How many grams of NaOH (molar mass = 40.000 g/mol) is required to prepare 100.0mL of 0.125M solution? 0.350 g 1.250 8 0.401 8 0.500 g 0.040 8 D

Answer:

D. The pressure of the gas on the left would double because the number of collisions would also double.

Explanation:

According to Boyle’s law, the pressure of a gas is inversely proportional to its volume.

As the number of particles was doubled in the left box, the particles have less space for movement as the volume occupied by gas particles has decreased and it will lead to the collision of gas particles with the walls of the container.

As the volume decreases as gas particles were doubled and so the pressure of the gas on the left would double.

Hence, the correct answer is "D. The pressure of the gas on the left would double because the number of collisions would also double."

The carbonic acid-bicarbonate buffer system plays a major role in maintaining the pH of human blood between the range of 7.35 and 7.45. Hence (d) is the correct option.

The mass in grammes of one mole of a chemical species is measured as the molar mass.On the one hand, the pan-resistant K. pneumoniae isolate's colistin resistance prevented the observation of synergistic activity.  Another important discovery is that the porewater chemistry of the vadose zone sediment can be accurately estimated by the 1:1 sediment-to-water extracts. Ka=Ka1×Ka2=10-6×10-10=10-16. A 1.0 M H2A solution has a pH of 3.00 (Ka1 = 1.0 10-6; Ka2 = 1.0 10-10).

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Given data:H2O vapor content: 13 gramsH2O vapor capacity: 52 grams at 25 degrees Celsius 13 grams at 10∘C52 grams at 30∘CFormula used to find the dew point:$$\dfrac{13}{52}=\dfrac{(A*3\pi)/(ln100)}{(17.27-A)}$$$$\frac{1}{4}=\dfrac{(A*3\pi)/(ln100)}{(17.27-A)}$$

Where A is the constantDew Point:It is the temperature at which air becomes saturated with water vapor when the temperature drops to a point where dew, frost or ice forms. To solve this question, substitute the given data into the formula.$$13/52=\dfrac{(A*3\pi)/(ln100)}{(17.27-A)}$$$$13(17.27-A)=3\pi A(ln100)$$By simplifying the above expression, we get$$A^2-17.27A+64.78=0$$Using the quadratic formula, we get$$A=9.9,7.4$$

The dew point is 7.4 since it is less than 10°C.More than 100:The term "More than 100" has not been used in the question provided.

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What should you have ready before introducing a sample or solvent to a separatory funnel. A flask under the separatory funnel, a stopcock closed, and a funnel at the top of the separatory funnel.

A tube used to pour liquids and powders in containers with small holes, having sides that slant inward and a broad opening just at top as well as a narrow aperture at the bottom: Through a funnel, pour the batter into the heated oil. funnel.

The steps that led to that conversion are tracked by a funnel. For instance, e-commerce businesses desire customers to make product purchases on their website. These are possible steps in their funnel: visited website, looked at merchandise, added item to basket, and made purchase.

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Answer:

Sr

Explanation:

because it's electronegativity is the highest.

1. The limiting reagent is sulfur trioxide, SO₃ and the excess reagent is water, H₂O

2. The mass of the excess reagent leftover is 14.92 g

3. The mass of sulfuric acid, H₂SO₄ is produced is 8.06 g

The limiting and excess reagent can be obtained as follow:

SO₃ + H₂O -> H₂SO₄

From the balanced equation above,

80 g of SO₃ reacted with 18 g of H₂O

Therefore,

6.58 g of SO₃ will react with = (6.58 × 18) / 80 = 1.48 g of H₂O

From the above calculation, we can see that only 1.48 g of H₂O out of 16.4 g is needed to react completely with 6.58 g SO₃.

Thus, the limiting reagent is SO₃ and the excess reagent is H₂O

The mass of the excess reagent leftover can be obtained as follow:

Mass of excess reagent, H₂O leftover = Mass given - mass reacted

Mass of excess reagent, H₂O leftover = 16.4 - 1.48

Mass of excess reagent, H₂O leftover = 14.92 g

The mass of H₂SO₄ produced can be obtained as illustrated below:

SO₃ + H₂O -> H₂SO₄

From the balanced equation above,

80 g of SO₃ reacted to produce 98 g of H₂SO₄

Therefore,

6.58 g of SO₃ will react to produce = (6.58 × 98) / 80 = 8.06 g of H₂SO₄

Thus, the mass of H₂SO₄ produced is 8.06 g

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Explanation:

Answer:

5 g/mL

Explanation:

So, if the mass is 10 g and the volume is 2 mL, the density equals...

10 g ÷ 2 mL = 5 g/mL

Answer:

5.13g of H2O.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

HBr(aq) + NaOH(aq) —> NaBr(aq) + H2O(l)

Next, we shall determine the masses of HBr and NaOH that reacted and the mass of H2O produced from the balanced equation.

This is illustrated below:

Molar mass of HBr = 1 + 80 = = 81g/mol

Mass of HBr from the balanced equation = 1 x 81 = 81g

Molar mass of NaOH = 23 + 16 + 1 = 40g/mol

Mass of NaOH from the balanced equation = 1 x 40 = 40g

Molar mass of H2O = (2x1) + 16 = 18g/mol

Mass of H2O from the balanced equation = 1 x 18 = 18g

Thus, from the balanced equation above,

81g of HBr reacted with 40g of NaOH to produce 18g of H2O.

Next, we shall determine the limiting reactant. This is illustrated below:

From the balanced equation above,

81g of HBr reacted with 40g of NaOH.

Therefore, 34g of HBr will react with = (34 x 40)/81 = 16.79g of NaOH.

From the calculations made above, we can see that it will take a higher mass (i.e 16.79g) of NaOH than what was given (i.e 11.4g) to react completely with 34g of HBr.

Therefore, NaOH is the limiting reactant and HBr is the excess react.

Finally, we can determine the maximum mass of H2O produced as shown below.

In this case the limiting reactant will used because it will produce the maximum mass of H2O since all of it is consumed in the reaction.

The limiting reactant is NaOH and the maximum mass of H2O produced can be obtained as follow:

From the balanced equation above,

40g of NaOH reacted to produce 18g of H2O.

Therefore, 11.4g of NaOH will react to produce = (11.4 x 18)/40 = 5.13g of H2O.

Therefore, the maximum mass of H2O produced from the reaction is 5.13g.

Answer:I think it’s the first option because of high temperatures there would be more evaporation and precipitation which would give plants water and exposure to the sun makes plants make food because of the photosynthesis process.

Explanation: Have a nice day and hope this helps : )

The calculated molar ratio of iron to oxygen in BIFs is 1.452.

Comparing this ratio to the molar ratios of Hematite (1:0.75) and Magnetite (1:0.67), we can see that the calculated value of 1.452 is closest to the Hematite molar ratio of 1:0.75. Therefore, Hematite is the more dominant iron component in BIFs.

To calculate the mass of oxygen contained within BIFs, we'll use the given information:

Total mass of the modern atmosphere = 5.01×10¹⁸ kg

Percentage of oxygen in the modern atmosphere = 21%

Mass of oxygen contained within the modern atmosphere = (5.01×10¹⁸ kg) × (0.21) = 1.051×10¹⁸ kg

Percentage of oxygen contained in BIFs = 6.6% (given)

Mass of oxygen contained within BIFs = (6.6% of 1.051×10¹⁸ kg) = 6.6/100 × 1.051×10¹⁸ kg = 6.9166×10¹⁶ kg

Therefore, the mass of oxygen contained within BIFs is 6.9166 × 10¹⁶ kg.

To calculate the number of moles of oxygen contained within BIFs, we'll use the molecular mass of O₂:

Molecular mass of O₂ = 0.032 kg/mole

Number of moles of oxygen contained within BIFs = (Mass of oxygen in BIFs) / (Molecular mass of O₂)

= (6.9166×10¹⁶ kg) / (0.032 kg/mole) = 2.1614375 × 10¹⁸ moles

Therefore, the number of moles of oxygen contained within BIFs is 2.1614375 × 10¹⁸ moles.

Next, let's calculate the mass of iron in BIFs:

Total mass of BIFs = 5.0×10¹⁷ kg

Percentage of iron in BIFs = 35%

Mass of iron contained within BIFs = (35% of 5.0×10¹⁷ kg) = 35/100 × 5.0×10¹⁷ kg = 1.75×10¹⁷ kg

To calculate the number of moles of iron contained within BIFs, we'll use the atomic mass of iron:

Atomic mass of iron = 0.0558 kg/mole

Number of moles of iron contained within BIFs = (Mass of iron in BIFs) / (Atomic mass of iron)

= (1.75×10¹⁷ kg) / (0.0558 kg/mole) = 3.1367419 × 10¹⁸ moles

Therefore, the number of moles of iron contained within BIFs is 3.1367419 × 10¹⁸ moles.

Finally, let's calculate the molar ratio of iron to oxygen in BIFs:

Molar ratio of iron to oxygen = (Number of moles of iron) / (Number of moles of oxygen)

= (3.1367419 × 10¹⁸ moles) / (2.1614375 × 10¹⁸ moles)

≈ 1.452

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The chemical that minimizes changes in the pH of a body fluid by releasing or binding hydrogen ions is called a buffer.

The chemical that minimizes changes in the pH of a body fluid b y - binding hydrogen ions is called a buffer. Buffers can absorb or release H+ ions, thus maintaining pH levels of a solution. The buffer system is an essential component of the body's pH regulation mechanism, enabling the maintenance of a consistent pH level that is optimal for cellular function. Buffers work by either absorbing or releasing H+ ions, and they are crucial in ensuring that the pH levels remain constant. Without the buffer system, the body's pH could become too acidic or too basic, making it challenging for cells to function normally. Buffers are solutions that resist changes in pH, and they play a vital role in regulating pH levels in the body.

Buffers are chemicals that minimize changes in pH levels by releasing or binding hydrogen ions.

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Answer:

Bq

Explanation:

The number of decays per second, or activity, from a sample of radioactive nuclei is measured in becquerel (Bq), after Henri Becquerel. One decay per second equals one becquerel.

The radioactive decay has been measured as decay per second by becquerel (Bq).

Radioactive decay has been given as the loss of energy by the nucleus. The release of energy has been in the form of radiation. The varying energy radiations have been termed alpha decay, beta decay, gamma decay.

The decay has been performed by unstable nuclei with the emission of multiple particles. The decay unit has been given by Henri Becquerel. The unit has been the determination of the decay performed per second and has been given by becquerel (Bq).

Thus, the unit for the measurement of radioactive decay has been becquerel (Bq).

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The specific gravity of urine is a measure of the concentration of dissolved particles in the urine. These particles include salts, minerals, and waste products, among others. The specific gravity of urine varies depending on factors such as fluid intake, diet, and health status.

When fluid intake is normal, the specific gravity of urine should be between 1.010 and 1.025. This range reflects a healthy balance of hydration and waste elimination. If the specific gravity is lower than 1.010, it may indicate that the person is overhydrated or has a condition that affects the kidneys' ability to concentrate urine. On the other hand, if the specific gravity is higher than 1.025, it may indicate dehydration, a high-protein diet, or a condition that affects the kidneys' ability to dilute urine.

It is important to note that specific gravity measurements are not definitive and should be interpreted in conjunction with other clinical data. For example, if a person has a high specific gravity but no symptoms of dehydration, further tests may be needed to determine the cause. Similarly, a person with a low specific gravity may need additional tests to rule out kidney disease or other conditions.

In conclusion, when fluid intake is normal, the specific gravity of urine should be between 1.010 and 1.025. However, specific gravity measurements should be interpreted in the context of other clinical data to accurately assess a person's health status.

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Answer:

5 is the answer since I did this and got it rigt

Answer:

they are known as metalloids. they are found in various groups in periodic table for ex- boron(b) is found in group 13/IIIA, silicon (si) and Germanium(ge) in group 14/IVA, arsenic (as) and antimony(sb) in group 15/VA and tellurium(Te) in group 16/VIA

Answer:

that's a difficult question

Explanation:

Sorry!!!!!

The element should be placed in the column for metalloids. Option A

We know that the properties of metals can be used to identify an unknown substances as a metal. We know that metals are able to react with acids to liberate the metal salt and hydrogen gas. Metals do not react with bases because they can not accept electrons.

Metalloids are generally amphoteric in nature. They can react with both the acid and the basses to form compounds. The nonmetals do not react with acid or base.

Looking at the result, we are told that the entry in the second row have the entries  nothing, nothing, nothing. If this is the outcome, then it follows that the element should be placed in the column for metalloids.

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Answer: A

Explanation:

In order to determine the empirical formula of a chloride of silicon containing 79.1 mass % cl, one needs to use the following steps. Step 1: Determine the masses of the elements in 100g of the compound To do so, assume that the sample is 100 g, which means that 79.1 g of the sample is Cl.

This means that the mass of silicon in the samples : masses of silicon = 100 - 79.1 = 20.9 g Step 2: Convert the masses into moles The molar masses of Cl and Si are: Cl = 35.5 g/mol Si = 28.1 g/mol The number of moles of each element can be calculated using their respective masses as shown below: Number of moles of Cl = 79.1 g / 35.5 g/mol = 2.23 mol Number of moles of Si = 20.9 g / 28.1 g/mol = 0.743 mol Step 3: Divide the number of moles by the smallest number of moles The smallest number of moles is 0.743 mol, which corresponds to silicon. Therefore, divide both the number of moles of Cl and Si by 0.743 mol. Number of moles of Cl in empirical formula = 2.23 mol / 0.743 mol = 3 mol Number of moles of Si in empirical formula = 0.743 mol / 0.743 mol = 1 mol The empirical formula of the chloride is therefore SiCl3. This means that the compound contains one atom of silicon and three atoms of chlorine. This formula is already in its simplest form, so it cannot be reduced any further.

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(alt + F4) might be the answer you are looking

Explanation:

I'm not exactly sure how I came up with this answer but it is for sure the answer

Mass percent concentration (% m/m) is given as the mass of the solute per 100 units mass of solution.

Answer: 83.3g of solution must be added to 10g of KCl in order to prepare 12.0% (m/m) KCl solution.

The color of an uninoculated fermentation tube is red. The uninoculated fermentation tube is a control tube that helps to detect changes in the medium or the environment. This uninoculated tube should remain red throughout the experiment.

The fermentation tube is a straight glass tube with a graduated scale of mL or cm³ on one side. It is used to measure the amount of gas produced by a particular microorganism during anaerobic respiration. The fermentation tubes are usually filled with a carbohydrate medium, such as glucose, and then sterilized. After sterilization, the fermentation tubes are inoculated with a specific bacterium.

The fermentation tube is then incubated at a specific temperature for a set period, depending on the bacterium's type. The bacteria in the fermentation tube will consume the carbohydrate in the medium and produce gas. The gas produced in the fermentation tube will rise up and displace the water in the open arm of the fermentation tube, pushing the water into the graduated arm and causing the water to rise.

The gas collected in the graduated arm of the fermentation tube is measured. This measurement is used to determine the amount of gas produced by the bacterium during the fermentation process.

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In the context of microbiology, an uninoculated fermentation tube is sterile, containing a colorless medium. The fermentation tube is used to determine the fermentation capabilities of different microorganisms.

An inoculated fermentation tube, on the other hand, is filled with a culture medium and a specific microorganism. When the organism ferments the medium, it produces gas that fills the Durham tube at the top of the fermentation tube. The Durham tube, which is an inverted vial, is present in the fermentation tube to trap and measure gas production. It is common to use phenol red broth, a pH indicator, to identify the fermentation of specific sugars such as lactose, glucose, or sucrose.The color of the phenol red broth changes with the pH, which is a measure of the acid produced by the organism during fermentation. A yellow color indicates acidic conditions, and a red color indicates an alkaline environment. A pink color can be indicative of a pH between neutral and acidic. Furthermore, if the organism is unable to ferment the sugar present in the medium, the uninoculated fermentation tube will have a colorless medium.

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The chemical formula for francium phosphide is FrP.

A chemical formula is described as a way of presenting information about the chemical proportions of atoms that constitute a particular chemical compound or molecule, using chemical element symbols, numbers, and sometimes also other symbols, such as parentheses, dashes, brackets, commas and plus and minus signs.

There are three main types of chemical formulas which include :

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Answer:

wrong.

Explanation: charged atoms have have more electrons than neural because  they charge it . a  neural atom has eaqual number of electrons and neutrons.

hope this helps(^人^)

Answer:

Animals, plants, fungi, bacteria, protists, etc.

Explanation:

Biotic means they are alive.

Salts such as \( Na_{2} SO_{4}\) are used in softening of hard water.

Hardness of water is the presence on water of dissolved metallic ions such as calcium and magnesium ions results in the water having additional properties such as taste.

Hardness of water is of significance in the laundry industry as it causes water to lather with difficulty and also produces sc_um.

To remove hardness of water or to soften water, salts such as \( Na_{2} SO_{4}\) are used.

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To calculate the amount of sodium monohydrogen phosphate (NaH2PO4) needed to make a 0.0800 M solution in a 0.5000 L beaker, you can follow these steps:

1. Determine the number of moles of NaH2PO4 needed:

  moles = Molarity × Volume

  moles = 0.0800 mol/L × 0.5000 L

2. Convert the moles of NaH2PO4 to grams using the molar mass of NaH2PO4:

  molar mass of NaH2PO4 = atomic mass of Na + (2 × atomic mass of H) + atomic mass of PO4

  molar mass of \(NaH2PO4 = 22.99 g/mol + (2 × 1.01 g/mol) + 97.99 g/mol\)

  grams = moles × molar mass of NaH2PO4

3. Calculate the amount of HCl or NaOH needed to adjust the pH to 8.3:

  Since NaH2PO4 is a weak acid, you can adjust the pH by adding either HCl or NaOH.

  To increase the pH:

  - Calculate the moles of HCl needed to react with the NaH2PO4 based on the balanced equation.

  - Convert the moles of HCl to volume using its molarity.

  To decrease the pH:

  - Calculate the moles of NaOH needed to react with the NaH2PO4 based on the balanced equation.

  - Convert the moles of NaOH to volume using its molarity.

Please note that to perform these calculations accurately, you would need to know the dissociation constants and pKa values of the acid and its conjugate base, as well as the pH range over which the buffer is effective.

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Answer: Not possible

Explanation:

It's not possible to determine how many moles of H2O2 you would end up with based on the information given.

The reason for this is that we don't know what is happening to the N2OOH in this scenario. Depending on the conditions and reaction occurring, the N2OOH could potentially break down into one or more different compounds, or it could react with another substance to form a new compound. Without this information, we cannot determine the amount of H2O2 that would result.

Explanation:

The chemical equation for the decomposition of N2OOH (dinitrogen trioxide) is:

N2OOH → 2 H2O2

This equation shows that one mole of N2OOH decomposes to produce two moles of H2O2.

If you start with 50 moles of N2OOH, you can calculate the number of moles of H2O2 produced by multiplying the number of moles of N2OOH by the stoichiometric coefficient of H2O2 in the balanced equation.

So,

Number of moles of H2O2 = 2 x 50 moles of N2OOH

= 100 moles of H2O2

Therefore, starting with 50 moles of N2OOH will produce 100 moles of H2O2 after complete decomposition

Answer: (2)

Explanation:

There are 16 oxygen atoms on the reactant side but only 10 on the products side.

Answer:

1.2M

Explanation:

Initial Volume 0.05L

Final Volume 0.250L

HCl Molar mass: 36.46 g/mol

M = 6M HCl

Molarity = mol solute /  L of solution

Inital M = Molarity = 6

mol solute = X = unknown

L of Solution = 0.05L

6 = X / 0.05

X = 0.3

X = 0.3/0.25

X = 1.2 M

​