How many moles of water are needed in order to produce 21.8 g of
calcium hydroxide?
CaC2 + 2H₂O -------> C₂H₂ + Ca(OH)2

The Correct electron configuration of carbon as 1s² 2s² 2p². Option B.

To understand why this is the correct electron configuration, let's break it down step by step:

The atomic number of carbon is 6, which means it has six electrons. Electrons are distributed in energy levels or shells around the nucleus.

The first shell, known as the 1s orbital, can hold a maximum of 2 electrons. Therefore, the first part of the electron configuration is 1s², indicating that two electrons occupy the 1s orbital.

The second shell has two subshells: the 2s orbital and the 2p orbital. The 2s orbital can hold a maximum of 2 electrons, while the 2p orbital can hold a maximum of 6 electrons. In the case of carbon, after the 1s orbital, two more electrons occupy the 2s orbital. So far, we have 1s² 2s².

The remaining two electrons in carbon are placed in the 2p orbital. The 2p orbital consists of three separate p orbitals: 2px, 2py, and 2pz. Each p orbital can hold a maximum of 2 electrons. Therefore, the last part of the electron configuration for carbon is 2p², indicating that two electrons occupy the 2px and 2py orbitals. Option B is correct.

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If 3 moles of MgCl₂ are put in the liter of the water then the true statement are :

d) True

e) True

f) True

g) True

h) True

The true statements are given below if the  3 moles of MgCl₂ are put in the liter of the water :

d) The solution would have an osmolarity of 6

e) The solution would have a molarity of 6

f) The solution would have a molarity of 1.5

g) The solution would have an osmolarity of 1.5

h) The solution would have an osmolarity of 9

The molarity can be calculated by the following formula :

Molarity = moles / volumes in L

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If the partial pressure of hydrogen in the mixture is 75 torr, the total pressure of the mixture is 100 torr.

Partial pressure is the notional pressure present in every gas.

Given,

The mole fraction of helium is 0.750.

The partial pressure of hydrogen in the mixture is 75 torr

The mole fraction of hydrogen is

To find the total pressure

By Roult's law

Partial pressures divided by mole fraction

75 / 0.750 = 100 torr

Thus, the correct option is a, 100 torr.

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There are approximately \(2.76 * 10^{24\) ammonia molecules in the given sample.

To calculate the number of ammonia molecules in the sample, we need to use Avogadro's number and the molar mass of ammonia.

The molar mass of ammonia \((NH_3)\) can be calculated by adding up the atomic masses of nitrogen (N) and hydrogen (H):

Molar mass of \(NH_3\) = (1 x atomic mass of N) + (3 x atomic mass of H)

              = (1 x 14.01 g/mol) + (3 x 1.01 g/mol)

              = 14.01 g/mol + 3.03 g/mol

              = 17.04 g/mol

Now, we can calculate the number of moles of ammonia in the sample using the formula:

Number of moles = Mass of the sample / Molar mass

Number of moles = 78.25 g / 17.04 g/mol

              ≈ 4.5865 mol (rounded to four decimal places)

Finally, we can use Avogadro's number, which represents the number of particles (atoms, molecules, etc.) in one mole of a substance. Avogadro's number is approximately \(6.022 * 10^{23\) particles/mol.

Number of ammonia molecules = Number of moles x Avogadro's number

Number of ammonia molecules ≈ 4.5865 mol x (\(6.022 * 10^{23\) molecules/mol)

                           ≈ \(2.76 * 10^{24\) molecules (rounded to two significant figures)

Therefore, the provided sample contains roughly \(2.76 * 10^{24\) ammonia molecules.

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The number of ammonia molecules in the sample is approximately 2.764 x \(10^{24}\) molecules.

To calculate the number of ammonia molecules in a given sample, we need to use Avogadro's number and the molar mass of ammonia.

The molar mass of ammonia (NH3) is calculated as follows:

Molar mass of N = 14.01 g/mol

Molar mass of H = 1.01 g/mol

Total molar mass of NH3 = 14.01 g/mol + (3 * 1.01 g/mol) = 17.03 g/mol

Now, we can calculate the number of moles of ammonia in the sample:

Number of moles = Mass of sample / Molar mass of NH3

Number of moles = 78.25 g / 17.03 g/mol = 4.594 moles

Next, we use Avogadro's number, which states that there are 6.022 x \(10^{23}\) molecules in one mole of a substance.

Number of molecules = Number of moles * Avogadro's number

Number of molecules = 4.594 moles * 6.022 x \(10^{23}\) molecules/mol = 2.764 x \(10^{24}\) molecules

Therefore, there are approximately 2.764 x \(10^{24}\) ammonia molecules in the given sample of 78.25 g.

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Explanation:

Zinc is the anode (solid zinc is oxidised). Silver is the cathode (silver ions are reduced).

By convention in standard cell notation, the anode is written on the left and the cathode is written on the right. So, in this cell: Zinc is the anode (solid zinc is oxidised). Silver is the cathode (silver ions are reduced).

Answer:

Evaluate the result (Apex)

Explanation:

This extremely high temperature indicates that under normal conditions, you do not need to worry about your car tire bursting from overheating as it is unlikely to reach such extreme temperatures.

To determine the temperature at which the tire will burst, we can use the ideal gas law equation:

PV = nRT

Where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin.

Rearranging the equation to solve for temperature, we have:

T = PV / (nR)

Given that the pressure threshold for bursting is 1.4 x 10^3 kPa, the volume is 30 L, and the number of moles of air is 2.5 mol, we can substitute these values along with the ideal gas constant R = 8.314 J/(mol K) into the equation.

T = (1.4 x 10^3 kPa) * (30 L) / (2.5 mol * 8.314 J/(mol K))

Converting kPa to Pa and L to m^3, and simplifying the equation, we find:

T ≈ 20,993 K

This extremely high temperature indicates that under normal conditions, you do not need to worry about your car tire bursting from overheating as it is unlikely to reach such extreme temperatures.

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Answer:

A. Solubility of calcium sulfite increases

B. Solubility of calcium fluoride increases

C. Solubility of Silver bromide decreases

Explanation:

The solubility factor is proportional to ions' concentration. The solubility of a solution can be predicted from Le Chatelier's principle which states that if an external constraint is imposed on a system in equilibrium, the equilibrium position will shift in order to annul the effect of the external constraint. So, If the reactant's concentration increases, the equilibrium shifts to the right indicating a higher solubility of the solution and if the product's concentration increases, the equilibrium shifts to the left indicating a lesser solubility of the solution.

Case 1. Calcium sulfite

The dissociation reaction of CaSO3 is given below:

CaSO3 ----> Ca²+ + SO3²-

SO3²- is the conjugate base of the weak acid, H2SO3. Therefore, on the addition of hydrobromic acid, some of the sulfite ion is removed from the solution by the following reaction;

H+ + SO3²- ---> HSO3-

This shifts the equilibrium to the right, more dissociation, thereby resulting in more solubility of the solute.

Case 2. Calcium fluoride

The dissociation reaction of calcium fluoride (CaF2) is shown below.

CaF2 ----> Ca²+ + 2F-

Fluoride ion (F-) is a strong conjugate base of the weak acid. Therefore, some of fluoride ions is removed by the addition of hydrobromic acid as shown below:

H+ + F- ---->. HF

Hence, the concentration of fluoride ions reduces, shifting equilibrium in the forward direction. Therefore, the solubility will be more than in pure water solution.

Case 3: Silver bromide

The dissociation reaction of AgBr is as follows:

AgBr ----> Ag+ + Br-

The addition of HBr will increase the concentration of bromide ions. Hence, equilibrium will shift in backward direction resulting in a lesser solubility than in water.

The solubility of calcium sulfite and calcium fluoride is greater in 0.10 M hydrobromic acid solution than in pure water while the solubility of silver bromide is lesser in 0.10 M hydrobromic acid solution than in pure water.

Common ion effect refers to the decrease in solubility of a substance in a solution that contains another solute with which it has a common ion. If a substance is dissolved in a solution that contains a solute with which it has a common ion, the solubility of the substance in that solution is less than its solubility in pure water.

Considering the substances given, the solubility of calcium sulfite and calcium fluoride in 0.10 M hydrobromic acid solution is more than their solubility in pure water the equilibrium position is shifted in the forward direction.

However, solubility of silver bromide in 0.10 M hydrobromic acid solution is less than its solubility in pure water due to common ion effect.

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Answer:

fan is a powered machine used to create a flow of air. A fan consists of a rotating arrangement of vanes or blades, ... Most fans are powered by electric motors

Answer:

James Chadwick conducted an experiment where he assailed the element Beryllium with alpha particles that came from the radioactive decay of Polunium. The experiment results showed highly penetrating radiation emitted from the Beryllium. In this, Chadwick proposed that radiation consisted of uncharged particles, which were later founded as neutrons.

6.02 x \(10^{20\) formula units of MgCl₂ is equal to 0.1 moles of MgCl₂.

To convert formula units of MgCl₂ to moles of MgCl₂, we need to use Avogadro's number, which relates the number of formula units to the number of moles.

Avogadro's number (NA) is approximately 6.022 x 10^23 formula units per mole.

Given that we have 6.02 x 10^20 formula units of MgCl₂, we can set up a conversion factor to convert to moles:

(6.02 x 10^20 formula units MgCl₂) * (1 mol MgCl₂ / (6.022 x 10^23 formula units MgCl₂))

The formula units of MgCl₂ cancel out, and we are left with moles of MgCl₂:

(6.02 x 10^20) * (1 mol / 6.022 x 10^23) = 0.1 mol

Therefore, 6.02 x 10^20 formula units of MgCl₂ is equal to 0.1 moles of MgCl₂.

It's important to note that this conversion assumes that each formula unit of MgCl₂ represents one mole of MgCl₂. This is based on the stoichiometry of the compound, where there is one mole of MgCl₂ for every one formula unit.

Additionally, this conversion is valid for any substance, not just MgCl₂, as long as you know the value of Avogadro's number and the number of formula units or particles you have.

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The skeletal structure of the organic compounds are the series of the atoms bonded together and form the important structure of the compound.

The statements that describe important rules for drawing skeletal structures are :

1)  all heteroatoms and the hydrogens directly bonded to them.

2)  there is a carbon atom at the junction of any two lines or at the end of any line.

3) there are enough hydrogens around each carbon to give it four bonds.

These three option are the correct statements to describe the important rule for the drawing skeletal structures to represents the important structure of the organic compound.

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Van Deemter's equation is represented by the notation A + B/u + Cu, where A represents eddy diffusion, B represents longitudinal molecular diffusion, and C represents mass transfer, contribute to separation.

One of the most crucial components of the van Deemter equation is the stationary phase particle size. The plate number (Nth) and the column packing's particle size have an inverse relationship for a given column length. The plate number and separation power increase with particle size. In order for the distinct components to be gathered in their purest form during chromatography, the components in solution must be sufficiently separated. The gap between the bands for each component increases, making it simpler to accomplish this.

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Answer: The final pressure inside the tank is 8.41 kPa.

Explanation: We can use the combined gas law to solve this problem, which relates the pressure, volume, and temperature of a gas:

(P1V1)/T1 = (P2V2)/T2

where P1, V1, and T1 are the initial pressure, volume, and temperature, respectively, and P2, V2, and T2 are the final pressure, volume, and temperature, respectively.

We are given P1 = 25.0 kPa, T1 = -50 C = 223 K, and V1 is unknown. We also know that the temperature decreases by a factor of three, so T2 = T1/3 = 223/3 K.

To find V2, we need to assume that the steel container is rigid and its volume remains constant. Therefore, V1 = V2, and we can cancel out the volume from the equation:

P1/T1 = P2/T2

Substituting the values, we get:

P2 = P1 * T2 / T1 = 25.0 * (223/3) / 223 = 8.41 kPa

Therefore, the final pressure inside the tank is 8.41 kPa.

Answer:

So if pressure of a gas is increased by 25%, the volume of a gas is decreased by 25%.

Explanation:

The statement that describes the Aufbau principle is ; ( A ) each electron is added to the lowest energy level orbital available

The Aufbau principle states that at ground level of an atom/ion the orbitals of the lowest energy levels of the atom are first filled up by electrons.  therefore

It can be said that each electron is added to the lowest energy level orbital available before electrons will be added to orbitals with higher energy levels.

Hence we can conclude that The statement that describes the Aufbau principle is each electron is added to the lowest energy level orbital available

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The volume of the gas will be 560 mL when the pressure is reduced to 125.0 kPa, assuming the temperature remains constant.

Boyle's law simply states that "the volume of any given quantity of gas is inversely proportional to its pressure as long as temperature remains constant.

Boyle's law is expressed as;

P₁V₁ = P₂V₂

Where P₁ is Initial Pressure, V₁ is Initial volume, P₂ is Final Pressure and V₂ is Final volume.

Substituting the given values, we get:

P₁ = 350.0 kPa (initial pressure)

V₁ = 200 mL (initial volume)

P₂ = 125.0 kPa (final pressure)

V₂ = ?

Solving for V₂, we get:

V₂ = ( P₁ × V₁ ) / P₂

V₂ = (350.0 kPa × 200 mL) / 125.0 kPa

V₂ = 560 mL

Therefore, the final volume of the gas is  560 mL.

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The force applied to the rocket by its engines remains constant as it moves up, while its mass decreases, resulting in an increase in acceleration.

Newton's laws of motion provide an explanation for the acceleration of a rocket as it moves away from the ground. According to Newton's second law, the force exerted on an object is directly proportional to its acceleration, and the force required to move an object increases as its mass increases.

In the case of a rocket, its mass decreases as it consumes fuel, which means that less force is required to move it as it climbs higher into the atmosphere.

As the rocket moves up, its acceleration increases while the force exerted on it remains constant. Newton's second law of motion explains that the acceleration of an object is directly proportional to the force applied to it. According to the second law of motion, an object's acceleration is equal to the force exerted on it divided by its mass.

This means that as the rocket climbs higher and its mass decreases due to the consumption of fuel, less force is required to accelerate it, and so its acceleration increases. In other words, the rocket's acceleration is increasing because the force required to move it is decreasing due to the decreasing mass of the rocket.

This phenomenon is also related to Newton's third law of motion, which states that every action has an equal and opposite reaction. The force exerted by the rocket's engines is balanced by an equal and opposite force exerted on the rocket by the exhaust gases, according to this law.

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Answer:

386 milligrams

Explanation:

Hey there! The answer is:

386 milligrams

Explanation:

To figure this out multiply 0.386 by 1000 because a milligram is 1000x bigger than a gram.

0.386 x 1000 = 386

Also, because it is 1000 times bigger, you can move the decimal over 3 places because there are 3 zeros in 1000.

Let me know if you have any questions! :)

The maximum mass of carbon dioxide that could be produced by the chemical reaction is 46.2 g

First, we shall determine the limiting reactant. This obtained as follow

2CH₃(CH₂)₂CH₃ + 13O₂ -> 8CO₂ + 10H₂O

From the balanced equation above,

116 g of CH₃(CH₂)₂CH₃ reacted with 416 g of O₂

Therefore,

48 g of CH₃(CH₂)₂CH₃ will react with = (48 × 416) / 116 = 172.14 g of O₂

From the above calculation, we can see that a higher amount (i.e 172.14 g) of O₂ than what was given (i.e 54.6 g) is needed to react with 48 g of CH₃(CH₂)₂CH₃

Thus, the limiting reactant is O₂

Finally, we shall determine maximum mass of carbon dioxide, CO₂ produced. Details below:

2CH₃(CH₂)₂CH₃ + 13O₂ -> 8CO₂ + 10H₂O

From the balanced equation above,

416 g of O₂ reacted to produce 352 g of CO₂

Therefore,

54.6 g of O₂ will react to produce = (54.6 × 352) / 416 = 46.2 g of CO₂

Thus, the maximum mass of carbon dioxide, CO₂ produced is 46.2 g

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Answer:

The molar mass of:

Helium = 4.00 g/mol

Potassium = 39.0983 g/mol

Manganese = 54.94 g/mol.

Boron = 10.81 g / mol

Explanation:

Helium = 4.00 g/mol

Potassium = 39.0983 g/mol

Manganese = 54.94 g/mol.

Boron = 10.81 g / mol

Answer:

Explanation: Sodium Nitroprusside, whose molecular formula is  • 2H2O, and whose molecular weight is 297.95. Dry sodium nitroprusside is a reddish-brown powder, soluble in water.

Answer:

Pressure

Explanation:

In an open system, the vapor pressure is equal to the outside air pressure.

The student obtained a higher final temperature in the calorimeter when using water compared to using automobile antifreeze due to water's higher specific heat capacity (4.18 J/g°C).

To determine in which experiment the student obtained the higher final temperature in the calorimeter, we need to compare the heat capacities of water and automobile antifreeze.

Water has a specific heat capacity of 4.18 J/g°C, while automobile antifreeze has a specific heat capacity of 2.41 J/g°C. The specific heat capacity represents the amount of heat required to raise the temperature of a given substance by 1 degree Celsius per gram.

Since the student used the same amount of copper in both experiments, the heat transferred to the calorimeter (water or antifreeze) will depend on its heat capacity. A higher heat capacity means that more heat can be absorbed by the substance without a significant increase in temperature.

Since water has a higher specific heat capacity (4.18 J/g°C) compared to automobile antifreeze (2.41 J/g°C), it can absorb more heat per gram without a substantial rise in temperature. Therefore, when using water in the calorimeter, the student is likely to obtain a higher final temperature compared to when using antifreeze.

In summary, the student would obtain a higher final temperature in the calorimeter when using water rather than automobile antifreeze due to the higher specific heat capacity of water.

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Answer:

2.3 mol of N2

Explanation:

mol N2 = 3.5 mol O2 x. 2 mol N2  

3 mol O2. = 2.3 mol N2.

Answer:

The answer is cell wall

Explanation:

Because it is

Answer:

It is a becaues i am a doctor and i know about that

Explanation:Just here to help

Answer:

K = 8x10¹⁸

Explanation:

When you sum a reaction, the result of this sum has a K equal to the multiplication of the K's of the reactions involved in the sum

The sum of two times the reaction:

NaO(g) ⇌ Na(l) + 1/2 O₂(g) K₂ = 2x10⁻⁵

2 NaO(g) ⇌ 2 Na(l) + O₂(g) K = K₂ₓK₂ = (2x10⁻⁵)² = 4x10⁻¹⁰

The result of the inverse reaction:

Na₂O₂(s) ⇌ 2 Na(l) + O₂(g) K₃= 5x10⁻²⁹

2 Na(l) + O₂(g) ⇌ Na₂O₂(s) K = 1/K₃ = 2x10²⁸

And the sum of the two bolded reactions:

2 NaO(g) + 2 Na(l) + O₂(g) ⇌ 2 Na(l) + O₂(g) + Na₂O₂(s)

2 NaO(g) ⇌ Na₂O₂(s) K = 4x10⁻¹⁰× 2x10²⁸