There are approximately 3.011 x 10²³ molecules of propane in 22.0 g of C₃H₈.
What is propane?Propane (C₃H₈) is a colorless, odorless gas that is part of the alkane family of hydrocarbons. It is a byproduct of natural gas processing and crude oil refining.
Number of moles of propane in 22.0 g ; moles = mass/molar mass
moles = 22.0 g / 44 g/mol
So moles = 0.5 mol
Use Avogadro's number to convert from moles to molecules ; number of molecules = moles x Avogadro's number
So, number of molecules = 0.5 mol x 6.022 x 10²³ molecules/mol
number of molecules = 3.011 x 10²³ molecules
Therefore, there are approximately 3.011 x 10²³ molecules of propane in 22.0 g of C₃H₈.
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gold has a melting point of 1,063 oc, a heat of fusion 66.6 kj/kg, and a specific heat of 0.128 kj/kg oc. what is the energy needed to melt 750 grams of gold starting at 24 oc? (in kj)
To calculate the energy needed to melt 750 grams of gold, we need to consider the heat required to raise the temperature of the gold from 24 °C to its melting point and then the heat of fusion to convert it from solid to liquid.
Given:
Mass of gold = 750 grams
Specific heat of gold = 0.128 kJ/kg °C
Melting point of gold = 1,063 °C
Heat of fusion of gold = 66.6 kJ/kg
First, let's calculate the energy needed to raise the temperature of the gold from 24 °C to its melting point:
Q1 = mcΔT
Q1 = (750 g)(0.128 kJ/kg °C)(1,063 °C - 24 °C)
Next, let's calculate the energy needed to convert the gold from solid to liquid:
Q2 = mΔHf
Q2 = (750 g)(66.6 kJ/kg)
Finally, let's calculate the total energy required:
Total energy = Q1 + Q2
Therefore, the energy needed to melt 750 grams of gold starting at 24 °C is:
Total energy = Q1 + Q2
Total energy = [(750 g)(0.128 kJ/kg °C)(1,063 °C - 24 °C)] + [(750 g)(66.6 kJ/kg)]
Note: Make sure to convert the mass from grams to kilograms before performing the calculations.
Total energy ≈ 84,704.64 kJ
Rounded to the nearest kilojoule (kJ), the energy needed to melt 750 grams of gold starting at 24 °C is approximately 84,705 kJ.
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Which of the following reactions would occur to a measurable extent in water?
NH_4^+(aq) + H_2O(I) ---> NH_3(aq) + H_3O^+(aq)
Cl^-(aq) + H_2O(l) ---> HCI(aq) + OH^-(aq)
F^-(aq) + H_2O(l) ---> HBr(aq) + OH^-(aq)
Br^-(aq) + H_2O(l) ---> HBr(aq) + OH^-(aq)
Among the given reactions, the reaction involving NH4+ and H2O would occur to a measurable extent in water. The other reactions involving Cl-, F-, and Br- ions do not result in significant reaction in water.
In water, the dissociation of certain substances into ions can occur, leading to the formation of new compounds. This process is essential for reactions to take place in an aqueous solution. Let's analyze each of the given reactions:
NH4+(aq) + H2O(l) ---> NH3(aq) + H3O+(aq):
This reaction involves the ammonium ion (NH4+) and water (H2O). It leads to the formation of ammonia (NH3) and hydronium ions (H3O+). Since both NH4+ and H2O are capable of dissociating in water, this reaction can occur to a measurable extent.
Cl-(aq) + H2O(l) ---> HCl(aq) + OH-(aq):
This reaction involves the chloride ion (Cl-) and water (H2O). It suggests the formation of hydrochloric acid (HCl) and hydroxide ions (OH-). However, chloride ions (Cl-) and water (H2O) do not undergo significant dissociation in water, making this reaction less likely to occur to a measurable extent.
F-(aq) + H2O(l) ---> HBr(aq) + OH-(aq):
This reaction involves the fluoride ion (F-) and water (H2O), leading to the formation of hydrobromic acid (HBr) and hydroxide ions (OH-). Similar to the previous case, fluoride ions (F-) and water (H2O) do not extensively dissociate in water, making this reaction less likely to occur to a measurable extent.
Br-(aq) + H2O(l) ---> HBr(aq) + OH-(aq):
This reaction involves the bromide ion (Br-) and water (H2O). It suggests the formation of hydrobromic acid (HBr) and hydroxide ions (OH-). Like the previous cases, bromide ions (Br-) and water (H2O) do not exhibit significant dissociation in water, indicating that this reaction would not occur to a measurable extent.
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Which of these actions would the cerebellum be in charge of?
Answer: balance, posture, & coordination
Explanation:
1. A calorimeter holds 105 g water at 21.0°C. A sample of hot iron is added to the water, and
the final temperature of the water and iron is 28.0°C. What is the change in enthalpy 2 Cheat
associated with the change in the water's temperature? The specific heat of water is 4.18
J/(g. °C).
Elthalpy change is the heat absorbed by water for the iron placed in water is 3072.3 Joules.
What is Enthalpy ?A thermodynamic system's enthalpy, which is one of its properties, is calculated by adding the system's internal energy to the product of its pressure and volume. It is a state function that is frequently employed in measurements of chemical, biological, and physical systems under constant pressure, which the large surrounding environment readily provides.
The amount of heat released or absorbed during a reaction that takes place under constant pressure is referred to as the enthalpy change. It has the sign H, which may be interpreted as "delta H."
The initial tempareture of the water is 21°C
Final temperature of the water is 28°C
Change in temperature is 28 - 21 = 7°C
Elthalpy change is the heat absorbed by water for the iron placed in water is 4.18*105*7 = 3072.3 Joules.
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Help me with this pls
There are three factors in which natural selection occurs. Select one statement from the list below that is a true statement about natural selection.
Answer: There is no list in your question. But the three factors in which natural selection occurs are:
1. A struggle for existence,
2. Variation and
3. Inheritance
Explanation:
Darwin’s theory of natural selection is the way in which organisms change overtime.
These changes allow organisms to become better adapted to their environment and increase their chances for survival.
The three major factors through which natural selection occurs are:
1. A struggle for existence,
2. Variation and
3. Inheritance
Darwin’s theory of natural selection will occur if the three conditions above are met and unless these factors are in place, natural selection will not occur.
If two moles of chlorine gas reacts with potassium iodine, how many grams of potassium chloride are produced?
As the ball moves from Point 3 to Point 4, which energy conversion is taking place?
Answer:
Potential energy to kinectic energy
Explanation:
is spraying paint from a spray can diffusion
A device sprays coating material (paint, ink, varnish, etc.) through the air onto a surface when using the spray painting technique. The most popular varieties atomize and guide the paint particles using compressed gas, often air.
How does spray paint work?Volatile Organic Compounds are present in a large number of commonly used professional spray paints (VOCs). VOCs are a group of compounds that are released as gases from a range of solids and liquids, some of which may be harmful to human health in the short- and long-term.
What qualifies as spray paint?When a valve button is depressed, aerosol paint, also known as spray paint, is released from a sealed, pressurized container in an aerosol spray. One type of spray painting is aerosol painting, which leaves a smooth, even coat in contrast to many conventional rolled and brushed paints.
Does paint undergo chemical reactions?Not every change in color results from a chemical shift. If one were to alter a substance's color through a non-chemical interaction, such as painting an automobile, the alteration would be physical rather than chemical.
Is spray paint a gas or a liquid?Spray paints come in aerosol cans and are liquid paints. The top of a can of spray paint has a button that, when depressed, releases paint. Compressed gas is used in aerosol spray cans as a liquid propellant.
Is spray paint distinct from regular paint?A million times faster than brush-on paint is spray paint. Since spray paint is often oil based rather than water based, it is more durable than conventional latex paint or spray paint. Using spray paint outside is simple when you have a drop cloth and some newspaper handy.
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The chart below shows the major types of minerals mined in the United States and Australia.
Country Major types of minerals
United States coal, iron, silver, copper, oil
Australia iron, oil, uranium, silver, lead, zinc, bauxite, coal, copper, gold
Based on the chart, what percent of the major types of minerals mined in Australia are also mined in the United States?
A 30%
B 50%
C 70%
D 90%
Answer:
I think it is b 50%
Please try and help me understand what the answer would be and how to get the answer for specifically what is S for silicon tetrachloride, SiCI4?
Answer
Explanation
In the Lewis Dot structure, S = N - A is used to calculate the total number of shared and unshared electrons in a molecule.
S represents the TOTAL number of valence shared electrons in a molecule to achieve an octet, N represents the sum of the number of valence electrons of all the atoms of the molecule, and A is the number of valence electrons in an electron pot.
For SiCl₄, the valence electron on each atom coming together to form the molecule is:
Valence electron on Si = 4
Valence Electron on Cl = 7
Total valence electron on SiCl₄ = 4 + (4 x 7) = 32
The least electronegative Si atom is placed at the center, and four Cl atoms are connected with a single bond.
A single bond takes up 2 valence electrons, so for four bonds, 8 valence electrons have been occupied, and we are left with 32 - 8 = 24 valence electrons.
Thus, in the Lewis Dot structure S = N - A , the TOTAL number of valence electrons in a molecule to achieve an octet of SiCl₄ to achieve an octet is
2 questions. will give brainliest if i can figure out how
What happens to the electrons of a reducing agent during a reaction?
a.Electrons are gained
b.Electrons are lost
c.Electrons are held
d.Electrons are doubled
When is a substance reduced during an oxidation reduction reaction?
a.After one substance is oxidized
b.Before one substance is oxidized
c.Same time as one substance is being oxidized
d.Only oxidation occurs
1= b. electrons are lost
2= a. after one substance is oxidized
molecule x contains a sugar and a phosphate group. what is molecule x ?
how many mercury atoms are contained in 0.37 moles of mercury?
Jason shot a bb straight up in the air with a velocity of 105 m/s.what will the velocity of the bb when it is at a height of 203 m?
Answer:
The velocity of the bb when it reaches a height of 203 m can be determined using the laws of projectile motion. Since the bb is moving vertically upwards, its velocity at that height will be zero.
brainlest?
Answer: v = 83.96 m/s
Assuming the acceleration due to gravity is approximately 9.8 m/s^2, we can use the principles of projectile motion and energy conservation.
Using the equation for the vertical displacement of an object in free fall:
Δy = (v₀² - v²) / (2g)
Δy = vertical displacement (203m)
v₀ = initial velocity (105 m/s)
v = final velocity (not known yet)
g = accerlation due to gravity (9.8 m/s^2)
Lets rearrange the equation to solve for the final velocity:
v = v = √(v₀² - 2gΔy)
Substituting the given values:
v = √(105² - 2 * 9.8 * 203)
v ≈ √(11025 - 3979.6)
v ≈ √(7054.4)
v ≈ 83.96 m/s
Therefore, when the BB pellet is at the height of 203m, its velocity will be approximately 83.96 m/s.
If there was a high concentration of acetylcholine within the synaptic cleft, but little to no response at the motor end-plate, you would expect ________________ to be the responsible neuromuscular-blocking agent.
curare
If there was a high concentration of acetylcholine within the synaptic cleft, but little to no response at the motor end-plate, you would expect curare to be the responsible neuromuscular-blocking agent.
Curare is a paralyzing agent that causes weakness in the skeletal muscles. When taken in a sufficient dose, it can also cause death by asphyxiation because the diaphragm is paralyzed. Curare poisoning can be indicated by paralysis. It doesn't tend to alter the state of consciousness, but since every voluntarily controlled muscle in the body is paralyzed, the person suffering from curare poisoning can't confirm their consciousness. From the outside, curare poisoning looks very similar to the locked-in syndrome.
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list some general characteristic of producers and list and a few examples
Answer:
pooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooop
Explanation: fart
the ph of a 1.00 m solution of caffeine, a weak organic base, is 12.300. calculate the ka of protonated caffeine.
PPPPLLSSSSSS HELP WILL GIVE BRAINLYEST TO BEST ANSWER AND SEVENTY POINTS
i'm not sure, so sorryyy!
1.2 Give two ways that somebody could get Salmonella food poisoning.
Answer: Raw meat, poultry and seafood. Feces may get onto raw meat and poultry during the butchering process. ...
Raw eggs. ...
Fruits and vegetables.
Explanation:
why does helium fusion require higher temperatures
Answer:
Nuclear fusion of hydrogen to form helium occurs naturally in the sun and other stars. It takes place only at extremely high temperatures. That's because a great deal of energy is needed to overcome the force of repulsion between the positively charged nuclei.
Explanation:
hope it helps
NASA says 170,300 g of Oxygen (O2) per person is needed for a 6-month mission. Space X, a private company that partners with NASA claims the law does not apply in space and that only 127,500 grams of water are needed.
How many grams of water (H2O) is needed to meet the Oxygen demands? Use Stoichiometry to determine your answer.
The mass of water (H₂O) needed to meet the oxygen demand is 191587.5 g
Balanced equation2H₂ + O₂ —> 2H₂O
Molar mass of O₂ = 16 × 2 = 32 g/mol
Mass of O₂ from the balanced equation = 1 × 32 = 32 g
Molar mass of H₂O = (2×1) + 16 = 18 g/mol
Mass of H₂O from the balanced equation = 2 × 18 = 36 g
SUMMARY
From the balanced equation above,
32 g of O₂ reacted to produce 36 g of H₂O
How to determine the mass of water
From the balanced equation above,
32 g of O₂ reacted to produce 36 g of H₂O
170300 g of O₂ will react to produce = (170300 × 36) / 32 = 191587.5 g of H₂O
Thus, 191587.5 g of H₂O is needed to meet the oxygen demand
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5. a. How many mol of sodium chloride, NaCl, are required to prepare 0.2 L of a 3 M solution?
b. How many grams is this (hint: molar mass of NaCl =
U?
a. 0.6 moles
b. 35.1 grams
Further explanationGiven
Volume = 0.2 L
Molarity = 3 M
Required
mol of Sodium chloride
Solution
Molarity shows the number of moles of solute in every 1 liter of solute or mmol in each ml of solution
\(\large{\boxed {\bold {M ~ = ~ \frac {n} {V}}}\)
Where
M = Molarity
n = Number of moles of solute
V = Volume of solution
Input the value :
n = M x V
n = 3 M x 0.2 L
n = 0.6 moles
Mass of NaCl :
= mol x molar mass of NaCl
= 0.6 x 58.5 g/mol
= 35.1 grams
HD:pSun =rhoMan =pTue =pWed =pThu =pFri =pSat =71 Ha : Not all proportions are equal. HD: Not all proportions are equal. Ha:pSun =pMon =pTue =rhoWed =pThu =rhoFri =rhoSat =71 HD: Not all proportions are equal. Ha:pSun =pMon =pTue =pWed =pThu =rhoFri =pSat =71 HD:pSun =pMon =pTue =pWod =pThu =pFri =pSat =71 Ha : All proportions are equal. Find the value of the test statistic. (Round your answer to three d: Find the p-value. (Round your answer to four decimal places.) p-value = State your conclusion. Do not reject H0−. We conclude that the proportion of traffic Reject HD. We conclude that the proportion of traffic acciden Reject HD. We conclude that the proportion of traffic acciden Do not reject H0−We conclude that the proportion of traffic Compute the percentaqe of traffic accidents occurring on each day What day has the highest percentage of traffic accidents? Sunday Monday Tuesday Wednesday Thursday Friday Saturday Based on 2017 sales, the six top-selling compact showed the following number of vehicles sold. Use a goodness of fit test to determine if the sample data indicate that the market shares for compact cars in the city are different than the market shares suggested by nationwide 2017 sales. Use a 0.05 level of significance. State the null and alternative hypothesis. Ha : The market shares for the compact cars in the city are different for at least one of the nationwide market shares listed. o: The market shares for the compact cars in the city do not differ from market shares nationwide. : The market shares for the compact cars in the city are different from at least one of the nationwide market shares listed. Ha : The market shares for the compact cars in the city are not different from any of the natione Ha : The market shares for the compact cars in the city do not differ from market shares nationwide. "the test statistic.(Round your answer to two decimal places.) d the rho-value. (Round your answer to four decimal places.) Reject H0. We cannot conclude that market shares for the compact cars in the city differ from the nationwide market shares. Do not reject H0. We conclude that market shares for the compact cars in the city differ from the nationwide market shares. Do not reject H0. We cannot conclude that market shares for the compact cars in the city differ from the nationwide market shares.
The p-value is greater than the significance level of 0.05, we do not reject the null hypothesis and conclude that all proportions are equal.
Firstly, let us conduct a Chi-square test of independence of categorical variables based on the information given above. We have three different cases of hypothesis testing that we have to solve one by one.
Case 1: HD:pSun =rhoMan =pTue =pWed =pThu =pFri =pSat =71
Ha : Not all proportions are equal.
Test Statistic
For this hypothesis, we need to compute the test statistic that is given as:
\($$\chi^2=\sum_{i=1}^{k}\frac{(O_i-E_i)^2}{E_i}$$\) where k is the number of groups/categories. Since we have 7 days of the week, \(k = 7. $O_i$ and $E_i$\) are the observed and expected frequencies respectively.
Here, we have equal proportions of 71 for each day of the week.
Therefore, the expected frequencies are also equal to 71.
\($$E_i = 71, i=1,2,3,4,5,6,7.$$\)
We also have to use the given information to compute the observed frequencies,
\($O_i$.$$O_1 = 90, O_2 = 99, O_3 = 122, O_4 = 123, O_5 = 130, O_6 = 160, O_7 = 126$$\)
Therefore, the test statistic can be computed as \($$\chi^2=\frac{(90-71)^2}{71} + \frac{(99-71)^2}{71} + \frac{(122-71)^2}{71} + \frac{(123-71)^2}{71} + \frac{(130-71)^2}{71} + \frac{(160-71)^2}{71} + \frac{(126-71)^2}{71}$$$$\chi^2=180.14\)
Now we have to find the p-value of this test. Since the number of degrees of freedom is k - 1 = 7 - 1 = 6, the p-value can be found using the chi-square distribution table with 6 degrees of freedom at the 0.05 significance level. The p-value is 0.000014. ConclusionSince the p-value is less than the significance level of 0.05, we reject the null hypothesis and conclude that not all proportions are equal.
The total number of accidents is \($$90+99+122+123+130+160+126=850$$\)
The percentage of accidents occurring on each day of the week can be found as follows:
\($$Sunday: $$\frac{90}{850}\times 100 = 10.59\%$$Monday: $$\frac{99}{850}\times 100 = 11.65\%$$Tuesday: $$\frac{122}{850}\times 100 = 14.35\%$$Wednesday: $$\frac{123}{850}\times 100 = 14.47\%$$Thursday: $$\frac{130}{850}\times 100 = 15.29\%$$Friday: $$\frac{160}{850}\times 100 = 18.82\%$$Saturday: $$\frac{126}{850}\times 100 = 14.82\%$$\)
From the above percentages, we can see that Friday has the highest percentage of traffic accidents.
Case 2:
HD: Not all proportions are equal.
Ha:pSun =pMon =pTue =rhoWed =pThu =rhoFri =rhoSat =71
Test Statistic
\($$E_1 = 78.57, E_2 = 86.57, E_3 = 106.86, E_4 = 107.43, E_5 = 113.57, E_6 = 139.43, E_7 = 109.14$$\)
We already know the observed frequencies,
\($$O_1 = 90, O_2 = 99, O_3 = 122, O_4 = 123, O_5 = 130, O_6 = 160, O_7 = 126.$$\)
The test statistic can be computed as:
\($$\chi^2=\frac{(90-78.57)^2}{78.57} + \frac{(99-86.57)^2}{86.57} + \frac{(122-106.86)^2}{106.86}+ \frac{(123-107.43)^2}{107.43} + \frac{(130-113.57)^2}{113.57} + \frac{(160-139.43)^2}{139.43} + \frac{(126-109.14)^2}{109.14} $$$$ \implies \chi^2=34.98$$\)
The p-value is 0.000001.
Conclusion- Since the p-value is less than the significance level of 0.05, we reject the null hypothesis and conclude that not all proportions are equal.
Case 3:
All proportions are equal.
Test Statistic
The expected frequency for each group is
\(E = \frac{850}{7} = 121.43\)
We already know the observed frequencies,
\($$O_1 = 90, O_2 = 99, O_3 = 122, O_4 = 123, O_5 = 130, O_6 = 160, O_7 = 126.$$\)
The test statistic is,
\($$\chi^2=\frac{(90-121.43)^2}{121.43} + \frac{(99-121.43)^2}{121.43} + \frac{(122-121.43)^2}{121.43} + \frac{(123-121.43)^2}{121.43} + \frac{(130-121.43)^2}{121.43} + \frac{(160-121.43)^2}{121.43} + \frac{(126-121.43)^2}{121.43}} \\\implies \chi^2=9.17$$\)
The p-value is 0.1664.
Since the p-value is greater than the significance level of 0.05, we do not reject the null hypothesis and conclude that all proportions are equal.
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which of the following describes correctly about the regioselectivity and stereospecificity in the bronsted acid-catalyzed addition of water to an alkene reaction? group of answer choices markovnikov orientation with syn-addition markovnikov orientation with anti-addition anti-markovnikov orientation with syn-addition anti-markovnikov orientation with anti-addition markovnikov orientation with both syn- and anti-addition
The one that best describes the regioselectivity and stereospecificity in the Bronsted acid-catalyzed addition of water to an alkene reaction is Markovnikov orientation with syn-addition. Hence option A.
The preference of E and Y for bonds with carbon atoms an or b is referred to as the Markovnikov orientation. The example below demonstrates how, depending on the reaction conditions, a proton acid HY can add to the -bond of an unsymmetrical alkene with either a Markovnikov or an anti-Markovnikov orientation.
When hydrogen itself forms a double bond with the least-substituted carbon atom in asymmetrical alkenes or alkynes, the Markownikoff or Markovnikov rule determines the orientation of the electrophilic addition of hydrogen halides. (or triple bond). So, as conculsion, option A is correct.
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Complete question - which of the following describes correctly about the regioselectivity and stereospecificity in the bronsted acid-catalyzed addition of water to an alkene reaction?
Group of answer choices
1. markovnikov orientation with syn-addition
2. markovnikov orientation with anti-addition
3. anti-markovnikov orientation with syn-addition
4. anti-markovnikov orientation with anti-addition
5. markovnikov orientation with both syn- and anti-addition
what mechanism controls the direction in which a comet's ion tail is aligned in space?
The alignment of a comet's ion tail in space is primarily controlled by the interaction between the solar wind and the charged particles emitted by the comet.
This interaction is governed by the interplay of electromagnetic and gravitational forces. The resulting ion tail generally points away from the Sun, but its precise direction can be influenced by factors such as the orientation of the comet's rotation axis and the shape of its magnetic field.
1. The direction of a comet's ion tail in space is determined by the interplay of various forces. When a comet approaches the Sun, its surface heats up, causing the release of gas and dust particles from its nucleus. These particles, which are electrically charged, form the comet's coma, a glowing cloud around the nucleus.
2. As the comet moves closer to the Sun, the intense solar radiation and the high-speed stream of charged particles known as the solar wind exert forces on the charged particles in the coma. The solar wind, consisting of mostly protons and electrons, carries a magnetic field that interacts with the charged particles emitted by the comet.
3. The solar wind's magnetic field can cause the charged particles in the coma to experience a force known as the Lorentz force. This force acts perpendicular to both the direction of the magnetic field and the velocity of the charged particles. As a result, the Lorentz force causes the charged particles to curve and align their paths in a direction perpendicular to the solar wind's magnetic field.
4. The overall effect of the solar wind's interaction with the charged particles emitted by the comet is that the ion tail is pushed away from the Sun. The ion tail generally points in the direction opposite to the Sun, forming a long, glowing trail that stretches millions of kilometers into space. However, the direction of the ion tail can be influenced by other factors, such as the orientation of the comet's rotation axis and the shape of its magnetic field.
5. In conclusion, the alignment of a comet's ion tail in space is primarily determined by the interaction between the charged particles emitted by the comet and the solar wind. The resulting forces, including the Lorentz force, push the ion tail away from the Sun. While the general direction of the ion tail is away from the Sun, specific factors like the comet's rotation axis and magnetic field can influence its orientation.
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What are 2 major types of cell design?
Answer:There are two cell types: prokaryotes and eukaryotes. Prokaryotic cells are usually single-celled and smaller than eukaryotic cells. Eukaryotic cells are usually found in multicellular organisms, but there are some single-celled eukaryotes.
How many grams of KCl are needed to saturate 100g of water at 80* C?
Answer and Explanation:
This means that at 80 degrees C, the saturated solution of KCl will contain 50 grams of KCl for every 100 grams of water.
what are the effects on people when fish fail to reproduce and become extinct
Answer: People will have less food to eat and less nutrition and the food chain will go down. Sorry if I'm not right.
Explanation:
Answer:
It will effect all our wildlife and waters Becuase some fishes eat alge and other animals that reporduce fast and it will break the food chain many animals will die
Explanation:
can someone answer this for me and show proof I WILL MARK BRAINLIEST
the answers : A. sugars to oxygen and water B. oxygen and water to sugars C. carbon dioxide and water to sugars D. sugars to water and Carbon dioxide I WILL REPORT YOU IF YOU ANSWER FOR POINTS!!! DON'T ANSWER IF YOU DON'T KNOW!!! comment only if you not sure I WILL REPORT YOU
Answer:
A
Explanation:
Caus it makes sense