How many grams of nacl are required to make 250.0 ml of a 3.000 m solution?

Answer:

It is energy

Explanation:

Your welcome! :)

Energy flows in one direction in an ecosystem.

An ecosystem is a system which shows the interaction between the living organisms and the non-living part of their environment.

An ecosystem usually shows a flow of nutrient and energy

Nutrients are cycled in an ecosystem but energy flows in only one direction.

Therefore, in an ecosystem, energy flows in one direction.

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The Microscope part and their right descriptions are as follows

Iris Diaphragm: A. Increases or decreases the light intensity

Objective Lens System: B. After light passes through the specimen, it next enters this lens system

Stage: C. Platform that supports a microscope slide

Adjustment Knob: D. Causes stage (or objective lens) to move upward or downward

Condenser: E. Concentrates light onto the specimen

Other parts of a microscope and their description that you should know about includes;

Eyepiece - The lens that you look through to see the image of the specimen.

Body tube - The tube that connects the eyepiece to the objective lenses.

Arm - The part of the microscope that supports the body tube and connects it to the base.

Base - The part of the microscope that supports the arm and provides stability.

Illuminator - The light source that provides light for the microscope.

Stage clips - The clips that hold the microscope slide in place on the stage.

Revolving nosepiece - The part of the microscope that holds the objective lenses and allows them to be rotated into place.

The above answer is in response to the full question below;

Match the names of the microscope parts in column A with the descriptions in column B. Place the letter of your choice in the space provided.

1. Iris diaphram

2. Objective lens system

3. Stage

4. Adjustment knob

5. Condenser

Increases or decreases the light intensity

2. After light passes through the specimen, it next enters this lens system

3. Platform that supports a microscope slide

4. Causes stage (or objective lens) to move upward or downward

5. Concentrates light onto the specimen

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Answer:the second one

Explanation:,Hydrogen bonding is a special type of dipole-dipole attraction between molecules ,not a covalent bond to a hydrogen atom. It results from the attractive force between a hydrogen atom covalently bonded to a very electronegative atom such as a N, O, or F atom and another very electronegative atom.

Answer:

8,68%

Explanation:

12g/mol de C divided by 138,2 g/mol de K2CO3

0.0868 x 100 = 8.68 %

If you traded (converted) 15 Skittles for M&Ms, you will have 20 M&Ms

We'll begin by converting 15 Skittles to cookies. This can be obtained as follow:

6 Skittles = 4 Cookies

Therefore,

15 Skittles = (15 Skittles × 4 cookies) / 6 skittles

15 Skittles = 10 cookies

We can convert 10 cookies to M&Ms as follow:

1 Cookies = 2 M&Ms

Therefore,

10 cookies = (10 cookies × 2 M&Ms) / 1 Cookies

10 cookies = 20 M&Ms

Thus, 15 Skittles is equivalent to 20 M&Ms

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In the second, third, fourth, fifth, and sixth squares, there is a pair each of upward and downward-pointing arrows, so the magnetic quantum number is -3, -2, -1, 0, 1, 2, and 3.

The magnetic quantum number, which ranges from -l to +l, provides information about the orientation of the electron's orbital, which is the angular momentum of the electron, and is important as it can be used to specify the exact spatial orientation of an electron's orbital.

Hence, in the second, third, fourth, fifth, and sixth squares, there is a pair each of upward and downward-pointing arrows, so the magnetic quantum number is -3, -2, -1, 0, 1, 2, and 3.

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Answer:

The answer is A, Neutron adds only mass

Answer:

Rubidium oxide

Explanation:

The Escape room winter wonderland is described as an immersive experience for  students during the winter time.

The Escape room winter wonderland  allows the students to demonstrate their knowledge of logic, weather, precipitation, and dichotomous keys in a fun and engaging way.

There are some materials which are mandatory and some which are optional and they include:

Required Materials:

- All printed materials (included)

- Manila envelopes (used for each of the puzzles)

- Hairdryer or heat source

- Fraxion pens

- UV pen/light

Optional Materials

- One Lockout Hasp

- Three, 4-digit locks

- Two, 3-digit locks

- One storage box that includes a place for the lockout hasp

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Answer:

nucleus is a collection of particles called protons,which are positively charged..and neutrons which are electrically neutral..electrons which are negatively charged..and neutrons are in turn made up of particles called quarks ..

Explanation:

hope this helps u ...

Answer:

The Nucleus is made up of protons and neutrons.

1) The number of moles of sodium acetate in the resulting solution is  1.1 * 10^-3 moles

2) Concentration of sodium acetate in the resulting solution is 0.09 M

3) The pH of the solution is predicted to be  5.6

We know that the term concentration has to do with the amount of substance that is in solution. In this case, what we have here is a buffer solution. A buffer is a solution of a salt and the weak acid.

Number of moles of acetate = 5.50/1000 L * 0.200 M

= 1.1 * 10^-3 moles

Number of moles of the acetic acid = 6.50/1000 L * 0.200 M

= 1.3 * 10^-3 moles

Total volume of the system = 5.50 + 6.50/ 1000

=  0.012 L

Concentration of sodium acetate in the resulting solution =

1.1 * 10^-3 moles/0.012 L = 0.09 M

Concentration of acetic acid  in the resulting solution =

1.3 * 10^-3 moles/0.012 L =0.011 M

pKa = - log(Ka)

= -log(1.8 * 10^-5)

= 4.7

Given that;

pH = pKa + log(A-)/(AH)

pH = 4.7 + log(0.09/0.011)

pH = 5.6

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Answer:

9.9 x 10^-2 g*cm²/s²

Explanation:

9.9 × 10^-9 kg*m²/s² =    g*cm²/s²

1 kg*m²/s² = 1 joule(s)

1 g*cm²/s² = 1 erg(s)

britannica

1 kg = 1000g = 1x10^3 g

1 m²= 10000 cm² = 1x10^4 cm²

add the exponents 3 and 4 which = 7

-9 + 7 = -2

9.9 × 10^-9 kg*m²/s² = 9.9 x 10^-2 g*cm²/s²

Answer:

C₂H₂O₄

Explanation:

Given parameters:

Mass of organic acid  = 5g

Mass of C  = 1.334g

Mass of O = 3.554g

Mass of H = 5  - (1.334 + 3.554)  = 0.112g

Molar mass  = 90.03g/mol

Unknown:

Molecular formula of the compound  = ?

Solution:

To solve this problem, we find the empirical formula of the compound first. It is the simplest formula of the compound.

Elements                        C                     H                        O

Mass                             1.334               0.112                   3.554

Molar mass                       12                   1                          16

Number of moles          1.334/12          0.112/1                 3.554/16

                                         0.112              0.112                     0.222

Divide by the

Smallest                         0.112/0.112        0.112/0.112          0.222/0.112

                                                1                       1                      2

           Empirical formula  = CHO₂  

The molar mass of this empirical formula  = 12 + 1 + 2(16) = 45g/mol

Now;

  Multiplication index  = \(\frac{90.03}{45}\)    = 2

Molecular formula  =  (CHO₂)₂    = C₂H₂O₄  

Benzene be B

Toluene be T

We have made then one lettered to make things easier

\(\\ \rm\Rrightarrow \dfrac{P^0_B-P_B}{P^0_B}=x_B\)

\(\\ \rm\Rrightarrow 95.1-P_B=95.(0.5)\)

\(\\ \rm\Rrightarrow 95.1-P_B=47.55\)

\(\\ \rm\Rrightarrow P_B=47.55mmHg\)

And

\(\\ \rm\Rrightarrow \dfrac{P^0_T-P_T}{P^0_T}=x_T\)

\(\\ \rm\Rrightarrow 28.4-P_T=28.4(0.5)\)

\(\\ \rm\Rrightarrow P_T=14.2mmHg\)

Total vapour pressure

There are two characteristics of molecules, one is geometry and other is shape. Shape is excluding lone pair surrounding the central element and geometry is including the lone pair. Therefore, the angles can be found out by VSEPR theory.

VSEPR stands for valence shell electron pair repulsions. VSEPR theory is used to predict the shape and geometry of molecules on the basis of valence electrons pairs that are present around the central element of the molecule.

According to VSEPR theory, Lone pair lone pair repulsion is greater than bond pair bond pair repulsion. There are so many limitations of VSEPR theory. There is a repulsion between bond pair electrons and lone pairs present on the central element.

Angle A:120 since lone pair is in conjugation with the ring so sp² hybridized.

Angle B:120, sp² hybridized

Angle C:180, sp hybridized

Angle D:109.5 sp³ hybridized

Angle E:120, sp² hybridized

Therefore, the angles can be found out by VSEPR theory.

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The empirical and molecular formulas of the quinine would be C40H48N and C23H27N respectively.

To determine the empirical formula, we need to find the mole ratios of each element in the compound.

First, let's calculate the number of moles of each product:

Next, let's find the number of moles of each element:

Now, we can find the empirical formula by dividing each mole value by the smallest mole value:

The empirical formula is C40H48N.

To find the molecular formula, we need to determine the molecular mass of the compound. The empirical formula mass is:

Empirical formula mass = (40 x 12.01 g/mol) + (48 x 1.01 g/mol) + (1 x 14.01 g/mol) = 549.88 g/mol

Molecular formula factor = 324 g/mol / 549.88 g/mol = 0.5899

Molecular formula = 0.5899 x (C40H48N) = C23H27N

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Hydrofluoric acid is a weak acid, which means that it is partially ionized when it is in presence of water.

This means that the correct answer is It would partially ionize.

Answer:

increase and then decrease

Explanation:

as a wavelength increases in size, its frequency and energy (E) decrease. From these equations you may realize that as the frequency increases, the wavelength gets shorter. As the frequency decreases, the wavelength gets longer. There are two basic types of waves: mechanical and electromagnetic

HOPE IT WORKS :)

Answer:

my take on this, is  32 but wait for others to answer as well  as i may be wrong

Explanation:

The Sun rotates at different rates at different latitudes on the Sun

The sun revolves around its axis like a ball in motion. One cycle of the sun takes approximately 27 days. But the sun rotates at various rates in various parts. The sun's equator rotates more quickly than its poles. Differential rotation is the name given to this phenomena.

The depth of the sun also affects how quickly it rotates, with the core regions rotating more slowly than the outer regions.

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Missing parts;

Which statement about the Sun's rotation is TRUE?

The Sun rotates only at the equator, where the sunspots are found; the rest of the Sun does not rotate

Only the atmosphere of the Sun rotates, not the main body of the Sun

The Sun rotates at different rates at different latitudes on the Sun

The Sun rotates once a day

The Sun does not rotate; only planets rotate

Answer:

\(0.175\; \rm mol \cdot L^{-1}\).

Explanation:

Magnesium chloride and silver nitrate reacts at a \(2:1\) ratio:

\(\rm MgCl_2\, (aq) + 2\, AgNO_3\, (aq) \to Mg(NO_3)_2 \, (aq) + 2\, AgCl\, (s)\).

In reality, the nitrate ion from silver nitrate did not take part in this reaction at all. Consider the ionic equation for this very reaction:

\(\begin{aligned}& \rm Mg^{2+} + 2\, Cl^{-} + 2\, Ag^{+} + 2\, {NO_3}^{-} \\&\to \rm Mg^{2+} + 2\, {NO_3}^{-} + 2\, AgCl\, (s)\end{aligned}\).

The precipitate silver chloride \(\rm AgCl\) is insoluble in water and barely ionizes. Hence, \(\rm AgCl\!\) isn't rewritten as ions.

Net ionic equation:

\(\begin{aligned}& \rm Ag^{+} + Cl^{-} \to AgCl\, (s)\end{aligned}\).

Calculate the initial quantity of nitrate ions in the mixture.

\(\begin{aligned}n(\text{initial}) &= c(\text{initial}) \cdot V(\text{initial}) \\ &= 0.25\; \rm mol \cdot L^{-1} \times 0.150\; \rm L \\ &= 0.0375\; \rm mol \end{aligned}\).

Since nitrate ions \(\rm {NO_3}^{-}\) do not take part in any reaction in this mixture, the quantity of this ion would stay the same.

\(n(\text{final}) = n(\text{initial}) = 0.0375\; \rm mol\).

However, the volume of the new solution is twice that of the original nitrate solution. Hence, the concentration of nitrate ions in the new solution would be \((1/2)\) of the concentration in the original solution.

\(\begin{aligned} c(\text{final}) &= \frac{n(\text{final})}{V(\text{final})} \\ &= \frac{0.0375\; \rm mol}{0.300\; \rm L} = 0.175\; \rm mol \cdot L^{-1}\end{aligned}\).

Answer:

the total distance moved by the wave from it's equilibrium point.

Explanation:

I picture the equivalent as standing on the floor is equilibrium point or starting. how high you jump is your amplitude.

Explanation:

for immiscible liquids it is quite easy to separate and the separating funnel can be used but for miscible liquid they form a single entity and separating them is quite impossible if the differences in temperature is not considered,so in distillation the one with lower boiling point evaporates out living behind the one with high boiling point

No of molecules=26.02×10²³molecules

No of moles

Molar mass

Mass

\(\\ \tt{:}\longrightarrow No\:of\:moles=\dfrac{Molecules}{Avagadro\:no}\)

\(\\ \tt{:}\longrightarrow No\:of\:moles=\dfrac{26.02\times 10^{23}}{6.023\times 10^{23}}\)

\(\\ \tt{:}\longrightarrow No\:of\:moles=4.32mol\)

We need the mass

\(\\ \tt{:}\longrightarrow No\:of\:moles\times molar\:mass\)

\(\\ \tt{:}\longrightarrow 32(4.32)\)

\(\\ \tt{:}\longrightarrow 138.24g\)

The mass of hydrogen needed to produce 51.0 grams of ammonia is  ≈ 9.07 grams.

To determine the mass of hydrogen required to produce 51.0 grams of ammonia (NH3) using the Haber process, we need to calculate the stoichiometric ratio between hydrogen and ammonia.

From the balanced chemical equation:

3 H₂(g) + N₂(g) → 2 NH₃(g)

We can see that for every 3 moles of hydrogen (H₂), we obtain 2 moles of ammonia (NH₃).

First, we need to convert the given mass of ammonia (51.0 grams) to moles. The molar mass of NH₃ is 17.03 g/mol.

Number of moles of NH₃ = Mass / Molar mass

                     = 51.0 g / 17.03 g/mol

                     ≈ 2.995 moles

Next, using the stoichiometric ratio, we can calculate the moles of hydrogen required.

Moles of H₂ = (Moles of NH₃ × Coefficient of H₂) / Coefficient of NH₃

           = (2.995 moles × 3) / 2

           ≈ 4.493 moles

Finally, we can convert the moles of hydrogen to mass using the molar mass of hydrogen (2.02 g/mol).

Mass of H₂ = Moles × Molar mass

          = 4.493 moles × 2.02 g/mol

          ≈ 9.07 grams

Therefore, approximately 9.07 grams of hydrogen is needed to produce 51.0 grams of ammonia in the Haber process.

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