how many of the following are weak acids? hno2 hf hno3 h2po4-

Answer:

5.0 L

Explanation:

Answer:

true

Explanation:

It's true man..............true.........

The mass of potassium chloride produced when potassium chlorate decomposes in this instance is 178.92 g.

The balanced chemical equation is:

2KClO3(s) → 2KCl(s) + 3O2(g)

From the equation, we can see that 2 moles of KClO3 produce 2 moles of KCl. Therefore, 1 mole of KClO3 produces 1 mole of KCl.

Given that 2.4 moles of KClO3 decompose, the amount of KCl produced will also be 2.4 moles.

Now, we need to find the mass of KCl produced, using the molar mass of KCl:

KCl: K = 39.10 g/mol, Cl = 35.45 g/mol

Molar mass of KCl = 39.10 + 35.45 = 74.55 g/mol

Mass of KCl produced = number of moles x molar mass

Mass of KCl produced = 2.4 moles x 74.55 g/mol = 178.92 g

Find out more on mass produced at https://brainly.com/question/15148249

#SPJ1

Force and gravity work together with simple objects exert an equal attractive force

Gravity or gravitational force is the force of attraction between any two objects in the universe and the force of attraction depends on the mass of the object and the square of the distance between them and it is by far the weakest known force in nature the size of the gravitational force is proportional to the masses of the objects and weakens as the distance between them increases and both objects exert an equal attractive force on each other and falling object is attracting the earth with the same size force as the earth is attracting it

Know more force and gravity

https://brainly.com/question/28667537

#SPJ1

Reading the buret to only one decimal place decreases the amount of precision of the result.

While performing an experiment,  if a value is measured 5 times, then if the values measured are same for most of the time or like three times out of five, it said to be accurate. The phenomenon is accuracy. On the other hand, precision is about comparing the values to each other then find them near to each other. Accuracy compares the experimental value to the theoretical value. So, when all the values are close to each other but not nearest to the theoretical value, then it is said to be precise but not accurate. Reading the buret to only one decimal place thus decreases the precision and might lead to occurance of errors.

To know more about accuracy here

https://brainly.com/question/16999977

#SPJ4

The variables in the ideal gas constant has V as the unit of liters and T has the unit of Kelvin. Thus, option C is correct.

The gas constant in an ideal gas equation has been the value of the energy absorbed by 1 mole of an ideal gas at standard temperature and pressure.

The value of R has been dependent on the units of volume, temperature and pressure of the ideal gas.

The given value of R has been 0.0821 L.atm/mol.K

The unit in gas constant has been L (Liter) for volume (V).

The unit of pressure (P) has been atm.

The unit of temperature (T) has been Kelvin  (K).

Thus the gas law constant used by student has V has the unit of liters and T has the unit of Kelvin. Thus, option C is correct.

For more information about the gas constant, refer to the link:

https://brainly.com/question/24814070

Answer:

The molar mass of gas Q is 43.923 g/mol

Explanation:

The given volume of ethane gas that diffuses through a porous plug in 100 seconds = 100 cm³

Therefore;

The rate of diffusion of ethane gas through the porous plug, \(v_{ethane}\), is given as follows;

\(v_{ethane}\) = (100 cm³/100 s) = 1 cm³/s

The molar mass of ethane, C₂H₆ = 2×12 g/mol + 6×1 g/mol = 30 g/mol

The given volume of gas, Q, that diffuses through a porous plug in 121 seconds = 100 cm³

∴ The rate of diffusion of the gas, Q, \(v_Q\) = 100/121 cm³/s

Graham's Law of diffusion states that the rate of diffusion of a gas is inversely proportional to the square root of the molecular mass of the gas

Mathematically, we have;

\(\dfrac{v_A}{v_B} =\sqrt{\dfrac{m_B}{m_A} }\)

Where;

\(v_A\) = The rate of diffusion of gas A

\(v_B\) = The rate of diffusion of gas B

\(m_A\) = The molar mass of the gas A

\(m_B\) = The molar mass of the gas B

Therefore, for ethane and gas Q, measured under the same condition, we have;

\(\dfrac{v_{ethane}}{v_Q} =\sqrt{\dfrac{m_Q}{m_{ethane}} }\)

\(\dfrac{1 \ cm^3/s}{\dfrac{100}{121} \ cm^3/s} =\sqrt{\dfrac{m_Q}{30 \ g/mol} }\)

\(m_Q = \left ({\dfrac{121}{100} } \right) ^2 \times 30 \ g/mol = 43.923 \ g/mol\)

The molar mass of gas Q, \(m_Q\) = 43.923 g/mol.

Specific heat capacity if the unknown metal is -0.450 J/(g°C).

The measure of heat complexity needed to increase the temperature of a single unit of substance mass by one degree Celsius is known as specific heat capacity. This factor is crucial in determining how much energy is required for temperature changes in a given substance.

q = mcΔT

where q is the change in thermal energy, m is the mass of the metal, c is its specific heat capacity, and ΔT is the change in temperature.

In this case, we have:

m = 150 g

ΔT = 22.4°C - 12.6°C = 9.8°C

q = -662 J

Plugging in the values,

-662 J = (150 g) c (9.8°C)

Solving for c, we get:

c = -662 J / (150 g × 9.8°C) = -0.450 J/(g°C)

To know more about specific heat capacity, click here

https://brainly.com/question/29766819

#SPJ1

Metal x is most likely a metal such as aluminum or iron. When metal x reacts with oxygen in the air, it forms metal oxide y.

What do you mean by metal?

Metal is a broad term used to describe a family of materials consisting of a wide range of elements and alloys. These materials have many different properties and uses, including everything from structural support in construction to conductivity in electronics. Metals are malleable, strong, and durable, making them ideal for a variety of applications.

Furthermore, metal oxide y is used in the cement industry to increase the strength of the cement. When metal oxide y is dissolved in water, it produces a gas, z, with a hissing sound. This gas is used for whitewashing. When the clear solution of gas z reacts with carbon dioxide, it forms a white precipitate. This precipitate is a solid form of the metal oxide y and is used to further strengthen the cement.

X: Iron (Fe)

Y: Iron(III) oxide (Fe2O3)

Z: Iron (III) hydroxide (Fe(OH)3)

The chemical reactions involved:

Reaction 1: Fe + O2 → Fe2O3

Reaction 2: Fe2O3 + H2O → Fe(OH)3 + H2O

Reaction 3: Fe(OH)3 + CO2 → FeCO3 + H2O

To know more about metals,

https://brainly.com/question/4701542

#SPJ1

Hey there!

Well, “Ca” is ‘Calcium’ the atomic number of calcium is 20 on the periodic table & “Ar” is ‘Argon’ and atomic number of argon is 18. But with Argon being a noble gas and it’s outer electron shell being already full of electrons with non to spare or receive, and Calcium only having 2 valence electrons.

The chemical bond would most likely be nothing even in a hypothetical situation

Good luck on your assignment & enjoy your day!

~Amphitrite1040:)

Answer: approximately 18.75 mL of 3.0 M HNO₂ solution can be completely neutralized by 75 mL of 1.5 M Mg(OH)₂ solution.

Explanation:

To determine the volume of 3.0 M HNO₂ solution that can be neutralized by 75 mL of 1.5 M Mg(OH)₂ solution, we can set up an equation based on the stoichiometry of the balanced chemical equation.

The balanced chemical equation for the neutralization reaction between HNO₂ and Mg(OH)₂ is:

2 HNO₂ + Mg(OH)₂ → Mg(NO₂)₂ + 2 H₂O

From the equation, we can see that it takes two moles of HNO₂ to react with one mole of Mg(OH)₂.

First, let's calculate the number of moles of Mg(OH)₂ present in 75 mL of 1.5 M solution:

Number of moles of Mg(OH)₂ = Volume (in L) × Concentration (in mol/L)

= 75 mL × (1 L / 1000 mL) × 1.5 mol/L

= 0.1125 mol

Since the stoichiometry ratio is 2:1 (HNO₂:Mg(OH)₂), we can conclude that 0.1125 moles of Mg(OH)₂ can neutralize 0.1125/2 = 0.05625 moles of HNO₂.

Now, let's determine the volume of 3.0 M HNO₂ required to contain 0.05625 moles:

Volume (in L) = Number of moles / Concentration (in mol/L)

= 0.05625 mol / 3.0 mol/L

≈ 0.01875 L

Finally, we convert the volume from liters to milliliters:

Volume (in mL) = Volume (in L) × 1000

≈ 0.01875 L × 1000

≈ 18.75 mL

Decreased alveolar PCO2 and increased alveolar PO2. When the amount and rate of carbon dioxide exhaled from the lungs exceeds the amount of carbon dioxide the body produces, hyperventilation results.

Hyperventilation may be brought on by emotional stress, worry, or fear. The body perceives itself as being under danger in any of these circumstances, triggering the fight-or-flight response, which causes the body to get ready to act and stay vigilant in order to survive. There is no actual threat in anxiety or emotional tension, but the mind perceives a situation as such and activates the aforementioned response, which results in hyperventilation because taking more breaths results in a lower concentration of carbon dioxide in the blood, which causes physical symptoms. 

To know more about hyperventilation visit

https://brainly.com/question/17352284

#SPJ4

The scientific method is used by biologists and other scientists to pose inquiries about the natural world.

The first step in the scientific method is an observation, which prompts a question from the scientist. They then develop a theory—a verifiable explanation—that responds to the query.

A controlled experiment is a scientific test that is carried out under predetermined circumstances, meaning that only one (or a small number of) variables are altered at a time while all other variables are held constant. The element that differs between the experimental and control groups—in this case, the volume of water—is referred to as the independent variable. The response tested in an experiment to establish if a treatment had an impact is known as the dependent variable.

Learn more about biologists:

https://brainly.com/question/28447833

#SPJ4

2,259.675kj/mol

10.16g of pentane is burned in a calorimeter, 9.87kg of water are heated from 21.6(degree) to 33.7(degrees), the molar heat of reaction for carbon dioxide will be

From the above statement , we have found

pentane  C5H12 = 10.16g

H2O =  9.87kg

TI = 21.6°C             T2 = 33.7°C

C5H12+8O2=5CO2+6H2O

as per the reaction, one mole of pentane gives 5 mole of carbon dioxide

now:

molar heat of CO2 = ncΔt ,

here n is number of mole, c is specific heat, t is temperature

Q = 5 ×37.35× 12.1

Q= 2,259.675kj/mol

To know more about  molar specific heat visit : https://brainly.com/question/27181520

#SPJ9

To determine the amount of water and methane needed, we can set up a system of equations based on the desired composition of the mixture. you should use 36 gallons of water and 54 gallons of methane to obtain a mixture of 90 gallons with a methane concentration of 60%.

Let's assume x represents the number of gallons of water and y represents the number of gallons of methane. We have the following information: The total volume of the mixture is 90 gallons: x + y = 90. The mixture should be 60% methane: (y / (x + y)) * 100 = 60. Simplifying the second equation: y / (x + y) = 0.6. Now we can solve the system of equations: From equation 1, we can express x in terms of y: x = 90 - y. Substituting this into equation 2: y / ((90 - y) + y) = 0.6. Simplifying further: y / 90 = 0.6. Solving for y: y = 0.6 * 90. y = 54. Now we can find x using equation 1: x = 90 - y. x = 90 - 54. x = 36. Therefore, you should use 36 gallons of water and 54 gallons of methane to obtain a mixture of 90 gallons with a methane concentration of 60%.

To learn more about methane, https://brainly.com/question/31473733

#SPJ11

The given amount of acetaminophen in a solution is 0.083 g in 150 ml of buffer solution. To calculate the molar concentration of acetaminophen in the given solution, we need to first find the number of moles of acetaminophen present in the given solution.

SGiven,Mass of acetaminophen (m) = 0.083 gVolume of solution (V) = 150 mL = 0.15 LTo find,Molarity of acetaminophen (M) = ?First, calculate the number of moles of acetaminophen present in the given solution using the formula, moles = mass / molar mass of acetaminophenMolar mass of acetaminophen = 151 g/molNumber of moles of acetaminophen present = 0.083 g / 151 g/mol = 0.00055 mol

Now, calculate the molar concentration of acetaminophen in the given solution using the formula,molarity = moles / volumeMolarity of acetaminophen = 0.00055 mol / 0.15 L= 0.00367 MTherefore, the molar concentration of acetaminophen in the given solution is 0.00367 M.

To know more about moles click on below link :

https://brainly.com/question/20486415#

#SPJ11

Explanation:

in the given chemical equation

C2H4 + O2 → CO2 + H2O

The reactants of this reaction IS

C2H4 and O2

the pH of the given buffer solution is 3.08.

The given buffer solution is made up of 60 mL of 0.25 M HCOOH and 10.0 mL of 0.500 M NaXOOH and we are to determine its pH.

The first step in solving this problem is to determine the moles of each species in the buffer. This can be accomplished by using the following equation:

n(HCOOH) = 0.25 moles/L x 0.060 L = 0.015 moles of HCOOHn

(NaXOOH) = 0.500 moles/L x 0.010 L = 0.005 moles of NaXOOH

Next, we need to calculate the concentration of the buffer:

Concentration of buffer = moles of HCOOH / total volume of buffer= 0.015 moles / (0.060 + 0.010) L = 0.1875 M

Now that we have the concentration of the buffer, we can use the Henderson-Hasselbalch equation to determine the pH:

pH = pKa + log ([A-] / [HA])

where pKa = 3.75 for HCOOHpH = 3.75 + log [(0.005 moles / 0.070 L) / (0.015 moles / 0.070 L)]= 3.75 + log [0.07143 / 0.21428]= 3.75 + (-0.6706)= 3.08

Therefore, the pH of the given buffer solution is 3.08.

learn more about pH here

https://brainly.com/question/172153

#SPJ11

The balanced chemical equation is:

0.5C7H16 + O2 → 0.5CO2 + H2O

For balancing the chemical equation C7H16 + O2 → CO2 + H2O, we can use linear algebraic techniques. We need to determine the coefficients that balance the number of atoms on both sides of the equation.

Let's denote the coefficients for C7H16, O2, CO2, and H2O as a, b, c, and d, respectively.

The balanced chemical equation can be written as:

aC7H16 + bO2 → cCO2 + dH2O

To balance the carbon (C) atoms, we have:

7a = c (Equation 1)

To balance the hydrogen (H) atoms, we have:

16a = 2d (Equation 2)

To balance the oxygen (O) atoms, we have:

2b = 2c + d (Equation 3)

We have three equations (Equations 1, 2, and 3) and four unknowns (a, b, c, d). To solve this system of equations, we can write it in matrix form and find the solution using linear algebraic techniques.

The augmented matrix for the system of equations is:

[ 7 0 -1 0 | 0 ]

[ 0 0 0 -2 | 0 ]

[ 0 -2 2 -1 | 0 ]

By performing row operations to row-reduce the augmented matrix, we can obtain the solution:

[ 1 0 -0.5 0 ]

[ 0 1 -1 -0.5 ]

[ 0 0 0 0 ]

The solution to the system of equations is:

a = 0.5

b = 1

c = 0.5

d = 1

Putting the values of a,b,c, and d we get the balanced chemical equation as:

0.5C7H16 + O2 → 0.5CO2 + H2O

To learn more about balancing, visit:

https://brainly.com/question/31242898

#SPJ11

The mass of oxygen that reacted would be 26.32 grams.

The balanced equation of the reaction would be as follows:

\(SO_2(g) + 2O_2(g) --- > 2SO_3(g)\)

Thus, the mole ratio of the \(SO_3\) that is produced and the \(O_2\) that reacts is 1:1.

Recall that, mole is the ratio of mass and molar mass. That is:

Mole = mass/molar mass

Mole of 65.8 grams of  \(SO_3\) = 65.8/80 = 0.8225 mol

From the mole ratio, the equivalent mol of  \(O_2\) that reacts would also be 0.8225 mol.

Mass of 0.8225 mol \(O_2\) = 0.8225 x 32

                                       = 26.32 grams

In other words, the mass of oxygen that reacted to produce 65.8 grams of \(SO_3\) according to the reaction is 26.32 grams.

More on stoichiometric problems can be found here: https://brainly.com/question/28297916

#SPJ1

t = 57 min., Therefore, we can say that it takes 57 minutes for cyclopropane's partial pressure to drop from 1 atm to 0.125 atm at 500°C.

Propene (CH3CH=CH2) is produced by the isomerization of cyclopropane, which is a first-order process. A sample of cyclopropane converts to propene in 79 minutes at 760 K.

The reaction is a first-order reaction because it is an isomerization reaction, and its rate constant is expressed in terms of minutes. The sum of the powers or exponents that the concentration terms are raised in the rate law expression can be used to define the order of a reaction.

to know more about isomerization here:

brainly.com/question/2226351

#SPJ4

Consider the oxidation and reduction reaction below. The substance which is being oxidized and which is being reduced are HBr and Cl₂ respectively.

This is defined as a process in which an electron is removed from a molecule during a chemical reaction.

In the equation given: Cl₂(g) + 2HBr(g) 2HCl(g) + Br₂(g).The Cl₂ is reduced from oxidation state 0 to -1 while HBr oxidized from -1 to 0 thios therefore means that Chlorine is oxidizing agent while HBr is reducing agent and is therefore the correct choice.

Read more about Oxidation here https://brainly.com/question/25886015

#SPJ1

Answer:

\(\lambda=6.56x10^{-7}m\)

Explanation:

Hello there!

In this case, it possible to use the Rydberg equation in order to calculate the wavelength for this transition from n=3 to n=2 as shown below:

\(\frac{1}{\lambda} =R_H(\frac{1}{n_f^2}-\frac{1}{n_i^2} )\)

Thus, we plug in the corresponding energy levels and the Rydberg constant to obtain:

\(\frac{1}{\lambda} =10973731.6m^{-1}(\frac{1}{2^2}-\frac{1}{3^2} )\\\\\frac{1}{\lambda} =1524129.4m^{-1}\\\\\lambda=\frac{1}{1524129.4m^{-1}} \\\\\lambda=6.56x10^{-7}m\)

Best regards!

Noble gas configuration for  elements is 1. [Ne] 3s² 3p5, 2.  [Ne] 3s² 3p⁴, 3.  [Ar] 4s² 3d⁵4. noble gas element in period 4 (krypton). 5.  [Kr] 5s² 4d¹⁰.

Noble gases are a group of chemical elements found in group 18 of the periodic table. They are also known as inert gases because they are very stable and non-reactive due to their outermost electron shells being completely filled with electrons. The noble gases include helium (He), neon (Ne), argon (Ar), krypton (Kr), xenon (Xe), and radon (Rn).

Noble gases are odorless, colorless, and tasteless. They have very low boiling points and exist as gases at room temperature and pressure. They are all monatomic, meaning that their atoms exist independently rather than bonded to other atoms in molecules.

Noble gases are used in various industrial applications, such as in lighting (neon lights), welding (argon), and cryogenics (helium). They are also used in medical applications, such as in MRI machines and anesthesia.

This electron configuration represents a non-metal element in group 17 (halogens). The noble gas configuration for this element is [Ne] 3s² 3p5.

This electron configuration represents a non-metal element in group 16 (chalcogens). The noble gas configuration for this element is [Ne] 3s² 3p⁴.

This electron configuration represents a transition metal element in period 4. The noble gas configuration for this element is [Ar] 4s² 3d⁵.

This electron configuration represents a noble gas element in period 4 (krypton).

This electron configuration represents a transition metal element in period 5. The noble gas configuration for this element is [Kr] 5s² 4d¹⁰.

To know more about  configuration  visit:

https://brainly.com/question/13933772

#SPJ1

The weight percentages of sodium chloride is 23.1 % and water is 76.9 % in the solution. The theoretical density of the initial concentrated solution is 0.30 g/mL.

The mass of the sodium chloride = 30 g

The mass of the water = 100 mL = 100 g

The total mass = 30 + 100

                         = 130 g

The mass percentage of sodium chloride = (30 / 130 ) × 100 %

                                                                        = 23.1 %

The weight percentage of the water = ( 100 / 130 ) × 100 %

                                                             = 76.9 %

The density of the solution = mass / volume

                                             = 30 / 100

                                            = 0.30 g/mL

To learn more about mass percentage here

https://brainly.com/question/16885872

#SPJ4

If 1.9022g pet is burned in oxygen it produces 0.6585 g h2o and 4.0216 g Co2. The empirical formula of PET is \(C_{10}\)\(H_{8}\)\(O_{5}\).

We are told that 1.250 g of PET is burned to produce 0.4328 g \(H_{2}\)O and     2.643g C \(O_{2}\).

By using percentage composition we can determine the masses of carbon dioxide and hydrogen from pet.

% composition = \(\frac{molar mass of element in compound }{molar mass of compound }\) x 100%

Now for Carbon.

% composition C = \(\frac{12.01 g/mole}{12.01 g/mole + (2 x 16.00 g/mol)}\) x 100% = 27.29%

Now multiplying the mass of carbon dioxide by percentage composition we can get the mass of C.

2.643g x 27.29% = 0.7213g

% composition H = \(\frac{2 x 1.01 g/mol }{16.00 g/mol + ( 2 x 1.01 g/mol)}\)  x 100%

Now multiplying the mass of water by percentage composition of hydrogen we can get the mass of H.

0.4328 g × 11.21 % = 0.04852 g

By subtracting the mass of carbon and hydrogen from the mass of the PET i.e. 1.250 g  we can get the mass of oxygen in PET.

1.250 g − 0.04852 g − 0.7213 g = 0.4802 g

Let's calculate the moles of each component.

Moles of carbon = 0.7213/ 12.01 g/mol = 0.06006 mol

Moles of hydrogen = 0.0485/ 1.01 g/mol = 0.04804 mol

Moles of oxygen = 0.4802/ 16.00 g/mol = 0.03001 mol

Now, to get the subscripts for the empirical formula, lets divide the moles of each element with the lowest number of moles.

Carbon = 0.06006/0.03001 = 2

Hydrogen = 0.04804/0.03001 = 1.6

Oxygen = 0.03001/0.03001 = 1

We see that 1.6 is not a whole integer and is equivalent to the fraction 8/5. So the empirical formula become \(C_{2}\)\(H\frac{8}{5}\)O which seems inappropriate as our empirical formulas do not include fractions. So, to fix this problem, let's multiply all the subscripts with the fraction 5.

The final empirical formula is \(C_{10}\)\(H_{8}\)\(O_{5}\).

If you need to learn more about empirical formula click here:

https://brainly.com/question/14318768

#SPJ4

A weak base, such as sodium cyanide (NaCN) or potassium cyanide (KCN), must be added to the hydrocyanic acid solution in order to form a buffer.

The hydrocyanic acid and weak base will combine to generate a weak acid and its conjugate base. The weak acid will then function as a buffer solution along with its conjugate base. The reaction's chemical equation is as follows:

HCN + CN⁻ ⇌ HCN + CN⁻

When moderate amounts of strong base are added to the buffer solution, the weak acid will react with the strong base to form the conjugate base of the weak acid. This reaction will consume the added strong base and prevent the pH of the buffer solution from changing significantly. The chemical equation for the reaction is:

HCN + OH⁻ ⇌ CN⁻ + H₂O

To calculate the pH of the buffer solution, you can use the Henderson-Hasselbalch equation:

pH = pKa + log([A⁻]/[HA])

where pKa is the acid dissociation constant, [A⁻] is the concentration of the conjugate base, and [HA] is the concentration of the weak acid.

To know more about a buffer solution, refer:

https://brainly.com/question/27371101

#SPJ4

Correct question is:

Given a solution of hydrocyanic acid (HCN), what additional regent or reagents are needed to prepare a buffer from hydrocyanic acid solution? Explain how this buffer solution resists a change in pH when moderate amounts of strong acid are added. Use a chemical equation in your explanation.

The element with a molar mass closest to 58.67 g/mol is nickel (Ni), which has a molar mass of 58.69 g/mol. Therefore, the element is nickel.

To identify the element, we'll first calculate the molar mass. In a face-centered cubic lattice, there are 4 atoms per unit cell. The unit cell volume can be calculated as V = (0.352 nm)^3 = 4.37 x 10^-23 cm^3. Given the density, we can find the mass of the unit cell: mass = density x volume = 8.90 g/cm^3 x 4.37 x 10^-23 cm^3 = 3.89 x 10^-22 g.

Now, we can determine the molar mass: molar mass = (mass of unit cell) / (number of atoms per unit cell) x Avogadro's number = (3.89 x 10^-22 g) / 4 x 6.022 x 10^23 = 58.67 g/mol.

The element with a molar mass closest to 58.67 g/mol is nickel (Ni), which has a molar mass of 58.69 g/mol. Therefore, the element is nickel.

To know about lattice:

https://brainly.com/question/31670105

#SPJ11