How many lenses are found in the simplest telescopes.

Answer:

16.64 km/h

Explanation:

Think of the x and y components as the a and b sides of a triangle and simply do the Pythagorean Theorem:

\(a^2+b^2=c^2\)

\(14^2+9^2=c^2\)

\(\sqrt{196+81}=c\)

\(\sqrt{277}=c\)

\(16.64 km/h\)

P1=P2=P3  is true about the pressure on the bottom in each container.

P=F/A

same area and same force lead to same pressure.

Pressure is defined as force/area. To calculate the pressure that snow exerts on a roof, divide the weight of the snow by the roof's surface area. Gases are a typical pressure source in physics. A "vacuum" is used to describe the absence of pressure. People have long held the belief that vacuums are improbably rare and unnatural because "nature abhors a vacuum." Actually, this is not the case.

The number of pressure units is ridiculous. The units torr or mmHg are frequently employed. The only subject of conversation is the height of a mercury column. The atmosphere contains 760 torr, or mmHg. You could also look at mmH2O, which makes use of a related idea.

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The wavelength of 6 x 10⁻⁷m is expected when frequency is 5 x 10¹⁴.

If the equations are different, the impact is huge. And the accumulation of matter consistent with the existence of life is wrong. That's one reason why it isn't. The Anthropic Principle states that in a universe incompatible with life, no life is arguing about it. When there are many universes, we occupy only the universe that nourishes us.

If our universe had 4 spatial dimensions (on our life scale), the equation would be 1/R. But every time we pass the jackhammer, we are reminded that our scale only has three spatial dimensions. The inverse square equation is not about the forces that follow it. The equations are about the nature of space (not space-time, just space, by the way).

E=hv

E=hc/y

v=c/y

y=c/v

y=3 x 10⁸/5 x 10¹⁴=6 x 10⁻⁷m

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A fuel-filled rocket is at rest. It burns its fuel and expels hot gas. The gas has a momentum of 1,500 kg m/s backward. So, The momentum of the rocket is -1500 kg m/s.

According to the law of conservation of momentum, in a closed system, the total momentum before and after a process remains constant.

A fuel-filled rocket that is initially at rest expels hot gas as it burns its fuel. The gas has a momentum of 1500 kg m/s backward.

We are required to determine the momentum of the rocket.

Consider the fuel-filled rocket as a system.

We have: Momentum before the burn = 0 kg m/s (since the rocket was at rest initially)Momentum after the burn = momentum of the expelled gas

We can therefore say that the initial momentum of the system was zero (0), and after the burn, the total momentum of the system remains the same as the momentum of the expelled gas.

Therefore: Momentum of rocket = - momentum of expelled gas

The negative sign signifies that the rocket's momentum is in the opposite direction of the expelled gas.

Hence, the momentum of the rocket is -1500 kg m/s.

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The magnet is moving down with the north pole downward, and during the transition, there will be an increase in magnetic flux through the ring, which will produce the induced current through the ring.

When the bar is moved toward loop the flux will increase and the induced current will counter this flux.

The induced current tries to oppose the change in magnetic flux and this is possible just if the current direction is counterclockwise.

Result: The current direction is counterclockwise

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Answer:

R = 35.8 Ω

Explanation:

Recall Ohm's Law:

V = I * R

then R = V / I

in our case:

R = 179 V / 5 A = 35.8 Ω

Answer:

the tension of the rope is 34.95 N

Explanation:

Given;

length of the rope, L = 3 m

mass of the rope, m = 0.105 kg

frequency of the wave, f = 40 Hz

wavelength of the wave, λ = 0.79 m

Let the tension of the rope = T

The speed of the wave is given as;

\(v = f\lambda = \sqrt{\frac{T}{\mu} } \\\\where;\\\\\mu \ is \ mass \ per \ unit \ length\\\\\mu = \frac{0.105}{3} = 0.035 \ kg/m\\\\v = f\lambda = 40 \times 0.79 = 31.6 \ m/s\\\\v = \sqrt{\frac{T}{\mu} } \\\\v^2 = \frac{T}{\mu} \\\\T = v^2 \mu\\\\T = (31.6^2)(0.035)\\\\T = 34.95 \ N\)

Therefore, the tension of the rope is 34.95 N

Answer:

Período del tambor: \(T = 0.25\,s\), fuerza sobre la prenda: \(F \approx 80.852\,N\), velocidad lineal del tambor: \(v \approx 10.053\,\frac{m}{s}\), velocidad angular del tambor: \(\omega \approx 25.133\,\frac{rad}{s}\).

Explanation:

La expresión tiene un error por omisión, su forma correcta queda descrita a continuación:

"Una prenda de 320 gramos de ropa gira en el interior de una lavadora si dicha lavadora tiene un radio de 40 centímetros y gira con una frecuencia de 4 hertz. Halle a) el período, b) la velocidad angular, c) la fuerza con la que gira la prenda y d) la velocidad lineal de la lavadora."

El tambor gira a velocidad angular constante (\(\omega\)), en radianes por segundo, lo cual significa que la prenda experimenta una aceleración centrífuga (\(a\)), en metros por segundo al cuadrado. En primer lugar, calculamos el período de rotación del tambor (\(T\)), en segundos:

\(T = \frac{1}{f}\) (1)

Donde \(f\) es la frecuencia, en hertz.

(\(f = 4\,hz\))

\(T = \frac{1}{4\,hz}\)

\(T = 0.25\,s\)

Ahora determinamos la fuerza aplicada sobre la prenda (\(F\)), en newtons:

\(F = m\cdot a\) (2)

\(F = \frac{4\pi^{2}\cdot m \cdot r}{T^{2}}\) (2b)

Donde:

\(m\) - Masa de la prenda, en kilogramos.

\(r\) - Radio interior del tambor, en metros.

(\(m = 0.32\,kg\), \(r = 0.4\,m\), \(T = 0.25\,s\))

\(F = \frac{4\pi^{2}\cdot (0.32\,kg)\cdot (0.4\,m)}{(0.25\,s)^{2}}\)

\(F \approx 80.852\,N\)

La velocidad lineal de la lavadora es:

\(v = \frac{2\pi\cdot r}{T}\) (3)

(\(r = 0.4\,m\), \(T = 0.25\,s\))

\(v = \frac{2\pi\cdot (0.4\,m)}{0.25\,s}\)

\(v \approx 10.053\,\frac{m}{s}\)

Y la velocidad angular del tambor de la lavadora:

\(\omega = \frac{2\pi}{T}\)

(\(T = 0.25\,s\))

\(\omega = \frac{2\pi}{0.25\,s}\)

\(\omega \approx 25.133\,\frac{rad}{s}\)

The tornado has the angular velocity of 0.568 revolutions per second. It is obtained by using the formula for angular velocity.

The formula for the angular velocity of the tornado can be found by:

ω = v/r

Where

We have a tornado with a diameter of 49.0 m and the linear velocity of wind of 315 km/h. Find the angular velocity in revolutions per second!

Let's find its radius and convert the unit of linear velocity.

The radius of the tornado can be found by dividing its diameter by 2:

r = d/2 = 49.0/2 = 24.5 m

The linear velocity in m/s is

315 km/h = 315 × 1,000 × 1/3,600 m/s

315 km/h = 87.5 m/s

We can rearrange the formula above to solve for angular velocity:

ω = v/r
ω = 87.5 m/s / 24.5 m
ω ≈ 3.57 rad per second

Remember that 1 revolution = 2π radians. So, we get angular velocity in rev per second:
ω = 3.57 rad/s

ω = 3.57/2π

ω ≈ 0.568 rev/s

Hence, the angular velocity of the tornado at its peak is approximately 0.568 revolutions per second.

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From a thermodynamic perspective, the thermodynamically irreversible process description among the following options is: Heat transfer between two objects with the same temperature.

In thermodynamics, an irreversible process is characterized by the inability to return the system and its surroundings to their initial state without external intervention. It is associated with an increase in entropy and the dissipation of energy. In the case of heat transfer between two objects with the same temperature, there is no temperature difference to drive the transfer of heat. Consequently, no useful work can be extracted from this process, and it does not generate any change or increase in entropy. As a result, this process is considered thermodynamically reversible since it can be easily reversed without any net change in the system or surroundings.

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The value of mass X will be 30kg if the three masses of people are 50 kg, X kg, and 15 Kg.

According to the principle of moments, the total sum of the clockwise and anticlockwise moments are equal when the system is in equilibrium. A system is considered to be in equilibrium when it is stable or in balance since all of the forces operating on it balance each other out.

Applying the principle of moment

Sum of anticlockwise moment=sum of clockwise moment

50 × 1.5 = X × 1.5 + 2 × 15

75 = 1.5 X + 30

75 - 30 = 1.5X

45 = 1.5X

X = 45/1,5

X = 30 kg

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Answer:

100kg

Explanation:

m=980n/9.8m/s^2=100kg

Mass is a constant quantity or property of a particle or an object. It doesn’t change.

Hence, mass of the man on the moon will be the same as mass of the man on earth; 100kg.

The weight of a particle or object is the force of gravity on the object; its is expressed as:

\(W = m * g\)

Where m is mass and g is acceleration due to gravity.

Given that the man's weight on earth is 980N and acceleration due to gravity g = 9.8m/s².

We substitute the values into the equation and solve for "m" mass\(980N = m * 9.8m/s^2\\\\m = \frac{980kg.m/s^2}{9.8m/s^2}\\\\m = 100kg\)

The man's mass on Earth is 100kg.

We know that, Mass is a constant quantity or property of a particle or object. It doesn’t change.

Hence, mass of the man on the moon will be the same as mass of the man on earth; 100kg.

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Answer:

Absolute strength = 1.25

Explanation:

Given:

Body weight of body = 120 lbs

Body weight of thing = 150 lbs

Find:

Absolute strength

Computation:

Absolute strength = Body weight of thing / Body weight of body

Absolute strength = 150 / 120

Absolute strength = 1.25

Answer:

It depends on the amount of pressure needed to cut the material.

Iron is a tougher material to cut though, so the blades must be shorter to create more pressure to break through the iron.

Cloth on the other hand is easier to cut through so the blades can be longer in order to cut more in each snip.

Explanation:

Answer:

The net force is 9.8ms2, but were you given the acceleration?

Important Formulas:

\(v=\lambda f\)

velocity(measured in m/s) = wavelength(measured in meters) * frequency(measured in hertz)

\(f=\dfrac{1}{T}\)

frequency(measured in hertz) = 1 / period(measured in seconds)

__________________________________________________________

Given:

\(v=362m/s\)

\(T=4.17s\)

\(\lambda=?\)

__________________________________________________________

Finding frequency:

\(f=\dfrac{1}{T}\)

\(f=\dfrac{1}{4.17}\)

\(f=0.24Hz\)

__________________________________________________________

Rearranging formula for velocity to make wavelength the subject:

\(v=\lambda f\)

\(\dfrac{v}{f} =\dfrac{\lambda f}{f}\)

\(\lambda=\dfrac{v}{f}\)

__________________________________________________________

Finding wavelength:

\(\lambda=\dfrac{v}{f}\)

\(\lambda=\dfrac{362}{0.24}\)

__________________________________________________________

\(\boxed{\lambda=1508.33m}\)

Answer:

Heavier than 2.2 pounds

Explanation:

Answer:

In coastal areas, strong winds and powerful waves break off soft or grainy rocks from hardier rocks. Too much weathering occurs, it might break off parts of the cliff and be dangerous to humans, or animals.

Rain has acid in it which could eat up the cliff.

Explanation:

The minimum force perpendicular to the wall that you must exert on the frame to keep it stationary is 43 N.

A force is described as an influence that causes the motion of an object with mass to change its velocity.

Given data :

Force = 18 newton

mass = ?

Acceleration = ?

We know that force = mass x Acceleration but in this case, we are looking for the minimum force perpendicular to the wall that you must exert on the frame to keep it stationary.

We get that

perpendicular Force =  force / coefficient of kinetic friction

perpendicular Force = 18 / 0.42

perpendicular Force = 43 newton

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The centripetal acceleration of the professor holding onto the end of the minute hand of a clock atop City Hall is 0.00133 m/s².

Centripetal acceleration is the inward force acting on a body moving in a circular path that changes the direction of the velocity of the body and constantly pulls it toward the center of the circle.To determine the professor's centripetal acceleration, we use the formula;

`a= (v²)/r`

Where `a` is the centripetal acceleration, `v` is the velocity, and `r` is the radius. We have the length of the minute hand which is the radius of the circle.

So,`r = 4 m`We need to find the velocity which is given by the formula:

`v= (2πr)/T`

Where `π` is pi (3.14), `r` is the radius, and `T` is the time taken for one complete rotation which is 60 minutes since it's the minute hand.

Therefore;`v = (2 x 3.14 x 4 m) / (60 min x 60 s / 1 min)``v = 0.42 m/s`Substitute `v` and `r` into `a = (v²)/r` to get:`a = (0.42 m/s)² / 4 m``a = 0.00133 m/s²`

Therefore, the centripetal acceleration of the professor holding onto the end of the minute hand of a clock atop City Hall is 0.00133 m/s².

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There is two component of force :-

First we solve cos component:-

Fcos60° = 200 × 0.5

Fcos60° = 100 N

Now, solve sin component:-

Fsin30° = 200 × 0.5

Fsin30° = 100 N

Push or pull of an object is called force. The unit of force is kg m s⁻², it is also called newton and is represented by N.

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Transfer function g(s)=vo(s)/vi(s) is G(s) = s/2s +1

In frequency domain Inductor L transforms to sL and Capacitor C transforms to 1/sC using this ,the output voltage in frequency i.e s domain using voltage division rule is

Vo (s) = Vi(s) * sL ║1 / 1 + sL║1 = Vi (s) * s║1 / 1+ s║1

assume L = 1H

Vo (s) = Vi (s) * s*1/s+1 / 1+ s*1/s+1

G(s) = Vo (s) /Vi (s) = s / s + 1+ s = s/2s + 1

G(s) = s/2s + 1

A mathematical function known as a system function or network function of a system, sub-system, or component theoretically simulates the output of the system for each potential input. Electronics and control systems use them extensively. This function, which is sometimes called a transfer curve or characteristic curve, is a two-dimensional graph of an independent scalar input vs a dependent scalar output. In electronics and control theory, transfer functions for components are used to build and analyze systems that are constructed from components, particularly when utilizing the block diagram technique.

The transfer function's parameters and units simulate the output response of the device for a variety of potential inputs.

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When the charges are brought closer together until they are 2 cm apart, the force between them becomes approximately 2.5 ×  \(10^{-4}\) N.

To determine the force between two charges when they are brought closer together from 10 cm to 2 cm apart, we can use the formula for Coulomb's Law:
F = k × |\(q_1 \times q_2\)| / r²
where F is the force between the charges,

k is Coulomb's constant (8.99 × \(10^9\) N·m²/C²),

\(q_1\) and \(q_2\) are the magnitudes of the charges, and r is the distance between the charges.
Since we know the initial force (F₁) and initial distance (r₁), we can find the product of the charges (\(q_1 \times q_2\)) using the formula:
F₁ = k × |\(q_1 \times q_2\)| / r₁²
Given F₁ = \(10^{-6}\) N and r₁ = 0.1 m,

we can solve for |\(q_1 \times q_2\)|:
\(10^{-6}\) = 8.99 × \(10^9\)  * |\(q_1 \times q_2\)| / 0.1²
|\(q_1 \times q_2\)| = (\(10^{-6}\)  * 0.1²) / 8.99 ×\(10^9\)
|\(q_1 \times q_2\)| ≈ 1.11 × \(10^{-11}\) C²
Now that we have the product of the charges, we can find the new force (F₂) when the charges are 2 cm (0.02 m) apart (r₂):
F₂ = k × |\(q_1 \times q_2\)| / r₂²
F₂ = 8.99 × \(10^9\) × 1.11 ×  \(10^{-11}\)/ 0.02²
F₂ ≈ 2.5 × \(10^{-4}\)  N
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The strong nuclear force overcomes the repulsive electric force of protons in the atomic nucleus because it is a much stronger force. It is able to act over very short distances and is mediated by particles that are much heavier than electrons and photons.

The repulsive electric force of protons in the atomic nucleus does not cause the protons to fly apart because of the strong nuclear force. The strong nuclear force is an attractive force between nucleons that overcomes the repulsion between protons due to the electromagnetic force. This force is responsible for holding the nucleus of an atom together.

We will explain the physics behind why the strong nuclear force overcomes the repulsive electric force. The protons in the nucleus are positively charged and would normally repel each other due to the electrostatic force. The reason why they do not is because they are held together by a stronger force, the strong nuclear force. This force acts between nucleons, which are particles found in the nucleus of an atom. The strong nuclear force is a short-range force that acts over distances of less than a femtometer. It is much stronger than the electrostatic force, which is why it is able to hold the nucleus together. The reason for this is that the strong nuclear force is mediated by particles called mesons, which are much heavier than electrons and photons. The strong force is able to overcome the repulsion between protons because it is much stronger than the electromagnetic force, which is what causes the repulsion in the first place.

The strong nuclear force overcomes the repulsive electric force of protons in the atomic nucleus because it is a much stronger force. It is able to act over very short distances and is mediated by particles that are much heavier than electrons and photons. This force is responsible for holding the nucleus of an atom together and is what allows for the existence of matter as we know it.

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The acceleration of the object with an applied force of 100N and a mass of 50kg is 2m/s².

Acceleration is defined as the change in velocity per unit time. Velocity is defined as the speed of the object in a particular direction. The acceleration is a vector quantity. The unit of acceleration is m/s².

According to Newton's second law, Force is directly proportional to the acceleration of the object. F = m×a, where F is the force of the object, m is the mass of the object and a is the acceleration of the object.

From the given,

Force, F = 100N

mass of the object, m=50kg

acceleration of the object, a=?

F = m×a

a =F/m

  = 100/50

  =2m/s².

Thus, the acceleration of the object is 2m/s².

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Answer:

Our kinetic energy becomes 4 times bigger

The radioactive decay equation for thorium-232 is  \(Th^{232} - > Ra^{238} + He^{4}\). The radioactive radiation activity of 10 g of thorium can be found by calculating the number of thorium-232 nuclei and then using the decay constant. The activity after 10 years can be determined using the radioactive decay law and the initial activity.

a) The radioactive decay equation for thorium-232 (\(Th^{232}\)) can be written as follows:

\(Th^{232} - > Ra^{238} + He^{4}\)

In this equation, thorium-232 decays into radium-228 by emitting an alpha particle (helium-4 nucleus). This process is a type of alpha decay.

b) To find the radioactive radiation activity of 10 g of thorium, we need to use the concept of activity. The activity (A) of a radioactive substance is defined as the rate at which radioactive decay occurs. It is measured in becquerels (Bq) or disintegrations per second.

To calculate the activity, we need to consider the number of radioactive nuclei present in the sample and the decay constant. The decay constant (λ) is related to the half-life (T1/2) of the isotope by the equation:

λ = ln(2) / T1/2

For thorium-232 with a half-life of 1.4 * \(10^{10}\) years, the decay constant is approximately λ = ln(2) / (1.4 * \(10^{10}\) years).

To find the number of radioactive nuclei (N) in 10 g of thorium, we can use Avogadro's number and the molar mass of thorium-232. The molar mass of thorium-232 is 232 g/mol.

N = (10 g) / (232 g/mol) * (6.022 * \(10^{23}\) nuclei/mol)

Now, we can calculate the activity (A) using the equation:

A = λ * N

c) To find the activity after 10 years, we use the radioactive decay law, which states that the activity of a radioactive substance decreases exponentially over time. The remaining activity (A_t) after a time t is given by:

A_t = A_0 * e^(-λ * t)

Where A_0 is the initial activity at t = 0.

To calculate the activity after 10 years, we substitute the appropriate values into the equation, including the initial activity calculated in part b, and evaluate A_t.

In summary, the radioactive decay equation for thorium-232 is  \(Th^{232} - > Ra^{238} + He^{4}\) To find the activity of 10 g of thorium, calculate the initial activity using the decay constant and the number of nuclei. Finally, to determine the activity after 10 years, use the radioactive decay law with the appropriate values.

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In order to get a stone slab to move, one would have to apply force to it. This can be done in a number of ways, depending on the situation. Here are a few possible laws that could be proposed for moving a stone slab:1. Newton's first law of motion: This law states that an object at rest will stay at rest unless acted upon by an external force. Therefore, to move a stone slab, one would need to apply a force to it.

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