How many moles are in 7.8g of CaO?

Answer: alpha radiation, uranium, radium, radon, polonium,

Explanation:

10 radioactive substances are:

Answer:

Hypertension stage 1 is 130-139 mm of HG

The amount of acetic acid (CH₃COOH) in grams needed to prepare the solution is 90

This is defined as the mole of solute per unit litre of solution. Mathematically, it can be expressed as:

Molarity = mole / Volume

Molarity = mole / Volume

Cross multiply

Mole = Molarity × Volume

Mole of CH₃COOH = 1.5 × 1

Mole of CH₃COOH = 1.5 mole

Mole = mass / molar mass

Cross multiply

Mass = mole × molar mass

Mass of CH₃COOH = 1.5 × 60

Mass of CH₃COOH = 90 g

Thus, 90 g of CH₃COOH is needed to prepare the solution

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Answer:

This is balanced

Explanation:

Both sides contain 2 Ag 2 NO3 1 Ba and 2 Cl.

After 5 half-lives, approximately 3.125 grams of the Protactinium-234 sample would be left.

The half-life of Protactinium-234 is given as 6.7 hours, which means that after every 6.7 hours, the amount of Protactinium-234 in a sample is halved.

To determine how much of the sample would be left after 5 half-lives, we need to calculate the remaining fraction of the original sample. Each half-life reduces the amount of the sample to half of its previous value.

Number of half-lives = 5

Fraction remaining after each half-life = 1/2

To calculate the remaining mass, we can multiply the fraction remaining by the original sample mass:

Remaining mass = Original sample mass * (Fraction remaining)^(Number of half-lives)

Remaining mass = 150 g * (1/2)⁵

≈ 150 g * (1/32)

≈ 4.6875 g

≈ 3.125 g (rounded to three significant figures)

Therefore, approximately 3.125 grams of the Protactinium-234 sample would be left after 5 half-lives.

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The units for work are given by force multiplied by distance. Since force is measured in Newtons (N) and distance is measured in meters (m), the units for work will be N.m (Newton-meters). Therefore, the answer is N.m.

 The happy to help with your question. Given that work is calculated as force x distance, and the SI unit for force is Newton N, the units for work will be Work = Force x Distance Units N.m So, the correct answer is N.m Newton meters.The SI unit of work is the joule (J). It is defined as the work done by a force of one newton through a distance of one meter. One newton is equal to 1 kilogram meter per second squared. In plain English, 1 newton of force is the force required to accelerate an object with a mass of 1 kilogram 1 meter per second per second.

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Answer:

it would be OA that is negatively charged

Solving part-1 only

#1

KMnO_4

#2

Actually it's the oxidation number of Mn

Let's find how?

\(\\ \tt\Rrightarrow x+1+4(-2)=0\)

\(\\ \tt\Rrightarrow x+1-8=0\)

\(\\ \tt\Rrightarrow x-7=0\)

\(\\ \tt\Rrightarrow x=+7\)

#3

#4

\(\boxed{\begin{array}{c|c|c}\boxed{\bf Tube} &\boxed{\bf Charge} &\boxed{\bf No\:of\; electrons\: loss}\\ \sf 2 &\sf +6 &\sf 6e^-\\ \sf 3& \sf +2 &\sf 2e- \\ \sf 4 &\sf 4 &\sf 4e^-\end{array}}\)

Answer:

b molartiary will decrease

Explanation

Answer:

Explanation:

Butanoic acid С₄Н₈0₂

M = 4·12 + 8·1 + 2·16 =  88

The empirical formula represents the simplest whole number ratio. The molecular formula of the compound X with a relative molecular mass of 88 is Butanoic acid and the molecular formula is C₄H₈O₂.

The formula in which the actual number of all the atoms of various elements present in one molecule of the compound is represented is known as the molecular formula.

The molecular formula of a compound is a whole number multiple of its empirical formula.

Molecular formula = n × Empirical formula

Here butanoic acid has the molar mass 88.11 g/ mol and its molecular formula is C₄H₈O₂. It is a straight chain alkyl carboxylic acid and it is an oily colourless liquid. It is also used as a food flavoring agent and a safe food additive.

Thus the compound X is Butanoic acid or Butyric acid.

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Answer:

2C7H6O2 + 15O2 → 14CO2 + 6H2O  

Explanation:

C7H6O2 + O2 → CO2 + H2O

Carbon is not balanced (Reactant - 7, Product - 1)

Adding 7 to CO2;

C7H6O2 + O2 → 7 CO2 + H2O

Carbon is now balanced, however hydrogen is not balanced (Reactant - 6, Product - 3)

Adding 3 to H2O;

C7H6O2 + O2 → 7 CO2 + 3 H2O

Hydrogen is now balanced, however oxygen is not balanced (Reactant - 4, Product - 3)

Since 3H2O gives an odd value of O, multiply all through by 2;

2C7H6O2 + 2O2 → 14 CO2 + 6 H2O

Oxygen is still not balanced (Reactant - 8, Product - 34)

Change 2O2  to 15O2;

2C7H6O2 + 15O2 → 14CO2 + 6H2O  

Equation is now balanced.

Answer:

Chemicals

Explanation:

Your answer would be chemicals because of you have different inputs you would also have a different output depending.

I hope it helps! Have a great day!

Anygays-

Answer:

Chemicals

Explanation:

Different ATCG makes different chemicals.

I hope it helps! Have a great day!

Muffin °-°

Noble gases have completely filled electronic configuration. Therefore, noble gases or group 18 elements are inert in nature.

Noble gases are 18th group elements in periodic table. They are all having complete filled electronic configuration. The group members are helium, neon, argon, krypton, xenon and radon.

All these elements are existing in gaseous state and they are unreactive. Atoms become reactive when they have extra electrons or are deficient of electrons. Thus to achieve octet, they bond with other atoms.

In the case of noble gases, the valence shell is already achieved octet and no need of lose or gain of electrons. Thus, they are generally inert.

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The density of the liquid is 0.794 g/mL.

To calculate the density of the liquid, we can use the formula:

Density = Mass / Volume

Given information:

Mass of the graduated cylinder = 105.56 g

Volume of the liquid = 45.4 mL

Total mass of cylinder and liquid = 136.15 g

To find the mass of the liquid, we subtract the mass of the cylinder from the total mass:

Mass of the liquid = Total mass - Mass of the cylinder

Mass of the liquid = 136.15 g - 105.56 g

Mass of the liquid = 30.59 g

Now we can calculate the density:

Density = Mass of the liquid / Volume of the liquid

Density = 30.59 g / 45.4 mL

Converting mL to cm³ (since 1 mL = 1 cm³):

Density = 30.59 g / 45.4 cm³

Density = 0.674 g/cm³

Rounding to three decimal places, the density of the liquid is approximately 0.794 g/mL.

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The potential for the spontaneous reaction between the half-reactions oxaloacetate- 2H+ 2e- ⟶ malate- can be determined by comparing their standard reduction potentials (ε∘′).

Let's assume the reduction potential of the oxaloacetate half-reaction (cathode) is ε∘′1 and the reduction potential of the malate half-reaction (anode) is ε∘′2. The potential for the spontaneous reaction can be calculated as:
Potential = ε∘′2 - ε∘′1
For example, if ε∘′1 = 0.5 V and ε∘′2 = 0.3 V, then:
Potential = 0.3 V - 0.5 V = -0.2 V

In this case, the potential for the spontaneous reaction would be -0.2 V.
Note that the negative sign indicates that the reaction is spontaneous in the reverse direction, meaning the malate half-reaction is more favorable compared to the oxaloacetate half-reaction.

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The student should add 628 mL (or 0.628 L) of the 0.50 M solution of silver nitrate to precipitate 45.0 grams of solid silver chloride in the presence of excess sodium chloride.

To find the volume of a 0.50 M solution of silver nitrate, AgNO₃(aq), needed to precipitate 45.0 grams of solid silver chloride, AgCl(s), in a solution containing excess sodium chloride, NaCl(aq), follow these steps:

1. Write the balanced chemical equation:
AgNO₃(aq) + NaCl(aq) → AgCl(s) + NaNO₃(aq)

2. Calculate the moles of silver chloride needed:
First, find the molar mass of AgCl: (107.87 g/mol for Ag) + (35.45 g/mol for Cl) = 143.32 g/mol
Next, divide the mass of AgCl by its molar mass: 45.0 g / 143.32 g/mol = 0.314 moles of AgCl

3. Determine the moles of silver nitrate required:
Since the mole ratio of AgNO₃ to AgCl is 1:1, you need 0.314 moles of AgNO₃.

4. Calculate the volume of the 0.50 M silver nitrate solution needed:
Use the formula: moles = molarity × volume
Rearrange for volume: volume = moles / molarity
Substitute the values: volume = 0.314 moles / 0.50 M = 0.628 L

So, the student should add 0.628 L (or 628 mL) of a 0.50 M solution of silver nitrate to the solution containing excess sodium chloride to precipitate 45.0 grams of solid silver chloride.

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Answer:

Definetly Nitrogen

Explanation:

Nitrogen is the most electronegative

INFORMATION:

We know that:

- sodium and oxygen react to produce Sodium Oxide

-

The addition of NaF to one beaker of water would result in a decrease in the boiling point of the solution, while the addition of KF to the other beaker would result in an increase in the boiling point of the solution.

Adding NaF (Sodium Fluoride) and KF (Potassium Fluoride) to two separate beakers of water would result in different effects on the boiling point of the solutions. NaF, being a soluble ionic salt, would cause a decrease in the boiling point of the water. This happens because the presence of ions in the solution reduces the strength of the attractive forces between the water molecules, making it easier for them to vaporize at a lower temperature. On the other hand, KF, which is a slightly soluble ionic salt, would result in an increase in the boiling point of the water. This occurs due to the elevation effect of solutes, where the solute particles raise the vapor pressure of the solvent, making it more difficult for the solvent to vaporize. In summary, the boiling point of water can be either raised or lowered depending on the type of ionic salt that is added to it.

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When table salt (sodium chloride which ionizes into Na and Cl) is added to alginate, a gel does not form and spherification does not occur. This happens because the salt only has one positive charge that neutralizes the negative charge in the alginate.

There are various types of Spherification. Spherification is the creation of small spheres with a thin film on the surface and a liquid center. The process of spherification is mostly used in molecular gastronomy to make small, flavorful balls of liquid ingredients that burst in the mouth when bitten into. The method involves a process of encapsulating liquid droplets in a sphere made of a gel-like film. This process requires sodium alginate (E401), a gel-forming ingredient that thickens the liquids.

Sodium alginate gelation occurs as a result of the mixture of an alginate solution with a cation solution that causes the solution to gel. The sodium ions present in the solution swap with calcium ions present in the cation solution, causing a gel to form. This occurs as a result of a chemical reaction known as cross-linking. When table salt is added to the alginate solution, a gel does not form and spherification does not occur since the salt only has one positive charge that neutralizes the negative charge in the alginate. Alginate requires a doubly charged cation to cross-link.

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Calorimetry is a scientific technique used to measure the heat transfer or energy changes associated with chemical reactions or physical processes. It involves the use of a calorimeter, which is a device designed to contain and measure these energy changes. The important components of a calorimeter include a sample chamber where the reaction takes place, a thermometer to measure temperature changes, and an insulating material to minimize heat loss to the surroundings. Terms necessary for calorimetry include heat capacity (the amount of heat required to raise the temperature of the calorimeter), specific heat capacity (the amount of heat required to raise the temperature of a substance), and the principle of conservation of energy.

The self-inductance of the device is approximately \(\(-72727272.727 \, \text{mH}\).\)

To determine the self-inductance of the device, we can use the formula:

\(\[L = \frac{-V}{\frac{di}{dt}}\]\)

where:

- L is the self-inductance of the device,

- V is the induced emf (opposing voltage),

- \(\(\frac{di}{dt}\)\) is the rate of change of current.

Given:

\(\(V = 160 \, \text{V}\),\)

\(\(\frac{di}{dt} = \frac{2.20 \, \text{A}}{0.140 \, \text{ms}}\).\)

To calculate the self-inductance, we substitute the given values into the formula:

\(\[L = \frac{-160 \, \text{V}}{\frac{2.20 \, \text{A}}{0.140 \times 10^{-3} \, \text{s}}}\]\)

\(\[L = \frac{-160 \times 10^3 \, \text{V}}{2.20 \times 10^{-3} \, \text{A}}\]\)

Converting the units to millihenries (mH) by multiplying by\(\(10^3\)\):

\(\[L = \frac{-160 \times 10^3 \, \text{V}}{2.20 \times 10^{-3} \, \text{A}} \times 10^3 \, \text{mH}\]\)

Calculating the value: \(\[L = \frac{-160 \times 10^3 \, \text{V} \times 10^3 \, \text{mH}}{2.20 \times 10^{-3} \, \text{A}}\]\)

Simplifying further:

\(\[L = \frac{-160 \times 10^3 \times 10^3}{2.20 \times 10^{-3}} \, \text{mH}\]\[L = \frac{-160 \times 10^{3+3}}{2.20 \times 10^{-3}} \, \text{mH}\]\[L = \frac{-160 \times 10^{6}}{2.20 \times 10^{-3}} \, \text{mH}\]\)

\(\[L = \frac{-160 \times 10^{6}}{2.20 \times 10^{-3}} \, \text{mH}\]\[L = \frac{-160 \times 10^{6}}{2.20 \times 10^{-3}} \, \text{mH}\]\[L \approx -72727272.727 \, \text{mH}\]\)

Therefore, the self-inductance of the device is approximately \(\(-72727272.727 \, \text{mH}\).\)

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There were approximately 128.94 g of ZnSO4 and 109.34 g of CoSO4 present in the original solution.

Electroplating is the process of coating a metal object with a thin layer of another metal by means of electrolysis. In an electrolytic cell with a solution of a salt of the metal to be deposited, the item to be plated is made the cathode (negative electrode).

The electroplating of Zn and Co from the solution involves the transfer of electrons from the cathode to the metal ions in the solution, which results in the deposition of the metals on the cathode. The amount of electricity required for this process is proportional to the amount of metal ions present in the solution, which in turn is proportional to the mass of the metals deposited.

Let's first calculate the moles of electrons transferred in the electroplating reaction:

1.436 F × (1 mol e⁻/1 F) = 1.436 mol e⁻

Since the number of electrons transferred is the same for both Zn and Co, the ratio of the moles of Zn and Co deposited should be the same as the ratio of their atomic masses. The atomic masses of Zn and Co are 65.38 g/mol and 58.93 g/mol, respectively, so the ratio of their masses is:

65.38 g/mol ÷ 58.93 g/mol ≈ 1.11

This means that for every 1.11 moles of Zn deposited, 1 mole of Co is deposited.

Let's assume that x moles of ZnSO4 and y moles of CoSO4 were present in the original solution. Then we can set up the following equations based on the balanced electroplating reaction:

2 e⁻ + Zn²+ → Zn (s)

2 e⁻ + Co²+ → Co (s)

The total number of moles of electrons transferred in the electroplating reaction is:

1.436 mol e⁻ = 2 mol e⁻/mol Zn × x mol ZnSO4 + 2 mol e⁻/mol Co × y mol CoSO4

Simplifying and solving for y:

y = (1.436 mol e⁻ - 2 mol e⁻/mol Zn × x mol ZnSO4) / (2 mol e⁻/mol Co)

y = 0.718 mol CoSO4

Since the ratio of the moles of Zn to Co deposited is 1.11, we can calculate the moles of ZnSO4 from the moles of CoSO4:

x = (1.11 mol Zn/mol Co) × (0.718 mol CoSO4) = 0.798 mol ZnSO4

Finally, we can calculate the masses of ZnSO4 and CoSO4:

mass of ZnSO4 = 0.798 mol × 161.47 g/mol = 128.94 g

mass of CoSO4 = 0.718 mol × 152.06 g/mol = 109.34 g

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Answer:

True

Explanation:

Temperature is a direct measure of thermal energy, which means that the hotter an object is, the more thermal energy it possesses. The amount of thermal energy transferred between two systems is measured as heat. It is simple to convert mechanical energy to thermal energy, for example, through friction.

Answer:

False.

Explanation:

I did this lesson and I clicked true and got it wrong.

The ratio of octene to oxygen is 1:12.

To determine the ratio of octene (C8H16) to oxygen (O2) in the given reaction, we need to examine the balanced chemical equation. However, the equation you provided does not seem to be balanced. The coefficients for each compound must be determined to achieve a balanced equation before we can calculate the desired ratio.

Assuming you meant the combustion reaction of octene, a balanced equation would be:

C8H16 + 12O2 → 8CO2 + 8H2O

From the balanced equation, we can see that for every 1 mole of octene (C8H16), we require 12 moles of oxygen (O2) to completely react.

This means that for every 1 mole of octene, we need 12 moles of oxygen to fully combust the octene and produce the corresponding amounts of carbon dioxide (CO2) and water (H2O) as shown in the balanced equation.

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Answer:

Kinetic and potential energy

Explanation:

Because of acceleration

Answer:

E

Explanation:

I will offer a broad response based on the common equation for photosynthesis because precise formulae or experiments are not provided:

C6H12O6 + 6O2 = 6CO2 + 6H2O + sunshine.

The total mass of the reactants and products in each chemical reaction must match, according to the Law of Conservation of Mass. This means that in the case of photosynthesis, the number of atoms of each element present in the reactants and the number present in the products must be equal. One molecule of glucose (C6H12O6) and six molecules of oxygen (O2) are present on the reactant side of the equation, which contains six molecules of carbon dioxide (CO2) and six molecules of water (H2O). It is evident that the equation is balanced and adheres to the Law of Conservation of Mass by counting the number of atoms of each element on both sides of the equation.

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