How many kinds of chemically non-equivalent hydrogens are there in each of the following compounds?.

Answer:

wooden

Explanation:

Answer:

.

Explanation:

Answer: Indicators are substances whose solutions change color due to changes in pH

Explanation:

Answer:

EXPLANATION

Explanation:

[not sure exactly what you mean by indicator but here's my very basic answer lol] They are substances that change color due to changes in pH levels.

Answer:

\(\boxed {\boxed {\sf v \approx0.295 \ mL}}\)

Explanation:

We are asked to find the volume of a metal cylinder. We are given the mass and the density.

We know that density is the mass per unit volume of a substance. It is found using the following formula.

\(\rho= \frac {m}{v}\)

We know the density is 21.0 grams per milliliter and the mass is 6.20 grams. We substitute these values into the formula.

\(21.0 \ g/mL = \frac{6.20 \ g}{v}\)

We are solving for the volume, so we must isolate the variable v. First, cross multiply. Multiply the first numerator by the second denominator, then the first denominator and the second numerator.

\(\frac {21.0 \ g/mL}{1} = \frac{6.20 \ g}{v}\)

\(21.0 \ g/ mL *v= 6.20 \ g * 1\)

\(21.0 \ g/ mL *v= 6.20 \ g\)

v is being multiplied by 21.0 grams per milliliter. The inverse operation of multiplication is division. Divide both sides of the equation by 21.0 g/mL.

\(\frac {21.0 \ g/ mL *v}{21.0 \ g/mL}= \frac{6.20 \ g }{21.0 \ g/mL}\)

\(v= \frac{6.20 \ g }{21.0 \ g/mL}\)

The units of grams cancel.

\(v= \frac{6.20 }{21.0 mL}\)

\(v=0.2952380952\)

The original measurements of density and mass both have 3 significant figures, so our answer must have the same. For this number, 3 sig fig is the thousandth place. The 2 in the ten-thousandth place tells us to leave the 5.

\(v \approx0.295 \ mL\)

The volume of the metal cylinder is approximately 0.295 milliliters.

Answer:C

Explanation:

Answer:

Fe2 + O2 > FeO

Explanation:

I don't know how to make the letters small...

The condensation (dehydrated) product rather than the aldol addition (hydrated) product obtained in this experiment is due to the greater stability of the condensation product.

The aldehyde is dehydrated in the aldol condensation process to produce the β-hydroxyaldehyde which then eliminates a water molecule to form an α,β-unsaturated aldehyde or ketone. The condensation product is obtained rather than the aldol addition product in this experiment due to the greater stability of the condensation product. The condensation product is exceptionally stable due because the resonance stabilization. In the condensation product, the carbonyl group in the β position is connected to the α-carbon through a double bond. The carbon-carbon double bond is delocalized over the two carbon atoms in the compound, and this contributes to the overall stability of the compound.

Chelation effect, the carbonyl group in the β position is also involved in chelation with the metal ion. As a result, the overall stability of the compound is increased. Elimination of the water molecule: In the aldol reaction, the product of the reaction has a water molecule in it. This water molecule is eliminated during the condensation reaction, which leads to an increase in the stability of the compound.

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When 52.0140 grams is added to 50.71 grams, the result is 102.72 grams.

When adding or subtracting numbers, it is important to consider the number of decimal places or significant figures in each value to determine the appropriate number of decimal places in the result.

In this case, we have 52.014 grams and 50.71 grams. Since the number 50.71 grams has the fewest decimal places (two decimal places), we need to round the result to two decimal places.

Adding 52.0140 grams to 50.71 grams gives us a result of 102.7240 grams. However, since we need to round to two decimal places, the final result is 102.72 grams.

Therefore, reported to the correct number of significant figures, the result when 52.0140 grams is added to 50.71 grams is 102.72 grams.

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The heat of reaction (ΔH) for the given reaction is 180.4 kJ/mol. To calculate the heat of reaction (ΔH) for the given reaction:

CCl₄(g) + H₂O(g) -> CHCl₃(g) + HCl(g)

You would need the standard enthalpies of formation for each compound involved in the reaction. The standard enthalpy of formation (ΔHf) is the enthalpy change when one mole of a compound is formed from its elements in their standard states.

Here are the standard enthalpies of formation for the compounds involved:

ΔHf[CCl₄(g)] = -135.5 kJ/mol

ΔHf[H₂O(g)] = -241.8 kJ/mol

ΔHf[CHCl₃(g)] = -104.7 kJ/mol

ΔHf[HCl(g)] = -92.3 kJ/mol

To calculate ΔH for the reaction, you need to sum up the enthalpies of formation of the products and subtract the sum of the enthalpies of formation of the reactants:

ΔH = ΣΔHf(products) - ΣΔHf(reactants)

ΔH = [ΔHf[CHCl₃(g)] + ΔHf[HCl(g)]] - [ΔHf[CCl₄(g)] + ΔHf[H₂O(g)]]

ΔH = [(-104.7 kJ/mol) + (-92.3 kJ/mol)] - [(-135.5 kJ/mol) + (-241.8 kJ/mol)]

ΔH = -196.9 kJ/mol - (-377.3 kJ/mol)

ΔH = 180.4 kJ/mol

Therefore, the heat of reaction (ΔH) for the given reaction is 180.4 kJ/mol.

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To address the crevice corrosion issue in the high-pressure connectors and piping of the SWRO plant, several remedies can be considered, A SWRO (Sea Water Reverse Osmosis) plant is a water desalination facility that uses reverse osmosis technology to treat seawater or brackish water and produce freshwater

Material Selection: Evaluate the material compatibility with the operating conditions, especially the chloride ion concentration and temperature. Consider using corrosion-resistant alloys such as duplex stainless steel (e.g., 2205) or super duplex stainless steel (e.g., 2507) that have better resistance to chloride-induced corrosion compared to 316L or 317L stainless steel.

Surface Treatment: Apply appropriate surface treatments to enhance corrosion resistance. Passivation or pickling can remove surface contaminants and create a protective oxide layer on the metal surface, reducing the susceptibility to corrosion.

Design Modifications: Evaluate the design of the connectors and piping to minimize crevices and stagnant areas where corrosion can occur. Smooth transitions, avoiding sharp angles or crevices, can help promote better fluid flow and prevent the accumulation of corrosive substances.

Cathodic Protection: Implement cathodic protection methods, such as impressed current or sacrificial anodes, to protect the connectors and piping from corrosion. This technique involves introducing a more easily corroded metal (anode) to the system, which sacrifices itself to protect the connected metal (cathode) from corrosion.

Monitoring and Maintenance: Regularly monitor the corrosion levels and condition of the connectors and piping. Implement a maintenance program that includes periodic inspections, cleaning, and repairs, if necessary, to prevent corrosion from progressing.

It is important to consult with corrosion experts and engineers who specialize in SWRO plant operations to assess the specific conditions, perform material testing, and provide tailored solutions to mitigate the crevice corrosion problem effectively.

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Answer:

Fossil energy has been a fundamental driver of the technological, social, economic and development progress which has followed.In 2019, around 84% of global primary energy came from coal, oil and gas. Over the coming decades we need to rapidly reduce this share by displacing them with low-carbon energy sources.Fossil energy has been a fundamental driver of the technological, social, economic and development progress which has followed.In the sections above we looked at the consumption of fossil fuels collectively. But it’s important to look at the role of coal, oil and gas individually – their impacts are not equal. Coal, for example, typically produces more CO2 and local air pollution per unit of energy.There would be more research on the use of alternate fuels.Moreover, fossil fuels are composed primarily of carbon and hydrogen atoms. On combustion they produce carbon dioxide, sulfur dioxide, and carbon monoxide as the main by-products.Solar energy can only be captured during daylight hours.

Explanation:

if you write this then you will get full marks in your assignment it is valied for up to 16 class I don't know about any further it I have mixed many iconic and logic facts that are imp in science!

The concentration is measured by molarity, the formula of molarity is:

Based on the given data, we've already had the volume in liters and we have to convert 6.25 grams of HCl to moles. We have to use the molar mass of HCl which is 36.4 g/mol (you can find the molar mass using the periodic table). The conversion would be:

And the final step is to replace the values we have in the formula of molarity:

The molarity of 6.25 g of HCl in 0.300 L of solution is 0.573 M.

Answer:

increase

Explanation:

dont known reason burr answer is correct

Answer:

When temperature increases ,gas increases ,because of the rise in temperature evaporation will take place.

Explanation:

When you boil water to make coffee/tea the kettle/boiler releases the evaporation caused by the rise in temperature.

Answer:

0.01679

Explanation:

1 ml = 0.0001 dal

167.9×0.0001 = 0.01679

The units like milliliter [mL] and dekaliter [daL] are used to measure the volume of the substance. 167.9mL is converted into daL and is equivalent to 0.01679 daL.

Units of measurement are used to denote the physical quantities of the substances and are converted into various units of the metric system to express the same quantity but in various expressions. They are the magnitudes that express the various parameters.

The units milliliter [mL] and dekaliter [daL] are used to express the smaller physical quantities of the volume. They are the derived units that arrive from the fundamental units. The units from milliliter [mL] to dekaliter [daL] are converted as:

1 mL = 0.0001 daL

Given,

Volume = 167.9mL

The units are converted as:

1 mL = 0.0001 daL

167.9mL =  167.9mL × 0.0001 daL

= 0.01679

Therefore, 0.01679 daL is the volume.

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Answer:

The visible light spectrum is the section of the electromagnetic radiation spectrum that is visible to the human eye. Essentially, that equates to the colors the human eye can see. It ranges in wavelength from approximately 400 nanometers (4 x 10 -7 m, which is violet) to 700 nm (7 x 10 -7 m, which is red).

(Hope this helps) Sky

The number of moles of carbon, C, in the original sample is 0.83 moles.

Combustion analysis allows us to determine the composition of a compound by measuring the amounts of carbon dioxide and water produced. In this case, 7.00 g of the unknown compound produced 10.3 g of carbon dioxide and 4.20 g of water. To calculate the number of moles of carbon in the sample, we need to find the moles of carbon dioxide formed during combustion.

We can start by converting the mass of carbon dioxide into moles using its molar mass. The molar mass of carbon dioxide (CO2) is approximately 44.01 g/mol (12.01 g/mol for carbon and 16.00 g/mol for oxygen). Dividing the mass of carbon dioxide (10.3 g) by its molar mass gives us the number of moles: 10.3 g CO2 / 44.01 g/mol = 0.234 mol CO2.

Since carbon dioxide (CO2) has a 1:1 mole ratio with carbon (C) in the combustion reaction, we can conclude that there are 0.234 moles of carbon in the original sample.

Combustion analysis is a crucial technique used in chemistry to determine the elemental composition of a compound. By quantifying the amounts of carbon dioxide and water produced during combustion, it is possible to calculate the number of moles of carbon, hydrogen, and oxygen in the original compound.

This information can then be used to deduce the molecular formula of the unknown compound. By utilizing the principles of stoichiometry and the molar masses of the involved elements, scientists can derive valuable insights into the composition and structure of various organic compounds.

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Answer:

Tectonic plates

Explanation:

All the natural disasters like earthquakes, volcanoes and geysers appear throughout the region of New Zealand because of the movement of tectonic plates underneath the surface. New Zealand rests on the edges of two tectonic plates including the Pacific and the Australian plates.

According to the given statement 0.3345 M  is the molarity of the Ba(OH)₂ solution.

The quantity of a substance in a specific solution volume is known as its molarity (M). The amount of moles of a solute every litre of a solution is referred to as molarity. The molecular concentration of a solution is another name for molarity.

Ba(OH)₂+  2HCl ⇒ BaCl₂ + H₂O

Ratio of moles Ba(OH)₂ ,  

HCl  = 1:2

Amount of HCl consumed

= 0.500/1000*66.90

= 0.03345 mol

So Ba(OH)₂ reacted = 1/2 * 0.03345 mol

If  molarity of Ba(OH)₂ is x then

x/1000*50 = 1/2 * 0.03345

x =  0.3345 M.

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In a neutralization reaction, water is always formed. This is because a neutralization reaction involves the reaction of an acid and a base to form a salt and water.

The acid donates a hydrogen ion (H+) and the base donates a hydroxide ion (OH-) to form water (H+ + OH- -> H2O) and the remaining ions combine to form a salt. The salt formed depends on the specific acid and base used in the reaction. Therefore, the correct answer is: water.

Water is a transparent, colorless, odorless, and tasteless liquid that is essential for most forms of life. It is a chemical compound with the formula H2O, meaning it is made up of two hydrogen atoms and one oxygen atom, held together by covalent bonds.

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Answer:

maybe 16?

Explanation:

Answer:

B

Explanation:

I believe it is B but I am not entirely sure! don't do this is B doesn't sound or look right to you!

Answer:

Its D

Explanation:

Larger atoms in group 8A require higher boiling points for the molecules to separate from each other than smaller atoms in group 8A.

When the arrangement of atoms changes in a substance, the properties of the substance can change as well. The different arrangements of atoms can lead to different chemical and physical properties.

For example, if the atoms of a substance are rearranged to form a new compound, the new compound will have different chemical properties than the original substance. A new compound may have a different color, odor, reactivity, or melting point than the original substance.

Changing the arrangement of atoms without changing the chemical composition can change the physical properties. For example, a crystalline solid has atoms or molecules arranged in a regular, repeating pattern. This arrangement gives the material unique properties such as density, melting point, and hardness. If the arrangement of atoms and molecules changes, the properties of solids can also change.

In summary, when the arrangement of atoms in a substance changes, the properties of the substance can also change. Different arrangements of atoms have different chemical and physical properties.

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Answer:

The gas will occupy a volume of 1.702 liters.

Explanation:

Let suppose that the gas behaves ideally. The equation of state for ideal gas is:

\(P\cdot V = n\cdot R_{u}\cdot T\) (1)

Where:

\(P\) - Pressure, measured in kilopascals.

\(V\) - Volume, measured in liters.

\(n\) - Molar quantity, measured in moles.

\(T\) - Temperature, measured in Kelvin.

\(R_{u}\) - Ideal gas constant, measured in kilopascal-liters per mole-Kelvin.

We can simplify the equation by constructing the following relationship:

\(\frac{P_{1}\cdot V_{1}}{T_{1}} = \frac{P_{2}\cdot V_{2}}{T_{2}}\) (2)

Where:

\(P_{1}\), \(P_{2}\) - Initial and final pressure, measured in kilopascals.

\(V_{1}\), \(V_{2}\) - Initial and final volume, measured in liters.

\(T_{1}\), \(T_{2}\) - Initial and final temperature, measured in Kelvin.

If we know that \(P_{1} = 121\,kPa\), \(P_{2} = 202\,kPa\), \(V_{1} = 2.7\,L\), \(T_{1} = 288\,K\) and \(T_{2} = 303\,K\), the final volume of the gas is:

\(V_{2} = \left(\frac{T_{2}}{T_{1}} \right)\cdot \left(\frac{P_{1}}{P_{2}} \right)\cdot V_{1}\)

\(V_{2} = 1.702\,L\)

The gas will occupy a volume of 1.702 liters.

Answer:

a. chemical

Explanation:

Chemical energy is energy stored in the bonds of atoms and molecules.

One mole of pennies weighs 1.51 x 1024 g. The moon has a mass of and a penny weighs.

What does the word "mass" mean?

a way to gauge the amount of material that is present in or makes up a physical body. The mass of an item is important to Newton's equations of motion in classical mechanics because it affects the force required to accelerate it and, subsequently, how much inertia it has.

What does a mass and an illustration mean?

The best method to grasp mass is to consider how much matter each object or body is made of. There is mass in everything that we can see. A table, a chair, your bed, a football, a glass, and even air are examples of items with mass.

Briefing:

mass of 1 mole of pennies

Data: mass of 1 penny = 2.50 g

1 mole = 6.022 * 10^ 23 units

Proportion:

 1 penny      6.022 * 10^23 penny

-------------- = ----------------------------

  2.50 g                    x

Solve: x = 6.022 * 10^23 penny * 2.50g / 1 penny = 15.055* 10^23

Since 2.50 has 3 significant figures, the answer must use 3 significant figures => x = 15.1 * 10^ 23 g = 1.51 * 10^24 g

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Explanation:

The right answer is Look .........

Certain females may only love a male for his looks and money.

Certain females may love a male for his personality.

Certain females may love a male depending on his height.

That's all I know.

Grams of Sodium hydroxide : 26.72 g

Molality shows the number of moles dissolved in every 1000 grams of solvent.

m = n. (1000 / p)

m = Molality

n = Number of moles of solute

p = Solvent mass (gram)

Can be written :

\(\tt m=\dfrac{mol~solute}{kg~solvent}\)

m=2.88

kg solvent(water)=232 g=0.232 kg

\(\tt mol~solute=m\times kg~solvent\\\\mol~solute=2.88\times 0.232=0.668\)

\(\tt mass=mol\times MW\\\\mass=0.668\times 40~g/mol=26.72~g\)

Answer:

V= 6.4 L

Explanation:

P1V1= P2V2

(3.2)(2)=(1)V2

V2= 6.4 L

If the pressure of the container of oxygen gas decreases to the given value, the volume increases to 6.4L.

Boyle's law simply states that "the volume of any given quantity of gas is inversely proportional to its pressure as long as temperature remains constant.

Boyle's law is expressed as;

P₁V₁ = P₂V₂

Where P₁ is Initial Pressure, V₁ is Initial volume, P₂ is Final Pressure and V₂ is Final volume.

Given the data in the question question;

We substitute our given values into the expression above to determine the new volume.

P₁V₁ = P₂V₂

V₂ = P₁V₁ / P₂

V₂ = ( 3.2atm × 2.0L ) / 1.0atm

V₂ = 6.4Latm / 1.0atm

V₂ = 6.4L

Therefore, if the pressure of the container of oxygen gas decreases to the given value, the volume increases to 6.4L.

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