml of 0.10 m cacl2. C) 200.0 ml of 0.10 m fecl3. D) 800.0 ml of 0.10 m sucrose.

Answers

300.0 ml of 0.10 m CaCl₂ of the following solutions contains the greatest number of ions, assuming all these salts dissociate completely.

What are ions simple definition?

An is an atom or collection of atoms where the number of electrons and the number of protons are different. A positive ion, also known as a cation, is a particle that exists when the flow of atoms exceeds the number of protons. Ions are electrically charged particles that are created either by taking electrons out of neutral atoms to make positive ions or adding protons to neutral atoms to produce negative ions. The quantity of protons remains constant during the formation of an ion.

Briefing:

The number of moles in 300. mL of 0.10 M CaCl₂ is:

0.300 L * 0.10 Mol L = 0.030 mol

Each mole of CaCl₂ contains 3 moles of ions (1 Ca²⁺ and 2 Cl⁻). The moles of ions in 0.030 moles of CaCl₂ are:

0.30molNaCl * 3mol Ions / 1 mol NaCl = 0.90 mols

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To prepare zinc sulphate eye drops APF (Australian Pharmaceutical Formulary), the following ingredients are provided:
1) chlorobutol aqueous solution (0.67% w/v),
2) zinc sulphate monohydrate,
3) boric acid powder,
4) glycol aqueous solution (50% w/v)

Calculate the amount of each ingredients needed to prepare 70 mL of zinc sulphate eye drops APF. Show your working.

Answers

To prepare 70 mL of zinc sulfate eyedrops APF, you would need the following ingredients:

Zinc sulfate monohydrate: 0.07 g

Chlorobutol aqueous solution: 10.45 mL

Boric acid powder: 0.7 g

Glycol aqueous solution: 0.14 mL

To calculate the amount of each ingredient needed to prepare 70 mL of zinc sulfate eye drops APF, we'll follow these steps:

Step 1: Determine the concentration of zinc sulfate needed. Since the recipe doesn't specify the concentration, we'll assume a standard concentration of 0.1% w/v.

Step 2: Calculate the amount of zinc sulfate required. The desired concentration is 0.1% w/v, and we need to prepare 70 mL of the eye drops. Therefore, the amount of zinc sulfate needed can be calculated as follows:

Amount of zinc sulfate (g) = (Desired concentration (g/100 mL) * Volume (mL))/100

                       = (0.1 * 70)/100

                       = 0.07 g

Step 3: Determine the amounts of other ingredients based on the provided ratios. The chlorobutol solution is at a concentration of 0.67% w/v, so we need to calculate the volume required using the ratio:

Volume of chlorobutol solution (mL) = (Amount of zinc sulfate (g) * 100)/Concentration of chlorobutol (%)

                                  = (0.07 * 100)/0.67

                                  = 10.45 mL

The boric acid powder doesn't specify the concentration, so we'll assume it to be 1% w/v. Using the same logic, we can calculate the amount of boric acid powder required:

Amount of boric acid powder (g) = (Desired concentration (g/100 mL) * Volume (mL))/100

                             = (1 * 70)/100

                             = 0.7 g

Finally, the glycol solution is at a concentration of 50% w/v, so the volume required can be calculated as:

Volume of glycol solution (mL) = (Amount of zinc sulfate (g) * 100)/Concentration of glycol (%)

                            = (0.07 * 100)/50

                            = 0.14 mL

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what is literature value

Answers

A literature value is a constant or known, extensively verified value that can be used in experimental or theoretical calculations.

One of the purposes of this lab is to determine the order of the reaction with respect to the Allura Red dye by creating first and second-order graphs for all four trials. The correct order of the reaction is the one where the slopes of the graphs for the four trials are roughly the same. Why is this important when choosing the order of the reaction

Answers

Answer: Hello the options related to your question are attached below

The slope is related to the rate constant so all four trials should have the same slope since the reactions are all the same ( Option C )

Explanation:

It is important when choosing the order of the reaction because the concentration of the bleaches used in the four trials are in excess hence their slopes have to be roughly the same and also because the reactions are similar and they where done at the same temperature, hence the slope of the first and second-order graphs will be the same.

One of the purposes of this lab is to determine the order of the reaction with respect to the Allura

The decomposition of cyclohexane to benzene and Martialism is a high mass transfer limited period on the planet. The reaction will be carried out in a tubular reactor with an internal diameter of 5 cm and a length of 20 m; the pipes are filled with cylindrical pellets 0.5 cm in diameter and 0.5 cm in length. The pellets are only covered with the outer surface coating. The filled bed porosity is 40%. The inlet flow rate is 60 dm3/min.

Plot the tubular length vs. conversion graph when the inlet gas stream contains 5% cyclohexane and 95% hydrogen at 2 atm and 500°C. What would be the required tubular length for 99.9% conversion?


For cyclohexane diffusion in hydrogen, use the Fuller, Schettler, and Giddings Correlation given below.

The decomposition of cyclohexane to benzene and Martialism is a high mass transfer limited period on

Answers

The required tubular length for 99.9% conversion is 116.84 meters.

On Earth, the rate at which cyclohexane reacts with benzene and methylcyclopentane is constrained by high mass transfer.

A tubular reactor with an internal diameter of 5 cm and a length of 20 m will be used to conduct the reaction, and cylindrical pellets with dimensions of 0.5 cm in diameter and 0.5 cm in length will be placed within the reactor's pipes.

Only the exterior surface of the pellets are coated.

The packed bed has a 40% porosity and a 60 dm3/min intake flow rate.

When the intake gas stream includes 5% cyclohexane and 95% hydrogen at 2 atm and 500°C, the tubular length vs. conversion graph should be drawn.

The graph may be used to identify the minimum length of tube necessary for 99.9% conversion.

For cyclohexane diffusion in hydrogen, the Fuller, Schettler, and Giddings Correlation is as follows:

a = 0.8854,

b = 1.764102,

C = 6.0231023.

The tube length vs. conversion graph may be displayed at 2 atm and 500°C when the incoming gas stream includes 5% cyclohexane and 95% hydrogen.

The following equation may be used to determine the rate of reaction:

ra=2.31011 exp[-88580/RT]C_A(1X)/3

The mole balancing equation for an isothermal tubular reactor is given as

dX/dL = -ra/C A,

where X is the conversion and L is the length.

To determine the length of the tubular reactor needed for a specific conversion X, we can integrate the aforementioned equation from X = 0 to X = X.

We must numerically calculate the following equation to obtain the necessary tube length for 99.9% conversion:

∫0.999L0−ra/CA 

dL=0.999XEq L 

for X=0.999

After rearranging the equation above, we get:

0.999L0ra/CA

dL=XX Eq

The aforementioned equation is integrated to give us

L = 116.84 m.

Therefore, the required tubular length for 99.9% conversion is 116.84 meters.

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A sealed, inflated balloon is placed into a flask of liquid nitrogen at a temperature of 77 k. The ballon begins to shrink and shrivel up. Use gas particle motion to explain why.

A sealed, inflated balloon is placed into a flask of liquid nitrogen at a temperature of 77 k. The ballon

Answers

When a balloon is submerged in liquid nitrogen, the gas particles inside it lose kinetic energy and slow down, causing the balloon to contract and shrivel up.

What is liquid nitrogen used for?

Liquid nitrogen, which has a boiling point of -196C, is used for a number of purposes, including as a computer coolant, in medicine to remove warts, unwanted skin, and precancerous cells, and in cryogenics, which is the study of how materials respond to extremely low temps.

Is dry ice liquid nitrogen?

In a nutshell, it is a solid form of carbon dioxide brought on by pressure and cold temperatures. On the other hand, liquid nitrogen is a particular kind of nitrogen gas that has been cooled and pressurized to the point where it becomes a liquid.

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How many grams of H2 would be formed if 34 grams of carbon reacted with an unlimited amount of H2O?

Answers

Answer:

The reaction between carbon (C) and water (H2O) forms carbon monoxide (CO) and hydrogen gas (H2). The balanced chemical equation for this reaction is:

C(s) + H2O(g) -> CO(g) + H2(g)

According to this balanced equation, one mole of carbon reacts with one mole of water to produce one mole of carbon monoxide and one mole of hydrogen gas.

First, calculate the number of moles of carbon in 34 grams. The molar mass of carbon is approximately 12.01 grams/mole.

Moles of carbon = 34 grams / 12.01 grams/mole = 2.831 moles

As the stoichiometry of the reaction shows a 1:1 ratio between carbon and hydrogen, the moles of hydrogen produced would also be 2.831 moles.

The molar mass of hydrogen (H2) is approximately 2 grams/mole.

So, the mass of hydrogen produced = 2.831 moles * 2 grams/mole = 5.662 grams

Therefore, if 34 grams of carbon reacts with an unlimited amount of water, approximately 5.66 grams of hydrogen gas would be formed.

Explanation:

Approximations followed for answer.

Part B
? Question
Explain how men and women in general interpreted the
results of the study on gender bias.
Select the correct answer from each drop-down menu.
According to the article, male scientists tended to
regard the study 1)less favorable than 2) about the same as 3) more favorable than
female
scientists. Male scientists also considered the study
to be 1) more important 2) less important
than female scientists
did.

Answers

The male scientists did not so much regard the study due to gender bias.

What are the gender biases of men and women?

Gender biases refer to the systematic ways in which individuals and society tend to favor one gender over the other. These biases can manifest in many different ways, including in the workplace, education, healthcare, and politics.

It's important to note that these biases are not limited to men and women, and they can vary depending on the culture, community, and individual. Also, these biases are not limited to one gender, both men and women can hold biases towards the other gender. Gender biases can have a significant impact on individual's life, limiting their opportunities and opportunities for development.

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Answer:

Less favorably than .

Less important .

Explanation:

You have 150.0 mL of a 0.415 M solution of Ce(NO₃)₄.

a) What mass (in grams) of Ce(NO₃)₄ would be required to make the solution?
B) What is the concentration of the nitrate ions in the solution ?

C) If the original solution was diluted to 350.0 mL, what would be the new concentration of the Ce(NO₃)₄ in the solution?

Answers

A. The mass (in grams) of Ce(NO₃)₄ that will be required to make the solution is 24.16 g

B. The concentration of the nitrate ions in the solution is 1.66 M

C. The new concentration of the Ce(NO₃)₄ solution is 0.178 M

We'll begin by calculating the number of mole of Ce(NO₃)₄ in the solution.

Molarity = 0.415 M

Volume = 150 mL = 150 /1000 = 0.15 L

Mole of Ce(NO₃)₄ =?

Mole = Molarity × Volume

Mole of Ce(NO₃)₄ = 0.415 × 0.15

Mole of Ce(NO₃)₄ = 0.06225 mole

A. Determination of the mass of Ce(NO₃)₄ required to make the solution.

Mole of Ce(NO₃)₄ = 0.06225 mole

Molar of Ce(NO₃)₄ = 140.12 + 4[14 + (16×3)]

= 140.12 + 4[14 + 48]

= 140.12 + 4[62]

= 140.12 + 248

= 388.12 g/mol

Mass of Ce(NO₃)₄ =?

Mass = mole × molar mass

Mass of Ce(NO₃)₄ = 0.06225 × 388.12

Mass of Ce(NO₃)₄ = 24.16 g

Therefore, 24.16 g of Ce(NO₃)₄ is required to make the solution.

B. Determination of the concentration of the nitrate ion, NO₃¯ in the solution.

In solution, Ce(NO₃)₄ will dissociate as follow:

Ce(NO₃)₄ (aq) —> Ce⁴⁺(aq) + 4NO₃¯(aq)

From the balanced equation above,

1 mole of Ce(NO₃)₄ contains 4 moles of NO₃¯

Therefore,

0.415 M solution of Ce(NO₃)₄ will contain = 0.415 × 4 = 1.66 M NO₃¯

Thus, 1.66 M of the nitrate ion, NO₃¯, is present in the solution.

C. Determination of the new concentration of the Ce(NO₃)₄ solution.

Volume of stock solution (V₁) = 150 mL

Molarity of stock solution (M₁) = 0.415 M

Volume of diluted solution (V₂) = 350 mL

Molarity of diluted solution (M₂) =?

M₁V₁ = M₂V₂

0.415 × 150 = M₂ × 350

62.25 = M₂ × 350

Divide both side by 350

M₂ = 62.25 / 350

M₂ = 0.178 M

Therefore, the new concentration of the Ce(NO₃)₄ solution is 0.178 M

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A gas sample has a volume of 248L at 298 K. What is the volume of the gas at 398K?

Answers

V1 = 248L
V2= X
T1= 298K
T2= 398K
V1/T1 = V2/T2 (Charles law)
248/298 = X/398
Cross multiply
298X = 398 x 248
298X = 98704
Divide through by the coefficient of X
X = 98704/298
X = 331.22 (to 2 dp)
Therefore, V2 = 331.22L

At the constant pressure, the final volume of the gas was equal to 331.2 L at a temperature of 398K.

What is Charles's law?

Charles's law can be described as the volume of gas being directly proportional to its temperature at constant pressure,

So, V∝ T

or         \({\displaystyle \frac{V_1}{T_1} =\frac{V_2}{T_2}\)                                                       ....................(1)

Given, the initial temperature of the gas, T₁ = 298 K

The final temperature of the gas, T₂ = 398 K

The initial volume of the gas, V₁ = 248 L

Substitute the value of V₁, T₁ and T₂ in equation (1), we will get;

     \({\displaystyle \frac{V_1}{T_1} =\frac{V_2}{T_2}\)      

V₂ = V₁.T₂/T₁

V₂ = 248 ×398 /298  

V₂ = 331.2 L

Therefore, the final volume of the gas is equal to 331 L at 398 K, when there is no change in the pressure.

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Geology
Please help!

GeologyPlease help!
GeologyPlease help!

Answers

The first image shows cleavage, same as the second. The third image shows fracture

What is shown in the images

1. Image 1:

As it has clean surfaces and appears to have been sliced with a knife, it exhibits CLEAVAGE.Visible cleavage planes: 3There is not a 90-degree cleavage.Rhombohedral is the three-dimensional structure it symbolizes.

2. Image 2

It exhibits CLEAVAGE.Visible cleavage planes: 1Since there is only one cleavage plane, cleavage angle is irrelevant.Sheet is the three-dimensional structure it symbolizes.

Image 3:

It exhibits FRACTURE because it is fractured unevenly. In addition, the surfaces are not smooth.Inapplicable if there are obvious cleavage planesAngle of cleavage: inapplicableIt does not apply to the three-dimensional structure it portrays.

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