How many solutions does (3x – 15) = x - 10 have?

Answer:

$16

Step-by-step explanation:

20% is the same as 0.2 in decimal form, since its decreasing you multiply $20 by 0.8 to get 16. If it was increasing, it would be 20 times 1.2

Answer:

$16.00

Step-by-step explanation:

This is the answer because:

1) Since the price decreases by 20%, we have to first figure out what 20% of $20 is:

20% of $20 = 4

2) Next, we just have to subtract 4 from 20 so we can find out how much the cost is:

$20.00 - 4 = $16.00

Therefore, the answer is $16.00.

Hope this helps! :D

answer 33

because i had abd and ur mum jk but yea

Answer:

10 x 10 = 100

6 x 6 = 36

:)

Answer:

10*10=100 | 6*6=36

Step-by-step explanation:

Well, 100/10=10

36/6=6

--------------

10+10+10+10+10+10+10+10+10+10=50+50=100

6+6+6+6+6+6=18+18=36

The table of values which represent the equation y = 7x - 3 is: table D.

In Mathematics, an ordered pair can be defined as a pair of two (2) elements or points that are commonly written in a fixed order within parentheses as (x, y), which represents the x-coordinate or x-axis (abscissa) and the y-coordinate or y-axis (ordinate) on the coordinate plane of any graph.

In order to determine the true ordered pair that is a solution for the given linear equation, we would have to test the ordered pair contained in each table by substituting it into the linear equation as follows;

For ordered pair (-2, -1), we have:

y = 7x - 3

-1 = 7(-2) - 3

-1 = -14 - 3

-1 = -17 (False).

For ordered pair (-2, -19), we have:

y = 7x - 3

-19 = 7(-2) - 3

-19 = -14 - 3

-19 = -17 (False).

For ordered pair (-2, -15), we have:

y = 7x - 3

-15 = 7(-2) - 3

-15 = -14 - 3

-15 = -17 (False).

For ordered pair (-2, -17), we have:

y = 7x - 3

-17 = 7(-2) - 3

-17 = -14 - 3

-17 = -17 (True).

In this context, we can logically deduce that all of the coordinates in table D represents the equation y = 7x - 3.

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Answer:

(2, -3)

Step-by-step explanation:

These are the steps I used:

(6x+2y=6) x3 -> 18x+6y=18

(7x+3y=5) x2 -> 14x+6y=10

When you subtract the equations you get:

4x=8

x=2

The solution to the system of equations is -3 and -2

The correct option is A

A mathematical equation is a statement with two equal sides and an equal sign in between. An equation is, for instance, 4 + 6 = 10. Both 4 + 6 and 10 can be seen on the left and right sides of the equal sign, respectively.

A system of equations is two or more equations that can be solved to get a unique solution. the power of the equation must be in one.

6x+2y=6 is equation (1)

7x+3y=5 is equation (2)

Multiplying equation (1) by (3)

18x+6y=18 is equation(3)

By multiplying (2) by 2

14x+6y=10 is equation (4)

Substrate equation (4) from (3)

4x=8 Now, divide both sides by 4

X=2

Substitute x=2 in (1)

6(2)+2y=6

12+2y=6

Substrate 12 from LHS and RHS

2y=-6

Divide both sides by 2

y=-3

Hence x=2 and y=-3

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Answer:

I would say the answer is 5.03m^2

Step-by-step explanation:

Hope this helps! Please consider marking brainliest! I hope you have an amazing day. Always remember, your smart and you got this! -Alycia :)

Answer:

a

Step-by-step explanation:

Answer:

Area: T = 18

a.  The triangle area using Heron's formula: T=  sqrt(s(s−a)(s−b)(s−c) )

​b. 2\(\sqrt{10}\)  

c. h = 5.69

d. T = 18

Step-by-step explanation:

a. T=  sqrt(s(s−a)(s−b)(s−c) )

T=sqrt( 11.16(11.16−10)(11.16−6)(11.16−6.32) )

​T=  sqrt(324 )

​T =18

b. We compute the base from coordinates using the Pythagorean theorem

c=  sqrt( ((−2−4)^2)+ ((1−3) ^2) )

c= sqrt(40) = 2sqrt(10)

c. Calculate the heights of the triangle from its area

​  

Answer:

since your adding to hours each time youll have 11, then the answer would be d the last one :)

Step-by-step explanation:

Answer:25.50 an hour

Step-by-step explanation:

Marshall is wondering whether he can participate in the LLP again next year. The statement that is true is "He can participate in the LLP again, but only to the extent that his existing LLP balance is less than $20,000.

The Lifelong Learning Plan is a program that helps Canadian residents finance their post-secondary education through their registered retirement savings plans (RRSP). If an individual is attending school full-time, they can withdraw up to $10,000 a year from their RRSP under the program, or up to $20,000 in total. There are certain rules that must be followed by an individual participating in the LLP. For example, withdrawals must be made within four years of enrolling in an eligible educational program, and repayments must begin within the same period.

Here are the statements: Provided he repays his LLP balance in full by the end of this year, Marshall can participate in the LLP again next year.Marshall can only participate in the LLP once over his lifetime. However, his wife can make a LLP withdrawal from her RRSP on his behalf. He can participate in the LLP again, but only to the extent that his existing LLP balance is less than $20,000. He can only participate in the LLP a second time if he repays his LLP balance in full and waits 5 years before he returns to school.The correct statement is: He can participate in the LLP again, but only to the extent that his existing LLP balance is less than $20,000.

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You should pay approximately $10,117.09 initially to secure the annuity and receive annual payments of $1500 over the 9-year period.

To find the cost of the annuity, we need to calculate the present value of the future payments. The present value represents the current worth of future cash flows, taking into account the interest earned or charged over time. In this case, we'll calculate the present value of the $1500 payments using compound interest.

The formula to calculate the present value of an annuity is:

PV = PMT × [1 - (1 + r)⁻ⁿ] / r

Where:

PV is the present value of the annuity (the amount you should pay initially)

PMT is the payment amount received annually ($1500 in this case)

r is the interest rate per period (6.28% or 0.0628)

n is the total number of periods (9 years)

Let's substitute the values into the formula:

PV = $1500 × [1 - (1 + 0.0628)⁻⁹] / 0.0628

Calculating this expression:

PV = $1500 × [1 - 1.0628⁻⁹] / 0.0628

PV = $1500 × [1 - 0.575255] / 0.0628

PV = $1500 × 0.424745 / 0.0628

PV ≈ $10117.09

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The angle of rotation at the point \(\(z_0 = 2i + 1\)\) when \(\(w = z^2\)\) is \(\(2\arctan(2)\),\) which is approximately 1.107 radians or 63.43 degrees.

To determine the angle of rotation at the point \(\(z_0 = 2i + 1\)\) when \(\(w = z^2\),\) we can follow these steps:

1. Express \(\(z_0\)\) in polar form: To find the polar form of \(\(z_0\)\), we need to calculate its magnitude \((\(r_0\))\) and argument \((\(\theta_0\))\). The magnitude can be obtained using the formula \(\(r_0 = |z_0| = \sqrt{\text{Re}(z_0)^2 + \text{Im}(z_0)^2}\)\):

\(\[r_0 = |2i + 1| = \sqrt{0^2 + 2^2 + 1^2} = \sqrt{5}\]\)

  The argument \(\(\theta_0\)\) can be found using the formula \(\(\theta_0 = \text{arg}(z_0) = \arctan\left(\frac{\text{Im}(z_0)}{\text{Re}(z_0)}\right)\)\):

\(\[\theta_0 = \text{arg}(2i + 1) = \arctan\left(\frac{2}{1}\right) = \arctan(2)\]\)

2. Find the polar form of \(\(w\)\): The polar form of \(w\) can be expressed as \(\(w = |w|e^{i\theta}\)\), where \(\(|w|\)\) is the magnitude of \(\(|w|\)\) and \(\(\theta\)\) is its argument. Since \((w = z^2\)\), we can substitute z with \(\(z_0\)\) and calculate the polar form of \(\(w_0\)\)using the values we obtained earlier for \(\(z_0\)\):

 \(\[w_0 = |z_0|^2e^{2i\theta_0} = \sqrt{5}^2e^{2i\arctan(2)} = 5e^{2i\arctan(2)}\]\)

3. Determine the argument of \(\(w_0\):\) To find the argument \(\(\theta_w\)\) of \(\(w_0\)\), we can simply multiply the exponent of \(e\) by 2:

  \(\[\theta_w = 2\theta_0 = 2\arctan(2)\]\)= 1.107 radians

Therefore, the angle of rotation at the point \(\(z_0 = 2i + 1\)\) when \(\(w = z^2\)\) is \(\(2\arctan(2)\).\)

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The complete question is:

"Determine the angle of rotation, in radians and degrees, at the point z0 = 2i + 1 when w = z^2."

There are 91,390,400 different ways to choose president, vice president, treasurer, and secretary from a class of 40 students.

To find the number of different ways to choose president, vice president, treasurer, and secretary from a class of 40 students, we need to use the formula for permutations. This formula is nPr = n! / (n - r)!, where n is the total number of items and r is the number of items being chosen. In this case, n = 40 and r = 4, so we have equations:

40P4 = 40! / (40 - 4)!
40P4 = 40! / 36!
40P4 = (40 x 39 x 38 x 37) / (4 x 3 x 2 x 1)
40P4 = 91,390,400

Therefore, there are 91,390,400 different ways to choose president, vice president, treasurer, and secretary from a class of 40 students. This means that each person in the class has a 1 in 91,390,400 chance of being chosen for all four positions.  

It's important to note that this calculation assumes that each person can only hold one position, and that the order in which the positions are filled matters. If these assumptions are changed, then a different formula would need to be used.

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To solve the integral of 1/sqrt(x^2 - a^2) dx, we can use the substitution method. Let u = x^2 - a^2, then du/dx = 2x, and dx = du/2x.
Substituting into the integral, we get:

∫ 1/sqrt(x^2 - a^2) dx = ∫ 1/sqrt(u) * du/2x
= (1/2) ∫ 1/sqrt(u) du  

= (1/2) * 2sqrt(u) + C
= sqrt(x^2 - a^2) + C

Therefore, the answer to the integral of 1/sqrt(x^2 - a^2) dx is sqrt(x^2 - a^2) + C, where C is the constant of integration.

In summary, the integral of 1/sqrt(x^2 - a^2) dx can be solved using the substitution method, where u = x^2 - a^2. The final answer is sqrt(x^2 - a^2) + C, where C is the constant of integration.

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The integral of \(\frac{1}{\sqrt{x^2 - a^2}} dx\) is \(\ln\left|\frac{\sqrt{x^2 - a^2}}{a} + \frac{x}{a}\right| + C\), where C is the constant of integration

What is intergration?

Integration is a fundamental concept in calculus that involves finding the antiderivative or integral of a function. It is the reverse process of differentiation, which is concerned with finding the derivative of a function.

To find the integral of \(1/\sqrt(x^2 - a^2) dx\), we can use a trigonometric substitution. Let's substitute \(x = a sec(\theta)\), where \(sec(\theta)\) is the reciprocal of the cosine function.

By making this substitution, we can express dx in terms of \(d(\theta)\) as follows:

\(dx = a sec(\theta) tan(\theta) d(\theta)\)

Now, let's substitute these values into the integral:

\(\int \frac{1}{\sqrt{x^2 - a^2}} dx\\\\= \int \frac{1}{\sqrt{(a \sec(theta))^2 - a^2}} (a \sec(\theta) \tan(\theta)) d(\theta)\\\\= \int \frac{1}{\sqrt{a^2(\sec^2(theta) - 1)}} (a \sec(\theta) \tan(\theta)) d(\theta)\\\\= \int \frac{1}{\sqrt{a^2(\tan^2(theta))}} (a \sec(\theta) \tan(\theta)) d(\theta)\\\\= \int \frac{1}{a \tan(theta)} (a \sec(\theta) \tan(\theta)) d(\theta)\)

Simplifying the expression, we have:

\(= \int \sec(\theta) d(\theta)\)

The integral of \(sec(\theta)\) can be evaluated as the natural logarithm of the absolute value of \(sec(\theta)\) plus the tangent\((\theta)\):

\(= \ln|\sec(\theta) + \tan(\theta)| + C\)

Finally, substituting back \(x = a sec(\theta)\), we get:

\(= \ln|\sec(\theta) + \tan(\theta)| + C\\\\= \ln\left|\frac{\sqrt{x^2 - a^2}}{a} + \frac{x}{a}\right| + C\)

Therefore, the integral of \(\frac{1}{\sqrt{x^2 - a^2}} dx\) is \(\ln\left|\frac{\sqrt{x^2 - a^2}}{a} + \frac{x}{a}\right| + C\), where C is the constant of integration

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The value of y for the given conditions is 82.2.

Repetitive subtraction is the process of division. It is the multiplication operation's opposite. It is described as the process of creating equitable groups. When dividing numbers, we divide a larger number down into smaller ones such that the larger number obtained will be equal to the multiplication of the smaller numbers.

Given a phrase, y divided by 6.85=1.2

y ÷ 6.85 = 12

y/6.85 = 12

multiply both sides by 6.85

y/6.85(6.85) = 12 x 6.85

y = 82.2

Hence the value of y is 82.2.

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Answer:

38?

Step-by-step explanation:

I can't tell if you were dividing, but 456/12 is equal to 38. Same goes if you were looking for 456=12*x, which x is also 38.

The greatest common divisor (GCD) of 735 and 504 is 21. Using the Euclidean algorithm, we find that the GCD can be expressed as 735x + 504y, where x = 11 and y = -5.

(a) To compute the GCD using the Euclidean algorithm, we start by dividing the larger number (735) by the smaller number (504):  \(735 = 504 * 1 + 231\)

Next, we divide the previous divisor (504) by the remainder (231):

\(504 = 231 * 2 + 42\)

We continue dividing the previous divisor by the remainder until we reach a remainder of 0:

\(231 = 42 * 5 + 21\\42 = 21 * 2 + 0\)

The last non-zero remainder is 21, which is the GCD of 735 and 504.

(b) To find integers x and y such that the GCD of 735 and 504 can be written in form 735x + 504y, we can use the extended Euclidean algorithm.

Starting with the last two equations from part (a):

\(21 = 231 - 42 * 5\\21 = 231 - (504 - 231 * 2) * 5\)

To simplifying, we have:

\(21 = 11 * 231 - 5 * 504\)

Therefore, we can write the GCD of 735 and 504 as:

\(21 = 11 * 735 - 5 * 504\)

So, x = 11 and y = -5 satisfy the equation 735x + 504y = 21, with x and y being integers.

In conclusion, the GCD of 735 and 504 is 21, and it can be expressed as 735x + 504y, where x = 11 and y = -5.

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The sequence {an} = (-1)^n/2 is divergent because it oscillates between two values infinitely often as n approaches infinity. Specifically, it alternates between 1 and -1 as n increases, and does not converge to a single limit.

The sequence {an} = (-1)^n/2 is an example of an oscillating sequence that does not converge to a single limit. It oscillates between two values, 1 and -1, depending on whether n is even or odd. As n increases, the oscillations become more frequent and rapid, and the sequence never settles down to a single value.

The sequence {an} = (-1)^n/2 is not convergent, because it oscillates between two values infinitely often as n approaches infinity.

Specifically, when n is even, we have a_n = (-1)^n/2 = (-1)^0 = 1, and when n is odd, we have a_n = (-1)^n/2 = (-1)^1 = -1. Therefore, the sequence alternates between 1 and -1 as n increases, and never settles down to a single value.

Since the sequence does not converge to a single limit, we can say that it diverges.

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\(\Large\texttt{Answer}\)

\(equation=\)\(\bold{y=5x-33}\)

\(\overline{\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad}\)

\(\Large\texttt{Process}\)

⇨ Use the formula below

\(\bf{y-\hfill\stackrel{y \:co-ordinate}{y1}=\hfill\stackrel{slope}{m}(x-\hfill\stackrel{x\:co-ordinate}{x1)}}\)

⇨ Substitute the parameters:

\(\bold{y-(-8)=5(x-5)}\)

\(\bold{y+8=5x-25}\)

\(\bold{y=5x-33}\)

Hope that helped

C) The lines g and g' are parallel and E'(-2,0) and F'(0, 1)

1) Let's locate points E and F.

E (0,2) and F( -4,0)

Given that line was dilated by a scale factor k = 1/2 about the origin we can state the following

• The line segment g' is shorter, half of g.

• Points E'(0,1) and F'(0,1)

3) Examining the answers we can state:

The lines g and g' are parallel and E'(-2,0) and F'(0, 1)

Answer:

The value of q = 11

Step-by-step explanation:

Number of pure cotton shirts = \(\frac{4+q}{20}\)

Probability of drawing pure cotton shirts = \(\frac{4+q}{20}\) = \(\frac{3}{4}\)

Substituting the above problem = 4(4 + q) = 3 x 20

                                                     =  16 + 4q = 60

                                                     = 4q = 60 - 16 = 44

                                                     = q = \(\frac{44}{4}\)

∴ q = 11

Answer:

yeah I can help you what's the problem

Answer:

256

Step-by-step explanation:

First, find g(2):

g(2) = 3(2)+2 = 6+2 = 8

Now, plug that result into f(x):

f(8) = 4(8)^2 = 4*64 = 256

The unit m/s represents the speed of light. Therefore, the units of the right-hand side of the equation prove that the speed of light is represented in the equation.

The equation mentioned in the question is as follows; The SI units of magnetic permeability and permittivity of free space are Henry/meter and farad/meter respectively. In order to prove that the units given by the right-hand side of the equation are m/s, we need to perform the following steps: Substitute the values of magnetic permeability and permittivity of free space in the equation. Let's substitute µ0 and ε0 values in the above equation, we get; In order to perform this step, we need to know the units of each component in the equation. A unit of force is Newton, and a unit of charge is Coulomb. A magnetic field has the unit Tesla. Let's find out the units of the right-hand side component of the above equation. We can now rearrange the equation to make it simpler.!)

The unit m/s represents the speed of light. Therefore, the units of the right-hand side of the equation prove that the speed of light is represented in the equation.

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Answer:

14

Step-by-step explanation:

Ok, 60! is a really big number

\(x!=x(x-1)(x-2)...1\)

So we have 60*59*58...*1

2 times 5 is 10 which makes a terminal zero (ending zero)

We need to count how many fives and twos are in 60!

There are 60/5=12 5^1's

There are 60/25=2 5^2's

So 12+2=14

There are way more 2's than fives so we take the lesser number

So the answer is 14

*Note that 60/25 is not 2, we need an integer rounded down

Step-by-step explanation:

Range=Highest-Lowest

=93-43

=50

Answer:

WALA PO AKONG ALAM SA MATH EHH HEHEH

Answer: y = 8x

Step-by-step explanation:

The firm's after-tax cost of debt on the bond will be 11.90% .

To calculate the firm's after-tax cost of debt on the bond, we need to follow these steps:

1. Determine the bond's yield to maturity (YTM) given its price, par value, annual interest, and time to maturity.
2. Calculate the bond's pre-tax cost of debt.
3. Adjust for flotation costs.
4. Apply the tax bracket to find the after-tax cost of debt.

1. The bond's YTM can be calculated using a financial calculator or software. Given the bond's price of $935, par value of $1,000, annual interest of 12% ($120), and a maturity of 0 years, the YTM is approximately 12.83%.

2. The pre-tax cost of debt is the YTM, which is 12.83%.

3. Flotation costs are 13% of the bond's market value ($935). Therefore, flotation costs are $121.55 ($935 * 0.13). The adjusted bond price, taking into account flotation costs, is $813.45 ($935 - $121.55). To find the adjusted YTM, we can use the adjusted bond price, keeping other factors constant. The adjusted YTM is approximately 14.87%.

4. The company is in a 20% tax bracket. To find the after-tax cost of debt, we need to apply the tax bracket: After-tax cost of debt = Adjusted YTM * (1 - Tax Rate) = 14.87% * (1 - 0.2) = 14.87% * 0.8 = 11.90%.

The firm's after-tax cost of debt on the bond will be 11.90% (rounded to two decimal places).

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Answer:

5/9

Step-by-step explanation:

brainliest when possible.