How many more barrels of gasoline than diesel were produced last year?
Answers
Related Questions
You purchase an old farmhouse for $175,000 with a 30% down payment. You have two loan options.
Loan #1: 7.25% for 20 years
Loan #2: 7.00% for 25 years
Answers
For Loan #1, the interest rate is 7.25%, and the loan term is 20 years. Using a mortgage calculator, the monthly payment would be $912.52, and the total interest paid over the life of the loan would be $119,005.24.
For Loan #2, the interest rate is 7.00%, and the loan term is 25 years. Using a mortgage calculator, the monthly payment would be $832.05, and the total interest paid over the life of the loan would be $139,614.68.
Comparing the two loans, Loan #2 has a lower interest rate and a longer loan term, which results in a lower monthly payment but a higher total interest paid over the life of the loan. Loan #1 has a higher interest rate and a shorter loan term, which results in a higher monthly payment but a lower total interest paid over the life of the loan.
In the end, the choice between the two loans depends on the individual's financial situation and priorities. If the individual values a lower total interest paid over the life of the loan and can afford a higher monthly payment, then Loan #1 may be the better option. If the individual values a lower monthly payment and is willing to pay more in total interest over the life of the loan, then Loan #2 may be the better option.
Chloe performs two transformations on trapezoid ARCD Io prove that it is congruent to trapezoid EFGH. Move phrases to the table to show two transformations that Chloe could perform reflection across a vertical line reflection across a diagonal line clockwise rotation of 90 degrees reflection across a honzontal line clockwise rotation of ISO degrees
Answers
Answer:
Clockwise rotation of 90 degrees and reflection across a vertical line. (as shown in picture)
Step-by-step explanation:
Hope this helps! Please let me know if you need more help, or if you think my answer is incorrect. Brainliest would be MUCH appreciated. Have a great day! :)
Need this ASAP PLZ .........................................:........
Answers
I don't now just need points
Elyas is on holiday in Greece.
He wants to buy a pair of sunglasses for €90
The exchange rate is €1 = £0.875
Elyas says, "The sunglasses cost less than £70"
Using a suitable approximation, show that Elyas is wrong.
Answers
Answer:
To convert euros to pounds, we have to multiply the amount in euros by the exchange rate. So, the sunglasses cost 90 * 0.875 = 78.75 pounds.
To use a suitable approximation, we can round the exchange rate to the nearest hundredth, which is 0.88. This makes the calculation easier and gives a close estimate of the actual value.
Using the rounded exchange rate, the sunglasses cost 90 * 0.88 = 79.2 pounds.
We can see that both the exact and the approximate values are greater than 70 pounds, so Elyas is wrong. The sunglasses cost more than 70 pounds
Step-by-step explanation:
Listed below is a table showing the number of employees. 20 years or older by gender in the United states
Answers
The total number of workers that were studied can be found to be 139,340,000.
The percent of workers unemployed would be 5. 4 %.
Percentage of unemployed men is 5. 6 % and unemployed women is 5. 1%.
How to find the employment figures ?Number of employed workers :
= 74,624,000 + 64, 716, 000
= 139,340,000
Percentage unemployed :
= ( 4, 209,000 + 3,314,000 ) / 139,340,000
= 5. 4 %
Percentage of unemployed men :
= 4,209,000 / 74,624,000
= 5.6 %
Percentage of unemployed women:
= 3,314,000 / 64, 716, 000
= 5. 1 %
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The full question is:
a. How many workers were studied?
b. What percent of the workers were unemployed?
c. Compare the percent unemployed for the men and the women.
Complete the following indirect proof (proof by contradiction).
Given: Adjacent angles LA and ZB, formed by the intersection of two lines
Prove: At least one of the angles LA and B has measure 90° or greater
Answers
First, we assume that this conclusion is false. In other words, we assume that the contrary statement "none of the two angles has measure \(90^{\circ}\) or greater" is true.
The assumption is equivalent to the following two statements:
(1) \(m\angle A\text{ } \boxed{ < 90^{\circ}}\)
(2) \(m\angle B\text{ } \boxed{ < 90^{\circ}}\)
Using (1) and (2) and the addition properties of inequalities, we conclude that \(m\angle A+m\angle B \text{ } \boxed{ < } \text{ } 180^{\circ}\).
On the other hand, two adjacent angles form a linear pair. Thus, the last statement contradicts the Linear Pair Property, which states that for a linear pair of angles \(\angle A\) and \(\angle B\), \(m\angle A+m\angle B \text{ } \boxed{=} \text{ } 180^{\circ}\).
Therefore, the assumption made is false, and the statement "at least one of the angles \(\angle A\) and \(\angle B\) has measure \(90^{\circ}\) or greater" is true.
Write 1 1/6 as an improper fraction
Answers
Step-by-step explanation:
Improper fractions have a numerator that is larger than the denominator
1 = 6/6
so 1 1/6 = 7/6
(-4x + 5) - (6x + 7) = 0
What is the solution to the equation?
O x = 6
O x= 1
O x = -0.2
O = -1.2
Answers
Someone please help me! Write the equation in standard form!
Answers
Answer:
x^2+y^2=6^2
Step-by-step explanation:
The equation of a circle is (x-h)^2+(y-k)^2=r^2
where h is the x coordinate of the center, k is the y coordinate of the center, and r is the radius of the circle.
We can see the center is on 0,0, and the radius is 6, so our equation is
(x-0)^2+(y-0)^2=6^2
or
x^2+y^2=6^2
Answer:
\( x ^2 + y^2 = 36 \)
Step-by-step explanation:
Center of the circle (h, k) =(0, 0)
Radius of the circle (r) = 6 units
Equation of circle in center radius form is given as:
\( (x-h) ^2 + (y-k) ^2 = r^2 \)
\( (x-0) ^2 + (y-0) ^2 = (6)^2 \)
\( x ^2 + y^2 = 36 \)
Can someone please provide a step-by-step explanation for the answer?
If the universe of discourse is the real numbers, give the truth value of each of the
following propositions:
(a) ∀x∃y(x = y²)
(b) ∀x∃y(x² = y)
(c) ∃x∀y(xy = 0)
(d) ∀x∃y(x + y = 1)
Answers
The Propositions are resulting
(a) ∀x∃y(x = y²) is False
(b) ∀x∃y(x² = y) is True.
(c) ∃x∀y(xy = 0) is True.
(d) ∀x∃y(x + y = 1) is True.
(a) ∀x∃y(x = y²)
This proposition states that for every x, there exists a y such that x is equal to y². To determine the truth value, we need to check if this statement holds true for every value of x.
If we take any positive value for x, we can find a corresponding value of y that satisfies the equation.
For example, if x = 4, then y = 2 satisfies the equation since 4 = 2². Similarly, if x = 9, then y = 3 satisfies the equation since 9 = 3².
Therefore, the proposition (a) is false.
(b) ∀x∃y(x² = y)
For any given positive or negative value of x, we can find a corresponding value of y that satisfies the equation.
For example, if x = 4, then y = 2 satisfies the equation since 4² = 2. Similarly, if x = -4, then y = -2 satisfies the equation since (-4)² = -2.
Therefore, the proposition (b) is true.
(c) ∃x∀y(xy = 0)
The equation xy = 0 can only be satisfied if x = 0, regardless of the value of y. Therefore, there exists an x (x = 0) that makes the equation true for every y.
Therefore, the proposition (c) is true.
(d) ∀x∃y(x + y = 1)
To determine the truth value, we need to check if this statement holds true for every value of x.
If we take any value of x, we can find a corresponding value of y that satisfies the equation.
For example, if x = 2, then y = -1 satisfies the equation since 2 + (-1) = 1. Similarly, if x = 0, then y = 1 satisfies the equation since 0 + 1 = 1.
Therefore, the proposition (d) is true.
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What are the zeroes of the function?
Answers
Answer:
2, 3 and 5
Step-by-step explanation:
Answer:
2,3,5
Step-by-step explanation:
Write an equation in standard form of thecircle with the given properties.Center at(-10, 0); r = square root of 13
Answers
Explanation: Below we have the equation standard form of the circle and what some variables represent.
Step 1: Now we can substitute and calculate as follows
Final answer: So the final answer is
.
6. Journalise the following transactions
1. Bricks for Rs 60,000 and timber for Rs 35,000 purchased for
the construction of building. The payment was made by cheque.
2. Placed in fixed deposit account at bank by transfer from current
account Rs 13,000.
3. Appointed Mr. S.N. Rao as Accountant at Rs 300 p.m. and
Received Rs 1000 as security Deposit at 5% p.a. interest.
4. Sold goods to shruti for Rs 80,000 at 15% trade discount and
4% cash discount. Received 75% amount immediately through a
cheque.
5. Purchased goods from Richa for Rs 60,000 at 10% trade
discount and 5% cash discount. 60% amount paid by cheque
immediately.
6.
On 18th jan,Sold goods to shilpa at the list price of Rs 50,000
20% trade discount and 4% cash discount if the payment is made
within 7 days. 75% payment is received by cheque on Jan 23rd.
7. On 25th jan, sold goods to garima for Rs 1,00,000 allowed her
20% trade discount and 5% cash discount if the payment is made
within 15 days. She paid 1/4th of the amount by cheque on Feb 5th
and 60% of the remainder on 15th in cash.
8. Purchased land for Rs 2,00,000 and paid 1% as brokerage and
Rs 15,000 as registration charges on it. Entire payment is made by
cheque.
9. Goods worth Rs 25,000 and cash Rs 40,000 were taken away
by the proprietor for his personal use.
10. Sold goods costing Rs 1,20,000 to charu at a profit of 33% 3 %
on cost less 15% trade discount.
9
11. Paid rent of building Rs 60,000 by cheque. Half the building is
used by the proprietor for residential purpose.
12. Sold goods costing Rs 20,000 to sunil at a profit of 20% on
sales less 20% trade discount .
13. Purchased goods for Rs 1000 from nanda and supplied it to
helen for Rs 1300. Helen returned goods worth Rs 390, which in
turn were returned to nanda.
14. Received invoice at 10% trade discount from rohit and sons
and supplied these goods to madan, listed at Rs 3000.
Answers
1.Bricks and timber purchased for construction. (Debit: Bricks - Rs 60,000, Debit: Timber - Rs 35,000, Credit: Bank - Rs 95,000)
2.Transfer of Rs 13,000 to fixed deposit account. (Debit: Fixed Deposit - Rs 13,000, Credit: Current Account - Rs 13,000)
3.Appointment of Mr. S.N. Rao as Accountant. (Debit: Salary Expense - Rs 300, Debit: Security Deposit - Rs 1,000, Credit: Accountant - Rs 300)
4.Goods sold to Shruti with discounts. (Debit: Accounts Receivable - Shruti - Rs 80,000, Credit: Sales - Rs 80,000)
5.Goods purchased from Richa with discounts. (Debit: Purchases - Rs 60,000, Credit: Accounts Payable - Richa - Rs 60,000)
6.Goods sold to Shilpa with discounts and received payment. (Debit: Accounts Receivable - Shilpa - Rs 50,000, Credit: Sales - Rs 50,000)
7.Goods sold to Garima with discounts and received partial payment. (Debit: Accounts Receivable - Garima - Rs 1,00,000, Credit: Sales - Rs 1,00,000)
8.Purchase of land with additional charges. (Debit: Land - Rs 2,00,000, Debit: Brokerage Expense - Rs 2,000, Debit: Registration Charges - Rs 15,000, Credit: Bank - Rs 2,17,000)
9.Proprietor took goods and cash for personal use. (Debit: Proprietor's Drawings - Rs 65,000, Credit: Goods - Rs 25,000, Credit: Cash - Rs 40,000)
10.Goods sold to Charu with profit and discount. (Debit: Accounts Receivable - Charu - Rs 1,20,000, Credit: Sales - Rs 1,20,000)
11.Rent paid for the building. (Debit: Rent Expense - Rs 60,000, Credit: Bank - Rs 60,000)
12.Goods sold to Sunil with profit and discount. (Debit: Accounts Receivable - Sunil - Rs 24,000, Credit: Sales - Rs 24,000)
13.Purchased goods from Nanda and supplied to Helen. (Debit: Purchases - Rs 1,000, Debit: Accounts Payable - Nanda - Rs 1,000, Credit: Accounts Receivable - Helen - Rs 1,300, Credit: Sales - Rs 1,300)
14.Purchased goods from Rohit and Sons and supplied to Madan. (Debit: Purchases - Rs 2,700, Credit: Accounts Payable - Rohit and Sons - Rs 2,700, Debit: Accounts Receivable - Madan - Rs 3,000, Credit: Sales - Rs 3,000)
Here are the journal entries for the given transactions:
1. Bricks and timber purchased for construction:
Debit: Bricks (Asset) - Rs 60,000
Debit: Timber (Asset) - Rs 35,000
Credit: Bank (Liability) - Rs 95,000
2. Transfer to fixed deposit account:
Debit: Fixed Deposit (Asset) - Rs 13,000
Credit: Current Account (Asset) - Rs 13,000
3. Appointment of Mr. S.N. Rao as Accountant:
Debit: Salary Expense (Expense) - Rs 300
Debit: Security Deposit (Asset) - Rs 1,000
Credit: Accountant (Liability) - Rs 300
4. Goods sold to Shruti:
Debit: Accounts Receivable - Shruti (Asset) - Rs 80,000
Credit: Sales (Income) - Rs 80,000
5. Goods purchased from Richa:
Debit: Purchases (Expense) - Rs 60,000
Credit: Accounts Payable - Richa (Liability) - Rs 60,000
6. Goods sold to Shilpa:
Debit: Accounts Receivable - Shilpa (Asset) - Rs 50,000
Credit: Sales (Income) - Rs 50,000
7. Goods sold to Garima:
Debit: Accounts Receivable - Garima (Asset) - Rs 1,00,000
Credit: Sales (Income) - Rs 1,00,000
8.Purchase of land:
Debit: Land (Asset) - Rs 2,00,000
Debit: Brokerage Expense (Expense) - Rs 2,000
Debit: Registration Charges (Expense) - Rs 15,000
Credit: Bank (Liability) - Rs 2,17,000
9. Goods and cash taken away by proprietor:
Debit: Proprietor's Drawings (Equity) - Rs 65,000
Credit: Goods (Asset) - Rs 25,000
Credit: Cash (Asset) - Rs 40,000
10. Goods sold to Charu:
Debit: Accounts Receivable - Charu (Asset) - Rs 1,20,000
Credit: Sales (Income) - Rs 1,20,000
Credit: Cost of Goods Sold (Expense) - Rs 80,000
Credit: Profit on Sales (Income) - Rs 40,000
11. Rent paid for the building:
Debit: Rent Expense (Expense) - Rs 60,000
Credit: Bank (Liability) - Rs 60,000
12. Goods sold to Sunil:
Debit: Accounts Receivable - Sunil (Asset) - Rs 24,000
Credit: Sales (Income) - Rs 24,000
Credit: Cost of Goods Sold (Expense) - Rs 20,000
Credit: Profit on Sales (Income) - Rs 4,000
13. Goods purchased from Nanda and supplied to Helen:
Debit: Purchases (Expense) - Rs 1,000
Debit: Accounts Payable - Nanda (Liability) - Rs 1,000
Credit: Accounts Receivable - Helen (Asset) - Rs 1,300
Credit: Sales (Income) - Rs 1,300
14. Goods received from Rohit and Sons and supplied to Madan:
Debit: Purchases (Expense) - Rs 2,700 (after 10% trade discount)
Credit: Accounts Payable - Rohit and Sons (Liability) - Rs 2,700
Debit: Accounts Receivable - Madan (Asset) - Rs 3,000
Credit: Sales (Income) - Rs 3,000
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find the value of x: then find the measure of each angle
Answers
Answer:
Step-by-step explanation:
In a parallelogram, opposite angles are equal.
∠G = ∠E
5x - 9 = 3x + 11
Add 9 to both sides
5x = 3x + 11 + 9
5x = 3x + 20
Subtract 3x from both sides
5x- 3x = 20
2x = 20
Divide both sides by 2
x = 10
∠G = 5x - 9
= 5*10 - 9
= 50 - 9
∠G = 41°
∠G = ∠E = 41°
In parallelogram, adjacent angles are supplementary.
∠G + ∠D = 180
41 + ∠D = 180
∠D = 180 - 41
∠D = 139
∠D = ∠F = 139°
The average rate of growth for human hair is about 0.3 millimeters per day. How many days will it take a hair that is 12 millimeters long to grow to be 16.5 millimeters?
Answers
It will take 15 days for the hair to grow from 12mm to 16.5mm
What do you mean by average rate?By "average rate" in this context, we mean the typical or usual amount of hair growth per unit of time, which is often measured in millimeters per day. This rate can vary slightly depending on factors such as age, gender, genetics, diet, and overall health.
Let's first find out how much the hair needs to grow by subtracting its initial length (12mm) from its target length (16.5mm):
16.5mm - 12mm = 4.5mm
Now we can divide this growth by the average rate of hair growth to find the number of days it will take to grow this much:
4.5mm ÷ 0.3mm/day = 15 days
Therefore, it will take 15 days for the hair to grow from 12mm to 16.5mm.
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What will be the result of substituting 2 for x in both expressions below?
+4
x+6-x-2
O Both expressions equal 5 when substituting 2 for x because the expressions are equivalent.
O Both expressions equal 6 when substituting 2 for x because the expressions are equivalent.
O One expression equals 5 when substituting 2 for x, and the other equals 2 because the expressions are not
equivalent.
One expression equals 6 when substituting 2 for x, and the other equals 2 because the expressions are not
equivalent.
Answers
Both expressions equal 5 when substituting 2 for x because the expressions are equivalent.
Equivalent Algebraic expressions:Algebra is the branch of mathematics that deals with numbers and values which are represented with letters and symbols.
Sometimes, we do not want to mention a particular number, we can represent the number by a letter or a suitable symbol. This approach is algebraic.
For example, d + d = 2d
This is an example of an algebraic expressionns.
Given the algebraic expressions,
\(\frac{1}{2}x + 4 \\ x + 6 - \frac{1}{2}x - 2\)
Substituting 2 for x in the first expression gives:
(1/2 × 2) + 4
1 + 4
5
Substituting 2 for x in the second expression gives:
2 + 6 - (1/2 ×2) - 2
8 - 1 - 2
8 - 3
5
Both expressions equal 5 when substituting 2 for x because the expressions are equivalent.
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.In a different biology lab, a population of single-cell parasites also reproduces hourly. An equation which gives the number of parasites, , after hours is Explain what the numbers 100 and 3 mean in this situation.
Answers
Answer: p=50 h=2
Step-by-step explanation:
so its 50 x 2=100 is the answer then u add 3
Please helppp meeee for brainliest!! ❤️❤️
Answers
Answer:
I'm sorry but I couldn't see the hole question
00:00
Brandy made 7 batches of cookies. Each batch contained 12 cookies.
She put the same number of cookies in each of 5 bags. How many cookies were NOT put in bags?
16 cookies
12 cookies
4 cookies
2 cookies
Answers
Answer:
4 cookies
Step-by-step explanation:
The remainder of (7x12)/5 is your answer.
first you multiply 7 by 12 and you get 84
then you divide 84 by 5 and you take the remaining cookies represented by decimals and you get 4
The numeric components of the electric field in a region of space can be calculated using the equations Ex=6xy and Ey= -5? Which of the following expressions vields the potentia difference between the points (0, Y) and (X,Y)
Answers
- [6xy × (3x'X - 3rY) - 5 × (3rY - 3x'X)] is the expression for the potential difference between the two points.
The potential difference between two points in an electric field can be calculated using the equation ΔV = - ∫Edl, where Edl is the dot product of the electric field vector and the displacement vector between the two points. In this case, we have the components of the electric field, Ex and Ey. To calculate the potential difference, we need to find the displacement vector between the two points.
The given points are ~3rY and 3x'X, so the displacement vector can be expressed as dl = (3x'X - 3rY)i + (3rY - 3x'X)j. Substituting this into the equation for ΔV, we get:
ΔV = - ∫ (Exi + Eyj) . (dl)
= - ∫ [6xy × (3x'X - 3rY) - 5 × (3rY - 3x'X)]
= - [6xy × (3x'X - 3rY) - 5 × (3rY - 3x'X)]
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The question is -
The numeric components of the electric field in a region of space can be calculated using the equations Ex=6xy and Ey= -5. Which of the following expressions fields the potential difference between the points ~3rY 3x'X 3X'X - 5
In a triangle with all sides equal, what is the degree measure of any of the
angles? Write one number. *
Answers
answer:
the degree measure would be 60°
60 + 60 + 60 = 180
therefore, 60 is the answer.
I am lost on this question i found both but it keeps on telling me i am incorrect
Answers
Answer:
I have completed the answers and attached them to the explanation.
Step-by-step explanation:
Answer:
Step-by-step explanation:
The question asks for a subtraction expression:
length is always a positive number so bigger number first here.
OB = 4-(-1) >only moves in x direction so subtract x's
AB = 4-(-2) >only moves in y direction so subtract y's
for a special fully discrete 20-year term insurance on (30): the death benefit is 1,000 during the first ten years and 2,000 during the next ten years.
Answers
The cost of the 20-year term insurance will be based on age, health, smoking, and other factors to determine the premium.
The cost of a special fully discrete 20-year term insurance on a 30-year-old would depend on a range of factors, including the insured's age, health, smoking status, and lifestyle. These factors would be used to calculate the risk of death during the 20-year term. The death benefit of 1,000 during the first ten years and 2,000 during the next ten years would also be taken into account when calculating the cost of the policy. Depending on the risk of death and the death benefits, the premium could vary significantly. For example, a 30-year-old in good health with no smoking history could pay less for the policy than a 30-year-old with a pre-existing condition and a smoking history. The premium could also be higher for individuals with riskier lifestyles. Ultimately, the cost of the 20-year term insurance will depend on the risk of death and the death benefit offered by the policy.
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A health insurer has determined that the "reasonable and customary" fee for a certain medical procedure is $1200. They suspect that the average fee charged by one particular clinic for this procedure is higher than $1200.
Explain in context the conclusion of the test if H0 is rejected.
Answers
Answer:
For the null hypothesis to be rejected , then the conclusion of the test is that the absolute values of the z-statistic and/or the t-test statistic is greater than the critical value
Step-by-step explanation:
Here, we want to explain the conclusion of the test given that the null hypothesis is rejected.
Mathematically, the null hypothesis is as expressed as below;
H0: μ = 1,200
The alternative hypothesis H1 would be;
H1: μ > 1,200
Now, before we can reject or accept the null hypothesis, we will need a sample size and thus calculate the test statistics and the z statistics
For us to reject the null hypothesis, one of two things, or two things must have occurred.
The absolute value of the z statistic |z| or the test statistic |t| must be greater than the critical value.
If this happens, then we can make a rejection of the null hypothesis
pls help me i need help
Answers
Answer:
90
Step-by-step explanation:
because its a right triangle
U= {1,2,3,4,5,6,7,8,}, A={1,4,5,7}, B= {2,5,6,7,}, and C= {3,4,6,7}
Complete the following set operations:
a. AU(BUC)
b. (AN(BNC))'
c. (ANB)U(ANC)
d. (ANB')U(ANC')
Answers
Answer:
a. {1, 2, 3, 4, 5, 6, 7}
b. {1, 2, 3, 4, 5, 6, 8}
c. {4, 5, 7}
d. {1, 4, 5}
Step-by-step explanation:
The union of two sets is the list of elements in either set. The intersection of two sets is the list of elements in both sets. The complement of a set is the list of elements in the universal set that are not in the set being complemented. The complement of a set can be indicated with an apostrophe: A' is the complement of set A, for example.
a. AU(BUC)B∪C = {2, 5, 6, 7} ∪ {3, 4, 6, 7} = {2, 3, 4, 5, 6, 7}
A∪(B∪C) = {1, 4, 5, 7} ∪ {2, 3, 4, 5, 6, 7} = {1, 2, 3, 4, 5, 6, 7}
b. (AN(BNC))'B∩C = {2, 5, 6, 7} ∩ {3, 4, 6, 7} = {6, 7}
A ∩ (B∩C) = {1, 4, 5, 7} ∩ {6, 7} = {7}
(A∩(B∩C))' = {7}' = {1, 2, 3, 4, 5, 6, 8}
c. (ANB)U(ANC)A∩Β = {1, 4, 5, 7} ∩ {2, 5, 6, 7} = {5, 7}
Α∩C = {1, 4, 5, 7} ∩ {3, 4, 6, 7} = {4, 7}
(A∩B)∪(A∩C) = {5, 7} ∪ {4, 7} = {4, 5, 7}
d. (ANB')U(ANC')(A∩B')∪(A∩C') = A∩(B'∪C') = A∩(B∩C)'
(B∩C)' = {6, 7}' = {1, 2, 3, 4, 5, 8}
A∩(B∩C)' = {1, 4, 5, 7} ∩ {1, 2, 3, 4, 5, 8} = {1, 4, 5}
__
Additional comment
In part (d) we made use of De Morgan's law for sets:
B'∪C' = (B∩C)'
We also made use of the distributive property for sets:
A∩(B∪C) = (A∩B)∪(A∩C)
Ms. Guzman asked each of her homeroom students’ “What did you make on your Unit 6 science test”? She graphed the results on the line plot. Which is the best description of the data? (AKS 42) The range is 35, there is a peak at 90, and there are no outliers or gaps. The mode is 90, the data is skewed to the right, and there is a gap at 70 & 75. The mean is about 90, gaps at 70-75, mode at 85 and 100, and the data is skewed to the left. The median is 90, the distribution is asymmetrical, and there are gaps from 70- 75, and an outlier at 65. The median is 90, the distribution is asymmetrical, and there are gaps at 60, 70-75, and an outlier at 65.https://d3rqz33hmpm7kb.cloudfront.net/2021-03-08/5f50fc4b574c12225922587b/604618b510ed2dcf941eee43_rich-text-file-2021-03-08T12-2-46-770Z.imagepng
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Write a two column proof (Given: x is the midpoint of WY and VZ) (Prove: VW=ZY)
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Bruce and Felicia would have a unique solution to the given equation. The value of x that satisfies the equation is 15.
To determine if the equation 6x + 2 = 5x + 17 has a unique solution, we need to check if the variable x has a consistent value that satisfies the equation.
By simplifying the equation, we can see that the equation becomes:
6x - 5x = 17 - 2
Simplifying further, we have:
x = 15
Since the variable x has a specific value, in this case, x = 15, the equation does have a unique solution. When x is substituted with 15 in the equation, both sides are equal.
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3/8=4/7x what is x please help me omg
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The value of the variable x = 21/32
What are algebraic expressions?Algebraic expressions are simply described as expressions that are composed of variables, coefficients, terms, constants and factors.
These expressions are also made up of certain arithmetic or mathematical operations.
These operations includes;
SubtractionDivisionAdditionMultiplicationBracketParenthesesFrom the information given, we have that;
3/8=4/7x
cross multiply the values, we have;
7x(3) = 8(4)
multiply the values and expand the brackets, we get the values;
21x = 32
Divide both sides by the coefficient of the variable x, we get;
x = 32/21
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A 3-D replica of the Great Pyramid of Giza was built at a 10 meter : 1 inch scale. If the volume of a pyramid can be calculated with the formula v= 1/3 length width height, what is the volume of the replica pyramid? scale is 10m/1in
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In this case, we'll have to carry out several steps to find the solution.
Step 01:
Data
l = w = 230.4m
h = 146.5 m
scale
10 m : 1 inch
Step 02:
real
v = (l * w * h) / 3
\(v\text{ = }\frac{230.4\cdot230.4\cdot146.5}{3}=2592276.48m^{3}\)replica
10 m ------------ 1 inch
230.4 m ------------ x
x * 10 = 230.4 * 1
x = 230.4 / 10 = 23.04
l = w = 23.04 in
h = 146.5 / 10 = 14.65 in
v replica :
\(v\text{ replica = }\frac{23.04\cdot23.04\cdot14.65}{3}=\text{ }2592.276in^3\)The answer is:
The volume of the replica is 2592.28 in³